a focused imaging system has a magnification m and uses a lens with focal length f. the distance between the image plane and the object plane is:

Answer:

D. Electromagnetic Induction.

Explanation:

The length of cable CD required for static equilibrium in the given position is determined by equating the tension in cable CD to the weight of the hanging mass. The tension in cable CD can be found using the formula T = mg.

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Answer:

B

Explanation:

Answer:

B

Explanation:

In contrast to other fish, who have bladders filled with gas, sharks have a liver filled with low-density oil that is similar to vegetable oil. This oil is lighter than water and tends to rise to the top of the water if not contained but because it is in the sharks liver its contained therefor the shark floats!

The functional group circled in the term "aspirin" is the carboxylic acid group.

Aspirin, also known as acetylsalicylic acid (ASA)), is a nonsteroidal anti-inflammatory drug (NSAID) used to reduce pain, fever, and/or inflammation and as an antithrombotic. Specific inflammatory conditions that aspirin is used to treat include Kawasaki disease, pericarditis, and rheumatic fever.

Aspirin can also have very serious side effects, such as bleeding in the brain or stomach or kidney failure. A rare side effect of daily low-dose aspirin is hemorrhagic stroke. Aspirin can help prevent and treat a range of health issues, but people under 18 should not take it without medical guidance.

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Answer:

Football

Power

Jamm

Steady

Kick

Answer:

C

Explanation: Water vapor can turn into liquid water when it cools and Liquid water turns into vapor when it heats

The temperature of the water after 30g of steam has condensed will be approximately 52.14°C.

To solve this problem, we need to consider the energy transfer that occurs when steam condenses into water. The energy released by the condensing steam will be absorbed by the water, resulting in a temperature change.First, let's calculate the energy released when 30g of steam condenses. The specific latent heat of steam is given as 2.26 × 10^6 J/kg, so the energy released by 30g of steam can be calculated as:

Energy released = (30g) × (2.26 × 10^6 J/kg) = 6.78 × 10^7 J

Next, we need to calculate the energy required to raise the temperature of the water from 20°C to the final temperature. The specific heat capacity of water is given as 4200 J/kgK, and the mass of the water is 500g. Therefore, the energy required can be calculated as:

Energy required = (500g) × (4200 J/kgK) × (final temperature - 20°C)

Since the energy released by the steam is equal to the energy required by the water, we can set up the equation:

6.78 × 10^7 J = (500g) × (4200 J/kgK) × (final temperature - 20°C)

Now, we can solve for the final temperature:

(final temperature - 20°C) = (6.78 × 10^7 J) / ((500g) × (4200 J/kgK))

(final temperature - 20°C) = 32.14°C

final temperature = 32.14°C + 20°C

final temperature ≈ 52.14°C

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The speed of the vehicle is 62.8 m/s

We have the descent vehicle landing on the moon and the following information  are available;

vertical velocity toward the surface of the moon = 29.1 m/s

horizontal velocity = 55.6 m/s

Thus the speed along the descent path = √(29.1)^2 + ( 55.6)^2

= 62.8 m/s

Now the angle is obtained from;

180° - tan-1( 55.6/29.1)

= 118 degrees

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The x-component of A vector is - 2.39 unit.

The y-component of A vector is  - 4.02  unit.

Vector is a colloquial term  that refers to some quantities that cannot be expressed by a single number (a scalar) or to elements of some vector spaces.

The magnitude of A vector is 4.68 unit.

The  direction of A vector is 30.7° to the left of the negative y-axis.

So, A vector is in 3rd co-ordinate.

Hence, the x-component of A vector is = - Asin30.7°

= - 4.68 × sin30.7°

= - 2.39 unit.

Hence, the y-component of A vector is = - Acos30.7°

= - 4.68 × cos30.7°

= - 4.02  unit.

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Answer: The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.

The reaction between acetic acid and potassium hydroxide (KOH) is given by the equation:

CH3COOH + KOH → CH3COOK + H2O.

It can be observed that for every mole of KOH added, one mole of H+ from CH3COOH reacts with one mole of OH- from KOH to produce one mole of H2O. Therefore, after the addition of n moles of KOH, the number of moles of H+ remaining is (0.200 - n) moles (since 0.200 M is the initial concentration of acetic acid). On the other hand, the number of moles of CH3COOK produced is also n moles; thus the final concentration of CH3COOK is n/V (where V is the total volume of the solution).

The reaction produces a salt (CH3COOK), which is neutral. Therefore, the final pH is given by: pH = pKa + log([A-]/[HA]) where A- is CH3COOK and HA is CH3COOH.

To find the pH of the resulting solution after the following volumes of KOH have been added, we need to calculate the number of moles of KOH added, the number of moles of CH3COOK produced, the number of moles of CH3COOH remaining, and the total volume of the solution. Then we can use the Henderson-Hasselbalch equation above to find the pH.

Here are the calculations: Initial number of moles of CH3COOH = M × V = 0.200 × 0.100 = 0.020 moles. For each mole of KOH added, one mole of CH3COOH reacts with one mole of KOH to produce one mole of CH3COOK.Number of moles of KOH added Volume of KOH added (mL)Moles of KOH added0.02 0.00 (initial) 0.000.02 10.10 0.010.02 20.20 0.020.02 30.30 0.030.02 40.40 0.040.02 50.50 0.05Number of moles of CH3COOK produced = number of moles of KOH added = n moles. Concentration of CH3COOK produced = n/V = n/(Vinitial + V added) = n/(0.100 L + V added)

Number of moles of CH3COOH remaining = initial number of moles - number of moles of KOH added = 0.020 - n moles. Total volume of the solution after the addition of KOH = V initial + V added = 0.100 L + V added. We can then use the Henderson-Hasselbalch equation to find the pH: pH = pKa + log([A-]/[HA])where A- is CH3COOK and HA is CH3COOH.pKa of acetic acid = 4.76

Let's tabulate the values of n, [A-], [HA], and pH for each volume of KOH added: Number of moles of KOH added n (moles)Concentration of CH3COOK produced [A-] (M)

Number of moles of CH3COOH remaining [HA] (M)pH0.000.000.020.76 (initial)0.010.010.019.84 0.020.020.018.98 0.030.030.018.20 0.040.040.017.49 0.050.050.016.85.

The pH of the solution after 50.5 mL of 0.100 M KOH has been added is 16.85.

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Explanation:

v = u + a * t

60 = 15 + 6 * t

t = 7.5 seconds

The Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light.

First, discuss the relationship between temperature, radiant energy, and lighting efficiency.
Incandescent light sources emit light due to their nonzero temperature. As the temperature of the source increases, the amount of radiant energy it gives off also increases. The Blackbody Spectrum simulation helps us visualize how the temperature of a substance affects the way light is emitted.
In the simulation, a curve represents the radiation intensity and energy emitted with respect to the wavelength at a given temperature. As the temperature rises, the curve's peak shifts towards shorter wavelengths, and the area under the curve increases. This shift indicates that the emitted light becomes more energetic and intense.
However, not all of this emitted energy is in the visible spectrum; a significant portion can be in the form of infrared radiation (heat). Incandescent light sources are not very energy-efficient, as a large portion of their energy output is wasted as heat rather than visible light. The lighting efficiency of an incandescent source is determined by the percentage of radiant energy that falls within the visible spectrum.
To summarize, the Blackbody Spectrum simulation allows us to explore how the temperature of incandescent light sources affects their emitted light. As the temperature increases, the emitted radiant energy also increases. However, a considerable amount of energy is lost as heat, making incandescent sources less energy-efficient compared to other lighting technologies.

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The tip of the turbine fan blade is moving at approximately 540 meters per second.

The tip of the turbine fan blade in a turbojet engine is moving at a considerable speed. To determine its velocity, we need to consider both the linear and rotational aspects of its motion.

First, let's calculate the linear velocity. The diameter of the turbine fan blade is given as 1.8 meters, which means the radius is half of that, or 0.9 meters. The linear velocity can be determined by multiplying the radius by the rotational velocity.

In this case, the blade rotates at 300 revolutions per second, so the linear velocity is 0.9 meters (radius) multiplied by 300 revolutions per second, resulting in 270 meters per second.

Next, to find the velocity of the blade tip, we need to consider the circumference of the circle traced by the blade tip during each revolution.

The circumference is given by 2π times the radius, which in this case is 2π multiplied by 0.9 meters, equal to approximately 5.65 meters. Multiplying this value by the rotational velocity of 300 revolutions per second gives us a tip velocity of approximately 1695 meters per second.

Therefore, the tip of the turbine fan blade in a turbojet engine is moving at approximately 540 meters per second, considering both its linear and rotational velocities.

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Answer:

Sound is a vibration, or wave, that travels through the air. Sound waves are invisible to our eyes; unless we find a way to make the sound waves move something that we can see. In this activity, your child will use different noise-making objects to cause sound waves and make sand visibly move.

Sound wave can be described by five characteristics: Wavelength, Amplitude, Time-Period, Frequency and Velocity or Speed. The minimum distance in which a sound wave repeats itself is called its wavelength.

Explanation:

When the vibrating air hits your eardrum, it causes your eardrum to vibrate, just as the balloon did. These vibrations are transferred through the tiny bones in your ear to the inner ear. These vibrations are detected by nerves, which send impulses that your brain "hears" as sound.

Answer:

frictonal force due to the surface of irregularities

The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The downtown is 5 miles far away, if the car travels at 10 miles / hour for 0.5 hours.

v = d / t

v = Velocity

d = Distance

t = Time

v = 10 mi / hr

t = 0.5 hr

d = v * t

d = 10 * 0.5

d = 5 mi

Velocity of the car is the rate of change of position of the car. In simple words it can be said as velocity is used to calculate the distance covered in a given amount of time.

Therefore, the downtown is 5 miles far.

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(a) Duration of the ball's flight is 2.5S

(b) Angle of its velocity is 16.1

(c) Speed of the ball is 22.53 m/s

(a). To determine the duration of the ball's flight in

We calculate the whole time when the ball touches the ground, thus we enter y=0 and all other specified values in the equation.

\(25sin30t-1/210t^{2} = 0\)

\(t = 2.5 s\)

(b) After it has been in the air for one-fourth of this period, determine the angle of its velocity with respect to the ground.

t1=1/4 t = 2.5/4 = 0.625 s

\(v_{x} = 25\sqrt{3} /2 m/s\)

\(v_{y} = 25/2 - 2.5/2 = 12.5/2 m/s\)

∅= 16.1

(c) To determine speed of the ball for time \(t_{1} ,t_{2} , t_{3}\)

\(v=\sqrt{v} ^{2}{x} + \sqrt{v} ^{2} y_{}\)

vt1 = 22.53 m/s

vt2 = 21.65 m/s

vt3 = 22.53 m/s

The turning point on the corresponding parabolic curve is where the speed is at its lowest in the xx direction. Physically speaking, the shift in speed does make sense. The ball's initial motion against gravity causes its speed to decrease, but after it reaches the turning point, its speed begins to increase as it descends.

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​

Answer:

1666.7 ETB (birr)

833.3 ETB (birr)

2083.3 ETB (birr)

Explanation:

The first worker

5000*1/3=1666.7

The second worker

5000*1/6=833.3

The third worker

5000*5/12=2083.3

Hope this helps :) ❤❤❤

Answer:

alright

Explanation:

that's so cool I'll join

Answer:

When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the object. For example, when energy is transferred to an Earth-object system as an object is raised, the gravitational field energy of the system increases. This energy is released as the object falls; the mechanism of this release is the gravitational force. Likewise, two magnetic and electrically charged objects interacting at a distance exert forces on each other that can transfer energy between the interacting objects.

Explanation:

Even when an object is sitting still, it has energy stored inside that can be turned into kinetic energy (motion). ... A force is a push or pull that causes an object to move, change direction, change speed, or stop. Without a force, an object that is moving will continue to move and an object at rest will remain at rest.

Energy can be transmitted to or from an object when two things interact because of the forces that each one of the items applies to the other.

For instance, the gravitational field energy of a system including the Earth and an object grows as energy is transmitted to the system when the object is raised.

As the object falls, this energy is released, and the gravitational force provides the mechanism for this release. Similar to this, when two electrically and magnetically charged objects contact at a distance, they exert forces on one another that can transmit energy.

Even when an item is at rest, it still contains energy that can be converted to kinetic energy (motion). A push or pull that moves, changes direction, or otherwise affects an object is called a force.

Therefore, Energy can be transmitted to or from an object when two things interact because of the forces that each one of the items applies to the other.

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Answer:

1) They are electrically neutral

2) They have slightly more weight than protons

Explanation:

The given atomic particle found in the nucleus has the following characteristics;

The location of the particle = The nucleus

The (numbers of the) particle does not contribute to (change) the atomic number of the element

The particles found within the nucleus of an atom are; Neutrons and protons

The particle within the nucleus that determines the atomic number = The number of protons

Therefore, the particle referenced in the question is the neutrons

The two characteristics of the neutron are;

1) The neutrons are neutral, electrically

2) Neutrons have slightly more weight than protons

3) Neutrons are magnetic

4) Neutrons are very small

5) Neutrons consist of three quarks; One 'Up', and two 'Down' quarks

Therefore, two characteristics of the particle are;

1) They are electrically neutral and 2) They are slightly heavier than protons.

Answer:

the steel ball has more potential

Explanation:

Answer:

steel ball has more potential energy

Answer:3

Explanation:

Answer:

I had this awhile ago if I'm not mistaking its A

Answer:

Force = 533.33N

Explanation:

Given the following data;

Power = 40000watt

Velocity = 75m/s

To find the force;

\( Power = force * velocity \)

Making force the subject of formula, we have;

\( Force = \frac {Power}{velocity}\)

\( Force = \frac {40000}{75} \)

Force = 533.33N

Answer:

The easiest way to do this is to realize that the time to fall is the same as the rise time (conservation of energy can easily verify this)

S = 1/2 g t^2      time to fall 2.5 m

t = (5 / 9.8)^1.2 = .714 sec         time in air

v = a t = 9.8 * .714 = 7 m/s     initial vertical speed

Check:

S = v t - 1/2 g t^2       where v is the initial vertical speed

S = 7 * .714 - 4.9 * .714^2 = 2.5 m        total vertical distance traveled

The charge of the particle in this situation is positive. When a charged particle is immersed in a uniform magnetic field, it experiences a force known as the Lorentz force, which is given by the equation:

F = q(v × B)

Where F is the Lorentz force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.

In this case, the particle is moving along a circular path in the counter-clockwise direction, which means that the force acting on the particle is directed towards the center of the circle. This force is known as the centripetal force, and it is given by the equation:

F = mv^2/r

Where m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circle.

Since the Lorentz force and the centripetal force are equal in magnitude and opposite in direction, we can equate the two equations to get:

q(v × B) = mv^2/r

Rearranging the equation and solving for q gives:

q = mv^2/(rB)

Since the particle is moving in the counter-clockwise direction, the velocity vector v is directed tangentially to the circle, and the magnetic field vector B is directed out of the page. The cross product of these two vectors is directed towards the center of the circle, which means that the charge of the particle must be positive in order for the Lorentz force to be directed towards the center of the circle.

Therefore, the charge of the particle in this situation is positive.

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The independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.The dependent variable, the one that you measure the response in, is the distance that the washers travel.

The independent variable in an experiment is the variable that is manipulated by the researcher. It is the variable that is intentionally changed by the researcher to examine the impact of this change on the dependent variable.The dependent variable, on the other hand, is the response that is measured by the researcher.

It is the variable that is being influenced by the independent variable in an experiment. Thus, in the given experiment, the car's hitting the barrier is the independent variable while the distance that the washers travel is the dependent variable.

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Explanation:

6. Converge or come together

7. convex

Answer:1) converge or come together. Convex lens bring together parallel rays of light which pass through it to a point. In other words the focus the intensity of a ray.

2) convex lens are wider in the middle than at the edges. An example of such a convex lens is the magnifying glass.

Explanation: