A car has a distance between axles of 6.2 m and a center of mass located 2.2 m from the front axle. What is the
ratio of the weights indicated by a scale when only the front axle is on the scale versus when only the rear axle
is on the scale?
Select one:
O a. W front axles / Wirear axle) = 1.62
O b. Wifront axles / Wirear axle)
1.93
O c. W front axe) / Wirear asse) =
1.81
1/ We
O d. Wifront axle
(rear axle) = 2.06

Answer:

20 kg*m/s

Explanation:

we're looking for the change in the cars momentum . the formula to identify the cars momentum is Δp=m*vf-m*vi . In this case m= mass , vf= velocity final, and vi= velocity initial . The mass is how much the car weighs , which is 4 kg . Velocity final would be 8 m/s since that's how fast it last was . Velocity initial would be 3 m/s since it had first started at that speed . Now we can jus plug it into the formula .

m= 4 kg

vf= 8 m/s

vi= 3 m/s

Δp= (4)*(8) - (4)*(3)

Δp= 32-12

Δp= 20 kg*m/s

hope this helps .

Answer:

i hope it will be useful for you

Explanation:

F=5.6×10^-10N

R=93cm=0.93m

let take m1 and m2 =m²

according to newton's law of universal gravitation

F=m1m2/r²

F=m²/r²

now we have to find masses

F×r²=m²

5.6×10^10N×0.93m=m²

5.208×10^-9=m²

taking square root on b.s

√5.208×10^-9=√m²

so the two masses are m1=7.2×10^-5

and m2=7.2×10^-5

The spring scale read just before the mass touches the lower spring is 80.36N, the spring constant for the lower spring is 2765N/m and at 2.9cm length the scale will read zero.

Given the mass of spring = 8.2kg

The force exerted for compressing of spring = 14N

The compression in spring = 2.4cm = 0.024m

(A.) Initially the spring scale reads only the weight of the mass = mg

W = 8.2 * 9.8 = 80.36N

(B) Let the value of spring constant = k

The net force exerted so that the scale reads(F') = 80.36N - 14 = 66.36N

We know that according to Hooke's law the force exerted on spring F = kx such that:

F' = kx then:

66.36 = k * 0.024

k = 66.36/0.024 = 2765N/m

(C) the compression where scale reads zero = x'

The scale reads zero when the restoring force equals to the weight of the mass then the scale reads zero such that:

x' = 80.36/2765 = 0.029m = 2.9cm

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Answer:

Separation of the Earth into layers (crust, mantle, inner core, and outer core) was largely caused by gravitational differentiation (separating different constituents at temperature where materials are liquid or plastic, owing to differences in density) early in Earth's history.

Explanation:

hoped it helped!!

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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The time taken for the object to travel the given height is determined as 12.48 seconds.

Time of motion of an object is the total time taken by the object to travel a given height or distance.

The time of motion of the boulder is calculated as follows;

h = vt + ¹/₂gt²

where;

1300 = 43t  +  0.5(9.8)t²

1300 = 43t + 4.9t²

4.9t² + 43t - 1300 = 0

solve the quadratic equation using formula method as shown below;

a = 4.9, b = 43, c = -1300

t = 12.48 seconds

Thus, the time taken for the object to travel the given height is determined as 12.48 seconds.

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Answer:

The correct statement must be: both balls hit the floor at the same time

Explanation:

This is a kinematics exercise. The ball thrown horizontally does not have vertical speed and the ball that is released does not have vertical speed, therefore both take the same time to reach the ground, if we neglect the air resistance

The correct statement must be: both balls hit the floor at the same time

This question involves the concepts of buoyant force and the weight of an object.

The buoyant force on the piece of metal is "8 N".

The apparent weight of the piece of metal is given by the following formula:

Apparent Weight = Actual Weight - Buoyant Force

Buoyant Force = Actual Weight - Apparent Weight

Buoyant Force = 20 N - 12 N

Buoyant Force = 8 N

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The attached picture illustrates the buoyant force.

Theprojectile launch allows to find the correct answer for the question about the direction of the ball when it hits the ground is:

       D)  θ = 37º measured clockwise from the x-axis.

projectile launch is an application of kinematics where there is no acceleration on the horizontal axis and the acceleration on the vertical axis is the gravity acceleration.

The horizontal distance traveled until it reaches the ground is

          x = v₀ₓ t

The height of the bullet is

          y = y₀ + \(v_o_y\)  t - ½ g t²

The initial vertical velocity is zero and when it reaches the ground its height is zero.

         0 = y₀ - ½ g t²

         t = \(\sqrt{\frac{2y_o}{g} }\)  

We substitute

          \(x = v_{ox} \ \sqrt{\frac{2y_o}{g} }\)  

They indicate that the distance is:

          x = \(\frac{8}{3} \ y_o\)  

We substitute

          \(\frac{8}{3} y_o = v_{ox} \sqrt{\frac{2y_o}{g} }\)  

          \(v_{ox} = \frac{8}{3} \sqrt{\frac{y_o g}{2} }\)  

The vertical speed when reaching the ground is:

         \(v_y = v_{oy} - g t \\v_y = - g t \\v_y = - g \sqrt{\frac{2y_o}{g} }\)

Let's use trigonometry for the direction at the point of hitting the ground.

         tan θ = \(\frac{v_y}{v_x}\)  

          θ = tan⁻¹ ( \(- \frac{3}{8} \ \frac{\sqrt{2y_o/g}}{\sqrt{y_o g /2} }\) )

          θ = tan⁻¹ ( \(tan ^{-1} (- \frac{3}{8} \sqrt{4} )= tan^{-1 } \ (- \frac{3}{4} )\)

          θ = -36.9º

The negative sign indicates that the angle is clockwise from the x-axis.

In conclusion, using the projectile launch we can find the correct answer for the question about the direction of the bullet when it hits the ground is:

      D) θ = 37º measured clockwise from the x-axis.

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Kinetic energy is the energy that an entity has as a result of its movement. If we want to accelerate an object, we must impart power to it. Using power needs us to put in effort.

In physics, an object's kinetic energy is the type of energy it has as a result of its velocity.  It is described as the amount of effort required to propel an entity of a given mass from rest to a given velocity. The body retains its kinetic energy after gaining it during acceleration unless its pace alters. The body does the same amount of effort when slowing down from its present speed to rest.

A kinetic energy is any term in a system's Lagrangian that contains a time component, as well as the second term in a Taylor expansion of a particle's relativistic energy.

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a. The energy diagrams when the ball is just thrown into the air and when it reaches maximum height is attached below.

b. The initial kinetic energy of the ball is 19.96 J.

c. The total energy of the ball at any time during its flight is the sum of its kinetic and potential energy.

d. The potential energy of the ball at the maximum height is 23.67 J.

e. The acceleration due to gravity on this planet is approximately 6.49 m/s²

Law of conservation of energy is the physical principle that the energy of interacting bodies or particles in a closed system remains constant. The kinetic energy that an object loses as it moves upward against gravity is converted into potential or stored energy, which is converted into kinetic energy as the object accelerates as it returns to Earth.

a. Here are two energy diagrams:

Initial state: The ball is thrown with a speed of 23 m/s from ground level. At this point, it has only kinetic energy.

Maximum height: The ball reaches a maximum height of 32 m, where it has zero kinetic energy and maximum potential energy.

b. The initial kinetic energy of the ball can be calculated using the formula:

KE = 0.5 × m × v²

Where m is the mass of the ball (0.0755 kg) and v is initial velocity (23 m/s). Plugging in the values, we get:

KE = 0.5 × 0.0755 kg × (23 m/s)²

KE = 19.96 J

c. The total energy of the ball at any time during its flight is the sum of its kinetic and potential energy.

Total Energy = Kinetic Energy + Potential Energy

d. At the maximum height, the ball has zero kinetic energy and maximum potential energy. The potential energy of the ball can be calculated using the formula:

PE = m × g × h

where m is the mass of the ball, g is the acceleration due to gravity on the planet, and h is the height of the ball. We are given that the ball reaches a maximum height of 32 m, so we can plug in the values to get:

PE = 0.0755 kg × 9.8 m/s² × 32 m

PE = 23.67 J

e. To determine how strong gravity is on this planet, we can use the formula for the maximum height of a projectile:

h = (v² × sin²θ) / (2 × g)

where v is the initial velocity, theta is the angle of projection (which we don't know), h is the maximum height, and g is the acceleration due to gravity on the planet (which we want to find).

Since we don't know the angle of projection, we can assume that the ball was thrown at a 45-degree angle, which will give us the maximum height for a given initial velocity. Plugging in the values, we get:

32 m = (23 m/s)² × sin²(45) / (2 × g)

Simplifying, we get:

g = (23 m/s)² × sin²(45) / (2 × 32 m)

g = 6.49 m/s²

So the acceleration due to gravity on this planet is approximately 6.49 m/s²

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Answer:

A. 9.31 x10^10J

B. -8.47x10 ^ 12J

C. 8.38x 10^12J

Explanation:

See attached file pls

Velocity = 14 m/s

Time = 20 s

Displacement = Velocity×Time = (14×20) m = 280 m

The displacement is 280 m towards the direction of motion.

Answer:280m

Explanation:

The work is done by the force pushing the mower is determined as 500 J.

The work done by the force is calculated as follows;

W = Fsinθ x d

where;

W = Fx(d)

W = 25 x 20

W = 500 J

Thus, the work is done by the force pushing the mower is determined as 500 J.

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Answer:

0.96 g/mL

Explanation:

The volume of 800 g of water is:

(800 g) / (1 g/mL) = 800 mL

The volume of 160 g of alcohol is:

(160 g) / (0.8 g/mL) = 200 mL

Density = mass / volume

ρ = (800 g + 160 g) / (800 mL + 200 mL)

ρ = 0.96 g/mL

Explanation:

i think it's more of a molecule, combination of atoms to form the simplest part of a substance, likewise a sandwich is the combination of bread and vegs to form a whole appetizer, in ratios, so it'll probably be more of a molecule than an atom

Molecule because, the combination of bread and veggies make it more likely to be a molecule.

Molecular function refers to processes that take place at the molecular level, such as catalysis or binding. GO molecular function words do not describe the location, timing, or context of an action; rather, they indicate activities rather than the objects (molecules or complexes) that carry them out.

One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Biological molecules like DNA and proteins can include thousands of atoms.

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77 degrees is the hiker's resultant displacement.

A resultant displacement is produced when displacement vectors are added. However, as long as two vectors have the same vector amount, any two vectors can be added. A resultant velocity is produced when two or more velocity vectors are added. A resultant force is created when two or more force vectors are joined together.

When specifying your initial and ultimate locations using units of distance, apply the resultant displacement calculation. S = √x²+y² is the displacement formula that results. For displacement, use the letter "S." The object is moving in two directions at once: X in the first direction and Y in the second. Y = 0 if your object only moves in one direction.

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Answer:

lucky mauld mauldgomary was an british poet...

Answer:

a

Explanation:

angle of incidence equals angle of reflection on flat surface

Answer:

40 degress

Explanation:

Answer:

Total work done  =force X displacement                      = 15 N X 2.5 m       [ given  F=15 N & d=2.5 m]                W   = 37.5 joules

Explanation:

this is just what i was able to find

The velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

The given parameters;

The resultant vertical velocity of the boat is calculated as;

\(v_y = 8 \ - \ 5 sin(30)\\\\v_y = 8 - 2.5\\\\v_y = 5.5 \ km/h\)

The resultant horizontal velocity of the boat is calculated as;

\(v_x = -2 \ + 5cos(30)\\\\v_x = 2.33 \ km/h\)

The resultant boat velocity is calculated as follows;

\(v = \sqrt{v_x^2 + v_y^2} \\\\v = \sqrt{2.33^2 + 5.5^2} \\\\v = 5.97 \ km/h\)

The direction of the velocity;

\(\theta = tan^{-1} (\frac{v_y}{v_x} )\\\\\theta = tan^{-1}(\frac{5.5}{2.33} )\\\\\theta = 67 \ ^0\)

Thus, the velocity of the boat moving at the given conditions is 5.97 km/h at 67⁰.

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Answer:A road sign gives drivers informaton about traffic on busy highways. One sign shows 15 miles in 20 minutes. What is this speed in miles per hour?

Explanation:

(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

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Answer You need to consider that the gravity on earth is 9.8 m/s/s. This means any object you let go on the earths surface will gain 9.8 m/s of speed every second. You need to apply a force on the object in the opposite direction to avoid this acceleration. If you are pushing something up at a constant speed, you are just resisting earths acceleration. The more massive and object is, the greater force is needed to accelerate it. The equation is Force = mass*acceleration. So for a 2kg object in a 9.8 m/s/s gravity you need 2kg*9.8m/s/s = 19.6 Newtons to counteract gravity. Work or energy = force * distance. So to push with 19.6 N over a distance of 2 meters = 19.6 N*2 m = 39.2 Joules of energy. There is an equation that puts together those two equations I just used and it is E = mgh

The amount of Energy to lift an object is (mass) * (acceleration due to gravity) * (height)

:Hence, the Work done to life the mass of 2 kg to a height of 10 m is 196 J. Hope it helps❤️❤️❤️

Explanation:

In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.

The period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,

Period of oscillation = 1.80s.

From here, finding the frequency is simple as, Frequency = 1/Period. Hence,

Frequency = 1/1.80

= 0.555 Hz (3 sf).

The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.

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The reflective surface of a concave mirror is curved inward and away from the light source. Concave mirrors focus light inward to a single focal point.

picture B correctly shows the path of the reflected light ray given an object inside the focal point.

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The gravitational potential energy added when the velociraptor and cage is lifted from the ground to a height of 9 m is approximately 15,998.95 joules.

What is Potential Energy?

Potential energy is a form of energy that is stored in an object due to its position or configuration in a system. It is the energy that an object has the potential to possess, or the ability to do work, as a result of its position or state.

The gravitational potential energy (GPE) added when the velociraptor and cage is lifted from the ground to a height of 9 m can be calculated using the formula:

GPE = mgh

Where m is the mass of the velociraptor and cage, g is the acceleration due to gravity (approximately 9.81 m/\(s^{2}\)), and h is the height lifted.

Given that the mass of the velociraptor and cage together is 175 kg, and the height lifted is 9 m, we can substitute these values into the formula:

GPE = mgh

GPE = (175 kg) x (9.81 m/\(s^{2}\)) x (9 m)

GPE = 15,998.95 J (joules)

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Answer:

what

Explanation: