a gas is compressed from 600 cm3cm3 to 200 cm3cm3 at a constant pressure of 400 kpakpa. at the same time, 400 jj of heat energy is transferred out of the gas. for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of fire piston. part a what is the change in thermal energy of the gas during this process? express your answer with the appropriate units.
Answers
The change in thermal energy of the gas during this process is -240 J (negative indicates a decrease in thermal energy).
ΔE = q - PΔV
Where:
ΔE is the change in thermal energy
q is the heat energy transferred out of the gas
P is the constant pressure
ΔV is the change in volume
Given:
q = -400 J (heat energy transferred out of the gas)
P = 400 kPa (constant pressure)
ΔV = V2 - V1 = 200 cm^3 - 600 cm^3 = -400 cm^3 (negative because the volume decreases)
Note: It's important to convert the units to a consistent system. In this case, we'll convert cm^3 to m^3 and kPa to Pa.
1 cm^3 = 1 x 10^-6 m^3
1 kPa = 1000 Pa
Converting the units:
ΔV = -400 cm^3 = -400 x 10^-6 m^3 = -0.0004 m^3
P = 400 kPa = 400 x 1000 Pa = 400,000 Pa
Now we can calculate the change in thermal energy:
ΔE = q - PΔV
= -400 J - (400,000 Pa) x (-0.0004 m^3)
= -400 J - (-160 J)
= -400 J + 160 J
= -240 J
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Related Questions
Sue wanted to know the mass of her earrings. She put them on a balance and added two 50 g weights, one 10 g weight, and three 1 g weights so that the balance was even. What was the mass of her earrings?  A. 120 g  B. 100 g  C. 140 g  D. 113 g
Answers
Answer:
113 grams
Explanation:
She put them on a balance and added two 50 g weights, one 10 g weight, and three 1 g weights so that the balance was even.
Two 50 g weights = 100 g
One 10 g weight = 10 g
Three 1 g weights = 3 g
Total weight = 100 g + 10 g + 3 g
= 113 g
So, the mass of her earrings is 113 grams.
how would sunspots appear if you could magically remove them from the sun?
Answers
If we could magically remove sunspots from the sun, it would appear smoother and more uniform in its brightness. Sunspots are darker, cooler regions on the sun's surface caused by magnetic activity, which creates areas of intense magnetic fields that suppress the movement of heat and gas.
Removing sunspots would affect the sun's overall magnetic field, which could potentially impact the sun's activity and influence space weather. Sunspots are closely related to solar flares and coronal mass ejections, which can cause disruptions in communication and navigation systems on Earth.
However, it is important to note that sunspots are a natural occurrence of the sun and play a significant role in regulating the sun's temperature and energy output. Removing them could have unintended consequences and may not be a practical solution.
Instead, scientists study sunspots to better understand the sun's behavior and predict potential space weather events. They use tools such as the Solar Dynamics Observatory to monitor the sun's activity and gather data that can inform space weather forecasts and help protect our technological infrastructure.
In conclusion, while removing sunspots may seem like a solution, it is important to consider the potential consequences and the valuable role they play in our understanding and management of the sun's behavior.
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what makes astronomers think that cygnus x-1 contains a black hole? (a) we can directly observe that one member of the system emits no light. (b) the unseen object orbited by a luminous star is too massive to be a neutron star. (c) the strong x-ray emission from the system means it must contain a black hole.
Answers
Astronomers think that cygnus x-1 contains a black hole because the unseen object orbited by a luminous star is too massive to be a neutron star and is therefore denoted as option B.
Who is an Astronomer?This is referred to as a type of scientists who studies the Universe and the objects within and around it.
Cygnus x-1 is referred to as a galactic X-ray source in the constellation Cygnus and was widely accepted to be a black hole as a result of the unseen object orbited by a luminous star is too massive to be a neutron star.
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To cause a 25 kg object to experience an acceleration of 2 m/s2 the net force that needs to be applied to the object is
Answers
Answer:
50 N
Explanation:
Remember:
F = m * a
= 25 * 2 = 50 N
The Round Up carnival ride below has a radius of 3.62 meters and rotates 0.537 times per second. As shown, riders can be held up by only friction. What coefficient of friction is needed to keep the riders from sliding down? Include units in your answer. Answer must be in 3 significant digits.
Answers
The free body diagram for the problem is shown below:
If the people don't slide down this means that the friction has to be equal to the Weight, then we have:
\(\begin{gathered} F_f-W=0 \\ F_f=W \\ \mu F_n=W \\ \mu=\frac{W}{F_n} \end{gathered}\)Now, from newton's second law we have that:
\(F_n=ma_c\)but
\(a_c=\frac{4\pi^2r}{T^2}\)then:
\(F_n=\frac{4\pi^2mr}{T^2}\)And then we have:
\(\begin{gathered} \mu=\frac{mg}{\frac{4\pi^2mr}{T^2}} \\ \mu=\frac{gT^2}{4\pi^2r} \end{gathered}\)Plugging the values given we have:
\(\begin{gathered} \mu=\frac{(9.8)(\frac{1}{0.537})^2}{4\pi^2(3.62)} \\ \mu=0.238 \end{gathered}\)Therefore the coefficient of friction is 0.238
The frame of reference for an outside observer of a moving
bus might be a house across the street.
-TRUE
-FALSE
Answers
Answer:
false
Explanation:
Which of the following energies defines energy stored inside a spring?
A. Gravitational Potential
B. Elastic potential
C. Kinetic
Answers
Answer:
Elastic potential energy
The continuity equation shows that the ratio of fluid velocities within different openings is inversely proportional to the cross-sectional areas of those openings. Provide one example where this might be useful for finding differences in areas after measuring velocities, or in finding differences in velocities after measuring areas. Describe your example in detail making sure to talk about the different variables involved.
Answers
Answer:
A typical example of where the continuity equation can be applied, is in finding the cross sectional area of a laminar falling stream of water from a pipe at an elevation, at the point where it hits the ground.
The speed of the water through the discharge opening of the pipe can be measured with a flow-meter, and the cross sectional opening of the pipe is known.
As the water leaves the pipe, and falls towards the ground, the water stream is accelerated under gravity, and the speed of the water stream increase. The increase in the speed of the water stream causes the cross sectional area to decrease in obedience of the continuity law and equation. If the speed of can be measured, then the area of the water stream just before the water touches the ground can be calculated from the continuity equation.
If the speed of the water stream can not be measured, then it can be calculated using Newton' equation of motion
\(v^{2} = u^{2} + 2gz\)
\(v = \sqrt{u^{2} + 2gz}\)
where
v = the velocity of the water stream at the point where it hits the ground
u = the velocity of the water at the pipe discharge (measured with a flow meter in the pipe)
g = acceleration due to gravity
z = the elevation of the pipe above the ground.
After calculating the speed of the water stream at the point where it hits the ground, the cross sectional area of the the stream can be calculated from the continuity equation.
\(uA = va\)
where
u and v are the velocities of the water stream at the pipe discharge and at the ground respectively.
A = the cross sectional area of the pipe
a = the area of the water stream before it hits the ground.
the equation is simplified as
\(a = \frac{uA}{v}\)
Evan drives a golf ball with an initial velocity of 49 meters per second at an angle of 16 degrees own a flat driving range. How far will the golf ball land?
Answers
Answer:
solusion Explanation:the answer in 984tha
. summarize what you found out about the charge (q) and the potential difference (v) for capacitors connected in series. write two equations to show the relations.
Answers
The summarize about the charge (q) and the potential difference (v) for capacitors connected in series are related in the following ways:
The charge (q) on each capacitor in a series is the same. The potential difference (v) across each capacitor in a series is different. The two equations that show these relations are:q = q1 = q2 = q3 = ... = qn V = V1 + V2 + V3 + ... + Vn
The charge (q) on each capacitor in a series is the same because the charge on one plate of a capacitor must be equal and opposite to the charge on the other plate, and in a series circuit, the charge has nowhere else to go but to the next capacitor.
The potential difference (v) across each capacitor in a series is different because the total potential difference across the series is equal to the sum of the potential differences across each individual capacitor.
For the equations above:
where q is the charge on each capacitor and q1, q2, q3, ... , qn are the charges on the individual capacitors in the series)where V is the total potential difference across the series and V1, V2, V3, ... , Vn are the potential differences across the individual capacitors in the seriesFor more information about potential difference refers to the link: https://brainly.com/question/12198573
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Work, Power, and Energy
A 3 kg ball falls from a height of 45 meters to a height of 32 meters. Calculate the amount of work done by gravity.
When writing your answer, please include the formula you used! Thank you!
Answers
Answer:
383.2
Explanation:
W=m×g(9.8)×(change in height)
=3×9.8× (45-32)
=3×9.8×13
=383.2
why is one year on earth 365 days but one year on mercury 88 days
Answers
Suggest a reason why the cell is switched off between measurements for the practical determining emf and internal resistance of a cell.
Answers
Answer:
Explanation:
One possible reason for switching off the cell between measurements when determining its electromotive force (emf) and internal resistance is to prevent any external influences or interference during the measurement process. Here's a more detailed explanation:
Minimizing external factors: Switching off the cell during measurements helps minimize the impact of external factors such as electromagnetic fields, stray currents, or fluctuations in the power supply. These external factors can introduce noise or errors into the measurements, making it difficult to obtain accurate results.
Avoiding self-discharge: Some types of cells, particularly rechargeable batteries, have a tendency to self-discharge over time, even when not in use. By switching off the cell between measurements, you can reduce the self-discharge rate and ensure that the cell's energy remains relatively stable throughout the measurement process. This helps maintain consistent and reliable readings.
Preserving battery life: If the cell being measured is not rechargeable or has limited capacity, switching it off between measurements helps conserve its energy. Constantly leaving the cell connected or in an active state could drain its power unnecessarily, leading to a shorter overall lifespan or the need for more frequent replacements.
Eliminating circuit effects: When a cell is connected to a circuit, it interacts with the circuit's components, including wires, resistors, and other elements. These interactions can affect the cell's behavior and introduce additional resistance into the circuit, potentially leading to inaccuracies in the measurement of the cell's internal resistance. By disconnecting the cell between measurements, you can isolate it from the circuit and obtain more precise results.
You use a rope and pulley system with an ideal mechanical advantage of 2.00. How big of an output load can you lift with an input
force of 200 N?
Answers
When two rope segments pull up on the load in the single movable pulley, the optimal mechanical advantage is 2. This sort of pulley does not change the direction of the applied force, but it does increase it by a factor of two.
What is the ideal mechanical advantage?There are two methods for calculating a pulley system's mechanical advantage.
The mechanical advantage may be calculated simply by counting the number of falls (or active lifting ropes) that are really attached to the load. You may also split the effort distance by the load distance.
Assuming an ideal rope and pulley system with a mechanical advantage of \(2.00\) , the output load that can be lifted with an input force of \(200 N\) can be calculated using the formula:
Output force = Input force x Mechanical advantage
Where the mechanical advantage is given as \(2.00\) .
Thus, the output force is:
Output force \(= 200 N \times 2.00 = 400 N\)
Therefore, with an input force of \(200 N\) , the rope and pulley system can lift an output load of up to \(400 N\) .
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In your own words explain why the thickness and length of a wire could effect the flow of electrons
Answers
Answer:
(you can use my exact words) The length and thickness would make it so that the electrons move differently than they would a shorter and thinner wire because with the wire being longer the electrons would have a longer trip and with the wire being thicker the electrons would be more spread out and move be able to move more freely
What generally happens when a comet nears the sun?
A
It freezes.
B
Its gas burns up
С
It becomes an asteroid.
D
It becomes a meteorite.
Answers
It's probably B or A
Answer:
B: its gas burns up
Explanation:
Because when it close to the sun it burns it gas of how hot the sun is.
15. A 0.500-kg mass suspended from a spring oscillates with a period of 1.50 s. How much mass must be added to the object to change the period to 2.00 s?
The answer is 0.389 kg but please show your work.
Answers
Let's look at relationship
\(\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{m}{k}}\)
\(\\ \rm\rightarrowtail T\propto \sqrt{m}\)
Hence
\(\\ \rm\rightarrowtail \dfrac{T_1}{T_2}=\sqrt{\dfrac{m1}{m2}}\)
\(\\ \rm\rightarrowtail \dfrac{1.5}{2}=\sqrt{\dfrac{0.5}{m2}}\)
\(\\ \rm\rightarrowtail 0.75^2=\dfrac{0.5}{m2}\)
\(\\ \rm\rightarrowtail m_2=\dfrac{0.5}{0.75^2}\)
\(\\ \rm\rightarrowtail m_2=0.889\)
Hence
Mass needs to added =0.889-0.500=0.389kgAnswer
Mass needs to added =0.889-0.500=0.389kg
Explanation:
Which statement describes an example of constructive interference?
A. Two TV signals reach an antenna and cancel each other out.
B. A cell-phone signal is lost when you pass through a certain area.
C. oil spilled in a water puddle shows different colors of light.
D. Light forms bars on a surface after passing through two slits.
Answers
Light that has passed through two slits and formed bars on a surface is an example of constructive interference.
Which of the following describes constructive interference?Constructive interference is the phenomenon where the total amplitude of two waves is equal to the sum of their separate amplitudes when two waves are in phase and their maxima add.
What is two-wave constructive interference?A single amplitude equal to the sum of the individual wave amplitudes is produced by the mutual reinforcement of two or more waves of similar frequency and phase during constructive interference. Phase differences between waves must be zero for constructive interference to occur.
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What is the define the newton
Answers
The Newton is a unit of force in the International System of Units (SI). It is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared.
In other words, one Newton is equal to the amount of force needed to move a one-kilogram object one meter in one second. Newton is named after Sir Isaac Newton, a famous physicist, and mathematician who is known for his laws of motion and the law of universal gravitation. In mathematical terms, one Newton is equal to one-kilogram meter per second squared (1 N = 1 kg m/s^2).
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Starting from rest, you pushed a 10.0 kg lawnmower a distance of 25 meters by applying a force of 75 N at an angle 35 degrees below horizontal, as shown below. Use work and energy principles to calculate how fast the lawn mower is moving (in m/s) at the end of the 25 meters.
Answers
The lawn mower is moving with a velocity of 17.53 m/s
Energy is the ability to do work while Work is defined as the product of force and distance moved in the direction of the force. Both work and energy are measured in Joule (J)
Work = Force (F) × distance (d) = FdCosθ
With the above formula, we can obtain the energy used in pushing the lawn mower as illustrated below
From the question given above, the following data were obtained:
•Force (F) = 75 N
•Distance (d) = 25 m
•Angle (θ) = 35°
•Energy (E) =?
E = FdCosθ
E = 75 × 25 × Cos 35
E = 1535.91 J
Definition and Determination of the velocityVelocity is the rate of change of displacement with time.
Velocity and energy are related according to the following equation:
E = ½ × mass (m) × square velocity (v²)
E = ½mv²
With the above formula, we can obtain the velocity of the lawn mower as follow
•Mass (m) = 10 Kg
•Energy (E) = 1535.91 J
•Velocity (v) =?
E = ½mv²
1535.91 = ½ × 10 × v²
1535.91 = 5 × v²
Divide both side by 5
v² = 1535.91 / 5
Take the square root of both side
v = √(1535.91 / 5)
v = 17.53 m/s
Thus, the lawn mower is moving with a velocity of 17.53 m/s
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The diagram at right shows the shadow PQ that is cast onto a wall by a six-foot person AB, who is illuminated by a spotlight on the ground at L. The distance from the light to the wall is LP = 50 feet, and the distance from the light to the person is LA-, a variable quantity. The length of the shadow depends on x, so call it S() (a) Use geometry to find an explicit formula for S() (b) For what values of r does S(x) make sense? (In other words, find the domain of S.) (
Answers
The component form of the velocity of the airplane is (-102.9 km/hr, 280.7 km/hr). This means the airplane is moving approximately 102.9 km/hr to the west and 280.7 km/hr to the north.
To find the component form of the velocity of the airplane, we need to break down the given velocity into its horizontal and vertical components.
Given that the airplane is traveling at a speed of 300 km/hr in the direction 20° west of north, we can represent this velocity as follows:
Magnitude of the velocity = 300 km/hr
Direction of the velocity = 20° west of north
To find the horizontal component, we need to determine the projection of the velocity vector onto the positive x-axis (east direction). Since the direction is west of north, the horizontal component will be negative. Using trigonometry, we can calculate:
Horizontal component = 300 km/hr * sin(20°) ≈ -102.9 km/hr
To find the vertical component, we need to determine the projection of the velocity vector onto the positive y-axis (north direction). Since the direction is north, the vertical component will be positive. Using trigonometry, we can calculate:
Vertical component = 300 km/hr * cos(20°) ≈ 280.7 km/hr
Therefore, the component form of the velocity of the airplane is (-102.9 km/hr, 280.7 km/hr). This means the airplane is moving approximately 102.9 km/hr to the west and 280.7 km/hr to the north.
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The work function of a specific metal is 2.91 eV Find the longest wavelength, in nanometers, photon that can eject an electron from potassium. Numeric A numeric value is expected and not an expression Aux
Answers
The longest wavelength photon that can eject an electron from potassium is 426 nm.
The work function of potassium is given as 2.91 eV. To find the longest wavelength photon that can eject an electron, we can use the equation:
E = h * c / λ
Where E is the energy in joules, h is the Planck's constant (6.626 x 10⁻³⁴ Js), c is the speed of light (3 x 10⁸ m/s), and λ is the wavelength in meters. First, we need to convert the energy from electron volts (eV) to joules (J):
1 eV = 1.602 x 10⁻¹⁹ J
E = 2.91 eV * (1.602 x 10⁻¹⁹ J/eV) = 4.66 x 10⁻¹⁹ J
Now, we can solve for the wavelength (λ):
λ = h * c / E
λ = (6.626 x 10⁻³⁴ Js) * (3 x 10⁸ m/s) / (4.66 x 10⁻¹⁹ J)
λ = 4.26 x 10⁻⁷ m
To convert this value to nanometers (nm), we simply multiply by 10⁹:
λ = 4.26 x 10⁻⁷ m * 10⁹ nm/m = 426 nm
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Two spheres A and B are placed in the arrangement shown below.
(a) If mA = 2m and mB = 7m, where on the dashed line should a third sphere C of mass 7m be placed so that the net force on it is zero? (Select 1)
-between A and B, closer to B
-at the midpoint between A and B
-to the left of B
-to the right of A
-between A and B, closer to A
(b) If the distance between the two spheres A and B is 500 cm, find the location for the third sphere C so that the net force on it is zero.
Answers
a. The third sphere must be placed between A and B, closer to A.
b. the third sphere must be placed at 175 cm from the first sphere.
a. If mA = 2m and mB = 7m, where on the dashed line should a third sphere C of mass 7m be placed so that the net force on it is zero?
Since
mA = 2 kg,mB = 7 kg and mC = 7kg,Using Newton's law of universal gravitation, the net force on the first sphere on the third sphere is F = mAmC/x² where x = distance between sphere C and A
Also, the Force of attraction between there second sphere and the third sphere is F' = mBmC/(R - x)² where R = distance between mA and mB and x = distance between mA and mC.
Since the net force must be zero, then
F = F'
mAmC/x² = mBmC/(R - x)²
So, (R - x)²/x² = mB/mC/mAmC
(R - x)²/x² = mB/mA
Substituting the values of mA and mB into the equation, we have
(R - x)²/x² = 7/2
(R - x)²/x² = 3.5
(R - x)/x = √3.5
(R - x)/x = 1.87
R - x = 1.87x
R = x + 1.87x
R = 2.87x
x = R/2.87
x = 0.35R
Since x = 0.35R, the third sphere must be placed between A and B, closer to A.
b. If the distance between the two spheres A and B is 500 cm, find the location for the third sphere C so that the net force on it is zero.Since the position of the third sphere is
x = 0.35R and R = 500 cmSo, x = 0.35 × 500 cm
x = 175 cm
So, the third sphere must be placed at 175 cm from the first sphere.
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What type of resistance training equipment has a fixed range of motion? Chains Resistance bands Free weights Weight machines
Answers
Chains are the type of resistance training equipment which has a fixed range of motion.
What is Resistance?This is a type of force which restricts the motion of an object thereby slowering it down.
Chains help to build stamina and power though varying the loads in a fixed range of motion. This is why it was chosen as the most appropriate choice.
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an object in mechanical equilibrium is an A. object having no changes in velocity. B. moving with constant velocity. C. at rest. all of the above
Answers
An object in mechanical equilibrium can be described as an object that is either at rest, moving with constant velocity, or having no changes in velocity. Therefore, the correct answer is option D, "all of the above."
Mechanical equilibrium refers to a state where the net force acting on an object is zero. In this state, the object experiences a balanced force, which can result in different conditions depending on the initial state of the object.
If the object is initially at rest and remains at rest, it satisfies the condition of mechanical equilibrium. In this case, the net force acting on the object is zero, and there are no changes in velocity.
If the object is initially in motion and continues to move with a constant velocity, it also satisfies the condition of mechanical equilibrium. The net force acting on the object is zero, meaning the forces acting on the object are balanced, and there are no changes in velocity.
Therefore, an object in mechanical equilibrium can be at rest, moving with a constant velocity, or experiencing no changes in velocity. Hence, the correct answer is option D, "all of the above."
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A boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6. 80 kg, and the boy exerts a horizontal force of 24. 0 n on the bag. As a result, the bag accelerates from rest to a speed of 1. 12 m>s in a distance of 5. 25 m. What is the coefficient of kinetic friction between the bag and the ground?
Answers
The coefficient of kinetic friction between the bag and the ground is found to be 0.0251. It represents the ratio of the frictional force to the normal force acting between them.
In this question, a boy pulls a bag of baseball bats across a ball field toward the parking lot. The bag of bats has a mass of 6.80 kg, and the boy exerts a horizontal force of 24.0 N on the bag. As a result, the bag accelerates from rest to a speed of 1.12 m/s at a distance of 5.25 m. We have to find the coefficient of kinetic friction between the bag and the ground.The formula used to find the coefficient of kinetic friction is given as,μk= (a/g) + μs (1 - a/g), Where, μk = coefficient of kinetic friction, a = acceleration of the body, g = acceleration due to gravity (9.8 m/s2), μs = coefficient of static frictionGiven, Mass of the bag (m) = 6.80 kg, Force applied (F) = 24.0 N, Initial velocity (u) = 0 m/s, Final velocity (v) = 1.12 m/s, Distance covered (s) = 5.25 m, Acceleration (a) = (v2 - u2) / 2s. Substituting the given values, a = (1.12² - 0²) / (2 * 5.25)m/s²a = 0.247m/s². Now, we will use the formula of the coefficient of kinetic friction. μk= (a/g) + μs (1 - a/g)Let's assume the value of μs to be zero.μk= (a/g) + 0 (1 - a/g) = μk= (a/g) + 0 (1 - a/g) = μk = (a/g) = μk = (0.247m/s²) / (9.8m/s²) = μk= 0.0251. Therefore, the coefficient of kinetic friction between the bag and the ground is 0.0251. In order to move the bag, the boy had to overcome friction. From the given values, we calculated the acceleration of the bag, which was found to be 0.247 m/s². Using this acceleration, we can find the coefficient of kinetic friction, which came out to be 0.0251. This value represents the ratio of the frictional force to the normal force acting between the bag and the ground.For more questions on kinetic friction
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A runner begins to run at the 5.0 meter mark and runs for 3.0 seconds. If they accelerate at approximately 5.0 m/s
2
. how far will they have run within that time period? 5.0 m 23 m 28 m 63 m Hint: the initial speed is zero, since they are just beginning to run when at the 5.0 m mark.
Answers
The runner will have run approximately 23 meters within that time period, option B.
The runner begins to run at the 5.0-meter mark and runs for 3.0 seconds. The runner accelerates at approximately 5.0 m/s². We are required to find how far they will have run within that time period.
Therefore, we can use the following formula:
Distance = (1/2) x acceleration x time²
Since the runner is starting from rest, the initial speed, u is zero.
Also, acceleration is given to be 5.0 m/s², and time is 3.0 seconds, thus:
Distance = (1/2) x 5.0 m/s² x (3.0 s)² = 22.5 m
Hence, the runner will have run approximately 22.5 meters within that time period.
Therefore, the answer is option B, 23 meters.
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centripetal force a 200 g ball is moving in a horizontal circle at 5 m/s. the tension in the string is 5n. (don't forget: mass in kg a. which force is providing necessary centripetal force to keep stone moving in circular motion? b. how much is centripetal force? c. how long is the string? (fc
Answers
The force applied to an item in curvilinear motion that is pointed at the center of rotation or the center of curvature is known as a centripetal force. Mass* centripetal acceleration is used to determine
How can this problem be solved?The provided ball weighs 0.35kg.
Given is a centripetal acceleration of 5 m/s2.
The centripetal force's magnitude must be determined.
Calculation
Centripetal force = mass*centripetal acceleration
= 0.35*5
= 1.75N
Hence , the centripetal force is 1.75N
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Spacecraft measurements near Venus indicate that the planet has
-a very powerful magnetic field, much stronger than that of Earth.
-a magnetic field that varies in concert with the 11-year solar activity cycle and is linked to it via the solar wind.
-no planetwide magnetic field.
-a variable planetwide magnetic field like Eart
Answers
A. Spacecraft measurements near Venus indicate that the planet has a very powerful magnetic field, much stronger than that of Earth.
Venus is one of the four terrestrial planets in the solar system with a magnetic field, along with Earth, Mercury, and Mars. The Venusian magnetic field is believed to be generated by the planet's iron-rich core, similar to the magnetic fields of the other terrestrial planets.
However, the Venusian magnetic field is much weaker than that of Earth, and it is not strong enough to provide significant protection from the solar wind or radiation.
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Coach Carver has created a new team game for his students to play. It involves sprinting, tagging, and throwing a ball. Each team consists of 30 to 40 students. Which place is the safest to play the game?
a. an outdoor basketball court
b. a gymnasium
c. an empty classroom
d. a football field
Answers
The safest plays to play sprinting, tagging, and throwing the ball is d) a football field
A football/soccer field is a rectangular field surrounded by lines called perimeters. The two long lines are the touch lines and the two short lines are the goal lines. It is divided in half by the midline connecting the midpoints of the two contact lines. The field is 100 yards long, with 10-yard end zones for each team. The field has stripes across the width of the field at 5-yard intervals. The soccer field is 160 feet wide. The games that can be played on the football field are sprinting, throwing the ball, tagging, etc.
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