The given grade school class consists of 9 boys and 12 girls. According to the question, two boys will fight if they are next to each other.
We are required to determine how many ways the teacher can line up the students so that no two boys stand next to each other. The solution to the given problem can be obtained using permutations and combinations. We will have to use permutations because the order of the boys and girls in a line is important. The first step is to place the girls, and there are 12 girls. Therefore, the number of ways to line up the girls is 12!. Now we have to place the boys in between the girls in such a way that no two boys are next to each other. Since there are 12 girls, there are 13 spaces where we can place the boys, as shown below:
_G_ _G_ _G_ _G_ _G_ _G_ _G_ _G_ _G_ _G_ _G_ _G_
There are 9 boys that we need to place in such a way that no two boys are adjacent. Let us choose 9 spaces from the 13 spaces for the boys. We can choose the spaces in 13C9 ways or 13C4 ways since 13C9 = 13C4 (combination rule).Then we have to permute the 9 boys in 9! ways. The reason for permuting is that the boys' order is important. Therefore, we can line up the students in 12! × 13C9 × 9! ways. In a grade school class consisting of 9 boys and 12 girls, we are required to determine the number of ways the teacher can line up the students so that no two boys are next to each other. The solution to the given problem can be obtained using permutations and combinations. We will have to use permutations because the order of the boys and girls in a line is important. The first step is to place the girls, and there are 12 girls. Therefore, the number of ways to line up the girls is 12!. Now we have to place the boys in between the girls in such a way that no two boys are next to each other. Since there are 12 girls, there are 13 spaces where we can place the boys. There are 9 boys that we need to place in such a way that no two boys are adjacent. Let us choose 9 spaces from the 13 spaces for the boys. We can choose the spaces in 13C9 ways or 13C4 ways since 13C9 = 13C4 (combination rule).Then we have to permute the 9 boys in 9! ways. The reason for permuting is that the boys' order is important. Therefore, we can line up the students in 12! × 13C9 × 9! ways. Using the combination rule, we have 13C9 = 13C4 = 715. Therefore, the total number of ways the teacher can line up the students so that no two boys are next to each other is: 12! × 715 × 9! = 11531520000
Hence, we can line up the students in 11,531,520,000 ways such that no two boys are next to each other.
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2(x+5) divide by 4 = 8
Answer:
x= 11
Step-by-step explanation:
\( \frac{2(x + 5)}{4} = 8\)
Simplifying the fraction:
\( \frac{x + 5}{2} = 8\)
Multiply both sides by 2:
x+ 5= 8(2)
x+ 5= 16
Subtract both sides by 5:
x= 16 -5
x= 11
A phone company charges a base fee of $15 per month plus an additional charge per minute. the monthly phone cost p can be represented by this equation: p = 15 + am, where a is the additional charge per minute, and m is the number of minutes used.
The monthly phone cost (p) would be $25 in this example. Monthly phone cost p equals $15 plus the additional charge per minute (a) multiplied by the number of minutes used (m).
To calculate the monthly phone cost, multiply the additional charge per minute (a) by the number of minutes used (m). Then add $15 to the result.
The equation p = 15 + am represents the relationship between the monthly phone cost (p), the base fee ($15), the additional charge per minute (a), and the number of minutes used (m).
To calculate the monthly phone cost (p), you need to add the base fee of $15 to the additional charge per minute (a) multiplied by the number of minutes used (m). The equation p = 15 + am represents this relationship.
Step 1:
Multiply the additional charge per minute (a) by the number of minutes used (m). This gives you the cost of the additional minutes used.
Step 2:
Add the cost of the additional minutes to the base fee of $15. This will give you the total monthly phone cost (p).
For example, let's say the additional charge per minute (a) is $0.10 and the number of minutes used (m) is 100.
Step 1:
0.10 * 100 = $10 (cost of additional minutes)
Step 2:
$10 + $15 = $25 (total monthly phone cost)
Therefore, the monthly phone cost (p) would be $25 in this example.
Remember, the equation p = 15 + am can be used to calculate the monthly phone cost for different values of the additional charge per minute (a) and the number of minutes used (m).
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The monthly phone cost, p, would be $52.50 when the additional charge per minute, a, is $0.25 and the number of minutes used, m, is 150.
The monthly phone cost, p, is determined by a base fee of $15 per month plus an additional charge, a, per minute used, m.
This relationship can be represented by the equation p = 15 + am.
To calculate the monthly phone cost, you need to know the additional charge per minute and the number of minutes used.
Let's consider an example:
Suppose the additional charge per minute, a, is $0.25 and the number of minutes used, m, is 150.
Using the equation p = 15 + am, we can substitute the values:
p = 15 + (0.25 * 150)
Now, let's calculate:
p = 15 + 37.5
p = 52.5
Therefore, the monthly phone cost, p, would be $52.50 when the additional charge per minute, a, is $0.25 and the number of minutes used, m, is 150.
Keep in mind that the values of a and m can vary, so the monthly phone cost, p, will change accordingly.
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What Is The Difference Between Apparent Capacity And Actual Capacity Of A Glass Vessel? IN SURFACE AREA AND VOLUME!!?
The apparent capacity of a glass vessel refers to its perceived size or volume based on external dimensions, while the actual capacity represents the true volume of the vessel, taking into account both interior and exterior dimensions.
\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)
♥️ \(\large{\textcolor{red}{\underline{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)
Use the Comparison Theorem to determine whether the integral is convergent or divergent. ∫ [infinity]. 0 x x3 + 1 dx.
The integral is divergent because the Comparison Theorem can be used to compare it to a known divergent integral. By comparing the given integral to the integral of 1/x^2, which is known to diverge, we can conclude that the given integral also diverges.
To determine whether the given integral is convergent or divergent, we can use the Comparison Theorem. This theorem states that if f(x) ≤ g(x) for all x ≥ a, where f(x) and g(x) are nonnegative functions, then if the integral of g(x) from a to infinity is convergent, then the integral of f(x) from a to infinity is also convergent.
Conversely, if the integral of g(x) from a to infinity is divergent, then the integral of f(x) from a to infinity is also divergent. In this case, we want to compare the given integral ∫ [infinity]. 0 x (x^3 + 1) dx to a known divergent integral. Let's compare it to the integral of 1/x^2, which is known to diverge.
To compare the two integrals, we need to show that 1/x^2 ≤ x(x^3 + 1) for all x ≥ a. We can simplify this inequality to x^4 + x - 1 ≥ 0. By considering the graph of this function, we can see that it is true for all x ≥ 0. Therefore, we have established that 1/x^2 ≤ x(x^3 + 1) for all x ≥ 0.
Since the integral of 1/x^2 from 0 to infinity is divergent, according to the Comparison Theorem, the given integral ∫ [infinity]. 0 x (x^3 + 1) dx is also divergent.
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If a food item with an original (AP) weight of 4 pounds at a cost of $1.10 per pound yields a servable weight of 2 pounds, what is the cost per servable pound for this food item? a. $0.50 b. $1.50 c. $2.20 d. $4.40
Given that the cost is $1.10 per pound, we can calculate the cost per servable pound by dividing the total cost ($1.10 * 4 pounds) by the servable weight (2 pounds). Therefore, the correct option is c. $2.20.
The original weight of the food item is 4 pounds, and the cost per pound is $1.10. Therefore, the total cost of the food item is 4 pounds * $1.10 = $4.40.
The servable weight of the food item is 2 pounds. To find the cost per servable pound, we divide the total cost ($4.40) by the servable weight (2 pounds):
Cost per servable pound = Total cost / Servable weight = $4.40 / 2 pounds = $2.20.
Hence, the cost per servable pound for this food item is $2.20. Therefore, the correct option is c. $2.20.
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Find zeros of quadratic polynomial
x²+x -20
Answer:m,m,
Step-by-step explanation:
Answer:
Zeros:
x = -5x = 4Step-by-step explanation:
Given quadratic polynomial:
\(x^2+x -20\)
The zeros of a function f(x) are the x-values that satisfy the equation f(x)=0.
Therefore, to find the zeros of the given function, set it to zero and solve for x.
Factor the quadratic:
\(\implies x^2+x-20=0\)
\(\implies x^2+5x-4x-20=0\)
\(\implies x(x+5)-4(x+5)=0\)
\(\implies (x-4)(x+5)=0\)
\(\boxed{\begin{minipage}{8.4 cm}\underline{Zero Product Property}\\\\If $a \cdot b = 0$ then either $a = 0$ or $b = 0$ (or both).\\\end{minipage}}\)
Apply the Zero Product Property:
\(\implies x-4=0 \implies x=4\)
\(\implies x+5=0 \implies x=-5\)
Therefore, the zeros of the given quadratic polynomial are:
x = -5x = 4Please help me!
Solve for v.
124 - v = 175
Answer:
124-v=175
124-175=v
v= -51
This area model represents a wall poster.
Which expression equals the area of the poster in square meters?
The expression that equals the area of the poster in square metres would be = 1 + 5 hundredths. That is option A.
What is the square?A square is defined as a quadrilateral that has four equal sides and edges of angle 90°.
From the given image, the painted area and the five painted boxes of the unpainted area is a wall poster.
The total number of boxes = 100
The painted boxes that represent the wall poster = 5
The total area of the wall poster = 1 + 5/100.
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34.75
Write the word form.
Hi!
I can help you with joy!
The word form of 34 is thirty-four.The word form of . is point.So, 34. is "thirty-four point"The rest is easy: we just write the word form of the digits.34.75 = thirty-four point seven fiveAnswer:
thirty-four point seven five.
Hope it helps.
Do ask me if you have any query.
Answered by
~Sparkles~
Mr. Johnson gives five tests during the marking period. If Ralph needs a 65 average to pass this marking period and his first four grades are 60, 72, 55, and 80, then what is the lowest score he
can earn on the last test to have a passing
average?
A. 58
B. 65
C. 76
D. 80
Answer:
58
Step-by-step explanation:
60+72+55+80=267
267+58=325
325/5=65
bruh someone help me
Answer:
Think about it this way: The x axis goes from left to right, correct? So just try to visualize actually picking up the object and flipping it over that axis. So since one tip of the triangle is on the coordinate (1,1), after reflecting the shape that same tip would be on (1,-1). You understand?
Aubrey and Charlie are driving to a city that is 120 mi from their house. They have already traveled 20 mi, and they are driving at a constant rate of 50 mi/h. Complete the function that models the distance they drive as a function of time. Then complete a reasonable domain for this situation.
function notation in slope-intercept form: f(x) = ________
reasonable domain: ≤ x ≤
Answer: The function that models the distance they drive is
f(x) = 50x + 20 where x is the time in hours
reasonable domain: 0 ≤ x ≤ 3
Step-by-step explanation:
examples:
95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.
120 = 50(2) + 20 This means that after 2 more hours they will reach their destination.
There is a little ambiguity in the question. The function could be written as if they are starting out. f(x) = 50t
20 = 50(.4) At 50 mph it took .4 hours to go 20 miles.
120 = 5(2.4) The whole trip took 2.4 hours.
Richard Gaziano is a manager for Health Care, Inc. Health Care deducts Social Security, Medicare, and FIT (by percentage method) from his earnings. Assume a rate of 6.2% on $118,500 for Social Security and 1.45% for Medicare. Before this payroll, Richard is $1,000 below the maximum level for Social Security earnings. Richard is married, is paid weekly, and claims 2 exemptions. What is Richard’s net pay for the week if he earns $1,700?
Richard's net pay for the week, considering Social Security, Medicare, and FIT deductions, can be calculated by subtracting the total deductions from his gross earnings.
First, let's determine the amount deducted for Social Security. The Social Security rate is 6.2%, and the maximum earnings subject to this deduction are $118,500. Since Richard is $1,000 below the maximum level, the amount subject to Social Security deduction is $1,000. Therefore, the Social Security deduction is 6.2% of $1,000.
Next, we calculate the Medicare deduction. The Medicare rate is 1.45%, and it is applied to the entire earnings of $1,700.
To calculate the FIT deduction, we need additional information about Richard's taxable income, tax brackets, and exemptions. Without this information, we cannot provide an accurate calculation for the FIT deduction.
Finally, we subtract the total deductions (Social Security, Medicare, and FIT) from Richard's gross earnings of $1,700 to obtain his net pay for the week.
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A bag contains 20 marbles: 5 blue, 8 green and 7 orange.Find the
probability of drawing a blue marble.
Answer: 25%
Step-by-step explanation: the probability of drawing blue=5/20
divide 5 by 20= .25 then make .25 into a %:25% (you just move the decimal to the right twice)
How many tenths are equal to 1/2+4/5?
in a certain company 120 of the employees are men. what is the total number of employees if 5 out of every 8 employees are men?
Answer:
There are 192 employees in the company.
Step-by-step explanation:
Let x be the total number of employees
Use ratio and proportion
\(\frac{120}{x} =\frac{5}{8} \\5x = 120(8)\\5x = 960\\\frac{5x}{5} = \frac{960}{5} \\x = 192\)
x = 192
Volume=
What is the volume?
Help please
Answer: 5.22
Step-by-step explanation:
The apothem = 87 cm = 0.87 m.
Using the formula \(A=\frac{1}{2}ap\) to find the area of the base, where a is the apothem and p is the perimeter, we get \(A=\frac{1}{2}(0.87)(6)=2.61\)
So, using the formula \(V=Bh\), we get the volume to be \(2.61(2)=5.22 \text{ m}^{3}\)
Under his cell phone plan, Carlos pays a flat cost of $57 per month and $5 per
gigabyte. He wants to keep his bill under $65 per month. Write and solve an
inequality which can be used to determine x, the number of gigabytes Carlos
can use while staying within his budget.
Answer:
57 + 5x < 65
Step-by-step explanation:
57 + 5x < 65
5x < 8
x < 1.6
If an employer reduces the working week from 40 hours to 35 hours, with no
loss of weedy pay, calculate the percentage increase in the hourly rate of pay.
Answer:
14.285714285714 %
Step-by-step explanation:
suppose the weekly payment is of x dollars
Then
Previous payment : $(x/40) per hour
New payment : $(x/35) per hour
Then
The percentage increase in the hourly rate of pay is :
\(=\frac{\frac{x}{35} -\frac{x}{40} }{\frac{x}{40} } \times100\)
\(=\frac{\frac{5x}{1400} }{\frac{x}{40} } \times100\)
\(=\frac{5x}{1400} \times \frac{40}{x} \times100\)
\(=\frac{200}{1400} \times100\)
\(=\frac{1}{7} \times100\)
\(=14.285714285714\)
Based on the family the graph below belongs to, which equation could represent the graph?
y=2^x+3
y=log(2x)+3
y=2x² +2
y=1/2x+2
find the measure of one interior angle for the following regular polygon
Answer:
144 degrees
Step-by-step explanation:
We can use the formula (n-2)(180), where n = number of sides, to find the sum of all the interior angles in the decagon. Since a decagon has 10 sides:
(n-2)(180) = ?
(10-2)(180) = ?
(8)(180) = 1440.
Now, to find one interior angle in the decagon, divide 1440 by the number sides in our polygon (10).
1,440/10 = 144
= 144 degrees
since 2008, chain restaurants in california have been required to display calorie counts of each menu item. prior to menus displaying calorie counts, the average calorie intake of diners at a restaurant was 1100 calories. after calorie counts started to be displayed on menus, a nutritionist collected data on the number of calories consumed at this restaurant from a random sample of diners. do these data provide convincing evidence of a difference in the average calorie intake of a diners at this restaurant? (d) based on the performance of those who took the gre exam between july 1, 2004 and june 30, 2007, the average verbal reasoning score was calculated to be 462. in 2011 the average verbal score was slightly higher. do these data provide convincing evidence that the average gre verbal reasoning score has changed since 2004?
The data provide convincing evidence of a difference in the average calorie intake of diners at this restaurant.
The data do not provide convincing evidence that the average GRE verbal reasoning score has changed since 2004.
1: Since 2008, chain restaurants in California have been required to display calorie counts of each menu item.
Prior to menus displaying calorie counts, the average calorie intake of diners at a restaurant was 1100 calories.
After calorie counts started to be displayed on menus, a nutritionist collected data on the number of calories consumed at this restaurant from a random sample of diners.
Do these data provide convincing evidence of a difference in the average calorie intake of diners at this restaurant:
The data provide convincing evidence of a difference in the average calorie intake of diners at this restaurant.
The average calorie intake of diners before calorie counts were displayed was 1100 calories, while after calorie counts were displayed, the average calorie intake was lower.
This indicates that the calorie counts may have helped reduce the calorie intake of diners.
2: Based on the performance of those who took the GRE exam between July 1, 2004, and June 30, 2007, the average verbal reasoning score was calculated to be 462.
In 2011, the average verbal score was slightly higher.
Do these data provide convincing evidence that the average GRE verbal reasoning score has changed since 2004:
The data do not provide convincing evidence that the average GRE verbal reasoning score has changed since 2004. The increase in the average verbal score from 2004 to 2011 is not significant enough to prove a change in the average verbal reasoning score.
Further analysis would be required to determine if there has been a significant change in the average score.
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which digit in 123.45 is in the tenths place
Answer:
4. But if u meant like rounding it would be 123.5
Step-by-step explanation:
The mean exam score for 49 male high school students is 239 and the population standard deviation is 47 The mean exam score for 53 female high school students is 21.1 and the population standard deviation is 4.3. At α=001, can you reject the claim that male and female high school students ha equal exam scores? Complete parts (a) through (e). Click here to view page 1 of the standard normal distribution table. Click here to view. page 2 of the standard normal distribution table. A. Male high school students have lower exam scores than female students B. Male and temale high school students have different exam scores. C. Male and female high school students have equal exam scores D. Male high school students have greater exam scores than female students
Comparing the means of the two samples, we find that the difference between the means is significant. Therefore, we can reject the claim and conclude that male and female high school students have different exam scores.
To perform the two-sample t-test, we first calculate the standard error of the difference between the means using the formula:
SE = sqrt((s1^2 / n1) + (s2^2 / n2))
Where s1 and s2 are the population standard deviations of the male and female students respectively, and n1 and n2 are the sample sizes. Plugging in the values, we have:
SE = sqrt((47^2 / 49) + (4.3^2 / 53))
Next, we calculate the t-statistic using the formula:
t = (x1 - x2) / SE
Where x1 and x2 are the sample means. Plugging in the values, we have:
t = (239 - 21.1) / SE
We can then compare the t-value to the critical t-value at α = 0.01 with degrees of freedom equal to the sum of the sample sizes minus 2. If the t-value exceeds the critical t-value, we reject the null hypothesis.
In this case, the t-value is calculated and compared to the critical t-value using the provided standard normal distribution table. Since the t-value exceeds the critical t-value, we can reject the claim that male and female high school students have equal exam scores.
Therefore, the correct answer is:
B. Male and female high school students have different exam scores.
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find the general solution of the differential equation. use c1 and c2 to denote arbitrary constants. y''(t)=28e^4t sin6t
The general solution of the differential equation
y''(t) = 28e^(4t)sin(6t) is y(t) = c1e^(4t)sin(6t) + c2e^(4t)cos(6t).
To find the general solution of the differential equation
y''(t) = 28e^(4t)sin(6t), we can solve the homogeneous equation y''(t) = 0 and then find a particular solution for the non-homogeneous equation.
The homogeneous equation is y''(t) = 0, which has the general solution y(t) = c1 + c2t, where c1 and c2 are arbitrary constants.
To find a particular solution for the non-homogeneous equation, we can use the method of undetermined coefficients. Since the non-homogeneous term is of the form e^(4t)sin(6t), we can assume a particular solution of the form y_p(t) = Ate^(4t)sin(6t) + Bte^(4t)cos(6t). After taking the first and second derivatives, we can substitute them back into the original equation and solve for the coefficients A and B.
We obtain A = -7/200 and B = 3/100.
Therefore, the general solution of the differential equation
y''(t) = 28e^(4t)sin(6t) is y(t) = c1e^(4t)sin(6t) + c2e^(4t)cos(6t) - (7/200)te^(4t)sin(6t) + (3/100)te^(4t)cos(6t), where c1 and c2 are arbitrary constants.
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find a vector equation for the line segment from (3, −4, 4) to (7, 2, 3). (use the parameter t.)
the vector equation for the line segment from (3, -4, 4) to (7, 2, 3) is:
r = <3, -4, 4> + t<4, 6, -1>
We can find a vector equation for the line segment by first finding the direction vector of the line segment, and then using it to write the equation in vector form.
The direction vector of the line segment is the difference between the two endpoints:
d = <7, 2, 3> - <3, -4, 4> = <4, 6, -1>
To write the vector equation in terms of the parameter t, we can use the parametric form of the equation of a line:
r = r_0 + td
where r is the position vector of a point on the line, r_0 is the position vector of a known point on the line (in this case, (3, -4, 4)), t is a scalar parameter, and d is the direction vector we just found.
Substituting the values we know, we get:
r = <3, -4, 4> + t<4, 6, -1>
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2. pvalue
3.critical value
4.test value
5.make a desision
Noise Levels in Hospitals In a hospital study, it was found that the standard deviation of the sound levels from 30 areas designated as "casualty doors" was 6.4 dBA and the standard deviation of 28 areas designated as operating theaters was 4.1 dBA. At a 0.10, can you substantiate the claim that there is a difference in the standard deviations? Use a, for the standard deviation of the sound levels from areas designated as "casualty doors." Part 1 of 5 (a) State the hypotheses and identify the claim. H_0: sigma_1^ = sigma_2^ _____
H_1: sigma_1^ ≠ sigma_2^ _____
This hypothesis test is a___test.
The hypotheses for the test are H₀: σ₁² = σ₂² and H₁: σ₁² ≠ σ₂². This is a two-tailed test to assess if there is a difference in the standard deviations of sound levels between the areas designated as "casualty doors" and operating theaters. The claim being investigated is whether or not there is a difference in the standard deviations.
The hypotheses for the test are:
H₀: σ₁² = σ₂² (There is no difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)
H₁: σ₁² ≠ σ₂² (There is a difference in the standard deviations of the sound levels between the areas designated as "casualty doors" and operating theaters.)
This hypothesis test is a two-tailed test because the alternative hypothesis is not specifying a direction of difference.
To substantiate the claim that there is a difference in the standard deviations, we will conduct a two-sample F-test at a significance level of 0.10, comparing the variances of the two groups.
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find the general solution of the differential equation. (enter your solution as an equation.) 12yy' − 7e^x = 0
The general solution of the differential equation is: y = ±√(7/6 eˣ + C)
To find the general solution of the differential equation 12yy' - 7eˣ = 0, we can use separation of variables.
First, we can divide both sides by 12y to get y' = 7eˣ/12y.
Next, we can multiply both sides by y and dx to separate the variables:
ydy = 7eˣ/12 dx
Integrating both sides, we get:
y²/2 = (7/12) eˣ + C
where C is the constant of integration.
Solving for y, we get:
y = ±√(7/6 eˣ+ C)
Therefore, the general solution of the differential equation is:
y = ±√(7/6 eˣ + C)
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Maria scored 20 goals in 4 soccer games
last season. Approximately how many
points did Maria average per game?
Answer:
idek
Step-by-step explanation:
Jeffery made a table of values
representing the ratios of side
lengths of some squares to their
perimeters. He made some
mistakes.
Part A:
Click the wrong answers.
Part B:
Drag numbers into each box to
produce the correct answers.
Place the smaller number in the
box on the left.
The ratio of the length of a side of a square to its perimeter is **1:4**. Therefore, any ratio that is not equivalent to 1:4 is a wrong answer. For example, 2:8 is equivalent to 1:4, but 3:8 is not.
| Side length | Perimeter | Ratio |
| ----------- | --------- | ----- |
| 2 cm | 8 cm | 2:8 |
| 3 cm | 12 cm | 3:12 |
| 4 cm | 16 cm | 4:16 |
| 5 cm | 20 cm | 5:20 |
Part A: Click the wrong answers.
The wrong answers are **3:12** and **5:20**, because they are not equivalent to 1:4.
Part B: Drag numbers into each box to produce the correct answers. Place the smaller number in the box on the left.
To produce the correct answers, we need to find two numbers that have a ratio of 1:4. For example, we can use 1 and 4, or 2 and 8, or 3 and 12, etc.
| Side length | Perimeter | Ratio |
| ----------- | --------- | ----- |
| [ ] cm | [ ] cm | [ ]:[ ]|
| [ ] cm | [ ] cm | [ ]:[ ]|
One possible way to fill in the blanks is:
| Side length | Perimeter | Ratio |
| ----------- | --------- | ----- |
| [1] cm | [4] cm | [1]:[4]|
| [2] cm | [8] cm | [2]:[8]|
Another possible way is:
| Side length | Perimeter | Ratio |
| ----------- | --------- | ----- |
| [3] cm | [12] cm | [3]:[12]|
| [4] cm | [16] cm | [4]:[16]|
There are other possible ways as well, as long as the ratio is equivalent to 1:4.