An object accelerates from rest to a velocity of 34 m/s
over a distance of 70 m. What was its acceleration?
Answer:
6.8m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 34m/s
Distance = 70m
Unknown:
To solve this problem we apply one of the motion equations;
V² = U² + 2aS
where V is the final velocity
U is the initial velocity
a is the acceleration
S is the distance covered
Input the parameters and solve;
34² = 0² + 2 x a x 70
34² = 140a
a = 6.8m/s²
A bumper of a new car is being tested. The 2300 kg vehicle, moving at 15 m/s is allowed to collide with the bumper and comes to rest after 0.54 seconds. What is the average force acting on the bumper during impact?
force=mass x acceleration
acceleration= velocity/time
given that m=2300kg
v = 15m/s
t = 0.54s
f= 2300 x 15/0.54
f =2300×27.777
f=63888.89
A chemist is studying an unknown substance and could break the substance into its elemental components only by using chemical means. Based on this observation, how should the unknown substance be classified?
A. impure substance
B. solution
C. mixture
D. pure substance
The answer is D
I took the quiz lol
A swing held up by someone at one side has the potential to swing when released.
True
False
Which of the following electromagnetic radiations have the smallest wavelength?A) Ultraviolet wavesB) X-rays C) Gamma raysD) Microwaves
Gamma rays have the smallest wavelength among the given options. So the correct option is C) Gamma rays.
Electromagnetic radiation is characterized by varying wavelengths. The electromagnetic spectrum spans a range of radiations, from longer wavelengths like radio waves to shorter wavelengths like gamma rays. Among the options provided, gamma rays have the smallest wavelength.
Gamma rays possess the smallest wavelength among the given electromagnetic radiations. Gamma rays have extremely short wavelengths, which are even shorter than X-rays and ultraviolet waves. They are highly energetic and are produced through various processes, such as radioactive decay or nuclear reactions. Gamma rays are used in various fields, including medicine (e.g., radiation therapy) and industry (e.g., sterilization), due to their ability to penetrate materials and interact with matter at the atomic level.
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Please ans fast I will mark brainliest
Answer:
Electrical energy; chemical energy.
Explanation:
Energy can be defined as the ability (capacity) to do work. The various forms of energy are solar energy, electrical energy, chemical energy, thermal energy, wind energy, nuclear energy etc.
In this scenario, electrical energy is present in the charger and the cable while we have chemical energy in the battery of the mobile phone.
The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.
This ultimately implies that, the electrical energy in the charger and cable is used to charge the battery of the mobile phone as chemical energy.
A chemical reaction is the only way to an
A: Element
B: Pure Substance
C: Mixture
D: Solution
Answer:
B: Pure Substance
Explanation:
At some time during the motion of a particle, the acceleration vector (its "tail" is
attached to the "velocity vector’s tip") makes an angle of 45° relative to the direction of the
velocity vector.
(a) In the "next instant of time" (Δis very small), the particle will move:
A. In a curved path (not a straight line) with constant speed.
B. In a straight line with decreasing speed.
C. In a curved path (not a straight line) with increasing speed.
(b) Sometime later during the motion of the particle, the acceleration vector makes an angle of
90° relative to the direction of the velocity vector. In the "next instant of time" (Δis very
small), the particle will move:
A. In a circular path with constant speed.
B. In a curved path (not a straight line) with decreasing speed.
C. In a straight line with increasing speed.
(c) After one minute (60 seconds) of motion from its start, the toy car battery "goes dead" (it
lost all of its electrical power), and the toy truck comes to a stop 10 seconds later because of
friction in the wheels.
How fast (speed) was the toy truck moving at the moment the battery lost its power?
A. 210 m/s
B. 0.11 m/s
C. 3.8 × 105 m/s
(d) What is the magnitude of the acceleration (deceleration) of the toy truck to bring it to a stop
after the battery "goes dead?" Assume that this acceleration (deceleration) is constant.
A. 0.34 m ⁄s2
B. 9.8 m ⁄s2
C. 21 m ⁄s2
(a) In the next instant of time, the particle will move in a curved path with increasing speed when the acceleration vector makes an angle of 45° relative to the velocity vector.
(b) In the next instant of time, the particle will move in a straight line with increasing speed when the acceleration vector makes an angle of 90° relative to the velocity vector.
(c) The speed of the truck, when the battery lost its power, was 0 m/s.
(d) The magnitude of the acceleration to bring the toy truck to a stop after the battery goes dead is 0 m/s².
(a) In the "next instant of time" (Δ is very small), the particle will move in a curved path (not a straight line) with increasing speed when the acceleration vector makes an angle of 45° relative to the direction of the velocity vector.
(b) Sometime later during the motion of the particle, the acceleration vector makes an angle of 90° relative to the direction of the velocity vector.
In the "next instant of time" (Δ is very small), the particle will move in a straight line with increasing speed when the acceleration vector makes an angle of 90° relative to the direction of the velocity vector.
(c) The truck's initial velocity, u = 0
Acceleration, a = -v / t (where v is the final velocity, t is the time taken)
The truck comes to rest after 10 seconds since the battery goes dead, i.e., t = 10 s
The final velocity of the truck, v = 0
The acceleration of the truck, a = -v / t = 0 / 10 = 0 m/s²
Thus, the speed of the truck when the battery lost its power was 0 m/s.
(d) The initial velocity, u = 0
The final velocity, v = 0
The time taken, t = 10 s
The acceleration of the truck,
a = (v - u) / t = (0 - 0) / 10 = 0 m/s²
Thus, the magnitude of the acceleration (deceleration) of the toy truck to bring it to a stop after the battery "goes dead" is 0 m/s².
Answer: B. 9.8 m ⁄s².
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In general, which type of marketing do you think is most effective for events: push or pull marketing?
Discuss how an event’s ability to help us escape from everyday life and worries can be advantageous for marketers. What should a company or organization do to minimize any negative buzz surrounding its event?
How effective do you think social media is about getting the word out and creating buzz for an event? Explain. Do you think encouraging people to engage on social media networks while at an event detracts from the event itself? Why or why not?
In general, pull marketing is often considered more effective for events as it focuses on attracting and engaging the target audience through various channels.
Pull marketing strategies aim to create demand and attract the audience towards the event by providing compelling information, building excitement, and leveraging the event's unique value propositions. This can be achieved through tactics such as social media campaigns, content marketing, influencer partnerships, and targeted advertising. By generating interest and curiosity, pull marketing encourages individuals to actively seek out information about the event and participate.
Events have the advantage of offering an escape from everyday life and worries. Marketers can leverage this by emphasizing the event's ability to provide entertainment, relaxation, inspiration, or educational experiences. Highlighting these benefits helps create a positive perception and makes the event more enticing to potential attendees.
To minimize negative buzz surrounding an event, a company or organization should ensure effective communication, clear expectations, and proper management. Transparent and timely information, addressing concerns proactively, and delivering on promised experiences are crucial. Additionally, actively monitoring and responding to feedback, providing exceptional customer service, and implementing appropriate contingency plans can help mitigate potential issues.
Social media is highly effective in getting the word out and creating buzz for an event. It allows marketers to reach a wide audience, engage with potential attendees, and generate excitement through content sharing, event announcements, behind-the-scenes sneak peeks, and interactive discussions. Social media platforms enable real-time updates, user-generated content, and word-of-mouth promotion, enhancing the event's visibility and reach.
Encouraging people to engage on social media networks while at an event can enhance the overall experience rather than detracting from it. It provides attendees with opportunities to share their experiences, connect with others, and extend the event's reach through user-generated content. When properly executed, social media engagement can enhance attendee satisfaction, foster a sense of community, and amplify the event's impact beyond its physical boundaries.
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Consider three notes: A 123 Hz; B 721 Hz; and C 458 Hz.
Rank them from highest to lowest for frequency.
The frequency of a note corresponds to its pitch. The higher the frequency of a sound wave, the higher the pitch. Conversely, the lower the frequency, the lower the pitch.Notes A, B, and C can be ranked in order from highest to lowest frequency as follows:B 721 HzA 123 HzC 458 Hz
The frequency of a note is a measure of the number of cycles of vibration per second that a sound wave generates. This measurement is made in Hertz (Hz).The A note in a typical orchestra or band has a frequency of 440 Hz. In other words, when the A note is played, the sound wave created by the instrument vibrates 440 times per second, producing a tone of 440 Hz. This is considered the standard for tuning musical instruments. The rest of the notes are then tuned based on this frequency.Notes A, B, and C can be ranked in order from highest to lowest frequency as follows:B 721 HzA 123 HzC 458 Hz
The notes can be ranked from highest to lowest frequency by evaluating the Hertz (Hz) value of each note. B has the highest frequency at 721 Hz, followed by C at 458 Hz, and A has the lowest frequency at 123 Hz.
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Pls help pls !!
a raw potato was found to have a mass of 330 g. the potato was sliced and the slices or set an a single layer on a piece of screen wire to dry in the sun. the potato was measured after 7, 14, in 21 days and found to be at 212 g, 148 g, and 126 g.
what is the total mass of the potato likely to be on day 23?
then determine when the potatoes mass was 170 g
and finally what was the total mass of the potato slices after 3 days of drying time
The total mass of the potato slices after 3 days of drying time is approximately 304.71 grams.
The total mass of the potato on day 23 can be estimated by observing the trend in mass reduction over time.
From the given data, we can see that the mass of the potato decreased by 118 grams in the first 14 days (from 330 g to 212 g), and then by 64 grams in the next 7 days (from 212 g to 148 g). Therefore, we can assume that the mass reduction rate is constant.
To find the mass on day 23, we can calculate the mass reduction rate per day:
Mass reduction rate = (330 g - 212 g) / 14 days = 118 g / 14 days = 8.43 g/day
So, the mass on day 23 would be:
Mass on day 23 = 148 g - (8.43 g/day * 9 days) = 148 g - 75.87 g = 72.13 g
The estimated total mass of the potato on day 23 is approximately 72.13 grams.
To determine when the mass was 170 g, we need to find the number of days it took to reach that mass.
Mass reduction rate = (330 g - 170 g) / n days
Solving for n:
(330 g - 170 g) / n days = 8.43 g/day
160 g / n days = 8.43 g/day
n = 160 g / 8.43 g/day
n ≈ 19 days
Therefore, the mass of the potato was 170 g on day 19.
Finally, to find the total mass of the potato slices after 3 days of drying time, we can use the mass reduction rate:
Mass on day 3 = 330 g - (8.43 g/day * 3 days) = 330 g - 25.29 g = 304.71 g
The total mass of the potato slices after 3 days of drying time is approximately 304.71 grams.
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Hi I don’t understand question and can really use some help! :D
Given
Mass of one of the object is doubled and the distance between the object is doubled.
To find
What happens to the gravitational force
Explanation
The gravitational force is directly proportional to the masses and inversely proportional to the distance between them
Keeping all other parameters constant,
\(F\propto\frac{m}{d^2}\)So when the mass doubles and the distance doubles we have,
\(\begin{gathered} F^{\prime}\propto\frac{2m}{(2d)^2} \\ \Rightarrow F\propto\frac{m}{2d}=\frac{F}{2} \end{gathered}\)Conclusion
A. The gravitational force becomes half as great.
How many grams are in 268.0 mg
0.268 because grams are 1000 times bigger than mg
1 milligram = 0.001 grams
268.0mg * 0.001g
\(=\fbox{0.268 grams}\)
When the large forces are 12 N and the small forces are 4n and what is the total net force?
When the large forces are 12 N and the small forces are 4n then the total net force is 16 newtons.
What is the total net force?The net force is the resultant of all the forces; it is the result of adding all the forces together the greater the net force acting on the object, the greater its acceleration will be. Newton's second law of motion summarizes these relationships. The equation for net force can be written as
Net Force = F1 + F2 + F3…. + FN.
The net force is zero Newtons. All the separate forces balance with each other. Suppose you and your friends A and B are together pushing the cupboard from the same direction. Force applied by you is 5N, and your friend's A and B apply the force of 6N and 5N, respectively so the total force will be 11 newtons.
so we can conclude that When the large forces are 12 N and the small forces are 4n then the total net force is 16 newtons.
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astronomers believe that early galaxies grew from the repeated mergers of smaller gas clouds. if this idea is true, then the properties of galaxies must have changed over time. determine whether each property below increases or decreases over time, and then sort each property into the appropriate bin.
According to the idea that early galaxies grew from the repeated mergers of smaller gas clouds, the properties of galaxies must have changed over time. The properties of galaxies that could have changed over time to the include size, mass, luminosity, and metallicity.
As gas clouds merge, they add to the overall mass of the galaxy, which can lead to an increase in size. Additionally, the increased mass can lead to an increase in luminosity, as there are more stars being formed. However, the metallicity of the galaxy may decrease over time, as smaller gas clouds tend to have lower metallicities than larger gas clouds. This means that as the smaller gas clouds merge and contribute to the overall metallicity of the galaxy, the average metallicity may decrease.
As smaller gas clouds merge, more stars are formed, causing the overall stellar mass of the galaxy to increase. As the available gas in the galaxies is used up over time to form stars, the star formation rate decreases. As stars evolve and die, they produce and release metals into the interstellar medium, which in turn increases the metallicity of the galaxy. The repeated mergers of smaller gas clouds cause galaxies to grow in size as they accumulate more mass and stars. the properties of galaxies change over time due to repeated mergers of smaller gas clouds: stellar mass and metallicity increase, while star formation rate decreases, and the size of galaxies increases.
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A 12-kilogram mass has a kinetic energy of 150 joules. The speed of the object is
A.25.0 B.12.5 c.3.55 D.5.00
Answer:
OPTION D 5 m/s
Explanation:
0.5 × 12 × v² = 150
sqrt(150/6) = v
v = 5 m/s
A plane moves at a certain velocity then accelerates at the rate of 52 m/s2 for a distance of 2300 m to reach a velocity of 620 m/s. How fast was the plane going before it began to accelerate?
What do you hope to learn from participating in the activity you selected?
Answer:
I hope to learn the basic moves and stances of boxing. I understand that I won't be boxing with another person, but that’s OK. These exercises seem like a good starting point. I really want to understand how to put together combinations. I’ve seen professional boxers throw combinations on TV, but their hands move so quickly that I can’t catch the finer details of the sport. Maybe this will be an opportunity for me to find out more.
Explanation:
I NEED HELP AS SOON AS POSSIBLE PLEASEEE!!
DO NOT ANSWER IF YOU DON'T KNOW IT PLEASE!
Use The Kinetic Theory To Explain:
•Boyle's Law
•Charles' Law
•Pressure Law
Answer:
Kinetic theory is based on the kinetic energy of moving particles. In Boyle's Law the temperature is helped constant, so the kinetic energy of the molecules is a constant. The pressure and the volume are inversely related in Boyle's Law. In Kinetic theory pressure is created by the collision of particles.
plz mark me as brainly
Explanation:
A red sled slides across a sheet of ice toward a stationary green sled. The two sleds collide and continue sliding together.
After the collision, what is true about the velocity of the two sleds?
If a red sled slides across a sheet of ice and collides to a stationary green sled and continue sliding together, the velocity of the two sleds will be equal.
This type of collision is called as inelastic collision. In this type of collision, the two objects that undergo collision will move a single object after collision. So they cannot have different velocities.
According to law of conservation of momentum,
m1u1+ m2u2 = m1v1 + m2v2
In inelastic collision,
v1 = v2 = v
m1u1+ m2u2 = ( m1 + m2 ) v
Therefore, the velocity of the two sleds will be equal.
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What happens when an object experiences friction?
A. Friction changes mechanical energy to heat energy
B. Friction changes mechanical energy to electrical energy.
C. Friction changes mechanical energy to pizza.
D. Friction changes mechanical energy to light energy
Answer:
its A. because since heat energy means thermal i think it is A and also When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy.
Explanation: your welcome and i hope its right
50cm long copper wire carries 5A current directed towards negative z-axis placed in a region if magneti field of strength 15T applied into the page the magnetic force will be?
Answer:
Your answer is 37.5 N
Explanation:
Force, F = BIL
F = 15 x 5 x 0.5 = 37.5 N
Lifestyle practice that can improve your quality of life
Explanation:
And keep changing gradually.
Eat a variety of foods. ...
Base your diet on plenty of foods rich in carbohydrates. ...
Replace saturated with unsaturated fat. ...
Enjoy plenty of fruits and vegetables. ...
Reduce salt and sugar intake. ...
Eat regularly, control the portion size. ...
Drink plenty of fluids. ...
Maintain a healthy body weight
Date:
Page:
# Excercise.
7.
A very short answer questions.
what is acceleration due to gravity? what is
value of 'g’ on equatorial region and
polar region of the earth?
the
Answer:
See the answer below
Explanation:
Acceleration due to gravity (g) is the accelerational force experienced by a body as a result of the influence of the earth's gravitational force. It is a vector quantity, that is, it has both magnitude and direction.
The acceleration due to gravity is inversely proportional to the square of the radius of the earth. Hence, g at the equatorial region is slightly lesser (9.780 m/s2) than that of the polar regions (9.832 m/s2) of the earth because the earth bulges at the equator leading to a higher radius than at the poles.
A woman creates transverse waves on a rope by moving her hand up and down twice every second. The length of the rope is . If 4 waves are generated in this length, what is the velocity of the wave
The velocity of a wave can be calculated using the formula v = fλ, where v is the velocity, f is the frequency, and λ is the wavelength.
In this case, we know that the woman is creating transverse waves on a rope by moving her hand up and down twice every second, so the frequency (f) is 2 Hz. We also know that 4 waves are generated in the given length of the rope. Since a wave consists of one complete wavelength, the wavelength (λ) can be calculated by dividing the length of the rope by the number of waves.
So, the wavelength (λ) = length of the rope / number of waves = L/4.
Now we can substitute the values of f and λ into the formula to calculate the velocity (v).
v = fλ = (2 Hz) × (L/4) = L/2.
Therefore, the velocity of the wave is equal to half the length of the rope.
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A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. What is the momentum of the rocket?
A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.
According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.
A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.
We are required to determine the momentum of the rocket.
Consider the fuel-filled rocket as a system.
We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas
We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.
Therefore: Momentum of rocket = - momentum of expelled gas
The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.
Hence, the momentum of the rocket is -1500 kg m/s.
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The horizontal constricted pipe illustrated in the figure (a Venturi tube), can be used to measure flow velocities in an incompressible fluid. The ratio for the cross section areas of A2/A1 =0. 46, the difference in the pressure is Pi - P2 = dP = 27. 6 Pa, and the density of the fluid is 2. 93 kg/m. Find the speed of the fluid near the right hand end of the tube (i. E. , find v2
The speed of the fluid near the right-hand end of the tube is approximately 10.06 m/s.
What is Bernoulli's equation?Bernoulli's equation is a fundamental principle in fluid mechanics that relates the pressure, velocity, and height of a fluid in a flow. It states that for an incompressible fluid flowing in a steady state through a pipe of varying cross-sectional area, the total energy of the fluid (consisting of pressure energy, kinetic energy, and potential energy) remains constant along any streamline of the flow. Mathematically, the equation is:
P + (1/2)ρv² + ρgh = constant
To find the speed of the fluid near the right-hand end of the tube, we can use the Bernoulli's equation, which relates the pressure and velocity of a fluid in a flow:
P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²
where P1 and v1 are the pressure and velocity of the fluid at the left hand end of the tube (where the pipe is wider), and P2 and v2 are the pressure and velocity at the right-hand end (where the pipe is narrower).
We can redo this equation to solve for v₂:
v₂ = sqrt(2*(P₁-P₂)/ρ + v₁²)
where sqrt denotes the square root.
Using the given values:
A₂/A₁ = 0.46
dP = 27.6 Pa
ρ = 2.93 kg/m³
We can find the pressure at the left hand end using the fact that the pressure is the same at the same height, and the fluid is incompressible, so its density is constant:
P₁ = P₂ + dP = P₂ + 27.6 Pa
The area ratio gives us:
A₂ = 0.46*A₁
Now we need to find v₁. We can use the continuity equation, which states that the mass flow rate (ρAv) is constant in an incompressible fluid:
ρ₁A₁v₁ = ρ₂A₂v₂
where ρ1 is the density of the fluid at the left hand end, which is the same as ρ₂, and A₁ and A₂ are the pipe's cross-sectional areas at the left and right ends, respectively.
Substituting A₂ = 0.46 × A₁ and simplifying, we get:
v₁ = (0.46)² × v₂
Substituting this into the Bernoulli's equation, we get:
P₁ + (1/2)ρv₁² = P₂ + (1/2)ρv₂²
Substituting P₁ = P₂ + 27.6 Pa and v₁ = (0.46)² × v₂, and solving for v₂, we get:
v₂ = √((227.6)/(0.46^2ρ) + (0.46)⁴ × v₂²/ρ)
Simplifying this equation, we get:
v₂= √((227.6)/(0.46^2ρ × (1-0.46⁴)))
Substituting the given values, we get:
v₂ = √((227.6)/(0.46²²°⁹³ × (1-0.46⁴))) = 10.06m/s
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one significant method for assessing body fat distribution is measurement of ______ circumference.
One significant method for assessing body fat distribution is measurement of waist circumference.
Waist circumference is a widely used method for assessing body fat distribution and is an important indicator of central obesity. It involves measuring the circumference of the waist at a specific anatomical landmark, typically at the level of the narrowest point between the ribs and the iliac crest.
The measurement of waist circumference provides valuable information about the distribution of body fat. Excess fat accumulation in the abdominal region, also known as central obesity or android obesity, is associated with a higher risk of various health conditions, including cardiovascular diseases, type 2 diabetes, and metabolic syndrome.
By measuring waist circumference, healthcare professionals can evaluate an individual's body fat distribution and assess their risk for developing obesity-related health problems.
The measurement of waist circumference is relatively simple and non-invasive, making it a practical method for assessing body fat distribution in clinical and research settings. It is often used in conjunction with other anthropometric measurements, such as body mass index (BMI), to provide a comprehensive evaluation of an individual's body composition and health status.
Regular monitoring of waist circumference can help track changes in body fat distribution over time and guide interventions aimed at reducing central obesity and improving overall health.
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Which projectile will be visibly affected
Answer:
leaf and a balloon is the correct answer
8. In the rope climb, an athlete (weight −875.6 N ) climbs a vertical distance of 6.8 m in 11 s. What minimum power ( in hp ) was used to accomplish this feat ? Hint: Fg=mg; Ihp-746 W; P=W/t;W=mgh;g=9.8 m/s2 a) 0.90 b) 0.52 c)1.2 d) 0.72 c) None of these is true
Using the formula P = W/t, where W is the work done and t is the time taken, we can substitute the values and calculate the power. Converting the power from watts to horsepower (1 hp = 746 W), we find that the minimum power used is 0.90 hp.
To calculate the power used to climb the rope, we need to determine the work done and the time taken. The work done can be calculated using the formula W = mgh, where m is the mass, g is the acceleration due to gravity, and h is the vertical distance climbed.
Given the weight of the athlete (−875.6 N), we can calculate the mass by dividing the weight by the acceleration due to gravity (9.8 m/s^2). The mass is approximately -89.3 kg.
Substituting the values into the work formula, we have:
W = (−89.3 kg) × (9.8 m/s^2) × (6.8 m)
W ≈ -5414.776 J
Next, we divide the work done by the time taken to obtain the power:
P = W / t
P = -5414.776 J / 11 s
P ≈ -492.252 W
To convert the power from watts to horsepower, we divide by 746:
P_hp = -492.252 W / 746
P_hp ≈ -0.66 hp
Since power cannot be negative in this context, we take the absolute value:
P_hp ≈ 0.66 hp
Therefore, the minimum power used to climb the rope is approximately 0.66 hp.
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