A gasoline engine has a power output of 210 kW (about 282 hp ). Its thermal efficiency is 28.5%.
a) How much heat must be supplied to the engine per second? Express your answer in joules.
b) How much heat is discarded by the engine per second? Express your answer in joules.

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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The magnitude of the maximum net force that is exerted on the object is equal to 1.60 N.

The magnitude of the maximum net force on the object is equal to the magnitude of the spring force at the maximum displacement of the object. The spring force is given by Hooke's law, which states that the force exerted by a spring is proportional to the displacement of the spring from its equilibrium position. The proportionality constant is called the spring constant, k.

The spring force can be expressed as F = -kx, where x is the displacement of the spring from its equilibrium position.

In this case, the maximum displacement of the object is A, so the magnitude of the maximum net force on the object is |F| = |-kx| = |-kA|.

Plugging in the given values, we get |F| = |-kA| = |-k(0.80 m)| = |-k(0.80 m)| = |1.60 N|.

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Answer:

C) experience a small induced magnetic moment when placed in an external magnetic field.

Explanation:

Diamagnetics materials are those that experience a small induced magnetic moment when placed in an external magnetic field. These materials, such as bismuth, copper, silver and lead, have elementary magnets in their compositions. When they are exposed to an external magnetic cap, these elemental magnets tend to follow an orientation contrary to the external magnetic field. As a result, a magnetic field is created in the opposite direction to the external magnetic field.

In order to measure the angle of incidence and the angle of refraction using Tracker's protractor tool (the green angle in the video frame), the following steps should be followed:

Step 1: Open the video in Tracker software.

Step 2: Click on the "Measure" button on the toolbar at the top of the software.

Step 3: From the dropdown menu, select "Angle".

Step 4: Click on the "protractor tool" icon (the green angle in the video frame).

Step 5: Position the vertex of the protractor exactly at the origin of the coordinate axis and move the arms of the protractor so that one arm is on the vertical axis (above or below, as appropriate) and the other on the light ray.

Step 6: Measure the angle of incidence and the angle of refraction for the frame numbers specified in the table below by using the step buttons on the right to advance the video a frame at a time.

Step 7: Record the measured angles in the table below. Note that the angle of incidence should be measured on the incident ray (the ray that is coming from the left), and the angle of refraction should be measured on the refracted ray (the ray that is coming from the right).In conclusion, by following these steps, one can measure the angle of incidence and the angle of refraction using Tracker's protractor tool.

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Answer: Dynamic balance

Explanation: Dynamic balance movements are movements in which constant agonist-antagonist muscle contractions occur in order to maintain a certain position or posture. ISSA pg 121

The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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The fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

What is balance?

To balance the system horizontally, the center of gravity (CG) of the bar and the attached masses should be placed directly above the fulcrum. We can find the location of the CG using the following formula:

CG = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)

where m1, m2, and m3 are the masses of the bar, the 0.055 kg mass, and the 0.110 kg mass, respectively, and x1, x2, and x3 are their respective distances from the left end of the bar.

We know that the total mass of the system is:

m = m1 + m2 + m3 = 0.120 kg + 0.055 kg + 0.110 kg = 0.285 kg

Let x be the distance from the left end of the bar to the fulcrum. Then, the distance from the fulcrum to the center of gravity is (L/2 - x), where L is the total length of the bar (90.0 cm). Therefore, we want to find x such that:

CG = (L/2 - x)

Substituting the expressions for the CG and the masses, we get:

(m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) = (L/2 - x)

Simplifying and rearranging, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

We can choose any two points on the bar as reference points, and take their distances as x1 and x3. Let's choose the left end of the bar as x1 = 0, and the right end of the bar as x3 = L = 90.0 cm = 0.900 m. Then, we can find x2, the distance from the left end to the 0.110 kg mass, as:

x2 = L - x1 - x3 = 0.900 m - 0 m - 0.090 m = 0.810 m

Substituting the masses and distances, we get:

x = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3) - L/2

x = (0 kg × 0 m + 0.055 kg × 0.810 m + 0.110 kg × 0.900 m) / (0.120 kg + 0.055 kg + 0.110 kg) - 0.450 m

x = 0.570 m - 0.450 m

x = 0.120 m

Therefore, the fulcrum should be placed 0.120 m from the left end of the bar to balance the system horizontally.

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The speed of the sound wave is 660 meters per second.

To calculate the speed of the sound wave, we need to use the formula:
Speed = Frequency x Wavelength
Here, the frequency of the sound wave is given as 880Hz, and the wavelength is given as 0.75. To get the answer, we just need to plug these values into the formula and solve for the speed:
Speed = 880 x 0.75
Speed = 660 meters per second
It's important to note that the speed of sound depends on the medium through which it is traveling. In air, the speed of sound is approximately 343 meters per second at standard temperature and pressure. However, this value can change depending on factors such as temperature, humidity, and altitude.
Understanding the speed of sound is important in various fields, such as music, engineering, and physics. For example, in music, the speed of sound determines the pitch of a note, while in engineering, it can be used to design and optimize acoustic systems. In physics, it's used to study the properties of waves and to explain phenomena such as Doppler effect and sonic booms.

Therefore, the speed of the sound wave is 660 meters per second.

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Answer:

If there was no friction it would be impossible to move in any direction other than down.

Explanation:

Friction stops things from sliding apart. If there was no friction everything would slide to the lowest point. It would be impossible to climb up anything. Imagine trying to climb a wall of ice without crampons and an ice pick. It would be impossible.

He would never stop.

Friction rubs one surface against another to generate heat and it slows objects, so if there was no friction, the baseball player would slip and fall and never slow down

Answer: 33.3 m/s^2

Explanation:

Here we need to use the second Newton's law.

F = m*a

Force equals mass times the acceleration.

Here we know that the force is F = 4000 N, and the mass is 120kg, then the acceleration must be:

4000 N = 120kg* a

a = (4000/120) m/s^2 = 33.3 m/s^2

Treating the box as a particle, there are two forces acting on it in opposite directions: the box's weight mg pulling it downward and the resistive force of the air pointing upward.

The box is falling at a constant speed, so by Newton's second law we have

mg - r = 0

where mg = (75.0 kg) (9.80 m/s²) = 735 N is the weight of the box and r is the magnitude of air resistance. So we have

r = mg = 735 N

The depth in the lake of pressure 173.693 lb/in² is 122.45 m.

Depth is the distance down either from the top of something to the bottom, or to a distance below the top surface of something.

To calculate the depth in the lake, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values in to equation 1

Hence, the depth in the lake is 122.45 m.

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The reaction to the action force of the impact of the ball against the player's glove is option B): "the force the glove exerts on the ball".

This is known as Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. So, as the ball exerts a force on the glove, the glove exerts an equal and opposite force on the ball, allowing the player to catch the ball. The other options listed (A, C, and D) are not directly related to the action-reaction force pair involved in the catch.

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Answer:

"Health psychology is a specialty area that focuses on how biology, psychology, behavior, and social factors influence health and illness."

-Verywell Mind

Hope I helped!

Explanation:

Answer:

\(force = mass \times acceleration \\ 100 = 50 \times a \\ a = 2 \: {ms}^{ - 2} \\ from : \: \: v = u + at \\ 150 = 100 + (2 \times t) \\ 50 = 2t \\ time = 25 \: seconds\)

The circuit in which lamps Q and R light but not lamp P when switch S is open is circuit B.

An electric circuit is a path for transmitting electric current.

Given the circuits below, when switch S is open, we want to determine the circuit in which lamps Q and R light but not lamp P.

To determine the circuit, we proceed as follows.

To determine the circuit in which lamps Q and R light but not lamp P, it must satisfy this condition

Looking at all the circuits, the circuit which satisfy these condition is circuit B

So, the circuit in which lamps Q and R light but not lamp P is circuit B.

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Answer:

chemical energy is the answer

Answer:

It is B.

Explanation:

This is because you want to see how fast the dog moves and the best way to find out is by seeing how fast it moves in a certain amount of time. pls brainly!

Answer:

Independent, then dependent

Explanation:

Just took this on Edge 2021

The exact length of the radius (r) of the regular hexagon ABCDEF is 12 inches., and the exact length of the perimeter of the regular hexagon ABCDEF is 216 inches.

To find the exact length of the radius and perimeter of the regular hexagon, we can use some properties of a regular hexagon and trigonometry.

Radius (r):

In a regular hexagon, the apothem (a) and radius (r) are related by the equation:

r = a/cos(π/6)

Given that the apothem (a) is 6√3 inches, we can substitute it into the equation to find the radius:

r = 6√3/cos(π/6)

To simplify further, we need to evaluate the cosine of π/6. Since cosine of π/6 is equal to √3/2, the equation becomes:

r = 6√3 / (√3/2)

r = 6√3 * (2/√3)

r = 12 inches

Therefore, the exact length of the radius (r) of the regular hexagon ABCDEF is 12 inches.

Perimeter:

The perimeter of a regular hexagon can be found by multiplying the length of one side by the total number of sides. Since all sides of a regular hexagon are equal, we only need to calculate the length of one side.

In a regular hexagon, the apothem (a) and side length (s) are related by the equation:

s = 2a/tan(π/6)

Substituting the value of the apothem (a) as 6√3 inches, we have:

s = 2(6√3) / tan(π/6)

To simplify further, we need to evaluate the tangent of π/6. Since the tangent of π/6 is equal to 1/√3, the equation becomes:

s = 2(6√3) / (1/√3)

s = 12√3 / (1/√3)

s = 12√3 * √3

s = 36 inches

Since a regular hexagon has 6 sides, the perimeter (P) is given by:

P = 6s

P = 6(36)

P = 216 inches

Therefore, the exact length of the perimeter of the regular hexagon ABCDEF is 216 inches.

Therefore, The exact length of the regular hexagon ABCDEF's radius (r) is 12 inches, and the exact length of the regular hexagon ABCDEF's perimeter is 216 inches.

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The distance mirror M2 must be moved so that one wavelength has produced one more new maxima than the other wavelength is;

L = 57.88 mm

We are given;

Wavelength 1; λ₁ = 589 nm = 589 × 10⁻⁹ m

Wavelength 2; λ₂ = 589.6 nm = 589.6 × 10⁻⁹ m

We are told that L₁ = L₂. Thus, we will adopt L.

Formula for the number of bright fringe shift is;

m = 2L/λ

Thus;

For Wavelength 1;

m₁ = 2L/(589 × 10⁻⁹)

For wavelength 2;

m₂ = 2L/(589.6)

Now, we are told that one wavelength must have produced one more new maxima than the other wavelength. Thus;

m₁ - m₂ = 2

Plugging in the values of m₁ and m₂ gives;

(2L/589) - (2L/589.6) = 2

divide through by 2 to get;

L[(1/589) - (1/589.6)] = 1

L(1.728 × 10⁻⁶) = 1

L = 1/(1.728 × 10⁻⁶)

L = 578790.67 nm

L = 57.88 mm

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Answer:

I think it's most likely true.

Explanation:

any organism has the properties of a living thing, which includes cells, whether it has one cell or many

Answer:

False

Explanation:

An organism is a living thing that is a single-celled life form

Answer: what characterizes moral development in mid to late childhood is

People at this level of moral development base their decisions on what their parents and/or law enforcement says is right. Stage 3 is about social conformity. ... Stage 4 is all about law and order for all. For example, someone may think, 'If I steal, I will break the law and breaking the law is wrong.Feb 17, 2016

Explanation:

The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

Music heals the brain and soul. It should listen at the time of stress. There are different types of music such as slow, fast, and retro music.

When the person is feeling very happy and energetic they usually listen to fast songs. When a person is lost he usually listens slow and Legato music.

In the disco usually fast and upbeat music is played. Algerado is a type of quick and lively music.

Therefore, The most common type of music which will be accompanied by a kitten will be slow, legato, and minor key.

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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Answer:

14.25 m/s

Explanation:

In this problem, we need to find the horizontal component of a ball thrown at a 27 degree angle at 16 m/s.

It can be given by :

\(v_x=v\cos\theta\\\\=16\times \cos(27)\\\\=14.25\ m/s\)

So, the horizontal component of the ball is 14.25 m/s.

Answer:

Explanation:

Formula

F = m * a

Givens

F = 48 N

a = 0.35 m/s^2

m = ??

Solution

F = m * a                                        Substitute the givens

48 = m * 0.35                                Divide by 0.35

48 / 0.35 = m *0.35/0.35            

137.1 kg = mass

Given that the force between two charged particles, we'll call charge 1 and 2 is, \(\vec F_{0}=200 \ N\). The question asks us to find the new force between charges 1 and 2 if the charge on 1 increases by 3 times and the charge on 2 decreases by 4 times.

Equation to calculate the electric force between two charged particles:

\(\vec F_e=k_e\frac{q_1q_2}{r^2} \\\\ k_e=Coulomb's \ Constant= 8.99 \times 10^9 \ \frac{Nm^2}{C^2}\\\)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

\(\vec F_0=k_e\frac{q_1q_2}{r^2} =200 \ N \ and \ \boxed{\vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} }\)

\(\Longrightarrow \vec F_f=k_e\frac{(3 q_1)(\frac{1}{4} q_2)}{r^2} \Longrightarrow \vec F_f=\frac{3}{4} k_e\frac{q_1 q_2}{r^2} \Longrightarrow \vec F_f=\frac{3}{4}(200) \Longrightarrow \boxed{\boxed{\vec F_f=150 \ N}}\)

Thus, the new force would be 150 N.

The new force will be 150N

The force between two charged objects is given by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically, Coulomb's law can be expressed as:

F = k * (q1 * q2) / r^2

where F is the force, k is Coulomb's constant, q1 and q2 are the charges of the two objects, and r is the distance between them.

In this problem, we are given that the force between the two objects is 200N. Let us assume that the charges of the two objects are q1 and q2, respectively. Using Coulomb's law, we can write:

200 = k * (q1 * q2) / r^2

Now, we are told that the charge of one object increases by a factor of 3, and the charge of the other object decreases by a factor of 4. Let us call the new charges q1' and q2', respectively. We can write:

q1' = 3 * q1

q2' = (1/4) * q2

Substituting these expressions into Coulomb's law, we get:

F' = k * (q1' * q2') / r^2

= k * [(3 * q1) * ((1/4) * q2)] / r^2

= k * (3/4) * (q1 * q2) / r^2

= (3/4) * F

Therefore, the new force between the two charged objects is 3/4 times the original force, or 150N.

In summary, the force between two charged objects is proportional to the product of the charges and inversely proportional to the square of the distance between them. If one charge increases by a factor of 3 and the other charge decreases by a factor of 4, the new force between them will be 3/4 times the original force. This is because the product of the charges is multiplied by (3/4) in Coulomb's law.

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