a half-wave dipole in free space is center-fed with a current of 10 amp. the frequency is 300 mhz. a) at a distance of 1,000 meters from the dipole, which is in the far field, and in a direction that is 30 degrees from the dipole axis, what is the field strength in volts per meter? b) another half-wave dipole antenna is placed at the reception point, oriented parallel to the transmitter antenna. how much power is available at the terminal of the receiving antenna?

Answers

Answer 1

The power available at the terminal of the receiving antenna is approximately\(2.97 x 10^-11 watts.\)

a) To calculate the electric field strength at a distance of 1,000 meters from the center-fed half-wave dipole, we can use the following formula:

\(E = (120π * I * l * sin θ) / r\)

where:

I = current in amperes

l = length of the dipole in meters

θ = angle between the direction of observation and the dipole axis in radians

r = distance from the dipole in meters

Plugging in the given values, we get:

\(E = (120π * 10 * 0.5 * sin(30°)) / 1000\\E = 0.198 V/m\)

Therefore, the electric field strength in volts per meter at a distance of 1,000 meters from the dipole, in a direction that is 30 degrees from the dipole axis, is approximately 0.198 V/m.

b) The power received by the second half-wave dipole antenna is given by the Friis transmission formula:

\(Pr = Pt * Gt * Gr * (λ / 4πr)^2\)

where:

Pr = received power

Pt = transmitted power (assumed to be radiated equally in all directions)

Gt = gain of the transmitting antenna (assumed to be 1 for a half-wave dipole)

Gr = gain of the receiving antenna (assumed to be 1 for a half-wave dipole)

λ = wavelength of the signal in meters (given by λ = c / f, where c is the speed of light and f is the frequency)

r = distance between the two antennas in meters

Plugging in the given values, we get:

\(λ = c / f = 3 x 10^8 / 300 x 10^6 = 1 meter\\\\r = 1000 meters\\Pr = Pt * Gt * Gr * (λ / 4πr)^2\\Pr = 10 * 1 * 1 * (1 / 4π * 1000)^2\\Pr = 2.97 x 10^-11 watts\\\)

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Related Questions

think critically a friend ask you to get his favorite item from the kitchen,but he uses chemical formulas to ask for it. He ask fir a drink which does not contain H2CO3,but does have H2C6H6O6. what might he be asking for?

Answers

Carbonic acid, which is frequently found in carbonated beverages such as soda, is denoted by the chemical formula H2CO3. In contrast, the formula H2C6H6O6 pertains to a different compound, which is a type of organic acid.

Based on the information provided, it appears that your acquaintance is requesting a beverage that does not contain carbonic acid but does contain an organic acid with the formula H2C6H6O6.

Lemonade, which includes citric acid, is one prevalent type of drink that fits this description. Citric acid's chemical formula is C6H8O7, but it can also be written as H3C6H5O7 or H2C6H6O6 if only the acidic properties of the molecule are considered.

As a result, if your friend requests a drink that does not contain H2CO3 but does contain H2C6H6O6, he may be requesting lemonade or another form of beverage containing citric acid.

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 Find the average acceleration of a northbound subway train that slows down from 12 m/s to 9.6 m/s in 0.8 seconds.​

Answers

Answer:

\(a=-3\ m/s^2\)

Explanation:

Given that,

Initial speed of a train, u = 12 m/s

Final speed of a train, v = 9.6 m/s

Time taken, t = 0.8 s

We need to find the average acceleration of the train. We know that the rate of change of velocity is equal to acceleration. So,

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{9.6-12}{0.8}\\\\a=-3\ m/s^2\)

So, the average acceleration of the train is equal to \(-3\ m/s^2\).

How weak is the value of g at an altitude of 300 km, with g being the force of gravity?

Please provide a thorough explanation of how you got your answer with the equations used/needed.

Answers

The gravitational force is inversely proportional to the distance from the surface of earth. Thus, value of g will be lower at higher altitudes.

What is gravitational force?

Gravitational force is a kind or force by which an object attracts other objects into its center of mass. It is dependent on the mass of the objects and distance between them.

According to the law of universal gravitation, the force of gravitation g is written as:

g = Gm/ r²

Here. m is the mass, G be the gravitational constant and r be the distance from the surface.

Thus, as per this equation g is inversely proportional to the square of the distance from earth's surface. Therefore, at higher altitudes, the gravity will be slightly lower,

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If the harmonic is 66 Hz, find the fundamental frequency

If the harmonic is 66 Hz, find the fundamental frequency

Answers

Pretty sure it’s 11hz

When an atom changes by alpha decay, its atomic number

Answers

When an atom changes by alpha decay, its atomic number decreases because of the losing of proton and neutron.

What changes occur when alpha decay occur?

An alpha particles is a helium nucleus that contains 2 protons and 2 neutrons. When the alpha decay occur, the atom loses an alpha particle which causes the loss of proton and neutron thus decreases the mass number as well as atomic number occur.

So we can conclude that When an atom changes by alpha decay, its atomic number decreases because of the losing of proton and neutron.

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Which axis is the horizontal axis in a graph?*
Oy-axis
O
Z-axis
O Axis of Evil
X-axis

Answers

X-axis is horizontal
I think its a X-axis

The following statements are all true. Which one counts as an "exception to the rule" in being unusual for our solar system?
Venus does not have a moon.
Jupiter has a very small axis tilt.
The diameter of Earth's Moon is about 1/4 that of Earth.
Saturn has no solid surface.

Answers

The statement that counts as an "exception to the rule" in being unusual for our solar system is: "Saturn has no solid surface." Option D is the correct answer.

What is  solar system?

This refers to  a group that includes one or more suns along with planets, moons, asteroids, comets, and other extraterrestrial object. Our solar system includes one sun and nine planets.

There are nine planets in the solar system. The four inner terrestrial planets are Mercury, Venus, Earth, and Mars, all of which consist mainly of rock. The four outer planets are Jupiter, Saturn, Neptune, and Uranus, giant planets that consist mainly of either gases or ice and Pluto.

While other gas giants in our solar system also lack a solid surface, such as Jupiter, Uranus, and Neptune, it is unusual for a planet to not have a solid surface. The majority of the planets and moons in our solar system have a solid surface, so Saturn's lack of one is exceptional.

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marta flies past you at 75% of the speed of light, traveling in a spaceship that would measure 50 meters from end to end if it were at rest in your reference frame. if you measure the length of her spaceship as it goes by, how long will it be from end to end? b. the star sirius is located 8.6 light-years from earth (in our earth-based reference frame). suppose you travel from earth to sirius at 92% of the speed of light. during your trip, how far would you measure the distance from earth to sirius to be?

Answers

The length of Marta's spaceship as it goes by will be 33 meters from end to end using Lorentz Contraction formula and the distance from Earth to Sirius as measured during the trip would be 22.6 light-years by using relativistic formula for length contraction.

What is Lorentz Contraction formula and relativistic formula for length contraction ?

The Lorentz Contraction formula states that the length of an object as measured in a reference frame moving at velocity v with respect to an observer is given by.

\(L=L_{0}\sqrt{1-\frac{v^{2} }{c^{2} } } }\)

where \(L_{0}\) is the length of the object at rest in the observer's reference frame, v is the velocity of the object relative to the observer, and c is the speed of light.To find the length of Marta's spaceship as it goes by, we need to use the Lorentz Contraction formula

The relativistic formula for length contraction states that, the length of an object as measured in a reference frame moving at velocity v with respect to an observer is given by.

\(L=\frac{L_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }\)

To find the distance from Earth to Sirius as measured during the trip, we need to use the relativistic formula for length contraction.

Calaculation

For a part

In this case, it is given that  \(L_{0}\) = 50 m, v = 0.75c, and c = 3×\(10^{8}\)m/s. Plugging in the values, we get.

\(L = 50 m * \sqrt{(1 - (0.75^2))}\)

\(L = 50 m * \sqrt{(1 - 0.5625)}\)

\(L = 50 m * \sqrt{(0.4375)}\)

\(L = 33 m\)

So, the length of Marta's spaceship as it goes by will be 33 meters from end to end.

For b part

In this case, \(L_{0}\) = 8.6 light-years, v = 0.92c, and c = 3 x 10^8 m/s. Plugging in the values, we get.

\(L= \frac{ 8.6}{\sqrt{(1 - (0.92^2))} }\)

\(L= \frac{ 8.6}{\sqrt{(1 - 0.8544)} }\)

\(L= \frac{ 8.6}{\sqrt{(0.1456)} }\)

\(L= 22.6\)

So, the distance from Earth to Sirius as measured during the trip would be 22.6 light-years.

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asynchronous communications does not happen in real time.

Answers

When communication occurs asynchronous, it doesn't happen immediately (e.g. on the phone, in-person, or during a live video conferencing meeting). The statement is true

What about asynchronous communication is accurate?

Information can be exchanged asynchronously when there is no need for timing. The recipient can respond to the message whenever it is convenient for them because it doesn't demand their immediate attention. Emails, forums, and group documents are a few examples of asynchronous communication.

What drawback does asynchronous communication have?

Despite all of its benefits, asynchronous communication for distant teams has drawbacks. feelings of loneliness Some employees may feel alone or alienated due to a lack of in-person interactions or meetings. There is no relationship.

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Asynchronous communications does not happen in real time.

True/ false

Conclusion: Suggest an equation relating Felect, q1, q2 and d of the form Felect = k•... where k is a proportionality constant (no need to determine its value). Place the three variables q1, q2 and d on the right side of the equation in a numerator or a denominator; use a power if needed. Your equation should be consistent with your claims made in Challenge #1 and Challenge #2. *I already solved the rest of the worksheet, I only need the conclusion.*

Answers

Answer:

\(F_{elect} = \frac{kq_1q_2}{d^2}\)

Explanation:

Consider the given variables:

Felect = Electrostatic Force between charged particles

k = Coulomb's Constant

q₁ = magnitude of first charge

q₂ = magnitude of second charge

d = distance between the charges

The relationship among these variables is given by the Coulomb's Law:

\(F_{elect} = \frac{kq_1q_2}{d^2}\)

This is the relationship that contains k, q₁, q₂, d on the right-hand side and Felect on the left-hand side.

Earthquakes at fault lines in Earth's crust create seismic waves, which are longitudinal (P-waves) or transverse (S-waves). The P-waves have a speed of about 5 km/s. Estimate the average bulk modulus of Earth's crust given that the density of rock is about 2,900 kg/m3

Answers

The bulk modulus is a measure of the resistance of a material to compression and is an important parameter for understanding the behavior of seismic waves in the Earth's crust during earthquakes.

The speed of longitudinal waves (P-waves) in a solid is given by:

v = √(K/ρ)

where v is the velocity of the wave, K is the bulk modulus, and ρ is the density of the medium.

Rearranging the above equation, we get:

K = ρ * v^2

Substituting the given values, we get:

K = 2,900 kg/m^3 * (5,000 m/s)^2

K ≈ 7.25 x 10^10 N/m^2

Therefore, the average bulk modulus of Earth's crust is approximately 7.25 x 10^10 N/m^2. This value is consistent with the bulk moduli of various types of rocks that make up the Earth's crust, which typically range from 5 x 10^9 N/m^2 to 100 x 10^9 N/m^2.

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54(a) Define the capacitance of a capacitor
(b) State:
three factors on which the capacitance
a parallel plate capacitor depends.
(ii) two uses of capacitors.
(c) The plates of a parallel - plate capacitor
are 5mm apart and 2m² in area. The plates
are in vacuum. A potential difference of 1kv
is applied across the capacitor.
Calculate the:
(i)
Capacitance
(ii) charge on each plate
ii) electric intensity in the space between them
iv) energy stored in the capacitor
[NECO,2000] [Permitivity of free space.
Do=8.85x10-¹² Nm²C²1

Answers

a) The ratio of the electric charge on each conductor to the potential difference (i.e., voltage) between them is used to express capacitance.

b) The area of the plates, the spacing between them, and the type of insulating material or dielectric between them are the three variables that have an impact on a parallel-plate capacitor's capacitance.

c) The area of each plate, the dielectric material separating the plates, and the distance between the plates all affect the capacitance of a parallel plate capacitor.

What is Capacitor?An electrostatic field of energy is stored in a capacitor, a passive electrical component. A capacitor is made up of two conducting plates and an insulating substance called the dielectric in its most basic form.Farads (F), which bear the name of English physicist Michael Faraday, are the units used to measure the capacitance of a capacitor (1791–1867). There is a lot of capacitance in a farad.a capacitor is an electrical energy storage device that consists of two conductors that are isolated from one another and placed near to one another. A straightforward illustration of such a storage system is the parallel-plate capacitor.A dielectric material and two metal plates serve as the building blocks of a capacitor.

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On a cello the 0.68 m long strings are turned by winding one end around a peg or fret. For a peg diameter of 15mm, calculate how many turns will be necessary to achieve a tension in the 1.36 mm diameter string of 84 N (approximately middle G)

Answers

The number of turns turned by winding around a peg are calculated to be 0.003.

Extension δ is given by the formula,

δ = εL = σL/E = FL/AE

where, F is force

L is length

A is area

E is modulus of elasticity

⇒ (84 × 0.68)/[π(1.36 × 10⁻³)²/4](210 × 10⁹) = 0.00019 m

And this is wrapped around the peg's circumference,

Number of turns n = 0.00019/π d = 0.00019/π(15 × 10⁻³) = 0.003 times or about 1.4 degrees.

The peg needs to be turned 1.4 degrees.

Thus, the number of turns turned by winding around a peg are calculated to be 0.003.

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Pete the Penguin loves to sled down his favorite hill. If he hits a speed of
50 m/s after 5 seconds, what is his rate of acceleration? Hint: He starts at
O m/s at the top of the hill.

Answers

a= v2-v1/t 50-0/5 = 10m/s

Answer:

10 m/per second

Explanation:

he speeds up 10 m in a single second

What defines a mixture?
for sience

Answers

In chemistry, a mixture is a material made up of two or more substances which are not chemically combined.

Hope this helps :)

The weakest gravitational force caused by the Moon is called the __________, which is found at the point on Earth farthest from the Moon.

Answers

This is called Nadir.

calculate the energy released when 0.521 kg of p-32 undergoes beta emission. (masses listed below)

Answers

The energy released when 0.521 kg of p-32 undergoes beta emission is 7.419126 x 10^-2 J.

When 0.521 kg of p-32 undergoes beta emission, it undergoes a nuclear decay process where a neutron is converted to a proton, emitting an electron and a neutrino. This process releases energy in the form of radiation. To calculate the energy released, we need to use the mass difference between the parent and daughter nucleus. The mass of p-32 is 31.9739076 u, while the mass of the daughter nucleus is 32.0236649 u.

The difference is 0.0497573 u, which is equivalent to 8.265696 × 10^-14 kg. Using Einstein's famous equation, E=mc^2, we can calculate the energy released as E = (8.265696 × 10^-14 kg) x (299,792,458 m/s)^2 = 7.419126 x 10^-2 J.

Therefore, the energy released when 0.521 kg of p-32 undergoes beta emission is 7.419126 x 10^-2 J.

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Learning Goal: To understand that centripetal acceleration is the acceleration that causes motion in a circle. Acceleration is the time derivative of velocity. Because velocity is a vector, it can change in two ways: the length (magnitude) can change and/or the direction can change. The latter type of change has a special name, the centripetal acceleration. In this problem we consider a mass moving in a circle of radius R with angular velocity ω, r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^] =Rcos(ωt)i^+Rsin(ωt)j^. The main point of the problem is to compute the acceleration using geometric arguments. (Figure 1) Part A What is the velocity of the mass at a time t? You can work this out geometrically with the help of the hints, or by differentiating the expression for r⃗ (t) given in the introduction. (Figure 2) Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (t) = Part Assume that the mass has been moving along its circular path for some time. You start timing its motion with a stopwatch when it crosses the positive x axis, an instant that corresponds to t=0. [Notice that when t=0, r⃗ (t=0)=Ri^. ] For the remainder of this problem, assume that the time t is measured from the moment you start timing the motion. Then the time − t refers to the moment a time t before you start your stopwatch. Part B What is the velocity of the mass at a time − t? Express this velocity in terms of R, ω, t, and the unit vectors i^ and j^. V⃗ (−t) = SubmitMy AnswersGive Up Part C What is the average acceleration of the mass during the time interval from − t to t? (Figure 3) Express this acceleration in terms of R, ω, t, and the unit vectors i^ and j^.

Answers

Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.

Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).

Part B :

We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :

The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)

The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore

\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)

The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).

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select the intermolecular forces present in water. group of answer choices h-bonding ion-dipole london dispersion dipole-dipole

Answers

The intermolecular forces present in water include hydrogen bonding and dipole-dipole interactions.

Water is a polar molecule, meaning it has a positive and a negative end due to an uneven distribution of electron density. This polarity gives rise to intermolecular forces that hold water molecules together.

One of the intermolecular forces present in water is hydrogen bonding. Hydrogen bonding occurs when a hydrogen atom, which is covalently bonded to an electronegative atom (in this case, oxygen), is attracted to another electronegative atom (such as oxygen or nitrogen) in a different molecule. In water, the oxygen atom of one water molecule forms a hydrogen bond with a hydrogen atom of a neighboring water molecule. Hydrogen bonding is a strong intermolecular force and contributes to many of the unique properties of water, such as its high boiling point and surface tension.

In addition to hydrogen bonding, water also exhibits dipole-dipole interactions. Dipole-dipole interactions occur between the positive end of one polar molecule and the negative end of another polar molecule. In water, the positive hydrogen end of one water molecule is attracted to the negative oxygen end of a neighboring water molecule. These dipole-dipole interactions are weaker than hydrogen bonds but still contribute to the overall intermolecular forces present in water.

Other intermolecular forces, such as ion-dipole interactions and London dispersion forces, are not as significant in water compared to hydrogen bonding and dipole-dipole interactions. Ion-dipole interactions occur between an ion and the charged end of a polar molecule, while London dispersion forces arise from temporary fluctuations in electron distribution. While these forces may exist in other substances, they play a relatively minor role in the intermolecular forces of water.

In conclusion, the intermolecular forces present in water are primarily hydrogen bonding and dipole-dipole interactions. These forces contribute to the unique properties and behavior of water as a liquid.

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Write the following in expanded form. 4.35 x 10^6

Answers

4.35x10x10x10x10x10x10 if you wanted complete expanded form it would be
4+.3+.05x10x10x10x10x10x10

The given expression can be written in an expanded form as 4,350,000

Given expression:

\(4.35 \times 10^6\)

To find:

the expanded form of the expression

To expand the given expression, multiply 4.35 by 1,000,000

\(= 4.35 \times 1,000,000\)

move the decimal point six (6) places to the right and you will obtain the following result.

\(= 4,350,000\)

Therefore, the expanded form of the expression is 4,350,000

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PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?

Answers

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object  2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

Pedro picked up and held a cube of ice in his hand and noticed that he no longer felt a difference in temperature after the ice cube melted in his hand. Which of the following statement best explains what happened?
1.Heat was transferred from Pedro’s hand to the ice increasing the temperature of the ice.
2.Heat was released from the ice cube into the air increasing the temperature of the ice.
3.Cold was transferred to Pedro’s hand from the ice increasing the temperature of the ice.
4.Heat was released from Pedro’s hand into the air melting the ice increasing the temperature of the ice.

Answers

Answer:

the answers is 1.

Explanation:

this is because heat always travel's from the warmest object to the coldest. His hands thermal energy is transferred to the ice making the ice round to the same temperature of his hand. This can also be an example of equalibrum.

Air is compressed by an adiabatic compressor from 100 kPa and 12∘C to a pressure of 800 kPa at a steady rate of 0.2 kg/s. If the isentropic efficiency of the compressor is 80 percent, determine
(a) the exit temperature of air and
(b) the required power input to the compressor

Answers

The required power input to the compressor is 55.7932 kW

To solve this problem, we need to use the following equations:

The adiabatic relation for an ideal gas:

\(P^\)((γ-1)/γ) * T = constant

where P is the pressure, T is the temperature, and γ is the ratio of specific heats for the gas.

The isentropic efficiency of the compressor:

η = (actual work input)/(isentropic work input)

where η is the efficiency and work input is the energy input required to compress the gas.

(a) To find the exit temperature of air, we can use the adiabatic relation for an ideal gas. Since the compression is adiabatic, there is no heat transfer involved. Therefore, the process is also isentropic. We can assume air to be an ideal gas with a ratio of specific heats γ = 1.4.

At the inlet, P1 = 100 kPa and T1 = 12°C = 285.15 K

At the exit, P2 = 800 kPa

The mass flow rate is given as mdot = 0.2 kg/s

Using the adiabatic relation, we can write:

\(P1^((γ-1)\)/γ) * T1 =\(P2^\)((γ-1)/γ) * T2

Solving for T2, we get:

T2 = T1 * \((P2/P1)^((γ-1)/γ)\)

T2 = 285.15 *\((800/100)^((1.4-1)/1.4)\)

T2 = 450.5 K

Therefore, the exit temperature of air is 450.5 K or 177.35°C.

(b) To find the required power input to the compressor, we can use the isentropic efficiency equation. The actual work input is given by:

W_actual = mdot * (h2 - h1)

where h1 and h2 are the specific enthalpies at the inlet and exit, respectively. Since the process is isentropic, we can assume h2s = h2. The isentropic work input is given by:

W_isentropic = mdot * (h2s - h1)

Using the isentropic efficiency equation, we can write:

η = W_actual/W_isentropic

0.8 = (mdot * (h2 - h1))/(mdot * (h2s - h1))

0.8 = h2/h2s

h2 = 0.8 * h2s

Using the thermodynamic property tables for air, we can find the specific enthalpies h1 and h2s at the inlet and exit, respectively.

At 100 kPa and 12°C, h1 = 293.05 kJ/kg. At 800 kPa and 177.35°C, h2s = 710.02 kJ/kg.

Substituting these values, we get:

h2 = 0.8 * 710.02 = 568.016 kJ/kg

Therefore, the actual work input is:

W_actual = mdot * (h2 - h1) = 0.2 * (568.016 - 293.05) = 55.7932 kW

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A butterfly flaps its wings 100 times in 10 seconds. What is the period and frequency? If the speed of sound is 340 m/s. What is the wavelength of the sound waves produced?

Answers

The wavelength of the sounds waves produced is 34,000

In zero gravity, do the laws of motion still apply? No, objects cannot
be in
motion in
space because
there is no gravity.
No, if you do not
have gravity you
have no motion.
Yes, objects in
motion in space do
not have inertia.
Yes, objects in motio
in space tend to stay
motion unless acte
upon by an outside
force.

Answers

Answer:

Im pretty sure that it applys

I’m pretty sure it does hope this helps you

twenty-four specific objects transmit complex radio codes, including time signals traveling at the speed of light. you can contact at least 4 of the 24 objects at any time of day or night.

Answers

The statement suggests that there are 24 specific objects that transmit complex radio codes, including time signals traveling at the speed of light. It also states that you can contact at least 4 of these objects at any time of day or night.



Based on this information, it seems like the objects being referred to are satellites. Satellites are objects that orbit the Earth and can transmit signals for various purposes, including time synchronization.

One example of such satellites is the Global Positioning System (GPS) satellites.

The GPS system consists of a network of satellites that transmit signals to GPS receivers on Earth, enabling us to determine our precise location and time.

In conclusion, the main answer to the question is that the 24 specific objects mentioned are likely satellites, such as GPS satellites, that transmit complex radio codes, including time signals. You can contact at least 4 of these objects at any time of day or night.

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When a molecule of diatomic is split into two oxygen atoms its results in

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The answer is more stability.

What is the acceleration due to gravity on a 9.8 x 1026 kg planet that has a radius of 2.8 x 107 m?

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The acceleration due to gravity on a 9.8 x 1026 kg planet that has a radius of 2.8 x 107 m g = 9.8 m/s2.

calculation using the equation:

Gravity (g) = (G x Mass of Planet)/(Radius of Planet)^2

Where G is the gravitational constant (6.67408 x 10-11m3kg-1s-2).

Therefore, gravity (g) = (6.67408 x 10-11m3kg-1s-2 x 9.8 x 1026 kg)/(2.8 x 107 m)^2

g = 9.8 m/s2

What is acceleration due to gravity?

Acceleration due to gravity is the acceleration of an object in a vacuum due to the force of gravity. It is commonly denoted by g and has a value of 9.8 m/s² or 32.2 ft/s² at sea level on Earth.

Therefore, The acceleration due to gravity on a 9.8 x 1026 kg planet that has a radius of 2.8 x 107 m g = 9.8 m/s2.

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A pure tone with a frequency f1 = 800 Hz is modulated by a frequency f2 = 160 Hz. The primary sidebands are______ Hz and ______Hz. The virtual pitch heard will be the related fundamental, _______Hz.

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A pure tone with frequency f1 = 800 Hz is modulated by frequency f2 = 160 Hz. The primary sidebands are 960 Hz and 640 Hz. The virtual pitch heard will be the related fundamental, 800 Hz.

In physics, the term frequency refers to the number of waves passing through a fixed point in unit time. It also describes the number of cycles or vibrations an object undergoes in periodic motion in a unit of time.

The wave frequency (f,) is the number of waves passing through a point in one second. Frequency is measured in Hertz (Hz). Here, 1 hertz corresponds to 1 wave per second.

Frequency is also called cycles per second or time frequency. The usual symbol for frequency is the Latin letter f or the Greek letter ν (nu).

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assuming the breakdown electric field for polyethylene foam is 3500kv/m, shat is the maximum voltage that you may apply to the cable before reaching breakdown

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The breakdown electric field of polyethylene foam alone cannot be used to estimate the highest voltage that can be applied to the wire before it breaks down.

The biggest electrical potential difference that a system can withstand without experiencing harm or failure is known as the maximum voltage. As exceeding the maximum voltage can lead to electrical failure, fire, or even harm, it is crucial in the design and operation of electrical and electronic devices. The design, manufacturing method, and material properties of the device, as well as the environment in which it will be utilised, all influence the maximum voltage. It is crucial to follow the manufacturer's recommendations for maximum voltage and to routinely test and maintain equipment to make sure it is operating within its limitations in order to ensure safe operation.

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