A car suspension can undergo a maximum displacement of about an additional 6 cm from its resting position when inside a car before breaking. The mass of the car is roughly 2000kg and the car suspension has an initial displacement of 8.5 cm from its equilibrium position, while the maximum force exerted on the car in the vertical direction is an additional 1.4x104 N before the spring breaks. Determine the change in elastic potential energy of the suspension between the maximum force before the spring breaks and when no additional force is being exerted on the care beside the Earth. State all of you assumptions here explicitly.

Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 5 = 590

We have the final answer as

Hope this helps you

Psychology is defined as the study of the brain in order to understand human behaviors.

The psychology science research field is a discipline aimed at understanding human behaviors and emotions by analyzing the functioning of the brain, which is the major organ in the nerve system responsible for modulating these types of functions.

Therefore, with this data, we can see that Psychology is a specific science research field related to understanding human behaviors and feelings by analyzing how the different parts of the brain are associated with this process.

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Answer: Psychology is the organized study of behavior and the mental processes that occur with it

Explanation:

Took the K12 test

Given data:

* The electrostatic force of repulsion between the charged bodies in the initial state is,

* The distance between the charged bodies in the initial state is,

* The distance between the charged bodies in the final state is,

Solution:

According to Coulomb's law, the electrostatic force of repulsion between the charged bodies in the initial state is,

where k is the electrostatic force constant, q_1 is the charge on the first charged body and q_2 is the charge on the second charged body,

The electrostatic force of repulsion between the charged bodies in the final state is,

Substituting the known values,

Thus, the electrostatic force of repulsion between the charged bodies in the final state is,

The bullet takes 0.0025 seconds to pass through the wooden plank of 5 cm thickness when it is traveling horizontally with an initial speed of 30 m/s and a final speed of 10 m/s.

The time taken by the bullet to pass through the wooden plank can be determined using the equation of motion for constant acceleration.

Given:
Initial speed (u) = 30 m/s

Final speed (v) = 10 m/s

Distance (s) = 5 cm = 0.05 m

To find the time taken (t), we need to calculate the acceleration (a) first. We can use the equation:

v² = u² + 2as

Rearranging the equation, we have:

a = (v² - u²) / (2s)

Substituting the given values:

a = (10² - 30²) / (2 * 0.05)

Simplifying the expression:

a = (-800) / (0.1)

a = -8000 m/s²

The negative sign indicates that the acceleration is in the opposite direction of the initial velocity.

Next, we can use the equation of motion:

v = u + at

Substituting the values:

10 = 30 + (-8000) * t

Simplifying the equation:

-8000t = -20

Dividing by -8000:

t = 20 / 8000
t = 0.0025 s

Therefore, the time taken by the bullet to pass through the wooden plank of 5 cm thickness is 0.0025 seconds.


To find the time taken by the bullet to pass through the wooden plank, we need to calculate the acceleration first using the equation of motion.

By rearranging the equation and substituting the given values, we can find the acceleration.

Then, using the equation of motion again, we can solve for time.

The negative sign in the acceleration indicates that it is in the opposite direction of the initial velocity.

The resulting time is 0.0025 seconds.

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Answer:

True

Explanation:

As far as I know, constructive interference means waves are "in phase" and destructive interference means the waves are "out of phase"

Answer:

true

Explanation:

destructive interference occurs when two identical waves are superimposed exactly out of phase.

To rank the time required for the crates to return to their initial positions from largest to smallest, you first need to calculate the time taken for each crate to return to its original position. This can be done using the formula:

Once you have the time taken for each crate to return to its original position, you can rank them from largest to smallest.

Compare the values in the list and rank them from largest to smallest. The highest value in the list will be the first, followed by the second highest value, and so on.

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Answer:

A) d_o = 20.7 cm

B) h_i = 1.014 m

Explanation:

A) To solve this, we will use the lens equation formula;

1/f = 1/d_o + 1/d_i

Where;

f is focal Length = 20 cm = 0.2

d_o is object distance

d_i is image distance = 6m

1/0.2 = 1/d_o + 1/6

1/d_o = 1/0.2 - 1/6

1/d_o = 4.8333

d_o = 1/4.8333

d_o = 0.207 m

d_o = 20.7 cm

B) to solve this, we will use the magnification equation;

M = h_i/h_o = d_i/d_o

Where;

h_o = 3.5 cm = 0.035 m

d_i = 6 m

d_o = 20.7 cm = 0.207 m

Thus;

h_i = (6/0.207) × 0.035

h_i = 1.014 m

Answer:

make the child walk by itself

Explanation:

duh

Answer:

b.

Explanation:

b) Heat the solution, dissolve the solute, and let the solution cool verifying nothing settled out.

7.5 hours or 450 minutes. 15/2=7.5

For the 1.0 gram sample of the same radionuclide, the required half life will be of 7.5 hours.

Given data:

The amount of sample at initial is, a = 2.0 g.

The half-life for 2.0 g sample is,  \(t_{1/2}=15 \;\rm hr\).

In the given problem, it is a simple calculation but the concept of half life is used . The half life is defined as the a time interval required for one-half of nucleus of sample to undergo complete decay.  

In the given problem,

2.0 g of sample = 15 hours

1.0 g of sample = 15/2 hours

                         = 7.5 hours

Thus, we can conclude that for the 1.0 gram sample of the same radionuclide, the required half life will be of 7.5 hours.

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Answer:

It is hard to push the empty upside down mug inside the water as it has air present inside its cavity which prevents the water from entering inside the mug.

I hope this helps a little bit.

The new magnitude of the force of attraction will be 6 times the original force of attraction

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

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Answer:

divide the number of times the event occurs by the length of time.

Explanation:

Answer:

As the density of the liquid increases, so does the pressure. If the liquid is open to the air, there will also be atmospheric pressure on its surface.

Explanation:

Answer:

A lunar eclipse occurs when the Moon moves into the Earth's shadow. ... The only light reflected from the lunar surface has been refracted by Earth's atmosphere. This light appears reddish for the same reason that a sunset or sunrise does: the Rayleigh scattering of bluer light.

Lunar eclipses can only happen when the Moon is opposite the Sun in the sky, a monthly occurrence we know as a full Moon. But lunar eclipses do not occur every month because the Moon's orbit is tilted five degrees from Earth's orbit around the Sun. Without the tilt, lunar eclipses would occur every month.

Explanation:

Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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The type of metal solids other then aluminum foil would be able to work is Copper,Tin,Stainless steel,Brass,Nickel and Silver foils.

There are several types of metal solids that can work similarly to aluminum foil in certain applications. Some options include:

1. Copper foil: Copper foil has good electrical conductivity and is often used in electrical and electronic applications, including circuit boards and electromagnetic shielding.

2. Tin foil: Tin foil, also known as tinfoil, is a thin sheet of tin. It is commonly used for wrapping food items and has similar properties to aluminum foil.

3. Stainless steel foil: Stainless steel foil is resistant to corrosion and has high strength. It can be used for various applications, such as heat exchangers, laboratory equipment, and packaging.

4. Brass foil: Brass foil is an alloy of copper and zinc, which provides good electrical and thermal conductivity. It can be utilized in applications similar to copper foil.

5. Nickel foil: Nickel foil has excellent resistance to corrosion and high-temperature environments. It is commonly used in battery manufacturing, aerospace components, and chemical processing.

6. Silver foil: Silver foil is highly conductive and often used in specialized applications where high conductivity is required, such as in certain types of electronic circuits and sensors.

These metal foils may not be as readily available or as widely used as aluminum foil, but they can serve specific purposes depending on their unique properties. It's important to consider factors such as electrical conductivity, thermal conductivity, corrosion resistance, and cost when selecting the appropriate metal foil for a particular application.

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An infinitely long circular cylinder of radius R carries a uniform magnetization M parallel to its axis, its magnetic field = B = μ₀ × M (k)

Take the coordinate system S, where the z axis and the cylinder's axis are the same. The material has a magnetism that is equivalent to

              M  = MÎ

A bound volume current Jₐ = Δ × M = 0         [ Consider M is constant ]

[bound surface current ] Kₐ = M × n = M × r

                                                 = M × φ

The current distribution in an infinitely long solenoid is identical to this current distribution. The magnetic field outside the magnetized cylinder will also be zero because the field outside an infinitely long solenoid is zero.

Ampere's law can be used to calculate the magnetic field inside an infinitely long solenoid, which is the same as the magnetic cylinder.

φB. dl = μ₀ × I

φB. dl = μ₀  × φKₐ . dl

∴ B = μ₀ ×Kₐ

B = μ₀ × M (k)

Electric current creates a magnetic field that is more concentrated in the center of the loop than it is outside of it. Stacking various circles thinks the field considerably more into what is known as a solenoid

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Explanation:

To find the formula for the incremental change in the amount of Kool-Aid (Δx) in Lake Alpha, we need to consider

Two factors: the amount of Kool-Aid flowing out of Lake Alpha and the amount of Kool-Aid remaining in the lake.

1. The outflow rate of Kool-Aid from Lake Alpha is proportional to the concentration of Kool-Aid in the lake. Since the outflow rate of water is 400 liters per hour, the outflow rate of Kool-Aid can be calculated as:

Outflow rate of Kool-Aid = (x kg / 500,000 L) * 400 L/h
in
2. The remaining Kool-Aid in Lake Alpha decreases as it flows downstream. The rate of change of Kool-Aid in the lake with respect to time (Δx/Δt) can be determined by considering the outflow rate of Kool-Aid:

⇒ Δx/Δt = - (x kg / 500,000 L) * 400 L/h

3. Multiply both sides by Δt to isolate Δx:

⇒ Δx = - (x kg / 500,000 L) * 400 L/h * Δt

Now, you can use this formula to find the incremental change in the amount of Kool-Aid in Lake Alpha (Δx) for any given amount of Kool-Aid (x) and an incremental change in time (Δt).

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An acoustic shadow is produced by a hard reflective surface.

Acoustic shadows occur when sound waves encounter an obstacle or object that reflects or absorbs the sound. When a sound wave encounters a hard reflective surface, such as a wall or large object, it can create an area behind the object where the sound is blocked or reduced, resulting in an acoustic shadow. This phenomenon is similar to how a physical shadow is formed when light encounters an object and is blocked. In the case of sound, the object acts as a barrier, preventing sound waves from reaching certain areas.

The perceiver's head or pinna (outer ear) can influence sound perception and localization, but they do not typically produce an acoustic shadow in the same way as a hard reflective surface. Environmental objects, such as trees or buildings, can create acoustic shadows depending on their size and position in relation to the sound source and the listener. However, the primary producer of an acoustic shadow is a hard reflective surface that obstructs the path of sound waves.

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The velocity of the projectile when it lands is 71.218 m/s.

The resultant velocity of the projectile when it lands is calculated by applying the following formula.

V = √ ( Vx²  + Vy² )

where;

The given parameters include the following;

the vertical velocity of the projectile = 44 m/s

the horizontal velocity of the projectile = 56 m/s

V = √ ( Vx²  + Vy² )

V = √ ( 56²  + 44² )

V = 71.218 m/s

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Answer:

thermal decomposition reaction

Explanation:

The reaction 2KCIO₃ → 2KCI + 3O₂ is a decomposition reaction. It dissociates into its constituent elements.

Decomposition reactions involve the breakdown of a compound into two or more simpler substances. In this case, potassium chlorate (KCIO₃) decomposes into potassium chloride (KCI) and oxygen gas (O₂).

The balanced equation for the reaction is:

2KCIO₃ → 2KCI + 3O₂

This reaction is typically initiated by applying heat to KCIO₃, causing it to decompose into its constituent elements.

Therefore, The reaction 2KCIO₃ → 2KCI + 3O₂ is a decomposition reaction. It dissociates into its constituent elements.

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Answer: b the masses will hang higher

Explanation:

F=kx

increasing the spring constant/stiffness means stretch distance is decreased, which causes it to hang higher

Answer:

7.5 × 10^-11 m

Explanation:

Hope this helps !