(a) The grindstone's angular acceleration is 1.86 rad/s².
(b) The grindstone turns through an angle of 83.8 radians during that time.
The angular acceleration of the grindstone can be calculated using the formula:
α = (ωf - ωi) / t
where α is the angular acceleration, ωi and ωf are the initial and final angular speeds, respectively, and t is the time interval. Substituting the given values, we get:
α = (12.5 rad/s - 4.80 rad/s) / 4.90 s
α = 1.86 rad/s²
The angle through which the grindstone turns during that time can be calculated using the formula:
θ = ωi t + 1/2αt²
where θ is the angle turned, ωi is the initial angular speed, α is the angular acceleration, and t is the time interval. Substituting the given values, we get:
θ = (4.80 rad/s) (4.90 s) + 1/2 (1.86 rad/s²) (4.90 s)²
θ = 83.8 rad
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2) marcy the 6 kg cat is on earth (5.97*10*4 kg ) 2 a) marcy pushes herself off the ground with a force of 50n so that she can jump. this push lasts for 1.5 seconds. calculate her momentum just as she jumps. b) calculate the speed she jumps with c) calculate the earth's speed just as marcy jumps. dis after jumping, marcy lands with the same speed she jumped with. if she is in the air for 2.55 seconds, how much force did she experience ?
a) Marcy's momentum just as she jumps is 75 Ns, and her velocity is 12.5 m/s.
b) Marcy jumps with a speed of 12.5 m/s.
c) Since the Earth is so massive compared to Marcy, its velocity is negligible and can be assumed to be zero.
d) Marcy experiences a force of approximately 29.41 N when she lands.
a) To calculate the value of the momentum of Marcy, we can use the formula: p = mv
where p is momentum, m is the mass of the body, and v is the velocity of the cat.
The impulse will be: J = Ft
where J is the impulse, F is the force, and t is the time for which the force is applied.
Substituting the given values, we get:
J = 50 N * 1.5 s = 75 Ns
Therefore, her final momentum just as she jumps is:
p = J = 75 Ns
Substituting the given mass of Marcy, we get:
p = m*v
75 Ns = 6 kg * v
v = 12.5 m/s
b) To calculate Marcy's speed as she jumps, we use the same velocity we calculated above. Therefore, Marcy jumps with a speed of 12.5 m/s.
c) To calculate the Earth's speed just as Marcy jumps, we need to consider conservation of momentum.
Since the Earth is much more massive than Marcy, its velocity does not change significantly when Marcy jumps.
Therefore, the initial momentum of the Earth and Marcy is zero, and the total momentum just as Marcy jumps is:
p_total = m_Marcy * v_Marcy
where m_Marcy is the mass of Marcy and v_Marcy is her velocity.
The momentum of the Earth is zero, so the total momentum just as Marcy jumps is entirely due to Marcy's momentum.
Therefore, we have:
p_total = m_Marcy * v_Marcy = 6 kg * 12.5 m/s = 75 kg m/s
Since the total momentum is conserved, the final momentum is also 75 kg m/s. Therefore, after Marcy jumps, the Earth has a velocity such that its momentum is also 75 kg m/s.
Since the Earth is so massive compared to Marcy, its velocity is negligible and can be assumed to be zero.
d) When Marcy lands, she experiences an impulse that changes her momentum. Since she lands with the same speed she jumped with, her change in momentum is:
Δp = mv - m0 = m*v
where m is the mass of Marcy and v is her velocity. The time for which Marcy experiences this impulse is the time she spends in the air, which is 2.55 seconds.
Therefore, the force that Marcy experiences is given by:
F = Δp/t = m*v/t = 6 kg * 12.5 m/s / 2.55 s = 29.41 N
Therefore, Marcy experiences a force of approximately 29.41 N when she lands.
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Image caught
on Screen is called
Answer:
Real Image
Explanation:
Images which are formed on the screen by the actual intersection of light rays are called real images.
Answer:
Virtual imageExplanation:
Virtual image can be caught on a screenhope this helps you.
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fill in the blank. * a within subjects experiment is used to the the effect of light colour on mood. The experiment has a single light bulb with three different ambient colour schemes. The experiment features three rooms each with a different light bulb, there are ___ factors in this experiment.
1
Two factors. The independent variable is the light colour and the dependent variable is the mood. The ambient colour is not a factor as it is being controlled in each room.
A within-subjects experiment is used to assess the effect of light colour on mood. The experiment has a single light bulb with three different ambient colour schemes. The experiment features three rooms each with a different light bulb, there are factors in this experiment.
In this within-subjects experiment designed to assess the effect of light colour on mood, there is 1 factor being manipulated, which is the ambient colour of the light bulb.
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When a tennis player practices by
hitting a ball against a wall, which of Newton's
laws of motion is the player making use of?
Answer:
2nd bscause there is a reaction
A car traveling at 7.5 m/s accelerates 2.9 m/s2
to reach a speed of 12.0 m/s.
How long does it take for this acceleration
to occur?
Answer in units of s.
Answer:
6.5/3.8 seconds
Explanation:
u=7.5
a=3.8
v=14
find t
The first formula has u,a v and t
so use that one
14=7.5+3.8t
6.5=3.8t
t=6.5/3.8 seconds
What is the name of the theory that states our Solar System formed through the gravitational contraction of a gas cloud?
The name of the theory that states our Solar System formed through the gravitational contraction of a gas cloud is the Nebular Hypothesis. This theory explains that our Solar System originated from a rotating cloud of gas and dust, which contracted due to gravitational forces, eventually forming the Sun and the planets.
According to this hypothesis, about 4.6 billion years ago, a molecular cloud composed mostly of hydrogen and helium, along with trace amounts of other elements, began to collapse under its own gravity. As the cloud contracted, it started to spin faster and flatten into a rotating disk shape.
The central region of the collapsing cloud became denser and hotter, eventually forming the protosun or the pre-Sun. Meanwhile, the material in the surrounding disk began to clump together due to gravity, leading to the formation of protoplanetary disks or accretion disks. Within these disks, dust and gas particles collided and gradually formed planetesimals, which further accumulated to become planets, moons, asteroids, and comets.
The nebular hypothesis provides a comprehensive explanation for the origin and formation of our Solar System, and it is widely accepted by the scientific community.
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In Einstein's special theory of relativity, mass and energy are equivalent. An expression of this equivalence can be made in terms of electron volts ( units of energy) and kilograms, with one electron volt (eV) being equal to 1.78*10^ -36 kg. Using this ratio, express the mass of the heaviest mammal on earth, the blue whale, which has an average mass of 1.90*10^ 5 kg , in mega electron volts and tera electron volts
Answer:
In MeV: 10.674 × 10^(34) MeV
In TeV: 10.674 × 10^(28) TeV
Explanation:
We are given that;
1.78 × 10^(-36) kg = 1 eV
We are now told that the blue whale has an average mass of 1.90 × 10^(5) kg
Thus, converting this mass of the blue whale to eV, we have;
(1.90 × 10^(5) × 1)/(1.78 × 10^(-36)) = 10.674 × 10^(40) eV
Now, converting to mega electron volts;
From conversions;
1 eV = 10^(-6) MeV
Thus,
10.674 × 10^(40) eV will be;
(10.674 × 10^(40) × 10^(-6))/1 = 10.674 × 10^(34) MeV
Also, converting to Tera electron Volts;
From conversion, we know that;
1 eV = 10^(-12) TeV
Thus;
10.674 × 10^(40) eV will give;
(10.674 × 10^(40) × 10^(-12))/1 = 10.674 × 10^(28) TeV
The gas law for an ideal at absolute temperature (in kelvins), pressure Pin atmospheres)and volume Vinters PV = ART, Where is the number of males of the - 0.0671 gal constant. Suppose that, at a certain instant, Postm and is increasing at a rate of 0.11 atm/min and verzand it decreasing at a rate of 0.27 min. Find the rate of change of with resped To time (in/min) at that instantin = 10 mo [Round your answer to four decimal places) K/min mit A
The rate οf change οf temperature with respect tο time is apprοximately -0.4223 K/min.
How to find the rate οf change οf temperature ?Tο find the rate οf change οf temperature (T) with respect tο time (t) at a certain instant, we can use the ideal gas law equatiοn PV = nRT and differentiate it with respect tο time:
PV = nRT
Taking the derivative with respect tο time:
P(dV/dt) + V(dP/dt) = nR(dT/dt)
Since we are interested in finding dT/dt, we can rearrange the equatiοn:
(dT/dt) = (P(dV/dt) + V(dP/dt)) / (nR)
Substituting the given values:
P = 7.0 atm
dV/dt = -0.17 L/min (negative sign indicates a decrease in vοlume)
dP/dt = 0.11 atm/min
n = 10 mοl
R = 0.0621 L·atm/(mοl·K)
(dT/dt) = (7.0 atm * (-0.17 L/min) + 12 L * 0.11 atm/min) / (10 mοl * 0.0621 L·atm/(mοl·K))
Calculating the rate οf change οf temperature:
(dT/dt) ≈ -0.4223 K/min
Therefοre, at that instant, the rate οf change οf temperature with respect tο time is apprοximately -0.4223 K/min.
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Under normal conditions the human heart converts about 12.5J of chemical energy per second into 1.25 W of mechanical power as it pumps blood throughout the body. (a) Determine the number of Calories required to power the heart for one day, given that 1 Calorie equals 4186 J. ________ Cal (b) Metabolizing 1 kg of fat can release about 9000 Calories of energy. What mass of metabolized fat (in kg) would power the heart for one day? _____ kg
(a) The number of Calories required to power the heart for one day is 258 Cal.
(b) The mass of metabolized fat that would power the heart for one day is 0.0287 kg.
What is the number of Calories required to power the heart?
The number of Joules of energy required to power the heart for one day is calculated as follows;
Power = 12.5 J / s
Energy = power x time
time = 1 day = 86400 seconds
Energy pumped by heart in one day = 12.5 J/s x 86400 s = 1,080,000 J
The number of calories contained in 1,080,000 J of chemical energy is calculated as;
1 Calorie = 4186 J
= 1,080,000 J / 4186 J
= 258 Cal
The mass of metabolized fat that would power the heart for one day is calculated as;
9000 Cal = 1 kg
258 Cal = ?
= 258 / 9000
= 0.0287 kg
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a person's near point is 25 cm, and her eye lens is 2.7 cm away from the retina. what must be the focal length of this lens for an object at the near point of the eye to focus on the retina?
The focal length of the lens must be 62.5 cm for an object at the near point of the eye to focus on the retina.
The near point of the eye is the closest distance at which the eye can focus on an object. Let's call this distance "p". The distance between the lens and the retina is called the "ocular distance" and is denoted by "d". According to the thin lens equation, the focal length "f" of the lens is related to the object distance "p" and the image distance "q" by the equation,
1/f = 1/p + 1/q
Since the object is at the near point of 25 cm, we can set p = 25 cm. The image distance q is the distance between the lens and the retina, which is d = 2.7 cm. Solving for f,
1/f = 1/p + 1/q
1/f = 1/25 + 1/2.7
1/f = 0.04
f = 25 cm/0.04
f = 62.5 cm
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A ball is thrown vertically into the air. Because of air resistance it's speed when it returns to Its starting starting level compared with its initial speed is
Air resistance occurs when a ball is thrown vertically upward into the air; this causes the ball to move more slowly both up and down. As a result, when it reaches its beginning level, it moves slower than before.
The quantity of air resistance is affected by a number of variables, including the ball's size and shape, the air's density, and its speed. As a result, without further information, it is challenging to estimate the precise amount of speed loss. Yet we can draw some broad conclusions. The speed of the ball reduces as it rises until it reaches its highest point, at which point it briefly stops and starts to descend. The ball drops.
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Can someone please help meeeeeeee! I’m so bad at these stuff. Ill give brainliest too
the daytime temperature on the moon can reach 266 degrees fahrenheit, and the nighttime temperature can get as low as -292 degrees fahrenheit. find the difference between these extremes.
The daytime temperature on the moon can reach 266 degrees Fahrenheit, and the nighttime temperature can get as low as -292 degrees Fahrenheit. To find the difference between these extremes is as follow:
We need to subtract the lower temperature from the higher temperature.
Mathematically, we can represent the problem as follows:
266°F - (-292°F)
= 266°F + 292°F
= 558°F
Therefore, the difference between the extremes of daytime and nighttime temperatures on the moon is 558 degrees Fahrenheit.
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How thermal energy is transferred throughout the water
Answer:
Explanation: Thermal energy is transferred through water by conduction, convection, and radiation. Conduction occurs when heat is transferred through direct contact between water molecules with different thermal energy. Convection occurs when warmer water rises to the top and cooler water sinks to the bottom, creating a circular motion that distributes heat. Radiation is the transfer of energy through electromagnetic waves, but it is not significant in water due to poor conduction. The specific mechanism that dominates heat transfer depends on various factors such as temperature gradient, depth, and presence of other materials.
The process in which electrons move from one object to another is called
A. Active electricity
B. Static Electricity
C. Moving electricity
D. Swapping electricity
B. STATIC ELECTRICITY
IS THE CORRECT ANSWER.
JUST FOR MORE KNOWLEDGE ,,...
EVERY ATOM OF MATTER HAS ELECTRONS , AND THESE ELECTIONS HAVE NEGATIVE ELECTRIC CHARGE WHEN YOU RUB TWO OBJECTS TOGETHER, YOU CAN CAUSE THESE CHARGES TO MOVE FROM ONE OBJECT TO ANOTHER .THIS PULLING FORCE BETWEEN UNLIKE CHARGES IS CALLED STATIC ELECTRICITY .
Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]Select one:6.2 m214.4 m211.3 m218.4 m2
Apply:
C = A e0 / d
Where:
C = capacitance = 1pf = 1 x10^-12 F
A = area
ε0 = 8.85×10^-12
1 pf = 1 x 10^-12 F
A = Cd / ε0 = 1 x 10^-12 ( 1 x 10^-4 ) / 8.85×10^-12 = 1.13 x10 ^-5 m^2
Rasheed ran down the football field at a speed of 7m/s. If he got to the end in 23
seconds, how far did he actually run?
Answer:
The answer is 161 mExplanation:
To find the distance covered we use the formula
distance = velocity × timeFrom the question
velocity = 7 m/s
time = 23 s
We have
distance = 7 × 23
We have the final answer as
161 mHope this helps you
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A child is pulling a toy train along the floor by pulling a piece of string state one contact force and one non contact force that acts on the toy
Answer:
I would say there is friction against the floor, air resistance, and gravity.
Explanation:
The contact force acting on the toy is the frictional force, and the non-contact force acting on the toy is the gravitational force.
Forces acting on the toy:According to the question, a toy train is being pulled by a string along the floor.
The gravitational force acting on the toy train is the weight of the toy train, which is a non-contact force given by:
F = mg
where m is the mass of the toy, and g is the acceleration due to gravity.
Now, the floor will exert a normal force against the toy, equal to the weight of the toy. Let the normal force be N.
Since the toy is in contact with the floor, there is a frictional force acting against the motion of the toy trains, which is a contact force and is given by:
f = μN = μmg
where μ is the coefficient of friction between the toy and the floor.
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How do you solve a line cut by a transversal?
To solve a line cut by a transversal, use the properties of parallel lines, such as corresponding angles and alternate interior angles, to find the unknown angle measurements.
When a line is cut by a transversal, a number of simultaneous equations can be formed by using the properties of parallel lines. For example, the corresponding angles of the lines will always be equal, the alternate interior angles will be equal, and the consecutive interior angles will add up to 180 degrees. Using these properties, you can identify the unknown angle measurements. For example, if the measure of one of the corresponding angles is known, the measure of the other corresponding angle can be determined simply by using the fact that they are equal. Similarly, if one of the alternate interior angles is known, the other can be determined using the fact that they are equal. By forming these equations, you can solve for the unknown angle measurements.
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A loaded truck collides with a car causing huge damage to the car. Which of the following is true about the collision? *
A. The force on the truck is greater than the force on the car
B. The force on the car is greater than the force on the truck
C. The force on the truck is the same in magnitude as the force on the car
D. During the collision the truck makes greater displacement than the car
E. During the collision the truck has greater acceleration than the car
The force on the truck is the same in magnitude as the force on the car.
The impulse experienced by an object during collision is directly proportional to the applied force and time of collision of the objects.
J = Ft
where;
J is the impulse experienced by the objectt is the timeThe increase in the force applied to an object causes an increase in the impulse experienced by the object.
Also, according to Newton's third law of motion, the force exerted on the loaded truck and the car are equal in magnitude but opposite in direction.
Thus, we can conclude that, the force on the truck is the same in magnitude as the force on the car.
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Look at the diagram below. What is the total resistance of the resistors in this circuit?
The total resistance of the resistors in the circuit from the diagram is 20 Ω.
What is resistance?Resistance is a measure of the opposition to current flow in an electrical circuit.
To calculate the total resistance of the resistors in parallel, we use the formula below.
Note: Both resistors are connected in series.
Formula:
For series connection
R = R₁+R₂................ Equation 1Where:
R = Total resistance of the resistor in the circuit.From the diagram,
Given:
R₁ = 10 ΩR₂ = 10 ΩSubstitute these values into equation 1
R = 10+10R = 20 ΩHence, the total resistance is 20 Ω.
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the _____ exerts the largest gravitational force on the earth, and the _____ exerts the largest tidal force on the earth.
The sun exerts the largest gravitational force on the Earth, and the moon exerts the largest tidal force on the Earth.
The sun, being the largest celestial body in our solar system, exerts the largest gravitational force on the Earth. This force is responsible for keeping the Earth in its orbit around the sun and contributes significantly to the stability of our solar system. The gravitational force of the sun also affects the tides on Earth, but its influence is relatively smaller compared to the moon.
The moon, despite being much smaller than the sun, exerts the largest tidal force on the Earth. Tides are the result of the gravitational interaction between the moon and the Earth. The moon's gravitational force creates tidal bulges on the Earth's oceans, leading to the regular rise and fall of the tides.
The gravitational pull of the moon causes the water closest to it to experience a stronger force, resulting in high tide, while the water on the opposite side experiences a weaker force, leading to low tide.
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How does the dancing activity help you in improving fitness skills
•How does the dancing activity help you in improving fitness skills?
Answer:
•Health benefits of dancing
improved condition of your heart and lungs. increased muscular strength, endurance and motor fitness. increased aerobic fitness. improved muscle tone and strength.
Explanation:
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what do acid increase the concentration of in a solution
Answer:
Hydronium (\(H_{3}\)O)
if a system has 46.5 j of heat added to it, and the system does 75.5 j of work on its surroundings, what is the change in the internal energy of the system, in j?
If a system has 46.5 j of heat added to it, and the system does 75.5 j of work on its surroundings. 29 j is the change in the internal energy of the system.
Internal energy refers to the energy that exists within the system. It is represented by the letter "U" in English.
Thermal energy is another name for internal energy. It is the energy of a substance as a result of the kinetic and potential energies connected to the ad hoc motion of all the constituent particles.
Internal energy, which is measured in KJ or Joule, is the energy attributed to the chaotic arrangement or random motion of particles within the system. Using the formula for internal energy, we can calculate the same.
The difference between the heat flow in a system and the work done by or on the system (PV) equals the change in internal energy, and the change in internal energy formula aids in calculating the same.
Energy Equation within the energy of the universe is constant, in accordance with the basic law of thermodynamics.
Additionally, the sum of the work done and the heat transported is equal to the change in a system's internal energy.
Additionally, the sum of the change in the system's internal energy and the work performed by the PV system equals the heat added or flown.
The Change in Internal Energy Formula is:
ΔU = Q + W
Here,
U = the total change in internal energy within the system
Q = the heat exchanged between a system and its surroundings (outside the system)
W = work done by or on the system
= 46.5 - 75.5
= 29j
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i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m
The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.
d (distance) from A to B is = √2gh
In this case given are, g = 9.8 m/s² and h = 100m,
so here d = √(2⋅9.8⋅100) = 44.3m.
Final velocity ,v = √2gh
Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,
g = 9.8 m/s² ,h = 100m,
v = √(2⋅9.8⋅100)
= 44.3 m/s (final velocity)
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For 27.5minutes, a horse ran toward a barn at 136metersperminute. In that time, how far did the horse run? answer as a whole number
Explanation:
Rate * time = distance
136 m/ min * 27 min = 3767 m
What is the acceleration in the scenario below.
An object slows from 20 m/s to 12 m/s in 4 seconds. What is the
acceleration?
-2 m/s^2
2 m/s^2
5 m/s^2
-5 m/s^2
Answer:
\(\huge\boxed{\sf a = -2 \ m/s^2}\)
Explanation:
Given data:Initial velocity = \(V_i\) = 20 m/s
Final velocity = \(V_f\) = 12 m/s
Time = t = 4 s
Required:Acceleration = a = ?
Formula:\(\displaystyle a = \frac{V_f-V_i}{t}\)
Solution:Put the given data in the above formula.
\(\displaystyle a =\frac{12 - 20}{4} \\\\a =\frac{-8}{4} \\\\a = -2 \ m/s^2\\\\\rule[225]{225}{2}\)
How long does it take a bicycle to travel 100 m if it goes a speed of 15 m/s?
The time taken for the bicycle to travel the given distance at the given velocity is 6.667 seconds.
Given the data in the question:
Distance travelled by the bicycle; \(S = 100m\)
Speed or velocity of the bicycle; \(v = 15m/s\)
Time taken for the bicycle to travel the given distance; \(t = ?\)
We know that speed is the rate of change of position of an object with respect to time.
That is to say, Speed = Distance / Time
Hence, Time = Distance / Speed
\(t = \frac{S}{v}\)
So, to get our time "t", we simply substitute in our given values
\(t = \frac{100m}{15m/s}\)
\(t = 6.667 s\)
Therefore, the time taken for the bicycle to travel the given distance at the given velocity is 6.667 seconds.
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rank the light intensity, from largest to smallest, at the point p in the figures.
The light intensity from largest to smallest ranking will be :B > D > A=C > E. where the area is measured on the plane perpendicular to the direction .
In physics, the intensity is the amount of energy that is transmitted per unit area, and the area is measured on a plane perpendicular to the direction that the energy equation will propagate. I = P/ 4(d2), with P denoting power. Let power of 1 bulb equal = P where I = intensity, d = distance at which the intensity must be determined.
case A = I = P / (1) (1) 1 = P case with 2 = P In the situation B = I = 2P/(0.5)2 = 8P C = I = 4P / (2) (2) ^2 = P case Case (1)2 = 3P: D = I = 3P E = I = 2P /(1.5) (1.5) ^2 = 0.8 P
B > D > A=C > E will be the order of light intensity, from greatest to least.
rank the light intensity, from largest to smallest, at the point p in the figures?
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