a carnival clown rides a motorcycle down a ramp and around a vertical loop. if the loop has a radius of 18.0 m, what is the slowest speed the rider can have at the top of the loop to avoid falling?(ans:13 m/s)

Answer:

B,C,E

Explanation:

Answer:

3) using Robert Boyles's law the pressure will be 4.375 atm

4) using Charle's law the volume will be 340 Liters

5) using Charle's law the new temprature will be 43.5 °C

The amount of power required for the firefighter to run up the stairs in 60s is 28.66 watts

Power is described as the amount of energy transferred or converted per unit time.

parameters given ate

mass= 80kg

distance = 60seconds

We need to calculate the distance over which the force is applied. In this case, the firefighter is running up a 21.5m flight of stairs, so the distance is 21.5m.

Then, we calculate the amount of work required, we use the formula

Work done = Force* distance

Work done =  80kg * 21.5m = 1720 Newton

Therefore power = work done/ time

= 1720/ 60

Power = 28.66 watts

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Answer:

1) Mercury

2) Venus

3) Earth

4) Mars

Explanation:

Answer:

The for inner/terrestrial planets are Mercury, Venus, Earth and Mars

Explanation:

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Answer:

C

Explanation:

The gravitational force of the Sun increased

If  the mass of the Sun increased during the formation of the solar system, the gravitational force of the Sun increased.

A massive concentration of interstellar gas and dust formed a molecular cloud that would become the sun's birthplace before the solar system existed. Cold temperatures caused the gas to clump together, increasing its density steadily.

Gravity continued to collapse the material onto the developing solar system, resulting in the formation of a star and a disc of material from which the planets would form. According to NASA, the newborn sun eventually accounted for more than 99% of the mass of the solar system (opens in new tab).

When the pressure inside the star became so high that fusion occurred, converting hydrogen to helium, the star began to blast a stellar wind, which helped clear out debris and prevented it from falling inward.

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Answer:

Velocity is quickness of motion or action. A synonym is celerity; a simpler word is speed. In physics, velocity specifically refers to the measurement of the rate and direction of change in position of an object.pls pls mark me branilest

Answer:

Velocity is defined as displacement travelled per unit time in a fixed direction. It is a vector quantity as it has both magnitude and fixed direction.

Please mark me brainliest.

The platy or sheet-like form that foliated rocks develop serves as a representation of the direction of pressure application. A few examples of rocks with foliated metamorphosed tectonic plates are slate, sandstone, and granite.

Foliated metamorphic rock must grow in a directed force or shear stress environment. When pressure is applied to a parent rock during recrystallization, the platy or extended minerals inside the parent rock become aligned or foliated. The platy and paper structure that foliated rocks take on is a representation of the direction in which pressure is applied. Tectonic plates that were foliated during metamorphism produced the rock types slate, schist, and gneiss. The many different types of foliated metamorphic rocks are classified by grade or quantity of metamorphic rocks, and the type includes slate, phyllite, schist, and gneiss.

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The platy or sheet-like form that foliated rocks develop serves as a representation of the direction of pressure application. A few examples of rocks with foliated metamorphosed tectonic plates are slate, sandstone, and granite.

Foliated metamorphic rock must grow in a directed force or shear stress environment. When pressure is applied to a parent rock during recrystallization, the platy or extended minerals inside the parent rock become aligned or foliated.

The platy and paper structure that foliated rocks take on is a representation of the direction in which pressure is applied. Tectonic plates that were foliated during metamorphism produced the rock types slate, schist, and gneiss. The many different types of foliated metamorphic rocks are classified by grade or quantity of metamorphic rocks, and the type includes slate, phyllite, schist, and gneiss.

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Answer:

Josie's ball faster than T

Given that the angular speed of the 27-inch-diameter tire is 5π radians per second. We need to find out the speed at which the cyclist is traveling.

The formula that relates angular speed, linear speed and radius of rotation is given as:v = rωwhere,v is the linear speed,ω is the angular speed andr is the radius of rotation.Since the diameter of the tire is 27 inches, the radius is 27/2 = 13.5 inches = 1.125 feet.Substituting the values in the above formula,v = rωv = (1.125) × (5π)v = 5.625π

The speed at which the cyclist is traveling when his 27-inch-diameter tires are rotating at an angular speed of 5π radians per second is 5.625π feet per second.

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Answer:

the new resister is 11 ohms.

Explanation:

Set it  up like this.

1/x + 1/1.1 = 1                    Subtract 1/1.1 from both sides

1/x = 1 - 1/1.1

1 - 1/1.1 = 1/11

1/x = 1/11                          Cross multiply

11 = x

If 1/11 bothers you, you could do it it another way.

1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1  Multiply top and bottom by 10

0.1*10/(1.1 * 10 ) = 1 / 11

Area, shape, distance, and direction are considered to be the four main properties of maps.

Area refers to the accurate representation of the size of geographic features on the map. Shape refers to the accurate representation of the shape of geographic features on the map. Distance refers to the accurate representation of the distance between geographic features on the map. Finally, direction refers to the accurate representation of the direction of geographic features on the map. These four properties are crucial in creating maps that are useful and accurate representations of the real world.

Additionally, it is important to note that maps can vary in their emphasis on these properties depending on their purpose and the needs of the user. For example, a map used for navigation would place more emphasis on the accurate representation of distance and direction, while a map used for land use planning would place more emphasis on the accurate representation of area and shape.

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Wendy riding her bike in a circle in the parking lot is a change in direction, but her speed is constant, so her velocity is not changing. Amber sitting on a park bench and Jessica walking her dog along Chestnut Avenue are both stationary, so there is no change in velocity.

What is Velocity?

It is defined as the change in position of an object over a unit of time, usually measured in meters per second (m/s) or kilometers per hour (km/h), in a specific direction.

In physics, velocity is distinguished from speed, which is the magnitude of an object's velocity but without regard to its direction. Velocity is a more precise term than speed because it includes both magnitude and direction. For example, a car traveling at 60 km/h east has a different velocity than a car traveling at 60 km/h west.

Velocity is a fundamental concept in many areas of physics, including mechanics, thermodynamics, and electromagnetism. It is used to describe the motion of objects ranging from subatomic particles to celestial bodies in the universe.

The only option that shows a change in velocity is Ken driving on Interstate 4 at 65 mph. This is because velocity is a vector quantity that includes both speed and direction. As Ken is driving, he is changing his direction or speed, or both, which means his velocity is changing.

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Answer:

Water ;)

Explanation:

have a great rest of your day :)

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

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Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.

The capacity or power to do work, such as the capacity to move an object by application of force is called energy.

Initial potential energy of compressed spring is:

Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J

k is spring constant, x is compression of the spring, and J is unit of energy in joules.

Final potential energy of the bricks is:

Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J

Ep = Ep

1/2 kx^2 = mgh

v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s

Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.

c.  Initial potential energy of compressed spring is: 1000 J

Ek = Ep = 1000 J

Kinetic energy of the bricks is given by:

Ek = 1/2 mv^2

1000 J = 1/2 * 100 N * v^2

v = sqrt(200 / 1) = 14.14 m/s

Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.

d.  As, Ep = m g h

where m is mass of the bricks, g is acceleration due to gravity, and h is  height of the hill.

Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J

Ep = 1/2 kx^2 = 1962 J

1/2 * 500 N/m * x^2 = 1962 J

x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m

Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.

e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,

0.85 * 1000 J = 1/2 mv^2

v = sqrt(170 / 1) = 13.04 m/s

Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.

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Answer:

Explanation:

In this problem, we are going to solve for the average speed and average velocity for the entrire trip made by the dolphin.

Given data

speed v= 2 m/s

time t= 24s

the distance travelled by the dolphin is

speed= distance/time

distance= speed*time

distance= 2*24

distance= 48m

now the dolpine made a reverse and covered this 48m in 8s to return to it initial position

the speed it took is

speed= distance/time

speed= 48/8

speed= 6m/s

It average speed is the total distance divided by the total time taken

average speed= (48+48)/(24+8)= 96/32= 3m/s

average speed= 3 m/s

it average velocity is the sum of the initial and final velocity is divided by 2 to find the average

(2+6)/2= 8/2= 4m/s

average velocity is 4m/s

At a particular instant, a free-falling object has a speed of 30 m/s. exactly 1 s later its speed will be 39.8 m/s.

As, this is a free-falling object with some,  initial velocity

so, u = 30m/s

the given time t = 1 sec

so, the final velocity will find out by using the kinematic equation

Using v = u + at

v = 30 + 9.8\(\times\)1

v = 39.8 m/s

The most crucial scientific notion is measurement. Base or physical basic units are used to quantify a wide range of quantifiable quantities. One such quantifiable metric is speed, which calculates the ratio between the distance an item travels and the time needed to cover that distance.

Speedometers are used to measure speed in moving vehicles. Odometers are used to calculate the distance traveled. A graph may be used to calculate speed as well. The distance-time graph aids in comprehending an object's speed.

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Answer:

20.46m/s

Explanation:

\(21 \times \cos(13) = 20.46\)

We will have the following:

The labeled point in the diagram represents a trough.

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 84 × 6.4

We have the final answer as

Hope this helps you

Answer:

4,312 J

Explanation:

PE = mgh

= 44(9.8)(10)

= 4,312

Radius of disk, `R`= `r`Charge of electron, `q`= `-e`Surface charge density of disk, `σ`= `4 µC/m²`= `4×10⁻⁶ C/m²`Using the formula for electric field at a point on the axis of a uniformly charged disk, we have:$$E=\frac{\sigma R}{2\epsilon_0}\left(1-\frac{z}{\sqrt{R^2+z^2}}\right)$$where,`z` is the distance from the center of the disk to the point where electric field is to be calculated.`ε₀` is the permittivity of free space.`

σ` is the surface charge density of disk.`R` is the radius of the disk.Substituting the given values, we get:$$E=\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{z}{\sqrt{R^2+z^2}}\right)$$On substituting `z=r`, where `r` is the distance from the center of the disk at which the electron is released, we have:$$E=\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The electric field is the force per unit charge acting on the electron.

So, the force `F` acting on the electron is given by:$$F=qE=-e\cdot \frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The acceleration `a` of the electron is given by:$$a=\frac{F}{m}$$$$a=\frac{qE}{m}=-\frac{e}{m}\cdot \frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$The negative sign indicates that the acceleration is opposite to the direction of electric field.The mass of electron, `m`= `9.11×10⁻³¹ kg`Substituting the given values, we have:$$a=-\frac{(1.60\times 10^{-19})}{(9.11\times 10^{-31})}\cdot\frac{(4\times10^{-6})\cdot R}{2\cdot 8.85\times 10^{-12}}\left(1-\frac{r}{\sqrt{R^2+r^2}}\right)$$On substituting the given values of `R` and `e`, we get the main answer of the given problem as:$$a=\frac{8\times 10^4}{\sqrt{r^2+4\times 10^8}}\left(1-\frac{r}{\sqrt{r^2+4\times 10^8}}\right)$$Hence, the magnitude of the electron's initial acceleration if it is released at a distance `r` from the center of the disk is `a = (8 × 10⁴)/√(r² + 4 × 10⁸)} × (1 - r/√(r² + 4 × 10⁸))`.

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Answer:

mass energy

Explanation:

because of the kinetic energy

Answer:

All extended structure compounds form cubes. Sodium and chlorine atoms both have cubical shapes. In the extended structure of NaCI, atoms are arranged in a cubical pattern

Diffusion and effusion are both processes that involve the movement of particles from one region to another, but they differ in their mechanisms and the conditions under which they occur.

Diffusion is the movement of particles from an area of high concentration to an area of low concentration, driven by the random motion of the particles.

Diffusion occurs in all states of matter and is responsible for many natural phenomena, such as the spreading of a perfume scent in a room or the exchange of gases in the lungs.

Effusion, on the other hand, is the escape of a gas through a small opening into a vacuum or a region of lower pressure. Effusion occurs because gas particles are in constant motion and collide with the walls of their container.

If one side of the container is open or has a small opening, some of the particles may escape into the lower pressure region, resulting in a net flow of gas from higher to lower pressure.

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The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.

Given:

Current (I) = 5 mA = 5 * 10^(-3) A

Resistance (R) = 18 kΩ = 18 * 10^(3) Ω

Using Ohm's Law, we can calculate the voltage drop (V):

V = I * R

= (5 * 10^(-3) A) * (18 * 10^(3) Ω)

= 90 V

Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.

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It is not possible to answer this question without more information about the distance between cities A and D, the distance between A and B, and the range of the station in City A.

What is distance?
Distance is a measurement of the distance apart two objects or points are, either numerically or occasionally qualitatively. Distance can be a physical length in physics or to an estimate based on other factors in everyday language (e.g. "two counties over"). The term is frequently was using metaphorically to refer to a measurement of the distance between two common pieces or even a degree of separation because spatial cognition is indeed a rich source of implicatures throughout human thought. The concept of a metric space is used in mathematics to formalise the majority of these notions of range, both literal and figurative. Distance in the social sciences can refer to different types of separation, including such social or psychological distance.

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Answer:So the lamp post is giving energy to the town and the kid is using mecanical energy to ride his skateboard

Explanation:

To lift an 875 lb block using friction tongs, we need to find the smallest allowable coefficient of friction between the blocks at d and e. Let's call this coefficient of friction "μ".

The force required to lift the block is equal to its weight, which is 875 lbs. This force is exerted on the friction tongs at point e. The force required to lift the block is balanced by the force of friction between the block and the tongs at point d.

The force of friction between the block and the tongs is equal to the coefficient of friction "μ" multiplied by the normal force between the block and the tongs. The normal force is equal to the weight of the block, which is 875 lbs.

So, the force of friction between the block and the tongs at point d is equal to μ x 875 lbs.

To lift the block, the force required at point e must be greater than or equal to the force of friction at point d. Therefore, we have:

μ x 875 lbs ≤ F

where F is the force required at point e to lift the block.

To find the smallest allowable coefficient of friction, we need to solve for μ. We can rearrange the above equation as:

μ ≤ F / 875 lbs

Substituting F = 875 lbs, we get:

μ ≤ 1

Therefore, the smallest allowable coefficient of friction between the blocks at d and e to lift the block is 1.

To find the smallest allowable coefficient of friction between the blocks at points D and E to lift an 875 lb block using friction tongs, follow these steps:

1. Identify the force acting on the block: The weight of the block is 875 lb.
2. Determine the force needed to lift the block: Since friction tongs rely on friction to lift the block, the force applied by the tongs (F) must be equal to or greater than the block's weight (W). So, F ≥ W = 875 lb.
3. Apply the friction formula: The force of friction (F_friction) is determined by multiplying the normal force (N) by the coefficient of friction (μ). In this case, F_friction = μ * N.
4. Determine the normal force (N): In the case of friction tongs, the normal force is equal to the force applied by the tongs, which we've determined is 875 lb. So, N = 875 lb.
5. Solve for the coefficient of friction (μ): Since we're looking for the smallest allowable coefficient of friction, we can set F_friction equal to the force needed to lift the block (875 lb). So, μ * N = 875 lb, and μ = 875 lb / N.
6. Plug in the value for N: μ = 875 lb / 875 lb.
7. Calculate the smallest allowable coefficient of friction: μ = 1.

Therefore, the smallest allowable coefficient of friction between the blocks at points D and E to lift the 875 lb block using friction tongs is 1.

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