Answer:
Step-by-step explanation:
58 ft (1/10 inch/ft) = 5.8 inch
1) Find an equation of the tangent line at each given point on the curve.x = t2 − 4, y = t2 − 2tat (0, 0)at (−3, −1)at (−3, 3)2) Find the arc length of the curve on the given interval. (Round your answer to three decimal places.)Parametric Equations Intervalx= sqrt1a.gif t y=5t-4 0 ≤ t ≤ 13) Find dy/dx and the slopes of the tangent lines shown on the graph of the polar equation. (If an answer does not exist, enter DNE.)r = 2(1 − sin(θ))
Answer:
1) at ( 0,0) : y = x/2. at(-3-1) : y = -1. at(-3,3) : y = 2x +9
2) DNE ( does not exist )
Step-by-step explanation:
The general equation of tangent line
y - y1 = m( x - x1 )
attached below is the detailed solution on how i derived the answers above
Question #3
Given the following stemplot, determine the maximum value of the original data set.
O 100
8
98
9
0000
Test Scores
5
479
6 146779
7 002557799
8 12223455789
9 000333368
The maximum value of the original data set is 109.
To determine the maximum value of the original data set from the given stemplot, we need to look at the rightmost digits in each stem and identify the highest value.
Looking at the stemplot:
O 10 | 0 0 8 9 8 9 0 0 0
0 20 | 5 4 7 9 6
0 30 | 1 4 6 7 7 9 7
0 40 | 0 0 2 5 5 7 7 9 9 8
0 50 | 1 2 2 2 3 4 5 5 7 8 9 9
0 60 | 0 0 0 3 3 3 3 6 8
The rightmost digits in each stem represent the original data values. We can see that the highest value occurs in the stem "10" with a rightmost digit of "9".
Therefore, the maximum value of the original data set is 109.
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Find the 5th term in a sequence whose general term is an = 3n + 7.A) 17B) 25C) 8D) 22
Given the sequence below
\(a_n=3n+7\)We are asked to find the 5th term of the sequence.
Explanation
This can be done by substituting 5 for n in the general term of the sequence.
Thus,
\(\begin{gathered} a_n=(3\times5)+7 \\ =15+7 \\ =22 \end{gathered}\)Answer:
Option D
in the expansion of (2a 4b)8, which of the following are possible variable terms? explain your reasoning. a2b3; a8; a5b3; ab8; a3b5; a7b; a6b5; b8
The possible variable terms are a2b3, a5b3, ab8, a3b5, a7b, and a6b5. These terms all contain the same number of a's and b's as the original expression, (2a4b)8.
The expansion of (2a 4b)8 can be found by multiplying the a coefficients and b coefficients by 8. The a coefficients would increase by a factor of 8 and the b coefficients would increase by a factor of 8. This means that the possible variable terms for (2a 4b)8 are all those that have 8 a's and 8 b's. This includes a2b3, a5b3, ab8, a3b5, a7b, and a6b5. These terms all contain the same number of a's and b's as the original expression, (2a4b)8, but with the coefficients multiplied by 8. For example, the term a2b3 would be the result of multiplying 2a4b by 8, which results in 16a32b. This can be simplified to a2b3. Similarly, a5b3 would be the result of multiplying 2a4b by 8, which results in 16a32b. This can be simplified to a5b3.
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Given the function f(x) = 0.5|x - 41-3, for what values of x is f(x) = 7?
x = -24, x = 16
x= -16, x = 24
x=-1, x = 9
x = 1, x = -9
The values of x for which f(x) = 7 are x = 61 and x = 21.
To find the values of x for which f(x) = 7, we can set up the equation and solve for x.
The given function is f(x) = 0.5|x - 41| - 3.
Setting f(x) equal to 7, we have:
0.5|x - 41| - 3 = 7.
First, let's isolate the absolute value term:
0.5|x - 41| = 7 + 3.
0.5|x - 41| = 10.
To remove the absolute value, we can consider two cases:
Case: (x - 41) is positive or zero:
0.5(x - 41) = 10.
Multiplying both sides by 2 to get rid of the fraction:
x - 41 = 20.
Adding 41 to both sides:
x = 61.
So x = 61 is a solution for this case.
Case: (x - 41) is negative:
0.5(-x + 41) = 10.
Multiplying both sides by 2:
-x + 41 = 20.
Subtracting 41 from both sides:
-x = -21.
Multiplying both sides by -1 to solve for x:
x = 21.
So x = 21 is a solution for this case.
Therefore, the values of x for which f(x) = 7 are x = 61 and x = 21.
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Determine the value of h in the equation 1/5+h=7/5. 6/5 8/25 6/25 8/5
The value of {h} is equivalent to 6/5.
What is a function?A function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that function takes.
Given is the function as follows -
(1/5) + h = (7/5)
We can write the function as -
(1/5) + h = (7/5)
h = 7/5 - 1/5
h = (7 - 1)/5
h = 6/5
Therefore, the value of {h} is equivalent to 6/5.
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In the diagram below of circle O, chords AD and BC intersect at E, and chords AB and CD are drawn.
Which statement must always be true?
PLEASE HELP!
The correct answer is (C) \(\angle B \cong \angle C.\) when In the diagram below of circle O, chords AD and BC intersect at E.
What is a circle ?
A circle is a two-dimensional geometric shape that consists of all the points in a plane that are at a fixed distance from a given point, called the center.
In the given diagram, we have a circle O with chords AB, CD, AD, and BC. The chords AD and BC intersect at point E.
Based on the diagram, we can see that the opposite angles in the quadrilateral AEDC are supplementary (i.e., they add up to 180 degrees). Therefore, we have:
\(\angle A + \angle C = 180^\circ\)
Similarly, the opposite angles in the quadrilateral BEFC are supplementary. Thus,
\(\angle B + \angle C = 180^\circ\)
We can rewrite the second equation as:
\(\angle C = 180^\circ - \angle B\)
Substituting this value of \angle C into the first equation, we get:
\(\angle A + 180^\circ - \angle B = 180^\circ\)
Simplifying, we get:
\(\angle A = \angle B\)
Therefore, the correct answer is (C) \(\angle B \cong \angle C.\)
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5 points
Q3) The population of elephants after t years in a zoo is modeled by the
function:P(t) = 9401+80e-0.15t Which of the following is the approximate
population of elephants after 3 years? *
w
1)18
2)32
3)36
4)80
5)940
Please answer this correctly
Answer:
1.5 meters
Step-by-step explanation:
The formula for the area of a trapezoid is h * (a+b)/2, where a is the first base and b is the second base. Now, we can work backwards to determine the height of the trapezoid:
3.75=h*(1.7+3.3)/2
3.75=h*2.5
h=3.75/2.5=1.5
Hope this helps!
Answer:
Step-by-step explanation:
use the formula and rearrange for h.
1/2 x h x (a + b) = A
1/2 x (1.7 + 3.3) x h = 3.75
2.5 x h = 3.75
h = 1.5
hope this helps! :)
Point M is the midpoint of AB. If the coordinates of A are ( -3 , 6 ) and the coordinates of M are ( -5 , 2 ), what are the coordinates of B? (reference sheet on the left side)
The coordinates of B are (-7,-2).
What do you mean by x and y coordinates?
The x and y coordinates are a component of the x-axis and y-axis in a 2D space in the Cartesian coordinate system. The x and y coordinates for a point in space are expressed as an ordered pair (x, y). The position of the point on the x-axis is shown by the first number, while its location on the y-axis is indicated by the second number.
According to the given data in the question,
if M is the location where line segment AB meets its midpoint.
Then, we will using the midpoint formula,
\((-5,2)=(\frac{-3+x}{2},\frac{6+y}{2})..............(1)\)
Putting the x-coordinates in (1),
\(-5=\frac{-3+x}{2}\\ -10=-3+x\\-10+3=x\\x=-7\)
Similarly, putting the y-coordinates in (1),
\(2=\frac{6+y}{2} \\4=6+y\\4-6=y\\y=-2\)
Hence, the coordinates of B are (-7,-2).
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In triangle FGH, g=8ft, h=13ft, and measure of angle F=72 degree. Find measure of angle G
To find the measure of angle G in triangle FGH, we can use the fact that the sum of angles in a triangle is always 180 degrees.
First, we can find the measure of angle H using the fact that the sum of angles in a triangle is 180 degrees:
H = 180 - F - G
H = 180 - 72 - G
H = 108 - G
Next, we can use the Law of Cosines to find the length of side FG:
FG^2 = GH^2 + FH^2 - 2(GH)(FH)cos(F)
FG^2 = 8^2 + 13^2 - 2(8)(13)cos(72)
FG^2 = 169.21
FG ≈ 13.01 ft
Finally, we can use the Law of Cosines again to find the measure of angle G:
cos(G) = (FG^2 + GH^2 - FH^2) / (2(FG)(GH))
cos(G) = (169.21 + 64 - 169) / (2(8)(13))
cos(G) = 0.7686
G ≈ 40.6 degrees
Therefore, the measure of angle G in triangle FGH is approximately 40.6 degrees.
Mr.villescas typed 16 names in a minute. at that rate, how many names could he type in one and a half minute?
He typed 16 names in 1 minutes
\(\begin{gathered} 1\text{ minutes=16 names} \\ 1\frac{1}{2}=\frac{3}{2}\text{minutes}=\text{? names} \\ \frac{3}{2}\times16=24\text{ names} \end{gathered}\)What number is missing from the table of equivalent ratios
8 is missing for the table
Please solve this
∫ (log(1 + x ^ 2))/((x + 1) ^ 2) dx
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
We have,
To solve the integral ∫ (log(1 + x²) / (x + 1)²) dx, we can use the method of substitution.
Let's substitute u = x + 1, which implies du = dx. Making this substitution, the integral becomes:
∫ (log(1 + (u-1)²) / u²) du.
Expanding the numerator, we have:
∫ (log(1 + u² - 2u + 1) / u²) du
= ∫ (log(u² - 2u + 2) / u²) du.
Now, let's split the logarithm using the properties of logarithms:
∫ (log(u² - 2u + 2) - log(u²)) / u² du
= ∫ (log(u² - 2u + 2) / u²) du - ∫ (log(u²) / u²) du.
We can simplify the second integral:
∫ (log(u²) / u²) du = ∫ (2 log(u) / u²) du.
Using the power rule for integration, we can integrate both terms:
∫ (log(u² - 2u + 2) / u²) du = log(u² - 2u + 2) / u - 2 ∫ (log(u) / u³) du.
Now, let's focus on the second integral:
∫ (log(u) / u³) du.
This integral does not have a simple closed-form solution in terms of elementary functions.
It can be expressed in terms of a special function called the logarithmic integral, denoted as Li(x).
Therefore,
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
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Find the measure of ∠B. Angles are in the image below, Need answers ASAP if possible thanks!
Answer:
30
Step-by-step explanation:
The red square means it equals 90 degrees
90 - 60 = 30
I hope this helps
Suppose that X and Y are integer valued random variables with joint probability mass function given by
PX, Y(a, b) = {1/4a, for 1 <= b <= a <= 4
0 otherwise.
a. Show that this is indeed a joint probability mass function.
b. Find the marginal probability mass function of X and Y.
c. Find P(X = Y + 1).
Answer:
Step-by-step explanation:
1)
Given that:
The joint pmf \(p_{X,Y(a,b)}=\left \{ {{\dfrac{1}{4a} \ for \ 1 \le b \le a \le 4 } \\ \\ \atop {0} \ \ \ \ \ \ otherwise} } \right.\)
To emphasize that this is a joint pmf;
We will notice that it obeys two conditions;
it comprises a non-negative number and which is less than 1the sum of all the probabilities adds up and becomes unity.Except that X and Y are integer value variables with 1 ≤ b ≤ a ≤ 4 and X = 1, 2, 3, 4 and Y = 1, 2, 3, 4 respectively, according to the condition Y ≤ X
The table below shows the joint probabilities as a result of this:
y = 1 y = 2 y = 1 y = 4 Total
x = 1 \(\dfrac{1}{4}\) 0 0 0 \(\dfrac{1}{4}\)
x = 2 \(\dfrac{1}{8}\) \(\dfrac{1}{8}\) 0 0 \(\dfrac{1}{4}\)
x = 3 \(\dfrac{1}{12}\) \(\dfrac{1}{12}\) \(\dfrac{1}{12}\) 0 \(\dfrac{1}{4}\)
x = 4 \(\dfrac{1}{16}\) \(\dfrac{1}{16}\) \(\dfrac{1}{16}\) \(\dfrac{1}{16}\) \(\dfrac{1}{4}\)
Total \(\dfrac{25}{48}\) \(\dfrac{13}{48}\) \(\dfrac{7}{48}\) \(\dfrac{3}{48}\) 1
In the table, it is obvious that each respective value of the probability is positive and the addition of all the values sums up to unity (1).
Hence, the given probability shows that it is indeed a pmf(probability mass function).
(b)
Marginal Pmf of x = \(\dfrac{sum \ of \ all \ prob. \ of (x,y)}{y}\)
Marginal Pmf of y = \(\dfrac{sum \ of \ all \ prob. \ of (x,y)}{x}\)
Thus, we can locate the respective values of the marginal probability in the last row as well as the last column in the explained table above.
(c)
To find P(X=Y+1):
P(X = Y + 1) = P(X = 2,3,4)
⇒ 1 - P(X=1)
\(\implies 1 - \dfrac{1}{4} \\ \\ \implies \dfrac{4-1}{4} \\ \\ \implies \dfrac{3}{4}\)
help me asap now pls
Answer:
b=60a
Step-by-step explanation:
What is an equation of the line that passes through the point (1,-7)(1,−7) and is parallel to the line 3x+y=33x+y=3?
Explanation:
Anything parallel to Ax+By = C is of the form Ax+By = D, where C and D are different values.
The given equation is 3x+y = 3. Anything parallel to this is 3x+y = D
Plug (x,y) = (1,-7) into that second equation to compute D
3x+y = D
D = 3x+y
D = 3(1)+(-7)
D = 3-7
D = -4
Therefore, our answer is 3x+y = -4
If you wanted to solve for y, then you'd get y = -3x-4. Both parallel lines have a slope of -3 but different y intercepts.
In Don Javier's milking, milk is collected in two containers, one with a 300-liter capacity and one with 180 liters, if they are filled with 15 and 20-liter jugs. Which of the pitchers exactly fill the containers without milk being left over or missing?
Answer:
Both Pitchers
Step-by-step explanation:
First, we determine how many of each pitcher it would take to fill the 300 liter and 180 liter containers.
300÷15=20 of the 15 liter pitcher
300÷20=15 of the 20 liter pitcher
Similarly
180÷15=12 of the 15 liter pitcher.
180÷20=9 of the 20 liter pitcher.
The two pitchers gives a whole number when their volumes divide the volumes of the containers.
Therefore, the two pitchers exactly fill the containers without milk being left over.
FOR 100 POINTS!!!!!!!!!!!
A food truck did a daily survey of customers to find their food preferences. The data is partially entered in the frequency table. Complete the table to analyze the data and answer the questions:
Likes hamburgers Does not like hamburgers Total
Likes burritos 29 41
Does not like burritos 54 135
Total 110 205
Part A: What percentage of the survey respondents liked neither hamburgers nor burritos? Show all work. (3 points)
Part B: What is the marginal relative frequency of all customers who like hamburgers? Show all work. (3 points)
Part C: Is there an association between liking burritos and liking hamburgers? Use ratios of joint and marginal frequencies to support your answer. (4 points)
Answer:
Part A:
To find the percentage of survey respondents who liked neither hamburgers nor burritos, we need to calculate the frequency in the "Does not like hamburgers" and "Does not like burritos" categories.
Frequency of "Does not like hamburgers" = Total in "Does not like hamburgers" category = 135
Frequency of "Does not like burritos" = Total in "Does not like burritos" category = 54
Total respondents who liked neither hamburgers nor burritos = Frequency of "Does not like hamburgers" + Frequency of "Does not like burritos" = 135 + 54 = 189
Percentage of survey respondents who liked neither hamburgers nor burritos = (Total respondents who liked neither hamburgers nor burritos / Total respondents) x 100
Percentage = (189 / 205) x 100 = 92.2%
Therefore, 92.2% of the survey respondents liked neither hamburgers nor burritos.
Part B:
To find the marginal relative frequency of all customers who like hamburgers, we need to divide the frequency of "Likes hamburgers" by the total number of respondents.
Frequency of "Likes hamburgers" = 110 (given)
Total respondents = 205 (given)
Marginal relative frequency = Frequency of "Likes hamburgers" / Total respondents
Marginal relative frequency = 110 / 205 ≈ 0.5366 or 53.66%
Therefore, the marginal relative frequency of all customers who like hamburgers is approximately 53.66%.
Part C:
To determine if there is an association between liking burritos and liking hamburgers, we can compare the joint and marginal frequencies.
Joint frequency of "Likes hamburgers" and "Likes burritos" = 29 (given)
Marginal frequency of "Likes hamburgers" = 110 (given)
Marginal frequency of "Likes burritos" = 70 (calculated by adding the frequency of "Likes burritos" in the table)
To assess the association, we compare the ratio of the joint frequency to the product of the marginal frequencies:
Ratio = Joint frequency / (Marginal frequency of "Likes hamburgers" x Marginal frequency of "Likes burritos")
Ratio = 29 / (110 x 70)
Ratio ≈ 0.037 (rounded to three decimal places)
Question 6 of 10
62
A
59°
59
Triangle A
Triangle B
Given the triangles above, what is the measure, in degrees, of angler?
Given that m*n = 3m-n/2 , evaluate 6*(3*1)
Answer:
24
Step-by-step explanation:
m × n = 3m - n ÷ 2
6 × (3 × 1)
6 × 4
24
Jessica needs to know how much water her new fish tank can hold:
A rectangular prism with a length of 8 inches, a width of 4 inches, and a height of 9 inches.
Determine the total volume of the fish tank.
The fish tank has a total volume of 288 inch³. As a result, Jessica's new fish tank has a capacity of 288 inch³ for water.
The volume of a rectangular prism can be calculated using the formula:
V = l x b x h..........(i)
where,
V ⇒ Volume
l ⇒ length
b ⇒ width
h ⇒ height
From the question, we are given the values,
l = 8 inches
b = 4 inches
h = 9 inches
Putting these values in equation (i), we get,
V = 8 x 4 x 9
⇒ V = 288 in³
Therefore, the fish tank has a total volume of 288 inch³. As a result, Jessica's new fish tank has a capacity of 288 inch³ for water.
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8) find the values of c that satisfy Rolle's Theorem.
SHOW STEPS
Hence the value of c = 4 in [3,5] for Rolles theorem.
Rolle's Principle
If a function f is defined in the closed interval [a, b] in a manner that meets the requirements listed below.
The interval [a, b] is closed and the function f is continuous.
ii) On the open interval, the function f can be differentiated (a, b)
iii) If f (a) = f (b), then at least one value of x exists; in this case, let's assume that this value is c, which is situated between a and b, i.e. (a c b), in such a way that f'(c) = 0.
There exists a point x = c in (a, b) such that f'(c) = 0 if a function is continuous on the closed interval [a, b] and differentiable on the open interval (a, b).
let f(x)=x²-8x+12 in [3,5]
i) f(x) is continuous in closed interval [3,5] because f(x) is algebraic function.
ii) f(x) is differentiable in the open interval (3,5) since the algebraic function is differentiable.
now f(3)=3²-8*3+12
f(3)= 9-24+12
f(3)= -3
f(5) = 25-40+12
f(5)= - 3
f(3) = f(5)
f'(x)= 2x-8
x=c ,c in [3,5]
f'(c)= 2c-8
2c-8=0
c=4
Hence the value of c = 4 in [3,5] for Rolles theorem.
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pls help me on algebra here is screenshot
Answer:
The answer to the question provided is option 2.
Given: tangent to Circle O.
If m = 140°, then A =
The measure of the angle A is 70 degrees if the DR is the tangent to the circle option (A) 70 degrees is correct.
What is a circle?It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)
The question is incomplete.
The complete question is in the picture, please refer to the attached picture.
It is given that:
Join the points B and O and then join points D and O
Angle A = (1/2)Angle BOD
Angle B = 140 degrees
Angle A = (1/2)140 degrees
Angle A = 70 degrees
Thus, the measure of the angle A is 70 degrees if the DR is the tangent to the circle option (A) 70 degrees is correct.
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ITS THE FOURTH QUESTION
The surface areas of the figures are 336, 82 and 836
How to calculate the surface areasFrom the question, we have the following parameters that can be used in our computation:
The figures
For the triangular prism, we have
Surface area = 2 * 1/2 * 6 * 8 + 12 * 10 + 8 * 12 + 6 * 12
Surface area = 336
For the rectangular prism, we have
Surface area = 2 * (7 * 3 + 3 * 2 + 2 * 7)
Surface area = 82
For the cylinder, we have
Surface area = 2π * 7 * (7 + 12)
Surface area = 836
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The surface area of the prisms are
1. 336 cm²
2. 82 m²
3. 836 cm²
What is surface area?The area occupied by a three-dimensional object by its outer surface is called the surface area.
A prism is a solid shape that is bound on all its sides by plane faces.
The surface area of prism is expressed as;
SA = 2B +pH
where B is the base area , p is the perimeter and h is the height.
1. SA = 2B +ph
B = 1/2 × 6 × 8
= 24 m²
p = 6+8+10 = 24m
h = 12m
SA = 2 × 24 + 24 × 12
= 48 + 288
= 336 cm²
2. SA = 2( 3× 2) + 3× 7)+ 2 × 7)
= 2( 6+21+14)
= 2( 41)
= 82 m²
3. SA = 2πr( r +h)
= 2 × 3.14 × 7( 7 + 12)
= 44( 19)
= 836 cm²
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Given that z is a standard normal random variable, what is the value of z if the area to the left of z is 0.9382:
a. 1.8
b. 1.54
c. 2.1
d. 1.77
Answer: 1.54
Step-by-step explanation:
Given that :
Z = normal random variable
Area to the left of z = 0.9382
For a random normal distribution ;
P(Z < x) = 0.9382
Using the Z table (standard normal distribution table) ;
Locating the probability value (0.9382) on the table and picking the intersecting z value both horizontally and vertically :
Horizontal value = 1.5
Vertical value = 0.04
Horizontal + vertical = (1.5 + 0.04) = 1.54
what is the volume of the cylinder below height 15 radius 11
Answer:
πr^2 h
π(11)^2 (15)
= 1815π or = 5701
g The altitude of a triangle is increasing at a rate 2 inch/hour while the area of the triangle is decreasing at a rate of 0.5 square inch per hour. At what rate is the base of the triangle is changing when the altitude is 6 inch and the area is 24 square inch
Answer:
The base of the triangle is decreasing at a rate of 1.4167 inch/hour.
Step-by-step explanation:
Area of a triangle:
The area of a triangle of base b and height h is given by:
\(A = bh\)
In this question:
We have to derivate the equation of the area implicitly in function of time. So
\(\frac{dA}{dt} = b\frac{dh}{dt} + h\frac{db}{dt}\)
The altitude of a triangle is increasing at a rate 2 inch/hour while the area of the triangle is decreasing at a rate of 0.5 square inch per hour.
This means that:
\(\frac{dh}{dt} = 2, \frac{dA}{dt} = -0.5\)
At what rate is the base of the triangle is changing when the altitude is 6 inch and the area is 24 square inch?
This is \(\frac{db}{dt}\) when \(h = 6\)
Area is 24, so the base is:
\(A = bh\)
\(24 = 6b\)
\(b = \frac{24}{6} = 4\)
Then
\(\frac{dA}{dt} = b\frac{dh}{dt} + h\frac{db}{dt}\)
\(-0.5 = 4(2) + 6\frac{db}{dt}\)
\(6\frac{db}{dt} = -8.5\)
\(\frac{db}{dt} = -\frac{8.5}{6}\)
\(\frac{db}{dt} = -1.4167\)
The base of the triangle is decreasing at a rate of 1.4167 inch/hour.