a charge q1=−6.5μc is at the origin, and a charge q2=−2.42μc is on the x-axis at x = 1.00m. find the magnitude of net force acting on a charge q3= 1.4μc located at x=0.55 m.

The planetary body with the fastest orbit is Mercury, and the one with the slowest orbit is Neptune.

There is a general pattern between orbital velocity and orbital radius known as Kepler's second law of planetary motion. According to this law, a planet sweeps out equal areas in equal times as it orbits the Sun. This implies that planets closer to the Sun have smaller orbital radii and must travel faster to cover the same area in the same amount of time.

The relationship between orbital velocity and orbital radius can be expressed as v ∝ 1/r, where v represents the orbital velocity and r denotes the orbital radius. This relationship shows that as the orbital radius increases, the orbital velocity decreases. In other words, planets farther from the Sun have slower orbital velocities compared to those closer to the Sun.

This pattern is consistent with observations in our solar system. The inner planets, such as Mercury, have smaller orbital radii and faster orbital velocities, while the outer planets, like Neptune, have larger orbital radii and slower orbital velocities.

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If the desk doesn't move, then it's not accelerating.

If it's not accelerating, then the net force on it is zero.

If the net force on it is zero, then any forces on it are balanced.

If there are only two forces on it and they're balanced, then they have equal strengths, and they point in opposite directions.

So the friction on the desk must be equal to your 245N .

Answer:.pi/15 cm/s (approx .2094395 cm/s)

Explanation:

Use 2 as your radius which will make the circumference of the clock equal to 4 pi (remember the formula for circumference is pi * diameter)

Using the circuference we can use the formula Speed = distance/Time and plug in our numbers

4pi / 60 seconds = .2094395 cm/s or .002094395 m/s

The magnitude of the glider's average acceleration is determined as 2.3 m/s².

The average acceleration of the glider is the rate at which the velocity of the glider changes with time.

Mathematically, the formula for average acceleration is given as;

a = v / t

where;

Since the glider is launched by the high winds so that in 45.0 sec the glider's speed equals the speed of the wind.

a = ( 103.33 m/s ) / ( 45 s )

a = 2.3 m/s²

Thus, the average acceleration of the glider is a function of the speed of the glider and the duration to attain such speed.

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According to the given statement , the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.

To find the fluid relative velocity at the interface between the two plates, we can use the concept of shear rate and the formula for the velocity gradient.

First, let's calculate the shear rate (γ) using the formula:

γ = Δv / Δx

Where:
- Δv is the velocity difference between the two plates, which is given as 1.3 m/s (since the upper plate has a speed of 1.3 m/s at the interface).
- Δx is the distance between the two plates, which is the sum of the thicknesses of the two fluid layers:

Δx = L1 + L2.

Given that L1 = 0.62 mm and L2 = 0.56 mm, we need to convert these values to meters:

L1 = 0.62 mm = 0.62 × 10⁻³ m
L2 = 0.56 mm = 0.56 × 10⁻³ m

Now we can calculate Δx:

Δx = L1 + L2

Substituting the values, we get:

Δx = 0.62 × 10⁻³ m + 0.56 × 10⁻³ m
   = 1.18 × 10⁻³ m

Now we can calculate the shear rate:

γ = Δv / Δx
  = 1.3 m/s / 1.18 × 10⁻³ m

Performing the division, we find:

γ ≈ 1101.7 s^-1

The shear rate (γ) represents the velocity gradient between the two fluid layers. To find the fluid relative velocity at the interface, we need to multiply the shear rate by the thickness of the first layer (L1).

Relative Velocity = γ * L1

Substituting the values, we get:

Relative Velocity = 1101.7 s⁻¹ * 0.62 × 10⁻³ m

Performing the multiplication, we find:

Relative Velocity ≈ 0.684 m/s

Therefore, the fluid relative velocity at the interface between the two plates is approximately 0.684 m/s.

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Answer:

B. underwater mountain range

Answer:

an underwater mountain range

The interstellar clouds that are made mostly of hydrogen are usually dominated by the color red because of its strong visible emission lines

Hydrogen is the most common element in the universe because a hydrogen is a pair of protons and electrons. Since they are oppositely charged they attract each other and it is easier to bond without the need of any external forces.

Red is colour in visible light spectrum with longest wavelength and has the lowest frequency. Because of its longer wavelength it can travel much farther distances than other colours in visible spectrum.

Therefore, these clouds usually dominated by the color red because of its strong visible emission lines

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The ball in the air is for  0.319 sec.

The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial to its vertical movement.

Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.

Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.

Calculate:-

H = ut + 1/2 gt²

Since the vertical initial velocity is 0.

H = 0 +gt²

t = \(\sqrt{ \frac{H}{g}\)

 = \(\sqrt{ \frac{1}{9.8}\)

 = 0.319 sec.

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The energy of one photon of the blue light of wavelength 433.9 nm is 4.58×10⁻¹⁹ J or 2.857 eV.

The relation between energy and wavelength can be derived from Plank's equation.

 E = hυ

      h is plank's constant and υ is the frequency.

Frequency and wavelength is related as

   c = υλ,

c is the velocity of light in vacuum

υ is the frequency and λ is the wavelength

From that,  υ = c/λ

Substituting in the equation of energy,

    E = hυ = hc/λ

       h= 6.626 ×10⁻²⁶

        c = 3× 10⁸

        λ = 433.9 nm = 4.339 ×10⁻⁷ m

Substituting the values,

     E = ( 6.626 ×10⁻²⁶ × 3× 10⁸) / 4.339 × 10⁻⁷

         = 4.58 × 10⁻¹⁹ J = 2.857 eV.

So the energy of one photon is  4.58 × 10⁻¹⁹ J or 2.857 eV.

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The equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

The rate of flow of charge per unit cross - sectional area is called electric current. Mathematically -

i = dq/dt

From this -

dq = i dt

∫dq = ∫i dt

Q = it

Current is measured in amperes and is a Tensor quantity.

Given is a circuit that measured a current of 11.5 milli amperes.

Now, the current in milli amperes is used to give the measurement of small amount of current. One milliampere of current is equivalent to -

1 mA = (1/1000) A = 10 ⁻³ A

So, in order to calculate the total current in amperes, we will multiply 11.5 milliamperes by 10 ⁻³ as follows -

11.5 milliamperes [mA] = 11.5 x 10⁻³ amperes[A]

Therefore, the equivalent measurement of 11.5 milliamperes is 11.5 x 10⁻³ amperes.

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(a) The distance between you and the deer (you’re driving down the highway late one night at 20 m/s, when a deer steps onto the road 44 m in front of you) when you come to stop = 14 m.

(b) The maximum speed you could have and still not hit the deer = 25.80 m/s

The distance covered before to applying the brake = (20 x 0.5)

= 10 m

(v1² - v0²) = 2as

Where:

s = distance (m)

v = velocity

a = acceleration due to gravity (10 m/s²)

s = (0² - 20²) / (2 x 10)

= 20 m

(a) The distance between you and the deer:

44 - 30 = 14 m

So, the deer won't be struck by the car.

(b)

The maximum speed:

(v1² - v0²) = 2as

v1² = v0² - 2as

= (0² - (2 x (-10) x (44 - 0.5v0)

= 880 - 10 v0

v0 = 25.80 m/s

The question is incomplete, it should be:

You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction time before stepping on the brakes is 0.50 s, and the maximum deceleration of your car is 10 m/s2.

Part A

How much distance is between you and the deer when you come to a stop?

Part B

What is the maximum speed you could have and still not hit the deer?

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When the Earth is at point C, Equinox happens.

In Equinox, the Sun is directly above the equitor making day and night equal in both hemispheres.

Answer:newtons second law

Explanation:

To get something to accelerate you have to apply a pull force . if the mass increase a grater pull is required

The law that explains the fact that a heavier truck takes a longer time to stop is Newton's law of inertia.

According to Newtons first law of motion also called the law of inertia, a body will continue in a state of rest or uniform motion unless it is acted upon by an external, unbalanced force.

This law explains the reluctance of heavier objects to move or stop. The law that explains the fact that a heavier truck takes a longer time to stop is Newton's law of inertia.

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Answer:

I. Aceleración, a = -2 m/s²

II. Distancia, S = 100 metros

Explanation:

Dados los siguientes datos;

Velocidad inicial = 72 km / h

Tiempo = 10 segundos

Velocidad final = 0 m/s

Conversión:

72 km/h a metros por segundo = 72 * 1000/3600 = 72000/3600 = 20 m/s

I. Para encontrar la aceleración, usaríamos la primera ecuación de movimiento;

\( V = U + at\)

Dónde;

Sustituyendo en la fórmula, tenemos;

\( 0 = 20 + a*10 \)

\( -20 = 10a \)

\( Aceleracion = \frac{-20}{10}\)

Aceleración, a = -2 m/s²

Nota: el signo negativo indica desaceleración o retraso.

II. To find the acceleration, we would use the third equation of motion;

\( V^{2} = U^{2} + 2aS \)

Dónde;

Sustituyendo en la fórmula, tenemos;

\( 0^{2} = 20^{2} + 2*(-2)*S \)

\( 0 = 400 - 4S \)

\( 4S = 400 \)

\( S = \frac {400}{4}\)

Distancia, S = 100 metros

The correct answer is B) partially inelastic. If the masses of the blocks and the velocities before and after being given then The collision is partially inelastic.

To determine the character of the collision, you need to compare the kinetic energy before and after the collision. If the kinetic energy is the same before and after the collision, the collision is elastic. If the kinetic energy is less after the collision, the collision is inelastic. If the kinetic energy is greater after the collision, the collision is not possible because energy cannot be created or destroyed, it can only be transformed from one form to another.

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To continue testing his hypothesis, Neil should repeat the experiment, but only wait 20 seconds before testing the comb's attractive effects.

In a controlled experiment, all other factors are held constant with the exception of one. One or more other groups are studied with all conditions being the same as the control group and each other except for one variable. Typically, a collection of data is considered to be the control group, which is often the normal or usual state.

Comparing a control group to an experimental group is a popular form of controlled experiment. The factor being examined is the only difference between the two groups' variables.

A controlled experiment has the benefit of making it simpler to determine whether the results are meaningful.

Imagine you want to know if the type of soil influences how long it takes a seed to germinate and you choose to conduct a controlled experiment to find out. Five similar pots might be used, each filled with a different kind of soil, and each with identical bean seeds. The pots could then be placed in a sunny window, watered equally, and the time it takes for the seeds in each pot to sprout could be recorded.

This is a controlled experiment because the only variable that will change is the kind of soil you use. You are in charge of these options.

Here in given case Neil's goal is to find out how quickly charge dissipate in humid air. So he should try his hypothesis by varying wait time.

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The average speed of the trolley after 5 seconds, given that it travels from2 m/s to 14 m/s is 8 m/s

First, we shall determine the total distance travelled in 5 seconds. Details below:

s = ½(u + v) × t

s = ½ × (2 + 14) × 5

s = ½ × 16 × 5

s = 8 × 5

s = 40 meters

Finally, we shall determine the average speed of trolley. This is shown below:

Average speed = Total distance / total time

Average speed = 40 / 5

Average speed = 8 m/s

Thus, the average speed of the trolley is 12.8 m/s

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Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

Smog development and infiltration over Los Angeles. haze and air pollution in the entire community.

Burning sulfur-containing fossil fuels, particularly coal, causes sulfurous smog, also referred to as "London smog," which is characterized by a high concentration of sulfur oxides in the atmosphere.

The two primary substances in automotive exhaust are nitrogen oxides, which are created in scorching internal combustion engines, and hydrocarbons, which are derived from gasoline.

Therefore, Both are dangerous on their own, but as they float through the air in Southern California's sunny climate, the sun bakes them into a new molecule called ozone, better known as smog.

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The answer is yes because of conservation of momentum. That is, the momentum before collision is equal to the momentum after collision.

Momentum is the product of mass and velocity. It is a vector quantity. And it is measured in Kgm/s

If two vehicles have a head-on collision, the vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. The final velocity for both vehicles immediately after the crash can be obtain by using the formula

v = u - at

Where

If you are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash, then you can determine the momentum of both vehicles before the collision by calculating the momentum of both after the collision because momentum is always conserved.

Or by first calculating the initial velocity for vehicle B by using the formula below

\(M_{1}U_{1} - M_{2}U_{2} = (M_{1} + M_{2} )V\)

where

After we obtain initial velocity for vehicle B, we can calculate the momentum of both vehicles before the collision

Therefore, the momentum of both vehicles before the collision can be determined.

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Answer:

The box gains 3200 J of kinect energy.

Explanation:

Kinect energy is the energy of an object has because of its motion. Almost anything that has mass and it's in motion has kinect energy. Examples:

Also known as the principle of work and kinect energy, it states that the work done by all forces acting upon an object equals the change of its kinect energy.

For example, if you pull a box, then you're exerting a force on it and it moves forward. Since the box has mass and it's in motion, you have changed its kinect energy.

Solution:

Write the data down:

\(\bullet \quad \mathsf{m=50\,kg}\\\\\bullet \quad \mathsf{F=400\,N}\\\\\bullet \quad \mathsf{d=8\,m}\)

Apply work energy theorem:

\(\mathsf{W}= \Delta\mathsf{K}\)

The amount work done equals the change of kinect energy:

\(\mathsf{W}=\mathsf{K-K_o}\)

Since the block is at rest at the beginning, so it has zero initial kinect energy:

\(\mathsf{W}=\mathsf{K-0}\\\\\\\mathsf{W}=\mathsf{K}\)

Now, apply the formula for work to the left hand side of the equation:

\(\mathsf{F\cdot d}=\mathsf{K}\\\\\\\mathsf{400\cdot 8}=\mathsf{K}\\\\\\\therefore \boxed{\mathsf{K=3200\,J}}\)

Conclusion: the box has gained 3200 J of kinect energy.

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Answer:

4.8 mph

Explanation:

From the question,

Average speed = total distance/total time

V = d/t....................... Equation 1

Where d = distance, t = time

Given: d = 26.2 miles, t = 5.5 hours.

Substitute these values into equation 1

V = 26.2/5.5

V = 4.76 mph

V ≈ 4.8 mph

Answer:

4.8mph

Explanation:

Doing it now on EDG

For those doing the exam on EDG science rn, i wish you luck~

Have a good day!~ :D

a) The magnetic field strength on the axis of a small bar magnet is given by the formula:
B = μ0/4π * (2M/d^3)

where B is the magnetic field strength, μ0 is the permeability of free space, M is the magnetic dipole moment of the magnet, and d is the distance from the center of the magnet to the point where the field is being measured.
We can rearrange this formula to solve for M:
M = (B * d^3)/(2 * μ0)
Plugging in the values given, we get:
M = (4.8 × 10^-6 T) * (0.15 m)^3 / (2 * 4π × 10^-7 T·m/A)
M = 3.39 × 10^-3 A·m^2
Therefore, the bar magnet's magnetic dipole moment is 3.39 × 10^-3 A·m^2.
b) To find the on-axis field strength at a distance of 19 cm from the magnet, we can use the same formula as before, but with the new distance value: B = μ0/4π * (2M/d^3)
B = 4π × 10^-7 T·m/A * (2 * 3.39 × 10^-3 A·m^2) / (0.19 m)^3
B = 2.07 × 10^-6 T
Therefore, the on-axis field strength 19 cm from the magnet is 2.07 × 10^-6 T.

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Your friend is correct. In order to determine the speed at which the person who leaves point B must walk, you need to know the length of AC and BC.

This is because the time it takes for each person to reach point C is dependent on the distance they must travel and the speed at which they are traveling.

Using the formula time = distance / speed, you can calculate the time it takes for each person to reach point C.

For the person leaving point A, the time it takes to reach point C is tA = AC / 3, since they are traveling at a speed of 3 miles per hour.

For the person leaving point B, the time it takes to reach point C is tB = BC / x, where x is the speed at which they are traveling.

Since both people are intended to reach point C at the same time, you can set the two equations equal to each other:

AC / 3 = BC / x

Cross-multiplying and solving for x gives you the speed at which the person leaving point B must walk:

x = 3BC / AC

Without knowing the length of AC and BC, you cannot determine the speed at which the person leaving point B must walk. Therefore, your friend is correct.

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The planet orbit Kepler was studying when he developed the law of orbital motion is Mars.

Kepler’s law of orbital motion are three laws  and can be stated as follows;

The first and second Kepler's law of orbital motion was proposed when Kepler discovered that the orbit of Mars was an ellipse.

Thus, the planet's orbit that Kepler was first studying when he began to develop his laws of orbital motion is Mars.

The correction that describes the planets orbit Kepler was studying is Mars.

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The statement 'The effective resistance of two series resistors is always greater than that of either resistor' is true.

The effective resistance of two series resistors is the sum of their individual resistances. When two resistors are connected in series, the current flowing through both of them is the same, but the voltage across each resistor is different, depending on its resistance.

Since the voltage drop across each resistor is proportional to its resistance, the larger resistor will have a larger voltage drop. Therefore, the effective resistance of the two series resistors will be greater than that of either resistor alone.

When resistors are connected in series, their effective resistance (or total resistance) is the sum of their individual resistances. Since both resistors have positive resistance values, the total resistance will always be greater than the resistance of either individual resistor.

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The student finds the density for Augite = 3.5 g/cm³

Mass of the metal = 35g

Volume of water in the graduated cylinder = 20 mL

When the metal is placed in the cylinder filled with water, the water level rises to 30 mL.

So, the volume of the metal = 30 - 20 = 10 mL

1 mL = 1cm³

∴ 10 mL = 10 cm³

Now, we know that,

\(Density = \frac{Mass}{Volume}\)

\(Density = \frac{35g}{10 cm^{3} }\)

\(Density = 3.5 g/cm^{3}\)

Therefore, the student finds the density for Augite = 3.5 g/cm³

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Answer:

Because the more coolant passed through the fins, the more energy can be emitted

Answer:

Vf = 11.04 m/s

Explanation:

First, we consider free fall motion with zero initial velocity. Using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height of bridge = ?

Vi = Initial  Speed  = 0 m/s

t = time taken = 4.5 s

g = 9.8 m/s²

Therefore,

h = (0 m/s)(4.5 s) + (1/2)(9.8 m/s²)(4.5 s)²

Therefore,

h = 99.225 m

Now, we consider the forced motion when the youth throws the ball with some negative initial energy:

Vi = - Vi

t = 3 s

h = 99.225 m

Therefore,

99.225 m = - Vi(3 s) + (1/2)(9.8 m/s²)(3 s)²

Vi = (- 99.225 m + 44.145 m)/3 s

Vi = - 18.36 m/s

Now, we use this in 1st equation of motion for final velocity:

Vf = Vi + gt

Vf = -18.36 m/s + (9.8 m/s²)(3 s)

Therefore,

Vf = 11.04 m/s

Rate of acceleration for a 5 kg grocery cart that’s being pushed with 50 N is 10 m/sec^2. The value of acceleration can be calculated with the help of following formula Fnet = m . a

Fnet is the  net force acting on the shopping cart

m is the mass of the grocery cart

a is the acceleration of the shopping cart

So on using the formula we get

Fnet = m . a

So on putting the values we get

Fnet = 50 N

m = 5kg

a = ?

50 = 5.a

On calculating we get the value of acceleration

a = 10 m/sec^2

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