The magnetic flux through the loop is 0.089 T·m².
What is magnetic flux?
The magnetic flux, represented by the symbol Φ, is the amount of magnetic field passing through a given area. It's usually expressed in units of webers (Wb), which are equivalent to tesla meters squared (T·m²).
Formula to calculate magnetic flux:Φ = BA cos θWhere:Φ is the magnetic flux B is the magnetic field A is the area of the loopθ is the angle between the magnetic field and the loop's normal vector .
So, using the formula above, we can calculate the magnetic flux through the loop. Given:
B = 0.37 T
(uniform magnetic field)
A = 0.27 m² (area of the loop)θ = 43°
(angle between the magnetic field and the loop's normal vector)
Φ = BA
cos θΦ = 0.089 T·m²Therefore, the magnetic flux through the loop is 0.089 T·m².
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Which best describes a saturated solution?
A
Additional solvent is able to be dissolved in the solute.
B
Additional solute is able to be dissolved in the solvent.
С
The maximum amount of solvent is dissolved in the solute.
D
The maximum amount of solute is dissolved in the solvent.
The maximum amount of solute is dissolved in the solvent. The correct option is D.
What is a saturated solution?A saturated solution is a type of solution where the maximum amount of solute has been dissolved in a solvent, at a specific temperature and pressure, such that any additional solute added will not dissolve.
A saturated solution is a solution in which the maximum amount of solute has been dissolved in the solvent at a specific temperature and pressure. Any additional solute added to the solution will not dissolve and will instead settle at the bottom of the container as solid particles.
The concentration of a saturated solution is at its maximum level and cannot be increased further unless the temperature or pressure is changed.
Therefore, the correct option is D.
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Sub Science Project work
Represent an idea of to demonstrate your innovation on one of the following topic through practical.
Utilization of wastes
Model of plantation
Craft works for utilization and preservation Exploring energy sources.
Application based device
One innovative project idea related to the topic of exploring energy sources could be the development of a small-scale renewable energy system.
The project could involve designing and constructing a miniature model that demonstrates the utilization of renewable energy sources such as solar, wind, or hydroelectric power. The model could consist of solar panels to harness sunlight, a wind turbine to capture wind energy, or a small water turbine to generate electricity from flowing water. The energy generated by these sources could be stored in batteries or used directly to power various devices or components of the model.
The project could also incorporate an application-based device to monitor and control the energy system. This device could provide real-time data on energy production, consumption, and efficiency. It could also allow users to control the system remotely, adjust settings, and optimize energy usage.
By creating this practical demonstration, the project aims to raise awareness about the importance of renewable energy sources and promote sustainable energy practices. It provides an opportunity to showcase the potential of renewable energy and encourage further exploration and innovation in this field
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What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2
Answer:
7.5 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 2.5 kg
acceleration = 3.0 m/s²
We have
force = 2.5 × 3.0 = 7.5
We have the final answer as
7.5 NHope this helps you
a proton and an antiproton are moving toward each other in a head-on collision. if each has a speed of 0.8c with respect to the collision point, how fast are they moving with respect to each other?
A proton and an antiproton are moving toward each other in a head-on collision. If each has a speed of 0.8c with respect to the collision point, they are moving with respect to each other is: 4.44c
When a proton and an antiproton move toward each other in a head-on collision, if each has a speed of 0.8c with respect to the collision point. The formula that can be used to calculate the relative velocity of the proton and antiproton is:
\(v= (u1+u2) / (1+(u1 * u2) / c^2)\)
Here,v is the relative velocity of the proton and antiprotonu1 is the velocity of the protonu2 is the velocity of the antiproton is the speed of light. The given velocity of the proton and antiproton are u1=0.8c and u2= -0.8c.
The negative sign of antiproton is because the velocity is in the opposite direction. So substituting the given values in the above formula, we get
\(v = (0.8c + (-0.8c)) / (1 + (0.8c * (-0.8c)) / c^2)\)
\(v= 1.6c / (1 - 0.64)\)
\(v= 1.6c / 0.36v= 4.44cc\) is the speed of light
So the relative velocity of proton and antiproton is 4.44 times the speed of light. Therefore, the relative velocity of the proton and antiproton with respect to each other is 4.44c.
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During a snow day you decide to go sledding! You exert a force of 45N in order to pull a sled. You also perform 4723 J of work on the sled. Find the distance that you pulled the sled horizontally along the ground.
Physical systems that serve as framework for city growth are called __________.
A.
commuters
B.
gridlocks
C.
infrastructure
D.
freeways
Please select the best answer from the choices provided.
A
B
C
D
Answer:
C
Explanation:
if a needle had to be removed from a syringe, what would be the safest way to do so based on safe sharps work practices? remove the needle by twisting off the syringe directly by hand ask a colleague to hold the syringe while you twist the needle off by hand recap the needle with a forceps, then remove the needle from the syringe by hand use a needle box equipped with a needle removal device that permits the needle to fall directly into the needle box or sharps container when removed
The safely removing a needle from a syringe based on safe sharps work practices is to use a needle box equipped with a needle removal device that permits the needle to fall directly into the needle box or sharps container when removed.
This method ensures that the needle is immediately disposed of in a safe manner, reducing the risk of accidental needlestick injuries. It is important to never remove the needle by twisting off the syringe directly by hand, as this can cause the needle to become dislodged and potentially cause harm. Similarly, asking a colleague to hold the syringe while you twist the needle off by hand also poses a risk. Recapping the needle with forceps before removing it by hand is also not recommended, as it increases the risk of needlestick injuries. Therefore, using a needle box equipped with a needle removal device is the safest and most effective method for removing a needle from a syringe.
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Match the following terms with their definitions. Question 1 options: Evading Skills Physics Motor Skills Sending Skills Coordination & Balance Locomotor Movement Receiving Skills Non-Locomotor Movement Biomechanics Kinesiology 1. Applies to any motion of the body through space: running, jumping, diving, and so forth. 2. Refers to the combined actions of your brain, nervous system, muscles, joints, and bones that allow you to do anything from trying your shoes to heading a soccer ball. 3. Means catching or collecting an object. 4. Analyzes forms and patterns of movement in scientific terms. 5. Refers to the motion of the body while it remains anchored in the same spot, such as bending, squatting, twisting, or turning. 6. Includes throwing or striking an object. 7. Are ways of describing your ability to perform certain functions using your motor skills. 8. The study of human movement. 9. The study of matter and its motion, along with related concepts such as energy and force. 10. Refers to the act of dodging or faking.
Explanation:
i dont know
3. The pressure at the bottom of the ocean is great enough to crush submarines with steel walls that are 10 centimeters thick. Suppose a submarine is at a depth of 1,000 meters. The weight of water above each square meter of the submarine is 9,800,000 newtons.
Answer:
just awnsered this one your awnser is the the second option
Answer:
answer one
Explanation:
help will mark as brainliest
Answer: i guess d is the correct answer
Answer:
D
Explanation:
I used this and passed my test! good luck!
A boat has a maximum velocity of 12 m/s. If the boat is sailing in the direction of 45 degrees and the ocean current that is 2 m/s directly south, what is the actual speed of the boat and in what direction is the boat heading?
Answer:
speed of the boat = 10.67 m/s...
direction the boat is 38.2 degrees north of east...
Explanation:
To solve this problem, we can use vector addition.
Let the velocity of the boat be represented by vector B, which has a magnitude of 12 m/s and is directed 45 degrees north of east. We can represent this vector as:
B = 12 m/s at 45 degrees
Let the velocity of the ocean current be represented by vector C, which has a magnitude of 2 m/s and is directed directly south. We can represent this vector as:
C = 2 m/s at 270 degrees
To find the actual speed of the boat and the direction it is heading, we need to add these two vectors together using vector addition. To do this, we can break each vector into its x and y components:
Bx = 12 m/s * cos(45) = 8.49 m/s
By = 12 m/s * sin(45) = 8.49 m/s
Cx = 0 m/s
Cy = -2 m/s
Now, we can add the x and y components of the vectors separately:
Rx = Bx + Cx = 8.49 m/s + 0 m/s = 8.49 m/s
Ry = By + Cy = 8.49 m/s - 2 m/s = 6.49 m/s
The resulting vector R has a magnitude of:
|R| = sqrt(Rx^2 + Ry^2) = sqrt((8.49 m/s)^2 + (6.49 m/s)^2) = 10.67 m/s
And a direction of:
theta = arctan(Ry/Rx) = arctan(6.49 m/s/8.49 m/s) = 38.2 degrees
Therefore, the actual speed of the boat is 10.67 m/s and the direction the boat is heading is 38.2 degrees north of east...
2. On a par 4 golf course, you make the ball in:
1. Hole in one
2. Birdie
3. Par
4. Eagle
5. Double bogey
6. Triple bogey
7. Bogey
a. 7 shots from the tee
b. 5 shots from the teel
c. 1 shot from the tee
d. 4 shots from the tee
e. 3 shots from the tee
f. 2 shots from the tee
g. 6 shots from the tee
Using the t-table, give the confidence coefficients for each of the following: 3. n = 21 with 96% confidence 4. n = 27 with 92% confidence 2. n = 15m 95% confidence 1. n = 12 with 95% confidence
According to the question we have These t-values are the confidence coefficients for each of the scenarios given.
To find the confidence coefficients using the t-table, you need to first determine the degrees of freedom (df) and the corresponding t-value for each given confidence level.
1. n = 12 with 95% confidence:
Degrees of freedom (df) = n - 1 = 12 - 1 = 11
For a 95% confidence level, the t-value from the t-table is approximately 2.201.
2. n = 15 with 95% confidence:
Degrees of freedom (df) = n - 1 = 15 - 1 = 14
For a 95% confidence level, the t-value from the t-table is approximately 2.145.
3. n = 21 with 96% confidence:
Degrees of freedom (df) = n - 1 = 21 - 1 = 20
For a 96% confidence level, the t-value from the t-table is approximately 2.528.
4. n = 27 with 92% confidence:
Degrees of freedom (df) = n - 1 = 27 - 1 = 26
For a 92% confidence level, the t-value from the t-table is approximately 2.056.
These t-values are the confidence coefficients for each of the scenarios given.
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a student compared two samples of matter. he recorded the results in the chart. Sample A: Appearance: shiny and yellow. Sample B: Appearance: Dull and yellow. Which property do the two samples have in common? A. volume. B. color
Answer:
The answer are B
Explanation:the two samples haves yellow color :)
Answer:
B or 2
Explanation:
both of the samples contain a yellow color.
How long does it take water to freeze at 32 degrees ?
Water freezes more quickly when it is exposed to colder temperatures and when it is in a container with a large surface area, which allows for faster heat transfer.
Water freezes at 32 degrees Fahrenheit (0 degrees Celsius). The time it takes for water to freeze at this temperature depends on several factors such as the volume of water, the container it is in, and the environment in which it is located.
Assuming that the water is in a typical home freezer and the volume of water is not too large, it would typically take several hours for the water to freeze completely. The exact amount of time it takes for the water to freeze would depend on the volume of water and the temperature of the freezer.
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From the window of a house that is placed 15 m
high, a stream of water is thrown at 20 m/s with an
angle of 37° over the horizontal. Ignoring friction
with the air, calculate: (Consider g = 10 m/s 2 )
a) Distance from the base of the house at which the
water will fall.
b) Velocity at which the water will reach the
ground.
Answer:
a) 52.915 m
b) The vertical velocity is approximately 21.092 m/s
The resultant velocity is approximately 26.5 m/s
Explanation:
a) The height of the window in the house from which the water was thrown = 15 m
The speed of the stream of water thrown = 20 m/s
The angle at which the water was thrown = 37° over the horizontal
The acceleration due to gravity, g = 10 m/s²
a) The distance from the base of the house at which the water will fall is given as follows;
y = y₀ + u·t·sin(θ) + 1/2·g·t²
Where;
y = The vertical height reached
u = The initial velocity
t = Time of flight
From the point the steam of water is thrown, we get;
y₀ = 15 m
Therefore;
y = 15 + 20 × t × sin(37°) - 1/2 × 10 × t²
y = 15 + 20 × t × sin(37°) - 5 × t²
When y = 0, Ground level, we get
0 = 15 + 20 × t × sin(37°) - 5 × t²
5·t² - 20×sin(37°)×t -15 = 0
∴ t = (20 ×sin(37°) ± √((-20 × ·sin(37°))² - 4 × (5) × (-15)))/(2 × 5)
t ≈ 3.3128302, or t ≈ 0.906
Therefore, the time of flight of the water, t ≈ 3.3128302 seconds
The distance from the base of the house at which the water will fall = The horizontal distance travelled by the water, x
x = u·cos(θ)×t
∴ x = 20 × cos(37°) × 3.3128302 ≈ 52.915
The distance from the base of the house at which the water will fall = x ≈ 52.915 m
b) The velocity at which the water will reach the ground, 'v', is given as follows;
The vertical velocity, \(v_y\) = u·sin(θ)·t - g·t
At the ground, t ≈ 3.3128302 seconds
∴ \(v_y\) = 20 × sin(37) - 10 × 3.3128302 ≈ -21.092
The vertical velocity at which the water will reach the ground, \(v_y\) ≈ 21.092 m/s (downwards)
The resultant velocity, v = √(\(v_y\)² + vₓ²)
∴ v = √(21.092² + (0 × cos(37°))²) ≈ 26.5
The resultant velocity at which the water will reach the ground, v ≈ 26.5 m/s.
Rhyolite forms as lava cools very quickly, forming holes.
Sometimes gems can form within the holes. The image
shows fire opal within rhyolite.
Which type of rock is rhyolite?
A. Intrusive igneous
B. Extrusive igneous
C. Metamorphic
D. Sedimentary
PREVIOUS
Answer:
B. Extrusive igneous
Explanation:
Its B
A green ball has a mass of 0.525 kg and a blue ball has a mass of 0.482 kg. A croquet player strikes the green ball and it gains an initial velocity of 2.26 m/s. It then strikes the blue ball, which is initially at rest. After the collision, the green ball has a velocity of 1.14 m/s in the same direction. If the balls roll on a frictionless surface and the collision is head-on, what is the final velocity of the blue ball? (Round your answer to the nearest hundredths place.)
Answer:
v' = 1.21 m/s
Explanation:
Mass of a green ball, m = 0.525 kg
Mass of a blue ball, m' = 0.482 kg
Initial velocity of green ball, u = 2.26 m/s
Initial velocity of blue ball, u' = 0 (at rest)
After the collision,
The final velocity of the green ball, v = 1.14 m/s
We need to find the final velocity of the blue ball after the collision if the collision is head on. Let v' is the final velcity of the blue ball. Using the conservation of momentum to find it :
\(mu+m'u'=mv+m'v'\\\\0.525 (2.26)+0=0.525 (1.14)+0.482v'\\\\0.588=0.482v'\\\\v'=\dfrac{0.588}{0.482}\\\\v'=1.21\ m/s\)
So, the final velocity of the blue ball is 1.21 m/s.
What is radiation produces a wave full energy.
Answer:
electromagnetic radiation hopefully
bio froghopper jump a spittlebug called the froghopper (philaenus spumarius) is believed to be the best jumper in the animal world. it pushes off with muscular rear legs for 0.0010 s, reaching a speed of 4.0 m/s. determine its acceleration during this launch and the distance that the froghopper moves while its legs are pushing.
A. Acceleration during launch = 4000 m/s²
B. Distance that the froghopper moves while its legs are pushing = 0.002 m
Kinematics is sometimes regarded as a subfield of mathematics and is sometimes referred to as the geometry of motion. But in physics, it serves as the basis for classical mechanics. Without considering the forces that propel an item, kinematics studies how an object moves. It gives a description of the spatial positions of bodies or systems of material particles as well as the velocities and rates of change of those velocities.
t = 0.001 s
u = 4 m/s
PART A :
a = Δv / t
a = \(\frac{4m/s}{0.001s}\)
a = 4000 m/s²
Therefore, Acceleration during launch = 4000 m/s²
PART B :
S = ut + \(\frac{1}{2}\)at²
S = 0(0.001s) + \(\frac{1}{2}\) x 4000 m/s² (0.001)²
S = 0.002 m
Therefore, the Distance that the froghopper moves while its legs are pushing = 0.002 m
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A reference point is an object or location from which the movement of another object is determined. Which of the following could be a reference point?
a house
a point on a map
a moving car
a person
Answer: l, ll, lll, and lV
Explanation: Study island
Which of the arrows is in the direction of the net force on charge b?
The correct answer is option: e. Because, this force always acts along line joining the two charges. For like charges, the force is repulsive in nature.
The Coulomb's law states how charges interact with each other. That law states that: \(F =q1q24πϵ0r2\)
If the charges are like , the force will be repulsive, meaning that each charge will exert a force on the other to push the two of them apart. If charges are opposite , they will exert an attractive force on each other. G or unlike charges, the force is attractive as shown below: ( as Shown in image attached to question), As we know none of the arrow moves in the direction of the net force. Hence, the correct answer is option: e
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A car moving at a velocity of 25 m/s [N] accelerates at a constant rate of 1.5 m/s2 [N] for 4.0 s. What is the final velocity of the car?
Answer:
Vf = 31 m/s
Explanation:
Have to use the Final Velocity Formula - Vf = Vi + a * t
Vf = Final Velocity
Vi = Initial Velocity
a = acceleration
t = time
* = multiply
Vf = 25 + 1.5 * 4
Vf = 25 + 6
Vf = 31 m/s
The final velocity of the car is 31 m/s.
The magnitude of the angular momentum of the two-satellite system is best represented by
The magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.
What is angular momentum.?The rotational analog of linear momentum is angular momentum also known as moment of momentum or rotational momentum.
It is significant in physics because it is a conserved quantity. the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.
The magnitude of the angular momentum of the two-satellite system is best represented as;
L=∑mvr
L=m₁v₁r₁-m₂v₂r₂
Hence, the magnitude of the angular momentum of the two-satellite system is best represented as, L=m₁v₁r₁-m₂v₂r₂.
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Two students are conducting an experiment in which they are trying to find a relationship between
the angle of incline of a ramp and the final speed a car reaches when rolling down the ramp. In
order to collect their data, the students must determine the final speed of the car at the bottom of
the ramp. The students discuss how they should determine this speed.
Student 1: "We need to measure the length of the ramp and the time it takes the car to roll down it.
Then we can divide the total distance by the total time to find the final speed."
What is wrong with Student 1's method for determining final speed?
1) This method does not account for the height of the ramp.
2) This method does not take into account the angle of the ramp.
3) This method will determine the acceleration, not the final speed.
4) This method will only determine the average speed, not the final speed.
This method will only determine the average speed, not the final speed. This is wrong with Student 1's method for determining final speed.
Speed is a rate of change of distance with respect to time. i.e. v =dx÷dt. Speed can also be defined as distance over time i.e. speed= distance ÷ time it is denoted by v and its SI unit is m/s. it is a scalar quantity. i.e. it has only magnitude not direction. ( velocity is a vector quantity, it has both magnitude and direction. when we define velocity, we should know about its direction) Speed shows how much distance can be traveled in unit time. As speed is scalar quantity it has nothing to do with the direction. student 1 has not considered the height and angle hence it tells about average velocity not the final velocity.
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Julietta and Jackson are playing miniature golf. Julietta's ball rolls into a long. Straight upward incline with a speed of 2.95 m/s and accelerates at -0.876 m/s/s for 1.54 seconds until it reaches the top of the incline and then continues along an elevated section. Determine the length of the incline.
Answer:
The length of the incline is 3.504 meters.
Explanation:
Let suppose that Julietta's ball decelerates uniformly, then we determine the length of the incline is determined by the following equation of motion:
\(\Delta s = v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}\) (Eq. 1)
Where:
\(\Delta s\) - Length of the incline, measured in meters.
\(v_{o}\) - Initial speed of the ball, measured in meters per second.
\(a\) - Aceleration of the ball, measured in meters per square second.
\(t\) - Time, measured in second.
If we know that \(v_{o} = 2.95\,\frac{m}{s}\), \(t = 1.54\,s\) and \(a = -0.876\,\frac{m}{s^{2}}\), then the length of the incline is:
\(\Delta s = \left(2.95\,\frac{m}{s} \right)\cdot (1.54\,s)+\frac{1}{2}\cdot \left(-0.876\,\frac{m}{s^{2}} \right) \cdot (1.54\,s)^{2}\)
\(\Delta s = 3.504\,m\)
The length of the incline is 3.504 meters.
tms works by a. passing a magnetic current through an electrode into the brain whose shape determines the properties and the size of the resulting magnetic field. b. passing an electric current through a magnetic coil into the brain whose shape determines the properties and the size of the resulting magnetic field. c. passing a chemical stimulus through a magnetic coil into the brain whose shape determines the properties and the size of the resulting magnetic field d. passing an electric current through a wire coil into the brain whose shape determines the properties and the size of the resulting magnetic field. e. passing an electric current through an electrode into the brain whose shape determines the properties and the size of the resulting magnetic field.
Tms works by : (c) passing an electric current through a wire coil into the brain whose shape determines the properties and the size of the resulting magnetic field.
What is the TMS's mechanism of action?
By introducing a brief capacitor discharge of electrical current into a stimulated coil, which then generates a magnetic field and induces neural cell membrane potentials, transcranial magnetic stimulation (TMS) is a flexible technique that non-invasively modifies neural processing in the brain.
This coil emits magnetic pulses that activate the brain's mood-control and depressive disorder-related nerve cells. It is believed to stimulate brain areas whose activity declines during depression. Similar to an MRI scanner, the majority of TMS magnets produce magnetic fields that are 1.5T to 2T in strength. However, because the TMS magnet is so much smaller than an MRI, the magnetic field's surface area is considerably less.
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Find the resultant of these two vectors: 200 units due east and 400 units 30.0° north of west.
The resultant of the two given vectors is 346.4 units.
What is the resultant of the three vectors?The resultant of the three vectors is the sum of all the three vectors acting together. The resultant vector is the single vector that will represent all the three vectors in terms of magnitude and direction.
The sum of the vectors in x-direction;
Vx = V cosθ
where;
θ is the angle of inclination of each vectorfor 200 units, θ = 0⁰ (above the horizontal)
for 400 units, θ = 60⁰ (above the horizontal)
Vx = 200 cos(0) - 400 cos(60)
Vx = 0
The sum of the vectors in y-direction;
Vy = 200 sin(0) + 400 sin(60)
Vy = 346.4 units
The resultant vector is calculated as;
V = √(Vx² + Vy²)
V = √(0² + 346.4²)
V = 346.4 units
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Distinguish between kinectic energy and potential energy
Answer:
kinectic energy-in physics kinetic energy of an object is the energy that it possesses due to its motion
it is defined as the work needed to accelerate a body of a given mass from rest to its started velocity.having gained this energy during its accelerationThe body maintains this kinetic energy unless its speed changes.
potential energy-in physics potential energy is the energy held by an object because of its position relative to other objects,its electric charge,or other factors
in the case of a bow and arrow ,when archer does work on the bow drawing the string back some if the chemical energy of the archer's body is transformed into elastic potential energy in the bent limb of bowAnswer:
Hey!
Well KINETIC ENERGY is...
the energy generated by the / of the object is that it possesses due to its motion...
POTENTIAL ENERGY is...
The energy held by an object because of its position relative to other objects, its electric charge, or other factors...
Explanation:
So in easier terms, KINETIC ENERGY is just the ENERGY GENERATED BY THE OBJECT'S MOVEMENT and...
POTENTIAL ENERGY IS THE TOTAL AMOUNT OF ENRGY THAT THE OBJECT HOLDS (due to an electric charge etc)
Hope this helps!
Pleasee help mee
a circular coil of 100 turns and cross-sectional area of 2. 0 cm² carrying a 50 mA current is placed in a magnetic field of 0. 5 T parallel to the plane of the coil. Calculate the torque acting on the coil?
A circular coil of 100 turns and a cross-sectional area of 2. 0 cm² carrying a 50 mA current is placed in a magnetic field of 0. 5 T parallel to the plane of the coil. The torque acting on the coil is 0.01 Nm.
The torque acting on a circular coil placed in a magnetic field can be calculated using the formula: \(T = NABsin\theta\) , where N is the number of turns in the coil, A is the area of each turn, B is the magnetic field strength, and θ is the angle between the magnetic field and the plane of the coil.
Substituting the given values, we have
\(T = (100)(2.0 \times 10^{-4} m^2)(0.5 T)sin90^{\circ}\)
T = 0.01 Nm.
Therefore, the torque acting on the coil is 0.01 Nm.
In this scenario, a magnetic field is acting parallel to the plane of the coil, which results in the maximum torque being produced, and thus, the value of the angle θ is 90°.
The magnetic field generates a force on each turn of the coil, and this force creates a torque that makes the coil rotate around an axis perpendicular to the magnetic field. The greater the number of turns in the coil, the greater the torque produced.
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