A chemist is trying to classify an unknown substance as either a metal or nonmetal. What question should the chemist use to help classify the material?

A. Does the material feel hard to the
touch?

B. Does the material feel rough or smooth?

C. Is the material a good conductor or a poor conductor?

D. Will the material float in water?


Please Help me!!!​

Answer:

Frequency is 2Hz

Explanation:

1) single replacement

2) Zn + 2HCl -----> ZnCl + H

equation is already balanced

The temperature, T2, is 359°C.

1st) We need to identify the volume and the temperature of the gas in the point A (initial state of gas) and point B (final state of gas):

- Point A:

V1= 1.65x10^3 L

T1= 43°C (316K)

-Point B:

V2= 3.30x10^3 L

T2= unknown

2nd) With the Ideal Gas Law and assuming there is no change in pressure or amount of gas in the balloon, we calculate the temperature in point B with the formula that relates temperature and volume:

It is important to use the units of the ideal gas constant, so the units must be in Kelvin (K) and liters (L). That's why the temperature (T2) it is 316 K.

3rd) Finally, it is necessary convert the Kelvin unit into Celsiud degrees:

So, the temperature, T2, is 359°C.

This is because in the sand bath the heating will be even and the heat will be distributed equally all around the glass vessel.

What is reflux?

Reflux is the procedure of gradually using a condenser to cool the resultant vapour back into liquid form while heating a chemical reaction for a predefined amount of time. The vapours produced above the reaction are condensed, which causes them to continuously return as a condensate to the flask. It guarantees that the reaction's temperature remains constant by doing this.

Reactants for reflux investigations could either be both liquids or both solids.

Instead of heating the bottom of the vessel and waiting for convection to heat the remaining portions, this method allows a reaction vessel to be heated evenly throughout with little stirring, reducing both the reaction's duration and the potential for side reactions that could happen at higher temperatures.

During the reflux of the reaction mixture in bromination of stilbenes, a sand bath is preferred over the water bath. This is because in the sand bath the heating will be even and the heat will be distributed equally all around the glass vessel.

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Iron and pure nickel can be differentiate by the it appearance as well as the density.

There are few property which can differentiate iron metal and pure nickel metal.

1)The density of iron= 7.87 \(gcm^{-3}\)

The density of pure nickel = 8.91  \(gcm^{-3}\)

2)The atomic number of iron = 26

The atomic number of nickel = 28

3)Appearance of iron = silver-grey metal

Appearance of pure nickel = silver -white metal.

Therefore, pure nickel and iron can be easily differentiate with the help of appearance and dansity.

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The energy that it takes to melt 2 kg of ice is; 2 kg * 1000 g/kg * 1 mol/18.02 g * 6.03 kJ/mol = 669 kJ. The correct option is C.

Energy is a quantitative value. It is the entity that is used in every reaction because without it no reaction can occur. In animals and plants and other organisms, energy is needed to carry out biological functions.

Mass of ice, m = 2 kg

Molar heat of fusion for ice; \(\rm \Delta_fus.H = 6.03 kJ/mol at 0°C.\).

The molar mass of Ice which is water is; 18.02 g/mol

By the formula for calculating energy is:

E = (m/M) * Δ_fus.H

Putting the values in the equation:

E = (2 kg * 1000 g/kg) * 1 mol/18.02 g * 6.03 kJ/mol = 669 kJ

Thus, the correct option is C, 2 kg * 1000 g/kg * 1 mol/18.02 g * 6.03 kJ/mol = 669 kJ.

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The presence of nonbonding electron pairs, also known as lone pairs or nonbonding electron domains, can have an effect on the shape of molecules. These lone pairs influence the molecular geometry by exerting electron repulsion and affecting the arrangement of atoms and bonding pairs.

Molecules that commonly exhibit the influence of nonbonding electron pairs on molecular shape include:

Water (H2O): In water, the two lone pairs of electrons on the oxygen atom affect the molecular shape, leading to a bent or V-shaped geometry.

Ammonia (NH3): Ammonia has one lone pair of electrons on the nitrogen atom, which leads to a pyramidal shape.

Nitrogen trifluoride (NF3): NF3 has one lone pair of electrons on the central nitrogen atom, resulting in a trigonal pyramidal shape.

Carbon dioxide (CO2): Although carbon dioxide does not possess any lone pairs on the carbon atom, the presence of two double bonds results in a linear molecular shape.

Sulfur hexafluoride (SF6): The six lone pairs of electrons on the sulfur atom in SF6 cause electronic repulsion, resulting in an octahedral shape.

These are just a few examples, but there are many molecules where nonbonding electron pairs influence the overall molecular shape. The presence and arrangement of these lone pairs affect the bond angles and distortions from ideal geometries in molecules, ultimately determining their three-dimensional shapes.

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The approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

Assuming that the annual rate of $20,000 is deposited at the beginning of each year, the total amount deposited over 6 years would be $120,000. With continuous compounding at 5% interest rate, the formula to calculate the balance in the account after 6 years is:
A = Pe^(rt)
Where A is the balance, P is the principal (amount deposited), e is the mathematical constant approximately equal to 2.71828, r is the interest rate in decimal form, and t is the time in years.
Plugging in the values, we get:
A = $120,000e^(0.05*6)
A = $159,073.51
Therefore, the approximate balance in the account at the end of 6 years is $159,074. Rounded to the nearest dollar, it is $159,074.

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Answer:

When the concentration is higher, more hydrogen ions are near the Zn atoms at any given time. This allows for more Zn atoms to be ionized and dissolved into the solution per second.

Explanation:

Answer:

Substance that are used in the reaction

Explanation:

I hope this will help you

Answer:

Substances that are used in the reaction. Hope my answer helps you!

Answer:

6=100  

Explanation:

Answer:

ionic bond, also called electrovalent bond, type of linkage formed from the electrostatic attraction between oppositely charged ions in a chemical compound. Such a bond forms when the valence (outermost) electrons of one atom are transferred permanently to another atom.

Explanation:

Answer:

The substance will be in liquid state at a temperature of 97.3 °C

Note: The question is incomplete. The complete question is given below :

Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)

Explanation:

1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT

Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C

H = 50 × 0.75 × 3 = 112.5 calories

b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g

H = 50 × 45 = 2250 cal

c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.

Amount of energy left = 5000 - 2362.5 = 2637.5 cal

The remaining energy is used to heat the liquid

H = mcΔT

Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change

2637.5 = 50 × 0.75 x ΔT

ΔT = 2637.5 / ( 50*0.75)

ΔT = 70.3 °C

Final temperature of sample = (70.3 + 27) °C = 97.3 °C

The substance will be in liquid state at a temperature of 97.3 °C

Answer:

\(d)cellulose \\ monomer \: is \: glucose \\ thank \: you\)

Answer:

cellulose

Explanation:

Answer:

Answer is 9.2 grams

Explanation:

Molar mass of ethanol

\({ \bf{CH _{3}CH_{2}OH}} = (12 \times 2) + (6 \times 1) + (16) \\ = 46 \: g\)

for moles:

\({ \sf{1 \: mole \: of \: ethanol \: weighs \: 46 \: g}} \\ { \sf{0.2 \: moles \: weigh \: (0.2 \times 46) \: g}} \\ = 9.2 \: g\)

The more unusual the value is relative to the other values in the dataset .In this case, the z-score for the systolic blood pressure is 2.18, while the z-score for the heart rate is -1.74. Since the absolute value of the z-score for the systolic blood pressure is larger than that of the heart rate, it can be concluded that the systolic blood pressure value is more unusual relative to the other patients in the sample as compared to the patient's heart rate value.

Question 24Given: Mean systolic blood pressure = 132 mm

Hg; standard deviation of systolic blood pressure = 33;

Systolic blood pressure of patient = 204 mmHg

.The formula to calculate z-score = `(x - μ) / σ`

Where, `x` is the value of the variable,

`μ` is the mean of the variable,

`σ` is the standard deviation of the variable

.Substituting the values, we getz-score = `(204 - 132) / 33 = 2.18`

Therefore, the z-score associated with the systolic blood pressure value of 204 mmHg is 2.18

. Question 25

Given: Mean heart rate = 99 bpm;

standard deviation of heart rate = 27;

Heart rate of patient = 52 bpm.

The formula to calculate z-score = `(x - μ) / σ

`Where, `x` is the value of the variable,

`μ` is the mean of the variable,

`σ` is the standard deviation of the variable.

Substituting the values, we getz-score = `(52 - 99) / 27 = -1.74

`Therefore, the z-score associated with the heart rate of 52 bpm is -1.74.

Question 26

Z-score can be used to compare two different data sets. The absolute value of the z-score shows how many standard deviations the value is away from the mean. Hence, the larger the absolute value of the z-score, the more unusual the value is relative to the other values in the dataset.In this case, the z-score for the systolic blood pressure is 2.18, while the z-score for the heart rate is -1.74. Since the absolute value of the z-score for the systolic blood pressure is larger than that of the heart rate, it can be concluded that the systolic blood pressure value is more unusual relative to the other patients in the sample as compared to the patient's heart rate value.

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The kind of chemical reaction that occurs when two molecules are connected in the places where hydrogen is removed from one molecule and a hydrogen and oxygen are removed from the other is called a dehydration synthesis reaction.

In this type of reaction, a new molecule is formed by removing water molecules from the two original molecules.

Dehydration synthesis reactions are combination or synthesis reactions which occur between the same or different monomer units with the elimination of water molecules.

It is a kind of condensation reaction in which water molecules are eliminated with the addition of two molecules.

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Given:

Sum of masses of two isotopes = 371.9087 u

Re-185 natural abudance = 37.40%

Re-187 natural abudance = 62.60%

Known:

atomic weight of Re = 186.207 u

Atomic mass of Re-185:

To find the atomic mass of Re-185, take the total mass given and subtract atomic weight.

abundance of Re-185 = 37.40% = 0.3740

(371.9087 - x) = atomic weight of Re-187 in u

To find mass of Re-187:

abundance of Re-187 = 62.60% = 0.6260

Solution:

Step 1. Multiply x times the abundance of Re-185 and multiply (371.9087 - x) times the abundance of Re-187.

Re-185: (0.3740)(x) = 0.3740x

Re-187: (0.6260)(371.9087 - x) = 232.8148462 - 0.6260x

Step 2. Add the results and set them equal to 186.207.

0.3740x + 232.8148462 - 0.6260x = 186.207

Step 3. Solve for x by subtracting 232.8148462 from both sides and then divide both sides by -0.2520.

0.3740x + 232.8148462 - 0.6260x - 232.8148462 = 186.207 -

232.8148462

0.3740x - 0.6260x = -46.6078462

-0.2520x = -46.6078462

-0.2520x/-0.2520x = -46.6078462/-0.2520

x = 184.9517706 u

Step 4. Atomic weights of Re-185 and Re-187.

x = 185.0 u = the atomic weight of Re-185

(371.9087 - 184.9517706) = 186.9569294 = 187.0 u = the atomic weight of Re-187

Therefore the atomic weight of Re-185 is 185.0 u, and the atomic weight of Re-187 is 187.0 u.

Answer:

venus

Explanation:

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Answer: I would say that Saturn is most like Earth. Not only does it have moons, like Earth, but the atmosphere is also denser like Earth. It also has windstorms, granite they are much more intense than Earth’s, but they do indeed happen. Saturn also has hydrogen gas; this gas is here on Earth supporting life in our ocean. Therefore, there is a chance that the conditions on Saturn could provide the essentials for there to be life.

Answer:

noble gases from what i learnt

Answer: 3.45 L carbon dioxide are produced

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number \(6.023\times 10^{23}\) of particles.

To calculate the moles, we use the equation:

\(\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles\)

\(C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O\)  

According to stoichiometry :

5 moles of \(O_2\) produce =  3 moles of \(CO_2\)

Thus 0.257 moles of \(O_2\) will produce=\(\frac{3}{5}\times 0.257=0.154moles\)  of \(CO_2\)  

Volume of \(CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45\)

Thus 3.45 L carbon dioxide are produced

There are approximately 6.071 × 10^23 fluorine atoms in 24.24 grams of sulfur hexafluoride.

To determine the number of fluorine atoms in 24.24 grams of sulfur hexafluoride (SF6), we need to use the concept of moles and Avogadro's number.

Calculate the molar mass of sulfur hexafluoride (SF6):

Sulfur (S) atomic mass = 32.07 g/mol

Fluorine (F) atomic mass = 18.998 g/mol

Molar mass of SF6 = (1 × Sulfur atomic mass) + (6 × Fluorine atomic mass)

= (1 × 32.07 g/mol) + (6 × 18.998 g/mol)

= 32.07 g/mol + 113.988 g/mol

= 146.058 g/mol

Calculate the number of moles of SF6:

Moles = Mass / Molar mass

= 24.24 g / 146.058 g/mol

≈ 0.166 moles

Determine the number of fluorine atoms:

Since there are 6 fluorine atoms in one molecule of SF6, we can calculate the number of fluorine atoms as:

Number of fluorine atoms = Moles of SF6 × Avogadro's number × Number of fluorine atoms in one molecule

= 0.166 moles × 6.022 × 10^23 atoms/mol × 6

≈ 6.071 × 10^23 fluorine atoms

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Answer:

New ideas would be created and tested

Explanation:

All old ideas would be discarded.

Scientific evidence would be weakened.

New ideas would be created and tested.

The limitations of science would be evident.

In science, old ideas are usually improved or modified and not entirely discarded. The old ideas form the basis for new ideas after extensive reviews. Differences in the interpretations made by scientists on any particular phenomenon give rooms for reviews. The reviews often generate new ideas or hypotheses and these can be tested using relevant experimental procedures according to the scientific method.

Hence, the correct answer would be that new ideas would be created and tested.

Two distinct products of the reaction could emerge, both of which might turn out to be stereoisomers of one another.

We now understand that the chemical as demonstrated can experience monobromination, and the resulting compound is the same compound. However, due to the reaction's nature, we would have two steroisomers.

Given the reaction's process, we are aware that there are two distinct reaction products that may turn out to be stereoisomers of one another.

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34.3gallon of  14% acid solution and 65.7gallon of  46% acid solution need to be mixed to make 100 gallons of 35.8% acid solution.

A gallon is the standard unit of volume indicated by the letter "gal," and it is primarily used to measure liquid quantity inside the customary systems of the United States as well as the Imperial System of measuring of the United Kingdom.

Following the 11th Conference on Measures and Weights in 1960, some countries approved an International System of Units (SI). As a result, this volume measurement unit is replaced by "litre."

0.14×x + 0.46×(100-x)= 0.35×100

0.14x + 46-0.46x=35

-0.32x=35 -46

-0.32x =-11

x=11/ 0.32=34.3gallon

100-34.3=65.7gallon

Therefore, 34.3gallon of  14% acid solution and 65.7gallon of  46% acid solution need to be mixed to make 100 gallons of 35.8% acid solution.

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Answer: Glucose (C6H12O6) is a hexose -- a monosaccharide containing six carbon atoms. Glucose is an aldehyde (contains a -CHO group). Five of the carbons plus an oxygen atom form a loop called a "pyranose ring", the most stable form for six-carbon aldoses.

Explanation:.

Sample A, with an activity of 6,500 Bq, has a higher activity and therefore produces a greater amount of radiation compared to Sample B, which has an activity of 92.5 Bq.

Radioisotopes are radioactive elements with unstable nuclei that undergo radioactive decay to achieve stability. During this process, radioisotopes emit radiation. Radiation refers to the energy emitted by a radioactive source. The type of radiation emitted during decay includes alpha particles, beta particles, and gamma rays.

The measure of the radiation produced by a radioisotope is known as its activity, which is quantified in units of Becquerel (Bq) or Curie (Ci). One Bq represents one decay per second, while one Ci corresponds to 3.7 x 10^10 decays per second. Thus, 1 Ci equals 3.7 x 10^10 Bq.

For example, Sample A has an activity of 6.5 kBq, which is equivalent to 6,500 Bq since one kiloBecquerel (kBq) equals 1,000 Becquerel (Bq). On the other hand, Sample B has an activity of 2.5 μCi, which is equivalent to 92.5 Bq since one microCurie (μCi) equals 37,000 Bq.

Consequently, Sample A exhibits a higher activity level than Sample B. In other words, Sample A produces a greater amount of radiation compared to Sample B.

To summarize, radioisotopes undergo radioactive decay and emit radiation, which is measured by their activity in units of Becquerel or Curie. Sample A, with an activity of 6,500 Bq, has a higher activity and therefore produces a greater amount of radiation compared to Sample B, which has an activity of 92.5 Bq.

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