A hiker walking with an average speed of 1.5 m/s would travel a distance of 2.55 kilometers in 1.7 hours.
This can be calculated using the equation Distance = Speed x Time, or D = S x T. Substituting the given values, we get D = 1.5 m/s x 1.7 hours = 2.55 kilometers.
Speed is a scalar quantity that refers to how quickly an object is moving. It is typically measured in meters per second (m/s). Speed is related to how much distance an object covers over a given amount of time. The faster an object moves, the greater the distance it covers in a given amount of time, and thus the greater its speed. Speed can also be measured in other units, such as miles per hour (mph).
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a 67.7-kg skier moving horizontally at 4.83 m/s encounters a 17.9° incline. a) how far up the incline will the skier move before she momentarily stops, ignoring friction?
The skier will move up the incline 4.65 meters before she momentarily stops, ignoring friction.
To solve this problem, we can use the principle of conservation of energy, which states that the total energy of a system remains constant as long as no work is done on it. At the bottom of the incline, the skier has kinetic energy due to her motion, but no potential energy. As she moves up the incline, her kinetic energy is converted into potential energy due to gravity.
The potential energy of an object of mass m at a height h above the ground is given by the formula P.E. = mgh, where g is the acceleration due to gravity (9.8 m/s^2). At the top of the incline, the skier will have no kinetic energy and all of her initial kinetic energy will have been converted to potential energy.
We can use the conservation of energy principle to set the initial kinetic energy equal to the final potential energy:
1/2 mv^2 = mgh
where m is the mass of the skier, v is her initial velocity, h is the height she reaches before stopping, and g is the acceleration due to gravity.
We can solve for h by rearranging the equation:
h = (1/2 v^2)/(g sin^2θ)
where θ is the angle of the incline. Substituting in the given values, we get:
h = (1/2 x 4.83^2)/(9.8 x sin^2 17.9°) = 4.65 meters
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If L α M3.5, what happens to the luminosity if we increase M by a factor of 5?A. Increases by factor 17.5B. decreases by factor of 17.5C. increases by factor 79D. increases by factor of 280E. decreases by factor of 79
The luminosity of the star will increase by a factor of 125. Therefore, the correct answer is (D) increases by a factor of 280.
If L α M3.5, this means that the luminosity of a star is proportional to the mass raised to the power of 3.5.
If we increase the mass of the star by a factor of 5, the new mass will be 5M, and the luminosity will be:
L' = k(5M)3.5, where k is a constant of proportionality.
Expanding this expression, we get:
L' = k(5³ × M3.5)
L' = k(125 × M3.5)
L' = 125kM3.5
Thus, the luminosity of the star will increase by a factor of 125. Therefore, the correct answer is (D) increases by a factor of 280.
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A) increases by a factor of 17.5
Solution - Hi! Based on the given relationship, L α M^3.5, if we increase M by a factor of 5, we need to calculate the new luminosity (L') using the formula:
L' α (5M)^3.5
To find the factor by which the luminosity increases, we can divide L' by the original L:
(L' / L) = ((5M)^3.5) / (M^3.5)
Since both expressions are proportional, we can focus on the numeric part:
Factor = 5^3.5 ≈ 17.5
So, the luminosity increases by a factor of 17.5, which corresponds to option A.
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Bob and Sarah build an electromagnet by wrapping a wire around a nail and connecting the wire to both terminals of a battery. When they test the electromagnet, it can pick up six paper clips. Their teacher wants all groups to pick up at least 10 paper clips. What revisions could Bob and Sarah make to increase the number of paper clips their electromagnet picks up
1). Wrap more turns of the wire around the nail.
2). Increase the electrical current through the wire. (Do this by inserting another battery in the circuit, in series with the first one.)
50 points
50 points
To whoever solves this
The period of rotation of the cow in the diagram is 1.85 seconds
How do i determine the period of rotation?First, we shall determine the length. Details below:
L² = 75² + 40²
L² = 5625 + 1600
L² = 7225
Take the square root of both sides
L = √7225
L = 85 cm
Finally, we shall obtain the period of rotation. Details below:
Length (L) = 85 cm = 85 / 100 = 0.85 mAcceleration due to gravity (g) = 9.8 m/s² Pi (π) = 3.14Period of rotation (T) =?T = 2π√(L/g)
T = (2 × 3.14) × √(0.85 / 9.8)
T = 6.28 × √(0.85 / 9.8)
T = 1.85 seconds
Thus, we can conclude from the above calculation that the period of rotation is 1.85 seconds
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Answer: the period of rotation is 1.85 seconds
Explanation: the other guy is right
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by:
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the phase-locking of the auditory nerve fibers.
This means that the nerve fibers fire in synchrony with the sound wave and the brain can then interpret this as a low-frequency tone. This is because the membrane's responsiveness decreases at lower frequencies, making it more difficult for it to accurately encode the pitch information.
While most pitches are encoded directly by the placement of a frequency on the membrane, low-frequency tones are encoded by the timing of the membrane's vibrations, also known as phase-locking. This explanation means that low-frequency sounds are represented by the synchronization of the membrane's movements with the incoming sound waves, allowing for accurate encoding of these lower pitches.
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a magnetic flux of 4.72 x 10^-4 Wb passes through a loop oriented 65.5 degrees to a magnetic field of 1.44 T. what is the area of the loop
Answer:7.904*10^-4
Explanation:
Trust me
Assuming the Pressure Gradient Force is the same in both a trough and a ridge, the trough will have the faster winds. True False
False
The Pressure Gradient Force (PGF) is the force that drives air from areas of high pressure to areas of low pressure. In both a trough and a ridge, the PGF is the same.
However, the winds will not be the same in both features.
In a trough, the winds tend to move towards the center of the trough, where the air is rising, and this causes convergence and lifting. This upward motion causes a decrease in pressure, leading to a steeper pressure gradient, which means stronger winds. On the other hand, in a ridge, the winds move away from the center of the ridge, where the air is sinking, and this causes divergence and sinking. This sinking motion causes an increase in pressure, leading to a weaker pressure gradient and lighter winds.
Therefore, assuming the same PGF, the trough will have the faster winds compared to the ridge.
Why are paperclips attracted to magnets? Group of answer choices They contain silver They contain aluminum They contain tin They contain iron
Answer:
They contain iron.
Explanation:
Iron is made of metal and magnets attract to metal Iron.
Collisions between galaxies typically unfold over a period of ______.
Collisions between galaxies typically unfold over a period of millions of years.
Galaxies are vast collections of stars, gas, and dust that are held together by gravity. When galaxies collide, the individual stars and gas clouds do not collide with one another. Instead, the gravitational forces between the galaxies cause them to distort each other's shape and pull material out into long streams. These tidal forces can trigger bursts of star formation, as gas clouds are compressed and collapse to form new stars. The actual collision process can take millions of years to complete, with the galaxies gradually merging together into a single, larger system.
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A small dog is trained to jump straight up a distance of 1.1 m. How much kinetic energy does the 7.7-kg dog need to jump this high? ( The acceleration due to gravity is 9.8 m/s2.) Show your work.
The potential energy at the maximum height is equal to the kinetic energy when the dog lands, the kinetic energy required for the dog to jump this high is also 84.906 Joules.
Potential energy is the stored energy possessed by an object due to its position or condition. It is the energy that an object has by virtue of its potential to be converted into other forms of energy, such as kinetic energy, when certain conditions or forces are applied.
To calculate the kinetic energy required for the dog to jump a distance of 1.1 m, we can use the formula for kinetic energy:
Kinetic Energy (KE) = 0.5 × mass × velocity²
Since the dog jumps straight up, its initial velocity is zero. Therefore, we only need to consider the potential energy (PE) of the dog at the maximum height, which will be converted into kinetic energy as it falls back down.
The potential energy at the maximum height can be calculated using the formula:
Potential Energy (PE) = mass × gravity × height
Given:
Mass of the dog (m) = 7.7 kg
Acceleration due to gravity (g) = 9.8 m/s²
Height (h) = 1.1 m
Calculating the potential energy:
PE = 7.7 kg × 9.8 m/s² × 1.1 m
= 84.906 Joules (rounded to three decimal places)
Therefore, Since the potential energy at the maximum height is equal to the kinetic energy when the dog lands, the kinetic energy required for the dog to jump this high is also 84.906 Joules.
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Consider the following scenarios. Which heuristic do they illustrate? Why does that heuristic lead to less-than-optimal decision making? a. Cindi gets a larger tax refund than expected and decides to splurge on some fancy jewelry. b. George has met two people who work for BuyſtNow, Inc. and both were very aggressive. George decides he does not want to apply for a job with BuyItNow, Inc. because of their aggressive culture. c. After seeing reports of a shark attack in the news, Mary refuses to go swimming while on vacation. d. Paul goes grocery shopping and sees an ad for chicken broth saying ‘limit 10 per customer'. Paul decides to purchase 10 boxes even though he only needs two.
a. Availability heuristic - recent larger tax refund influences spending decision.
b. Representativeness heuristic - generalizing based on two individuals' behavior.
c. Availability heuristic - fear from recent shark attack influences decision.
d. Anchoring heuristic - purchase decision based on advertised limit, ignoring actual need.
a. Availability heuristic - Cindi is influenced by the recent event of receiving a larger tax refund and uses it as a basis for making a splurging decision, without considering other factors like long-term financial goals.
b. Representativeness heuristic - George generalizes his experience with two aggressive individuals to the entire company, leading to a biased decision without considering other aspects of the job or company culture.
c. Availability heuristic - Mary's decision is based on the availability of information about a shark attack, leading to an overestimation of the likelihood of a shark attack and an avoidance behavior.
d. Anchoring heuristic - Paul is influenced by the limit mentioned in the ad and anchors his purchase decision on that number, even though it exceeds his actual requirement, leading to unnecessary purchases.
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what force is exerted on the sled by the hill? answer in units of n.
Answer:
frictional force in units of newton
water is discharged through the 40-mm-diameter elbow at 0.012 m3/s. the pressure at a is 170 kpa .
The pressure at point B is 622.5 kPa.
Based on the information provided, we can determine the velocity of the water through the 40-mm-diameter elbow using the formula Q = Av, where Q is the volumetric flow rate (0.012 m³/s), A is the cross-sectional area of the elbow (πr², where r is the radius of the elbow), and v is the velocity of the water.
We can rearrange the formula to solve for v:
v = Q / A
The radius of the elbow can be determined by dividing the diameter by 2:
r = 40 mm / 2 = 20 mm = 0.02 m
The cross-sectional area of the elbow can then be calculated using the formula A = πr²:
A = π(0.02 m)² = 0.00126 m²
Substituting these values into the formula for velocity:
v = 0.012 m³/s / 0.00126 m² = 9.52 m/s
Now that we know the velocity of the water, we can use Bernoulli's equation to determine the pressure at point B:
P₁ + 0.5ρv₁² + ρgh₁ = P₂ + 0.5ρv₂² + ρgh₂
Where P₁ is the pressure at point A (170 kPa), ρ is the density of water (1000 kg/m³), g is the acceleration due to gravity (9.81 m/s2), h₁ and h₂ are the heights of points A and B above a reference level (we can assume they are the same), and P₂ is the pressure at point B (what we want to find).
Rearranging the equation and substituting in the known values:
P₂ = P₁ + 0.5ρ(v₁² - v₂²)
P₂ = 170 kPa + 0.5(1000 kg/m³)(9.522 - 02) = 170 kPa + 452.5 kPa
P₂ = 622.5 kPa
Therefore, the pressure at point B is 622.5 kPa.
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Interpret the data:
Make a claim that answers the scientific question.
Calculate the speed for a car that went a distance of 125 miles in
2 hours time? Provide the speed in kilometer per hour
The scatterplot shows the energy in watts and the light output in lumens per watt of several lightbulbs
The statements D best represents the relationship between the energy and light output.
What is scatter plot ?A scatter plot is a form of plot displays values for two variables for a collection of data using coordinates system.
The scatter plot depicts the energy input and light output in lumens per lightbulb. The statements D best represents the relationship between the energy and light output.
There is no apparent association between the energy and light output, shows the relationship between the energy and light output.
Hence,statement D is correct.
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A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.
If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?
The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.
What is the sound's velocity?By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.
Briefing:The following equation relates the distance to the direction and initial velocity:
d = [v₀²sin2θ]/g, where θ – the angle of the jump.
Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62
v₀ = 10.65 m/s ( the take off speed).
The horizontal velocity equals:
vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s
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What will happen to people involved in handling Gamma rays if they are not providedwith lead coated apron and equipment without safety measures❤
Answer:
When gamma rays pass through the human body, they ionize the tissue. gamma ray ionization can affect healthy cells. When high levels of gamma rays bombard a body, a resulting dangerous ionization of tissue can cause skin cancer.
Explanation:
Mars has two moons. What does the orbital speed of these moons depend on?
Answer:
their masses and their distances from Mars
Explanation:
Hope this helped
Also can u pls mark me brainliest
can someone help me with this question?
why does this bulb not glow?
The possibilities are
The cell is out of battery .There may be no charge in battery that can glow the bulb.You may have connected wire of poor conductors like nonmetals .Resistance of wire may be too heavy that doesn't letting the current go to bulb.The stars of the milky way are all near a great circle on the celestial sphere. This great circle.
The stars of the milky way are all near a great circle on the celestial sphere. This great circle is called milky circle.
Milky Way Galaxy, large spiral system consisting of several hundred billion stars, one of which is the sun.It takes its name from the Milky Way, the irregular luminous band of stars and gas clouds that stretches across the sky as seen from Earth.Although Earth lies well within the Milky Way Galaxy, astronomers do not have as complete an understanding of its nature as they do of some external star systems. Although most stars in the Galaxy exist either as single stars like the Sun or as double stars.Milky circle is the great circle in which all stars of milky way are present.To know more about galaxy visit:
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The stars of the milky way are all near a great circle on the celestial sphere. This great circle is called milky circle.
What is Milky Way Galaxy ?Milky Way Galaxy, large spiral system consisting of several hundred billion stars, one of which is the sun.It takes its name from the Milky Way, the irregular luminous band of stars and gas clouds that stretches across the sky as seen from Earth.Although Earth lies well within the Milky Way Galaxy, astronomers do not have as complete an understanding of its nature as they do of some external star systems.Although most stars in the Galaxy exist either as single stars like the Sun or as double stars.Milky circle is the great circle in which all stars of milky way are present.To know more about Milky Way visit: https://brainly.com/question/13956361
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What is the flux through any closed surface surrounding a cylinder with surface charge densityσ = k sin φ , where k is a constant. Its height is H , and its radius is R.
The flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
Since the cylinder's surface charge density is given by σ = k sin φ
Therefore, the total charge on the cylinder's curved surface
Q = σ(2πRL)
Where L is the height of the cylinder, Q = 2πRLk sin φ .
From Gauss's Law, the total flux through a closed surface surrounding a cylinder with height H and radius R is given by φ₀=Qε₀ .Here, ε₀ represents the vacuum permittivity. Now, substituting the value of Q, we get
φ₀ = (2πRLk sin φ)/ε₀
Therefore, the flux through any closed surface surrounding a cylinder with height H and radius R having surface charge density σ = k sin φ, where k is a constant, is φ₀=2πRLk sin φ/ε₀.
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does anyone know the answer to this?
Answer:
The cat went up
Explanation:
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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 A beach ball moving with the speed of 1.27 m/s rows of a pier and hits the water 0.75 m from the end the pier how high is the pier above the water
Answer:
75.8
Explanation:
because just divide 1.27 into 0.75 and there's your answer
Please help I’m dying trying to solve this.
Please find attached photograph for your answer. The answers are all estimated values. Hope it helps! Please do comment
On a hot day, a child drinks all the water in a plastic bottle. She then screws the
cap back tightly on the bottle, so that the bottle contains only air. She throws the
bottle into a wastebasket, where the Sun shines on it. After a while in the Sun's rays,
the air in the bottle is much hotter than before.
cap screwed on
(i) State what has happened to the pressure of the air in the bottle.
Give a reason for your answer.
(ii) In terms of the behaviour of the air molecules, explain your answer
to a(i)
what is the formula to calculate Acceleration?
Answer:
too much :(
Explanation:
\overline{a} = \frac{v - v_0}{t} = \frac{\Delta v}{\Delta t}
\overline{a} = average acceleration
v = final velocity
v_0 = starting velocity
t = elapsed time
Answer:
a = Δv⁄t.
Explanation:
Find something (top, coin) to spin and watch it spin! It’s happening to earth now! List the 3 main orbital changes earth undergoes and their time periods. What does this have to do with climate change? List the 3 cyclical orbital changes and their times associated with Milankovitch
2. List all the EMR in order of wavelength. What forms of EMR from the sun are reaching you right now? How many forms are reaching the Moon right now (from the sun)? Explain the role of ozone in our atmosphere...where it is, how it formed and what is does for life! How does the balance of EMR play a critical role in Climate Change and "The Greenhouse Effect". Explain how CO2 and a Greenhouse balance Infrared Radiation creation and absorption?!
3. List and describe the 4 forms of heat transfer to and on planet earth!?! What does this have to do with "weather". Explain and give examples! Explain how a microwave oven heating a bowl of cold soup covers all forms of heat transfer. Earth and soup. SAME! How long does it take for EMR from University of Delaware to reach…. A. moon B. Jupiter C. closest star (not sun) D. your mother
Here are the answers to the questions:1. Three main orbital changes that the earth undergoes and their time periods are:A. Precession- every 26,000 years B. Obliquity- every 41,000 years C. Eccentricity- every 100,000 yearsThese changes in the earth's orbit, together, have an impact on the amount of solar radiation that reaches the Earth's surface, which then affects climate change. Three cyclical orbital changes and their times associated with Milankovitch are:A. Eccentricity - every 100,000 yearsB. Obliquity - every 41,000 yearsC. Precession - every 26,000 years2. All EMR in order of wavelength are:- Gamma rays- X-rays- Ultraviolet radiation- Visible light- Infrared radiation- Microwave- Radio wavesForms of EMR from the sun that are reaching right now are UV radiation, visible light, and infrared radiation.
The number of forms of EMR reaching the moon right now is two, UV radiation, and visible light.The ozone layer is present in the stratosphere and is formed through a series of complex chemical reactions. The primary function of the ozone layer is to protect the earth from the harmful effects of UV radiation by absorbing it. The balance of EMR plays a critical role in the greenhouse effect. As the amount of greenhouse gases increases, the amount of energy that is absorbed by the Earth's surface also increases. Carbon dioxide and other greenhouse gases can absorb and emit infrared radiation, which plays a crucial role in climate change.3. The four forms of heat transfer to and on planet earth are:- Conduction- Convection- Radiation- AdvectionThese four forms of heat transfer are responsible for weather on planet Earth.
For example, when the sun heats the ground, it results in conduction, which then results in convection as the air heats up and rises. This can lead to cloud formation and precipitation.4. The time it takes for EMR from the University of Delaware to reach:A. Moon - About 1.28 secondsB. Jupiter - About 33.75 minutesC. Closest star (not the sun) - About 4.37 yearsD. Your mother - This question is not clear, please provide more context.
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Compared to visible light, the wavelength of X-rays is
and the frequency is
Answer:
shorter,higher
Explanation: