a circuit consist of four resistor in parallel with a battery three resistors have resistance of 1 ohms ,2 ohms and 3 ohms , respectively, the total resistance the circuit is 0,5 ohms and the current through the 1 ohms resistor is 4A
​

what is the value of fourth resistor

Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)

When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.

In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.

When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.

Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.

If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.

Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)

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Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration.

1. Elements are arranged on the periodic table in terms of valence electrons based on their atomic number and electron configuration. The valence electrons are the outermost electrons in an atom's electron shell, and they are crucial in determining the chemical properties and reactivity of elements.

2. Evidence from data tables can be shown by examining the electron configuration and the group and period numbers of various elements on the periodic table. Here is a simplified example:

Element   | Electron Configuration | Group | Period |

--------------------------------------------

Hydrogen  | 1s^1                              | 1     | 1      |

Lithium       | [He] 2s^1                     | 1     | 2      |

Carbon       | [He] 2s^2 2p^2          | 14    | 2      |

Oxygen      | [He] 2s^2 2p^4          | 16    | 2      |

Neon          | [He] 2s^2 2p^6          | 18    | 2      |

--------------------------------------------

3. The evidence from the data table supports the claim that the arrangement of elements on the periodic table is based on valence electrons.

- Group Trend: Elements within the same group (vertical columns) share the same number of valence electrons. In the example table, Hydrogen, Lithium, and Neon are all in Group 1, indicating they have 1 valence electron.

- Period Trend: Elements within the same period (horizontal rows) have the same number of electron shells. In the example table, Hydrogen and Lithium are in Period 1, indicating they have their valence electron in the first energy level. Carbon, Oxygen, and Neon are in Period 2, indicating they have their valence electrons in the second energy level.

By examining the electron configurations, group numbers, and period numbers, we can clearly see the trends and patterns in the number of valence electrons for both groups and periods on the periodic table. This evidence supports the claim that the arrangement of elements on the periodic table is based on their valence electrons, which play a crucial role in determining their chemical behavior and properties.

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Nernst potential for K+ ions bathed in DMEM at 37°C is  55 mV. The correct option is A.

The Nernst potential for K+ ions bathed in DMEM at 37°C is a measure of the equilibrium potential for K+ ions across a cell membrane in a solution of DMEM. It is calculated using the Nernst equation, which takes into account the concentration gradient of K+ ions across the membrane, as well as the valence of K+ ions and the temperature of the solution.

The Nernst potential for an ion at a given temperature is calculated using the Nernst equation:

E = (RT/zF) * ln([ion]out/[ion]in)

Where:

E is the Nernst potential (in mV)

R is the gas constant (8.314 J/K/mol)

T is the temperature (in Kelvin)

z is the valence of the ion

F is the Faraday constant (96,485 C/mol)

[ion]out is the concentration of the ion outside the cell (in mM)

[ion]in is the concentration of the ion inside the cell (in mM)

ln is the natural logarithm function

Using the values from the table given in the question, we can calculate the Nernst potential for K+ ions bathed in DMEM at 37°C:

Plugging in the values for K in DMEM:

E = (RT/zF) * ln([K+]out/[K+]in)

E = (8.314 * 310.15)/(1 * 96485) * ln(5.3/140)
E≈ 0.055 V

E ≈ 55 mV

Therefore, The correct option is A.

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You need to survive from extreme cold and extreme hot temperature, low air pressure with difficulty in breathing and no medium of sound travel, when you are in  thermosphere.

All life on Earth is shielded by the atmosphere, which is made up of gases that regulate temperature and reflect harmful solar rays. It shields living things from the sun's harmful rays.

From 80 to 400 km are in the thermosphere r above the mesopause. The earth's radio waves are reflected by this stratum. In this layer, as you ascend, the temperature begins to increase once more.

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The distance that the log has moved till it got to where Ernie reached Burt  would be 0.37m

We have the following details that would be used to get the solution to this problem

length of log = 4. 0 m

The mass of the log is 210 kg

The weight pof Burt = 40 . 5 kg

The weight of ernie would be 25.5 kg

The formula to be used would be in the form of

x(mass of log) + x(mass of Burt) + mass of ernie (x - length of wood)

such that we would have

210x + 40.5x + 25.5(x - 4) = 0

210x + 40.5x + 25.5x - 102 = 0

276x - 102 = 0

cross sign to the other side

276x = 102

To get the distance we would have to divide through by 276 and this value that we would get is going to be the x value

276x / 276 = 102 / 276

x = 0.369

~ 0.37m

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Answer:

It's dimension is (d) [M L-1 T-1]

We know By Einstein's Photoelectric Equation:

\({:\implies \quad \sf h\nu =h\nu_{0}+\dfrac{1}{2}m{v^{2}}_{max}}\)

\({:\implies \quad \sf h\nu =h\nu_{0}+eV_{0}}\)

\({:\implies \quad \sf eV_{0}=h\nu -h\nu_{0}}\)

\({:\implies \quad \sf V_{0}=\dfrac{h\nu}{e}-\dfrac{h\nu_{0}}{e}}\)

Since \({\nu}\) is plotted along X-axis and \({V_0}\) along Y-axis, it represents a straight line

(i) The slope of \({V_{0}}\) versus \({\nu}\) graph= (h/e) i.e it is a constant quantity and does not depend on the nature of the metal surface

(ii) The intercept on the \({\nu}\)-axis = \({(h\nu_{0}/e)}\) i.e it depends on the work function of the metal surface

Refer to the attachment for the graph

Answer:

Explanation:

a ) Restoring force in special spring F = k x³

let it is stretched by length l and it is further stretched by dl .

work done on spring in stretching by dl

= F dl

= k l³ dl

work done in stretching by A

= ∫k l³ dl between limit 0 to A

= k [ l⁴ / 4 ] between limit 0 to A

= k A⁴ / 4 ;

b )

Let v be the maximum speed attained ,

kinetic energy of mass = potential energy of spring

1/2 M v² = k A⁴ / 4

v² = kA⁴ / 2

v = A² √( k/2 )

c ) Let the required displacement be d .

potential energy = k d⁴ / 4

at displacement d , potential energy and kinetic energy are equal so potential energy = 1 /2 of total potential energy = 1/2 x k A⁴ / 4

= k A⁴ / 8

So

k A⁴ / 8  = k d⁴ / 4

\(d = A\times ( \frac{1}{2} )^\frac{1}{4}\)

Explanation:

To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:

Efficiency = (Output Work / Input Work) * 100

Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.

Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.

Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."

Using the velocity ratio, we have the following relationship:

dE / dL = 5

Now, we can calculate the input work (Wi) and the output work (Wo):

Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)

Output Work (Wo) = Load (L) * Distance moved by the load (dL)

Given that the efficiency is 80%, we can rewrite the formula for efficiency as:

0.80 = (Wo / Wi) * 100

Now, let's solve for the effort (E) using the given values:

Load (L) = 200N

Efficiency = 0.80

Velocity Ratio = 5

First, calculate the output work (Wo):

Wo = Load (L) * Distance moved by the load (dL)

Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):

dL = (1/5) * dE

Wo = L * (1/5) * dE

Wo = 200N * (1/5) * dE

Wo = 40N * dE

Next, calculate the input work (Wi):

Wi = Effort (E) * Distance moved by the effort (dE)

Wi = E * dE

Now, substitute the values into the efficiency formula:

0.80 = (Wo / Wi) * 100

0.80 = (40N * dE) / (E * dE) * 100

0.80 = 40 / E * 100

0.80 * E = 40

E = 40 / 0.80

E = 50N

Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.

The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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sound wave amplitude

Answer:

Using Ohm's law, we can calculate the current (I) by dividing the voltage (V) by the resistance (R):

I = V / R

Substituting the given values:

I = 54 V / 3 Ω

I = 18 A

Therefore, the current running through the fan when it's in use is 18 A.

Explanation:

Answer:

The values are \(I_L  =  500.37 \ mL / minutes \)

and \(I_r  = 299.63 \ mL / minutes \)  

Explanation:

From the question we are told that  

   The pressure at the bifurcation of the femoral artery is  \(P = 100\ mm\ Hg\)

   The pressure at the left or right femoral artery is  \(P_r = P_l  =  10 \  mm \  Hg\)

   The resistance in the  left femoral artery is  \(R_L\)

   The resistance in the  right  femoral artery is  \(R_r =  1.67 R_L\)

   The total  flow rate is  \(I = 800 mL/minute\)

The diagram illustrating this question is shown on the first uploaded image

Generally this flow of blood through the artery can be compared to the a circuit as shown on the first uploaded image

Generally the rate at which blood flows through the  left femoral artery is mathematically represented as

      \(I_L  =  I * \frac{R_r }{R_L + R_r}\)

=>      \(I_L  =  800 * \frac{1.67 R_L }{R_L + 1.67 R_L}\)

=>    \(I_L  =  800 * \frac{1.67 R_L }{2.67 R_L}\)

=>    \(I_L  =  500.37 \ mL / minutes \)

Generally the rate at which blood flows through the  right  femoral artery is mathematically represented as

      \(I_r  =  I * \frac{R_L }{R_L + R_r}\)

=>      \(I_r  =  800 * \frac{R_L }{R_L + 1.67 R_L}\)

=>    \(I_r  =  800 * \frac{ R_L }{2.67 R_L}\)

=>    \(I_r  = 299.63 \ mL / minutes \)    

Answer:

0.10 N

Explanation:

The drag force can be expressed using the following formula:

F = 1/2 * rho * A * Cd * v^2

Let's calculate the cross-sectional area of the sphere:

A1 = pi * r1^2

A1 = pi * (0.02 m)^2

A1 = 0.00126 m^2

Converting the speed to meters per second:

v1 = 0.1 m/s

Now we can use the formula to solve for the density times the drag coefficient:

rho * Cd = 2 * F / (A1 * v1^2)

rho * Cd = 2 * 8 N / (0.00126 m^2 * (0.1 m/s)^2)

rho * Cd ≈ 1.592 kg/m

For the second sphere with a radius of 4 cm and a speed of 5 cm/s, we can calculate the cross-sectional area and the speed in the same way:

A2 = pi * r2^2

A2 = pi * (0.04 m)^2

A2 = 0.00502 m^2

v2 = 0.05 m/s

Using the same value of the density times the drag coefficient:

F2 = 1/2 * rho * Cd * A2 * v2^2

F2 = 1/2 * (1.592 kg/m) * 0.00502 m^2 * (0.05 m/s)^2

F2 ≈ 0.10 N

Answer:

\(\frac{1}{512}\) seconds

Explanation:

T = 1 / f

    where T is the period and f is frequency.

Here the frequency is 512 Hz.

Using the formula:

                                  T = \(\frac{1}{512}\) seconds

Explanation:

Memory loss in retrograde amnesia has long been held to be larger for recent periods than for remote periods, a pattern usually referred to as the Ribot gradient. One explanation for this gradient is consolidation of long-term memories. Several computational models of such a process have shown how consolidation can explain characteristics of amnesia, but they have not elucidated how consolidation must be envisaged. Here findings are reviewed that shed light on how consolidation may be implemented in the brain. Moreover, consolidation is contrasted with alternative theories of the Ribot gradient. Consolidation theory, multiple trace theory, and semantization can all handle some findings well but not others.

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

Determine the maximum acceleration for these elevators

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N

At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

Answer:

1885.2 ohms

Explanation:

Step one:

given data

L=5H

f=60Hz

Required

The inductive reactance of the inductor

Step two:

Applying the expression

XL= 2πfL

substitute

XL=2*3.142*60*5

XL=1885.2 ohms

The difference between the earth's greenhouse effect and an actual greenhouse is that the glass in a greenhouse traps heat, while greenhouse gases in the atmosphere absorb and recycle heat. That is option B.

The greenhouse gas is the type of gas that is found in the earth's atmosphere that has the ability to absorb heat from the earth's environment.

Examples of greenhouse gases include the following:

An ordinary greenhouse is used to grow crops such as tomatoes and tropical flowers. Heat is bring trapped inside these houses as the sun shines during the day time.

Therefore, it can be concluded that the major difference between the earth's greenhouse effect and an actual greenhouse is that the glass in a greenhouse traps heat, while greenhouse gases in the atmosphere absorb and recycle heat.

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Answer:

d

Explanation:

Answer:

C

Explanation:

Horsepower refers to the power an engine produces. It's calculated through the power needed to move 550 pounds one foot in one second or by the power needs to move 33,000 pounds one foot in one minute. The power is gauged by the rate it takes to do the work.

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Have a nice day

Answer:

to answer the first part of the question.

what is the velocity after 5s.

a=(v-u)/t

a=10m/s²

u=0m/s( initial velocity)

t=5s

10m/s²=(v-0m/s²)/5s

10m/s²×5s=v-0m/s²

50m/s=v

the velocity after 5s will be 50m/s

to answer the second question we use the newton's second equation of linear motion, that is

S=(displacement)

S=ut+0.5at²

S=0m/s²×5s+0.5×10m/s²×(5s)²

S=0.5×10m/s²×(5s)²

S=5m/s²×(25s²)

S=125m

it had fallen 125m from where it was thrown.

HOPE IT HELPED,

PLEASE MARK BRAINLIEST