a force of 30 n is applied to a ball, and it takes the ball 1.5 seconds to travel 4 meters. what is the work done on the ball?

Answer:

Weight = 88N

Explanation:

Given the following data;

Acceleration due to gravity on moon = 1.6m/s²

Weight on earth = 539N

To find the weight on moon.

First of all, we would calculate the mass;

Weight = mass * acceleration due to gravity.

We know that acceleration due to gravity on earth is equal to 9.8m/s²

Substituting into the equation, we have;

539 = mass * 9.8

Mass = 539/9.8

Mass = 55 kg.

Now, we solve for the weight on moon.

Weight = 55 * 1.6

Weight = 88N

The distance between two lines in the grating is  0.00045 cm.

A diffraction grating is an optical element with a periodic structure used in optics that diffracts light into many beams that move in various directions. A type of structural coloring is the coloration that is emerging.

A good diffraction grating has 2210 lines/cm, that means,

The diffraction grating has 2210 lines in 1 cm.

Hence, the distance between two lines in the grating is = (1 ÷ 2210) cm

= 0.00045 cm.

Hence, the distance between two lines in the grating is  0.00045 cm.

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Explanation:

A) 1.05

B) 1.33

C) 1.16

D) 0.62

All units in cm

Answer:

stars #3

Explanation:

they didn't know it was stars

If the net force were doubled, its acceleration would double. The correct option is B).

Newton's second law of motion relates force, mass, and acceleration.

The equation is

F = ma,

where F is force, m is mass, and a is acceleration. Acceleration is directly proportional to force according to this equation.

When the net force acting on an object increases, the acceleration also increases because the force and acceleration are directly proportional. If the net force acting on an object is doubled, its acceleration also doubles. This implies that the acceleration of an object is proportional to the net force acting on it, according to Newton's second law of motion.

So, if the net force were doubled, its acceleration would double. Therefore, the answer is B) double.

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Answer:

The answer is B) Lourdes>Jameson= Katherine >Montel

Explanation:

Use: W= mgs

Answer:

2 x 10^(-5)

Explanation:

The linear expansivity α can be calculated using the following equation:

Where ΔL is the change in length, ΔT is the change in temperature and L is the original length of the metal. So, replacing the values, we get:

Then, solving for α, we get:

Therefore, the linear expansivity of the metal is 2 x 10^(-5)

Answer: a piece of iron near a magnet

Explanation:

A contact lens with a +3.014 diopters power will enable a farsighted woman with a near point of 70.0 cm to see objects clearly at a distance of 27.3 cm.

We have do = 23cm and di = -75cm

So 1/f = 1/do + 1/di = 1/23 + 1/(-75) = .03014

So f = 1/.03014=33.17

So power = 1/0.3317 = +3.014Diopters (converging lens)

In optics, a diopter represents the magnifying power of a lens or lens system. The power of a lens is proportional to unity (one) divided by the focal length (see lens), so the power of a lens in diopters is mathematically equal to 1 meter is divided by the focal length. A healthy human eye can concentrate on an object or picture that is 1/40 of a meter away with an optical power of roughly 40 diopters. A average young person's eye has an additional 20 diopters of adjustment.

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The force exerted by one plate for two parallel plates arrangement is F = QE/2.

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

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To see a 3.2-times magnified virtual image of an object placed 4.7 cm from the mirror's vertex, you need to use a concave mirror with a focal length of -15.04 cm.

1. Determine the magnification required:

  The magnification, M, is given by the formula M = -v/u, where v is the image distance and u is the object distance. In this case, M = 3.2 (since the image is 3.2 times magnified).

2. Calculate the object distance:

  Given that the object is placed 4.7 cm from the mirror's vertex, we have u = -4.7 cm (negative sign denotes object distance in front of the mirror).

3. Calculate the image distance:

  Using the magnification formula, we can rearrange it as v = -M * u. Plugging in the values, we get v = -3.2 * (-4.7) cm = 15.04 cm.

4. Determine the focal length:

  For a concave mirror, the focal length, f, is half the radius of curvature (R). In this case, the mirror forms a virtual image, so the focal length is negative. Therefore, f = -R/2.

5. Calculate the radius of curvature:

  The mirror equation is given by 1/f = 1/v + 1/u. Plugging in the values for v and u, we can solve for f. 1/f = 1/15.04 + 1/(-4.7). Solving this equation gives f = -15.04 cm.

Thus, to see a 3.2-times magnified virtual image of an object placed 4.7 cm from the mirror's vertex, you need to use a concave mirror with a focal length of -15.04 cm.

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The triangular crest. shows the resulting wave when they cross at a point x. The meeting point of two waves is known as wave interference ia x.

A wave pulse is a short, non-periodic wave that is formed by a single energy input rather than a continuous or repeated energy input.

Wave interference is the result of multiple waves interacting. There are two types of interference: constructive and destructive.

The relative displacement of the waves is the difference between the two. Wave beats are frequently caused by wave interference.

Hence the triangular crest. shows the resulting wave when they cross at a point x.

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Answer:

B

Explanation:

Got it right on edge

1074022.08 tonnes/year is equivalent to 340 kmol/second assuming an average molar mass of 100 g/mol.

To convert 1074022.08 tonnes/year to kmol/second, we need to consider the molar mass of the substance involved. Since the question does not specify the substance, let's assume we are converting a substance with an average molar mass of 100 g/mol.

First, convert tonnes/year to kilograms/second by dividing by 31,536,000 (the number of seconds in a year). Thus, 1074022.08 tonnes/year is equivalent to 34 kg/s.

Next, convert kilograms to moles by dividing by the molar mass. In this case, dividing 34 kg/s by 0.1 kg/mol (since 100 g/mol is equivalent to 0.1 kg/mol) gives us 340 kmol/s.

1074022.08 tonnes/year is equivalent to 340 kmol/second when assuming an average molar mass of 100 g/mol.

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Answer:

From the figure,

The free-body diagrams for  and  are shown in the figures below. The only forces on the blocks are the upward tension  and the downward gravitational forces  and  . Applying Newton’s second law, we obtain:   

which can be solved to yield 

Substituting the result back, we have 

(a) With  and , the acceleration becomes   

(b) Similarly, the tension in the cord is   

To prove that rock layers in one area match rock layers found in another area, geologists use the principles of stratigraphy, including fossil, lithologic, and chemical correlation techniques.

One way to prove that rock layers in one area match rock layers found in another area is by using the principle of stratigraphy, which is the study of rock layers (strata) and their relationships. Geologists can use several techniques to correlate rock layers between different locations, including:

Fossil correlation: If a particular fossil is found in two different rock layers at different locations, it is a good indicator that the layers are of the same age. This is because certain fossils only existed during specific time periods, and so if the same fossil is found in two different rock layers, it can be inferred that those layers were deposited during the same time period.

Lithologic correlation: Rocks can have unique characteristics that allow geologists to match them to other rocks of the same type. For example, sandstone can have unique grain sizes or shapes that can help identify it as coming from a specific location.

Chemical correlation: Some rocks have unique chemical compositions that can be used to match them to other rocks of the same type. For example, volcanic rocks can have unique isotopic signatures that can help identify them as coming from a specific volcano.

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The density of water expressed in SI unit is 1000.3 kg/m³

Density is defined as the ratio of mass per unit volume.

where M is the mass of the object and V is the volume occupied by the object

As we know that 1 slug = 14.593 kg

So 1.94 slug = 1.94 × 14.593 kg

Also 1 ft³ = 0.0283 m³

On converting slug/ft³ to kg/m³

= (1.94 slug/ ft³) * (14.593/1 slug) * (1/0.0283 )

= 1000.3 kg/m³

Therefore the density in SI unit is 1000.3 kg/m³.

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Answer:

no such thing i dont think

Explanation:

Answer:

Polygraph tests are used to determine whether someone is lying or not, and display the physical signs someone is showing when they speak to be interpreted. Polygraphs measure things like heartbeat, breathing rate, and electrical conductivity of the skin, which are signs that get more and more severe when someone tells major lies or lies a lot. Polygraph tests are pretty unreliable because everyone shows different reactions to speaking depending on how anxious they are or any other medical condition, which could falsely incriminate them, but I think it is still important to determine the signs someone displays to use as a datapoint later on in the trial. For those reasons, they should still be used but shouldn't be relied on as heavily.

Explanation:

Answer:

The correction is the state of mind being for the Fahrenheit that is calculator from anarchy

Explanation:

Answer:

Si system is :kilo miligram kelvin

us system is: Fahrenheit Ounce yard inch

Explanation:

Answer:

4500N

Explanation:

Force =mass into acceleration

So 1500 into 3 you will get 4500

Answer:

I = 138.75N*s

Explanation:

I = F*t

I = Impulse or momentum

t = Time or duration

F = Force

I = 18,500N*0.0075s

I = 138.75N*s

Small stars have a longer and less dramatic life cycle than large stars. They gradually expand and cool as they run out of fuel, eventually becoming white dwarfs. Large stars, on the other hand, go through a more explosive and shorter life cycle, culminating in a supernova that can create neutron stars or black holes.

Small and large stars have different life cycles because they have different masses, which affects their gravitational forces and the fusion processes that occur in their cores.

Here's a comparison of their life cycles:

Small Stars:

Protostar: A cloud of gas and dust collapses under its own gravity, forming a dense, hot core.

Main Sequence: Nuclear fusion of hydrogen in the core produces energy, which counteracts the force of gravity and keeps the star stable. This phase can last for billions of years.

Large Stars:

Protostar: A cloud of gas and dust collapses under its own gravity, forming a dense, hot core.

Main Sequence: Nuclear fusion of hydrogen in the core produces energy, which counteracts the force of gravity and keeps the star stable. This phase can last for millions of years.

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Ridge push refers to the pressure exerted by the excess height of the mid-ocean ridge, while Slab pull refers to the force exerted by the weight of the subducted slab on the plate it is attached to.

The two forces that form mid-ocean ridges are ridge-push and slab pull.

Ridge push refers to the pressure exerted by the excess height of the mid-ocean ridge.

Slab pull refers to the force exerted by the weight of the subducted slab on the plate it is attached to.

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The coefficient of friction can be calculated by dividing the friction force by the normal reaction force. In this case, the coefficient of friction is 0.64.

Coefficient of friction (μ) is defined as the ratio of the frictional force to the normal reaction force. So, we can use the given formula,
Coefficient of friction (μ) = Frictional force (f)/Normal reaction force (N)

Calculate the friction force by dividing the normal reaction force by the coefficient of friction:
Friction force = Normal reaction force / Coefficient of friction
Friction force = 120 N / 0.64
Friction force = 77.4 N

Calculate the coefficient of friction by dividing the friction force by the normal reaction force:
Coefficient of friction = Friction force / Normal reaction force
Coefficient of friction = 77.4 N / 120 N
Coefficient of friction = 0.64


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Answer:

Systems always tend toward a state of decreasing order unless more energy is provided into the system to counteract this tendency.

Answer:

3

Explanation:

let the number be x

perform and forming expression

12 is added

=12 + x

4 is multiplied to expression

= 4 (12 + x)

result is 60

equating

4(12 + x) = 60

48 + 4x=60

4x = 60-48

4x = 12

x= 12/4

x= 3

The ball will be 246.12 meters away from the starting point at 12 seconds after it is kicked and the greatest height reached by the ball is approximately 20.81 meters.

A. To find where the ball will be at 12 seconds after it is kicked, we need to first break down the initial velocity into its horizontal and vertical components.

The horizontal component, Vx, can be found using the equation Vx = Vcos(theta), where V is the initial velocity (25 m/s) and theta is the angle of the kick (35 degrees).

Vx = 25 m/s * cos(35)

Vx = 20.51 m/s

The vertical component, Vy, can be found using the equation Vy = Vsin(theta).

Vy = 25 m/s * sin(35)

Vy = 14.26 m/s

We can then use the equation of motion to find the horizontal displacement, dx, after 12 seconds:

dx = Vx * t

dx = 20.51 m/s * 12 s

dx = 246.12 m

Therefore, the ball will be 246.12 meters away from the starting point at 12 seconds after it is kicked.

B. To find the greatest height reached by the ball, we can use the vertical component of the initial velocity, Vy, and the acceleration due to gravity, g, which is approximately 9.8 m/s².

We can use the following kinematic equation:

\(Vy^2 = V0y^2 + 2gh\)

where V0y is the initial vertical velocity (14.26 m/s) and h is the maximum height reached by the ball.

We can rearrange the equation to solve for h:

\(h = (Vy^2 - V0y^2) / 2g\)

\(h = (0 - 14.26^2) / (2 \times -9.8)\)

h = 20.81 m

Therefore, the greatest height reached by the ball is approximately 20.81 meters.

Summary: To find the position of the ball after 12 seconds and its maximum height, we first calculated the horizontal and vertical components of the initial velocity. Using the horizontal component, we calculated the horizontal displacement after 12 seconds.

Using the vertical component and the acceleration due to gravity, we calculated the maximum height reached by the ball. The ball will be 246.12 meters away from the starting point 12 seconds after it is kicked and it will reach a maximum height of approximately 20.81 meters.

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An equation relating the length that you measure l to the ship's proper length l0  is  

l =l0/y. This is further explained below.

Generally, Any object's length in a moving frame will look shortened or contracted when seen in that direction. The Lorentz transformation may be used to determine the amount of contraction.

In conclusion, To use the Lorentz Lorentz transformation, the length Lo-x2 - may be determined if it is measured in the moving reference frame. Hence the Resultant l = l0/y.

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The force exerted by the biceps and the elbow is 239.9 N and 215.89 N respectively.

When we use only your forearms to lift an object, assume that your biceps are the main muscle that lifts your arm. Suppose the weight of the forearm he is 1.50 kg. If the biceps is attached to the forearm 2.50cm from the elbow, with the forearm parallel to the floor, flex the biceps to hold a 950g ball on the end of the elbow at a distance of 36.0cm from the elbow.

Against this background,

forearm mass = 1.50 kg

forearm length = 2.50 cm

The weight of the ball is 950 g.

36.0 cm ball spacing

Forearm strength needs to be calculated. Balance Elbow Using

Torque,

Fb x Db = Wf x Df/2 + Wball x Dball

Putting Value,

Fb x .025 = 1.5 x 9.8 x .36/2 + 0

95 x 9.8 x 0.36

Fb = 239.9 N

Now elbow force,

Fb = Fl + Wf + Wb

Fl = Fb - Wf - Wb

Putting value,

Fl = 239 .9 - (1.5 x 9.8 ) - (0.95×9.8)

Fl = 215.89 N.

Therefore the force on the elbow is 215.89 N.

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