A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center, as shown in the figure below. (Figure 1)The linear speed of a passenger on the rim is constant and equal to 6.00 m/s .

ANSWER

True

EXPLANATION

A concave mirror, or a converging mirror, is one in which the rays of light incident on it converge at a point after they are reflected from the reflecting surface of the mirror.

A concave mirror can produce several types of images depending on the distance of the object from the mirror. They can be upright or inverted, they can be behind the mirror or in front of the mirror and they can be real or virtual.

Hence, it is true.

Answer:

Unequal Wavelengths

Explanation:

Got it right on the exam

Unequal wavelengths limit interference between waves because the waves will have different frequencies and will not be able to form a stable interference pattern. When waves of different wavelengths interact, they will interfere constructively and destructively at different points, creating an unpredictable pattern.

Answer:

Unequal wavelengths

Explanation:

Got it correct on the quiz.

Answer:

b

Explanation:

Answer: C.

Correct me if I'm wrong.

(a) The magnitude of the spring's displacement when the acceleration of the box is zero can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(b) The magnitude of the spring's displacement when the spring is fully compressed can be determined by equating the initial gravitational potential energy to the elastic potential energy stored in the spring.

(a) To determine the magnitude of the spring's displacement when the acceleration of the box is zero, we need to apply the principles of conservation of energy.

Initially, the box has gravitational potential energy given by mgh, where m is the mass of the box, g is the acceleration due to gravity, and h is the height from which the box was dropped. The initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring and the kinetic energy of the box just before it makes contact with the spring.

The gravitational potential energy is given by:

mgh = (1.9 kg)\((9.8 m/s^2)h\)

The elastic potential energy stored in the spring is given by:

1/2 kx^2\(kx^2\), where k is the spring constant and x is the displacement of the spring.

The kinetic energy of the box just before it makes contact with the spring is given by:

\(1/2 mv^2,\) where m is the mass of the box and v is the speed of the box.

Since the acceleration of the box is zero at the instant when the spring's displacement is maximum, the kinetic energy is zero. Therefore, we can equate the initial gravitational potential energy to the elastic potential energy to find the spring's displacement.

mgh = 1/2 \(kx^2\)

Substituting the given values, we have:

\((1.9 kg)(9.8 m/s^2)h = 1/2 (300 N/m)x^2\)

Solving for x, the magnitude of the spring's displacement, we can determine its value at the instant when the acceleration is zero.

(b) To find the magnitude of the spring's displacement when the spring is fully compressed, we need to consider the conservation of mechanical energy once again.

At maximum compression, all the initial gravitational potential energy is converted into the elastic potential energy stored in the compressed spring.

mgh = 1/2 \(kx^2\)

Substituting the given values and solving for x, the magnitude of the spring's displacement, we can determine its value when the spring is fully compressed.

It's important to note that in both cases, the negative sign of the displacement indicates that the spring is being compressed. The magnitude of the displacement will be a positive value.

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Answer:

SI = 2.31

d = 0.161 m

Explanation:

First, convert km/h to m/s.

12.1 km/h × (1000 m/km) × (1 h / 3600 s) = 3.36 m/s

Find the time.

v = at + v₀

3.36 = (35.0)t + 0

t = 0.0960

Find the value of a.

a = a / g

a = 35.0 / 9.8

a = 3.57

Solve for SI.

SI = (3.57)^(⁵/₂) (0.0960)

SI = 2.31

Solve for d.

v² = v₀² + 2aΔx

(3.36)² = 0² + 2 (35.0) d

d = 0.161

The corresponding downward force on the top of a horizontal square is 375 lb.in

The pressure is the amount of force applied per unit area. It is represented as

Pressure p = Force/Area

If the atmospheric pressure is 15 lb/in and  area 5 inches on each side is

A = 5² = 25  in²

The force applied is

15 lb/in = F /25 in²

F = 375 lb.in

Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in

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Answer:

I would say the answer is All the above.

Explanation:

If this wasn't what you were looking for please don't hesitate to comment again! Have a nice day/night! :)

Answer:

all the above

Explanation:

Answer:

21.8°

Explanation:

Let's call θ the angle between BC and the horizontal.

Draw a free body diagram for each block.

There are 4 forces acting on block D:

Weight force P pulling down,

Normal force N₁ pushing perpendicular to AB,

Friction force N₁μ pushing parallel up AB,

and tension force T pushing parallel up AB.

There are 4 forces acting on block E:

Weight force P pulling down,

Normal force N₂ pushing perpendicular to BC,

Friction force N₂μ pushing parallel to BC,

and tension force T pulling parallel to BC.

Sum of forces on D in the perpendicular direction:

∑F = ma

N₁ − P sin θ = 0

N₁ = P sin θ

Sum of forces on D in the parallel direction:

∑F = ma

T + N₁μ − P cos θ = 0

T = P cos θ − N₁μ

T = P cos θ − P sin θ μ

T = P (cos θ − sin θ μ)

Sum of forces on E in the perpendicular direction:

∑F = ma

N₂ − P cos θ = 0

N₂ = P cos θ

Sum of forces on E in the parallel direction:

∑F = ma

N₂μ + P sin θ − T = 0

T = N₂μ + P sin θ

T = P cos θ μ + P sin θ

T = P (cos θ μ + sin θ)

Set equal:

P (cos θ − sin θ μ) = P (cos θ μ + sin θ)

cos θ − sin θ μ = cos θ μ + sin θ

1 − tan θ μ = μ + tan θ

1 − μ = tan θ μ + tan θ

1 − μ = tan θ (μ + 1)

tan θ = (1 − μ) / (1 + μ)

Plug in values:

tan θ = (1 − 0.4) / (1 + 0.4)

θ = 23.2°

∠BCA = 45°, so the angle of AC relative to the horizontal is 45° − 23.2° = 21.8°.

Answer:

D)parallel circuit

Explanation:

the components are placed parallel from eachother

Answer:

electrical transfers into mechanical energy Explanation:

Answer:

5.67 m/s

Explanation:

The speed of a wave can be calculated as the distance traveled by the wave divided by the time taken:

Speed = Distance/Time

In this case, the distance traveled by the wave is the length of the pool, which is 17 m. The time taken by the wave to travel this distance is 3 seconds.

So, the speed of the wave can be calculated as:

Speed = 17 m/3 s

Speed = 5.67 m/s

Therefore, the speed of the water wave in the 17 m long pool is 5.67 m/s.

Since S can be assumed to represent G itself, every finite group is finitely produced. Countable groups need not be finitely generated, but every infinite finitely generated group must be countable.

Any machine that transforms mechanical energy into electricity for transmission and distribution via power lines to residential, commercial, and industrial consumers is known as an electric generator, sometimes known as a dynamo. In addition, generators provide the additional electrical power needed for boats, trains, cars, and other types of transportation. A hydroelectric facility is one where turbine generators are propelled by falling water. Hydraulic motors that produce electricity power electrical generators.

In the event of a power outage, generators are practical equipment that supply electricity, keeping daily tasks or company operations operating smoothly. For usage in a number of applications, generators are available in a variety of electrical and physical designs.

It operates under the principles of Faraday's electromagnetic induction law. According to the faradays law, an electromagnetic field (EMF) is created anytime a conductor is subjected to a changing magnetic field.

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Answer:206.3

Explanation:

Explanation:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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In a case whereby two springs are attached to two hooks and Spring A has a greater force constant than spring B. Equal weights are suspended from both then Spring B will have more extension than spring A.

Force constant or spring constant  serves as the measure of the stiffness of a spring which can be explained as the force per unit deformation of the spring.

In the case above, we can see that since Equal weights are suspended from both, then there will be more extension at the side of  Spring B  since A has a greater force constant.

Therefore, option B is correct.

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Answer:

Transformers do not allow DC input to flow through. This is known as DC isolation. This is because a change in current cannot be generated by DC

Explanation:

Hope this helps

Answer:

a change in current cannot be generated by DC;

When the teacher asked the student to make words out of the jumbled word gzeysktqix, the student was being tested on his ability to unscramble words. Unscrambling words is the process of taking a word or series of letters that are out of order and rearranging them to form a word that makes sense.

When trying to unscramble a word, it is important to look for any patterns that can help identify smaller words within the jumbled letters. This can help make the process easier and quicker. For example, in the jumbled word gzeysktqix, one might notice that the letters "sktqix" appear together.

This could indicate that these letters could potentially form a word. By looking at the remaining letters, one could notice that the letters "g", "z", "e", and "y" could also form smaller words. After some rearranging, the letters can be unscrambled to form the words "sky", "zig", "sex", and "yet". These are just a few examples, as there are likely many other words that can be formed from this jumbled word.

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Answer:

Look down below

Explanation:

300Hz is the 5th harmonic in a 60 Hz system, or the 6th harmonic in a 50 Hz system.

Answer:

D. Push Factor

Explanation:

Weather hazards and natural disasters are horrendously negative things that people actively seek to avoid; they make people want to leave or depart from an area in order to escape them. As such, they are considered push factors.

(Weather hazards and natural disasters are not pull factors because when discussing push vs pull we are specifically describing the mentioned factor. This aspect is not considered both because the migration factor mentioned in this question actively makes people want to move to any area that avoids their issue. Remember that pull factors make people want to move to a specific place for a unique advantage, while push factors make people want to move to any general place for a common advantage.)

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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Answer:

35, I got you bro, i got you

The pressure exerted by a rectangular block on the ground is 8 Pascal (Pa) when its weight is 320 N and its dimensions are 4 meters by 10 meters. The greatest pressure occurs when the block is vertically placed at 20 Pa, while the least pressure occurs when it is horizontally placed at 8 Pa.

To calculate the pressure exerted by the rectangular block on the ground, we need to consider the formula for pressure:

Pressure = Force / Area

Given that the weight of the block is 320 N and the dimensions of the block are 4 meters by 10 meters, we can calculate the area of the block in contact with the ground. In this case, it is the length multiplied by the width of the block.

Area = length * width

Area = 4 meters * 10 meters

Area = 40 square meters

Now, we can calculate the pressure exerted by the block on the ground:

Pressure = 320 N / 40 square meters

Pressure = 8 N/m^2 (Pascal)

Therefore, the pressure exerted by the rectangular block on the ground is 8 Pascal (Pa).

To determine the greatest pressure and the least pressure that can be exerted on the ground, we need to consider the orientation of the block.

The greatest pressure occurs when the block is placed vertically on one of its smallest faces. In this case, the entire weight of the block (320 N) is concentrated on a smaller area.

The area in contact with the ground is given by the length multiplied by the width of the smallest face.

Area = 4 meters * 4 meters = 16 square meters

Greatest Pressure = 320 N / 16 square meters = 20 \(N/m^2\)(Pascal)

The least pressure occurs when the block is placed horizontally on one of its largest faces. In this case, the weight of the block is distributed over a larger area.

The area in contact with the ground is given by the length multiplied by the width of the largest face.

Area = 4 meters * 10 meters = 40 square meters

Least Pressure = 320 N / 40 square meters = 8 \(N/m^2\)(Pascal)

Therefore, the greatest pressure that can be exerted on the ground is 20 Pascal (Pa), and the least pressure is 8 Pascal (Pa).

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Explanation:

Potential Energy = m g h

400 J   =  8 kg  * 9.81 m/s^2  * h

400 / (8 *9.81) = h = 5.1 m

Answer:

α = 36.21 °

β = 143.79°

Explanation:

To do this, we need to know the expression to calculate the angle.

In this case:

α₁ = tan⁻¹ (Fy₁/Fx₁)   (1)

Now, let's analize the given data.

We have a charge q₁ at the origin of the cartesian coordinate system, so, it's at the 0. The charge q₂ is 20 cm above q₁, meaning is on the y-axis. Finally q₃ it's 20 cm to the right, meaning it's on the x-axis.

Knowing this,we can calculate the force that q₂ and q₃ are exerting over q₁. As these forces are in the x and y-axis respectively, we also are calculating the value of the forces in the x and y axis, that are needed to calculate the direction.

The expression to calculate the force would be Coulomb's law so:

F = K q₁q₂ / r²    (2)

The value of K is 9x10⁹ N m² / C². Let's calculate the forces:

F₁₂ = Fy = 9x10⁹ * (7.1x10⁻⁴) * (6.5x10⁻⁴) / (0.020)²

Fy = 1.04x10⁷ N

F₁₃ = Fx = 9x10⁹ * (7.1x10⁻⁴) * (8.9x10⁻⁴) / (0.020)²

Fx = 1.42x10⁷ N

Now that we have both forces, we can calculate the magnitude of the force:

F = √(Fx)² + (Fy)²

F = √(1.04x10⁷)² + (1.42x10⁷)²

F = 1.76x10⁷ N

Finally, the direction would be applying (1):

α = tan⁻¹ (1.04x10⁷/1.42x10⁷)

α = 36.21 °

And counter clockwise it would be:

β = 180 - 36.21 = 143.79°

Hope this helps

1) describe the life cycle of a star before it collapses into a black hole.

1) describe the life cycle of a star before it collapses into a black hole.ans: A star's life cycle is determined by its mass. The larger its mass, the shorter its life cycle. A star's mass is determined by the amount of matter that is available in its nebula, the giant cloud of gas and dust from which it was born. Over time, the hydrogen gas in the nebula is pulled together by gravity and it begins to spin. As the gas spins faster, it heats up and becomes as a protostar. Eventually the temperature reaches 15,000,000 degrees and nuclear fusion occurs in the cloud's core. The cloud begins to glow brightly, contracts a little, and becomes stable. It is now a main sequence star and will remain in this stage, shining for millions to billions of years to come. This is the stage our Sun is at right now.

2) describe the life cycle of a star before it becomes a dwarf.

ans: The life cycle of a low mass star (left oval) and a high mass star (right oval). ... As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf.

3) what is the likely outcome of our sun?

ans: All stars die, and eventually — in about 5 billion years — our sun will, too. Once its supply of hydrogen is exhausted, the final, dramatic stages of its life will unfold, as our host star expands to become a red giant and then tears its body to pieces to condense into a white dwarf.