A hockey pucks average velocity is 22m/s off of a NHL player's stick. How long does the puck slide across the ice if it travels 132m?

Answers

Answer 1

Answer:

Explanation:

s=vt

v=22 m/s

s=132 m

s=vt

t=s/v

t=132/22

t=6 s

Answer 2

Answer:

6 sec.

Explanation:

distance travel = 132 m

velocity = 22 m/s

find time

solution:

time = distance / velocity

       = 132 m

          22 m/s

       = 6 sec.


Related Questions

How does the Doppler Effect work?

Answers

Answer:

Doppler Effect works on both light and sound objects.

Explanation:

Like when a sound object moves towards you, the frequency of the sound waves increases, leading to a higher pitch.

if it moves away from you, the frequency of the sound waves decreases and the pitch comes down.

PLEAS HELPM ME FASTTT MARKING PERIOD IS ABOUT TO END.

Most areas have two high and two low tides each day, this is called ___________.

Question 2 options:

gravity


semi-diurnal


low tide

Answers

Answer:

the answer is semidiurnal

Answer:

I think it is semi-diurnal :)

Hope this helps!!

Have a great day!!

Please rate and mark brainliest!!

A student is creating a model of a concave lens. The diagram shows her incomplete model.



Which action would best complete her model?
A
The student should draw the light moving into the lens and then exiting in converging lines.

B
The student should draw the rays of light moving into the lens and then exiting at right angles.

C
The student should draw the rays of light moving into the lens and then exiting in a straight path.

D
The student should draw the light moving into the lens and then exiting in lines that are spreading out.

Answers

Answer:

D

Explanation:

I’m pretty sure it’s correct but I don’t really know. Just trying to pass science

Answer:

The correct answer is D trust me I did the test

When the concave lens moves in it exit by spreading out like water

an object has a kinetic energy of 36.0 j. an object with three times the mass moving at the same speed will have a kinetic energy of

Answers

The kinetic energy of another body having three times the mass of the given object will be 108 J

Kinetic energy-In physics, the kinetic energy of an object is the energy  it has due to  motion. It is defined as the work required to accelerate a body from a given mass from rest to a specified speed.

The kinetic energy of a body is given by \(K.E= \frac{1}{2}Mv^{2}\) (first equation)

Given K.E= 36J

Now the mass of second body is m=3M

also the second body is moving with the same speed v

So kinetic energy of second body K.E₂= \(\frac{1}{2}mv^{2} =\frac{1}{2}(3M)v^{2}\)=36×3

=108J (from first equation)

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what's is the kinetic energy of a .235-kg baseball thrown at 50.0m/s

Answers

Answer:

34.51

Explanation:

k=1/2mv² is the kenetic energy equation to fill is in

k=[1/2(0.235)×50]²

I. a specimen of a ceramic material having a modulus of elasticity of 300 gpa is pulled in tension with a stress of 900 mpa. will the specimen fail if the its "" most severe flaw is an internal crack that has a length od 0.30mm and tip radius of curvature of 5×10-4 mm? why or why not?

Answers

the specimen will not fail because the stress intensity factor is below the critical value required for crack propagation. This means that the internal crack with a length of 0.30mm and a tip radius of curvature of 5×10-4 mm will not cause failure in the ceramic material.

The main answer to the question is that the specimen will not fail if its most severe flaw is an internal crack with a length of 0.30mm and a tip radius of curvature of 5×10-4 mm.

This is because the stress intensity factor, which determines whether a crack will propagate or not, is calculated using the formula K = Y * (σ * √(π * a)), where K is the stress intensity factor, Y is a geometric factor, σ is the stress applied, and a is the crack length.

In this case, the stress intensity factor is below the critical value needed for crack propagation.

To further explain, the stress intensity factor depends on the crack length, the applied stress, and the geometric factor, which accounts for the shape and orientation of the crack.

In this scenario, the crack length and the applied stress are provided, and assuming a typical value for the geometric factor, the stress intensity factor is calculated to be below the critical value for crack propagation. the specimen will not fail.

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What is 170 Celsius in Fahrenheit?

Answers

Answer: 170 Celsius = 338 Degree Fahrenheit

170 Celsius in Fahrenheit 340°F. Celsius (°C) is a temperature scale based on 0° for the melting point of ice and 100° for the boiling point of water.

What is Celsius?

It was devised by the Swedish astronomer Anders Celsius in 1742. Celsius is now the most widely used temperature scale, with the international standard metric definition being that 0°C is equal to 273.15K (Kelvin). Celsius is an absolute temperature scale, meaning that the zero point is the same everywhere. This makes it easy to compare temperatures in different locations. The degree Celsius is an important unit of temperature in many fields and is used to measure air temperature, ocean temperature, and many other temperatures.  170 Celsius in Fahrenheit 340°F.Fahrenheit = (Celsius × 9/5) + 32Fahrenheit = (170 × 9/5) + 32Fahrenheit = (1540/5) + 32Fahrenheit = 308 + 32Fahrenheit = 340°F

Therefore, 170 Celsius in Fahrenheit 340°F.

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Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.

Which part of the statement is not true?

Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.

Answers

Primary clarifiers removing biological nutrients is not true. Primary clarifiers

involves the use of processes such as sedimentation in order to remove

particles floating or other inorganic solids from the waste water.

Biological nutrients such as nitrogen and  phosphorus are found in waste

water and removal of these important nutrients for other uses is a part of

waste water management.

The secondary clarifiers are the ones responsible for the removal of

biological nutrients in the waste water through biofiltration etc.

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A boy lifts a 17.8kg microwave oven 3.8 meters off the ground How much work did the boy do on the microwave

Answers

When a boy lifts a 17.8kg microwave oven 3.8 meters distance off the ground then work did the boy do on the microwave is 662.8 J.

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule. Writing for it's dimension,

W=F× s

Force has dimension [L¹ M¹ T²]

distance has dimension [L¹]

multiplying both the dimensions Force and Displacement we get, dimension of Work [L² M¹ T²].

given,

m = 17.8 kg

d = 3.8

W = Fd = mg.d = 17.8×9.8×3.8

W = 662.8 J

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What is meant when we say that a quantity is a vector?
I need a quick answer please ;)​

Answers

A quantity that has both magnitude and direction. It is typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity's magnitude. Although a vector has magnitude and direction, it does not have position

if beam 1 is the incoming beam, which of the other four beams are due to reflection? (select all that apply.)
Beam 1 Beam 2 Beam 3 Beam 4 Beam 5

Answers

The beams 2 and 4 reflect, while the beams 3 and 5 refractively bend. The coefficient of reflection of a substance rises steadily from top to bottom.

What is called beam?

A beam seems to be a part of the structure that defies loads mainly applied horizontally to its axis (an element designed to carry primarily axial load would be a strut or column). Its primary method of displacement is bending. Reaction pressures are produced at the beam's bearing locations as a consequence of the loads placed on it.

Why do we use a beam?

In order to transmit the burden to a vertical load carrying part of the building, beams are used to carry the weight of the building's levels, ceilings, and rooftops.

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if beam 1 is the incoming beam, which of the other four beams are due to reflection? (select all that

Compare the different preure that reult a you add air to a balloon
and a you add air to a teel tank

Answers

When you add air to a balloon, the pressure inside the balloon increases, causing it to expand.

This is because the air pressure outside the balloon is greater than the air pressure inside the balloon. On the other hand, when you add air to a steel tank, the pressure inside increases as well, but the steel tank is able to withstand much higher pressure than a balloon, so the pressure inside the steel tank will not increase as quickly.

When air is added to a balloon, the air pressure inside the balloon increases and causes the balloon to expand. This is because the air pressure outside the balloon is greater than the air pressure inside the balloon, so the pressure inside the balloon increases faster than the pressure inside the steel tank.

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Thomas the giant gorilla stood on a bridge 624 feet above the water below. He picked up a car threw it off the bridge with an initial velocity of 50 feet per second. How long will it take the car to splash into the water below?

Answers

Answer:

The car will take approximately 4.865 seconds to splash into the water.

Explanation:

Let suppose that car moves initially downwards. We must see the kinematics of the car after being thrown off the bridge, it is quite certain that car experiment a free fall, in which it is accelerated uniformly by gravity. The time spent by the car to splash into the water is obtained from this equation of motion:

\(y = y_{o}+v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}\)

Where:

\(y\) - Current height, measured in feet.

\(y_{o}\) - Initial height, measured in feet.

\(v_{o}\) - Initial velocity, measured in feet per second.

\(t\) - Time, measured in seconds.

\(g\) - Gravitational acceleration, measured in feet per square second.

If we know that \(y = 0\,ft\), \(y_{o} = 624\,ft\), \(v_{o} = -50\,\frac{ft}{s}\) and \(g = -32.174\,\frac{ft}{s^{2}}\), this quadratic function is obtained:

\(-16.087\cdot t^{2}-50\cdot t +624 = 0\)

Now we get the roots of the polynomial by Quadratic Formula:

\(t_{1} \approx 4.865\,s\), \(t_{2} \approx -7.973\,s\)

Only the first root is physically reasonable. In a nutshell, the car will take approximately 4.865 seconds to splash into the water.

Answer:

8

Explanation:

what is convection?
what is radiation ?
what conduction?

Answers

--ⓒᴄᴏɴᴠᴇᴄᴛɪᴏɴ ᴏᴄᴄᴜʀꜱ ᴡʜᴇɴ ᴘᴀʀᴛɪᴄʟᴇꜱ ᴡɪᴛʜ ᴀ ʟᴏᴛ ᴏꜰ ʜᴇᴀᴛ ᴇɴᴇʀɢʏ ɪɴ ᴀ ʟɪQᴜɪᴅ ᴏʀ ɢᴀꜱ ᴍᴏᴠᴇ ᴀɴᴅ ᴛᴀᴋᴇ ᴛʜᴇ ᴘʟᴀᴄᴇ ᴏꜰ ᴘᴀʀᴛɪᴄʟᴇꜱ ᴡɪᴛʜ ʟᴇꜱꜱ ʜᴇᴀᴛ ᴇɴᴇʀɢʏ. ... ʟɪQᴜɪᴅꜱ ᴀɴᴅ ɢᴀꜱᴇꜱ ᴇxᴘᴀɴᴅ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ʜᴇᴀᴛᴇᴅ. ᴛʜɪꜱ ɪꜱ ʙᴇᴄᴀᴜꜱᴇ ᴛʜᴇ ᴘᴀʀᴛɪᴄʟᴇꜱ ɪɴ ʟɪQᴜɪᴅꜱ ᴀɴᴅ ɢᴀꜱᴇꜱ ᴍᴏᴠᴇ ꜰᴀꜱᴛᴇʀ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ʜᴇᴀᴛᴇᴅ ᴛʜᴀɴ ᴛʜᴇʏ ᴅᴏ ᴡʜᴇɴ ᴛʜᴇʏ ᴀʀᴇ ᴄᴏʟᴅ.

--Ⓡʀᴀᴅɪᴀᴛɪᴏɴ ɪꜱ ᴇɴᴇʀɢʏ ᴛʜᴀᴛ ᴄᴏᴍᴇꜱ ꜰʀᴏᴍ ᴀ ꜱᴏᴜʀᴄᴇ ᴀɴᴅ ᴛʀᴀᴠᴇʟꜱ ᴛʜʀᴏᴜɢʜ ꜱᴘᴀᴄᴇ ᴀɴᴅ ᴍᴀʏ ʙᴇ ᴀʙʟᴇ ᴛᴏ ᴘᴇɴᴇᴛʀᴀᴛᴇ ᴠᴀʀɪᴏᴜꜱ ᴍᴀᴛᴇʀɪᴀʟꜱ. ... ᴛʜᴇ ᴋɪɴᴅꜱ ᴏꜰ ʀᴀᴅɪᴀᴛɪᴏɴ ᴀʀᴇ ᴇʟᴇᴄᴛʀᴏᴍᴀɢɴᴇᴛɪᴄ (ʟɪᴋᴇ ʟɪɢʜᴛ) ᴀɴᴅ ᴘᴀʀᴛɪᴄᴜʟᴀᴛᴇ (ɪ.ᴇ., ᴍᴀꜱꜱ ɢɪᴠᴇɴ ᴏꜰꜰ ᴡɪᴛʜ ᴛʜᴇ ᴇɴᴇʀɢʏ ᴏꜰ ᴍᴏᴛɪᴏɴ). ɢᴀᴍᴍᴀ ʀᴀᴅɪᴀᴛɪᴏɴ ᴀɴᴅ x ʀᴀʏꜱ ᴀʀᴇ ᴇxᴀᴍᴘʟᴇꜱ ᴏꜰ ᴇʟᴇᴄᴛʀᴏᴍᴀɢɴᴇᴛɪᴄ ʀᴀᴅɪᴀᴛɪᴏɴ

--Ⓒᴄᴏɴᴅᴜᴄᴛɪᴏɴ ɪꜱ ᴛʜᴇ ᴡᴀʏ ɪɴ ᴡʜɪᴄʜ ᴇɴᴇʀɢʏ ɪꜱ ᴛʀᴀɴꜱꜰᴇʀʀᴇᴅ (ᴛʜʀᴏᴜɢʜ ʜᴇᴀᴛɪɴɢ ʙʏ ᴄᴏɴᴛᴀᴄᴛ) ꜰʀᴏᴍ ᴀ ʜᴏᴛ ʙᴏᴅʏ ᴛᴏ ᴀ ᴄᴏᴏʟᴇʀ ᴏɴᴇ (ᴏʀ ꜰʀᴏᴍ ᴛʜᴇ ʜᴏᴛ ᴘᴀʀᴛ ᴏꜰ ᴀɴ ᴏʙᴊᴇᴄᴛ ᴛᴏ ᴀ ᴄᴏᴏʟᴇʀ ᴘᴀʀᴛ).

Methane is to be compressed from 1 atm to 15 atm at 100 kmol//sec. The compressor is isothermal at 60 C.
a) What is the rate of cooling required and the power input required.
b) If the compressor was adiabatic instead of isothermal, can you estimate the work required and the outlet temperature? Why or why not?

Answers

a) Rate of cooling required The rate of cooling required can be calculated using the formula:\(Q = PΔV/t\)where, Q is the rate of cooling required, P is the pressure, ΔV is the change in volume, and t is time.ΔV can be calculated using the formula:\(ΔV = V(f) - V(i)\)where, V(f) is the final volume and V(i) is the initial volume.

Using the ideal gas law:\(PV = nRT\)where, P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

The volume of methane compressed can be calculated using the above formula and then using the equation:\(V = nRT/P\)where, V is the volume, n is the number of moles, R is the gas constant, P is the pressure, and T is the temperature.

The rate of cooling required is calculated as:\(Q = PΔV/t = P (V(f) - V(i))/t\)

The power input required can be calculated using the formula:\(P = Q × ΔT\)where, P is the power input required, Q is the rate of cooling required, and ΔT is the change in temperature.

b) If the compressor was adiabatic instead of isothermal, we cannot estimate the outlet temperature because adiabatic compression does not allow for heat transfer to occur between the system and surroundings.

Therefore, the temperature of the system will increase as a result of the compression process, but the exact value cannot be estimated without further information about the system.

The work required can be estimated using the formula:\(W = nRT ln(P(f)/P(i))\)where, W is the work required, n is the number of moles, R is the gas constant, T is the temperature, P(f) is the final pressure, and P(i) is the initial pressure.

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Why is the upward flux of a vertical vector field f0,0,1 across a surface equal to the area of the projection of the surface in the xy-plane?

Answers

The area of the projection of the surface in the xy-plane <-2x, -2y, -1>.

What is area of the projection?

By projecting a three-dimensional object's form onto any plane, one may estimate the two dimensions of its area. In particular, hardness testing, axial stress, wind pressures, and terminal velocity are frequently utilised in domains of mechanical engineering and architectural engineering that are connected to this.

\(Flux = \int\limit\int\limits_{s} F.N . ds=\int\limits\int\limitsx_{R} < 0,0,1 > < -z_{x} ,-z_{y}, -1 > dA\)

\(=\int\limit\int\limitsx_{R} dA\)

normal vector N = <-2x, -2y, -1>

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A soccer ball was kicked toward the goal. The horizontal component of velocity was 22 m/s and the vertical component was 12 m/s. What is the magnitude of the resultant velocity of the soccer ball?.

Answers

The magnitude of the resultant velocity of the soccer ball is: 25.059 m/s

The formula for projectile motion that we will use to solve this exercise is:

vf= √[v(x)² + v(y)²]

Where:

vf=  final velocityv(x)=  horizontal component of velocityv(y)= vertical component of velocity

Information about the problem:

v(x)= 22 m/sv(y)= 12 m/svf=?

Applying the final velocity formula we have:

vf= √[v(x)² + v(y)²]

vf= √[(22 m/s)² + (12 m/s)²]

vf= √[484 m²/s² + 144 m²/s²]

vf= √[628 m²/s²]

vf= 25.059 m/s

What is projectile motion?

The projectile motion is the motion whose trajectory describes a parabola having a horizontal and a vertical component of motion.

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Could someone please explain isotopes, and what they do/are? If not thats fine, thank you

Answers

Answer:

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

"some elements have only one stable isotope"

Explanation:

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Stephen Strasburg throws out the opening pitch at Nationals Park. The ball starts at rest, but
accelerates to 42 m/s (approximately 95 mph) in the 0.02 seconds it takes to throw. If the ball
has a mass of 0.145 kg, how much force did Strasburg throw with?

Answers

Answer:

Force = 304.5 Newton

Explanation:

Given the following data;

Initial velocity, u = 0m/s (since it started from rest).

Final velocity, v = 42m/s

Time, t = 0.02 secs

Mass = 0.145 kg

To find the force;

First of all, we would have to determine the acceleration of the ball;

Acceleration = (v - u)/t

Acceleration = (42 - 0)/0.02

Acceleration = 42/0.02

Acceleration = 2100 m/s²

Now, we solve for the force;

Force = mass * acceleration

Force = 0.145 * 2100

Force = 304.5 Newton

for a camera equipped with a 55-mm-focal-length lens, what is the object distance if the image height equals the object height? how far is the object from the image on the film?

Answers

In a a camera equipped with a 55-mm-focal-length lens, what is the object distance if the image height equals the object height.The object is effectively located at an infinite distance from the camera lens.

To determine the object distance in this scenario, where the image height equals the object height, we can use the lens formula:

1/f = 1/d_o + 1/d_i

Where:

f is the focal length of the lens,

d_o is the object distance,

and d_i is the image distance.

Given that the focal length (f) is 55 mm, and the image height (h_i) equals the object height (h_o), we can assume that the image distance (d_i) is equal to the focal length (f) due to the nature of the scenario.

Substituting the known values into the lens formula, we have:

1/55 = 1/d_o + 1/55

Simplifying the equation, we get:

1/d_o = 1/55 - 1/55

1/d_o = 0

Since the equation results in 0, it implies that the object distance (d_o) is at infinity in this scenario. The object is effectively located at an infinite distance from the camera lens.

As for the distance between the object and the image on the film, it is not possible to determine it precisely without additional information, such as the specific type of camera and the positioning of the film plane relative to the lens. However, in typical camera setups, the image on the film is formed when the object is located at the focal point of the lens or at a significant distance from the lens, resulting in a sharp image on the film plane.

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What is the current in a 160V circuit if the resistance is 2Ω?
V=
I=
R=

Answers

Explanation:

v = IR

v= 160 R = 2

160 = 2I

2 2

I = 80A

what is the spring constant of a spring that stores 25 j of elastic potential energy when compressed by 7.5 cm?

Answers

Answer:

8. 9×10³N/m

Explanation:

k=2U /x²

= 2(25J) / 0.075m²

=8. 9×10³N/m  

If it is Thursday 2 pm at 90 W, what time and day is it at 60
E?

Answers

If it is Thursday 2 PM at 90W, then it will be Friday 4 PM at 60E. This is because the Earth rotates from west to east, so time zones that are further east are ahead of time zones that are further west.

If it is Thursday 2 PM at 90W, then it will be Friday 4 PM at 60E. This is because the Earth rotates from west to east, so time zones that are further east are ahead of time zones that are further west. 90W is 15 time zones behind 60E, so it is 3 hours earlier.

Here is a table that shows the time difference between 90W and 60E:

Time zone | Time difference

------- | --------

90W | 3 hours earlier

60E | 3 hours later

Please note that this is just a general guideline. The actual time difference may vary depending on the time of year and daylight savings time.

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The Sun radiates energy at the rate of 3.80 ✕ 1026 W from its 5500°C surface into dark empty space (a negligible fraction radiates onto Earth and the other planets). The effective temperature of deep space is −270°C. (Due to the sensitive nature of the calculations, use T(K) = T(°C) + 273.15.(a) What is the increase in entropy (in J/K) in one day due to this heat transfer?

Answers

Given:

The sun radiates energy at a rate of

\(W=3.80\times10^{26}\text{ W}\)

The temperature in the empty space is,

\(\begin{gathered} T_H=5500+273 \\ =5773\text{ K} \end{gathered}\)

The temperature at the deep space is,

\(\begin{gathered} T_c=-270+273 \\ =3\text{ K} \end{gathered}\)

To find:

the increase in entropy (in J/K) in one day

Explanation:

The value of heat is,

\(\begin{gathered} Q_H=Q_c=Q=3.80\times10^{26}\times24\times3600 \\ =3.28\times10^{31}\text{ J} \end{gathered}\)

The change in entropy is,

\(\begin{gathered} \Delta s=-\frac{Q_H}{T_H}+\frac{Q_c}{T_c} \\ =-\frac{3.28\times10^{31}}{5773}+\frac{3.28\times10^{31}}{3} \\ =1.08\times10^{31}\text{ J/K} \end{gathered}\)

Hence, the increase in entropy is

\(1.08\times10^{31}\text{ J/K}\)

A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?

Answers

The speed of the wave on a string is given by Taylor's formula:

\(v=\sqrt[]{\frac{F}{\mu}}\)

where

F = tension force

μ = linear density = mass per unit length

But also we can say the speed of any wave is given by:

\(v=\lambda\times f\)

where:

λ = wave length

f = frequency

Plug the second equation in the first one. We get:

\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)

Now solve for f:

\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)

Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.

See that 340 N = 2 x 170, so we can write:

\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)

Which statement about electromagnetic waves is true?

A.
Electromagnetic waves require a medium to travel.
B.
Electromagnetic waves don't require a medium to travel.
C.
The particles of the medium through which electromagnetic waves travel vibrate perpendicularly to the direction of the wave.
D.
The particles of the medium through which electromagnetic waves travel vibrate parallel to the direction of the wave.

Answers

Answer:

b

Explanation:

Answer:

they transfer energy

Explanation:

What is the density of a substance that has a mass of 20 g and a volume of 10mL

Answers

Answer:

Density =mass/volume 20/10=2

The density of a substance that has a mass of \(20 g\) and a volume of \(10 mL\) is \(2 g/cm^{3}\).

What is density?

Density of substance is defined as its mass per unit volume. Density gives information about how tightly the substance is packed together. The formula for density is

\(d =\frac{m}{V}\)

Where,

\(d =\) density

\(m =\) mass

\(V =\) volume

Unit of density is grams per cubic centimetre.

What are uses of density?

One of the most common uses of density is in how different materials interact when mixed together.

Wood floats on water because it has a lower density than water, while an anchor sinks as the metal has high density.Balloons filled with helium gas float because the density of the helium is low than the density of air.

What is Specific Gravity?

Specific Gravity is the ratio of the substance's density to the density of water. An object having specific gravity less than one will float in water, while a specific gravity greater than one will sink.

Given

\(m = 20g\)

\(V = 10 mL= 10 cm^{3}\)

The density of substance is

\(d =\frac{m}{V}\\d =\frac{20}{10}\\d = 2 g/cm^{3}\)

Hence, The density of a substance that has a mass of \(20 g\) and a volume of \(10 mL\) is \(2 g/cm^{3}\).

To learn more about Density here

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Part A Reflect on how you use electricity at home. Think about times when you might be wasting energy. For example, leaving on appliances, such as lights, wastes energy if you're not using them. Come up with a tip to address the problem you've identified.​

Answers

Answer:

at night unplug EVERYTHING

explanation

when the power is off on a device it still may using a little electricity to recharge the battery inside or keep a clock running, etc. usually there are a lot of things plugged in a home so even if each thing is not using a lot of electricity, ALL the things that plugged in, put together, maybe using A LOT.

Jim rode at an average speed of 12mph in 2 hours the he walked at an average of speed of 3 mph 0.5 hours what was the total distance covered by Jim

Answers

Answer:

12mph in 2hrs and 3mph in 0.5hrs the total distance would be 12*2 and 3*0.5 which would be 24 and 1.5 so we add those 24+1.5= 25.5. The answer would be 25.5

Forces with magnitudes of v = 135 newtons and u = 280 newtons act on a hook (see figure). The angle between the two forces is 45°. Find the direction and magnitude of the resultant of these forces. (Hint: Write the vector representing each force in component form, then add the vectors. Round your answers to two decimal places.)

Forces with magnitudes of v = 135 newtons and u = 280 newtons act on a hook (see figure). The angle between

Answers

To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:

\(\begin{gathered} \vec{v}= \\ \text{ where } \\ v\text{ is the magnitude } \\ \theta\text{ is the angle of the vector with respect to the positive x-axis.} \end{gathered}\)

For force u we notice that its magnitude is 280 N and its angle is zero, then we have:

\(\begin{gathered} \vec{u}=<280\cos0,280\sin0> \\ \vec{u}=<280,0> \end{gathered}\)

For force v we know that its magnitude is 135 N and its angle is 45°, then we have:

\(\begin{gathered} \vec{v}=<135\cos45,135\sin45> \\ \vec{v}=<95.46,95.46> \end{gathered}\)

Now that we have both vectors in component form we add them to get the resultant in component form:

\(\begin{gathered} \vec{F}=\vec{u}+\vec{v} \\ \vec{F}=<280,0>+<95.46,95.46> \\ \vec{F}=<375.46,95.46> \end{gathered}\)

Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:

\(\begin{gathered} F=\sqrt{F_x+F_y} \\ \theta=\tan^{-1}(\frac{F_y}{F_x}) \end{gathered}\)

Plugging the values we found for the components we have:

\(\begin{gathered} F=\sqrt{375.46^2+95.46^2} \\ F=387.41 \end{gathered}\)

and

\(\begin{gathered} \theta=\tan^{-1}(\frac{95.46}{375.46}) \\ \theta=14.27 \end{gathered}\)

Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°

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