An object moves along the x-axis. Its position is given by the equation y( X = 4t^2 - 41t+ 78 \). Find the position of the
object when it changes direction
The object changes direction when its velocity changes sign. You can get the velocity function by differentiating the position function with respect to time t :
x(t) = 4t ² - 41t + 78
→ v(t) = dx(t)/dt = 8t - 41
Solve v(t) = 0:
8t - 41 = 0
8t = 41
t = 41/8 = 5.125
Just to confirm that the velocity indeed changes sign:
• Pick any time before this one to check the sign of v :
v (0) = 8•0 - 41 = -41 < 0
• Pick any time after and check the sign again:
v (6) = 8•6 - 41 = 7 > 0
Now just find the position at this time:
x (5.125) = -433/16 = -27.0625
which means the object is 27.0625 units on the negative x-axis.
You can also do this without calculus by completing the square in the position function:
4t ² - 41t + 78 = 4 (t ² - 41/4 t ) + 78
… = 4 (t ² - 2• 41/8 t + (41/8)² - (41/8)²) + 78
… = 4 (t ² - 2• 41/8 t + (41/8)²) - 4•1681/64 + 78
… = 4 (t - 41/8)² - 433/16
which describes a parabola that opens upward. When t = 41/8 = 5.125, the quadratic term vanishes and the turning point of the parabola occurs at a position of -433/16 units.
Voltage
Depends on the amount of resistance
Depends on the amount of current
Is the measurement of electrical pressure
All of the above
Voltage depends on the amount of resistance, current according to the Ohm's law, and, by definition, is the measurement of electrical pressure.
According to the Ohm's Law, the current through a conductor between two points is directly proportional to the voltage across the two points.
Mathematically,
V ∝ I
V = IR
where, R is the resistance of the conductor and I is the current flowing in the conductor. So, the voltage depends on the amount of resistance and current.
Also, Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light.
Hence All of the above option in the given question are true.
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A vertical spring stretches 3.8 cm when a 13-g object is hung from it. The object is replaced with a block of mass 20 g that oscillates in simple harmonic motion. Calculate the period of motion.
Answer:
The period of motion is 0.5 second.
Explanation:
Given;
extension of the spring, x = 3.8 cm = 0.038 m
mass of the object, m = 13 g = 0.013 kg
Determine the force constant of the spring, k;
F = kx
k = F / x
k = mg / x
k = (0.013 x 9.8) / 0.038
k = 3.353 N/m
When the object is replaced with a block of mass 20 g, the period of motion is calculated as;
\(T = 2\pi\sqrt{\frac{m}{k} } \\\\T = 2\pi\sqrt{\frac{0.02}{3.353} } \\\\T = 0.5 \ second\)
Therefore, the period of motion is 0.5 second.
A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole in the table as shown in the figure. Start by showing the free-body diagrams and force equations for each mass, and then derive an equation for the tangential speed of the puck. This will be an algebraic expression that includes the variables mentioned above.
The dangling mass will not move and the puck will keep rotating in its orbit, Therefore, V = √(mgR/M) will be an algebraic expression that includes the variables mentioned above.
What is centripetal force?A centripetal force that causes a body to travel along a curved path. The centripetal force always acts orthogonally to the motion of the body and towards the fixed point of the path's instantaneous centre of curvature. Isaac Newton described it as "a force by which bodies are drawn or impelled, or in any way tend, towards a point as to a centre". Gravity is the centripetal force that causes astronomical orbits, according to Newtonian mechanics theory.
A common example of centripetal force is when a body moves at a constant speed along a circular path. The centripetal force is directed at right angles to the motion as well as along the radius of the circular path towards the centre.
Fc = mg
Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or
Fc = Mac
centripetal acceleration is related to the tangential velocity of the puck as
ac = V²/R
where R is the radius of the orbit. Then we have
Fc = M ac =M ω² R = M V² / R
and, thus
M V² / R = mg
and, solving for V, we get
V = √(mgR/M)
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effort distance of a lever should be increased to lift the havier load give reason
The effort distance of a lever should be increased to lift a heavier load because it provides a mechanical advantage, allowing for easier lifting of the load.
The effort distance of a lever should be increased to lift a heavier load because it allows for a mechanical advantage that compensates for the increased weight.
In a lever system, the effort distance is the distance between the point of application of the input force (effort) and the fulcrum, while the load distance is the distance between the point of application of the output force (load) and the fulcrum. The mechanical advantage of a lever is determined by the ratio of the load distance to the effort distance.
By increasing the effort distance, the mechanical advantage of the lever system is increased. This means that for the same input force (effort), a greater output force (load) can be achieved. When dealing with a heavier load, a higher mechanical advantage is required to overcome the increased resistance.
By increasing the effort distance, the lever system can effectively multiply the applied force, making it easier to lift the heavier load. This allows for the redistribution of force and facilitates the efficient use of human effort in various applications, such as in construction, engineering, and even everyday tools like scissors and pliers.
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What landforms are found on the Moon? (Select all that apply.)
mountains
plateaus
lakes
craters
Answer: I think it’s craters
Explanation:
Answer:
MOUNTAINS
CRATERS
PLATEAUS
Explanation:
The Moon has many familiar landforms like mountains, plains, and dark patches that look like seas. We now know that these areas are not seas filled with water. They are deep dry plains.
Find the acceleration due to gravity on planet Fergie which has a mass of 6.23 * 10^23 kg and a radius of 5.79* 10^7 m
Answer:
The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
Explanation:
We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.
Now, the acceleration due to gravity is defined through the following equation:
\(mg = GMm/R^2\)
where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.
Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get
g = 0.0123 m/s^2.
Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.
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Two identical charges are located 1 m apart and feel a 1 N repulsive electric force. What is the charge of each particle.
The charge on each particles which are 1 m apart and feeling a repulsive force of 1 N is 1.05×10¯⁵ C
AssumptionLet the charge on each particles be q
How to determine the charge Final force (F) = 1 NDistance apart (r) = 1 mElectrical constant (K) = 9×10⁹ Nm²/C²Charge on 1st particle (q₁) = q =? Charge on 2nd particle (q₂) = q =?The charge on each particle can be obtained by using the Coulomb's law equation as shown below:
F = Kq₁q₂ / r²
F = Kq² / r²
1 = (9×10⁹ × q²) / 1²
1 = 9×10⁹ × q²
Divide both side by 9×10⁹
q² = 1 / 9×10⁹
Take the square root of both side
q = √(1 / 9×10⁹)
q = 1.05×10¯⁵ C
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A man yells across a canyon to his friend who hears the yell 3.25 seconds later. How far away is the man's friend? (speed of sound in air = 343 m/s)
The man's friend is at a distance 552.5 m away.
Speed of sound in air, v = 340 m/s
Time after which the echo is heard, t = 3.25 s
The expression for the total distance covered by the sound in the given time,
d = v x t
d = 340 x 3.25
d = 1105 m
Therefore, the distance where the friend is staying would be half of the total distance covered by the sound during the given time.
So, the distance of the friend from the man,
d' = d/2
d' = 1105/2
d' = 552.5 m
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Someone please help with this question. From my knowledge the answer I believe to be correct is 4Em but I’m still not so sure. Please explain!
Answer choices:
1/2 Em
Em
2Em
4Em
Answer:
Explanation:
For an ideal spring over a frictionless horizontal surface, stored energy is only a function of the spring constant k and the distance of compression. The mass of the block doing the compressing is irrelevant
Energy stored in the first example is
Em = ½kd²
Energy stored in the second example is
E₂m = ½k(2d)² = 4(½kd²) = 4Em
So the second situation has four times as much stored spring potential energy as the first situation
4 Em is correct
Good job!
Define power and describe how to determine power.
Answer:Power is a measure of the amount of work that can be done in a given amount of time. Power equals work (J) divided by time (s). The SI unit for power is the watt (W), which equals 1 joule of work per second (J/s). Power may be measured in a unit called the horsepower
Explanation:
Answer:
Explanation:Power equals work (J) divided by time (s).
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
a. The magnitude of the electric force that one particle exerts on the other is 1.72 millinewtons (mN). and b. the force is repulsive
To calculate the magnitude of the electric force between two charged particles, we can use Coulomb's Law, which states that the magnitude of the electric force (F) between two charged objects is given by:
F = k * (|q1| * |q2|) / r^2
where k is the electrostatic constant (k = 8.99 x 10^9 N·m^2/C^2), q1 and q2 are the charges of the particles, and r is the distance between them.
Given:
q1 = 8.01 nC (nanocoulombs)
q2 = 4.22 nC (nanocoulombs)
r = 1.72 m
Converting the charges to coulombs:
q1 = 8.01 x 10^-9 C
q2 = 4.22 x 10^-9 C
Plugging the values into Coulomb's Law:
F = (8.99 x 10^9 N·m^2/C^2) * ((8.01 x 10^-9 C) * (4.22 x 10^-9 C)) / (1.72 m)^2
Calculating the magnitude of the force:
F ≈ 1.72 x 10^-3 N
Therefore, the magnitude of the electric force that one particle exerts on the other is approximately 1.72 millinewtons (mN).
To determine if the force is attractive or repulsive, we need to consider the signs of the charges. If the charges have opposite signs (one positive and one negative), the force is attractive. If the charges have the same sign (both positive or both negative), the force is repulsive.
In this case, both charges are positive, so the force between them is repulsive. The particles will experience a repelling force due to their like charges, causing them to push away from each other.
The question was incomplete. find the full content below:
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 8.01 nC, and the other has a charge of 4.22 nC.
(a) What is the magnitude (in N) of the electric force that one particle exerts on the other?
(b) Is the force attractive or repulsive?
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Analyze each line (A,B,C and D) on this graph to describe the acceleration, and
conclude which line represents the highest acceleration during time 10 sec to 15 sec.
Answer:
i think the 2nd one
the first=0 b/c it's initial velocity and final ones are equal the third one is constant
What mass of a material with density is required to make a hollow spherical shell having inner radius r1 and outer radius r2? (Use any variable or symbol stated above along with the following as necessary: .)
mass =
The mass of a material with density is required to make a hollow spherical shell having an inner radius of r1 and an outer radius of r2 is given as \(\frac{4\pi.p(r^3_2-r^3_1)}{3}\)
What is Density?The amount of anything in relation to a unit of volume, area, or length: as. : the substance's mass in relation to its volume. grams per cubic centimeter is a unit of density.
The volume of a spherical shell can be calculated from:
V= \(V_o - V_1 = \frac{4}{3}\pi(r^3_2 - r^3_1)\)
From the definition of density, ρ = m/v
So,
m = pv = p\((\frac{4}{3} \pi)\)\((r^3_2 - r^3_1)\) = \(\frac{4\pi.p(r^3_2-r^3_1)}{3}\)
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Heat can be transferred by conduction when one object is in direct contact with another object. Conduction can occur in solids, liquids, or gases, but it is more effective in A. gases because their particles are moving faster. B. liquids and gases because they occur at higher temperatures. C. liquids because they have a definite volume but not a definite shape. D. solids and liquids because their particles are arranged more closely together.
Answer:
The correct answer is D. solids and liquids because their particles are arranged more closely together.
Skid of weight 440 N is stuck in the middle of a circular frozen pond of radius 5 m. He cannot move because the pond is absolutely frictionless. He happens to have his 2.6 kg physics textbook so he looks for a solution to his problem. Unable to find a solution he throws his physics textbook in a fit a rage. Skid throws it at a velocity of 4 m/s directly away from him. After throwing the book, how long does it take Skid to reach the edge of the pond
Answer:
It takes 21.7 seconds for Skid to reach the edge of the pond.
Explanation:
We can calculate the time that takes Skid to reach the edge of the pond by conservation of linear momentum:
\( p_{i} = p_{f} \)
\( m_{1}v_{1_{i}} + m_{2}v_{2_{i}} = m_{1}v_{1_{f}} - m_{2}v_{2_{f}} \) (1)
Where:
m₁: is the Skid's mass
m₂: is the book's mass = 2.6 kg
\(v_{1_{i}}\): is the initial speed of Skid = 0 (he was at rest)
\(v_{2_{i}}\): is the initial speed of the book = 0 (it was at rest)
\(v_{1_{f}}\): is the final speed of Skid =?
\(v_{2_{f}}\): is the final speed of the book = 4 m/s. This value is negative since it is moving in the opposite direction of Skid.
First, we need to calculate Skid's mass.
\( m_{1} = \frac{P}{g} \)
Where:
P: is the weight of Skid = 440 N
g: is the acceleration due to gravity = 9.81 m/s²
\( m_{1} = \frac{P}{g} =\frac{440 N}{9.81 m/s^{2}} = 44.8 kg \)
Now, we can find the speed of Skid from equation (1):
\( 0 = 44.8 kg*v_{1_{f}} - 2.6 kg*4 m/s \)
\( v_{1_{f}} = \frac{2.6 kg*4 m/s}{44.8 kg} = 0.23 m/s \)
Finally, the time to reach the edge can be found by using the following equation:
\( v_{1_{f}} = \frac{d}{t} \)
Where:
d: is the distance = radius = 5 m
t: is the time =?
\( t = \frac{d}{v_{1_{f}}} = \frac{5 m}{0.23 m/s} = 21.7 s \)
Therefore, it takes 21.7 seconds for Skid to reach the edge of the pond.
I hope it helps you!
In hiking, what fitness component is required of you
What is the force between two 1.0 X 10^-5 C charges separated by 2.0 m?
According to Coulomb's law, the force between the given charges is 0.225N which is explained below.
Coulomb's Law:Force on two identical charges q separate by a distance of r is given by:
F = kq²/r²
where k is Coulomb's constant
q is the charge
r is the separation between the charges
Given that q = 1×10⁻⁵C,
and r = 2m
So, the force between the given charges will be:
F = (9×10⁹)(1×10⁻⁵)²/2²
F = 0.225N is the required force.
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A baby carriage is sitting at the top of a hill that is 21 m high. The carriage with the baby weighs 20
kg. The carriage has
energy. Calculate it
Answer:
Energy in carriage (Potential energy) = 4,116 J
Explanation:
Given:
Mass of baby = 20 kg
Height = 21 m
Find:
Energy in carriage (Potential energy)
Computation:
The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.
In carriage accumulated energy is potential energy.
Energy in carriage (Potential energy) = mgh
Energy in carriage (Potential energy) = (20)(9.8)(21)
Energy in carriage (Potential energy) = 4,116 J
astone is thrown upwards with an initial velocity of 25m/s atan angle of 30 to the ground.what is the work out the stones horizantal range ?
Answer:
Range is 62.5 metres
Explanation:
Time of flight
\(t = \frac{2u \sin( \theta) }{g} \)
for range, acceleration is zero
from second newton's equation:
\(S = ut + \frac{1}{2} {at}^{2} \)
but a = 0:
let range be x:
\(x = ut \\ x = \frac{2 {u}^{2} \sin( \theta) }{g} \\ \\ x = \frac{ \{2 \times 25 {}^{2} \sin(30 \degree) \}}{10} \\ \\ x = 62.5 \: metres\)
[ taken g to be 10 m/s² ]
Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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Which statement is true about the theory of plate tectonics and the theory of continental drift?
A) The theory of plate tectonics proves the theory of continental drift completely wrong.
B) The theory of plate tectonics tells exactly where the continents were before Pangaea divided.
C) The theory of plate tectonics gives the method by which continents can move as part of plates.
D) The theory of plate tectonics does not explain how continental movements could occur.
The statement that is true about the theory of plate tectonics and the theory of continental drift C. The theory of plate tectonics gives the method by which continents can move as part of plates .
What is theory of plate tectonics and the theory of continental drift ?According to the scientific hypothesis of plate tectonics, the underground movements of the Earth create the primary landforms. By explaining a wide range of phenomena, including as mountain-building events, volcanoes, and earthquakes, the theory, which became firmly established in the 1960s, revolutionized the earth sciences.
The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century.
According to tectonic theory, the Earth's surface is dynamic and can move up to 1-2 inches every year. The numerous tectonic plates constantly move and interact. The outer layer of the Earth is altered by this motion. The result is earthquakes, volcanoes, and mountains.
Therefore, option C is correct.
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As an object moves, the distance it travels increases with time.
Agree
Disagree
Answer: Agree
Explanation:
The idea is that it will be at a farther place at a later period.
An experiment is set up to determine the speed of charged particles as they move through a region that is traversed by a constant electric and a constant magnetic field. The particles are moving toward the right of the page when they encounter the region. The electric field points toward the top of the page, and the magnetic field points out of the page. Required:
Predict how the positively and negatively charged particles of various speeds will behave in this experiment
The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.
What are charged particles?Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.
Generally, the Magnetic area points internal the airplane so through fleming left hand rule is
F = q ( V x B). Ie
hence
qVB = qE
V= E/B then no deflection.
V > E/B then magnetic pressure is dominant over electric powered force.
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Fig on the left shows a stationary source emitting the waves. Fig on the right shows the waves in the medium as the source starts moving towards the left. If you were an observer to the left of the source, what would you observe about the wavelength and the frequency of the waves?
A. Wavelength-Increase, Frequency-Decrease
B. Wavelength-Increase, Frequency-Increase
C. Wavelength-Decrease, Frequency-Increase
D. Wavelength-Decrease, Frequency-Decrease
An image is a copy of an objecí formed by what light
Answer:
Plane mirror
Explanation:
A virtual image is a copy of an object formed at the location from which the light rays appear to come.
What is the value of the charge that experiences a force of 2.4×10^-3N in an electric field of 6.8×10^-5N/C
Hi there!
\(\large\boxed{\approx 35.29 C}\)
Use the following formula:
E = F / C, where:
E = electric field (N/C)
F = force (N)
C = Charge (C)
Thus:
6.8 × 10⁻⁵ = 2.4 × 10⁻³ / C
Isolate for C:
C = 2.4 × 10⁻³ / 6.8 × 10⁻⁵
Solve:
≈ 35.29 C
8. Combine the ice and the room-temperature water. Stir the mixture until the thermometer stays at the
same temperature for at least 1 minute. This means the thermometer is at the same temperature as the
mixture.
9. Record the temperature.
10. Stir the ice-water mixture occasionally for another 5 minutes. Then, record its temperature.
Table B: Part 2 Observations
Initial temperature (in "C) of the room-temperature water
Initial temperature (in "C) of the warm water
Temperature (in "C) of mixed warm water and room-temperature water
Temperature (in "C) of mixed warm water and room-temperature water after 5 min
Temperature (in "C) of mixed warm water and room-temperature water after 10 min
Initial temperature (in "C) of the ice
Temperature (in °C) of mixed ice and room-temperature water
Temperature (in "C) of mixed ice and room-temperature water after 5 min
Physical Science page
The answer for the experiment is obtained by the principle of Newton's law of cooling. The initial temperature of the Room is taken as 32°C.
The ice cubes are mixed with room-temperature water, the ice starts to melt and the water becomes cold. This is because the ice and water have two different temperatures and when they are mixed there is an exchange of heat is taken place. When the ice cubes mixed with water the room temperature is decreases from 32°C. After stirring the mixture because of the heat released, the temperature increases.
When the ice-water mixture is stirred, the heat energy is evolved which melts the ice in the mixture, and therefore the temperature increases gradually. And stirring of water for every 5 minutes leads ice cubes to melt completely to form water and the level of water increases in the final stage. This was given by Newton's law of cooling.
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Dominic has a brain injury. Why is this MOST likely to be a serious injury?
If Dominic has a brain injury, then he must have sustained a serious injury.
Functions of the brainThe brain coordinates all the activities in the body such as speech, locomotion, coordination and intelligence. This makes the brain the master point of control in the body.
Brain injuryWhenever there is an injury to the brain, various parts of the body could be affected. Functions such as speech, locomotion and general coordination may become largely impaired.
Therefore, if Dominic has a brain injury, then he must have sustained a serious injury.
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what are the factors affecting center of mass in an object