The force exerted by the hand is equal to the weight of the cylinder and hand truck.
How Force becomes equal to weight of cylinder and hand truck?
A hand truck is used to move a compressed-air cylinder. Assume that the combined weight of the truck and cylinder is 220 lb.
The force exerted by the hand is equal to the weight of the cylinder and hand truck. The hand truck makes it easy to move the cylinder by redistributing the weight of the cylinder, making it more manageable to move. The force exerted by the hand is equal to the weight of the cylinder and hand truck.
A hand truck is a simple, two-wheeled device that is ideal for transporting objects of varying sizes and weights. They come in a variety of sizes, shapes, and configurations, and are commonly used in commercial, industrial, and home settings.
The weight of a compressed air cylinder is heavy. The average weight of a standard compressed air cylinder is around 170 pounds, depending on the size and gas capacity. When moving a compressed air cylinder, it's critical to exercise caution and use a hand truck or similar device.
Hand truck will make it easier to transport the cylinder because the weight of the cylinder is distributed more evenly across the truck, making it easier to manage.
A hand truck enables the user to leverage the force of their body weight to more easily lift and maneuver the cylinder, making the task less physically taxing.
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Based on illustrations of magnetic field lines, where could an object be placed so it would not experience a magnetic force?
halfway between the like poles of two magnets, because the field lines bend away and do not enter this area
halfway between the opposite poles of two magnets, because the field lines are the closest together
above the middle of a bar magnet, because the magnetic field lines are only found around the sides of the magnet
above a pole of a bar magnet, because the magnetic field lines either go in or go out at the end
Answer:
(a) halfway between the like poles of two magnets, because the field lines bend away and do not enter this area
Explanation:
Got it correct on the test.
Answer:
(a) halfway between the like poles of two magnets, because the field lines bend away and do not enter this area
Explanation:
Too many greenhouse gasses in the atmosphere may block heat from escaping into space and trap too much heat next to the Earth’s surface causing: ____________. *
another ice age
global warming
earthquakes
volcanoes
Answer:
global warming.
because these gases, react with the ozone gas in the ozone, hence fading away the ozone layer.
This allows direct sun rays to fall on to Earth's surface hence warming up called global warming
Too many greenhouse gasses in the atmosphere may block heat from escaping into space and trap too much heat next to the Earth’s surface causing: global warming. *
What is global warming?The human activities produce greenhouse gases such as carbon dioxide, carbon monoxide, methane, nitrogen oxides and others gases.
These gases when enter into the atmosphere because of their diatomic structure are capable of trapping the light energy from sun.
The abundance of these gases in the air is making the global temperature warm, which chiefly responsible for drought like conditions and melting of glaciers in some locations.
Then The trapped sunlight cannot be reflected back to the space this phenomena is called as greenhouse effect and the phenomena of increase in global temperature is called as global warming.
Which allows direct sun rays to fall on to Earth's surface hence warming up called global warming.
Hence, Too many greenhouse gasses in the atmosphere may block heat from escaping into space and trap too much heat next to the Earth’s surface causing: global warming. *
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Which frequencies can humans can hear but not mice
Scenarios that demonstrate the Motion of objects in Space! PLEASEEEE!!!!
There are several objects that move in space.
What are the Scenarios that demonstrate the Motion of objects in Space?There are many scenarios that demonstrate the motion of objects in space. Here are some examples:
Planetary motion: The motion of planets in the solar system is a classic example of objects in space in motion. The planets orbit around the sun in elliptical paths, with their motion governed by the gravitational pull of the sun.
Satellites: Satellites are artificial objects that are launched into space to perform various tasks, such as communication, navigation, and weather monitoring. The motion of satellites is determined by the gravitational forces of the Earth and other celestial bodies.
Asteroids and comets: Asteroids and comets are small, rocky or icy objects that orbit the sun. Their motion is also governed by the gravitational forces of the sun and other celestial bodies, and their orbits can be highly elliptical.
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determine the metacentric height of a cylinder of 4 m diameter and height of 4m floating in water with its axis vertical, if period of oscillation is 6 seconds
Answer:
-0.383 m
Explanation:
Diameter of cylinder = 4m therefore r = 2
height of cylinder ( H ) = 4 m
specific gravity = 0.6 ( assumed )
depth of immersion = 'h'
Determine the metacentric height
weight of cylinder in water = water displaced
= 0.6 * 1000 * πr^2* H = 1000 * πr^2* h
= 0.6 * 4 = h
∴ h = 2.4 m
hence the depth of center of buoyancy from free space = h /2 = 1.2 m
The metacentric height can be calculated using the formula below
Gm = Io / Vsubmerged - BG
attached below is the remaining solution
A person has long hair hanging straight down from their head. A second person rubs a balloon with felt so that the balloon is negatively charged, then brings it near the first person's hair without allowing the balloon to touch the hair. They notice that strands of the first person's hair are attracted to the balloon. The second person then rubs another balloon with plastic wrap so that it is positively charged, and again they notice that the balloon attracts strands of the first person's hair. Which is the best explanation for the attraction of the hair to the balloon
Answer:
The best explanation is that the first person is grounded to the earth, and his/her body either draws up negative charges from the earth, or tend to conducts negative charges to the earth, depending on the charge on the balloon.
Explanation:
The earth is an infinite store for charges. In the first case where the second person brings a negatively charged balloon towards the first person, the negative charges on the balloon induces the first person's body to tend to attract the negative charges on the balloon through the first person's body to the positive charges within the earth. In the second case when again a positively charged balloon is brought near the first person's hair, the positive charges on the balloon induce the first person's body into drawing up negative charges from within the earth. This charges, and their opposite induced charges, create an attractive force between the hair strands and the balloons.
1. Give three examples, from the lab, where potential energy was converted to kinetic energy:
Answer:
A book on a table before it falls.
A yoyo before it is released.
A raised weight.
Explanation:
These are all examples of potential energy. So I hope you can find something that is comparable from the lab.
Bone has a Young's modulus of about 1.8 x 1010 Pa. Under compression, it can withstand a stress of about 1.51 × 108 Pa before breaking. Assume that a femur (thigh bone) is 0.5 m long, and calculate the amount of compression this bone can withstand before breaking. Answer in units of mm.
The femur can withstand a compression of about 4.1945 mm before breaking.
Compression calculations explained.We can use the formula for compressive stress to calculate the amount of compression that the femur bone can withstand before breaking:
Stress = Force / Area
where the force is the force applied to the bone and the area is the cross-sectional area of the bone.
To find the cross-sectional area of the femur bone, we can assume that it has a circular cross-section and use the formula:
Area = πr^2
where r is the radius of the cross-section.
Since the length of the femur bone is 0.5 m, we can assume that the cross-sectional area remains constant along its length.
Let's assume that the force required to break the bone is the maximum compressive stress that it can withstand, which is 1.51 × 10^8 Pa. We can rearrange the stress formula to solve for the force.
We can use the equation for strain under compression:
strain = stress / Young's modulus
where stress is the maximum stress the bone can withstand before breaking, and Young's modulus is a measure of the stiffness of the material. The strain is a measure of how much the bone compresses under stress.
To find the compression distance, we can rearrange this equation to solve for the compression distance:
compression distance = strain x original length
where the original length is the length of the bone before compression
Substituting the given values:
stress = 1.51 × 10^8 Pa
Young's modulus = 1.8 × 10^10 Pa
original length = 0.5 m
First, we can calculate the strain:
strain = stress / Young's modulus = (1.51 × 10^8 Pa) / (1.8 × 10^10 Pa) ≈ 0.008389
Next, we can calculate the compression distance:
compression distance = strain x original length = (0.008389) x (0.5 m) = 0.0041945 m
Finally, we can convert the result to millimeters:
compression distance = 0.0041945 m x (1000 mm/m) = 4.1945 mm
Therefore, the femur can withstand a compression of about 4.1945 mm before breaking using Stress = Force / Area
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I need help with parts ANB of question number two
Answer:
a.
b.
Explanation:
The change in tire's angular velocity is
\(\Delta\omega=\omega_f-\omega_i\)Now,
\(\begin{gathered} \omega_f=3.9\text{rad}/s \\ \omega_i=-3.9\text{rad}/s \end{gathered}\)Therefore,
\(\Delta\omega=3.9-(-3.9)\)\(\boxed{\Delta\omega=7.8\text{rad}/s\text{.}}\)Part B.
The average angular acceleration is given by
\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}\)Now,
\(\Delta\omega=7.8\text{rad}/s\)and
\(\Delta t=1.85s\)Therefore,
\(\alpha_{\text{avg}}=\frac{\Delta\omega}{\Delta t}=\frac{7.8}{1.85}\)\(\Rightarrow\boxed{\alpha_{\text{avg}}=4.22\text{rad}/s^2}\)which is our answer!
How is speed related to kinetic energy?
Answer:
K.E. = 1/2mv^2
Explanation:
v is velocity (a vector) not speed (a scalar) but they have the same magnitude
an athlete in a hammer-throw event swings a 7.0-kilogram hammer in a horizontal circle at a constant speed of 12 meters per second. The radius of the hammer's path is 2.0 meters.
Answer:
ac = 72 m/s²
Fc = 504 N
Explanation:
We can find the centripetal acceleration of the hammer by using the following formula:
\(a_c = \frac{v^2}{r}\)
where,
ac = centripetal acceleration = ?
v = constant speed = 12 m/s
r = radius = 2 m
Therefore,
\(a_c = \frac{(12\ m/s)^2}{2\ m}\)
ac = 72 m/s²
Now, the centripetal force applied by the athlete on the hammer will be:
\(F_c = ma_c\\F_c = (7\ kg)(72\ m/s^2)\)
Fc = 504 N
A force of 10N is making an angle of 300 with the horizontal. Its horizontal components will be
Answer: 5N
Explanation:
Horizontal component is the force that is applied as a result of the diagonal application of force.
here in this case,
given diagonal force =10N.
angle= 30°
horizontal component is found using trigonometry..
so,
A vector of magnitude 10 N is provided.
It is at an angle of 30° to the + x axis.
To find:
The components along the x and y axis.
Calculation:
Along x axis:
F(x) = F cos(θ)
=> F(x) = 10 × cos(30)
=> F(x) = 10 (√3/2) = 5√3N
Along y axis:
F(y) = F sin(θ)
=> F(y) = 10 sin(30°)
=> F(y) = 10 × ½
=> F(y) = 5 N.
Additional information:
1. A vector is a quantity that can be defined with both magnitude and direction.
2. Since force is a vector, we are able to break it down into components along chosen axis.
find the acceleration gained by a body in 6 seconds if its initial velocity is 30 meter/seconds and final velocity is 60/seconds meter and spammers stay away
Answer:
Acceleration, a = 5 m/s²
Explanation:
Given the following data;
Initial velocity = 30 m/s
Final velocity = 60 m/s
Time = 6 seconds
To find the acceleration, we would use the first equation of motion;
V = U + at
Where;
V is the final velocity.
U is the initial velocity.
a is the acceleration.
t is the time measured in seconds.
Substituting into the equation, we have;
60 = 30 + a*6
60 - 30 = 6a
30 = 6a
Acceleration, a = 30/6
Acceleration, a = 5 m/s²
PLEASE HELPPP! :))))
Answer:
Jupiter Neptune moon Uranus
Explanation:
A pot plant falls off the balcony of an apartment. The balcony is 20 m above the ground and the pot plant has a mass of 2 kg. After falling a distance of 2 m from the balcony, the pot plant has a velocity of 6,26 m·s-1 . Ignore the effect of air resistance. 5.1
Calculate the gravitational potential energy of the pot plant before it begins to fall. 5.2 Calculate the total mechanical energy of the pot plant after it has fallen two meters. 5.3 Is this a closed system?
Explain your answer. 5.4 Calculate the speed with which the pot plant hits the ground.
The gravitational potential energy of the pot plant before it begins to fall is 392 J.
The total mechanical energy of the pot plant after it has fallen two meters is 78.39 J.
The speed with which the pot plant hits the ground is 19.8 m/s.
What is the gravitational potential energy?
The gravitational potential energy of the pot plant before it begins to fall is calculated as follows;
P.E = mgh
where;
m is mass of the potg is acceleration due to gravityh is height of the initial height of the potP.E = (2 kg) (9.8 m/s²) (20)
P.E = 392 J
The total mechanical energy of the pot plant after it has fallen two meters is calculated as follows.
M.E = K.E + P.E
where;
K.E is kinetic energyP.E is potential energyM.E = ¹/₂mv² + mgh
M.E = ¹/₂(2 kg)(6.26 m/s)² + (2 kg)(9.8 m/s²)(2 m)
M.E = 78.39 J
The speed with which the pot plant hits the ground is calculated by applying the principle of conservation of energy as follows;
K.E(bottom) = P.E(up)
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
h is the initial height of the potv = √(2 x 9.8 x 20)
v = 19.8 m/s
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how to test a zener diode with a digital multimeter
To test a Zener diode with a digital multimeter, follow these steps:
1. Turn off the power supply to the circuit.
2. Set your multimeter to the diode test mode. This is usually represented by a diode symbol on the multimeter dial.
3. Connect the black probe of the multimeter to the cathode end of the Zener diode and the red probe to the anode end of the diode.
4. Check the voltage reading on the multimeter. If the voltage reading is zero, the Zener diode is not conducting and is faulty. If the voltage reading is close to the Zener voltage rating, the Zener diode is good.
5. Reverse the probes and repeat the test. The voltage reading should be close to zero volts. If the voltage reading is still close to the Zener voltage rating, the Zener diode is faulty.
Note: Be sure to consult the datasheet of the Zener diode you are testing to ensure that you are using the correct voltage rating.
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Which of the following types of ES is frequently used to support operational procurement activities? A) ERP B) SCM C) SRM D) Two of the above,
Among the following options, Enterprise Resource Planning (ERP) is the type of ES frequently used to support operational procurement activities.
What is ERP?ERP or Enterprise Resource Planning is a software application that an organization uses to manage its business processes. It integrates various departments, such as finance, HR, inventory, and procurement, into a single system and streamlines communication between them. This assists firms in effectively utilizing resources and achieving their objectives.
ERP system is frequently used to support operational procurement activities because it can help in coordinating the purchasing process from start to finish. It also automates many activities such as generating purchase orders, tracking shipments, recording receipts, and paying invoices.
Thus, it can increase the efficiency and accuracy of procurement processes, reducing the need for manual intervention.
Therefore, the correct answer is A) ERP.
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When blue light (450 nm) is shone on a particular metal surface, electrons are ejected with a kinetic energy of 2.5 x 10-20 J. Calculate the work function for this metal.
Answer:
the work function of the metal is 4.167 x 10⁻¹⁹ J .
Explanation:
Given;
wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m
kinetic energy, K.E = 2.5 x 10⁻²⁰ J
The energy of the incident light is calculated as;
\(E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J\)
Apply Einstein photoelectric equation to determine the work function of the metal;
E = W + K.E
where;
W is the work function of the metal
W = E - K.E
W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J
W = 44.17 x 10⁻²⁰ J - 2.5 x 10⁻²⁰ J
W = 41.67 x 10⁻²⁰ J
W = 4.167 x 10⁻¹⁹ J
Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .
The work function of the photon is 4.167*10^19J
The energy of this photon can be calculated as
E = hc/λ
Data given;
λ = 450nm = 450*10^-9mh = 6.626*10^-34JSK.E = 2.5*10^-20Jc = 3.0*10^8m/sEnergy of the Photonsubstituting the values into the equation;
\(E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J\)
Work FunctionThe work function of the photon can be calculated as;
E = K.E + Ф
4.42*10^-19 = 2.5*10^-20 + Ф
Ф = \(4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J\)
The work function of the photon is 4.167*10^-19 J
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Draw a wave that has a wavelength of 3 cm and an amplitude of 1 cm. Label the wavelength, the amplitude, the rest position, and the crest and trough of your wave.
Answer:
Please find attached, the required wave drawn with MS Excel
Explanation:
Functions that represent waves is given as follows
A general form of the wave equation is A·sin(B·x) + D
Where;
B = 2·π/T
T = The period of the wave = 1/f
D = The vertical shift of the wave = 0
A = The amplitude of the wave = 1 for sine wave
v = The wave velocity
λ = The wavelength of the wave
f = The frequency of the wave
v = f·λ
At constant v, λ ∝ 1/f
∴ λ ∝ T
Where T = 3, we have;
B = 2·π/T
∴ B = 2·π/3
Therefore, we have the wave with an amplitude of 1 cm, and wavelength, 3 cm, given as follows
y = sin((2·π/3)·x)
Plotting the above wave with MS Excel, we can get the attached wave
If a baseball lands with a speed of 80 miles/hr after traveling with an acceleration of -6 miles/hr/sec for 5seconds, what was the initial speed at which the ball was hit?
We are given that an object falls with an acceleration of -6 miles/h/s. To determine the initial velocity we will use the following motion:
\(v_f=v_0+at\)Where:
\(\begin{gathered} v_f,v_0=\text{ final and initial velocity} \\ a=\text{ acceleration} \\ t=\text{ time} \end{gathered}\)Now, we solve for the initial velocity by subtracting "at" from both sides:
\(v_f-at=v_0\)Now, we plug in the values:
\(80\frac{mi}{h}-(6\frac{mi}{hs})(5s)=v_0\)Now, we solve the operations:
\(50\frac{mi}{h}=v_0\)Therefore, the initial velocity is 50 mi/h.
Fill in the blanks below with the best answer from the options given.
Hot objects contain _____ energy and emit ______ photons at all wavelengths, compared to cool objects
Hot objects emit more energy at ________ frequencies and ________ wavelengths
Cool objects appear _______ in color than hot objects
Answer choices: more, less, higher, lower, longer, shorter, up, down, left, right, redder, greener, bluer, whiter
Hot objects contain more energy and emit photons at higher frequencies and shorter wavelengths compared to cool objects. Cool objects appear redder in color than hot objects.
Hot objects have a higher internal energy compared to cool objects. This higher energy is manifested in the form of increased thermal motion of particles within the object. As a result, hot objects emit more energy in the form of photons.
When it comes to the emission of photons, hot objects emit more photons at higher frequencies and shorter wavelengths. This is because the energy of individual photons is directly proportional to their frequency. Hotter objects have more energetic particles, leading to the emission of photons with higher frequencies and shorter wavelengths.
On the other hand, cool objects emit fewer photons and at lower frequencies and longer wavelengths. The lower energy of the particles in cool objects results in the emission of photons with lower frequencies and longer wavelengths.
In terms of color appearance, cool objects appear redder than hot objects. This is because cooler objects emit more photons in the red part of the electromagnetic spectrum, while hotter objects emit more photons in the blue part of the spectrum.
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Which of the following types of microscopes reveals the surface features of small molecules? - a confocal microscope - a fluorescent microscope - a transmission electron microscope (TEM) - an atomic force microscope
The types of microscopes that reveals the surface features of small molecules is an atomic force microscope.
The Atomic Force Microscope (AFM) is useful for imaging the surface topography of living, soft materials in their natural settings. It can be used to examine the inherent elastic modulus and receptor-ligand interactions of cells and extracellular matrix, among other mechanical properties. SEM pictures can investigate surface features that are several tenths of a nanometer in size, but AFM resolution is less than 0.1 nm. As a result, AFM can discern objects on flat surfaces with molecular dimensions.
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A flashlight that is powered by 3 Volts and uses a bulb with a
resistance of 68. will have a current of Amps
A jet airliner moving initially at 103 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 441 mph in a direction 19° north of east. What is the new speed of the aircraft with respect to the ground?
The new speed with respect to the ground is 512 m/h.
What is speed?We can tell that is speed is the rate at which the velocity changes with respect to time. In this case, we can see that the jet airliner moving initially at 103 mph (with respect to the ground) to the east moves into a region where the wind is blowing at 441 mph in a direction 19° north of east.
Hence;
→ The east component = 103 + 441 cos(52) = 375 m/h
→ The north component = 441 sin(52) = 348 m/h
We can now get the new velocity by the use of;
√( 375)^2 + (348)^2 =
= 512 m/h
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IA body starts to move from rest and travels with uniform acceleration of 7mls2. How far will the body move in 4 second .
Can someone please help me?
An alien spaceship is 650 m above the ground and moving at a constant velocity of 175 m/s upwards.
How high above the ground is the ship after 5 seconds?
Answer:
1525 meters above ground
Explanation:
So to do this you will need to write this in slope intercept form or \(y=mx+b\). So 650 would be the b, 175 would be the m, and the x would be 5 so the equation would be \(y=175(5)+650\) so if you solve or simplify the equation you will get 1525 meters above the ground and that would be our final answer.
Convection takes place because
Explanation:
the particles in liquids and gases move faster when they are heated than they do when they are cold. As a result, the particles take up more volume.
if 6 j of work are needed to stretch a spring from 7 cm to 9 cm and 10 j are needed to stretch it from 9 cm to 11 cm, what is the natural length of the spring?
The natural length of the spring is 5 cm.
Given dataThe amount of work done to stretch a spring from 7 cm to 9 cm is 6 J.The amount of work done to stretch a spring from 9 cm to 11 cm is 10 J.
The formula for potential energy stored in a spring is
U=12kx2
Here,
U is potential energy stored in a spring
k is a spring constantx is the displacement of the spring from its natural length
U = 12kx2
Thus, U is proportional to x2
For the first stretching, we have
U1 = 12k(0.02)2
For the second stretching, we have
U2 = 12k(0.02)2
The difference in the amount of work done to stretch a spring is proportional to the difference in the potential energy stored in the spring.
So,U2 - U1 = 10 J - 6 J= 4 J= 12k(0.02)2 - 12k(0.02)2= 12k(0.04)k = 4/3
The natural length of the spring is given by x0 = U/k
Here, U is the potential energy stored in a spring when stretched by x So, the natural length of the spring is
x0 = 12kx02x0 = 12(4/3)(0.05)2x0 = 5 cm
Therefore, the natural length of the spring is 5 cm.
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if the acceleration of the paramecium in part a were to stay constant as it came to rest, approximately how far would it travel before stopping?
The approximate distance the paramecium will travel before stopping, if the acceleration of the paramecium were to stay constant as it came to rest, can be found using the kinematic equation.
A paramecium is a unicellular organism.
Given that:
Initial velocity, u = 0
Acceleration, a = - 2.5 µm/s²
Final velocity, v = 0
The distance traveled, s = ?
We can use the kinematic equation:
v² - u² = 2as
Plugging in the known values:
v² - u² = 2as
0² - 0² = 2(- 2.5) s0
= - 5s
Thus, the approximate distance the paramecium will travel before stopping, if the acceleration of the paramecium were to stay constant as it came to rest is 5 µm.
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Which structure is found in some but not all plant cells?
vacuole
ribosome
cell wall
lysosome
HELP PLEASE AND THERES ONLY ONE CORRECT ANSWER!!!!!!!
Answer:
Lysosme
Explanation:
All plant cells have cell walls due to their ability to not protect themseleves unlike us humans or aniamls. Ribosomes and vacuoles also are in all plant cells as provide it with nutrients. Lysosme are not always commonly found in all plant cells because they have cell walls to proctect them. Hope this helps :)