A flat, circular loop has 15 turns. The radius of the loop is 14.0 cm and the current through the wire is 0.55 A. Determine the magnitude of the magnetic field at the center of the loop (in T). T

Decibel (dB)

Sound intensity is the power carried by sound waves per unit area in a perpendicular direction to that area.

The unit of sound intensity is the decibel

Answer:

Unbalanced

Explanation:

Answer:

the cave walls reflect sound waves

Explanation:

i did the study island

Answer:

the ball lose kentic energy and gains potential energy rolling upward

Answer:

c

Explanation:

when a ball is rolling down it loses potential and gains kinetic, but in this case since the ball is going upwards it is losing kinetic energy and gaining potentail like a roller coaser

In a reference frame fixed to Earth, a point on the equator moves zero distance in 1 hour.

A frame of reference in physics is made up of an abstract coordinate system and the collection of physical reference points that fix the coordinate system specifically and regulate measurements inside it.

When we take a reference frame fixed to Earth,  the displacement due to earth's rotation can not be measured. So, any point on earth remains in rest through out the day with respect to the reference frame fixed to Earth. Hence, a point on the equator moves no distance in 1 hour in a reference frame fixed to Earth.

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Answer:

24 m/s

Explanation:

V=Vi+at

given initial velocity is 0, acceleration is 2 and time is 12 sec

find final velocity by plugging in the variables into the equation above.

V=0+2x12=24m/s

The velocity is 4.9 m/s.

Centripetal acceleration is the acceleration that acts towards the center of a circular path and is required to maintain an object in circular motion. It is defined as the rate of change of velocity of an object moving in a circular path.

The formula for centripetal acceleration can be expressed as:

a_c = v^2 / r

Given that;

a = v^2/r

a = acceleration

v = tangential velocity

r = radius

Thus;

v = √ar

v = (6 * 4)^1/2

v = 4.9 m/s

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Answer:

\(\boxed {\boxed {\sf a \approx 0.4 \ m/s^2}}\)

Explanation:

According to Newton's Second Law of Motion, force is the product of mass and acceleration.

\(F= m \times a\)

The net force is 5 Newtons and the mass is 13 kilograms. Let's convert the units for force to make the problem and unit cancellation easier.

Now we know the values for 2 variables:

Substitute the values into the formula.

\(5 \ kg *m/s^2 = 13 \ kg * a\)

Since we are solving for the accleration we must isolate the variable, a. It is being multiplied by 13 kilograms and the inverse of multiplication is division. Divide both sides by 13 kg

\(\frac {5 \ kg *m/s^2}{13 \ kg}= \frac{ 13 \ kg *a}{13 \ kg}\)

\(\frac {5 \ kg *m/s^2}{13 \ kg}=a\)

The units of kilograms (kg) cancel.

\(\frac {5 m/s^2}{13 }=a\)

\(0.384615385\ m/s^2=a\)

The original measurements of force and mass ( 5 and 13) have 1 and 2 significant figures. We must round our answer to the least number of sig figs: 1.

For the number we found, that is the tenths place. The 8 in the hundredth place (0.384615385) tells us to round the 3 up to a 4.

\(0.4 \ m/s^2 \approx a\)

The acceleration is approximately 0.4 meters per square second.

The torque acting on the nut is given as,

The work done on the nut can be given as,

Substitute the known expression,

Substitute the known values,

Thus, the work done by person to rotate the nut is 147.2 J.

The wavelength of a wave is the distance it travels in the direction of propagation over a period of periodic time.

The distance covered by a point on the wave pattern in one unit of time is referred to as wave speed. It specifies the speed at which the wave is travelling through the medium and is frequently measured in figures like meters/second. The distance an object goes in a certain amount of time determines its speed, whether it be an object or a wave.

A wave is what? A wave is an energetic disturbance in a medium that doesn't include any net particle motion. Elastic deformation, a change in pressure, an electric or magnetic intensity, an electric potential, or a change in temperature are a few examples.

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It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Answer:

v = 7.2 m/s

Explanation:

After covering the 14-meter distance, the sprinter's final speed will be 7.2 m/s.

Describe acceleration.

The rate at which velocity changes in relation to time is referred to as acceleration. In mathematics -

a =Δv/Δt

Given is a sprinter who begins at rest and covers a distance of 14 metres at a speed of 1.87 metres per second. This allows us to write:

Initial speed [u] equals zero

The speed [a] is 1.87 m/s2.

Distance [d] = 14 metres.

Assume that v will be the final velocity.

Using the third motion equation -

v² - u² = 2aS

v² = 2aS

v² = 2 x 1.87 x 14

v² = 52.36

v = √52.36

v = 7.2 m/s

When a 0.80 Kg block is used in place of a 0.25 Kg block, the length of the string is increased by 19.6 cm.

The formula used by the Hooke's Law Calculator is Fs = -kx, where F is the spring's restoring force, k is the spring constant, and x is the displacement, or the length by which the spring is being stretched

We'll start by determining the spring's string constant. Specifics below:

Extension (e) = 6.0 cm

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.25 × 9.8 = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 6

Divide both sides by 6

K = 2.45 / 6

K = 0.40 N/cm

The extension will be calculated after the 0.25 kg block is replaced with the 0.80 kg block. As demonstrated below:

Mass (m) = 0.80 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) = mg = 0.80 × 9.8 = 7.84 N

Spring constant (K) = 0.40 N/cm

Extension (e) = ?

F = Ke

7.84 = 0.40 × e

Divide both sides by 0.40

e = 7.84 / 0.40

e = 19.6 cm

We may thus deduce from the preceding computation that the spring will lengthen by 19.6 cm.

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Answer:

Convection and Radiation

Explanation:

Because the sun heats up the earth which cause the warm temperature and you probably know convection heat up the coefficient  and radiation transfer heat electromagnetic or heat LOL

The cause of weather systems on earth is CONVECTION.

This transfer of heat can be calculated as

In conclusion, the cause of weather systems on earth is CONVECTION.

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Answer:

Physics

Explanation:

The period of a pendulum is the time it takes for the pendulum to complete one full oscillation, or swing back and forth. The frequency of a pendulum, on the other hand, is the number of oscillations it completes in one second. The frequency is calculated by taking the reciprocal of the period, or 1/period.

If the period of a pendulum decreases from 8 seconds to 2 seconds, it means that the pendulum is swinging back and forth more quickly, as it is taking less time to complete one full oscillation. To find the new frequency of the pendulum, we can use the formula:

frequency = 1 / period

Initially, when the period was 8 seconds, the frequency was:

frequency = 1 / 8 = 0.125 Hz

After the period decreased to 2 seconds, the new frequency can be calculated as:

frequency = 1 / 2 = 0.5 Hz

So, the frequency of the pendulum increases from 0.125 Hz to 0.5 Hz when the period decreases from 8 seconds to 2 seconds. This means that the pendulum is oscillating at a faster rate, completing more oscillations in one second.

The speed of the spaceship relative to Arrakis is 0.842c.The accompanying image provides the answer to the provided query and an explanation.

A launch vehicle from Earth can launch a spaceship, which is made to go in space. In order to complete a mission with or without people and then return to Earth, it may carry a payload.Arrakis, also called "Dune," and subsequently "Rakis" following the demise of God Emperor Leto Atreides II, is a harsh desert planet that may be found in the Canopus star system, outside the Old Imperium. Under Muad'Dib's reign, it subsequently became into the hub of the Imperium. It served as the first and for a while only source of the Spice Melange, an essential component of space travel.

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Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

The distance should be 480.2 m

Since A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. And, there is the velocity of 343 m/s

\(v = 2x \div t\\\\343 = 2x \div 2.8\\\\2x = 343 \times 2.8\)

2x = 960.4

x = 480.2 m

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Answer:

The faster object

Explanation:

Sure they may have the same mass but the item with more speed is going to take more force to cancel out or stop its motion. It would take less force to halt the slower object as less momentum is behind it.

The mass of an object depends on the mass and speed of the object. If two same masses are moving in different speed, the faster object is having greater momentum.

Momentum of an object is its ability to bring the force in making maximum displacement. In physics momentum is the product of mass and velocity.

P = mv.

Hence, momentum is directly proportional to the mass and speed of the object. It has the unit Kg m/s.

In a collision between two objects the total initial momentum of the objects will be equal to the total final momentum of them. Hence, momentum of a system is conserved.

As per the above equation, as the mass or speed or both increases, momentum increases. Hence, for two objects with same mass, the one moving faster will have greater momentum.

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The free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

Free body diagram refers to the formation of a system showing all the possible forces that are being exerted on the body isolating it from the surrounding.

System refers to the object of inspection i.e. the thing that is being noted down a system can be anything from an object to multiple objects and even surrounding whereas surrounding is everything else that is not a part of the system.

We have been already given all the required inputs that will help us to create a free body diagram including:

Friction force on the body being = 12 Newton

Weight of the body = 15 Newton

Normal acting on the body = 9 Newton

To create the free body diagram we simply isolate or from the surrounding and consider it to be a system then help of the vectors we will create the system consisting of the body and all the possible forces that acting on it.

We now draw the vectors for friction force weight of the body and normal acting on the body to get our required free body diagram.

Therefore, the free body diagram of the given system will include a normal force of value 9 Newton perpendicular to the surface with friction force at 30° with 12 newton force and the weight of 15 Newton pointing downwards.

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Answer: a rubber band

Explanation: A rubber band has no conductivity and no electricity would be able to flow whereas steel and copper and aluminum would be able to allow electricity to flow due to how they are built

Answer:

F = M A

F = 750 * 0.90

F = 675

hope it helps you

Answer:

0.1667 meters/second.

Explanation:

To find Jibari's average velocity for the trip, we need to first calculate his average velocity for each leg of the trip. To do this, we need to divide the distance he traveled by the time it took him to travel that distance.

For the first leg of the trip, Jibari walked 40.0 meters east in 120.0 seconds. His average velocity for this leg of the trip is therefore 40.0 meters / 120.0 seconds = 0.3333 meters/second east.

For the second leg of the trip, Jibari walked 30.0 meters west in 60.0 seconds. His average velocity for this leg of the trip is therefore 30.0 meters / 60.0 seconds = 0.5000 meters/second west.

To find Jibari's average velocity for the entire trip, we need to add the velocities for each leg of the trip, taking into account their direction. Since the first leg of the trip was east and the second leg was west, we can simply add the two velocities together to find the overall average velocity.

Jibari's overall average velocity for the trip is therefore 0.3333 meters/second east + 0.5000 meters/second west = 0.1667 meters/second.

Therefore, Jibari's average velocity for the trip was 0.1667 meters/second.

Jibari's average velocity for the trip is 0.7 m/s east.

To solve for Jibari's average velocity, we will first need to find his total displacement. We can do this by adding the magnitudes of his eastward and westward displacements. The magnitude of Jibari's eastward displacement is 40.0 meters, and the magnitude of his westward displacement is 30.0 meters. So, his total displacement is

40.0 - 30.0 = 10.0 meters east.

We can then find Jibari's average velocity by dividing his total displacement by the total time it took him to complete the trip. The total time it took Jibari to complete the trip is

120.0 + 60.0 = 180.0 seconds.

So, his average velocity is

10.0 / 180.0 = 0.7 m/s east.

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The forces F3 and F6 form a couple since they are parallel, act in the same directions, and have the same magnitude (both are 3N), but they do not have the same point of application.

A couple is a pair of equal but disjointed forces that act in opposite directions and along parallel lines of force.

The rigid body rotates about its center of mass as a result of the forces acting on it at various places.

We can observe that the forces F3 and F6 in the provided set of forces are parallel, have the same magnitude of 3N, and act in opposite directions.

However, because they are applied to various locations on the rigid body, the body will rotate as a result. The stiff body tends to rotate around its center of mass because of this phenomenon, which is known as a couple.

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Answer:

\(F = 5.4*10^{-8}\ N\)

Explanation:

Given

Represent the mass of the student with M and the mass of the slice of pizza with m

\(M = 92kg\)

\(m = 550g\)

\(d = 25cm\)

Required

Determine the force of attraction

This is calculated as:

\(F = \frac{GMm}{d^2}\)

Where G = gravitational constant

\(G = 6.67408 * 10^{-11}\ m^3 kg^{-1} s^{-2}\)

Convert both mass to kilogram and distance to metre

\(m = 550g\)

\(m = 550kg/1000\)

\(m = 0.55kg\)

\(d = 25cm\)

\(d = 25m/100\)

\(d = 0.25m\)

Substitute these values in \(F = \frac{GMm}{d^2}\)

\(F = \frac{6.67408 * 10^{-11} * 92 * 0.55}{0.25^2}\)

\(F = \frac{6.67408 * 92 * 0.55* 10^{-11} }{0.25^2}\)

\(F = \frac{337.708448* 10^{-11} }{0.0625}\)

\(F = 5403.335168* 10^{-11}\)

\(F = 5.403335168* 10^3*10^{-11}\)

\(F = 5.403335168*10^{3-11}\)

\(F = 5.403335168*10^{-8}\)

\(F = 5.4*10^{-8}\ N\)

Answer:

I don't know.

The mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. The number that was removed is 75.

To solve this problem, we can use the concept of the mean (average) and apply it to the given information. Let's go through the steps to determine the number that was removed.

Step 1: Find the sum of the 6 numbers.

Since the mean of the 6 numbers is 25, we can multiply the mean by the total number of values to find the sum. In this case, 25 * 6 = 150.

Step 2: Find the sum of the remaining numbers.

To find the sum of the remaining numbers, we need to subtract the number that was removed from the original sum. Let's denote the number that was removed as "x". Therefore, the sum of the remaining numbers is 150 - x.

Step 3: Determine the number of remaining numbers.

Since one number was removed, the total number of remaining numbers is 6 - 1 = 5.

Step 4: Calculate the average of the remaining numbers.

We are given that the average of the remaining numbers is 15. To find the sum of the remaining numbers, we can multiply the average by the number of remaining numbers. Therefore, 15 * 5 = 75.

Step 5: Set up the equation and solve for the removed number.

Now we can set up the equation using the information from Steps 2 and 4. We have the equation: 150 - x = 75.

Step 6: Solve the equation.

To find the value of x, we can solve the equation. Subtracting 75 from both sides gives us 150 - 75 = x, which simplifies to x = 75.

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Answer:

16

Explanation:

6+10=16

the box will go forward but it will be a little harder.

To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

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