A car is stopped at a traffic light. It then travels along a straight road so that its distance from the traffic light is given by x(t)=bt2−ct 3, where b=2.40ms −2 and c=0.120ms −3.The instantaneous velocity of the car at t=5.0s is?

The force acting on the electron is 1.92 x 10^-17 N.

The problem states that an electron of charge 1.6 x 10^-19 is located in a uniform electric field of 120 Vm^-1, and it asks us to determine the force acting on it.

We can use Coulomb's law, which states that the force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them. If the charges are of opposite signs, the force is attractive, while if the charges are of the same sign, the force is repulsive.

The formula for Coulomb's law is F = kq1q2/r^2, where F is the force between the charges, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between them.

Since the electron has a charge of 1.6 x 10^-19 C, and the electric field strength is 120 Vm^-1, we can use the equation F = qE to find the force acting on it.

F = qE = (1.6 x 10^-19 C)(120 Vm^-1) = 1.92 x 10^-17 N.

Therefore, the force acting on the electron is 1.92 x 10^-17 N.

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(a) The mass of water is approximately 49.65 kg. (b) The final temperature of the water vapor will be 120°C. (c) The total enthalpy change is approximately 277,956 kJ. (d) Diagram shown below.

(a) To determine the mass of the water, we need to know its density at the given conditions. The density of water changes with temperature and pressure. At 40°C and 200 kPa, the density of water is approximately 993 kg/m³.

Since we have 50 L of water, we need to convert it to cubic meters:

50 L = 0.05 m³

Now we can calculate the mass of water:

Mass = Density * Volume

Mass = 993 kg/m³ * 0.05 m³

Mass ≈ 49.65 kg

Therefore, the mass of water is approximately 49.65 kg.

(b) To find the final temperature, we need to consider the phase change from liquid to vapor. At constant pressure, the temperature will remain constant until all the liquid water has vaporized. This temperature is called the saturation temperature.

We can determine the saturation temperature at 200 kPa using a steam table or other relevant data sources. Let's assume that the saturation temperature is 120°C.

Therefore, the final temperature of the water vapor will be 120°C.

(c) To calculate the total enthalpy change, we need to consider the energy required to heat the water from its initial temperature to the saturation temperature, as well as the energy required for the phase change from liquid to vapor.

The enthalpy change during heating can be calculated using the formula:

ΔH1 = Mass * Specific Heat Capacity * ΔT1

Where:

Mass = 49.65 kg (from part a)

Specific Heat Capacity = specific heat capacity of water at constant pressure = 4.18 kJ/(kg·°C)

ΔT1 = final temperature - initial temperature = 120°C - 40°C = 80°C

ΔH1 = 49.65 kg * 4.18 kJ/(kg·°C) * 80°C

ΔH1 ≈ 165,938 kJ

The enthalpy change during phase change can be calculated using the formula:

ΔH2 = Mass * Latent Heat of Vaporization

Where:

Mass = 49.65 kg (from part a)

Latent Heat of Vaporization = energy required to vaporize 1 kg of water = 2257 kJ/kg

ΔH2 = 49.65 kg * 2257 kJ/kg

ΔH2 ≈ 112,018 kJ

The total enthalpy change is the sum of ΔH1 and ΔH2:

Total Enthalpy Change = ΔH1 + ΔH2

Total Enthalpy Change ≈ 165,938 kJ + 112,018 kJ

Total Enthalpy Change ≈ 277,956 kJ

Therefore, the total enthalpy change is approximately 277,956 kJ.

(d) The process can be shown on a T-v (temperature-volume) diagram with respect to saturation lines. In this case, the process starts at the initial temperature and pressure (40°C, 200 kPa), and moves along the constant pressure line until reaching the saturation temperature (120°C). Then, the process follows the saturation line until the entire liquid is vaporized.

Here is a simplified representation of the process on a T-v diagram:

           |

Saturation |                       |

 Line   |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

 Initial |-----------------------------| Final

           |                             |

           |                             |

           |                             |

           |                             |

           |                             |

           |                            

This diagram is a rough representation and does not accurately reflect specific volume values or scale. It simply illustrates the general process from initial conditions to the final state along the constant pressure and saturation lines.

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Please i have asked a.question please help.me

Explanation:

Please i have asked a question in math please help me

Answer:

there is no acceleration

Explanation:

acceleration only occurs when the speed changes for example if you were to start at 10m/s and after ten seconds be at 50m/s then there would be acceleration but because speed is constant there is no acceleration

(a) The work done by the 150 N force is 877.5 Joules.

(b) The coefficient of kinetic friction between the crate and the surface is approximately 0.437.

To answer this problem, we must take into account the work done by the applied force as well as the work done by friction.

(a) The applied force's work may be estimated using the following formula:

Work = Force * Distance * cos(theta)

where the force is 150 N and the distance is 5.85 m. Since the force is applied horizontally and the displacement is also horizontal, the angle theta between them is 0 degrees, and the cosine of 0 degrees is 1.

As a result, the applied force's work is:

Work = 150 N * 5.85 m * cos(0) = 877.5 J

So, the work done by the 150 N force is 877.5 Joules.

(b) Frictional work is equal to the force of friction multiplied by the distance. The work done by friction is identical in amount but opposite in direction to the work done by the applied force since the crate travels at a constant speed.

The frictional work may be estimated using the following formula:

Work = Force of Friction * Distance * cos(theta)

The net force applied on the crate is zero since it is travelling at a constant pace. As a result, the friction force must be equal to the applied force, which is 150 N.

Thus, the work done by friction is:

Work = 150 N * 5.85 m * cos(180) = -877.5 J

Since the work done by friction is negative, it indicates that the direction of the frictional force is opposite to the direction of motion.

The coefficient of kinetic friction may be calculated using the following equation:

Friction Force = Kinetic Friction Coefficient * Normal Force

The normal force equals the crate's weight, which may be computed as:

Normal Force = mass * gravity

where the mass is 35.0 kg and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal Force = 35.0 kg * 9.8 m/s^2 = 343 N

Now, we can rearrange the equation for the force of friction to solve for the coefficient of kinetic friction:

Force of Friction = coefficient of kinetic friction * Normal Force

150 N = coefficient of kinetic friction * 343 N

coefficient of kinetic friction = 150 N / 343 N ≈ 0.437

As a result, the kinetic friction coefficient between the container and the surface is roughly 0.437.

In summary, the work done by the 150 N force is 877.5 Joules, and the coefficient of kinetic friction between the crate and the surface is approximately 0.437.

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Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.

Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.

Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.

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Answer:

electron shell

Explanation:

the proton and nucleus are inside the electron shell so the arrow is point on the outer shell which is the electron shell.

Answer:

The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.

The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.

Explanation:

The Earth's magnetic field at the location has a magnitude of 5.50×10^−5 T and points into the Earth at an angle of 58.0 degrees below a line pointing due north.

What is Magnetic Field?

A magnetic field is a region of space surrounding a magnet or a current-carrying conductor in which magnetic forces are exerted on other magnetic objects or moving charged particles. Magnetic fields are characterized by their direction, magnitude, and polarity. The direction of a magnetic field is defined as the direction in which a magnetic north pole would be pulled or aligned, and is conventionally represented by magnetic field lines that form closed loops.

Based on the information provided, it seems like you have described a situation where a circular coil with a diameter of 14.0 cm and containing nine loops is lying flat on the ground.

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A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this location has magnitude 5.00×10−5T and points into the Earth at an angle of 58.0 ∘ below a line pointing due north. A 6.90-A clockwise current passes through the coil. Determine the torque on the coil, and which edge of the coil rises up: north, east, south, or west?

The degree of data stability when the measurement is replicated under identical circumstances is known as reproducibility or reliability.

Reproducibility determines how an entire study an experiment can be replicated, whereas repeatability assesses the variation in data made by a single equipment or human under similar circumstances.

Science needs reproducibility because it enables more in-depth investigation, and replication validates our findings. There are several investigations and experiments, which result in a wide range of variables, unforeseen, and things that are either outside your influence or you cannot guarantee.

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The patient eating a candy bar instead of fasting for the test should be told

that the test results will be wrong and he may receive a wrong diagnosis.

The medical practitioners told him to fast when coming for a reason and he

forgetting and eating something means the objective for the test may have

been defeated.

This is why it's best to explain to him about the consequences of his actions

which is likely getting a wrong result and diagnosis.

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With the use of formulas, the capacitance is 33500000000 nF and the charge is 301.5 Coulombs

Capacitance of a Capacitor can be defined as charge to potential difference ratio.

Given that a parallel plate capacitor having plates of area 1.3 cm2 that are separated by 0.026 mm of neoprene rubber with the assumption that the rubber has a dielectric constant κ = 6.7.

The capacitance C = kA/d where

Substitute all the parameters into the formula

C = (6.7 × 0.00013)/0.000026

C = 33.5 Farad

The charge, in coulombs when 9.00 V is applied across it will be

Q = CV

Q = 33.5 × 9

Q = 301.5 Coulombs

Therefore, the capacitance in nanofarads is 33500000000 nF and the charge, in coulombs when 9.00 V is applied across it is 301.5 Coulombs

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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Answer:

Explanation:

40 km/h

The boy weighs at about 80 kg. When, as illustrated, a N 784 guy balances the youngster on a teeter-totter.

A way to determine how much material, in mass, makes up a physical body.

In classical mechanics, an object's mass is essential to Newton's equations of motion because it affects the force required to accelerate it and, subsequently, how much inertia it has.

Language expert Peter Trudgill claims that the name "Tittermatorter" from the Norfolk language is its origin. Trudgill can trace all of his great-great-grandparents to a tiny region of eastern Norfolk.

As per the question:

Weight is come under gravity and become force

80g = mg

m = 80

Force = 80(9.8) = 784N

Thus, the answer is 784N.

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The speed at the intake is 199.89 cm/s

Since the volume flow rate, Q = Av is constant where

We have that from the continuity equation,

A₁v₁ = A₂v₂ where

So, A₁v₁ = A₂v₂

πd²v₁/4 = L²v₂

Making v₁ subject of the formula, we have

v₁ = 4L²v₂/πd²

So, substituting the values of the variables into the equation, we have

v₁ = 4L²v₂/πd²

v₁ = 4(25.06 cm)² × 100 cm/s/[π(20 cm)²]

v₁ = 4 × 628.0036 cm² × 100 cm/s/[400π cm²]

v₁ = 2512.0144 cm² × 100 cm/s/1256.6371 cm²

v₁ = 1.9989 × 100 cm/s

v₁ = 199.89 cm/s

So, the speed at the intake is 199.89 cm/s

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Answer:

i dont know

Explanation:

sorry i cant answer this question

If the potential difference across a capacitor is doubled, the energy stored in it is quadrupled.

The ability difference between any points inside the electric-powered field is defined as the quantity of labor done in transferring a unit of fantastic charge without acceleration from one point to another alongside any route among the 2 factors. The distinction in price between higher capability and lower capacity is known as a voltage or capacity distinction.

The voltage between points can be a result of the build-up of electric rate (e.g., a capacitor), and from an electromotive pressure (e.g., electromagnetic induction in generators, inductors, and transformers).On a macroscopic scale, a potential distinction can be due to electrochemical methods (e.g., cells and batteries), the stress-induced piezoelectric effect, and the thermoelectric effect.

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Answer:

When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors. When a meteoroid survives a trip through the atmosphere and hits the ground, it's called a meteorite.

Explanation:

Answer: Meteoroid: Small particle from a comet or asteroid orbiting the Sun. Meteor: The light phenomena which results from a meteoroid entering the Earth's atmosphere and vaporizing; this is basically a shooting star. Meteorite: A meteoroid that survives through the Earth's atmosphere and lands on the Earth's surface.

Answer:

[See Below]

Explanation:

✦ Formula = \(Mass / 1000\)

  ✧ \(4800 / 1000 = 4.8\)

So \(4800\) grams is equal to \(4.8\) kilograms.

~Hope this helps Mate. If you need anything feel free to message me.

Answer:

it will most likely be the free energy

Answer:

Explanation:

The work done by an object can be found by using the formula

From the question

force = 600 N

distance = 4 m

We have

work done = 600 × 4

We have the final answer as

Hope this helps you

Joule (J). This is the fundamental energy unit of the metric system, or the International System of Units in a later, more thorough version (SI).

The SI unit of energy, the joule (J), was created in honour of James Prescott Joule and his research on the mechanical equivalent of heat since energy is defined through labour. In terms of SI base units, 1 joule is equivalent to 1-newton metre and, in slightly more basic words.

Potential energy, which can be calculated using the formula P.E. = mgh. Unit is the energy that an object has stored due to its position and height. Joules is the SI unit for energy (J).

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The change in entropy of the gas is -8.14 J/K.

In thermodynamics, entropy is a measure of the system's thermal disorder or randomness, and it is related to the number of ways that a system can be arranged in a given state.

The change in entropy, ΔS, can be calculated using the equation

ΔS=qrev/T, where qrev is the amount of heat transferred reversibly and T is the temperature.

For an ideal gas, the change in entropy during a reversible isothermal process can be calculated using the following equation:

ΔS=nRln(Vf/Vi), where n is the number of moles of the gas, R is the gas constant, Vi is the initial volume of the gas, and Vf is the final volume of the gas.

To solve this problem, we can use the following steps:

Step 1: Calculate the final volume of the gas using the ideal gas law. The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of the gas, R is the gas constant, and T is the temperature. Since the process is isothermal, the temperature remains constant at 20.00C, or 293.15 K.

Therefore, we can write PV = nRT as P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume. Since the gas is compressed, the final pressure is greater than the initial pressure. We can assume that the pressure is constant throughout the compression, so we can write P = F/A, where F is the force and A is the area. Since the work done on the gas is 1850 J, we can write W = Fd, where d is the distance that the force acts over. Since the force is constant, we can write F = W/d.

Therefore, we can write P = W/(Ad). Since the area and distance are not given, we cannot calculate the pressure directly. However, we can write P1V1 = P2V2 as V2/V1 = P1/P2. Therefore, we can write V2 = V1(P1/P2). Since we cannot calculate P2 directly, we need to find a way to relate it to the work done on the gas.

Step 2: Relate the work done on the gas to the change in internal energy of the gas. The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. In this case, since the process is reversible and isothermal, the heat added to the system is equal to the work done on the system.

Therefore, we can write ΔU = q + W = W + 1850 J, where ΔU is the change in internal energy, q is the heat added to the system, and W is the work done by the system. Since the process is isothermal, the change in internal energy is zero, so we can write 0 = W + 1850 J, or W = -1850 J.

Therefore, the work done on the gas is negative, which means that the gas is doing work on its surroundings, and the change in internal energy is zero.

Step 3: Calculate the final volume of the gas. Since the change in internal energy is zero, we can write PV = nRT as P1V1 = P2V2, where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume. Since the temperature remains constant, we can write P2 = P1(W/P1V1), or P2 = P1 - (W/V1), where W is the work done on the gas, which is negative, and V1 is the initial volume of the gas.

Therefore, we can write V2 = V1(P1/P2), or V2 = V1/(1 - W/(P1V1)). Substituting the values we know, we get V2 = 4.797 L.

Step 4: Calculate the change in entropy of the gas. We can use the equation ΔS = nRln(Vf/Vi), where n is the number of moles of the gas, R is the gas constant, Vi is the initial volume of the gas, and Vf is the final volume of the gas. Substituting the values we know, we get ΔS = (3 mol)(8.314 J/mol K) ln(4.797 L/5.940 L) = -8.14 J/K.

Therefore, the change in entropy of the gas is -8.14 J/K.

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Two things that keep windows from shattering are the strength of the glass and the ability of the window frame to dampen vibrations.

The strength of the glass is important because it determines how much force the glass can withstand before it breaks. Modern windows are typically made of tempered glass, which is treated with heat to make it stronger and more resistant to shattering.

The ability of the window frame to dampen vibrations is also crucial because glass is prone to resonance, which is a phenomenon that occurs when an object is subjected to vibration at its natural frequency.

If the frequency of the vibration matches the natural frequency of the glass, the glass can begin to vibrate and eventually shatter. To prevent this, window frames are designed to be sturdy and to dampen vibrations, which helps to prevent the glass from vibrating and shattering.

In summary, both the strength of the glass and the ability of the window frame to dampen vibrations are important factors that help to prevent windows from shattering.

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It would require 28618.56 J of heat to raise the temperature of 90 g of water from 12°C to 88°C.

Given that:

Mass of water m = 90g

Initial temperature = 12°C

Final temperature = 88°C,

The amount of heat required to raise the temperature of a substance is given by:

Q = mCΔT

Where Q is the amount of heat, m is the mass of the substance, C is the specific heat capacity of the substance, and ΔT is the change in temperature.

Note that: the specific heat capacity of water is 4.184 J/g°C.

So, for raising the temperature of 90 g of water from 12°C to 88°C, we have:

Q = mCΔT

Q = (90 g) × (4.184 J/g°C) × (88°C - 12°C)

Q = (90 g) × (4.184 J/g°C) × (76°C)

Q = 28618.56 J

Therefore, the required heat is 28618.56 Joules.

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