A frog of mass 0.5 kg jumps vertically upward with the initial velocity is (B) Pave = 2.5 W, Pinst = 0
The average power exerted by gravity on the frog from the start of the jump to its highest point (Pave),
Pave = ΔPE / Δt
where ΔPE is the change in potential energy and Δt is the change in time.
At the highest point of the frog's jump, its velocity will be momentarily zero. Therefore, the change in potential energy (ΔPE) can be calculated using the formula:
ΔPE = mgh
where m is the mass of the frog, g is the acceleration due to gravity, and h is the height.
Since the frog jumps vertically upward, the height reached is the maximum height of the jump.
h=(v²2) / (2g)
where v is the initial velocity of the frog.
Substituting the given values:
m = 0.5 kg
g = 10 m/s²2
v = 1.0 m/s
h = (1.0²2) / (2 × 10) = 0.05 m
The change in potential energy:
ΔPE = mgh = 0.5 × 10 ×0.05 = 0.25 J
Since the frog momentarily stops at the highest point, the change in time (Δt) can be considered as the time taken to reach the highest point, which can be calculated using:
Δt = v / g
Substituting the values:
Δt = 1.0 / 10 = 0.1 s
The average power:
Pave = ΔPE / Δt = 0.25 / 0.1 = 2.5 W
Therefore, the correct answer is (B) Pave = 2.5 W.
Now let's determine the instantaneous power exerted by gravity on the frog at the highest point (Pinst). Instantaneous power is the power at a specific instant, which can be calculated using the formula:
Pinst = F ×v
where F is the force and v is the velocity.
The force acting on the frog at the highest point is the gravitational force, given by:
F = mg
Substituting the values:
F = 0.5 ×10 = 5 N
Since the frog momentarily stops, its velocity is zero.
Pinst = F ×v = 5 × 0 = 0 W
Therefore, the correct answer is (B) Pinst = 0.
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A seal swims toward an inlet with a speed of 7.0 m/s as a current of 1.5 m/s
flows in the opposite direction. How long will it take the seal to swim
120. m?
Answer:
scees 3
Explanation:
fd4cesv 3sce3bd. s3 s3vd3 ze ze 4s d4 zr s3 d4
pls help documents are attached
Answer: do you need a essay for it? also i need a close up!!
Explanation:
The experimental setup shown in the picture has a fixed ramp and an adjustable ramp. Students roll a ball down the fixed ramp and measure how far up the adjustable ramp the ball travels. During
the experiment, they change the slope of the adjustable ramp and record their data in the table
1
8) The students concluded that the lower the slope of the adjustable ramp, the greater the distance the ball continued to roll. What other conclusion can also be drawn from the findings?
A) The ball stops because there is some force acting on it
B) The only force acting on the ball during its journey is gravity
The ball stops eventually because there is no force acting on it
D) The slope of the ramp has no role to play in the stopping of the ball
A. Another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.
What are the forces acting on an object moving on inclined plane?There are several forces that will act on an object moving on an inclined plane. These forces include the following;
gravitational forcefrictional forceapplied forceWhen the object is moving up, gravitational force will tend to pull the object downwards and the frictional force will tend to oppose this downward motion of the object.
When the object is rolled down the plane, gravitational force tends to aid the motion of the object while frictional force tends to slow the object down.
Eventually, the object stops because the frictional force opposing the object motion is greater than the gravitational force pushing the object downwards.
Thus, another conclusion that can be drawn from the student experiment is the ball stops because there is some force acting on it.
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Which of the following is a cue used by artists to convey depth on a flat canvas? a. interposition b. proximity c. closure d. continuity.
The correct answer to your question is a. interposition. Interposition is a cue used by artists to convey depth on a flat canvas. In this technique, artists place objects in front of one another to create the illusion of depth and distance. This method helps to suggest that some objects are closer to the viewer, while others are further away
One of the cues that artists use to convey depth on a flat canvas is interposition. This refers to objects in the foreground overlapping those in the background, creating a sense of depth and distance. Other cues that artists may use include proximity, which is the placement of objects in relation to each other, and continuity, which refers to the smooth flow of lines and shapes. Closure, on the other hand, is the ability of the viewer to mentally complete incomplete shapes or patterns, and is not necessarily related to depth perception. Overall, artists use a variety of techniques and cues to create the illusion of depth on a two-dimensional canvas, and these skills are essential to creating engaging and realistic works of art.
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Are yall a Furry like me, if so what is you fursoina
Answer:nvm
Explanation:
Answer:
A furry and they cant spell god
Explanation:
What is the change of state when magma crystallises to form igneous rock?
Answer:
liquid
Explanation:
due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock
Please help! I'm begging anyone! This is urgent! These are the problems in physics I am having difficulty with!
1) While helping a friend move, you lift a 189 N box full of books and perform 174 J of work to do so. What distance, directly upward, do you lift the box? Show all of your work.
2) A bungee jumper with a weight of 613 N leaps off a bridge. He is in free fall for a distance of 22.6 m before the cord begins to stretch. How much work, in kilojoules, does the force of gravity do on the jumper before the cord begins to stretch? Show all of your work.
3) You and your neighbor are shoveling snow. If your neighbor pushes a shovel four times as far as you do, but exerts only half the force, which one of you does more work and by how much? Show all of your work.
Answer:
1.
Distance = 0.921 meters
2.
Work = 13.9 kJ
3.
The neighbor
Double your work
Explanation:
1.
Work = Force × Distance
Distance = Work / Force
Distance = 174J /189 N
Distance = 0.921 meters
2.
Work = force × distance
Work = (613 N) (22.6 m)
Work = 13,900 J
Work = 13.9 kJ
3.
Work is a product of force and distance, expressed as W=Fd where W is work in Nm, F is applied force and d is the distance in m
Since your neighbor pushes 4 times then you just push 1m when he pushes 4m, that is an example. Also, since the neighbor only exerts half the force i.e. 0.5N then you exert full force of 1N
Work from your neighbor will be 4d*0.5F=2dF
Work from you will be dF
Clearly, 2dF=2(dF) hence the neighbor exerts double work
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Someone draw me a Rube Goldberg Machine.
Displacement includes both distance and direction.
a. true
b. false
Answer:
True
Explanation:
Displacement can be considered as a distance with direction when an object moves in straight line. Distance is a scalar quantity which means it has only magnitude but lack of direction. Magnitude basically means how far or how long from the initial startup (e.g 7 km) is magnitude.
On the other hand, displacement is a vector quantity which means it has both magnitude and direction. We can use a symbol of negative and positive to determine the direction. Generally, up is positive; down is negative; west is negative and east is positive but it depends on some case where down can be positive (e.g projectile motion) but you can specify or modify how you want your direction to be, make sure to calculate it right though.
Displacement means changes in position which can be expressed as \(\displaystyle{p_2 -p_1}\) where \(\displaystyle{p_2}\) is final position/destination and \(\displaystyle{p_1}\) is initial position/destination. Displacement does include distance but maybe not total distance if we go for a right-triangle distance. However, displacement includes total distance if an object moves in a straight point. (e.g moving to 20 km straight) - both distance and displacement are same in this case.
A 15kg object is travelling 10m/s and hit a stationary 10kg object and stuck together. What is the final velocity of the objects?
Answer:
first object final velocity =2m/s
second = 12m/s
Explanation:
i hope this will help you,..,
An engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring. He can only make one adjustment to the initial conditions of the car. Which of the following modifications to the car design would have the greatest effect on increasing the kinetic energy of the car?
A. Decrease the mass of the car slightly.
B. Increase the mass of the car slightly.
C. Decrease the launch speed of the car slightly.
D. Increase the weight of the car slightly.
The modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly (option B).
What is kinetic energy?Kinetic energy is the energy possessed by an object because of its motion. The kinetic energy equal (nonrelativistically) to one half the mass of the body times the square of its speed.
According to this question, an engineer is designing a small toy car that will be launched from rest. The engineer wants to maximize the kinetic energy of the car when it is launched by a compressed spring.
However, he can only make one adjustment to the initial conditions of the car. Considering the fact that the mass of an object is directly proportional to the kinetic energy.
This suggests that the modifications to the car design that would have the greatest effect on increasing the kinetic energy of the car is to increase the mass of the car slightly.
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A star is observed to have an apparent brightness which is 10⁻⁴ times its absolute brightness. How far away is it?
The star is located at a distance of 31.62 parsecs from us.
To determine the distance of the star, we need to use the inverse square law, which states that the apparent brightness of a star decreases as the square of its distance increases. Mathematically, it can be represented as:
Apparent brightness ∝ 1/Distance²
Given that the star's apparent brightness is 10⁻⁴ times its absolute brightness, we can write:
Apparent brightness = Absolute brightness/ (Distance)²
10⁻⁴ = Absolute brightness/ (Distance)²
Solving for distance, we get:
Distance = √(Absolute brightness/10⁻⁴)
However, we don't have the value of absolute brightness. But we can use the information that the star is observed to have an apparent magnitude of 10. Since apparent magnitude is a logarithmic scale, we know that a difference of 5 magnitudes corresponds to a difference of 100 times in brightness. Therefore, the star's absolute magnitude can be calculated as:
Absolute magnitude = Apparent magnitude - 5 log(distance/10)
Substituting the values, we get:
10 = Absolute magnitude - 5 log(distance/10)
Absolute magnitude = 10 + 5 log(10⁻⁴) = 14
Therefore, the distance can be calculated as:
Distance = 10^(1+((Apparent magnitude - Absolute magnitude)/5))
= 10^(1+((10 - 14)/5))
= 31.62 parsecs
Thus, the star is located at a distance of 31.62 parsecs from us.
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1. What is the role of the battery in an electric circuit? a. Transformer b. Conductor c. Source d. switch
Answer:
Conductor
Explanation:
A battery holds all of the energy in itself. So without the battery, the circuit cannot work.
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An incline plane is 12-m long and 4-m high. A block is pulled up the ramp with a spring scale. The reading on the spring scale is 70-N. How many Newtons would the block actually weigh if you had to lift it the 4-m height?
Answer:
W = 210 N
Explanation:
For an ideal machine:
\(Work\ In = Work\ Out\\(P)(L)=(W)(H)\)
where,
P = Effort = Spring Scale Reading = 70 N
L = Effort Arm = Length of inclined plane = 12 m
W = Actual Load (Weight) to be lifted = ?
H = Load Arm = Height = 4 m
Therefore,
\((70\ N)(12\ m) = (W)(4\ m)\\\\W = \frac{(70\ N)(12\ m)}{4\ m}\)
W = 210 N
What is the maximum number of electrons any orbital can hold?.
Answer:
2n^2
Explanation:
depends on n
if first orboit n = 1
and so on
nere -9dixinjakc
infses ADM What is the andular speed in raifiantinec? tadiansranc
The answer to the given question is indeterminate or cannot be calculated.Sometimes the question may contain spelling errors or typos that make it difficult to understand. In such a case, it is best to double-check the question before attempting to answer it.
The given question, "What is the angular speed in radians per second?" can be solved using the formula for angular speed.
Angular speed is defined as the rate of change of angular displacement with respect to time. The angular speed is usually denoted by the Greek letter omega, ω.
The formula for angular speed, ω is given by;ω = Δθ/Δt
where,Δθ = change in angular displacement
Δt = change in time
Since there are no values for Δθ and Δt given in the question, we cannot solve the angular speed.
Therefore, The response to the query is ambiguous or impossible to calculate.Sometimes the question may have grammatical or spelling problems that make it challenging to understand. In this situation, it is best to confirm the question before attempting to respond to it.
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Astronomers have not yet been able to detect planets outside our solar system. true false
Solve it pleaseeeeeeeee
The force exerted to push the 25 Kg wooden box across the wooden floor at a constant speed of 1.0 m/s is 49 N (2nd option)
How do i determine the force exerted?Frictional force is given by the following formula
Frictional force = coefficient of friction (μ) × normal reaction (N)
Since the speed is constant,
Frictional force = Force exerted
Thus,
Force exerted = coefficient of friction (μ) × normal reaction (N)
F = μN
Now, we shall determine the force exerted to push the box. Details below:
Mass of box (m) = 25 KgCoefficient of friction (μ) = 0.2Acceleration due to gravity (g) = 9.8 m/s² Normal reaction (N) = mg = 25 × 9.8 = 245 NForce exerted (F) =?F = μN
F = 0.2× 245
F = 49 N
Thus, the force exerted to push the box is 49 N (2nd option)
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Alkaline earth metals have a low density
true
false
true
Explanation:
this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons
Calculate the volume of 500 kilograms
to 2 decimal places
flead if the density of lead is 11400 kg/m². Give your answer
Enter your answer to 2 decimal places
Answer:
d (density) = M / V
V = M / d = 500 kg / (11400 kg / m^2 = .044 m^3
A block of mass 1kg is placed on an inclined plane at an angle of 30° to the horizontal. Calculate the frictional force, normal reaction, the coefficient of the static friction
Question:
A block of mass 1kg is placed on an inclined plane at an angle of 30° to the horizontal. Calculate the frictional force, normal reaction, the coefficient of the static friction
Answer:
Break the mg force into components in the plane of the inclined plank. Now force acting parallel is mgsin37°. Perpendicular force is mgcos37° which is equal to normal force.
Now calculate max value of friction force which is 0.8*mg cos37°. Since its greater than pulling force mgsin37°, the body will be at rest and acceleration is zero.
Force applied by surface is vector sum of normal force and friction force acting.
Like all planets, the planet Venus orbits the Sun in periodic motion and simultaneously spins about its axis. Just as on Earth, the time to make one complete orbit (i.e., the period of orbit) is what defines a year. And the time to make one complete revolution about its axis (i.e., the period of rotation) is what defines a day. The period of orbit for the Earth is 365.25 days and the period of rotation is 24 hours (1.00 day). But when these same values for Venus are expressed relative to Earth, it is found that Venus has a period of orbit of 225 days and a period of rotation of 243 days. So for Venus inhabitants, a day would last longer than a year! Determine the frequency of orbit and the frequency of rotation (in Hertz) on Venus. Ans: A marine weather station detects waves which are 9.28 meters long and 1.65 meters high and travel a distance of 50.0 meters in 21.8 seconds. Determine the speed and the frequency of these waves. Ans:
Answer:
a) F = 5.14 10⁻⁸ Hz, f = 4.76 10-8 Hz, b) v = 2.29 m / s, f = 42.5 Hz
Explanation:
a)This problem has two parts.
For the calculations relative to the planet Venus, we use that the period and the frequency are related
f = 1 / T
frequency of the orbit around the Sun
Let's reduce the period to the SI system
T = 225 days (24h / 1days) (3600 s / 1h) = 1.94 10⁷ s
F = 1 / 1.94 10⁷
F = 5.14 10⁻⁸ Hz
rotation frequency
T = 243 d = 2.1 107 s
f = 1 / T
f = 1 / 2.1 107
f = 4.76 10-8 Hz
b) give the data of some marine waves
the speed of the wave can be found with kinematics
v = x / t
v = 50.0 / 21.8
v = 2.29 m / s
If the wavelength is L = 9.28m
this distance is the distance between two consecutive ridges or valleys
λ / 2 = L
λ = 2L
λ = 2 9.28
λ = 18.56 m
the speed of the wave is
v = λ f
f = v /λ
f = 2.29 / 18.56
f = 42.5 Hz
what is refraction and reflection
Answer:
Reflection is simply the property of a light that rebounds or bounces back after hitting a surface.
Refraction is when the light, which passes through a surface, undergoes some changes in appearance whenever it usually passes through a medium.
HELP ME PLSSSS PLSSS PLSSSS
Answer:
Its upside down
Explanation:
I recommend asking a teacher for help
Please help!!!
Layne walked 1200m E to get her lunch. If it took her 25s to go get it
What is her average speed?
What is her average velocity?
Answer:
48
Explanation:
you basically divide 1200 into 25
How far must I compress a spring with spring constant 573N/m to produce a force of 184N? Express your answer to the nearest hundredth
compressed0.32 meters
Explanation
Step 1
The force exerted by a spring on objects attached to its ends is proportional to the spring's change in length away from its equilibrium length and is always directed towards its equilibrium position.
\(F=-kx.\)so
let
\(\begin{gathered} k=573\text{ }\frac{\text{N}}{m} \\ F=184\text{ N} \end{gathered}\)replace and solve for x
\(\begin{gathered} F=-kx \\ 184=-573\frac{N}{m}\cdot x \\ divide\text{ both sides by 573 N/m} \\ \frac{184}{-573\frac{N}{m}}=\frac{-573\frac{N}{m}\cdot x}{-573\frac{N}{m}} \\ -0.32\text{ m=x} \end{gathered}\)the negative symbol indicates the spring is compresed
so, the answer is
0.32 meters
I hope this helps you
What are Prevailing Westerlies? a Calm area with rising air b Wind blowing West to East away from horse latitudes c Wind blowing East to west away from horse latitudes d Air being blown away from the poles
Answer:
b Wind blowing West to East away from horse latitudes
Explanation: prevailing Westerlies are winds which blows away from the horse latitudes, this type of wind blow towards the poles between latitude 30 degrees to latitude 60degrees.
Prevailing Westerlies are known to be strongest in the winter months in the and weakest in the summer months
They are also very strong when the pressures are low over the poles and also very weak when the pressures are high over the poles.
Which of the following statements about peer pressure is TRUE?
A) Peer pressure is saying “no” and meaning it.
B) Peer pressure is the pressure to go along with the behavior and beliefs of your friends.
C) Peer pressure encourages people to do things they know are wrong.
D) Peer pressure is the pressure to do something dangerous.
Answer:
B because I remember that's what peer pressure is
Answer:
C
Explanation:
I think it is C because peer pressure is doing something you don't want to do and you think it is wrong to do that, but it could aslo be B.
FAILURE OF THE PRODUCT Instructions 1. Select THREE from everyday below items from the list and discuss the way this item can potentially fail (list minimum THREE failures). Justify your answer by considering Load Strength graph and what can be done to prevent those failures. -Ball Pen -Room Key - Blender
The three product which can be potentially fail considering Load Strength graph and precautionary measure to prevent failure are as below;
Ball Pen:
1. Ink Leakage: One potential failure of a ball pen is ink leakage. This can occur due to poor sealing between the ink reservoir and the ballpoint mechanism. Ink leakage can result in messy hands, stained documents, and reduced functionality of the pen. To prevent this failure, manufacturers can improve the quality control process to ensure proper sealing and use high-quality materials for the pen's components.
2. Ballpoint Jamming: Another failure is ballpoint jamming, where the ball gets stuck and prevents smooth writing. This can be caused by a buildup of dried ink or debris inside the pen's mechanism. To prevent ballpoint jamming, regular cleaning and maintenance of the pen can be recommended. Additionally, manufacturers can design the pen with features that facilitate easy cleaning or provide instructions on how to clear any blockages.
3. Weak Barrel Construction: The barrel of the pen may also be prone to failure if it is weak or brittle. Excessive pressure or rough handling can lead to cracks or breakage, rendering the pen unusable. To prevent this, manufacturers can use durable materials for the pen barrel, such as sturdy plastics or reinforced metal, and perform quality checks to ensure structural integrity.
Room Key:
1. Keycard Malfunction: A potential failure of a room key is a malfunction in its electronic components. This can result in the keycard being unreadable by the door lock system, preventing access to the room. To prevent this failure, regular maintenance and replacement of keycard readers can be implemented. Additionally, guests should be advised to keep their keycards away from magnets and electronic devices that can interfere with the card's functionality.
2. Magnetic Strip Damage: Another failure can occur if the magnetic strip on the keycard gets damaged or demagnetized. This can happen due to exposure to magnetic fields or physical damage. To prevent this failure, keycards can be made more durable with protective coatings or alternative technologies such as RFID. Guests should also be educated on proper handling and storage of keycards to avoid damage.
3. Battery Drain: Some room keys use batteries to power their electronic components. A failure can occur if the battery drains, leading to an inactive keycard. To prevent this, low-power consumption designs can be implemented, and regular battery checks or replacements can be carried out by hotel staff. Guests should be informed about the importance of returning the keycard to the front desk for recycling or proper disposal to ensure the battery is replaced as needed.
Blender:
1. Motor Burnout: One potential failure of a blender is motor burnout due to prolonged use or overloading. Continuous operation at high speeds or attempting to blend hard or frozen ingredients beyond the blender's capacity can cause the motor to overheat and fail. To prevent motor burnout, manufacturers can provide clear guidelines on the maximum load capacity and recommended usage durations. Automatic thermal protection mechanisms can also be incorporated to shut off the blender if it detects excessive heat.
2. Blade Jamming: Another failure can occur if food particles or ingredients get jammed between the blender's blades, preventing them from spinning freely. This can happen if the blender is not properly cleaned or if ingredients are not adequately prepared before blending. To prevent blade jamming, users should be advised to clean the blender thoroughly after each use and ensure that ingredients are cut into manageable sizes. Manufacturers can also design blades with accessible mechanisms for easy cleaning or provide cleaning tools.
3. Leakage: A failure in a blender can also manifest as leakage. This can happen if the blender jar or its sealing components are damaged or improperly assembled. Liquid or food can leak out during blending, resulting in a messy and potentially unsafe situation. To prevent leakage, manufacturers should ensure proper sealing mechanisms and use high-quality materials for the blender jar and lid. Regular inspection of the sealing components can be advised,
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Could society survive without energy transformations? Explain your reasoning.