The maximum vertical force that may be applied to link ab without causing the disk to slip at c is 0.2mg.
When the disk is on the verge of slipping, the friction force acting on it is at its maximum value. The friction force is given by f = μN, where μ is the coefficient of static friction and N is the normal force acting on the disk.
In this case, the normal force is equal to the weight of the disk, which is mg, where g is the acceleration due to gravity. Therefore, the maximum friction force is μmg.
To prevent the disk from slipping, the vertical force applied to link ab should not exceed the friction force, i.e., P ≤ μmg. Substituting μ = 0.2, we get P ≤ 0.2mg. Therefore, the maximum vertical force that may be applied to link ab without causing the disk to slip at c is 0.2mg.
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1. If the velocity of an object changes from 20 m/s to 50 m/s over the course of 5
seconds, what is its acceleration?
2. if the velocity of an object changes from 40 m/s to 10 m/s over a time interval of 2
seconds what is its average acceleration? Help please
The accelaration is 15 ms.
What is accelaration?Acceleration (a) is the reason that change in velocity (Δv) over to the change in time (Δt).
represented by the equation to a = Δv/Δt. This allows you to measure how fast velocity by the changes in meters per second squared (m/s^2).
1 . Here the change in to the velocity is (50-20) or 30 m/s
And the time interval by to the 5
So acceleration is 30/5 or 6 ms^-2
2. Here the change is the (40-10) or 30 m/s in time is the interval is 2 second
So acceleration is 30/2 or 15 ms^-2.
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ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
If all forces are equal and opposite how do things accelerate?
Answer:
It is true that in accordance with Newton's third law of motion, every action has an equal and opposite reaction, meaning that when one object exerts a force on another object, the second object exerts an equal and opposite force back on the first object. However, this does not necessarily mean that the objects will not accelerate.
Acceleration depends on the net force acting on an object, which is the sum of all forces acting on the object. If the forces are balanced (i.e. they are equal and opposite), then there is no net force and the object will not accelerate. However, if the forces are unbalanced (i.e. they are not equal and opposite), then there is a net force and the object will accelerate in the direction of the net force.
For example, if you push a book across a table with a force of 5 N to the right, the book will experience a force of 5 N to the left due to friction. These two forces are equal and opposite, but they are not balanced because they act in opposite directions. The net force on the book is therefore 5 N to the right, which causes the book to accelerate in that direction.
the core of a highly evolved high mass star is a little larger than:
The core of a highly evolved high mass star, depending on the type of stellar remnant, can be as small as the size of the Earth (for a white dwarf) or as compact as about 10 kilometers (for a neutron star).
The core of a highly evolved high mass star is typically a compact object known as a stellar remnant. There are two main types of stellar remnants that can form depending on the mass of the star: white dwarfs and neutron stars.
A white dwarf is the remnant of a star with a mass up to about 8 times that of the Sun. Its core is about the size of the Earth, which is much smaller compared to the original size of the star.
On the other hand, a neutron star is formed when a star with a mass greater than about 8 times that of the Sun undergoes a supernova explosion. The core of a neutron star is incredibly dense and compact, with a radius typically on the order of 10 kilometers (6.2 miles). Neutron stars are composed primarily of tightly packed neutrons and are extremely massive.
In summary, the core of a highly evolved high mass star, depending on the type of stellar remnant, can be as small as the size of the Earth (for a white dwarf) or as compact as about 10 kilometers (for a neutron star).
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___________ is the ability to keep your body stable and in control while standing still or moving.
A.
Agility
B.
Balance
C.
Coordination
D.
Speed
25pts and brainliest(no links and this is actually pe)
Answer:
B). Balance is ur answer... Hope this helps you....
Explanation:
Answer:
B: Balance
Explanation:
Calculate the potential energy of a person who weighs 80n standing on top of the sunshine bridge 300 meters in the air
73.5 kilojoules are the answer. Since we can compute potential energy, we can convert 250 into 9.8 into 30 into 73500 joules, or u equal to m g h. Consequently, the body's potential energy will be 73500 joules, which is the necessary amount.
This potential energy calculator allows us to calculate the amount of energy that an elevated object has stored inside it. The full name of this effect is gravitational potential energy, and it refers to the energy that an item stores as a result of its height or vertical position.
The great wrecking ball of the crane. The ball's gravitational potential energy depends on both its mass and how high it is elevated. The relationship between gravitational potential energy and an object's mass and height is seen in the following equation:
PE Gravity equals (m, h, and g). The formula is rather simple to comprehend. The height of a non-raised object will be zero, and as a result, it will have no potential energy.
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If the winch applies a force of 1200N, what is the rescuer and victim's [m=120kg]accceleration? make sure to draw a free body diagram of the rescuer and victim
The rescuer and victim's accceleration when 1200N of force is applied will be 0.2m/s².
forces in the y direction: upward force + down force
Due to the downward weight, this is bad. The weight of the people
W = mg
W = 120 kg × (-9.8 )m/s²
W = -1176 Nt
Force up. This is positive because the helicopter is lifting the two people.
F = 1200 Nt
∴ F + W = 24 Nt
The direction is positive, meaning that the people are being moved up.
∵ F = ma
24 Nt = 120 kg × a
acceleration (a) = 24 Nt / 120 kg = 0.2 m/s²
What is force?
A push or pull that an object experiences as a result of interacting with another object is known as a force.
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Radio stations broadcast signals on two different frequency bands. These are called
Answer:
AM(amplitude modulation) and FM(frequency modulation)
Explanation:
A radio frequency band is a small adjacent section of the radio spectrum frequencies, whereby channels are usually used or set aside to be used.
They are usually of two different bands called AM which is known as amplitude modulation and FM which is known as frequency modulation
PLS HELP RN
A stone is thrown horizontally from the top of a 31.2 m tall cliff. The stone lands at a distance
of 21.4 m from the edge of the cliff. What is the initial horizontal velocity of the stone?
When a stone is hurled horizontally from the top of a 31.2 m tall cliff, its horizontal initial velocity is 39.25 m/s.
What is the initial horizontal velocity formula?By measuring the ball's diameter d and dividing it by the time t it takes for it to cross the photogate, one can also calculate the ball's starting horizontal velocity. Therefore, Vo = d/t. The kinematics equations of motion can be used to calculate the horizontal velocity of a projectile motion made by a person or an item.
Calculation:Height of cliff is 31.2 m
distance is 21.4
t = √2h/g
t = √2×31.4/9.8
t = √62.8/9.8
t = 0.80
The stone's first motion:V = 31.4/0.08
V = 39.25 m/s.
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The electric field in an electromagnetic wave propagating in a vacuum has a peak value of 3,000 NIC and wavelength of 500 nm Which of the following is the correct expression for the electric field? B = 12pTcos[(1.05 x 107 m- F1)x - (3.14x 1014 rad/s)t] b. B 1OpTcos[(1.26 x 107 m~1)x (3.77 x 1015 rad/s)t] B = 10uTcos[(600 nm)x (3.14x 1015 rad/s)t] B = 20pTcos[(1.05 x 107 m-1)x - (3.14x 1015 rad/s)t] B 20pTcos[(1.10 x 106 m-1)x (1.57 x 1015 rad/s)t]
The correct expression for the electric field in an electromagnetic wave propagating in a vacuum with a peak value of 3,000 NIC and wavelength of 500 nm would be B = 20pTcos[(1.05 x 107 m-1)x - (3.14x 1015 rad/s)t]. This is because the electric field in an electromagnetic wave is related to its frequency and wavelength through the equation E = hf/λ, where E is the energy of the wave, h is Planck's constant, f is the frequency, and λ is the wavelength. Given the wavelength of 500 nm, we can calculate the frequency of the wave to be 6 x 10^14 Hz.
Then, using the equation E = hc/λ, where c is the speed of light, we can calculate the energy of the wave to be 3.97 x 10^-19 J. Finally, using the equation E = 1/2ε_0 B^2, where ε_0 is the permittivity of free space, we can solve for the amplitude of the electric field, which is 3,000 NIC. Plugging these values into the equation for the electric field of an electromagnetic wave yields the correct expression.
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A 16-gram rubber stopper is attached to a string and spun clockwise in a horizontal circle with a radius of 1.7 m. The stopper maintains a constant speed of 1.8 meters per second. Calculate the magnitude of the centripetal acceleration of the stopper. Round your answer to the nearest tenth of a meter per second (m/s).
The magnitude of the centripetal acceleration of the stopper, given that the rubber stopper has a mass of 16 grams is 1.9 m/s²
How do i determine the magnitude of the centripetal acceleration?The centripetal acceleration can be obtained as illustrated by the following formula:
Centripetal acceleration = v² / r
Where
v is the velocityr is the radiusThe following data were obtained where obtained from the question:
Radius (r) = 1.7 mVelocity of stopper (v) = 1.8 m/sCentripetal acceleration =?Centripetal acceleration = v² / r
Centripetal acceleration = (1.8)² / 1.7
Centripetal acceleration = 1.9 m/s²
Thus, the centripetal acceleration is 1.9 m/s²
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A football player kicks a ball horizontally off a hill with an initial velocity of 42.0 m/s. It travels a horizontal distance of 59.2m. How y’all was the hill he kicked the ball off of?
Answer:
9.74 m
Explanation:
Given the following :
Initial Velocity(u) = 42m/s
Horizontal distance (d) = 59.2m
Using the motion equation:
H = ut + 0.5×g×t^2
Where H = height, g = acceleration due to gravity (9.8m/s^2), t = time, u= Initial Velocity
Time(t) = horizontal distance / velocity
t = 59.2 / 42 = 1.41seconds
Therefore,
H = (0 × 1.41) + 0.5(9.8)×(1.41)^2
H = 0 + 9.74169
H = 9.74m
to pass a slow-moving truck, you need your 1300 kg car to accelerate from 13.4 m/s to 17.9 m/s in 3 seconds. what is the power required to pass
Answer:
P = E / t definition of power
P = (1/2 m v2^2 - 1/2 m v1^2) / t
P = m / (2 * t) * (v2^2 - v1^2)
P = 1300 kg / 6 sec * (17.9^2 - 13.4^2)
P = 217 * 141 = 30,600 J/sec
The power required to pass the slow-moving truck is 34,905 watts.
What is power?Power is a physical quantity that measures the rate at which work is done or energy is transferred. It is defined as the amount of energy transferred or work done per unit time. The SI unit of power is watts (W), which is equivalent to joules per second (J/s).
In simpler terms, power is the rate at which energy is used or work is done. It is a measure of how quickly something can accomplish a certain task or transfer energy. The greater the power of a system, the faster it can perform a given amount of work.
Power = Work done / time taken = Force x distance/time taken
Here in the Question,
To calculate the power required to pass the slow-moving truck, we need to use the formula:
Power = Force x Velocity
where Force is the net force acting on the car and Velocity is the final velocity of the car after acceleration.
To find the force, we can use Newton's second law of motion:
Force = mass x acceleration
where mass is the mass of the car and acceleration is the change in velocity over time.
Given:
Initial velocity, u = 13.4 m/s
Final velocity, v = 17.9 m/s
Time, t = 3 s
Mass of car, m = 1300 kg
The acceleration can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration = (17.9 m/s - 13.4 m/s) / 3 s
Acceleration = 1.5 m/s^2
Now we can calculate the force:
Force = mass x acceleration
Force = 1300 kg x 1.5 m/s^2
Force = 1950 N
Finally, we can calculate the power required to pass:
Power = Force x Velocity
Power = 1950 N x 17.9 m/s
Power = 34,905 W
Therefore, the power required to pass the slow-moving truck is 34,905 watts (or approximately 35 kW).
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Consider a 0.95 MeV y-ray photon. Randomized Variables E = 0.95 MeV
Considering a 0.95 MeV y-ray photon and Randomized Variables E = 0.95 MeV so the frequency of light will be 2.294×10²⁰ Hz.
Given,
The energy of photon
E = 0.95 MeV = 0.95× 1.6×10⁻¹³ J or 1.52 × 10⁻¹³ J
Using E = hυ
We have:
υ = E/h = 1.52×10⁻¹³/(6.626×10⁻³⁴)
= 2.294×10²⁰ Hz
Thus the frequency of light will be 2.294×10²⁰ Hz.
Associated to each wave vector ~k and polarization state σ there is an electromagnetic normal mode of oscillation with frequency ω(k) = kc and complex amplitude aσ( ~k). In the absence of sources, the behavior of the electromagnetic field is completely described by these normal modes. We will assume the normal modes are defined using periodic boundary conditions.
For each ~k and σ there is a Hilbert space of square integrable functions and a Hamiltonian( ~k). For each ~k and σ there is a basis of energy eigenvectors; the corresponding ladder operators act on this basis by adding and subtracting quanta of energy ω(k).
We can use this basis to induce a basis for the tensor product over all the oscillator Hilbert spaces, which is the state space for the composite system of normal modes, i.e., the electromagnetic field.
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A ball is thrown horizontally out the window of a tall building with a velocity of 7.3 m/s
from a height of 206 m. How far from the base of the building will the ball land?
gravity=10m/s²
A branch of physics called kinematics, which originated in classical mechanics, defines how points, bodies, and systems of bodies move without taking into account the forces that are responsible for their motion.
Let's go over the four basic kinematic equations of motion with constant acceleration:
s = ut + ½at^2 …. (1)
v^2 = u^2 + 2as …. (2)
v = u + at …. (3)
s = (u + v)t/2 …. (4)
where an is acceleration, s is distance, u is beginning velocity, v is final velocity, and t is time.
To determine the horizontal distance traveled in this instance, we first need to determine the time it takes for the ball to fall vertically to the ground.
Knowing u = 0, a = g = 9.81 m/s2, and s = 5 m for the vertical drop, we can use equation (1) to obtain
s = ut + ½at^2
5 = 0 +4.905t^2
t = √(5/4.905) = 1.01s
Now that we have t, we can calculate the horizontal distance.
s = ut + ½at^2
s = 35(1.01) + 0 (no horizontal acceleration) (no horizontal acceleration)
s = 35.35m
The ball thus travels 35.35 meters before striking the ground.
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a horizontal wire that is 25 m long and has a mass of 100 g is held under a tension of 10 n. a sinusoidal wave of frequency 25 hz and amplitude 15 mm travels along the wire. calculate the maximum traveler velocity of any particle of the wire.
the maximum velocity of movement of any particle of the wire is 3.87 m/s
AND)
and)
L = wire length = 25 m
m = weight of wire = 100 g = 0.1 kg
The linear mass density of the wire is given as
μ = m/L = 0.1/25 = 0.004 kg/m
T = tensile force in the wire = 10 N
the speed of the wave along the wire is given as
v =√(T/μ)
v = √ (10/0.004)
v = 50 m/s
(ii)
A = amplitude = 15 mm = 0.015 m
f = frequency = 25 Hz
the maximum lateral velocity is given as
Vmax = 2πfA
Vmax = 2(3.14)(25)(0.015)
Vmax = 2.4 m/s
b)
F = force acting on each edge = 2.5 N
L = length of each edge = 0.75 m
m = weight of each edge = 125 g = 0.125 kg
the speed of the waves on the sheet is given as
v = √(FL/m) = √(2.5 x 0.75/0.125) = 3.87 m/s
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calculate the deceleration of the car
Answer:
C
Explanation:
Answer:
i think the answer is a because of division
Explanation:
Q: Why are distances in space often measured in light years?
A) The light year is a commonly used unit of measurement
B) Distances in space are so great that a large unit is needed
C) Scientists like to use measurements to confuse people
D) Light years are easy to measure and understan
Which one of these Target games uses the underhand throw?
A: Golf
B: KanJam
C: Corn-Hole
D: None Of The Above
HELP!!
Answer:
Cornhole
Explanation:
Listed in the Item Bank are individual steps that need to be ordered. To find out more information about steps, some have more details
available when you click on them. Drag and drop the steps in the proper order by placing each in its corresponding open rectangle. Be sure
that the earliest step is placed next to the number 1.
Answer:
radio
microwave
Infrared
Visible
Ultraviolet
X-ray
Gamma ray
I hope this helps you a little bit
Sound waves travel at a speed of 330.0 m/s . How long does it take for the sound of thunder to travel 1.5 km ? (20points)
4.55 seconds
Step-by-step explanation:-Given, Speed = 330.0 m/s
To find the time, it will take for the sound of thunder to travel 1.5 km, we have to apply the formula for speed :
\(speed = \frac{distance}{time} \)
This implies that:-
\(time = \frac{distance}{speed} \)
So, Let's get started with the steps -
Step 1- Convert 1.5 km to metres.
\(1.5 \: km \: \\ = > \: 1.5 \times 1000 \\ = > 1500 \: m\)
Step 2- Now, to get time, substitute the values you got now in "time=distance/speed"
\(t = \frac{1500}{330}\)
\( => t = 4.55 \: seconds\)
Therefore, the answer is 4.55 seconds
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What is the “sum of forces” acting on the cart?
The “sum of forces” acting on a cart can be explained as the net force or resultant force acting on it. This term refers to the total amount of force acting on an object, considering both the direction and magnitude. The cart's acceleration is influenced by this force, which is critical in the laws of physics.
The following is a description of the “sum of forces” acting on a cart: The sum of forces can be calculated using the formula F = ma, where F is the force acting on the cart, m is the mass of the cart, and a is the acceleration produced by the force. If there is more than one force acting on the cart, it is necessary to calculate the net force, which is the sum of all the forces acting on the cart.
The sum of forces can be split into two components: internal and external forces. Internal forces are those generated within the object, whereas external forces are exerted by other objects. The frictional force between the wheels of the cart and the surface is an example of an internal force acting on the cart.
The gravitational force exerted by the Earth is an example of an external force acting on the cart. If there are more than two forces acting on the cart, vector addition must be used to determine the net force.
The sum of forces acting on the cart is critical in the laws of physics. If the sum of forces acting on the cart is zero, it implies that there is no net force acting on it, and it is either stationary or moving at a constant velocity. If the sum of forces is nonzero, it implies that there is a net force acting on the cart, and it is either accelerating or decelerating.
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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
Answer:
Newton's second law: F=ma.
Force = mass x acceleration
This basically means, that the more massive something is, and the faster it is going, the more force the object will have.
So, the factors that can be used to find acceleration are:
F=ma
a=F/m
So, we see that the correct answer is A, mass and force.
Let me know if this helps!
I need help with this question, please add an explanation so can understand
The acceleration of the the object is 20m/s²
What is force?Force can be defined as the product of the mass of an object with it's acceleration. It is measured in Newton(N) and it is a vector quantity. This means that force has both magnitude and direction.
from the diagram two forces are acting on the object in opposite directions. Therefore the net force = 30-10 = 20N
force = mass × acceleration. This operational definition of force is obtained from Newton second law of motion.
where mass = 1kg
20N = 1× acceleration
acceleration = 20/1= 20m/s²
therefore the acceleration of the object = 20m/s²
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What do we mean when we say that momentumis a vector
Answer:
it has both magnitude and direction.
Explanation:
which equation correctly represents the gravitational potential energy of a system?
Answer:ME= 1\2mv^2 + mgh
Explanation: I hope this helped.
The correctly represents the gravitational potential energy of a system is = - ΣGM₁M₂/R. Negative sign appears as gravitational force is attractive force.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.
If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.
Potential energy of a system of particles can be represented as summation of individual's potential energy. Hence, the correctly represents the gravitational potential energy of a system is = - ΣGM₁M₂/R.
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if the free energy of the product (p) is greater than the free energy of the substrate (s) there will be a greater concentration of p than s present at equilibrium.
T/F
True. The free energy of a system refers to the energy that is available to do work and is represented by the symbol "G." The Gibbs free energy change (∆G) of a chemical reaction is a measure of the difference in free energy between the products and the reactants.
If the free energy of the products is greater than that of the substrates, the Gibbs free energy change will be negative (∆G<0). This means that the reaction is exergonic, and it proceeds spontaneously in the forward direction.
At equilibrium, the concentrations of reactants and products are balanced, and the Gibbs free energy change is zero (∆G=0). If the free energy of the products is greater than that of the substrates, it means that the products have a higher free energy potential and are more energetically favored than the substrates. As a result, there will be a greater concentration of products than substrates at equilibrium.
In summary, the statement is true because a negative Gibbs free energy change indicates that the products are favored over the substrates, resulting in a higher concentration of products at equilibrium.
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what is the mass of a hiker 350m above the ground if her GPE is 120,200 J?
Given:
The height from the ground is h = 350 m
The gravitational potential energy is GPE = 120,200 J
To find the mass of the hiker.
Explanation:
The mass of the hiker can be calculated by the formula
\(\begin{gathered} GPE\text{ =mgh} \\ m\text{ =}\frac{GPE}{gh} \end{gathered}\)Here, g =9.8 m/s^2 is the acceleration due to gravity.
On substituting the values, the mass of the hiker will be
\(\begin{gathered} m\text{ =}\frac{120200}{9.8\times350} \\ =35.044\text{ kg } \end{gathered}\)Thus, the mass of the hiker is 35.044 kg
Consider the following figures. Determine the direction of the current in the current-carrying wire that produces the field indicated in the figure.
Options:
out of the screen
into the screen
toward the left
toward the right
toward the top of the screen
toward the bottom of the screen
The direction of the current in the current-carrying wire that produces the field indicated in the figure is given below.
Conventionally, a positive charge would go in the same direction as an electric current. As a result, the battery's positive terminal receives less current in the external circuit than its negative counterpart. Indeed, electrons would go in the reverse direction across the cables.
According to Fleming's right-hand rule gives which direction the current flows. The right hand is held with thumb, index finger & middle finger mutually perpendicular to each other. The thumb is pointed in direction of motion to magnetic field of conductor relative to magnetic field.
(A) from right hand rule direction of current is towards left.
(B) Out of the Screen.
(C) Lower left to upper right.
According to Fleming's Right Hand Rule, if the thumb, forefinger, and middle finger are arranged in a straight line on the right hand, the thumb will point in the direction of the conductor's motion in relation to the magnetic field, the forefinger will point in the direction of the magnetic field, and the middle finger will point in the direction of the induced current.
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Full Question ;
Consider the following figures. Determine the direction of the current in the current-carrying wire that produces the field indicated in the figure. (a) * * * * * * * * * * * Bin * O out of the screen O into the screen O toward the left toward the right toward the top of the screen toward the bottom of the screen (b) O out of the screen O into the screen O toward the left toward the right O toward the top of the screen toward the bottom of the screen (C) * * * * O out of the screen into the screen lower right to upper left lower left to upper right upper right to lower left upper left to lower right
how would an increase in force affect the mechanical advantage of a simple machine
Mechanical advantage is a measure of the ratio of the output force produced to the input force applied in a system, mainly in the case of simple machines, such as levers and pulleys. It is a dimensionless quantity.
From the definition, the mechanical advantage of a simple machine is inversely proportional to the input force applied on the system. So, an increase in this force decreases the mechanical advantage of a simple machine.
For example, the mechanical advantage of a lever can be decreased by increasing the force on load arm or by reducing the force on the effort arm.
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