A deck of cards has dimensions 8.9cm x 5.72cm x 1.82 cm. What is the volume of the deck in cubic centimeters?

Answer:

The ranks is

Ge: 3d10 4s2 4p2 (6 electrons in the outer shell)

Br: 3d10 4s2 4p5 (7 electrons in the outer shell)

Kr: 3d10 4s2 4p6 (8 electrons in the outer shell)

Explanation:

Electronic configuration reffers to the distribution of electrons of an atom or molecule in atomic or molecular orbitals. It gives us the understanding of the shape and energy of its electrons. The electronic configuration explain the The electron affinity or propensity to attract electrons

It Should be noted that the most stable configuration in an electronic configuration is attributed to when the last shell is full, i.e. when the last shell has 8 electrons.

When an atom is closer to reach the 8 electrons in the outer shell, then it's electron affinity big.

Considering the given three configuration of the elements above, we can see that "Br"needs requires only 1 electron to have 8 electrons in the outer shell, therefore, it is considered to have the biggest electron affinity among them which is reffers to as the LEAST NEGATIVE.

Ge: with the electronic configuration 3d10 4s2 4p2 has 6 electrons in the outer shell which means it still requires 2 electrons to complete 8 electrons in its outer shell, so it can be deducted that it posses an atom that is more negative than Br.

Kr: with the electronic configuration 3d10 4s2 4p6 which is a noble gas has 8 electrons in the outer shell cannot add more electrons to its outer shell because the 8 electrons is complete posses the least electron affinity among the three elements and it is the MOST NEGATIVE

Strong bonds between the atoms are shown by the high melting and boiling temperatures of metals.

The coordination number for each atom is either eight or twelve, and metallic solids contain metal atoms arranged in face-centered or body-centered patterns. The difficulty is that the bonding is too strong for London Dispersion forces, in addition to the fact that there are insufficient electrons to form covalent bonds. The problem is solved by the fact that the nuclei of the metals float in a sea of electrons. Metals transmit electricity because the electrons are mobile and delocalized.

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Answer:

15

Explanation:

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

The measured cell potential would be decreased to 0.01% if the salts are the conducting and spontaneous with a standard potential 0.59eV.

The potential difference between two half cells in an electrochemical cell is measured as the cell potential, or Ecell. The electrons ability to move from one half cell to the other is what causes the potential difference.

Due to the fact that the chemical reaction is a redox reaction, electrons can move between the electrodes. When one substance is reduced while another is oxidized, a redox reaction takes place.

As a result of losing one or more electrons during oxidation, the substance gains a positive charge. On the other hand, the substance picks up electrons during reduction and becomes negatively charged.

Cell potential = E-e

=2.18-4.19=-1.01eV

The difference between the potential for the reducing agent to become oxidized and the potential for the oxidizing agent to become reduced will determine the cell potential, which is relevant to the measurement of the cell potential.

A specific value can be assigned to the cell potential because the cell potential (Ecell) is measured in voltage (V).

Standard reduction potential =Ecell/2

=1.18/2=0.59eV

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Answer: B. all the resources used to produce any goods and services

Explanation:

      The factors of production are all the resources used to produce any goods and services. This means our answer is option B.

      This includes, but is not limited to, land, labor, capital, and entrepreneurship.

Answer:

Explanation:

\(\text{From the information given:}\)

\(C_o = 0.20 \ wt\% \\ \\ C_s = 1 \ wt\% \\ \\ t = 51 \ h \\ \\ x = 3.9 \ mm \\ \\ C_x = 0.35 \ wt\%\)

\(\text{Using Fick's 2{nd} \ law \ of \ diffusion;} \\ \\ \dfrac{C_x- C_o}{C_s-C_o}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})\)

\(\dfrac{0.35-0.20}{1-0.20}= 1 - erf ( \dfrac{x}{2\sqrt{Dt}})\)

\(0.1875 = 1 - erf ( \dfrac{x}{2\sqrt{DT}}) \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 1 - 0.1875 \\ \\ erf ( \dfrac{x}{2\sqrt{DT}}) = 0.8125\)

\(\text{To find the value of Z by Obtaining Data from Tabulation of Error Function}\) \(\text{Table Values:}\)

Z              erf(z)

0.90  →  0.7970

0.95  →  0.8209

?        →  0.8225

∴

\(\dfrac{z-0.90}{0.95-0.90}= \dfrac{0.8125-0.7970}{0.8209-0.7970}\)

\(\dfrac{z-0.90}{0.05}= \dfrac{0.0155}{0.0239}\)

\(z = 0.9324\)

\(\text{To determine the diffusion coefficient;}\)

\(erf (0.9324) = 0.8125 = erf (\dfrac{x}{2\sqrt{Dt}}) \\ \\\)

\(\dfrac{x}{2 \sqrt{Dt}}= 0.9324 \\ \\ \dfrac{3.9 \times 10^{-3}}{2 \times \sqrt{D\times 51 \times 3600}} = 0.92324 \\ \\ \sqrt{D} = 4.88 \times 10^{-6} \\ \\ D = \sqrt{4.88 \times 10^{-6}} \\ \\ D = 2.38 \times 10^{-11} \ m^2 /s\)

Answer:

The mass of zinc sulfide produced is  \(M_{ZnS} = 0.76 \ g\)

Explanation:

From the question we are told that

   The mass of zinc is  \(m_z = 0.750 \ g\)

    The mass of sulfur is  \(m_s = 0.250 \ g\)

The molar mass   of  \(Zn_{(s)}\)  is a constant with value  65.39 g /mol

The molar mass of \(S_{(s)}\)  is a constant with value  32.01 g/mol

The molar mass of  \(ZnS_{(s)}\) is a constant with value 97.46  g/mol

The reaction is  

        \(Zn_{(s)} + S_{(s)} ------> ZnS_{(s)}\)

   So from the reaction

       1 mole of  \(Zn_{(s)}\) react with 1 mole of  \(S_{(s)}\) to produce 1 mole of \(ZnS_{(s)}\)

This implies that

65.39 g /mol of  \(Zn_{(s)}\) react with 32.01 g/mol of  \(S_{(s)}\) to produce   97.46  g/mol  of \(ZnS_{(s)}\)

From the values given we can deduce that the limiting reactant is sulfur cause  of the smaller mass

 So  

    0.250 g of  \(Zn_{(s)}\) react with 0.250 of  \(S_{(s)}\) to produce \(x \ g\) of  \(ZnS_{(s)}\)

So

      \(x = \frac{97.46 * 0.250}{32.01}\)

       \(x = 0.76 \ g\)

Thus the mass of the mass of zinc sulfide produced is

    \(M_{ZnS} = 0.76 \ g\)

Answer: how do we answer when there are no options??

Explanation:

Question 1

1) The formula of iron(II) iodide is \(\text{FeI}_{2}\) and has a formula mass of 309.654 g/mol. This means that in 12.2 grams, there are

So, the molarity is (0.039398812868557)/(0.5) = 0.0788 M (to 3 sf)

2) In 0.039398812868557 mol of iron(II) iodide, there are 0.039398812868557 moles of iron(II) iodide cations, and thus the molarity is still 0.0788 M (to 3 sf)

3) In 0.039398812868557 mol of iron(II) iodide, there are

Thus, the molarity is (0.078797625737114)/(0.5) = 0.158 M (to 3 sf)

Question 2

1) The formula of iron(III) sulfate is \(\text{Fe}_{2}\text{(SO}_{4})_{3}\) and has a formula mass of 399.9 g/mol. This means that in 16.8 grams, there are

So, the molarity is (0.042010502625656)/(0.25) = 0.168 M (to 3 sf)

2) In 0.042010502625656 moles of iron(III) sulfate, there are 2(0.042010502625656)=0.084021005251312 moles of iron(III) cations, so the molarity is:

3) In 0.042010502625656 moles of iron(III) sulfate, there are 3(0.042010502625656)=0.12603150787697 moles of sulfate anions, so the molarity is:

Question 3

Since we need 50.0 mL of solution at 0.271 M,

So, we need this from 12.0 M HBr so, meaning that:

In English, you're asked to write a reflective narrative about a life event with a deeper impact than initially visible. Describe the event, your reaction, its deeper meaning, and how it shaped you.

This question pertains to reflective writing, a style typically used in English subject coursework. The task is about developing a narrative based on a memorable experience in your life that had a deeper impact than initially visible. Begin by selecting an event, which while appearing simple, had profound implications in retrospect. Describe the event in detail (who, what, where, when), discussing your personal reaction at the time. Then, explain its deeper meaning or the impact it had on you. Drawing conclusions about how this event shaped your perspectives or behaviours would constitute the reflective element of your narrative.

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Answer:

400 mL

Explanation:

Boyle's Law: \(P_1*V_1 = P_2*V_2\)

Let x = the resulting volume

350 (200) = 700 (x)

x = 400 mL

Answer:

c. liquid

Explanation:

because the are not very close if the said very closely packed together it would have been a solid

The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na +  HOH → NaOH + H\(_2\). Cd (g) + S\(_8\) (g) → CdS (g) is combination reaction.

An equation per a chemical reaction is said to be balanced if both the reactants plus the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides between the reaction have an equal balance of mass and charge. The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na +  HOH → NaOH + H\(_2\).

Cd (g) + S\(_8\) (g) → CdS (g) = combination reaction

K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\)  = decomposition reaction

Na +  HOH → NaOH + H\(_2\) = Hydration reaction

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The molarity of the stoke solution is 14.8 M. Then we need 101.35 ml of the stoke solution with 648.65 ml of distilled water to make 750.0 ml of 2.00 M H₃PO₄ solution.  

Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute to the volume of solution in liters.

If we have a stoke solution of molarity M1 and volume V1, and the solution prepared from the stoke solution is having molarity M2 and volume V2, then,

M1 V1 = M2 V2.

Given, M1 for the stoke acid solution = 14.8 M

M2 = 2 M

V2 = 750 ml.

then V1 = M2 V2/V1

V1 = 750 ml × 2 M /14.8 M= 101.35 ml.

water to be added to 750 ml = 750 - 101.35 = 648.65 ml

Therefore, you have to combine 101.35 ml of 14.8 M H₃PO₄ with  648.65 ml distilled water to make 750 ml of 2 M solution.

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The main consequence of exposure to the chemicals at Love Canal was:

allergies.

hair loss.

upper respiratory disease.

The following balanced chemical equation may be used to describe the interaction between aluminum (Al) and calcium nitrate (Ca(NO₃)₂):

2 Al + 3 Ca(NO₃)₂ → 2 Al(NO₃)3 + 3 Ca

Reactants are the chemicals that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

The substances that initiate a chemical reaction. Products are the substances that are created during the reaction. Compounds or elements can act as reactants and products.

Aluminium and calcium nitrate interact in this reaction to form aluminium nitrate (Al(NO₃)₃) and calcium (Ca), which are the end products.

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In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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The saturated molecules of the organic compounds shown are option aA and B.

Saturated organic compounds are organic compounds that have only single carbon-to-carbon bonds present in their molecules.

Saturated organic compounds are mainly the family of hydrocarbons called alkanes.

Alkanes are hydrocarbons, that is, organic compounds made up f only carbon and hydrogen in their molecules.

Examples of alkanes include methane, heptane, butane, etc.

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The compounds that are saturated are the compounds A and B.

A compound is saturated if the compound is made up of only singe bonds. The implication of this is that all the carbon atoms that can be found in the compound all have the full compliment of the hydrogen atoms that they ought to have.

Looking at the compounds tat we have as is shown in the options, the compounds that do have the single bonds are the options A and B and these are the compounds that can be said to be saturated.

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1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Ca(OH)₂ having a different solubility with a change in pH. Option 3 is correct.

The solubility of a compound can be affected by changes in pH when the compound has acidic or basic properties. If the compound can undergo an acid-base reaction in solution, the solubility may be influenced by the pH of the solution.

Out of the given compounds, the compound that can undergo an acid-base reaction and show a different solubility with a change in pH is Ca(OH)₂ (option 3). This compound is a strong base and can react with protons (H⁺) in solution to form Ca²⁺ ions and water molecules:

Ca(OH)₂ + 2 H⁺ → Ca²⁺ + 2 H2₂O

As the pH of the solution decreases (i.e. becomes more acidic), the concentration of H⁺ ions in solution increases, favoring the reaction to the left and decreasing the solubility of Ca(OH)₂.

Conversely, as the pH of the solution increases (i.e. becomes more basic), the concentration of H⁺ ions in solution decreases, favoring the reaction to the right and increasing the solubility of Ca(OH)₂.

Hence, 3. Ca(OH)₂ is the correct option.

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4

beacause it is4 is teta and 7 is hepta

Answer:

The three pKa values for phosphoric acid (H3PO4) are 2.12, 7.21, and 12.32.

1,3 diiodo propane is formed when oxetane is heated at reflux.

Reflux is defined as the process which involves heating the chemical reaction for a specific amount of time, while continually cooling the vapor produced back into liquid form, using a condenser. The vapors that are produced above the reaction continually undergo condensation, returning to the flask as a condensate.

Oxetane is a stable carbon compound which shows characteristic properties when reacted with conc. acids. When oxetane reacts with HI it gets reduced to form 1,3 diiodo propane which is also an organic compound.

Therefore, when oxetane is heated in excess amount of concentrated HI, the product formed is 1,3 diiodo propane.

The reaction is given in the image attached below.

The given question is incomplete and the completed question is given below.

Draw the structural formula(s) for the organic product(s) formed when the following compound (OXETANE) is heated at reflux in an excess of concentrated (HI) .

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The minimum entropy change of the heat-supplying source is -0.87 kJ/K.

In this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.

S₁ = 1.485  +  (0.1)(5.6865) = 2.0537 kJ/kg K

The entropy at the final state given the new 40-% quality:

S₂ = 1.4337  +  (0.4)(5.7894) = 3.7495 kJ/kg K

m₁ = 0.026/(0.001057   +  0.1 x 1.002643) = 0.257 kg

m₂ = 0.026/(0.001053   +  0.4 x 1.158347)  = 0.056 kg

ΔS + S₁  - S₂  + S₂m₂  - S₁m₁  -  sfg(m₂  -  m₁)  > 0

ΔS + 2.0537 -  3.7495 + (3.7495 x 0.056)  -   (2.0537 x 0.257)  - 5.6865( 0.056 - 0.257)  >  0

ΔS > -0.87 kJ/K

Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.

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The balanced chemical equation for the reaction between strontium and oxygen can be written as follows: 2 Sr (s) + \(O_2\)(g) → 2 SrO (s).

In this equation, solid strontium (Sr) reacts with gaseous oxygen (\(O_2\)) to produce solid strontium oxide (SrO).

To determine the mass of product expected to form in this reaction, we need to consider the molar ratio between strontium and strontium oxide. From the balanced equation, we can see that 2 moles of strontium react to produce 2 moles of strontium oxide.

The molar mass of strontium (Sr) is 87.62 g/mol, and the molar mass of strontium oxide (SrO) is 119.62 g/mol. Since the molar ratio is 1:1 between strontium and strontium oxide, the mass of strontium oxide formed will be equal to the mass of strontium used.

In this case, the student added 4.93 g of strontium to the crucible. Therefore, the expected mass of strontium oxide formed will also be 4.93 g.

It's important to note that this calculation assumes that the reaction proceeds to completion, meaning that all of the strontium reacts with oxygen. In actual laboratory conditions, the yield of the reaction may be less than 100% due to factors such as incomplete reaction, side reactions, or product loss.

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