a current of 0.300 a through your chest can send your hear into fibrillation, ruining the normal rhythm of heart beat and disrupting the flow of blood (and thus oxygen) to your brain. if that current persists for 3.37 min, how many conduction electrons pass through your heart?

The width of the slit is approximately \(1.78\)x \(10^{-5}\)meters

To solve this problem, we can use the equation for the location of the dark bands in a single-slit diffraction pattern:

sin(θ) = (mλ) / w

Where θ is the angle between the center of the pattern and the m-th dark band, λ is the wavelength of the light, w is the width of the slit, and m is the order of the dark band (in this case, m = 1).

We can rearrange this equation to solve for the slit width:

w = (mλ) / sin(θ)

Plugging in the given values, we have:

λ = 439 nm = 4.39 x \(10^{-7}\) m
m = 1
θ = \(tan^{-1}\) (0.41 / 91) = 0.00245 radians

Plugging these values into the equation, we get:

w = (1 x 4.39 x \(10^{-7}\)) / sin(0.00245) = 1.78 x \(10^{-5}\) m

Therefore, the width of the slit is approximately 1.78 x\(10^{-5}\) meters.

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Answer:

x = 5 + 8.3

x = 13.3

x = 13

Hope this helps

The correct choice is the third option.

This comes from the fact that the packing material cushions the impacts of the content in case of a fall.

The initial potential energy of the child-Earth system is 509.4 J, and the change in system kinetic energy during the jump is 509.4 J.

In the first scenario, with x=0 at the bottom of the fence, we can calculate the initial potential energy (Ui) using the formula Ui = mgh, where m is the mass of the child (29 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the fence (1.8 m). Substituting the values, Ui = 29 kg × 9.8 m/s^2 × 1.8 m = 509.4 J.

Since there is no external work done on the child during the jump, the change in system kinetic energy (change of U) is equal to the negative of the initial potential energy. Therefore, the change of U = -509.4 J.

In the second scenario, with x=0 at the top of the fence, the initial potential energy (Ui) is still the same, i.e., 509.4 J. However, since the child is starting from a higher position, the change in system kinetic energy (change of U) will be different. The change of U will still be equal to -509.4 J since it depends on the initial potential energy, regardless of the reference point.

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Answer:

The bottom three pie graphs show the breakdown for each of three greenhouse gases in comparison to the total. Seventy two percent (72%) of the total greenhouse gases emitted was carbon dioxide, 18% methane and 9% nitrous oxide.

Explanation:

Answer:

An archers bow that is drawn back

Answer:

A)a diver standing on a diving platform.

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Answer:

The time taken for the paint ball to hit the ground is \(t = 2.143 \ s\)

The distance of the landing point from the tower is \(d = 192.86 \ m\)

Explanation:

From the question we are told that

   The height of the tower is \(h = 45 \ m\)

    The speed of the paintball in the horizontal direction is  \(v_x = 90 \ m/s\)

Generally from kinematic equation we have that

      \(h = ut + \frac{1}{2} at^2\)

Here u is the initial  velocity of the paintball in the vertical direction and the value is 0 m/s , this because the ball was fired horizontally

         a is equivalent to \(g = 9.8\ m/s^2\)

        t is the time taken for the paintball to hit the ground

   So    

       \(45 = 0* t + \frac{1}{2} 9.8 * t^2\)

=>    \(t = 2.143 \ s\)

Generally the distance of its landing position from the tower is

         \(d = v * t\)

=>      \(d = 90 * 2.143\)

=>    \(d = 192.86 \ m\)

Answer:

b

Explanation:

Answer:

B. Earth's rotation on its axis.

Explanation:

:) good luck

According to the Evidence was critical to the development of the atomic model. Match each experimental evidence with the model it produced. evidence that led to the establishment of the atomic model was a few positive particles that were fired at a piece of gold foil and appeared to bounce back. Rutherford conducted an experiment in which he allowed alpha particles to strike the gold foil.

There are heavy particles present at the centre of an atom, as evidenced by the fact that some of the particles bounced back. There is a lot of vacant space in an atom since the majority of alpha particles pass through it.

(A) Cathode-Ray bends towards positively charged plate: Electrons orbit nucleus in fixed circular orbits.

(B) Alpha-particles pass through the gold foil, and only some were deflected: Electrons and protons embedded in the particle.

(C) Mathematically determined the number of electrons that occupy regions around the nucleus: The electrons surround a positively charged nucleus.

(D) Differing brightness of electron density around nucleus: Electrons occupy specific sections around the nucleus called orbitals.

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The elastic potential energy of the spring is 1.6 J.

The elastic potential energy of the spring is the energy stored in the spring and it is calculated as follows;

U = ¹/₂kx²

where;

The given parameters include;

U = ¹/₂kx²

U = ¹/₂ (80) (0.2)²

U = 1.6 J

Thus, the elastic potential energy of the spring is a function of the spring constant and the extension of the spring.

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Irina of mass 110 kg floats in fresh water, the volume is 0.06m³.

The buoyant force is the upward force exerted on any object by the fluid. If the buoyant force is lesser than the object's weight, the object will sink while if buoyant force is greater than the object's weight it will float.

In the question irina of mass 110 kg floats in fresh water that indicates:

weight of irina = buoyant force

mg = Vρg

m =  Vρ

Where, m = mass of irina

V = volume

ρ = density of water

110 = V × 1000

V = \(\frac{110}{1000}\)

V = 0.11m³

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Ten devices that use batteries are: smartphones, laptops, flashlights, digital cameras, portable speakers, electric toothbrushes , remote controls, electric shavers, handheld game consoles, and electronic toys

What are the batteries?

Here are ten devices that use cells or batteries:

Whether or not the cells or batteries used in these devices are the best choice depends on various factors such as the device's power requirements, energy efficiency, cost, and environmental impact.

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when a server touches the food-contact surfaces of a water glass while setting the table, this is an example of cross-contamination.

Cross-contamination occurs when harmful bacteria or allergens transfer from one object to another, potentially posing a risk to the health of the guests. In this scenario, the server's hands may carry pathogens or allergens which can transfer to the water glass, contaminating it.

To prevent cross-contamination, servers should follow proper hygiene practices such as handwashing and handling items like glassware and utensils by their non-food-contact surfaces. This ensures a clean and safe dining experience for the guests.

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Answer:

t_total = 6.99 s

Explanation:

It asks us how long it takes to hear the sound, for this we must look for the time (t₁) it takes for the sound to reach the microphone, the time it takes for the video signal (t₂) to reach the television and the time (₃) it takes for the TV sound to reach us, so the total delay time is

         t_total = t₁ + t₂ + t₂

we look for t1, it indicates that the distance x = 22m

          v = x / t

           t = x / v

           t₁ = 22/343

           t₁ = 6.41 10-2 s

time t₂

          t₂ = 4500 103/3 108

          t₂ = 1.5 10-5 s

time t₃

          t₃ = 2/343

          t₃ = 5.83 10⁻³

Total time is

         t_total = t₁ + t₂ + t₃

         t_total = 6.41 10⁻² + ​​1.5 10⁻⁵ + 0.583 10⁻²

         t_total = 6.99 s

The principal quantum number of the first d subshell is 3.

The principal quantum number (n) represents the energy level or shell in which an electron resides in an atom. For the d subshell, which corresponds to the transition metals in the periodic table, the principal quantum number starts at n = 3. This is because the d orbitals are available for filling from the third energy level onwards. In the first energy level (n = 1), there are only s orbitals. In the second energy level (n = 2), both s and p orbitals are present. It is not until the third energy level (n = 3) that the d orbitals come into play. Thus, the first occurrence of the d subshell is in the third energy level, giving it a principal quantum number of 3.

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The principal quantum number of the first d subshell is 3.

The principal quantum number (n) determines the energy level or shell in which an electron resides in an atom. In the case of the d subshell, it is the third energy level (n = 3) where the d orbitals are found.

The principal quantum number (n) can have positive integer values starting from 1 and increasing in ascending order. Each value of n corresponds to a different energy level, with the innermost level being n = 1, followed by n = 2, n = 3, and so on.

The d subshell is part of the third energy level (n = 3). It consists of five d orbitals, labeled as dxy, dxz, dyz, dx²-y², and dz². These orbitals can accommodate a total of 10 electrons.

Therefore, the principal quantum number of the first d subshell is 3 because it belongs to the third energy level. It's important to note that the d subshell does not appear until the third energy level, so the first and second energy levels (n = 1 and n = 2) do not contain any d orbitals.

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Answer:

La velocidad media es 5 \(\frac{km}{h}\), que equivale a 1.389 \(\frac{m}{s}\)

Explanation:

La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.

La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:

\(velocidad=\frac{distancia}{tiempo}\)

En este caso:

Entonces, reemplazando en la definición de velocidad media:

\(velocidad=\frac{10 km}{2 h}= \frac{10,000 m}{7,200 s}\)

Resolviendo se obtiene:

\(velocidad=5 \frac{km}{h}= 1.389\frac{m}{s}\)

La velocidad media es 5 \(\frac{km}{h}\), que equivale a 1.389 \(\frac{m}{s}\)

300 meters = 0.186411 miles, 65 minutes = 1.08333 hours, 35 yards = 32.004 meters

1. To convert 300 meters to miles, you can use the conversion factor 1 mile = 1609.344 meters. So, 300 meters = 300/1609.344 miles = 0.186411 miles.
2. To convert 65 minutes to hours, you can use the conversion factor 1 hour = 60 minutes. So, 65 minutes = 65/60 hours = 1.08333 hours.
3. To convert 35 yards to meters, you can use the conversion factor 1 yard = 0.9144 meters. So, 35 yards = 35*0.9144 meters = 32.004 meters.
In summary:
300 meters = 0.186411 miles
65 minutes = 1.08333 hours
35 yards = 32.004 meters

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Answer:

there are just a bit over 1.6 km in a mile so 7.5*1.6=12. something so there is just a little bit more distance in 7.5 miles

Explanation:

The period of oscillation of a spider hanging on a silk thread, tapped once every second, is one second.

What is the period of oscillation of a spider hanging on a silk thread when tapped once every second?

The time it takes for one complete up-and-down motion of the spider on the silk thread is called the period of oscillation, denoted by T. We know from the problem statement that the spider has the largest amplitude on its bungee cord when tapped exactly once every second.

If the tapping is done exactly once every second, then the spider is experiencing a periodic force with a frequency of 1 Hz. In this case, the period of oscillation T is equal to the reciprocal of the frequency, which is:

T = 1/f = 1/1 Hz = 1 second

Therefore, the spider completes one full oscillation (i.e., up-and-down motion) every second.

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The force exerted on the hockey by the stick is -56.7 N.

Force is the product of mass and acceleration.

To calculate the force on the hockey, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the force on the hockey is -56.7 N.

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Answer:

s

Explanation:

The gravitational potential energy (GPE) of an object is determined by its height (h) above the ground, it's mass (m), and the acceleration due to gravity (g). The GPE can be calculated using the formula:

GPE = m * g * h

In the given situation, the first stone has a mass of m and is held at a height of h above the ground. The second stone has four times the mass (4m) and is held at the same height (h).

To compare the gravitational potential energies of the two stones, we can use the formula for GPE for both stones.

GPE1 = m * g * h (for the first stone)
GPE2 = (4m) * g * h (for the second stone)

To determine the relationship between GPE1 and GPE2, we can set up a ratio:

GPE2 / GPE1 = [(4m) * g * h] / [m * g * h]

Notice that both g and h appear in both the numerator and denominator, which allows us to cancel them out:

GPE2 / GPE1 = (4m) / m

The mass m also cancels out, leaving:

GPE2 / GPE1 = 4

This shows that the gravitational potential energy of the second stone is four times as much as that of the first stone. Therefore, the correct answer is option d. Four times as much.

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The number of significant figures in the calculation for the perimeter should match the least number of significant figures among the measurements, which is 2. Therefore, the calculation for the perimeter should be reported with 2 significant figures.

When performing calculations, it is important to consider the rules of significant figures. The rule states that the result of a calculation should be rounded to match the least number of significant figures in the given measurements.

In the given measurements, the least number of significant figures is 2, which is found in Side 3 (2.000 m). Therefore, when calculating the perimeter of the seven-sided figure, the result should be rounded to 2 significant figures.

For example, if the calculated perimeter is 41.756 meters, it should be rounded to 42 meters since 2 is the least number of significant figures. This ensures that the result aligns with the precision of the measurements provided.

By adhering to the rules of significant figures, we can maintain consistency and accuracy in our calculations and ensure that the level of precision is appropriate for the given data.

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The flux of the curl of the vector field Ĥ(x, y, z) = (y², x, z²) across the portion S3 of the paraboloid z = x² + y² lying below z = 1, oriented by upward normal vectors, is 0.

To calculate the flux of the curl of the vector field across the surface, we can use the surface integral formula:

Flux = ∬S (curl(Ĥ) ⋅ n) dS,

where S is the surface, curl(Ĥ) is the curl of the vector field Ĥ, n is the unit normal vector to the surface, and dS is the differential surface area element.

First, let's calculate the curl of Ĥ:

curl(Ĥ) = (∂Q/∂y - ∂P/∂z, ∂R/∂z - ∂P/∂x, ∂P/∂y - ∂Q/∂x)

        = (0 - 2z, 0 - 0, 2y - 1)

Next, we need to determine the unit normal vector to the surface S3. Since S3 is a paraboloid and is oriented by upward normal vectors, the unit normal vector is given by n = (−∂f/∂x, −∂f/∂y, 1)/√(1 + (∂f/∂x)² + (∂f/∂y)²), where f(x, y, z) = z - (x² + y²).

Taking the partial derivatives and plugging them into the formula, we get n = (−2x, −2y, 1)/√(1 + 4x² + 4y²).

Now, let's compute the flux:

Flux = ∬S (curl(Ĥ) ⋅ n) dS

     = ∬S (2y - 1)(−2x, −2y, 1)/√(1 + 4x² + 4y²) dS.

To evaluate this integral, we need to parameterize the surface S3. We can use spherical coordinates, where x = rcosθ, y = rsinθ, and z = r². The limits of integration will be 0 ≤ r ≤ 1 and 0 ≤ θ ≤ 2π.

dS in spherical coordinates is given by dS = r²sinθ dr dθ.

Now, let's substitute the parameterization and compute the integral:

Flux = ∫∫S (2rsinθ - 1)(−2rcosθ, −2rsinθ, 1)/√(1 + 4r²cos²θ + 4r²sin²θ) r²sinθ dr dθ

     = ∫₀²π ∫₀¹ (2rsinθ - 1)(−2rcosθ, −2rsinθ, 1) r²sinθ dr dθ.

After evaluating this double integral, we find that the flux is equal to 0.

The flux of the curl of the vector field across the surface S3 is 0. This indicates that there is no net flow of the vector field across the surface, meaning the field lines do not penetrate or leave the surface S3.

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a. The total mechanical energy is \(EM = -4.4*10^{14} J.\)

b.  The angular momentum of the satellite at point A is \(L = 8.5*10^{12} kg m2/s.\)

c.The minimum speed of the satellite at point A in order to escape from Earth is \(ve = 11.2*10^{3 }m/s.\)

a. The total mechanical energy of the satellite at point A is equal to the sum of its kinetic and potential energies. The kinetic energy is given by \(KE = \frac{1}{2} mv2,\), where m is the mass of the satellite and v is the orbital velocity. The potential energy is given by \(PE = \frac{-GMEm}{r}\), where G is the gravitational constant, M is the mass of the Earth, and r is the orbital radius. Thus, the total mechanical energy is

\(EM = KE + PE = \frac{1}{2} mv2, - \frac{GMEm}{r}.\). Substituting \(m = 2,000 kg, v = 7.1*10^{3} m/s, \\G = 6.67*10^{-11} N m2/kg2, M = 6*10^{24} kg,\\r = 1.2*10^{7} m\)

we obtain\(EM = -4.4*10^{14} J.\)

b. The angular momentum of the satellite at point A is given by L = mvr, where m, v, and r are as defined above. Substituting the given values, we obtain  \(L = 8.5*10^{12} kg m2/s.\)

c. The minimum speed of the satellite at point A in order to escape from Earth is the escape velocity, which is equal to the square root of twice the gravitational potential energy at point A. Substituting the given values for M and r, we obtain the escape velocity  \(ve =\sqrt(2GM/r) = 11.2*10^{3 }m/s.\)The minimum speed of the satellite must be greater than the escape velocity in order for it to escape from Earth.

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One way that Accenture is seeking to achieve its sustainability goals is by integrating sustainability metrics into all of its client engagements.

What is sustainability?

Sustainability is the practice of using resources in a manner that meets the economic, social, and environmental needs of the present without compromising the ability of future generations to meet their own needs. It is a systemic approach to creating and maintaining conditions that allow people to thrive in the present without compromising the planet’s ability to support future generations.

This includes leveraging Accenture’s proprietary Sustainability Maturity Model, which provides a structured approach to measure and track sustainability performance. It also includes embedding sustainability into the design of client projects, developing strategies to enable clients to reach their sustainability goals, and exploring the potential of emerging technologies to accelerate progress. Additionally, Accenture is committed to providing its clients with data-driven insights and best practices that enable them to meet their sustainability objectives.

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The rotational kinetic energy has decreased by \(1.4175 kg.m^2/s^2\). To find the final rotational kinetic energy of the rotating disk, we can use the formula for rotational kinetic energy:

Rotational kinetic energy = (1/2) * (moment of inertia) *\( (angular velocity)^2\)
First, we need to find the moment of inertia of the rotating disk. For a solid disk, the moment of inertia is given by the formula:

Moment of inertia = (1/2) * (mass) *\( (radius)^2\)
Substituting the given values:
Moment of inertia = (1/2) * (0.7 kg) * \((0.1 m)^2\)
Moment of inertia = \(0.035 kg.m^2/\(

Next, we need to find the final angular velocity of the rotating disk. Given that the rotation rate decreases by 20%, the final angular velocity will be 80% of the initial angular velocity.
Final angular velocity = 0.8 * 15 rev/s
Final angular velocity = 12 rev/s

Now we can calculate the final rotational kinetic energy using the formula:
Rotational kinetic energy = (1/2) *\( (moment of inertia) * (angular velocity)^2\)
Final rotational kinetic energy = (1/2) *\( (0.035 kg.m^2) * (12 rev/s)^2\)
Simplifying the equation:

Final rotational kinetic energy = 0.5 * 0.035 *\( (12^2) kg\(.\(m^2/s^2\)
Final rotational kinetic energy = 0.5 * 0.035 * 144 kg.\(m^2/s^2\)
Final rotational kinetic energy = 2.52 kg.\(m^2/s^2\)
So, the final rotational kinetic energy of the rotating disk is 2.52 kg.\(m^2/s^2\)
To find how much the rotational kinetic energy has decreased, we can subtract the final rotational kinetic energy from the initial rotational kinetic energy.

Initial rotational kinetic energy = \((1/2) * (moment of inertia) * (initial angular velocity)^2\)
Initial rotational kinetic energy = \((1/2) * (0.035 kg.m^2) * (15 rev/s)^2\)
Simplifying the equation:
Initial rotational kinetic energy = \(0.5 * 0.035 * (15^2) kg.m^2/s^2\)
Initial rotational kinetic energy = \(0.5 * 0.035 * 225 kg.m^2/s^2\)
Initial rotational kinetic energy = \(3.9375 kg.m^2/s^2\)

Rotational kinetic energy decrease = Initial rotational kinetic energy - Final rotational kinetic energy
Rotational kinetic energy decrease = \(3.9375 kg.m^2/s^2 - 2.52 kg.m^2/s^2\)
Rotational kinetic energy decrease = \(1.4175 kg.m^2/s^2\)

Therefore, the rotational kinetic energy has decreased by \(1.4175 kg.m^2/s^2\).

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Waves share common characteristics such as wave motion, amplitude, wavelength, frequency, wave speed, and interactions with boundaries. These properties are fundamental to understanding the behavior and properties of various types of waves, including sound waves, electromagnetic waves, water waves, and seismic waves.

A characteristic of all waves is their ability to transfer energy without transferring matter. This fundamental property distinguishes waves from other forms of energy transfer, such as the movement of objects in a solid or the flow of fluids. Waves propagate through various mediums or through empty space, carrying energy from one location to another.

Waves exhibit several common characteristics, including:

1. Wave Motion: Waves involve the transfer of energy through periodic oscillations or vibrations. The particles or fields involved in the wave motion move back and forth around their equilibrium positions, transmitting the energy along the wave path.

2. Amplitude: The amplitude of a wave represents the maximum displacement or disturbance from the equilibrium position. It corresponds to the intensity or strength of the wave and can be measured as the maximum height, displacement, or value of a wave.

3. Wavelength: The wavelength of a wave is the distance between two consecutive points with the same phase or the distance covered by one complete cycle of the wave. It is commonly represented by the symbol λ and is usually measured in meters or other appropriate units.

4. Frequency: The frequency of a wave refers to the number of complete oscillations or cycles that occur per unit of time. It is denoted by the symbol f and is measured in hertz (Hz). The frequency and wavelength of a wave are inversely related and are related to the speed of the wave through the equation v = fλ, where v represents the wave velocity.

5. Wave Speed: The wave speed represents the rate at which a wave travels through a medium or through empty space. It is the product of the wavelength and the frequency of the wave and is usually denoted by the symbol v. The speed of a wave depends on the properties of the medium through which it travels.

6. Reflection, Refraction, and Diffraction: Waves can undergo interactions with boundaries or obstacles, resulting in phenomena such as reflection (bouncing off a surface), refraction (bending when passing through different mediums), and diffraction (spreading out or bending around obstacles).

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