hi hai na usne bheji to make sure to Manas he has to
А masd
Of 500kg a raised to a height of 6m In 30s
Find (a) Workdone .
Answer:
Work done is 882000joule.
power is 29400watt.
Explanation:
given,
Mass(m)=500kg
Acceleration due to gravity(g)=9.8m/s²
Height(h)=6m
Time taken(t)=30s
Workdone=?
Power=?
now,
workdone=force*displaxement
= m*g*h
=500*9.8*6
=8,82,000joule
so, the work done by the man is 8,82,000joule.
then,
power=workdone/time taken
=8,82,000/30
=29,400watt
so, the required power to lift a load is 29,400watt.
Using the Left Hand Rule, if motion is away from you and the current is left, which way is the field?
A. Down
B. Left
C. Up
D. Right
Explanation:
To apply the Left Hand Rule, point your left thumb in the direction of the current and your left fingers in the direction of the motion. The direction in which your left palm faces is the direction of the magnetic field. In this case, if the motion is away from you (i.e., in the direction of your eyes), and the current is left, then the magnetic field will be directed upwards.why fan videos be streamed from the cloud to a computer with no lost quality
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
How do digital signals work?
An established or one that represents data as a step made up of discrete values is known as a digital signal. There is no noise produced by digital signals. Electronic signals sent as pulses are used to transmit digital signals to computers. These signals can be found in things like digital phones and computers.
Because digital signals are used to transport data to and from the cloud, it should be noted that videos are said to stream from the cloud to a computer without quality degradation.
Videos can be streamed from the cloud to a computer with no loss in quality because Digital signals are used to transmit data to and from the cloud.
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A 35 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block are 0.6 and 0.3, respectively. A horizontal string is attached to the block and a constant tension is maintained in the string. What is the force of friction acting on the block if the tension is 16 N? Answer in units of N.
What is the force of friction acting on the block if the tension is 38 N? Answer in units of N.
Answer:
(a) Frictional Force = 16 N
(b) Frictional Force = 10.5 N
Explanation:
(a) FOR TENSION OF 16 N:
First we find the static friction force (Fst):
Fst = (μs)(W)
Fst = (0.6)(35 N)
Fst = 21 N
Since, Tension < Fst
Frictional Force = Tension
Frictional Force = 16 N
(b) FOR TENSION OF 38 N:
Since, Tension > Fst
Frictional Force = Kinetic Friction = (μk)(W) = (0.3)(35 N) =
Frictional Force = 10.5 N
Anyway you could help me with an economic presentation ??
Economics as defined by authors of Economics books Paul Samuelson (Economics) “the observation of the way human beings and society grow to be selecting.
Atoms of institution 18 elements have eight valence electrons or within the case of helium. these elements have already got a complete outer electricity degree, so they may be very stable. As a result, they hardly ever if ever react to other factors.
SeF4 is a polar molecule because of its trigonal bipyramidal geometry and notice-noticed form. The asymmetric shape of the molecule consequences in the non-0 value of the dipole moment. Fluorine is more electronegative than Selenium due to which the Se-F bond is likewise polar.
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Suppose three forces are acting on a model rocket launching into the air. The force of gravity is 1.2 N acting downward. The rocket engine has a force of 12.3 N acting at an angle of 65⁰ above the horizontal to the right. The wind pushes the rocket with a force of 2.5 N to the left. Find the magnitude and direction of the resultant force on the rocket.
Please answer!!! Offering 50 points for answer and explanation
Answer:
can you include a picture
Decompose the forces acting on the rocket in horizontal and vertical components.
• net horizontal force:
∑ F = (12.3 N) cos(65°) - 2.5 N ≈ 2.7 N
(notice we're taking "to the right" to be the positive direction)
• net vertical force:
∑ F = (12.3 N) sin(65°) - 1.2 N ≈ 9.9 N
The resultant force then has magnitude
√((2.7 N)² + (9.9 N)²) ≈ 10.3 N
Since the horizontal and vertical components of the resultant are both positive, it points at an angle between 0° and 90° from the positive horizontal, so that
tan(θ) ≈ (9.9 N) / (2.7 N) ≈ 3.69
===> θ ≈ arctan(3.69) ≈ 75°
a ball is tossed straight upward, in the y direction. at the instant the ball reaches its maximum height, which statement concerning its velocity and acceleration in the y direction is correct? a. both its velocity and acceleration are zero. b. its velocity is zero but its acceleration is positive. c. both is velocity and acceleration are negative. d. both its velocity and acceleration are positive. e. its velocity is zero but its acceleration is negative
When a ball is thrown straight up in the y direction, its velocity is negative although its acceleration is significant in the y direction, which is the correct result.
What is velocity, exactly?The orientation of movement of a body or object is determined by its velocity. In its purest form, movement is a scale parameter. In essence, velocity is a vector quantity. It is the speed at which distance is changing. It describes the rate at which displacement is changing.
Can zero be the final velocity?People wrongly believe that because a bullet stops when it hits the ground, a simple pendulum's maximum speed is also zero. In physical difficulties, an object's greatest velocity refers to the rate at which it is moving shortly before colliding with the earth.
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Suppose you buy a pair of shoes. They come in a box. You take the shoes
out of the box to wear them. How do the mass and the volume of the shoe
box compare before and after you take the shoes out?
Answer:
unchanged
Explanation:
the box itself has same mass and volume with or without the shoes
When a stone is projected, its horizontal range is 24m and greatest height 6m. Find its velocity of projection.
Answer:
15.33 m/s
Explanation:
We are here given that ,
Range = 24m (R)Maximum height= 6m (h)velocity of projection= ? (u)As we know that,
\(\longrightarrow R = \dfrac{u^2\sin2\theta}{g} \dots (1)\\\)
And ,
\(\longrightarrow h =\dfrac{u^2\sin^2\theta}{2g} \dots (2)\\\)
Divide equation 1 and 2 ,
\(\longrightarrow \dfrac{R}{h}=\dfrac{4 \cos\theta}{\sin\theta} \\\)
\(\longrightarrow \dfrac{24m}{6m}=4 \cot\theta \\\)
\(\longrightarrow \cot\theta = 1 \\\)
\(\longrightarrow \theta = \cot^{-1}(1) \\\)
\(\longrightarrow \underline{\underline{\theta = 45^{\circ}}}\\\)
Now we may substitute this value in equation 1 as ,
\(\longrightarrow 24 =\dfrac{ u^2\sin(2\times 45^{\circ} )}{g} \\\)
\(\longrightarrow 24g = u^2\sin90^\circ \\\)
\(\longrightarrow u^2 = 24 \times 9.8 \\\)
\(\longrightarrow u =\sqrt{235.2} m/s \\\)
\(\longrightarrow \underline{\underline{ u \approx 15.33 \ m/s }}\\\)
and we are done!
a particle of mass slides without friction on the inside of a cone in a circular orbit of radius at height above the base of the cone. the cone is rotating about the vertical axis with angular velocity . the velocity of the particle as observed in the rotating reference frame is given by . here both and are magnitudes (positive quantities). the axis of the cone is vertical and gravity points downward. the apex half-angle of the cone is
the apex half-angle of the cone is \(\frac{V^{2} }{g}\)
Calculation :
Ncosθ = mg ---1
Nsinθ =\(\frac{mv^{2} }{r}\)
divide eqn 1 and 2
tanθ = V²/rg ---3
now tan θ = h/r ---4
fro eqn 3 and 4
h= \(\frac{V^{2} }{g}\)
A cone is a three-dimensional geometric shape that tapers from a flat base (often not necessarily circular) to a point called the vertex or apex.
A cone is formed by a series of line segments, half-lines, or lines that connect a point (vertex) common to all points on the base in a plane that does not contain vertices. Depending on the author, the basis may be restricted to a circle, a one-dimensional square in the plane, a closed his one-dimensional figure, or any of the above plus all enclosed points. A cone is a solid object if the base contains the enclosed points. Otherwise, it is a 2D object in 3D space. For solids, the boundaries formed by these lines or partial lines are called faces. If the sides are unlimited, it is a conical surface.
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In what ways does ecotourism help living things in ecosystems?
Ecotourism has the potential to eliminate the requirement to hunt wildlife for a living. Ecotourism generates revenue by maintaining the rainforest; deforestation is discouraged because it reduces tourist revenue.
What role does ecotourism play in biodiversity conservation?Ecotourism firms safeguard biodiversity by preserving animals in their natural habitats and preserving natural ecosystems in biosphere reserves, wildlife sanctuaries, and national parks.
Can tourism save the environment?Ecotourism contributes to the preservation of a destination's ecological and biological diversity. For example, since Costa Rica's jungle is so popular with visitors, inhabitants work hard to protect it instead of attempting deforest it for a short-term profit.
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A 1.6-lb collar is attached to a spring and slides without friction along a circular rod in a vertical plane. The spring has an unstretched length of 6 in. The collar is released from being held at A, and it passes ponit B with a speed of 16.0 ft/s. Determine the spring constant. The circular rod is kept from moving.
Answer:
k = 652 lb/ft
Explanation:
Given :
Weight of the collar = 1.6 lb
The upstretched length of the spring = 6 in
Speed = 16 ft/s
PA = 8 + 10
= 18 inch
Let the initial elongation be \($\Delta x_i$\)
∴ \($\Delta x_i$\) = 18 - 6
= 12 inch = 1 foot
\($PB = \sqrt{13^2+5^2}$\)
= 13.925 inch
Final elongation in the spring
\($\Delta x_B = 7.928 $\) inch = 0.66 feet
Applying the conservation of the mechanical energy between A and B is
\($K.E_A+P.E_{g,A}+P.E_{sp,A}= K.E_B+P.E_{g,B}+P.E_{sp,B} $\)
\($0+mg_r+\frac{1}{2}k(\Delta x_i)^2=\frac{1}{2}mv_B^2+0+\frac{1}{2}k(\Delta x_B)^2$\)
\($\frac{1}{2}k[(1)^2-(0.66)^2]=\frac{1.6}{2}\times (16)^2-1.6 \times 32 \times \frac{5}{12}$\)
\(0.281 \ k =204.8-21.33\)
k = 652 lb/ft
Francesco, a pizza chef preparing the dough for your pizza is throwing it to expand it. In this process, you notice that a chunk of it comes off, flying separately from the rest and on to the floor. If Francesco is 6 feet and 3 inches tall, and the chunk flies off vertically straight up from this height at a speed of 1 m/s, with what speed does the chunk hit the ground?
Answer:
6.12 m/s
Explanation:
In order to solve this we have two parts of this problem, first we have the time that the pizza dough spent going upwards and after that we have a free fall from there, so we will use the free fall formula after we figured out whats the final height the dough reached after being thrown from Francesco's height which is 6ft3inches or 1.90 meters
We first have to find out how much time the dough spent in the air before reaching 0 as final speed and then started the free falling:
The formula would be:
\(Vf=Vo-at\\0=1-(-9.81t)\\1=9.81t\\t=\frac{1}{9.81}\\t=.101\)
The formula to find out final height would be:
\(y = \frac{ h + Vy (t-gt^{2})}{2} \\\)
Now we just insert the values we know
\(y = h+ \frac{ Vy (t-gt^{2})}{2} \\\\y = 1.90 +\frac{ .101-(-9.81)(.101)^{2})}{2} \\\\y=1.91\)
So from 1.91 meteres the free fal started we have to just calculate the final velocity with the formula for free fall and velocity:
\((vf)^{2} =Vo^2 +2ad\)
Since Vo is 0 because we are talking about free falling we just insert the values we know:
\((vf)^{2} =Vo^2 +2ad\\(vf)^{2} =2ad\\(vf)^{2} =2(9.81)(1.91)\\vf=\sqrt{37.4742} \\Vf=6.12m/s\)
So the final speed that the dough hit the ground with is 6.12 m/s
Which of the following is NOT a scientific hypothesis?
A. Neon atoms emit red light.
B. There is an attractive force between the earth and moon.
C. Halle Berry is attractive.
D. Summer days are hottest
E. The sky is blue.
The following statement is not a scientific hypothesis:
C. Halle Berry is attractive.
A scientific hypothesis is a proposed explanation for an observation or pattern in nature that can be tested through further investigation and experimentation. It should be testable, falsifiable, and based on evidence.
Neon atoms emit red light. This is a scientific hypothesis that can be tested and confirmed by looking at the spectrum of light emitted by neon atoms.
B. There is an attractive force between the earth and moon. This is a scientific hypothesis that can be tested and confirmed by measuring the force of gravity between the earth and moon.
D. Summer days are the hottest of the year. This is a scientific hypothesis that can be tested and confirmed by collecting temperature data during the summer months.
E. The sky is blue. This is a scientific hypothesis that can be tested and confirmed by observing the sky under different atmospheric conditions.
The statement "Halle Berry is attractive" is a subjective opinion that cannot be tested or confirmed through scientific investigation, hence it is not a scientific hypothesis. Attractiveness, as a concept, can vary widely based on personal, cultural, and social factors.
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Which activities are ways that scientists gather information? (Select all that apply.
Answer:
Real life relations and experiments
the very act of observing a particle has a dramatic effect on its behaviour why do you think this is the case
Answer:
Explanation:
In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.
So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.
What is the power (P) of an electric circuit with a current (I) of 2.5 A and a voltage (V) of 120 V? The formula for power is P = IV
The electric power of an electric circuit with a current of 2.5 A and voltage of 120 V is 300 watts.
What is Electric power?Electric power is the rate at which work has to be done or the energy is transformed into an electrical circuit to work. Power is a measure of how much energy is used in a span of time. The SI unit of power is watt (W). Power can be defined as the product of voltage and electric current.
P = VI
where, P is the power,
V is the voltage or potential difference,
I is the electric current
P = VI
P = 120 × 2.5
P = 300 watts
Therefore, the electric power in the circuit will be 300 watts.
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Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1750 kg and was approaching at 6.00 m/s due south. The second car has a mass of 700 kg and was approaching at 19.0 m/s due west.(a) Calculate the final velocity of the cars. (Note that since both cars have an initial velocity, you cannot use the equations for conservation of momentum along the x-axis and y-axis; instead, you must look for other simplifying aspects..)Magnitude m/sDirection ° (counterclockwise from west is positive)(b) How much kinetic energy is lost in the collision? (This energy goes into deformation of the cars.) J
Given:
• Mass of first car 1, m1 = 1750 kg
,• Mass of second car, m2 = 700 kg
,• Initial velocity of car 1, u1 = 6.00 m/s due south
,• Initial velocity of car 2, u2 = 19.0 m/s due west.
Let's solve for the following:
• (a). Calculate the final velocity of the cars.
Apply the conservation of momentum.
In the West direction(x-direction), we have:
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_x \\ \\ 1750(0)+700(19.0)=(1750+700)v_x \\ \\ 13300=2450v_x \\ \\ v_x=\frac{13300}{2450} \\ \\ v_x=5.43\text{ m/s} \end{gathered}\)In the South direction (y-direction), we have:
\(\begin{gathered} m_1u_1+m_2u_2=(m_1+m_2)v_y \\ \\ 1750(6.00)+700(0)=(1750+700)v_y \\ \\ 10500=2450v_y \\ \\ v_y=\frac{10500}{2450} \\ \\ v_y=4.29\text{ m/s} \end{gathered}\)To find the magnitude, we have:
\(\begin{gathered} v=\sqrt{v_x^2+v_y^2} \\ \\ v=\sqrt{5.43^2+4.29^2} \\ \\ v=\sqrt{29.4849+18.4041} \\ \\ v=\sqrt{47.889} \\ \\ v=6.92\text{ m/s} \end{gathered}\)To find the direction, apply the formula:
\(\begin{gathered} \theta=tan^{-1}(\frac{v_y}{v_x}) \\ \\ \theta=tan^{-1}(\frac{4.29}{5.43}) \\ \\ \theta=tan^{-1}(0.79) \\ \\ \theta=38.31^o\text{ south of west} \end{gathered}\)• (b). How much kinetic energy is lost in the collision?
To find the loss of kinetic energy, apply the formula:
\(KE_{loss}=KE_{initial}-KE_{final}\)Using the Kinetic energy formula, we have:
\(\begin{gathered} KE_{loss}=(\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2)-\frac{1}{2}(m_1+m_2)v^2 \\ \\ KE_{loss}=(\frac{1}{2}*1750*6.00^2+\frac{1}{2}*700*19^2)-(\frac{1}{2}(1750+700)6.92^2) \end{gathered}\)Solving further:
\(\begin{gathered} KE_{loss}=(31500+126350)-58660.84 \\ \\ KE_{loss}=157850-58660.84 \\ \\ KE_{loss}=99189.16\text{ J} \end{gathered}\)Therefore, the amount of kinetic energy lost is 99189.16 J.
• ANSWER:
(a). Magnitude = 6.92 m/s
Direction = 38.31° South of West
(b). 99189.16 J.
BRAINLY PLS HELP ME!!!
Should the Us government regulate sugar? In once sentence write down what you are preparing to argue or what stance you are going to take. This will help you to create a starting point for your idea
Answer:
yes
Explanation:
Sugar can cause health problems.
I believe that sugar should be regulated by the government since it causes heath problems. As according to this website heathline.com that up to one third of the population in America is obese. As well as that regulating sugar will greatly help lowering that number, seeing that many food products have tons of sugar in them. By lowering the sugar and regulating it can cause less obesity among the average person in the US. As stated by HeathlyFoodAmerca.org consuming too much sugar can cause increased heath problems as shown, heart disease, diabetes, and teeth decay and this is why I believe that the U.S government should regulate sugar more.
Weather hazards and natural disasters such as tsunamis, earthquakes, and flooding are considered which type of migration factor?
A. Pull factor
B. Both push and pull factors
C. Neither push or pull factor
D. Push factor
Answer:
D. Push Factor
Explanation:
Pull factors are known as positive aspects of a place that make people want to stay/remain in that area.Push factors are known as negative aspects of a place that make people want to leave/depart from that area.Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.
(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)
A spider walks a distance of 0.2 m at a constant speed of 0.1 m/s. The time interval is
A.2 s
B.0.02s
C.0.5s
D.20s
Answer:
A. 2s
Explanation:
time = distance ÷ speed
T = .2 ÷.1
T= 2
The time interval will be Option B (0.02 s).
The given values in the question are:
Distance,
D = 0.2 m
Speed,
S = 0.1 m/s
As we know the formula,
→ \(Speed = \frac{Distance}{Time}\)
or,
→ \(Time = \frac{Distance}{Speed}\)
By substituting the values, we get
→ \(= \frac{0.2}{0.1}\)
→ \(= 0.02 \ s\)
Thus the above answer is right.
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What makes astronomers think that impact rates for the Moon must have been higher earlier than 3.8 billion years ago?
Answer: See explanation
Explanation:
The reason why astronomers think that the rates of impact for the Moon must have been higher earlier than 3.8 billion years ago is because on the older highlands, there are ten times more craters than on the younger maria.
It is believed that the impact rate was higher earlier and thus can be seen when the numbers of the craters that can be seen on the lunar highlands is being compared to that on the maria. It should be noted that there are about 10 times more craters that can be found on the highlands than those on the maria.
If there was a constant rate of impact throughout the history of the Moon, then the highlands be about 10 times older and therefore will have been formed about 38 billion years ago.
If you were to calculate the pull of the Sun on the Earth and the pull of the Moon on the Earth, you would undoubtedly find that the Sun's pull is much stronger than that of the Moon, yet the Moon's pull is the primary cause of tides on the Earth. Tides exist because of the difference in the gravitational pull of a body (Sun or Moon) on opposite sides of the Earth. Even though the Sun's pull is stronger, the difference between the pull on the near and far sides is greater for the Moon.
Required:
a. "Let F(r) be the gravitational force exerted on one mass by a second mass a distance r away. Calculate dF(r)/dr to show how F changes as r is changed.
b. Evaluate this expression for dF(r) jdr for the force of the Sun at the Earth's center and for the Moon at the Earth's center.
c. Suppose the Earth-Moon distance remains the same, but the Earth is moved closer to the Sun. Is there any point where dF(r)/dr for the two forces has the same value?
Answer:effective
Explanation:
An object with a mass of 9 kg weighs 33.3 N on Mars. What is the acceleration due to Mar's gravity?
O 1.6 m/s^2
O 9.8 m/s^2
O 3.7 m/s
O 8.9 m/s
Answer:
3.7m/s^2
Explanation:
Weight (W)= mass (m) x acceleration due to gravity (g)
therefore
g = W/mg
g = 33.3/9
9 = 3.7m/s^2
Hi
Please help on question asap if the answer is correct I'll rate you five stars a thanks and maybe even brainliest!
When two light bulbs are connected in series, the resistance in the circuit is increase compared to that with one lightbulb. The increased resistance opposes the flow of current so far fewer electrons pass per second , transferring less energy. The lightbulbs are therefore not as bright as In a circuit with same voltage but only one bulb.
However, when Two lightbulbs are connected in parallel, each loop behaves like a separate circuit . The resistance in each branch is the same as if there were just one light bulb in the whole circuit.there is the same current in each branch of the circuit ,so the bulbs Will light up with the same brightness as a single bulb circuit. The energy stored in the battery will decrease twice as quickly and battery will run out faster than I series circuit.
6) explain the advantages and disadvantages of arranging components in series or parallel.
Which of the following is true of Newton's First Law?
A. The greater the object's mass, the great its inertia, and the greater the needed force to move it
B. Increasing the mass on an object experiencing the same force would decrease the acceleration
C. A baseball hits collides with a fence and they exchange forces
D. An object at rest will move due to an applied balanced force
Answer:
D. An object at rest will move due to an applied balanced force
Explanation:
Newton's first law states that an object at rest stays at rest, and an object in motion will stay in motion, until acted upon by an unbalanced forced. In other words, a net force is required for a change in motion.
Answers A and B are true of Newton's second law (F=ma), and answer C is true of Newton's third law (every action has an opposite and equal reaction).
A cubic box is completely filled with 2800 g of water. What is the length of one side of the box, in meters?
m
Explain your reasoning.
Since the density of water is
cm3 is
g/cm3, then the volume of 2800 g of water is
cm on each side. Converting [ cm to meters, the cube is
Proy
13 of 15
⠀⠀⠀
Next
cm³. A cubic box with a volume of [
m on each side.
The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.
Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.
Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.
So the filled cubic box has a side length of approximately 0.141 m.
C) A University student calculated the density of a liquid by measuring its mass (2.22g ± 0.05g) and volume (1.14 ± 0.04 ml), calculate density
The density of the liquid as measured by the student is 1.9473 g/ml
Computation of the density of a liquidDefinition of density: A material's density is determined by how closely it is packed. As the mass per unit volume, it has that definition. Symbol for Density: D or Density
Given Data
Mass = 2.22g ± 0.05g
Volume = 1.14 ± 0.04 ml
We know that the expression for density is given as
Density = Mass/Volume
Substituting our given data into the expression above, we have
Density = 2.22/1.14
Density = 1.9473 g/ml
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what is the 'Water Column"
Answer:a vertical expanse of water stretching between the surface and the floor of a body of water
Explanation:
A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s after this, the ball reaches the bottom of the incline. (a) What was the magnitude of the ball's acceleration, assume it to be constant
Answer:
a) a = 2.35 m/s^2
Explanation:
(a) In order to calculate the magnitude of the acceleration of the ball, you use the following formula, for the position of the ball:
\(x=v_ot+\frac{1}{2}at^2\) (1)
x: position of the ball after t seconds = 87 m
t: time = 8.6 s
a: acceleration of the ball = ?
vo: initial velocity of the ball = 0 m/s
You solve the equation (1) for a:
\(x=0+\frac{1}{2}at^2\\\\a=\frac{2x}{t^2}\)
You replace the values of the parameters in the previous equation:
\(a=\frac{2(87m)}{(8.6s)^2}=2.35\frac{m}{s^2}\)
The acceleration of the ball is 2.35 m/s^2