A ferryboat is traveling in a direction 35.0° north of east with a speed of 3.18 m/s relative to the water. A passenger is walking with a velocity of 1.19 m/s due east relative to the boat. What is (

Answers

Answer 1

(a) The magnitude of the velocity of the passenger with respect to the water is approximately 4.19 m/s.

(b) The direction of the velocity of the passenger with respect to the water is approximately 26.7° east of north.

To find the magnitude and direction of the velocity of the passenger with respect to the water, we can use vector addition.

Let's break down the velocities into their horizontal (x) and vertical (y) components.

For the ferryboat:

Speed = 3.18 m/s

Direction = 35.0° north of east

The x-component of the ferryboat's velocity is given by:

V_ferryboat_x = Speed * cos(angle)

V_ferryboat_x = 3.18 m/s * cos(35.0°)

V_ferryboat_x ≈ 2.60 m/s

The y-component of the ferryboat's velocity is given by:

V_ferryboat_y = Speed * sin(angle)

V_ferryboat_y = 3.18 m/s * sin(35.0°)

V_ferryboat_y ≈ 1.81 m/s

For the passenger:

Velocity = 1.19 m/s

Direction = due east

Since the passenger is moving due east, there is no vertical (y) component to consider. The x-component of the passenger's velocity is the same as their velocity, which is 1.19 m/s.

Now, let's add the x-components and y-components of the velocities to find the overall velocity of the passenger with respect to the water.

The x-component of the overall velocity is given by:

V_overall_x = V_ferryboat_x + V_passenger_x

V_overall_x = 2.60 m/s + 1.19 m/s

V_overall_x ≈ 3.79 m/s

The y-component of the overall velocity is given by:

V_overall_y = V_ferryboat_y + V_passenger_y

V_overall_y = 1.81 m/s + 0 m/s (since the passenger is not moving vertically)

V_overall_y = 1.81 m/s

The magnitude of the overall velocity is given by the Pythagorean theorem:

Magnitude = √(V_overall_x^2 + V_overall_y^2)

Magnitude = √((3.79 m/s)^2 + (1.81 m/s)^2)

Magnitude ≈ 4.19 m/s

To find the direction, we can use the inverse tangent function (tan^(-1)) of the ratio of the y-component to the x-component of the overall velocity:

Direction = tan^(-1)(V_overall_y / V_overall_x)

Direction = tan^(-1)(1.81 m/s / 3.79 m/s)

Direction ≈ 26.7°

(a) The magnitude of the velocity of the passenger with respect to the water is approximately 4.19 m/s.

(b) The direction of the velocity of the passenger with respect to the water is approximately 26.7° east of north.

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Question

A ferryboat is traveling in a direction 35.0° north of east with a speed of 3.18 m/s relative to the water. A passenger is walking with a velocity of 1.19 m/s due east relative to the boat. What is (a) the magnitude and (b) the direction of the velocity of the passenger with respect to the water?


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All the following statements about Venus are true. Which one offers evidence of a global repaving about a billion years ago? Venus has relatively few impact craters and these craters are distributed fairly evenly over the entire planet.

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Venus has relatively few impact craters and these craters are distributed fairly evenly over the entire planet.

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The solar system is an arrangement of the sun and the planets. The sun is at the focus of the solar system and it is surrounded by the planets moving radially outwards from the focus. This is the heliocentric model of the solar system.

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an empty parallel plate capacitor is connected between the terminals of a 6.33-v battery and charges up. the capacitor is then disconnected from the battery, and the spacing between the capacitor plates is doubled. as a result of this change, what is the new voltage between the plates of the capacitor?

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The new voltage between the plates of the capacitor in the terminals of a 6.33-V battery is 6.33-V.


The voltage between the plates of the capacitor will remain the same after the spacing between the plates is doubled. This is because the voltage of a capacitor is determined solely by the amount of charge stored in the capacitor. Increasing the spacing between the plates does not change the charge stored on the capacitor, so the voltage between the plates stays the same.

In this case, the new voltage between the plates of the capacitor would remain at 6.33-V.

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The diagram below shows three kettles with their powers and the time they take to boil 500cm3 of water. How much energy is transferred (in kilojoules, kJ) by the 3kW kettle while it boils the water?

The diagram below shows three kettles with their powers and the time they take to boil 500cm3 of water.

Answers

The kettle with 3kW power taking 3 minutes to boil 500 cm³ of water perform a work of 540 KJ which is equivalent to the energy transferred by the kettle.

What is power ?

Power is the rate of work done by an object. Thus, power is the rate of work done. Work done on a body is equivalent to the energy of the body. Thus power is rate of energy too.

If a force applied on a body results in displacement, it is said to be work done on the body. The ratio of work done to the time is the power of the object.

P = w/t

then w = P t

Given that P = 3 kW for 3 minutes

3 minutes = 180 seconds

Then w = E = 3 × 180 = 540 KJ

Therefore, the energy transferred by the 3kW kettle in 3 minutes is 540 KJ.

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If you put something like a piece of cardboard between a magnet and an iron nail, the magnet still holds the nail in place, even though the magnet is not touching the nail.
Explain how that happens.

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Answer:

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Explanation:

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a 0.60-kg puck revolves at 2.4 m/s at the end of a 0.90-m string on a frictionless air table. if the string is pulled in until its length is 0.60 m, what is the new speed of the puck?

Answers

Answer:

3.6 m/s

Explanation:

The mass of the puck, m = 0.60kg

The speed of the puck, v1 - 2.4 m/s

The initial length of the string, r1 = 0.90 m

Formula Used:

The angular momentum of mass m moving in a circle or radius r with a speed v is given by,

L=mvr

And, when no external acts on a system, then the angular momentum of the system remains conserved.

Proof:

Since no external torque is exerted on the puck, hence the angular momentum of the puck string remains conserved.

Then, using the given values,

L1 = L2

mv1r1 = mv2r2

v2 = v1r1/r1

Using the given values in above,

     v2 = (2.4)(0.90)/0.60

    = 3.6 m/s

Conclusion:

Hence, when the string is shortened to 0.60m, the speed of the considered puck will be 3.6 m/s.

An object is moving at a velocity of 11.5 m/s to the left. How far does it move in
312.24 seconds?

Answers

Answer:

\(\huge\boxed{\sf d = 3590.76\ m}\)

Explanation:

Given data:

Velocity = v = 11.5 m/s

Time = t = 312.24 s

Required:

Displacement = d = ?

Formula:

d = v × t

Solution:

d = 11.5 × 312.24

d = 3590.76 m

\(\rule[225]{225}{2}\)

the nucleus of our Galaxy (which may be elongated and not spherical) generates

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The elongated nucleus of our galaxy is responsible for generating a wide range of phenomena, including the influence of a supermassive black hole, star formation activity, and the production of synchrotron radiation. These processes are vital to understanding the overall structure, dynamics, and evolution of the Milky Way.

The nucleus of our galaxy, also known as the galactic center, is a region that plays a crucial role in generating various phenomena. Located approximately 26,000 light-years from Earth, it is thought to have an elongated shape rather than being perfectly spherical.

At the heart of the galactic nucleus lies a supermassive black hole called Sagittarius A* (Sgr A*). This black hole is responsible for generating intense gravitational forces, which influence the motion and behavior of surrounding stars, gas, and dust. Additionally, Sgr A* is a major source of X-ray and radio emissions, contributing to the overall energy output of the galaxy's core.

The galactic center also exhibits a high degree of star formation activity. Massive, young stars in this region emit intense ultraviolet radiation, which in turn ionizes the surrounding gas clouds. This process leads to the creation of H II regions, which are areas of glowing ionized gas. These regions not only serve as stellar nurseries but also contribute to the overall appearance and structure of the galactic nucleus.

Furthermore, the interaction of energetic particles, magnetic fields, and turbulent gas flows in the galactic nucleus generates synchrotron radiation, which is emitted at various wavelengths, including radio, infrared, and X-ray. This radiation is an important tool for astronomers to study the complex processes occurring within the core of our galaxy.

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A dog in an open field runs 12.0 m east and then 28.0 m in a direction 50.0 ∘west of north. In what direction and how far must the dog then run to end up 10.0 m south of her original starting point?

Answers

The direction and how far the dog must run to end up 10.0 m south of her original starting point are 30.99 m and 117° east of south respectively.

The figure below represents the given data of the dog that runs 12.0 m east and then 28.0 m in a direction 50.0 ∘ west of north.

From the given figure, the following can be calculated:

1. Distance between the starting point and the end point of the dog= 34.76 m

2. The horizontal distance travelled by the dog= 12 m

3. The vertical distance travelled by the dog = 28sin(50°) = 21.47 m

4. The distance the dog needs to travel to end up 10.0 m south of her original starting point= 10 m. So, the dog needs to travel in such a way that the distance travelled in the vertical direction is 10 m.

5. Now, we can use the Pythagoras theorem to calculate the horizontal distance travelled by the dog. We have,

Distance traveled in the vertical direction= 21.47 - 10 = 11.47 m.

Now, applying Pythagoras theorem to calculate the horizontal distance travelled, we have

$(horizontal distance)^2$+$(vertical distance)^2$= $(distance)^2$(horizontal distance)^2+($11.47 m$)^2= $(34.76m)^2$(horizontal distance)²= $(34.76m)^2$ - $(11.47m)^2$(horizontal distance)²= $1089.5375m^2$ - $131.0209m^2$(horizontal distance)²= $958.5166m^2$(horizontal distance)= $\sqrt{958.5166}$= $30.99m$

So, the distance travelled in the horizontal direction is 30.99 m.

6. Hence, the direction and how far the dog must run to end up 10.0 m south of her original starting point are 30.99 m and 117° east of south respectively.

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A dog in an open field runs 12.0 m east and then 28.0 m in a direction 50.0 west of north. In what direction

two long ideal solenoids (with radii 20 mm and 30 mm respectively) have the same number of tunrs of wire per unit length. the smaller solenoid is mounted inside the larger, along a common axis. it is observed that there is zero magnetic field within the inner solenoid. the current in the inner solenoid must be

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The fact that there is zero magnetic field within the inner solenoid implies that the magnetic field generated by the larger solenoid cancels out the magnetic field generated by the smaller solenoid at its center. This means that the current flowing through the inner solenoid must be equal and opposite in direction to the current flowing through the outer solenoid.

We know that the magnetic field inside a solenoid is directly proportional to the current flowing through it, and inversely proportional to its radius. Since the two solenoids have the same number of turns of wire per unit length, their magnetic fields at a given distance from their centers will be proportional to their radii. Therefore, we can conclude that the current flowing through the inner solenoid must be less than the current flowing through the outer solenoid, since its radius is smaller.

To determine the exact ratio of the currents, we can use the fact that the magnetic field at the center of a solenoid is proportional to the product of its current and the number of turns of wire per unit length. Equating the magnetic fields of the two solenoids at the center of the inner solenoid, we can solve for the ratio of the currents. This gives us the exact value of the current in the inner solenoid that is required to cancel out the magnetic field of the outer solenoid at its center.

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A coin rests on a turntable a distance r from the axis of rotation. The turntable rotates with a constant speed of v. What is the minimum coefficient of static friction between the turntable and the coin?.

Answers

The minimum coefficient of static friction between the turntable and the coin if the coin is not to slip is  r (2πf)² / g  .

How to calculate minimum coefficient of static friction between the turntable and the coin if the coin is not to slip ?

Given ,

N=normal force acting on the coin

Normal force in the upward direction balances the weight of the coin, hence

N=mg

f=frequency of rotation Angular velocity of turntable is hence given as

w=2πf

r = distance from the axis of rotation

µ = minimum coefficient of static friction

static frictional force is given as

f= µN

f= µmg

The  static frictional force provides the necessary centripetal force , hence

Centripetal force = Static frictional force

mrw² =  µmg

rw² = µg

µ = rw²/g

µ = r (2πf)² / g

Therefore the minimum coefficient of static friction between the turntable and the coin if the coin is not to slip is  r (2πf)² / g

The complete question is : A coin of mass m rests on a turntable a distance r from the axis of rotation. The turntable rotates with a frequency of f. What is the minimum coefficient of static friction between the turntable and the coin if the coin is not to slip?

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Which sentence best explains the difference between potential energy and
kinetic energy?
A. Potential energy is related to an object's position, and kinetic
energy is related to its motion.
B. Potential energy is related to an object's motion, and kinetic
energy is related to its position.
C. Potential energy is related to an object's position, and kinetic
energy is related to the arrangement of its particles.
O D. Potential energy is related to an object's shape, and kinetic energy
is related to its position.

Answers

Answer:

C. Potential energy is related to an object's position, and kinetic

Explanation:

The energy contained in the small motions of the object's molecules can be broken up into a combination of microscopic kinetic energy and potential energy.

Answer:

c. potential energy is related to an object's position, and kinetic energy is related to its motion

Explanation:

In the long run, people who practice self-regulation through physical exercise and time-managed programs experience an increase in

Answers

Answer:

Self control

Explanation:

Self control involves individuals having a strong discipline towards certain conditions. The conditions could be cravings for something or other forms of activities.

Self control is usually developed by people who practice self-regulation through physical exercise and time-managed programs experience as they have been known to bring about an increase in it.

An object increases vert its velocity from 22M/S 236M/S and five seconds. What is the acceleration of the object

Answers

Answer:

\(\boxed {\boxed {\sf a=42.8 \ m/s^2}}\)

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

\(a=\frac{v-u}{t}\) (v is the final velocity, u is the initial velocity, t is the time).

The velocity increased from 22 m/s to 236 m/s in 5 seconds. Therefore:

\(v=236 \ m/s\\u=22 \ m/s\\t= 5 \ s\)

Substitute the values into the formula.

\(a=\frac{236 \ m/s - 22 \ m/s}{5 \ s}\)

Subtract in the numerator.

236 m/s-22 m/s=214 m/s

\(a=\frac{214 \ m/s}{5 \ s}\)

Divide.

\(a=42.8 \ m/s^2\)

The acceleration of the object is 42.8 meters per square second.

A steam engine only converts 20 percent of its input energy into useful
work. How many kilojoules of work does this engine do if its input energy
is 300 kilojoules?

Answers

The steam engine does 60 kilojoules of useful work out of the 300 kilojoules of energy supplied, since its efficiency is only 20%.

What is the amount of useful work done by a steam engine with 20% efficiency, if the input energy is 300 kilojoules?

The efficiency of a steam engine is a measure of how much of the input energy is converted into useful work. In this case, we know that the efficiency of the steam engine is 20%, which means that only 20% of the input energy is converted into useful work.

To find out how much work the steam engine does, we use the formula:

Useful work = Input energy x Efficiency

In this formula, the input energy is the amount of energy that is supplied to the steam engine, and the efficiency is the percentage of that energy that is converted into useful work.

So, in this case, we know that the input energy is 300 kilojoules, and the efficiency is 20%. we get:

Useful work = 300 kilojoules x 0.20

Useful work = 60 kilojoules

Therefore, the steam engine does 60 kilojoules of useful work. This means that out of the 300 kilojoules of energy that were supplied to the steam engine, only 60 kilojoules were converted into useful work, and the remaining 240 kilojoules were lost as heat or other forms of energy.

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Convert using dimensional analysis
I) 18/5 kmph into m/s (velocity)
II) 5/18 m/s into kmph(velocity)

Answers

I) The velocity 18/5 kmph in m/s is 4 m/s.

II) The velocity 5/18 kmph in m/s is 20 kmph.

Dimensional Analysis is a mathematical process used to convert one unit to another. This is done by multiplying the original value with a ratio of equivalent units that is equal to 1. When using dimensional analysis, it is important to keep track of units and cancel out any units that are not needed.

The following is the solution to the conversion of kmph to m/s and vice versa using dimensional analysis.

I) 18/5 kmph into m/s (velocity)When converting kmph to m/s, we need to multiply by 1000/3600 which is equal to 5/18 since there are 1000 meters in one kilometer and 3600 seconds in one hour. Therefore,18/5 kmph x 1000 m/1 km x 1 hour/3600 s = 4 m/s (velocity). Thus, 18/5 kmph is equal to 4 m/s.

II) 5/18 m/s into kmph (velocity)When converting m/s to kmph, we need to multiply by 3600/1000 which is equal to 18/5 since there are 3600 seconds in one hour and 1000 meters in one kilometer. Therefore,5/18 m/s x 3600 s/1 hour x 1 km/1000 m = 20 kmph (velocity). Thus, 5/18 m/s is equal to 20 kmph.

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​Two college students push a broken down, 711 kg car to a mechanic. If the first student pushes with a force of 638 N and the second student pushes with a force of 573 N, what is the magnitude of acceleration of the car?

Answers

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) .

Acceleration is the rate of change of velocity with respect to time.

Also it is the capacity of the vehicle to gain speed.

Mass of the car = 711 kg

Force exerted by the Student 1 = \(F_1\) =  638 N

Force exerted by the Student 2 = \(F_2\) =  573 N

Total force exerted on the car = F  = \(F_1\) + \(F_2\)

F = 638 + 573

F = 1,211 N

As we know that, Force is the product of mass and acceleration i.e.

F = m * a

\(a = \frac{F}{m}\)

a = \(\frac{1211}{711}\)

a = 1.70 \(m/s^{2}\)

The magnitude of acceleration of the car is  1.70 \(m/s^{2}\) to push it to a car mechanic.

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A train consists of a locomotive (50t) and 20 cars ( 15t each). He drives on a track with a gradient of 2%. The friction coefficient for the driving resistance is 1%. The gravitational acceleration g=9.81 m/sec2 What steady-state speed can be achieved with a maximum drive power of the locomotive of 1.0 mW?

Answers

The steady-state speed that can be achieved with a maximum drive power of 1.0 MW is approximately 9.73 m/s.

To determine the steady-state speed that can be achieved with a maximum drive power of 1.0 MW (megawatt), we need to consider the driving resistance and the available power.

Given information:

Mass of the locomotive (m1): 50 tonnes = 50,000 kg

Mass of each car (m2): 15 tonnes = 15,000 kg

Number of cars (n): 20

Gradient of the track (θ): 2% = 0.02

Friction coefficient (μ): 1%

Gravitational acceleration (g): 9.81 m/s^2

Maximum drive power (Pmax): 1.0 MW = 1,000,000 W

First, let's calculate the total mass of the train:

Total mass (M) = Mass of locomotive + Mass of cars

M = m1 + (m2 × n)

M = 50,000 kg + (15,000 kg × 20)

M = 50,000 kg + 300,000 kg

M = 350,000 kg

Next, we can calculate the driving resistance:

Driving resistance (R) = Gravitational resistance + Rolling resistance

Gravitational resistance (Rg) = M × g × sin(θ)

Rolling resistance (Rr) = μ × M × g × cos(θ)

R = Rg + Rr

Substituting the given values:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

R = Rg + Rr

Calculate Rg:

Rg = 350,000 kg × 9.81 m/s^2 × sin(0.02)

Rg ≈ 350,000 kg × 9.81 m/s^2 × 0.02

Rg ≈ 68,430 N

Calculate Rr:

Rr = 0.01 × 350,000 kg × 9.81 m/s^2 × cos(0.02)

Rr ≈ 0.01 × 350,000 kg × 9.81 m/s^2 × 0.9998

Rr ≈ 34,267 N

Calculate R:

R = Rg + Rr

R ≈ 68,430 N + 34,267 N

R ≈ 102,697 N

Now, we can calculate the maximum velocity (vmax) using the maximum power available:

Power (P) = Force (F) × Velocity (v)

P = R × v

vmax = Pmax / R

Substituting the given values:

vmax = 1,000,000 W / 102,697 N

vmax ≈ 9.73 m/s

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an object sits at rest with no unbalanced forces acting upon it. what do we expect this object to do?

Answers

Unless acted on by an imbalanced force, an object is at rest can tend to stay as rest, and a motion should tend to maintain its current speed and direction.

Describe a force.

A pull or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items touch, a force is exerted on each of objects.

Which types of force are there?

Forces acting and act at a range forces are the two different types of forces. Your daily use of force is evident. Essentially, thrust and pull are forces. You exert force on an object if you push against it or pull against it.

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Which has more energy, light with a wavelength of 580 nm or light with a wavelength of 660 nm?
a. 580 nm
b. 660 nm

Answers

Light with a 660 nm wavelength has more energy than light with a 580 nm wavelength.

Which type of light—light with a wavelength of 660 nm or one of 580 nm—has more energy?Light with a 660 nm wavelength has more energy than light with a 580 nm wavelength. This is due to the fact that the relationship between light energy and wavelength is inverse.In other words, a light's energy content increases with its shorter wavelength. The energy of the light diminishes with an increase in wavelength. As a result, light with a 660 nm wavelength has a shorter wavelength and more energy than light with a 580 nm wavelength.This is as a result of the shorter wavelength of the 660 nm light's greater ability than the longer wavelength of the 580 nm light to permeate into the substance.Because the 660 nm light has a greater frequency and more energy than the 580 nm light, it is able to transfer more energy to the substance. This explains why light with a 660 nm wavelength has more energy than light with a 580 nm wavelength.

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a charge q is transferred from an initially uncharged plastic ball to an identical ball 28 cm away. the force of attraction is then 62 mn .

Answers

To determine the value of the charge q transferred between the two plastic balls, we can use Coulomb's law, which relates the force between two charged objects to the distance between them and the magnitude of the charges.

Coulomb's law states that the force of attraction or repulsion between two charges is given by the formula:

F = k * (|q1| * |q2|) / r^2,

where F is the force between the charges, k is the electrostatic constant (approximately 8.99 x 10^9 Nm^2/C^2), |q1| and |q2| are the magnitudes of the charges, and r is the distance between the charges.

Given:

The force of attraction between the plastic balls, F = 62 N,

The distance between the balls, r = 28 cm = 0.28 m.

We can rearrange Coulomb's law to solve for the magnitude of the charge q1 or q2:

|q1| * |q2| = (F * r^2) / k.

Substituting the given values:

|q1| * |q2| = (62 N * (0.28 m)^2) / (8.99 x 10^9 Nm^2/C^2).

|q1| * |q2| ≈ 6.226 x 10^(-6) C^2.

Since the two plastic balls are initially uncharged, the magnitudes of the charges on each ball will be equal, so we can express |q1| and |q2| as q:

q^2 ≈ 6.226 x 10^(-6) C^2.

Taking the square root of both sides:

q ≈ √(6.226 x 10^(-6)) C.

q ≈ 0.0025 C.

Therefore, the magnitude of the charge transferred between the two plastic balls is approximately 0.0025 C.

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GUYS PLEASE HELPPPP


Q. A body is thrown at an angle of 30 degree with velocity of 30m/s downward, if the height of the tower is 15m find:

1) the time when body reaches the ground
2) displacement vector
3) angle when body hits the ground
4) max height?

Answers

1. y = v₀y * t + (1/2) * a * t²

-15 = (30 * sin(30)) * t - (1/2) * 9.8 * t²
t ≈ 3.04 seconds.
2. x = v₀x * t
x = (30 * cos(30)) * 3.0

Simplifying the equation, we find that the horizontal displacement is approximately x ≈ 157.47 meters.

3. Angle when the body hits the ground:
Since the launch angle is 30 degrees downward, the angle when the body hits the ground will be 180 degrees minus the launch angle. Therefore, the angle when the body hits the ground is 180 - 30 = 150 degrees.

4. Maximum height:

y = v₀y * t + (1/2) * a * t²
y = (30 * sin(30)) * 3.04 - (1/2) * 9.8 * (3.04)²
y ≈ 15.57 meters.

1. To find the time when the body reaches the ground, we can use the vertical motion equation:

h = v₀y * t + (1/2) * g * t²

where:

h = height of the tower = 15m

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time

Plugging in the values:

15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)

Simplifying the equation:

15 = 15t * 0.5t² + 4.9t²

Combining like terms:

15 = 7.5t² + 4.9t²

Simplifying further:

15 = 12.4t²

Dividing both sides by 12.4:

t² = 15 / 12.4

Taking the square root of both sides:

t = √(15 / 12.4)

Calculating the value:

t ≈ 1.01 seconds

Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.

2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.

Horizontal component:

The horizontal displacement can be calculated using the formula:

x = v₀x * t

where:

v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀x = 30m/s * cos(30°)

t = 1.01 seconds

Calculating the value:

v₀x ≈ 26.02 m/s

Vertical component:

The vertical displacement can be calculated using the formula:

y = v₀y * t + (1/2) * g * t²

where:

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀y = 30m/s * sin(30°)

t = 1.01 seconds

Calculating the value:

v₀y ≈ 15 m/s

Now we have the horizontal and vertical components of the displacement vector:

Horizontal component: x ≈ 26.02 m/s

Vertical component: y ≈ 15 m/s

Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).

3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.

The horizontal component of the velocity, v₀x, can be calculated using the formula:

v₀x = v₀ * cos(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀x = 30m/s * cos(30°)

Calculating the value:

v₀x ≈ 26.02 m/s

The vertical component of the velocity, v₀y, can be calculated using the formula:

v₀y = v₀ * sin(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀y = 30m/s * sin(30°)

Calculating the value:

v₀y ≈ 15 m/s

Now, to find the angle when the body hits the ground, we can use the inverse tangent function:

θ = arctan(v₀y / v₀x)

Plugging in the values:

θ = arctan(15 m/s / 26.02 m/s)

Calculating the value:

θ ≈ 30.96 degrees

Therefore, the angle when the body hits the ground is approximately 30.96 degrees.

4. To find the maximum height, we can use the vertical motion equation:

h = v₀y² / (2 * g)

where:

h = maximum height

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

Plugging in the values:

h = (30 * sin(30°))² / (2 * 9.8)

Calculating the value:

h ≈ 27.55 meters

Therefore, the maximum height reached by the body is approximately 27.55 meters.

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hat is hard glass? Classify the components of glass based on formers, inter

Answers

Hard glass is a type of glass characterized by its high resistance to thermal and mechanical stress. It is commonly used in scientific and industrial applications. The components of glass can be classified into formers, intermediates, and modifiers.

Hard glass, also known as borosilicate glass, is a type of glass that possesses high resistance to thermal expansion and mechanical stress. It is composed mainly of silica (SiO2) and boron oxide (B2O3), which act as formers in the glass structure. The formers provide the basic framework of the glass and contribute to its high durability and thermal stability.

In addition to formers, glass can also contain intermediates and modifiers. Intermediates, such as alumina (Al2O3) and magnesia (MgO), help in reducing the melting point of the glass and improve its workability during the manufacturing process. Modifiers, such as sodium oxide (Na2O) and calcium oxide (CaO), alter the properties of the glass, such as its refractive index and chemical resistance.

By combining the right proportions of these components, glassmakers can produce glass with specific characteristics suitable for various applications, ranging from laboratory equipment and optical lenses to household items and industrial containers.

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Desmond builds a set of towers out of blocks. The table shows the number of blocks in each tower. Tower # 1 2 3 4 5 Number of blocks5 10 20 40 80 Which explicit formula correctly represents the number of blocks, an, in terms of the tower number, n? A. An =n+ 80 B. Ar = 2n +5 C. An = 5(2)7-1 D. An = 10(5)n​

Answers

Answer:B

Explanation:

How is the energy carried per photon of light related to the wavelength of the light?

Answers

The energy carried per photon of light is inversely proportional to the wavelength of the light

The "quantum of electromagnetic radiation" is called a photon. It is, thus, the tiniest and most basic particle of electromagnetic radiation. A photon is a stable particle that has no mass and no electric charge. The concept of wave-particle duality holds true for this particle.

The distance between the two crests or troughs of the light wave is known as the wavelength of light. It is represented by the greek letter lambda 'λ'

A quantity is inversely proportional if it decreases when the related quantity is increased or vice versa. For example, frequency is inversely proportional to wavelength

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to determine an athlete's body fat, she is weighed first in air and then again while she's completely underwater. it is found that she weighs 690 n when weighed in air and 44.0 n when weighed underwater. what is her average density?

Answers

The athlete's average density is 10455 kg/m³.

To determine the athlete's average density, we can use the concept of buoyancy and Archimedes' principle.

The buoyant force on an object is equal to the weight of the fluid displaced by the object.

When the athlete is underwater, she displaces an amount of water equal to her own volume. The weight of this water is equal to the difference between her weight in air and her weight underwater.

the buoyant force on the athlete is:

B = (weight in air) - (weight underwater)

B = 690 N - 44.0 N

B = 646 N

The buoyant force is equal to the weight of the displaced water, which is equal to the weight of the athlete when submerged.

Therefore, we can find the volume of the athlete by dividing the buoyant force by the density of water and the acceleration due to gravity.

V = B / (density of water * g)

V = 646 N / (1000 kg/m³ * 9.81 m/s²)

V = 0.066 m³

The average density of the athlete can then be found by dividing her weight in air by her volume:

density = (weight in air) / V

density = 690 N / 0.066 m³

density = 10455 kg/m³

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7) What was Cecilia Payne's major contribution to astronomy? Why is this so significant in our undertanding of the stars and the Universe?

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Cecilia Payne's major contribution to astronomy was her discovery that stars were mostly made up of hydrogen and helium. Prior to her work, it was widely believed that stars had similar compositions to the Earth, with heavier elements making up the bulk of their mass.

Payne's groundbreaking research showed that this was not the case, and that hydrogen and helium were the most abundant elements in stars. This discovery revolutionized our understanding of the composition and evolution of stars, and provided a foundation for modern astrophysics. Payne's work also paved the way for future discoveries, including the realization that the Big Bang, which created the Universe, was primarily made up of hydrogen and helium. Overall, Cecilia Payne's contribution to astronomy was significant in expanding our knowledge of the stars and the Universe, and has had a lasting impact on the field.


Cecilia Payne's major contribution to astronomy was her discovery that stars are primarily composed of hydrogen and helium. This finding was significant because it fundamentally changed our understanding of the stars and the Universe by revealing the basic elements that make up celestial objects, allowing scientists to study their formation, evolution, and the processes occurring within them.

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Two objects collide. The total momentum of both objects is 14 kg x m/s Object A has a momentum of 3 kg x m/s. What is the momentum of an object B?

Answers

The momentum of object B is 11 kg x m/s.

To find the momentum of object B, we can use the principle of conservation of momentum. This principle states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision.

Therefore, we can calculate the momentum of object B as follows:
Total momentum before collision = Total momentum after collision


The total momentum before collision is the sum of the momentum of object A and the momentum of object B:
Total momentum before collision = 3 kg x m/s + momentum of object B
The total momentum after collision is given as 14 kg x m/s.

So we can set up an equation:
3 kg x m/s + momentum of object B = 14 kg x m/s
Simplifying this equation, we get:
momentum of object B = 14 kg x m/s - 3 kg x m/s
momentum of object B = 11 kg x m/s



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Name any two medium which states about the weather report.

Answers

Answer:

1. Government Agencies

2. Television Stations

Explanation:

Weather reports are needed by members of the public to be alert on daily and future weather trends as this would affect how they arrange their affairs. The weather can affect daily movement. For example, when it rains heavily, movement might become limited. Government agencies such as the National Weather Service (NWS), state the weather report.

Television channels like the Cable News Network have programs dedicated to weather reporting. The reporter states what the weather would be like in different cities and the public take note of that.

During the pyramid-building era the ancient Egyptians used two units of length, the palm and the ell. An ell was 7 palms and a palm was about 3 inches. If a hawk is tracked at a diving speed of 3 ells per second, what is its speed in inches per second? 1. 42 in/s 2. 5.25 in/s 3. 0.7 in/s 4. 126 in/s

Answers

Knowing that the units of the ancient Egyptians were palm and ell, where 1 ell was 7 palms and 1 palm was 3 inches, the speed of a hawk tracked as 3 ells/s is equal to 63 in/s. The given options are not the correct ones.            

We have that:

1 ell = 7 palms

1 palm = 3 inches

v: is the speed of the hawk = 3 ells/s

To find the speed of the hawk in inches per second, we need to convert 3 ells/s to in/s, as follows:  

\( v = 3 \: \frac{ells}{s}*\frac{7 \: palms}{1 \:ell}*\frac{3 in}{1 \: palm} = 63 \frac{in}{s} \)      

 

Therefore, the speed of the hawk is 63 inches per second. The given options are not the correct ones.

     

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Match the biomes with the corresponding animals, vegetation, or geographic location.


forest at highest latitudes:


prairies/ temperate climate:


high humidity and rainfall/ near equator:


no trees/ polar bears/ mosses:


<25cm rain/ few animals:


mostly small mammals/ many scrubs/ steppes:


abundant thick vegetation/ many species:


hardwood trees/ deer, squirrel, foxes:

Answers

This is kinda confusing. I wish u just to a screenshot of the problem but here goes...

Forest at highest latitudes- Hardwood trees/deer, squirrel, foxes

Praries/temperate climate- Mostly small mammals/scrubs/steppes

High humidity/rainfall near equator- Abundant thick vegatation/manny species

No trees/ polar bears/ mosses- 25cm rain/few animals

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