The induced current moves in a clockwise direction.
Induced current is formed in a conductor as a result of a change in the magnetic flux flowing through the area.
The magnetic field vector in the conducting loop is pointing straight up.
A current is induced in the magnetic field as a result of the constant strength increase.
The induced current moves in a clockwise direction when seen from above.
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Here is my question.
A ball is thrown vertically upward from the surface of theearth. Consider the following quantities:
1. the speed of the ball. 2. The velocity ofthe ball 3. The acceleration of the ball
Which of these is (are) zero when the ball has reached themaximum height?
a. 1 b. 2 only c. 1 and 2 d. 1 and 3 e. 1,2, and 3
Please tell my why when you have the answer.
A ball is thrown vertically upward from the surface of the earth. both velocity and speed will become zero at highest point. so correct option is c. 1 and 2
what is velocity and speed ?Speed is a scalar quantity and velocity is a vector. Speed only determines the magnitude that is how fast is a body moving whereas velocity determines the direction also that is in which direction the body is moving. Speed is the rate of change of distance whereas velocity is the rate of change of displacement.
Velocity is a measure of how fast something moves in a particular direction. To define it needs both magnitude and direction.
At highest point acceleration is not zero because we have acc due to gravity acting downwards.But since velocity and speed is zero the ball reaches the ground back
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i need help to find the answer
Answer:
Virtual, erect, and equal in size to the object. The distance between the object and mirror equals that between the image and the mirror.
the density of mercury is 13.5 g/ml and the density of water is 1.00 g/ml . if a mercury barometer reads 803 mmhg , what is the barometric pressure in centimeters of water ( cmh2o )?
The barometric pressure in centimeters of water (cmH₂O) if a mercury barometer reads 803 mmHg and the density of mercury is 13.5 g/mL and the density of water is 1.00 g/mL is 1033.25 cmH₂O.
1. Convert 803 mmHg to cmH₂O using the conversion factor 1 mmHg = 1.36 cmH₂O.
803 mmHg × 1.36 cmH₂O/mmHg = 1092.08 cmH₂O.
2. Determine the pressure due to the mercury column using the density of mercury and the height of the mercury column. The height of the mercury column is the same as the pressure reading in mmHg.
Pressure = density × gravity × height. 13.5 g/mL × 9.81 m/s² × (803 mmHg ÷ 760 mmHg/atm) × (1 atm/101325 Pa) = 101.47 kPa.
3. Determine the pressure due to the air above the mercury column. This is the difference between the atmospheric pressure and the pressure due to the mercury column.
Atmospheric pressure = 1 atm = 101.325 kPa.
Pressure due to air = atmospheric pressure − pressure due to mercury column.
Pressure due to air = 101.325 kPa − 101.47 kPa = −0.145 kPa.
4. Convert the pressure due to air to centimeters of water using the conversion factor 1 cmH₂O = 0.098 kPa. −0.145 kPa × (100 cmH2O/0.098 kPa) = −148.47 cmH2O.5.
Add the pressure due to the mercury column and the pressure due to the air to get the barometric pressure in cmH₂O.
Barometric pressure = pressure due to mercury column + pressure due to air.
Barometric pressure = 1092.08 cmH₂O + (−148.47 cmH₂O) = 943.61 cmH₂O.
However, since the pressure due to the air is negative, the actual barometric pressure is higher than the calculated value.
The correct answer is 1092.08 cmH₂O − 148.47 cmH₂O = 943.61 cmH₂O + 1090.86 cmH₂O = 1033.25 cmH₂O.
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Choose the polar molecule.
A. C
B. CH4
C. H20
D. F2
Answer : H20
Explanation:
A student releases a ball from rest on an inclined plane and measures that it travels a distance of 0.6 m in a time of 4.0 s. Find the average speed of the ball.
The average speed of the ball is 0.15 m/s.
The average speed of the ball can be calculated using the formula below.
Average speed:This is the ratio of the total distance to the total time traveled by a body
Formula:S = d/t.................. Equation 1Where:S = Average speedd = total distancet = total time.From the question,
Given:d = 0.6 mt = 4.0 sSubstitute these values into equation 1
S = 0.6/4S = 0.15 m/sHence, the average speed of the ball is 0.15 m/s.
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Which of the following correctly lists our "cosmic address" from small to large?
a. Earth, solar system, Milky Way Galaxy, Local Group, Local Supercluster, universe
b. Earth, solar system, Local Group, Local Supercluster, Milky Way Galaxy, universe
c. Earth, Milky Way Galaxy, solar system, Local Group, Local Supercluster, universe
Our "cosmic address" from small to large are earth, solar system, milky way galaxy, local group, local supercluster, universe (option A)
The "smallest" is earth, it is the planet where we live and the third of the eight planets in the solar system.
The solar system is a collection of celestial bodies consisting of a star called the sun and all the objects that are bound by its gravitational force. And the milky way galaxy is the galaxy that contains our solar system. It is a barred spiral galaxy 100,000-120,000 light years in diameter containing 100-400 billion stars.
The local group is the group of galaxies that includes the milky way among others. It consists of more than 54 galaxies, including dwarf galaxies.
The local supercluster is one of the largest known cosmic structures in the universe. They are large, threadlike formations, with a typical length of 50 to 80 megaparsecs h-1, which form the boundaries between the great voids in the universe.
The universe is isotropic, the distance to the edge of the observable universe is approximately the same in all directions. That is, the observable universe is a spherical (spherical) volume centered on the observer, regardless of the shape of the universe as a whole.
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Answer:
Our "cosmic address" from small to large are earth, solar system, milky way galaxy, local group, local supercluster, universe (option A)
Blank is a good way to for me to see where I am going while
dribbling
Answer:
???
Explanation:
Use the inteediate value theorem to prove the following claim. There is at least one number that is three greater than twice its fifth power. (Remember, whenever you apply a theorem, you must explain why its hypotheses are satisfied; it is not sufficient to merely assert that they are satisfied.)
The claim that there is at least one number that is three greater than twice its fifth power can be proven using the Intermediate Value Theorem.
To apply the Intermediate Value Theorem, we need to show that the function f(x) = \(2x^5\)+ 3 is continuous on a closed interval [a, b] and takes on both positive and negative values.
1. Continuity:
The function f(x) = \(2x^5\) + 3 is a polynomial function, and polynomial functions are continuous for all real numbers. Therefore, f(x) is continuous on the entire real number line.
2. Positive and Negative Values:
To show that f(x) takes on both positive and negative values, we can consider the limits of f(x) as x approaches positive and negative infinity:
- As x approaches positive infinity, the term \(2x^5\) dominates the function, and f(x) approaches positive infinity.
- As x approaches negative infinity, the term \(2x^5\) dominates the function, and f(x) approaches negative infinity.
Since f(x) approaches both positive and negative infinity as x approaches infinity and negative infinity respectively, it must take on all values in between, including positive and negative values.
By the Intermediate Value Theorem, since f(x) is continuous on the real number line and takes on both positive and negative values, there must exist at least one number c for which f(c) = 0. In other words, there is at least one number that is three greater than twice its fifth power.
In conclusion, by satisfying the hypotheses of the Intermediate Value Theorem, we can prove the claim that there is at least one number that is three greater than twice its fifth power.
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If mass of an empty 7.0 mL pycnometer is 10.2g and the mass of the same pycnometer with an unknown liquid is 21.8g. Determine the density of the unknown liquid to ONE DECIMAL PLACE in g/mL.
The formula for calculating density is expressed as
Density = mass/volume
From the information given,
mass of empty pycnometer = 10.2
mass of the same pycnometer with an unknown liquid is 21.8.
Mass of unkown liquid = 21.8 - 10.2 = 11.6
volume of unknown liquid = 7
Thus,
Density = 11.6/7
Density = 1.7 g/ml
help pls help pls help pls help pls help pls
A certain simple pendulum has a period on earth of1.72{\rm s}.
What is its period on the surface of Mars,where the acceleration due to gravity is 3.71student submitted image, transcription available below?
The answer is that the period of the simple pendulum on Mars is 2.66 s. The period of a simple pendulum on Mars is to be determined, given that the period on Earth is 1.72 s and the acceleration due to gravity on Mars is 3.71 m/s².
We know that the time period of a simple pendulum is given as:
`T=2π√(l/g)`Where, T is the time period of the pendulum, l is the length of the pendulum, g is the acceleration due to gravity
We also know that, `g_mars/g_earth = (R_earth/R_mars)^2`, Where, g_mars and g_earth are the acceleration due to gravity on Mars and EarthR_earth and R_mars are the radius of the Earth and Mars respectively
We can use the above equation to determine g_mars.
Step 1: Determine g_mars/g_earth: `g_mars/g_earth = (R_earth/R_mars)^2`⇒`g_mars/g_earth = (6378.1/3389.5)^2`⇒`g_mars/g_earth = 3.73`
Therefore, acceleration due to gravity on Mars, `g_mars = 3.73 × 9.8 = 36.6 m/s²`
Step 2: Determine the period on Mars: We know that,`T=2π√(l/g)` Given that the length of the pendulum remains constant, we can use the following equation to determine the period of the pendulum on Mars.`
T_mars/T_earth = √(g_earth/g_mars)`
Therefore,`T_mars/T_earth = √(9.8/3.71)`
From the above equation, we can determine `T_mars` by substituting `T_earth = 1.72 s`. `T_mars = T_earth × √(g_earth/g_mars)`
Putting the given values,`T_mars = 1.72 × √(9.8/3.71)`
Therefore,`T_mars = 2.66 s`
Therefore, the period of the simple pendulum on Mars is 2.66 s.
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Consider the nozzle on a turbojet engine. If the nozzle is isentropic, what can you say about the outlet temperature compared to a nozzle with some irreversibility?
a.The isentropic nozzle outlet temperature will be higher
b. The isentropic nozzle outlet temperature will be the same
c. The isentropic nozzle outlet temperature will be lower
d. Not enough information
(a) The isentropic nozzle outlet temperature will be higher than a nozzle with some irreversibility in a turbojet
If the nozzle on a turbojet engine is isentropic, it means that the process of the gas flow through the nozzle is reversible and adiabatic. This implies that there is no entropy generation during the expansion of the gas through the nozzle. In other words, the isentropic nozzle is a theoretical ideal case where the gas undergoes a perfect adiabatic expansion.
In contrast, a nozzle with some irreversibility, such as friction or heat transfer to the surroundings, will generate entropy during the expansion of the gas through the nozzle. This means that the temperature at the outlet of the nozzle will be lower than that of the isentropic nozzle, because some of the energy is lost due to the irreversibility.
Therefore, the correct answer is (a) the isentropic nozzle outlet temperature will be higher than a nozzle with some irreversibility. This is because in an isentropic nozzle, the gas expansion is adiabatic and reversible, so there is no loss of energy due to irreversibility, and the gas will exit the nozzle at a higher temperature than in a nozzle with some irreversibility.
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In the Compton effect experiment, the change in a photon's wavelength depends onA. the scattering angle.B. the initial wavelength.C. the final wavelength.D. the density of the scattering material.E. the atomic number of the scattering material.
The density of the scattering material and the atomic number of the material may affect the probability of scattering but do not directly influence the change in wavelength. So the correct answers are A and B.
In the Compton effect experiment, the change in a photon's wavelength depends on the scattering angle and the initial wavelength of the photon. The Compton effect is the result of the interaction of a photon with a charged particle, typically an electron. When a photon collides with an electron, it transfers some of its energy to the electron, causing the photon to scatter at a different angle and with a different wavelength. The amount of energy transferred to the electron depends on the initial energy of the photon, which is related to its wavelength, and the angle of scattering. The final wavelength of the scattered photon can be calculated using the initial wavelength and scattering angle. The density of the scattering material and the atomic number of the material may affect the probability of scattering but do not directly influence the change in wavelength. (Option A & B)
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can someone please answer this, ill give you brainliest and your getting 100 points.
Answer:
Point number 3.
Explanation:
Volcanism can be studied to found out evidence of the internal structure of the Earth.
Answer:
Volcanism
Explanation:
Volcanism refers to study about the creation of volcanos.We know the earth's inner side is filled of magma which gets out through volcanos.So volcanism should be learntplease type any energy transformation it will help a lot i would really appreciate it
prize: brainliest
Answer:
in electric lamp
Electric Energy to Heat and Light Energy
Explanation:
Answer:
Ex: an electric fan transforms electric energy to kinetic energy
Or
Chemical energy to heat and light energy
Explanation:
Hope this helps
an object is placed at dist 25cm in front of concave mirror and image has magnification of -2 .find focal length
Answer:
Given,
Object distance, u=25cm
Focal length, f=20cm
From mirror formula
f
1
=
v
1
+
u
1
−20
1
=
v
1
−
25
1
⇒
v
1
=−
20
1
+
25
1
v=100cm
The image will be real, inverted magnified
Explanation:
Given,
Object distance, u=25cm
Focal length, f=20cm
From mirror formula
f
1
=
v
1
+
u
1
−20
1
=
v
1
−
25
1
⇒
v
1
=−
20
1
+
25
1
v=100cm
The image will be real, inverted magnified
I need help again this is really important this is due tomorrow
D, invisible is not a way light can be transmitted.
How can light be transmitted?Light can be transmitted through a medium such as air, water, glass, or a vacuum. When light is transmitted, it passes through the medium without being absorbed or reflected, allowing it to be seen on the other side of the medium. Transmission of light can occur in a straight line or can be refracted or diffracted, depending on the properties of the medium it is passing through.
Light can be absorbed by a material, which means that the energy of the light is transferred to the material. When this happens, the material may become excited, and the energy can cause a change in the material, such as heating it up, causing it to emit light, or causing a chemical reaction.
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T/F : water beads up on wax paper because its cohesive forces are greater than the adhesive forces.
The given statement is true as the its cohesive forces are greater than the adhesive forces.
Water beads up on wax paper because the cohesive forces between water molecules are greater than the adhesive forces between water and the wax paper surface. The cohesive forces between water molecules cause them to stick together, forming a droplet shape. The adhesive forces between the water and the wax paper surface are not strong enough to overcome the cohesive forces within the water droplet, so the droplet beads up into a ball.
This is because the cohesive forces between water molecules are strong due to the hydrogen bonds that form between them. Meanwhile, the adhesive forces between the water and the wax paper surface are weaker because the surface of the wax paper is hydrophobic (water-repelling) due to its non-polar nature.
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Can someone help me on boding elements? please im struggling. look at the picture and also if you answer can you have a picture of it written out like it is. :)
Answer : the first product for carbon dioxide is C2CNT. Product: Carbon nanotubes, carbon fiber. the second product for hydrogen is fertilizer. a product for oxygen is water. the reactants of carbon dioxide is carbon dioxide (CO2), water (H2O), and usable energy. the reactants of hydrogen is Both hydrogen and oxygen gases exist as diatomic (“two-atom”) molecules. the reactants of oxygen is oxygen gas and the 2 in front of the water vapor are called the reaction coefficients.
Explanation: your welcome everyone!
Which is a TRUE statement about a series circuit
A. the charge has only one path through which it can flow.
B. The current through the circuit can take several paths
C. every part of the circuit is negatively charged
sistanc
ed to as
D. every part of the circuit is positively charged
Please answer this I have 20 minutes to finish this test
Answer:
A the charge has only one path through which it can flow.
6 latter word and it has a s and a I and it has mass (9.______________liquids, and gases all have mass.)
Answer:
Solids
Explanation:
Solids, liquids, and gases all have mass.
Particles q1, 92, and q3 are in a straight line.
Particles q1 = -28.1 uc, q2 = +25.5 uc, and
q3 = -47.9 uc. Particles q1 and q2 are separated
by 0.300 m. Particles q2 and q3 are separated by
0.300 m. What is the net force on q3?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-28.1 μC:
+25.5 °C
-47.9 uc
The particle when placed nearby at a distance, the force acting between the charges will be towards each other. The net force on q₃ is 88.496 N.
What is the electrostatic force?The force between the charged particles when they are kept a distance apart is called electrostatic force.
Referring to the figure, Particles q₁ = -28.1 μC = -28.1 x 10⁻⁶, q₂ = +25.5 μC =+25.5 x 10⁻⁶, and q₃ = -47.9 μc =-47.9 x 10⁻⁶ C kept at distance r = 0.3 m
Net force on q₃ , F₃ = F₁₃ - F₃₂
F₃ = k q₁q₃ / (0.3 +0.3)² + k q₂q₃ / (0.3 )²
where k = 9 x 10⁹ N.m²/C²
Substitute the values into the equation, we get the net force.
F₃ = 88.496 N
Therefore, the net force on q₃ is 88.496 N.
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Answer:
-88.496
Explanation:
acellus
It takes Miss Slotman 4 seconds to go from a speed of 3 m/s to a speed of 10 m/s. What is
her acceleration?
PLS HELP!!!! ASAP:(
Answer:
so to find the acceleration we divide the change in velocity by the time taken for it so intial velocity was 3m/s and final velocity is 10m/s. we substract 3 from 10 to get the change in velocity ie 10m/s -3m/s = 7m/s. now decide this by the time taken for it that is 4 sec as given. acceleration is 7/4 = 1.75m/s^2
explain why at the atomic level, conductors move charge easily and insulators do not
Point l is located a distance d2–√ from the midpoint between the two wires. Find the magnitude of the net magnetic field bl created at point l by both wires.
the magnitude of the magnetic field bl created at point l by both wires. is 0.0071 μI / d
since we know the formula we can refer to the magnetic field is
B= μI / 2πR
where I is the current flowing through the wires, R is the distance
Here Using the Pythagoras theorem
R= √d² + (2d)²
R = √d² + 4d²
r = √5d²
r = d√5
substituting the value of R in the formula, we get
= μI / 2π(d√5)
= μI / 2dπ√5
= (1 / 2π√5)(Iμ/d)
=0.0071 μI / d
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the easting coordinate for a point is 632,506.084 m. what is the coordinate using the international foot definition?
Using the international foot definition, the easting coordinate of 632,506.084 m can be converted to feet, which is equal to 0.3048 meters.
Simply multiply the value in meters by the conversion factor to convert the coordinate:
632,506.084 meters * (1 foot/0.3048 meters) = 2,073,587.719 feet
As a result, using the international foot definition, the easting coordinate is 2,073,587.719 feet. It is important to note that the use of different units can affect the accuracy and precision of the coordinate, so when working with geographic data, it is critical to use the correct unit definition and conversion factors.
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An object travels 40 m in 4 s and then another 50 m in 5 s .What is the average speed of the object?
Answer:
10m/sExplanation:
Average speed is the change in distance of a body/object with respect to time. Speed is expressed by the expression;
Speed = \(\frac{change\ in\ distance}{change\ in\ time}\)
speed ΔV = ΔS/Δt
ΔV = S₂-S₁/t₂-t₁
given S₂ = 50m, S₁ = 40m, t₂ = 5s, t₁ = 4s
average speed = 50-40/5-4
average speed = 10/1
average speed = 10m/s
average speed of the object is 10m/s
Someone is singing in a shower that measures 2. 40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz
When a person sings in a shower and causes the shower to resonate with a fundamental frequency of 73 Hz, this is an example of a standing wave, also known as a resonance.
The fundamental frequency of a standing wave is determined by the length of the resonant cavity, which in this case is the shower. The fundamental frequency is related to the length of the cavity by the equation:
f = v / 2L
where f is the frequency, v is the velocity of sound in the medium (in this case, air), and L is the length of the cavity. Given that the shower has a length of 2.40 meters and the fundamental frequency is 73 Hz, we can use the equation above to calculate the velocity of sound in air.
73 = v / (2 * 2.40)
Solving for v, we get:
= v
= (73 * 2 * 2.40)
= 350.4 m/s
The speed of sound in air is approximately 343 m/s at 20 °C at sea level. The velocity of sound in air can change with temperature, humidity and pressure. Given that the velocity of sound in air is around 343 m/s, the frequency of 73 Hz is a close match to the fundamental frequency of the shower with 2.40 meters high, It is important to note that the fundamental frequency is not the only frequency that could resonate in the shower, other overtones and harmonics might also resonate.
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Question- Someone is singing in a shower that measures 2.40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz. Here, this situation is an example of? justify. The given situation is an example of which physics phenomenon and justify the given example with some details.
ector has a magnitude 5.00 and points in a direction 60.0° clockwise from the negative y axis. what are the x and y components of vector .
The x and y components of vector A are directed along negative X and Y axes respectively having magnitudes 4.330 and 2.5 units respectively.
Let the vector be taken as A.
Magnitude of the vector A = |A| = 5 units
We are aware that the positive X-axis and the negative Y-axis form a 270° anti-clockwise angle.
θ = Angle of vector A with positive X-axis = (270° - 60°) = 210°
So, x component of vector A = A x = |A| × cos 210° = |A| × cos (180° + 30°) = |A| × (- cos 30°) = 5 × (-0.866) = -4.330
And, y component of vector A = Ay = |A| × sin 210° = |A| × sin (180° + 30°) = |A| × (- sin 30°) = 5 × (-0.5) = -2.5
Thus, Ax and Ay both are negative relative to positive X and Y axes respectively. So, the x and y components of vector A are directed along negative X and Y axes respectively with magnitudes 4.330 and 2.5 units respectively.
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Jimmy held the end of a metal bar over a fire while holding on to the opposite end. After a few minutes, the end he was holding began to get very hot. Which of the following processes correctly describes the heat traveling from one end of the bar to the other?
Answer:
Hey mate....
Explanation:
This is ur answer....
The heat is transferred by the process of conduction of heat.
It is given that, Jimmy held the end of a metal bar over a fire while holding on to the opposite end.
After some time, the end he was holding began to get very hot.
The process of traveling heat from one end of the bar to the other end is called conduction. It is the process of transfer of heat by the interaction of particles and motion of electrons.
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