Information given are: L=65cm =0.65m, f=196Hz, a v=?, Wavelength by: λ=2L, When we put known values into the previous equation we get: λ=2⋅0.650m = 1.30m, And speed is given by: v=λf, v=1.30m⋅196Hz, Finally: a v = 255 m/s, b., f2=392Hz, f3=588 Hz.
Which is the length of a standing wave with four antinodes vibrating on a 60 cm long guitar string?AI's Preferred Response:You need to know the object's length and frequency in order to compute the wavelength of an object that is vibrating.The frequency in this instance is 60 Hz, and the length was 60 cm.This wave has a 2.4 cm wavelength.
How can I determine frequency?
For the given string, L = 65.0 cm = 0.65 m and v = 254.8 m/s. The next two higher resonant frequencies can be calculated as:
f_2 = 2(v/2L) = (2)(254.8 m/s)/(2)(0.65 m) = 196.0 Hz x 2 = 392 Hz
f_3 = 3(v/2L) = (3)(254.8 m/s)/(2)(0.65 m) = 196.0 Hz x 3 = 588 Hz
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Which of the following requires the most work done by the brakes of a car?
A. slowing down from 80 mph to 55 mph
B. Stopping from 55 mph
C. equal amounts of work for both
Stopping from 55 mph requires the most work done by the brakes of a car.
Hence, the correct option is B.
When a car slows down or comes to a complete stop, the work done by the brakes is directly related to the change in kinetic energy of the car. The kinetic energy of an object is given by the equation:
Kinetic energy = (1/2) * mass * \(velocity^2\)
Comparing the options:
A. Slowing down from 80 mph to 55 mph: In this case, the car is experiencing a decrease in velocity, resulting in a decrease in kinetic energy. However, the change in kinetic energy is less compared to option B.
B. Stopping from 55 mph: In this case, the car comes to a complete stop, resulting in a significant decrease in velocity and a substantial change in kinetic energy. The brakes need to dissipate the entire kinetic energy of the car, requiring the most work.
C. Equal amounts of work for both: This option is incorrect. Slowing down from a higher speed to a lower speed (option A) requires less work than coming to a complete stop (option B). The work done by the brakes is directly proportional to the change in kinetic energy, and stopping from a higher speed involves a greater change in kinetic energy.
Therefore, Stopping from 55 mph requires the most work done by the brakes of a car.
Hence, the correct option is B.
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what is the current in a circuit that is powered by a 1.5 V battery and connected in a series by a 3.0 resistor and a 5.0 resistor
The current in the circuit is 0.1875 amperes or 187.5 milliamperes.
To calculate the current in this circuit, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by its resistance (R). In this case, we have two resistors connected in series, so the total resistance (R) is the sum of the individual resistances: 3.0 + 5.0 = 8.0 ohms.
Next, we can use the voltage of the battery (V) as our input, which is 1.5 V. Plugging in the values,
we get: I =\frac{ V}{R }
I= \frac{1.5}{8.0}
I = 0.1875 A (or 187.5 mA).
Therefore, the current in the circuit is 0.1875 amperes or 187.5 milliamperes.
It's important to note that the current is the same throughout the circuit since the resistors are connected in series. Additionally, since the voltage of the battery remains constant, the current flowing through the resistors also remains constant, provided that the resistance of the circuit does not change.
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Step-by-Step on how to calculate 14N = 3.5 kg × 4 m/sec²?
The formula for calculating force is:
force = mass x acceleration
The force is 14 Newtons (N).
What is force?
Force is a physical quantity that describes the interaction between two objects, resulting in the acceleration of one or both objects. Force can cause a stationary object to move or change its direction, or it can alter the speed or direction of a moving object. Force is measured in the unit of Newtons (N) and is represented by the symbol F.
In this case, we have a mass of 3.5 kg and an acceleration of 4 m/sec². To find the force, we simply multiply the two values:
force = 3.5 kg x 4 m/sec²
To calculate this, we can use a calculator or do the multiplication by hand. Here's how to do it step-by-step:
Write down the values given in the problem:
mass = 3.5 kg
acceleration = 4 m/sec²
Write down the formula for force:
force = mass x acceleration
Substitute the values given in the problem into the formula:
force = 3.5 kg x 4 m/sec²
Multiply the two values:
force = 14 kg m/sec²
Simplify the unit by replacing kg m/sec² with Newtons (N), which is the unit of force:
force = 14 N
Therefore, the force is 14 Newtons (N).
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For each of the questions or incomplete statements below, two of the suggested answers will be correct For each of these questions, you must select both correct choices to earn credit. No partial credit will be earned if only one correct choice is selected. Select the two that are best in each case and then enter both of the appropriate letters in the corresponding space on the answer sheet. The figure above shows a representation of a wave traveling in a uniform medium at a particular instant Correct statements about the wave include which of the following? Select two answers The largest distance between two successive dots is the amplitude Distance a is the wavelength It is a longitudinal wave The number of dots per unit length is the frequency
The correct statements about the wave include are distance a is the wavelength (Option B) and the number of dots per unit length is the frequency (Option D).
Wavelength is the distance between two successive points in a wave that are in the same phase (e.g., two consecutive peaks or troughs). In this case, distance a represents that distance. The number of dots per unit length is the frequency: Frequency is the number of wave cycles that pass a given point per unit of time. It is related to the number of dots per unit length in the representation of the wave.
To summarize, the correct answers are that distance a is the wavelength and the number of dots per unit length is the frequency.
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You pull a sled with a package on it across a snow-covered flat lawn. If you
apply a force of 46.8 N to the sled, it accelerates at 0.75 m/s2. What is the
combined mass of the package and the sled? (Assume there is no friction.)
A. 62.40 kg
B. 52.50 kg
C. 96.75 kg
D. 35.10 kg
Answer:
m = 62.4 kg
Explanation:
The force applied to the sled, F = 46.8 N
Acceleration of the sled, a = 0.75 m/s²
We need to find the combined mass of the package and the sled. Let it is m. Using definition of force as follows :
F = ma
\(m=\dfrac{F}{a}\\\\m=\dfrac{46.8}{0.75}\\\\m=62.4\ kg\)
So, the mass of the package and the sled is 62.4 kg.
Answer:A
Explanation:
plaque contains billions of bacteria true or false
Answer:
true
Explanation:
Answer: True
Explanation:
understanding where earthquakes occur can help develop ways to lessen their effects because...please help dudes ;-;
Answer:
build the resilience of the society physically, socially and economically.
Explanation:
They actually build the resilience of the society , physically or socially or economically All three .
the acceleration of an object is due to the net force on the object and the objects?
Answer:
The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object.
The specific heat of copper is 387 J/kg C. The temperature of a 0.35-kg sample of copper decreases from 86.0 °C to 22.0 °C. How much heat flows out of the copper
sample during this temperature drop?
08,700 J
0 9,600 J
O 12,000 J
O15,000 J
The heat flow out of the copper sample during this temperature drop is 9003 J. Rounded to the nearest hundred, the answer is 9,000 J.
To calculate the heat flow, we can use the formula:
Q = mcΔT
Where Q is the heat flow, m is the mass of the sample, c is the specific heat, and ΔT is the change in temperature.
Given:
Mass of copper sample (m) = 0.35 kg
Specific heat of copper (c) = 387 J/kg°C
Change in temperature (ΔT) = 86.0°C - 22.0°C = 64.0°C
Substituting the values into the formula:
Q = (0.35 kg)(387 J/kg°C)(64.0°C)
Q = 9003 J
Therefore, the heat flow out of the copper sample during this temperature drop is 9003 J. Rounded to the nearest hundred, the answer is 9,000 J.
The closest option provided is 8,700 J, which is not an exact match. However, considering rounding or calculation errors, 8,700 J can be considered a reasonable approximation for the heat flow in this scenario.
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A 1.2 m steel rod moves through a uniform magnetic field of 0.020 T at 30 m/s. What emfis induced between the two ends of the steel rod?
0.36 V
0.50 V
0.60 V
0.72 V
Answer:
0.50v
Explanation:
Now EMF is induced when there is motion of a conductor in an electric field. Michael Faraday in the annals of scientific history discovered this.
This is expressed mathematically as;
E = Magnetic field / t
but t = d/ v; d- distance, v-velocity, time
Hence E = magnetic field/ d/v
= Magnetic field× v/ d
= 0.02×30/ 1.2= 0.5
suppose you exert a force of 288 n tangential to a grindstone (a solid disk) with a radius of 0.275 m and a mass of 92.2 kg what is the resulting angular acceleration of the grindstone assuming negligible opposing friction?
The resulting angular acceleration of grindstone assuming negligible opposing friction is \(82.616 rad/s^{2}\).
What is angular acceleration?Angular acceleration can be defined as the temporal rate at which angular velocity changes. The standard unit of measurement is radians per second square. It is also called rotational acceleration. It is a numerical representation of the variation in angular velocity over time.
A pseudoscalar, angular acceleration, exists. If the angular speed rises counterclockwise, the sign of angular acceleration is taken to be positive; if it grows clockwise, it is taken to be negative. Angular acceleration makes it easier to the motion of rotating objects.
The symbol for angular acceleration in SI units is alpha (\(\alpha\)), and it is expressed as radians per second squared (\(rad/s^{2}\)).
We know that,
Force on grindstone, F = 288 N
Radius of grindstone, r = 0.275 m
Mass of grindstone, m = 92.2 kg
The grindstone's angular acceleration must be determined. The relationship between torque and angular acceleration in rotational motion is given by:
τ = I x α
α = τ/I
I is the moment of Inertia of solid disk.
I =\(\frac{mr^{2}}{2}\)
τ represents the torque exerted
τ = F x r
Thus
\(\alpha = \frac{Fr}{\frac{mr^{2}}{2}}\)
\(\alpha = \frac{2Fr}{{mr^{2}}}\)
\(\alpha = \frac{2(288) F}{(92.2 kg) (0.275^{2} m^{2} )}}\)
\(\alpha = 82.616 rad/s^{2}\)
Thus, we can conclude that the angular acceleration of the grindstone is 82.616 \(rad/s^{2}\).
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What is the normal force exerted on the rider when passing point D? (A) 0.2F, (B) 0.8F (C) 1.0F (D) 1
The normal force acting on the rider at point D is equal to the gravitational force, which is indicated by the letter F. So, the appropriate response is (D) 1.
To determine the normal force exerted on the rider when passing point D, we need to consider the forces acting on the rider at that point. The normal force is the force exerted by a surface perpendicular to the surface itself.
In this case, the rider is moving along a circular path, which means there is a centripetal force acting towards the center of the circle. This force is provided by the friction between the rider and the track. At point D, the rider is moving in the upward direction, and the centripetal force is directed towards the center of the circular path.
Considering that the normal force is perpendicular to the track's surface, it must counterbalance the gravitational force acting on the rider. Therefore, the normal force is equal to the rider's weight.
Since the gravitational force is denoted by F, the normal force exerted on the rider at point D is equal to F. Therefore, the correct answer is (D) 1.
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if the mass of the eyeball is 7.6 g , a typical value, what is the effective spring constant of the musculature that holds the eyeball in the socket?
The effective spring constant of the musculature attached to the eyeball is 252 N/m as spring consequently in the recipe the mass of the eyeball ought to be subbed to track down the spring constant of the muscle.
The idea expected to take care of this issue is that when two bodies are in reverberation then it implies that they have same recurrence.
In order to determine the resonating system's spring constant, first create the formula for the spring mass system frequency and then substitute the eyeball's mass and frequency.
Resonance:If the vibrational frequency of two bodies is the same, they are said to be in resonance.
Recurrence for spring mass framework:
f = \(\frac{1}{2} \sqrt{\frac{k}{m} }\)
f is the recurrence of the spring mass framework, m is the mass of the connected body, and k is the spring constant of the body.
29 Hz is the frequency at which the head blurs the image.The normal recurrence of the eyeball is 29 Hz. Because the head and the eye have the same natural frequency, they are in resonance, and the image seen is blurry.
The eyeball has a frequency of 29 Hz if we consider the eyeball and muscle to be a spring mass system.
The frequency at which a system cannot vibrate is known as the natural frequency. The system's natural frequency or one of its harmonics should be used to vibrate it.
The spring constant of the muscle is determined utilizing the accompanying recipe:\(f = \frac{1}{2\pi } \sqrt{\frac{k_{m} }{m_{c} } }\)
\(\sqrt{\frac{k_{m} }{m_{c} } } = 2\pi f\)
km = 4π²f²\(m_{e}\)
km = 4π²(29Hz)²( 7.6 g)
= 4π²( 29Hz)²7.6 g /1000g × 1 kg
= 4π²( 29Hz)²7.6 × 10⁻³ kg
= 252 N/m
Here the body which is vibrating is eyeball and the muscle is going about as spring consequently in the recipe the mass of the eyeball ought to be subbed to track down the spring constant of the muscle.
Incomplete question :
Vision is blurred if the head is vibrated at 29 {\rm Hz} because the vibrations are resonant with the natural frequency of the eyeball held by the musculature in its socket.
If the mass of the eyeball is 7.5 {\rm g}, a typical value, what is the effective spring constant of the musculature attached to the eyeball?
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8.3 calculate the synodic period of venus relative to the earth. {ans.: }
The synodic period of Venus relative to Earth is the time it takes for Venus to return to the same position in the sky as seen from Earth.
This is because the synodic period is based on the alignment of the Earth, Venus, and Sun. Venus takes about 225 days to complete one orbit around the Sun, while Earth takes about 365 days. Therefore, the synodic period of Venus is calculated as the reciprocal of the difference between the inverse of Venus' orbital period and the inverse of Earth's orbital period, which is approximately 584 days. In other words, Venus and Earth will be in conjunction (when they appear closest together in the sky) every 584 days. This synodic period is an important concept in astronomy, as it is used to predict future planetary alignments and conjunctions.
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forces can be________. What phrase completes the sentence.
1.Pushes only
2.Pushes or pulls
3.Pulls only
Answer:
pushes or pulls
Explanation:
hope this helps....
a doubly charged ion is accelerated to an energy of 36.0 kev by the electric field between two parallel conducting plates separated by 1.60 cm. what is the electric field strength (in v/m) between the plates?
The electric field strength between the conducting plates would be 3.6 x 10⁵ V/m.
What is electric field strength?
Electric field strength (E) is a measure of the force exerted on a charged particle by an electric field. It is measured in units of volts per meter (V/m) or newtons per coulomb (N/C). An electric field can be created by a static charge or by a changing magnetic field. The strength of the electric field is affected by the distance from the source of the field, the charge of the source, and the permittivity of the medium. Electric fields are used in many applications, including in electric motors, generators, and particle accelerators. It is also used in the study of charges and the behavior of conductors and insulators.
The electric field strength (E) can be determined by using the equation: E = W / qd
Where,
W = energy of the ion (36.0 keV)
q = charge of the ion (doubly charged ion, so 2e)
d = distance between the plates (1.60 cm)
To convert keV to J and cm to m:
1 keV = 1.602176634 x 10⁻¹⁶ J
1cm = 0.01m
Therefore,
E = (36.0 x 1.602176634 x 10⁻¹⁶ J) / (2e x 0.01m)
E = (57.634 x 10⁻¹⁶J/C) / (2 x 1.602176634 x 10⁻¹⁹ C x 0.01m)
E = 3.6 x 10⁵ V/m
So, the electric field strength between the plates is 3.6 x 10⁵ V/m.
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If a sample of a radioactive isotope has a half-life of 1 year, how much of the original sample will be left at the end of the second year?
Answer:
1/4 of the original
Explanation:
That would be TWO half lives:
1/2 * 1/2 = 1/4 <======= 1/4 would be left
with the aid of a string, a gyroscope is accelerated from rest to 36 rad/s in 0.7 s. (a) what is its angular acceleration in rad/s2? 51.43 correct: your answer is correct. rad/s2 (b) how many revolutions does it go through in the process?
The principles of angular motion's equations of motion are relevant to this query.
a) An angular acceleration of "80 rad/s2" will occur.
b) During the procedure, it completes "1.02 revolutions."
What is angular acceleration?Acceleration is the effect of a changing velocity. We refer to an object as speeding angularly if it is spinning and its speed is changing
To determine the angular acceleration, we shall utilize the first equation of motion for angular motion:
where,
= angle-moving speed =?
= 32 rad/s for the final angular speed
= 0 rad/s for the initial angular speed
t = time spent = 0.4 s
Therefore,
b)To determine the number of rotations, we will now utilize the second equation of motion for the angular motion:
where,
Angle displacement equals:?
Therefore,
Following are the numbers for the number of revolutions (N):
1.02 rotations per N
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If your weight is 588N on the earth, how far should you go from the centre of the earth so that your weight will be 300N? The radius of the earth is 6400km and the value of g on the earth surface is 9.8m/s2.
Answer:
Hmm, Well I am pretty sure the answer is 288N
Explanation:
I got the answer 288N but I am not sure if that is correct. Hope it helps! :D
a rifle is aimed horizontally at a target 86.48 m away. the bullet hits the target 2.58 cm below the aim point. what was the bullet's flight time?
After applying the kinematic relation, the bullet’s flight time would be 0.0726 s
The kinematic equations are a set of four equations that can be used to make predictions about information regarding an item's motion that is unknown, provided that other information regarding the motion of the object is known. The equations can be applied to any motion that can be characterized as either having a constant velocity (an acceleration of 0 m/s/s) or a constant acceleration (an acceleration of 0 m/s/s), and they can be used to analyze both types of motion. They are never permitted to be used during any time frame in which the acceleration is undergoing a change.
In this case we will be using the third kinematic relation:
d = vt + ½ gt²
in this case, we are given that:
d = (2.58 cm × ( 1 m ÷ 100 cm))
v = 0 m/s
g = 9.8 m/s
Thus, the bullet’s flight time would be:
(2.58 cm × ( 1 m ÷ 100 cm)) = (0 m/s) × t + ½ (9.8 m/s) × t²
½ (9.8 m/s) × t² = (2.58 cm × ( 1 m ÷ 100 cm))
T = √0.005265
T = 0.0726 s
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Need help on this question??please
*(d) The map below shows the positions of some seismic earthquake stations in the UK.
nd
TE
At the seismic stations, scientists record the arrival of earthquake waves.
They use this data to locate where an earthquake happened.
Describe how they use the data to find out where an earthquake happened.
You may add to the diagram above or draw your own diagram to help with your
answer.
Vnjbsdjvbsdbv
(6)
Scientists use the arrival times of seismic waves at multiple stations, along with amplitude data, to triangulate the location of an earthquake epicenter.
To determine the location of an earthquake, scientists use the data recorded at seismic stations. The seismic stations are equipped with seismometers that detect and record seismic waves generated by the earthquake. These waves travel through the Earth's interior and arrive at different times at various seismic stations.To locate the epicenter of the earthquake, scientists analyze the time differences between the arrivals of primary (P) waves and secondary (S) waves at multiple stations. P waves are faster and arrive first, followed by slower S waves. By comparing the time interval between the arrival of P and S waves at different stations, scientists can calculate the distance of each station from the earthquake epicenter.
Using the distances from at least three seismic stations, scientists plot circles around each station on a map. These circles represent the potential distance between the station and the epicenter. The intersection of the circles determines the most likely location of the earthquake epicenter. This method is known as the "triangulation" technique.Additionally, the amplitude of the recorded seismic waves provides information about the earthquake's magnitude. By analyzing the amplitude data from different stations, scientists can estimate the earthquake's size or magnitude.
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Note- Sorry The diagram cannot be added .
How do force affect the acceleration of a body?
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
It is estimated that the human brain has a power requirement of 40W. How much energy does it use in an hour?
Explanation:
P=40w
T=1hrs
=1×60=60
Now,
P2=40×60=2400
Hence, in a hour, the brain uses 2400w
Choose the law that BEST explains the example:
Throwing a ball with more force to increase acceleration is an example of Newton’s
first law?
2nd law
third law
none of these
488 nm light passes through a single
slit. The first (m = 1) diffraction
minimum occurs at an angle of
0.559º. What is the width of the slit?
[?] x 10-5 m
Answer:
5.00
Explanation:
a sinθ=mλ
You are missing (a) so you move sinθ to the other side than solve from there.
For first diffraction, the width of the slit is \(5*10^{-5} m\).
What is diffraction?Diffraction of light is defined as the bending of light around corners such that it spreads out and illuminates areas where a shadow is expected.
a sinθ=mλ
\(a = \frac{1*488*10^{-9} }{sin 0.559}\)
\(a = 5*10^{-5} m\)
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You lift a 44 N box from the floor and place it on a shelf that is 1.5 m above the ground . How much work did you use in lifting the box ?
Answer:
W = 66 J
Explanation:
Given that,
The weight of the box, W = 44 N
It is placed on a shelf that is 1.5 m above the ground.
We need to find the work done in lifting the box.
We know that,
Work done, W = Fd
So,
W = 44 N × 1.5 m
= 66 J
So, the required work done is equal to 66 J.
NEED HELP!!!!!
Chandra is setting up her exercise program. She is interested in losing a little weight, so she would like higher than average aerobic activity. What would be the BEST way to add about 30 percent more aerobic activity to her week?
options:
A.
100 minutes of intense activity weekly
B.
100 minutes of moderate activity weekly
C.
250 minutes of intense activity weekly
D.
250 minutes of moderate activity weekly
PLEASE NO LINKS
Answer:
c
Explanation:
would be the BEST way to add about 30 percent more aerobic activity to her week, She is interested in losing a little weight, so she would like higher than average aerobic activity, 250 minutes of moderate activity weekly would be the BEST way to add about 30 percent more aerobic activity to her week
What is the unit of weight ?Weight can be defined as the force at which the gravitational field pulls the object towards the earth’s surface which is the center of gravity which has a specific force attracts objects towards it.
The SI unit of weight of kg/mt/sq sq. is Newton (N),
W = 1 kg (mass) X 1 mtr/sec sq (force of gravity), Unit of Weight is calculated as the product of mass, distance, and time.
Dimensional Unit of weight (W) = Mass (M) X Distance (L) X Time (t sq) CGS unit of Weight is represented as Dyne, in terms of the product of centimeter gram and seconds.
The Basic Unit of Weight has the same value as that of the SI unit of weight and other units of weights also used includes gram, slug, pound-force, etc.
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how do you know which magnitude is higher or how do you compare them?
1.2 A 7,5 kW, 230 V-shunt motor has a full-load speed of 1 200 r/min. The resistance of the armature and field circuits are 0, 3 ohm and 180 ohms, respectively. The full-load efficiency of the motor is 86 per cent. Ignore the effect of armature reaction. Calculate the following: 1.2.1 The speed at which the motor will run on no-load, if the total no- load input is 600 W (9) 1.2.2 a The value of a resistance to be added in the armature circuit to reduce the speed to 1 000 r/min when giving full-load torque. Assume that the flux is proportional to the field current (5) [18]
The speed at which the motor will run on no-load can be determined by using the concept of the motor's input and output power.
Given:
Full-load power (output power) = 7.5 kW
Full-load efficiency = 86% = 0.86
Total no-load input power = 600 W
First, we can calculate the full-load input power using the efficiency formula:
Full-load input power = Full-load power / Full-load efficiency
Full-load input power = 7.5 kW / 0.86 = 8.72 kW
Now, we can determine the ratio of the no-load input power to the full-load input power:
Power ratio = Total no-load input power / Full-load input power
Power ratio = 600 W / 8.72 kW = 0.0688
Since power is directly proportional to the speed of the motor, we ca
calculate the speed on no-load using the power ratio
No-load speed = Full-load speed * √(Power ratio)
No-load speed = 1,200 r/min * √(0.0688) ≈ 292.78 r/min
Therefore, the motor will run at approximately 292.78 r/min on no-load.
1.2.2 To reduce the speed to 1,000 r/min when giving full-load torque, we need to add a resistance in the armature circuit. The speed of the motor is inversely proportional to the armature circuit resistance.
Given:
Full-load speed = 1,200 r/min
Target speed = 1,000 r/min
Using the speed ratio formula:
Speed ratio = Full-load speed / Target speed
Speed ratio = 1,200 r/min / 1,000 r/min = 1.2
Since the speed is inversely proportional to the resistance, we can calculate the resistance ratio:
Resistance ratio = 1 / Speed ratio
Resistance ratio = 1 / 1.2 ≈ 0.833
Now, we can calculate the required resistance to be added in the armature circuit:
Required resistance = Armature circuit resistance * Resistance ratio
Required resistance = 0.3 ohm * 0.833 ≈ 0.25 ohm
Therefore, a resistance of approximately 0.25 ohm needs to be added in the armature circuit to reduce the speed to 1,000 r/min when giving full-load torque, assuming the flux is proportional to the field current.
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