The answer is B. It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons.
Given the data from the question, the correct statement is:
It has a central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons (Option B) Composition of atomAn atom is composed of a centrally placed nucleus (containing protons and neutrons) and a cloud of electrons revolving round it.
How to determine the number of neutrons Mass number = 64Proton = 29Neutron =?Mass number = Proton + Neutron
64 = 29 + Neutron
Collect like terms
Neutron = 64 – 29
Neutron = 35
Note
Proton = Electron = 29 (since the atom is neutral)
Thus, we can conclude that the atom has central nucleus composed of 29 protons and 35 neutrons, surrounded by an electron cloud containing 29 electrons (Option B)
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A body accelerate uniformly from rest at 0.2m/s for one-fifth of a minute. Calculate the distance covered by the body.
Answer:
14.4 mThe distance covered by the body is 14.4 m.
Solution,
Initial velocity(u)= 0 m/s( according to Question, the body starts from rest.that's why initial velocity(u) becomes zero.
Acceleration (a)= 0.2 m/s
Time (t):
\( \frac{1}{5} minute = \frac{1}{5 } \times 60 \: seconds\)
\( = 12 \: seconds\)
Now,
Applying third equations of motion:
\(s = ut + \frac{1}{2} a {t}^{2} \\ s = 0 \times 12 + \frac{1}{2} \times 0.2 \times {(12)}^{2} \\s = 0 + 14.4 \\ s = 14.4 \: metre\)
Thus, the distance covered by the body is 14.4 metre.
Further more information:
Application of equation of motion in different situation:When a certain object comes in motion from rest, in the case, initial velocity(u)= 0 m/sWhen a moving object comes in rest,in the case, final velocity(v)= 0 m/sIf the object is moving with uniform velocity, in the case, (u=v)If any object is thrown vertically upward, in the case, acceleration (a)= -gWhen an object is falling from certain height, in the case, u= 0 m/sWhen an object is thrown vertically upwards in the case, final velocity at maximum height becomes 0.9-47 in an elastic collision, a 400.0-kg bumper car collides directly from behind with a second, identical bumper car that is traveling in the same direction. the initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s. assuming that the mass of the drivers is negligible, find the final speeds of both cars relative to the ground after the collision?
The final speeds of both cars relative to the ground after the collision are V₁ = 6 m/s and V₂ = 5.6 m/s respectively.
An elastic collision is a collision in which there is no internet loss in kinetic energy within the gadget because of the collision. each momentum and kinetic electricity are conserved portions in elastic collisions.
Given;
m₁ = m₂ = 400 kg
v₁ = 5.6 m/s
v₂ = 6 m/s
According to the law of conservation of momentum,
m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂
According to the law of conservation of energy,
m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2
Now, applying the law to momentum and law of conservation of energy,
m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂
5.6 + 6 = v₁ + v₂ ----------------(1)
m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2
(5.6)² + (6)² = (v₁)² + (v₂)²
67.36 = (v₁)² + (v₂)² ---------------(2)
From equation 1 and 2
V₁ = 6 m/s and V₂ = 5.6 m/s
An elastic collision is a come between two bodies in which the full kinetic energy of the two bodies remains equal. In an ideal, perfectly elastic collision, there may be no internet conversion of kinetic strength into other kinds which includes heat, noise, or capacity electricity.
Elastic collisions arise whilst both the momentum and kinetic energy are conserved, just like how billiard balls bounce off each different and move at the same speeds as earlier. Inelastic collisions appear whilst simplest the momentum is conserved but not the kinetic power.
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Ricardo looked out of a window at his home and saw snow falling on the mountains nearby. He knew that the snow would arrive near his home soon. Ricardo lives in the mountains along the west coast, where the winds blew off the Pacific Ocean. Multiple factors contribute to an area’s climate. Identify three of these factors, and explain how they determine the climate in an area.
Climate in an area is determined by a complex interplay of factors, including mountains latitude, topography, and atmospheric circulation patterns. Understanding these factors is crucial in predicting weather patterns.
Three factors that contribute to an area's climate are:
1) Latitude: The latitude of an area determines the angle at which the sun's rays hit the earth's surface, which affects the amount of solar energy that is absorbed. Areas near the equator receive more direct sunlight and therefore tend to be warmer, while areas near the poles receive less direct sunlight and tend to be cooler.
2) Topography: The topography of an area, including its elevation and proximity to large bodies of water or mountains, can greatly influence its climate. Areas at high elevations are generally cooler than areas at lower elevations, and areas near large bodies of water tend to have milder temperatures due to the moderating effect of the water. Mountains can also influence climate by blocking or redirecting prevailing winds, leading to variations in temperature and precipitation.
3) Atmospheric circulation patterns: The movement of air masses and weather systems around the globe is driven by a complex interplay of factors, including temperature, pressure, and the rotation of the earth. These circulation patterns can greatly affect the climate of an area by determining the direction and intensity of winds, the amount of precipitation, and the frequency and severity of storms.
In Ricardo's case, the climate in his area is likely influenced by all three of these factors. The latitude of his location along the west coast of the mountains will determine the angle at which the sun's rays hit the earth's surface and thus the amount of solar energy absorbed. The topography of the area will also play a role in determining the temperature and precipitation patterns, as well as the effect of ocean winds blowing from the Pacific. Finally, atmospheric circulation patterns will determine the direction and intensity of winds and the frequency and severity of storms that pass through the area.
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To build a neutral atom, there must be an equal number of protons and electrons.
Refresh the simulation, and then add six protons and six electrons to make a neutral carbon atom. Click the plus sign on
the Mass Number window. What's the mass number of this carbon atom?
Answer:The mass number of this carbon atom is six.
Explanation:
Thats the answer on plato
I'm confused with this I need this ASAP
After cycling of the deicing boots, residual ice will A. decrease as the airspeed decreases or the temperature increases. B. remain constant until leaving the icing conditions. C. increase as the airspeed or temperature decreases.
After cycling of the deicing boots, residual ice will decrease as the airspeed decreases or the temperature increases. Deicing boots work by inflating and deflating rapidly, which breaks the ice off the surface of the boots.
Sometimes residual ice can remain after cycling the boots. This residual ice can be reduced by increasing the airspeed or temperature. Increasing the airspeed causes more airflow over the surface of the wings, which helps to remove any residual ice. Similarly, increasing the temperature can help to melt any remaining ice.
It is important to note that residual ice should always be monitored carefully and the pilot should take appropriate actions to ensure that the aircraft remains safe. Ultimately, residual ice can be dangerous and should be minimized as much as possible to prevent any accidents or incidents from occurring.
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Answer:
C. increase as the airspeed or temperature decreases.
Explanation:
You want to know the effect of temperature and airspeed on residual ice after the deicing boots on an aircraft wing have been cycled.
IcingIce can accumulate on airplane wings when temperature, humidity, and/or precipitation conditions are just right. An airplane can defend itself against this potentially dangerous condition by ...
heating the wing to melt the ice or prevent its formationflexing the deicing boot to break off any accumulated ice.After the deicing boot has been cycled, there may be residual ice. This residual ice may increase if the conditions conducive to ice formation remain. That is, it will ...
increase as the airspeed or temperature decreases, choice C.
__
Additional comment
Of course, the best approach to icing is to avoid flying in conditions conducive to ice formation, or to pass through those conditions as quickly as possible.
A ball is dropped off the roof of a tall building. If the ball reaches the ground in 8 seconds, how tall is the building, in meters? Round to the nearest whole number (a=9.8 m/s2)
Let b be the height of the building, and y the height of the ball at time t, given by
y = b - 1/2 gt²
where g = 9.8 m/s² is the magnitude of the acceleration due to gravity.
It takes the ball 8 s to reach the ground, at which point y = 0, so that
0 = b - 1/2 (9.8 m/s²) (8 s)²
b = 1/2 (9.8 m/s²) (8 s)²
b = 313.6 m
airport security uses electromagnetic waves to see items inside of luggage without having to open the bags. which type of electromagnetic waves would be best for airport security to use?
Airport security uses X-rays to see items inside of luggage without having to open the bags. Hence, the type of electromagnetic waves that would be best for airport security to use is X-rays.
Electromagnetic waves are a type of wave that includes both electric and magnetic energy that propagate through space at the speed of light. They are created by the oscillation of electric and magnetic fields that are perpendicular to one another. They are classified according to their frequency or wavelength.
The different types of electromagnetic waves are:
Radio wavesMicrowavesInfrared wavesVisible lightUltraviolet lightX-raysGamma raysX-rays are a form of electromagnetic radiation. They have a higher frequency and shorter wavelength than ultraviolet (UV) radiation. X-rays are used to take images of the inside of objects or to treat cancer.What are X-rays used for?X-rays are used for medical imaging, such as chest X-rays, mammograms, and dental X-rays. They are also used in the manufacturing industry to check for defects in products, in research to study the properties of materials, and in security to scan luggage at airports.
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The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.3 m/s. Initially, the car is also traveling at a speed 20.3 m/s and its front bumper is a distance 24.7 m behind the truck's rear bumper. The car begins accelerating at a constant acceleration 0.650 m/s2, then pulls back into the truck's lane when the rear of the car is a distance 25.5 m ahead of the front of the truck. The car is of length 4.80 m and the truck is of length 21.5 m. A. How much time is required for the car to pass the truck?
B. What distance does the car travel during this time?
C. What is the final speed of the car?
Answer:
Explanation:
Initial relative velocity of the car = 0
relative acceleration = .65 m /s²
relative distance covered = 24.7 + 21.5 + 4.8 + 25.5 = 76.5 m
Let time taken be t
from the relation
s = ut + 1/2 a t²
76.5 = 0 + .65/2 t²
t = 15.34 s
actual distance covered by car during this period
s = ut + 1/2 a t²
= 20.3 x 15.34 + 1/2 x .65 x 15.34²
= 311.4 +76.47
= 387.87
C )
v = u + at
= 20.3 + .65 x 15.34
= 30.27 m /s
Which of the following affects the rate constant of a reaction?
A. The entropy of the reaction
B. The enthalpy of the reaction
C. The volume of the system
D. The temperature of the system
A car arrives at the speed limit sign at the outskirt of a town with a speed of 10m/s^2. It then accelerate s unitormly at 1m/s^2 for 15s and then travels at a uniform velocity for 3 minutes. immediately after the driver sees a police checkpoint 500m ahead and so decelerates uniformly bringing the car to rest at the checkpoint. a. sketch a velocity time hraph for motion b.calculate i. the highest velocity reach by the car ii. the time spent decelerating iii. the distance between the speed limit sign and the checkpoint iv. Average velocity for the whole journey
Don't forget to make brainliest answer
-
a) Here is a sketch of the velocity-time graph for the motion described:
```
| _________
v (m/s)| / \
| / \
| / \
| / \
|___/__________________\___
t=0 15s 3min 3min 30s
```
b)
i. The highest velocity reached by the car is the velocity it travels at during the uniform motion phase, which is constant at the end of the acceleration phase. We can find this velocity using the equation:
v = u + at
where u is the initial velocity (10 m/s), a is the acceleration (1 m/s^2), and t is the time taken to accelerate (15 s).
v = 10 + 1(15) = 25 m/s
So the highest velocity reached by the car is 25 m/s.
ii. The time spent decelerating can be found using the equation:
v = u + at
where v is the final velocity (0 m/s), u is the initial velocity (25 m/s), a is the deceleration (unknown), and t is the time taken to decelerate.
0 = 25 + a(t)
t = -25/a
We know that the distance travelled during deceleration is 500 m, so we can also use the equation:
s = ut + 0.5at^2
where s is the distance travelled (500 m), u is the initial velocity (25 m/s), a is the deceleration (unknown), and t is the time taken to decelerate (from above).
500 = 25(-25/a) + 0.5a(-25/a)^2
500 = -625/a + 3125/a
500a = 3125 - 625
a = 5 m/s^2
Substituting this value of a back into the expression for t, we get:
t = -25/5 = -5 s
Since time cannot be negative, we take the absolute value of t:
t = 5 s
So the time spent decelerating is 5 seconds.
iii. The distance between the speed limit sign and the checkpoint is the sum of the distances travelled during each phase of the motion:
s = ut + 0.5at^2 (for acceleration phase)
s1 = 10(15) + 0.5(1)(15)^2 = 187.5 m
s2 = vt (for uniform motion phase)
s2 = (25)(3)(60) = 4500 m
s3 = vt + 0.5at^2 (for deceleration phase)
s3 = (25)(0) + 0.5(5)(5)^2 = 62.5 m
s_total = s1 + s2 + s3 = 187.5 + 4500 + 62.5 = 4750 m
So the distance between the speed limit sign and the checkpoint is 4750 meters.
iv. The average velocity for the whole journey is given by the total distance travelled divided by the total time taken:
s_total = 4750 m
t_total = 15 + 180 + 5 = 200 s
v_avg = s_total / t_total = 4750 / 200 = 23.75 m/s
So the average velocity for the whole journey is 23.75 m/s.
list and describe the two types of optical telescopes.
There are two main types of optical telescopes: refracting telescopes and reflecting telescopes.
1. Refracting telescopes: These telescopes use lenses to gather and focus light. The primary component is a large objective lens that collects and refracts incoming light towards a focal point. The light is then magnified by an eyepiece for viewing. Refracting telescopes are known for providing sharp and clear images, especially when observing celestial objects such as the Moon and planets. However, they can suffer from chromatic aberration, which causes color distortion due to the different wavelengths of light bending at different angles.
2. Reflecting telescopes: Reflecting telescopes use a curved mirror to gather and focus light. The primary mirror collects incoming light and reflects it to a secondary mirror, which then directs the light towards the eyepiece or a camera. Reflecting telescopes eliminate chromatic aberration, as mirrors do not refract light like lenses. They are also more versatile and cost-effective than refracting telescopes, allowing for larger apertures and the ability to gather more light. Reflecting telescopes are commonly used in astronomical research and provide high-quality images of various celestial objects, including galaxies, nebulae, and distant stars.
Overall, both types of telescopes have their advantages and are used for different applications in the field of astronomy.
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can some help with this? id appreciate your help :)
Answer:
I am not really sure but i think its option 2
Explanation:
write about cassiopeio
Answer:
Cassiopeia was one of the 48 constellations listed by the 2nd-century Greek astronomer Ptolemy, and it remains one of the 88 modern constellations today. It is easily recognizable due to its distinctive 'W' shape, formed by five bright stars. Visible at latitudes between +90° and −20°.
Answer:
Cassiopeia is a fascinating constellation with a rich history and cultural significance, as well as an important object of study for astronomers and scientists
Explanation:
Cassiopeia is a constellation located in the northern hemisphere of the sky. It is one of the 88 constellations officially recognized by the International Astronomical Union (IAU). The constellation is named after Queen Cassiopeia of Greek mythology, who was the wife of King Cepheus and mother of Princess Andromeda.
The constellation is easily recognizable for its distinctive shape, which looks like a "W" or "M" depending on its orientation in the sky. This shape is formed by five bright stars, which represent the Queen's throne and her legs. The brightest star in the constellation is known as Gamma Cassiopeiae, which is a massive blue-white star located about 550 light-years away from Earth.
Cassiopeia is visible in the sky all year round from most locations in the northern hemisphere, and it can be easily found by looking for its distinctive shape. It is also part of the Milky Way galaxy, which makes it a popular target for amateur astronomers who want to observe the stars and galaxies in our own galaxy.
Overall, Cassiopeia is a fascinating constellation with a rich history and cultural significance, as well as an important object of study for astronomers and scientists.
walk done in units time is called
Answer:
Explanation:
work done per unit time is caleed power.it's SI unit is watt.it depends upon time.
Unbeknownst to the students, every time the school floors are waxed, Mr. Tracy, the principal, likes to slide down the Hallway in his socks. Mr. Tracy weighs 85 kg and the coefficient of sliding friction between his socks and the floor is 0.120. What is the force of friction that opposes Mr. Tracy's motion down the hall?
Answer:
f = 99.96 N
Explanation:
Weight of Mr. Tracy, W = 85 kg
The coefficient of sliding friction between his socks and the floor is 0.12.
We need to find the force of friction that opposes Mr. Tracy's motion down the hall.
The force of friction is given by :
\(f=\mu mg\\\\f=0.12\times 85\times 9.8\\\\f=99.96\ N\)
So, the required force of friction is 99.96 N.
If a car travels 540 km in 4.5 hours, what would be its average speed in m/s?
To find the average speed in meters per second, we need to convert both the distance and time to the same units. Since 540 km is equal to 540000 meters and 4.5 hours is equal to 16200 seconds, we can calculate the average speed as:
Average speed = distance / time = 540000 meters / 16200 seconds = 33.333 meters/second.
Genevieve was working on a science lab. In her lab, she was combining two chemicals and timing how long the reaction took to form a precipitate. She repeated the investigation a total of five times. Her times are shown below. trial time (min:sec) 1 08:37 2 07:59 3 08:16 4 08:21 5 08:03 The next day, the instructor told Genevieve that the standard time for her investigation should have been 8 minutes 7 seconds. Which of the following choices describes Genevieve's work in the lab?
Answer: Her test trials had a high level of accuracy but a low level of precision.
Explanation:
Answer:
Her test trials had a high level of accuracy but a low level of precision.
Explanation:
Help with physics please!
Answer:
The elastic potential is 1/2 as much.
Explanation:
The reason I say this is because of you take a new rubber band, after stretching the first time, all the way until it doesn't snap, you stretch it again and there's not as much resistance as when it was new.
I hope this helps.
You are sitting on the beach and wondering about the properties of mechanical waves. Describe them in terms of ocean waves.
Answer:
The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region
Explanation:
A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.
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what is refraction?
this my in sta id-:akhilrawat9453
Answer:
refers to the bending of light
the fact or phenomenon of light, radio waves, etc. being deflected in passing obliquely through the interface between one medium and another or through a medium of varying density.
A series RLC circuit has R = 20 kΩ, L = 0.2 mH, and C = 5 μF. What type of damping is exhibited by the circuit?
In order to determine the type of damping exhibited by the series RLC circuit, we need to look at the values of R, L, and C and calculate the circuit's damping ratio,
which is defined as the ratio of the circuit's damping coefficient to its natural frequency.
The damping ratio (ζ) can be calculated using the following formula:
ζ = R / (2√(L/C))
Plugging in the values given in the question, we get:
ζ = 20,000 / (2√(0.2 x 10^-3 / 5 x 10^-6))
ζ = 20,000 / 2√40
ζ = 20,000 / (2 x 6.324)
ζ = 1578.3
Since the damping ratio (ζ) is greater than 1, the circuit exhibits over-damping. This means that the circuit's response is critically damped, which is characterized by a slow decay without oscillations.
The circuit's output will return to zero after a long time without any overshoot.
In conclusion, the series RLC circuit with R = 20 kΩ, L = 0.2 mH, and C = 5 μF exhibits over-damping, which results in critically damped behavior without any oscillations or overshoot.
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A student has a 0. 125 kg mass and a spring. As part of a laboratory exploration, the student hangs the mass on the spring, sets it into oscillation, and collects data for position and velocity of the mass as a function of time
The period of an oscillation depends on the mass of the object attached to the spring, as well as the elasticity and length of the spring.
When a student has a 0.125 kg mass and a spring in the laboratory exploration, he/she hangs the mass on the spring, sets it into oscillation, and collects data for position and velocity of the mass as a function of time.
The following is the meaning of the terms spring and oscillation:
Spring: A spring is a mechanical device that stores elastic energy. Springs are devices that absorb mechanical energy or force and then release it later.
Oscillation: It is the repetitive variation, typically in time, of some measure about a central value (often a point of equilibrium) or between two or more different states. A mass of 0.125 kg hangs from a spring in this scenario.
When the spring is stretched by a certain distance, the mass oscillates with a certain frequency or a series of back-and-forth vibrations. These vibrations are referred to as oscillations. The energy saved in the spring is what powers the oscillations.
As a result, the period of an oscillation depends on the mass of the object attached to the spring, as well as the elasticity and length of the spring.
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At the center, 6 unmarked red balls are interspersed with 4 blue balls marked with plus signs. A green cloud with 2 concentric white lines surrounds the center, with 2 small green balls marked with minus signs on the inner white line and 2 small green balls marked with minus signs on the outer white line. How many neutrons does this atom have? 4 6 10 14
Answer:
10
Explanation:
Amu denotes for unified atomic mass.
it is mostly used to define the atom's mass and molecules.
we know that
One unit of amu is 1 ÷ 12 of the mass of a nuclide 12C
And 1 u = 1.660 538 921 × 10-27 kg
In the inside we can found that there is 10 nucleons so here the alss of the atoms would be 10 amu
Answer:
guy above me is right
Explanation:
A rocket accelerates at 65 m/s² with the force of 54,080 N. What is the mass of the rocket?
Answer:
832 kgExplanation:
The mass of the rocket given it's acceleration and force can be found by using the formula
\(mass = \frac{f}{a} \\ \)
where
f is the force in N
a is the acceleration in m/s²
From the question
f = 54,080 N
a = 65 m/s²
We have
\(mass = \frac{54080}{65} = 832 \\ \)
We have the final answer as
832 kghope this helps you
A shuffle board disk is pushed at a rate of 6.0 m/s over a 10.8 m distance by a player. How long did the player push the disk? A. 65 s B. 17 s C. 2 s or D. 4 s
It's obvious that 65 s isn't the answer. I'm still doing this question myself
a heavy spherical ball is dropped into the can, and then liquid is poured into the can until the ball is just covered. recall that the volume of a cylider is
This means that the can can hold up to 785.4 cubic centimeters of liquid when filled to the brim.
Based on the information provided, it sounds like we're dealing with a cylinder-shaped container (the can) that has a heavy spherical ball dropped into it. Then, liquid is poured into the can until the ball is just covered.
To calculate the volume of the cylinder (which we'll need to know in order to figure out how much liquid was poured in), we'll need to know the height and radius of the cylinder. Once we have those values, we can use the formula for the volume of a cylinder, which is:
V = πr^2h
where V is the volume, π (pi) is a constant equal to approximately 3.14, r is the radius, and h is the height.
So, if we know that the cylinder is, say, 10 cm tall and has a radius of 5 cm, we can plug those values into the formula to get:
V = π(5^2)(10)
V = 785.4 cubic centimeters (rounded to one decimal place)
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A 9V battery is attached to 6Ω and 3Ω resistor. What is the voltage going to the 3Ω resistor?
1 V
3 V
9 V
2 V
4.5 V
It is a short circuit
Answer:
Voltage across 3 resistor =13.5v
Explanation:
Voltage=resistance *Current
But we don't have total current, so we must find total current
Current =v/R
Current=9/2
Current =4.5I
From
V=R*I
V=3*4.5
V=13.5v
At an amusement park, you and a friend sit on a large rotating disk. You sit at the edge and have a rotational speed of 10 RPM and a linear speed is 12 m/s. Your friend does halfway to the center What is her rotational speed and linear speed