A car can go from 0 to 60 mph in 6.0 s .assuming that it could maintain the same acceleration at higher speeds, how long would it take the car to go from 0 to 120 mph?

Answer:

brainless plsss

The box accelerates down the inclined plane at a rate of approximately 2.93 m/s².

To calculate the rate at which the box accelerates down the inclined plane, we need to consider the forces acting on the box. These forces include the gravitational force and the force of kinetic friction.

Given:

Mass of the box (m) = 6.0 kg

Angle of the inclined plane (θ) = 39°

Coefficient of kinetic friction (μ) = 0.40

First, we determine the gravitational force acting on the box. The gravitational force can be calculated using the formula:

Force_gravity = m × g

Force_gravity = 6.0 kg × 9.8 m/s²

            = 58.8 N

Next, we calculate the force of kinetic friction using the formula:

Force_friction = μ × Force_normal

The normal force (Force_normal) is the component of the gravitational force perpendicular to the inclined plane. It can be calculated as:

Force_normal = Force_gravity × cos(θ)

Force_normal = 58.8 N × cos(39°)

                     ≈ 45.0 N

Substituting this value into the formula for the force of kinetic friction:

Force_friction = 0.40 × 45.0 N

              = 18.0 N

The net force acting on the box down the inclined plane can be calculated as:

Net_force = Force_gravity × sin(θ) - Force_friction

Net_force = 58.8 N × sin(39°) - 18.0 N

         ≈ 35.6 N - 18.0 N

         ≈ 17.6 N

Finally, we calculate the acceleration (a) using Newton's second law:

Net_force = m × a

17.6 N = 6.0 kg × a

a ≈ 2.93 m/s²

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Answer:

the average speed of the car during this time interval is 40 m/s i thinkk..

Answer:

The frequency at which the string will create a standing wave be  with three loops is 8.6 Hz

Explanation:

The speed of the of the wave, v = 12.9 m/s

The number of loops of the standing wave = 3 loops

The length of the string = 2.00 m

Given that one loo = half of the wavelength, we have;

Three loops = 3 × half = One and half wavelength  = 1.5·λ

The frequency of a wave = f = v/λ

Therefore, we have;

The frequency, f = 12.9/1.5 = 8.6 Hz

The frequency at which the string will create a standing wave be  with three loops = 8.6 Hz.

Answer:

9.675

Explanation:

got it right on acellus

Answer: It increased by a factor of 5

Explanation:

Gravitational potential energy  is given by the following formula:

Answer:

This is true fact.

Well done bud keep up the hard work at school

true As a non-zero net force

The statement which is false is as follows:

Thus, the correct option for this question is D.

Friction may be defined as a type of force that resists the sliding or rolling of one solid object over another through the surface that acts on it.

Friction is a force that takes place as the resistance of motion when one object rubs over another. Friction force always opposes the motion along with air resistance.

Friction can also be somehow reduced with the impact of lubrication over the rubbing surface. It is true that air resistance is greater the faster the object is traveling.

Air resistance does not depend on the blowing of the wind. It does not mean that if there is no wind blowing, the air resistance is negligible.

Therefore, the correct option for this question is D.

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Answer:   b or c

Explanation:  on khan academy

the correct answer is option a. m^2, as it is the proper unit for the second moment of area (q) in the shear formula.

In the shear formula, τ=vqit, q represents the area over which the shear force is applied. The units of q should be in square meters (m^2) to ensure that the overall unit of the formula is in Newtons per square meter (N/m^2) or Pascals (Pa). Therefore, option (e) m^2 is the proper unit of q. Option (a) m^2 is also correct but it is not specifically labeled as a unit.

Option (b) m^4 is incorrect because it is a unit of volume. Option (c) dimensions and option (d) me are not valid units of area. Lastly, option (f) None of these is incorrect since option (e) m^2 is the correct answer. The proper unit of q in the shear formula τ = vqit is "m^2".

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Answer:

25000 J or 25 kJ

Explanation:

K = 1/2 mv^2

where mass is in kilograms kg

and velocity is in metres per seconds m/s

Here, m = 2000, v = 5

v^2 = 5*5 = 25

1/2 mv^2 = 1/2 * 2000 * 25

= 50000/2

= 25000

Hope it helps!

The spinning tube of air created by winds moving in opposite directions to tip upwards and become vertical because of the updraft of wind in a supercell. Hence, option (A) is correct.

As a deep, continuously revolving updraft known as a mesocyclone, a supercell is a type of thunderstorm. This causes these storms to occasionally be called spinning thunderstorms.

Supercells, which are the least frequent and have the potential to be the most severe of the four types of thunderstorms (supercell, squall line, multi-cell, and single-cell), are the least common overall.

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The expression for the buoyant force is F = ρghs²

Buoyant force is the force exerted on a object by a liquid.

Given that the pressure from the fluid at a certain depth is given by P = P₀ + ρgh where

We know that the buoyant for is due to the pressure difference frm the top and bottom of the fluid.

Since

P = P₀ + ρgh

P - P₀ = ρgh

ΔP =  ρgh

Now, we know that pressure difference, ΔP = F/A where

So, making F subject of the formula, we have that

F = ΔPA

Now since the object is a perfect cube of length, s, its area at its bottom surface perpendicular to F is A = s²

So, F = ΔPA

F = ΔPs²

So, substituting ΔP into the equation, we have that

F = ΔPs²

F = ρghs²

So, the buoyant force is F = ρghs²

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To define the system so that the energy changes are all transformations internal to an isolated system, we need to choose a closed system that does not exchange energy with the surroundings. The most appropriate option would be to select only the diver as the system.

This means that the energy transformations that occur during the dive, such as gravitational potential energy converting to kinetic energy as the diver falls, and kinetic energy converting to thermal energy as the diver hits the water, will all be internal to the system and not influenced by external factors such as the Earth or the water in the pool. Therefore, the answer is option (a) - Include the diver.
To define the system so that the energy changes are all transformations internal to an isolated system when a diver leaps from a high platform, speeds up as she falls, and then slows to a stop in the water, you should include the diver, Earth, and the water in the pool (option b). This way, the gravitational potential energy, kinetic energy, and the energy dissipated in the water are all accounted for within the system, ensuring all energy transformations are internal.

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Answer:

The kinetic energy of the phone would increase. The gravitational potential energy of the phone would decrease.

Explanation:

The kinetic energy \({\rm KE}\) of an object is proportional to the square of the speed of that object. If air resistance is negligible, the phone would accelerate under gravitational pull and speed up. Hence, the kinetic energy of the phone would increase.

The gravitational field near the surface of the earth is approximately constant. Hence, the gravitational potential energy \({\rm GPE}\) of the phone would be proportional to its height. As the phone approaches the ground, the height of the phone becomes lower and the gravitational potential energy of the phone would decrease.

Answer:

Sn = 515 km * sin 19.5 = 172 km      distance North

Sw = 515 km * cos 19.5 = 485 km       distance West

Check (172^2 + 485^2)^1/2 = 515 km

The ship is approximately 486.4 km north of the harbor.

We can begin by drawing a diagram of the problem:

  A

  |\

  | \

  |  \ 515 km

  |   \

  |    \

  |19.5°\ B

  -------

    X km

Here, point A represents the harbor, point B represents the ship's current location, and X represents the distance the ship has traveled westward.

To find X, we can use trigonometry. The angle between the ship's direction and due west is 90° - 19.5° = 70.5°. Therefore, we can find X using the cosine of 70.5°:

cos(70.5°) = X / 515 km

Solving for X, we get:

X = 515 km * cos(70.5°) ≈ 162.7 km

So the ship is approximately 162.7 km west of the harbor.

To find the distance the ship has traveled northward, we can use the sine of 70.5°:

sin(70.5°) = Y / 515 km

Solving for Y, we get:

Y = 515 km * sin(70.5°) ≈ 486.4 km

So the ship is approximately 486.4 km north of the harbor.

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Two students push on a box in the same direction and a third student pushes in the opposite direction. The net force on the box if each push with a force of 50 N is (F)= 50N.

According to the first law of newton's law of motion when a particle is at rest it always be at rest if any external thing affect on it. That external or internal thing that helps the object move that called Force. It can be measured in Newton, Dyne.

To calculate the force we have to study the question carefully. Two  students push on a box in the same direction and a third student pushes in the opposite direction. So according to the question the net force will be,

F = 2f₁-f₂

Here we know,

f₁= The amount of force that two students apply on the same direction. = 50 N.

f₂= The amount of force that students apply on the opposite direction. = 50 N.

We have to calculate the net force= F N.

Now we put the values in above equation, we get,

F = 2f₁-f₂

Or, F= 100-50

Or, F=50N

From the above calculation we can say that,  The net force on the box if each push with a force of 50 N is (F)= 50N.

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Answer:

the answer is full moon

Explanation:

When the moon passes between earth and sun the lunar shadow is seen as solar eclipse on earth.

The smallest number of DAC bits that would satisfy the requirements is 13. The correct option is a.

To determine the smallest number of DAC bits required to satisfy the given requirements, we can use the formula:

Resolution = (Voltage Range) / (2ⁿ - 1)

Here, the voltage range is 0 to 5V, and the required resolution is 1mV (0.001V). We need to find the smallest integer value of n that satisfies the equation.

0.001V = 5V / (2ⁿ - 1)

By solving for n, we get:

2ⁿ = 1 + (5V / 0.001V) = 1 + 5000 = 5001

Taking the logarithm base 2 of both sides, we get:

n = log2(5001)

n ≈ 12.287

Since n must be an integer, we round up to the next whole number:

n = 13

Therefore, the smallest number of DAC bits required is 13 (option A).

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The applied force equal to the weight

In order to maintain constant velocity (zero acceleration).

The power of the force required to move elevator cab is 235 kW

P = Fv

=(1800 kg+4500 kg)(9.8 m/s^2)(3.80 m/s)

=235 kW

The applied force equal to the weight

in order to maintain constant velocity (zero acceleration).

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The capacitor with the smaller plate separation will have a stronger electric field between the plates.

The electric field strength in a capacitor is determined by the voltage applied across the capacitor and the distance between the plates. According to the principles of electrostatics, the electric field strength is directly proportional to the voltage and inversely proportional to the plate separation. In other words, when the voltage applied across the capacitor increases, the electric field strength between the plates also increases. Conversely, when the plate separation decreases, the electric field between the plates becomes stronger. This relationship illustrates how adjusting the voltage and plate separation can control the electric field strength in a capacitor, which is a crucial factor in its operation and functionality.

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Answer:

I = 50 A

Explanation:

The magnetic field created by a wire with a current can be calculated as:

Where μ is a constant equal to 4π x 10^(-7) T m/A, I is current, and r is the distance from the wire. So, replacing the values, we get:

Then, solving for I, we get:

Therefore, the current that is traveling through the wire is 50 A.

On the other hand, if the current is moving upward, the direction of the magnetic field can be found by the rule of the right hand, so the magnetic field will have the following direction:

Answer:

Simple machines are useful because they reduce effort or extend the ability of people to perform tasks beyond their normal capabilities. Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever.

Answer:

Simple machines are useful because they reduce effort or extend the ability of people to perform tasks beyond their normal capabilities. Simple machines that are widely used include the wheel and axle, pulley, inclined plane, screw, wedge and lever.

Explanation:

funny answer cuz peeps be lazy

If you increase the frequency of a sound wave four times, the speed will increase four times. The correct option is A.

Particles that are vibrating make up sound waves. These collide with other particles, causing them to vibrate, which allows the sound to escape the source.

Your ear drums vibrate as a result of air vibrations, which allows you to perceive sound. This vibration is transformed into messages, which proceed to your brain via a nerve.

When sound is produced, air molecules shake and collide, causing vibrations to travel between air molecules. The sound is transmitted by the vibrating particles, which also cause the ear drum to vibrate.

A sound wave's frequency can be increased four times without increasing its speed.

Thus, the correct option is A.

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Answer:

uaa,uag,uga

Explanation:

We will have the following:

First, we remember that:

So:

So, the change in length of the rod is approximately 4.41 mm.

Answer:

C

Explanation:

Answer:

C) an investigation of conduction through collisions between particles in space

Answer:

5270 N

Explanation:

We have,

• Mass, m = 1054 kg

• Acceleration, a = 5 m/s²

We have to find Force Applied, F.

\(\longrightarrow\) F = ma

\(\longrightarrow\) F = 1054 × 5 N

\(\longrightarrow\) F = 5270 N (Answer)

Horizontal motion is defined as a projectile motion in a horizontal plane depending upon the force acting on it. For a short distance, the vertical and horizontal components of a projectile are perpendicular and independent of each other.

Answer:

A projectile moves along its path with a constant horizontal velocity

The calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.

The period of vibration of an object attached to a spring is related to the mass of the object and the spring constant. The formula to calculate the period (T) of an oscillating mass-spring system is:

T = 2π√(m/k)

Where:

T = period of vibration

m = mass of the object

k = spring constant

In this case, the period (T) is given as 3.0 seconds, and the mass (m) is 1.0 kg. We can rearrange the formula to solve for the spring constant (k):

T = 2π√(m/k)

(3.0 s) = 2π√(1.0 kg/k)

Now, we can isolate k:

(3.0 s) / (2π) = √(1.0 kg/k)

(3.0 s) / (2π) = √(k/1.0 kg)

Square both sides:

(3.0 s / 2π)^2 = k / 1.0 kg

Simplifying:

(9.0 s^2 / 4π^2) = k / 1.0 kg

Multiplying both sides by 1.0 kg:

k = (9.0 s^2 / 4π^2) kg

Therefore, the calculated spring constant is approximately (9.0 s^2 / 4π^2) kg.

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