A holiday decoration involves blue and white lights the ratio of blue lights to white lights is three to two the box the decorations came in stated that the number of blue lights was 114 but didn't give the number of white lights or the total number of lights.
A) What is the ratio of the number of blue lights to the total number of lights?
B) If the total number of lights is represented by the variable t, create a proportion that you can use to solve for t and solve it.
Answers
The ratio of the number of blue lights to total lights is 3:5
The total number of lights is 190
How to solve for the ratioTo solve the problem we need to have the ratios out first.
we have a ratio of blue to white lights as
3 : 2
The ratio of the number of blue lights to white lights would be
114 : x
Such that we would have
3:2 = 114:x
This would give us
\(\frac{3}{2 } =\frac{114}{x}\)
We would have to solve for the value of x
To do this we are to cross multiply
3*x = 114*2
3x = 228
x = 228 / 3
= 76
ratio = 3 + 2 = 5
3 : 5
The proportion that can be used to solve for t is given as 114 : 3 = 38
38 x 5 = 190
or 114 + 76 = 190
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Related Questions
I need to solve -15 (1/5w -1/3) problem for math class
Answers
-3w-5
hope that helps^^
The U.S Census Bureau provides data on the number of young adults, age 18-24, who are living in their parents’home. Let
M= the event a male young adult is living in his parent’ home
F = the event a female young adult is living in her parent’ home
If we randomly select a male young adult and a female adult, the Census Bureau data enable us to conclude P(M)=0,56 and P(F)=0,42 (The World Almanac, 2006).The probability that both are living in their parent’home is 0,24
a, What is the probability at least one of the two young adults selected is livingin his or her parent’ home?
b, What is the probability both young adults selected are living on their own (neither is living in their parent’ home?
Answers
a) The probability that at least one of the two young adults selected is living in his or her parent’s home is; 0.74.
b) The probability both young adults selected are living on their own is; 0.26
How to solve Conditional Probability?We are given the events as;
M = the event a male young adult is living in his parent’ home
F = the event a female young adult is living in her parent’ home
We are also given that;
Probability that a male young adult is living in his parent’ home; P(M) = 0.56
Probability that a female young adult is living in her parent’ home; P(F) = 0.42
a) The probability that at least one of the two young adults selected is living in his or her parent’ home is;
P(at least one of the two young adults selected is living in his or her parents home) = P(M or F) = P(M) + P(F) - P(M and F)
= 0.56 + 0.42 - 0.24 = 0.74.
B) The probability both young adults selected are living on their own which means neither is living with their parents is;
P(neither living with parents) = 1 - P(M or F)
= 1 - 0.74 = 0.26.
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Differentiate cos 5x
Answers
Answer
\( - 5 \sin(5x) \)
6. Journalise the following transactions
1. Bricks for Rs 60,000 and timber for Rs 35,000 purchased for
the construction of building. The payment was made by cheque.
2. Placed in fixed deposit account at bank by transfer from current
account Rs 13,000.
3. Appointed Mr. S.N. Rao as Accountant at Rs 300 p.m. and
Received Rs 1000 as security Deposit at 5% p.a. interest.
4. Sold goods to shruti for Rs 80,000 at 15% trade discount and
4% cash discount. Received 75% amount immediately through a
cheque.
5. Purchased goods from Richa for Rs 60,000 at 10% trade
discount and 5% cash discount. 60% amount paid by cheque
immediately.
6.
On 18th jan,Sold goods to shilpa at the list price of Rs 50,000
20% trade discount and 4% cash discount if the payment is made
within 7 days. 75% payment is received by cheque on Jan 23rd.
7. On 25th jan, sold goods to garima for Rs 1,00,000 allowed her
20% trade discount and 5% cash discount if the payment is made
within 15 days. She paid 1/4th of the amount by cheque on Feb 5th
and 60% of the remainder on 15th in cash.
8. Purchased land for Rs 2,00,000 and paid 1% as brokerage and
Rs 15,000 as registration charges on it. Entire payment is made by
cheque.
9. Goods worth Rs 25,000 and cash Rs 40,000 were taken away
by the proprietor for his personal use.
10. Sold goods costing Rs 1,20,000 to charu at a profit of 33% 3 %
on cost less 15% trade discount.
9
11. Paid rent of building Rs 60,000 by cheque. Half the building is
used by the proprietor for residential purpose.
12. Sold goods costing Rs 20,000 to sunil at a profit of 20% on
sales less 20% trade discount .
13. Purchased goods for Rs 1000 from nanda and supplied it to
helen for Rs 1300. Helen returned goods worth Rs 390, which in
turn were returned to nanda.
14. Received invoice at 10% trade discount from rohit and sons
and supplied these goods to madan, listed at Rs 3000.
Answers
1.Bricks and timber purchased for construction. (Debit: Bricks - Rs 60,000, Debit: Timber - Rs 35,000, Credit: Bank - Rs 95,000)
2.Transfer of Rs 13,000 to fixed deposit account. (Debit: Fixed Deposit - Rs 13,000, Credit: Current Account - Rs 13,000)
3.Appointment of Mr. S.N. Rao as Accountant. (Debit: Salary Expense - Rs 300, Debit: Security Deposit - Rs 1,000, Credit: Accountant - Rs 300)
4.Goods sold to Shruti with discounts. (Debit: Accounts Receivable - Shruti - Rs 80,000, Credit: Sales - Rs 80,000)
5.Goods purchased from Richa with discounts. (Debit: Purchases - Rs 60,000, Credit: Accounts Payable - Richa - Rs 60,000)
6.Goods sold to Shilpa with discounts and received payment. (Debit: Accounts Receivable - Shilpa - Rs 50,000, Credit: Sales - Rs 50,000)
7.Goods sold to Garima with discounts and received partial payment. (Debit: Accounts Receivable - Garima - Rs 1,00,000, Credit: Sales - Rs 1,00,000)
8.Purchase of land with additional charges. (Debit: Land - Rs 2,00,000, Debit: Brokerage Expense - Rs 2,000, Debit: Registration Charges - Rs 15,000, Credit: Bank - Rs 2,17,000)
9.Proprietor took goods and cash for personal use. (Debit: Proprietor's Drawings - Rs 65,000, Credit: Goods - Rs 25,000, Credit: Cash - Rs 40,000)
10.Goods sold to Charu with profit and discount. (Debit: Accounts Receivable - Charu - Rs 1,20,000, Credit: Sales - Rs 1,20,000)
11.Rent paid for the building. (Debit: Rent Expense - Rs 60,000, Credit: Bank - Rs 60,000)
12.Goods sold to Sunil with profit and discount. (Debit: Accounts Receivable - Sunil - Rs 24,000, Credit: Sales - Rs 24,000)
13.Purchased goods from Nanda and supplied to Helen. (Debit: Purchases - Rs 1,000, Debit: Accounts Payable - Nanda - Rs 1,000, Credit: Accounts Receivable - Helen - Rs 1,300, Credit: Sales - Rs 1,300)
14.Purchased goods from Rohit and Sons and supplied to Madan. (Debit: Purchases - Rs 2,700, Credit: Accounts Payable - Rohit and Sons - Rs 2,700, Debit: Accounts Receivable - Madan - Rs 3,000, Credit: Sales - Rs 3,000)
Here are the journal entries for the given transactions:
1. Bricks and timber purchased for construction:
Debit: Bricks (Asset) - Rs 60,000
Debit: Timber (Asset) - Rs 35,000
Credit: Bank (Liability) - Rs 95,000
2. Transfer to fixed deposit account:
Debit: Fixed Deposit (Asset) - Rs 13,000
Credit: Current Account (Asset) - Rs 13,000
3. Appointment of Mr. S.N. Rao as Accountant:
Debit: Salary Expense (Expense) - Rs 300
Debit: Security Deposit (Asset) - Rs 1,000
Credit: Accountant (Liability) - Rs 300
4. Goods sold to Shruti:
Debit: Accounts Receivable - Shruti (Asset) - Rs 80,000
Credit: Sales (Income) - Rs 80,000
5. Goods purchased from Richa:
Debit: Purchases (Expense) - Rs 60,000
Credit: Accounts Payable - Richa (Liability) - Rs 60,000
6. Goods sold to Shilpa:
Debit: Accounts Receivable - Shilpa (Asset) - Rs 50,000
Credit: Sales (Income) - Rs 50,000
7. Goods sold to Garima:
Debit: Accounts Receivable - Garima (Asset) - Rs 1,00,000
Credit: Sales (Income) - Rs 1,00,000
8.Purchase of land:
Debit: Land (Asset) - Rs 2,00,000
Debit: Brokerage Expense (Expense) - Rs 2,000
Debit: Registration Charges (Expense) - Rs 15,000
Credit: Bank (Liability) - Rs 2,17,000
9. Goods and cash taken away by proprietor:
Debit: Proprietor's Drawings (Equity) - Rs 65,000
Credit: Goods (Asset) - Rs 25,000
Credit: Cash (Asset) - Rs 40,000
10. Goods sold to Charu:
Debit: Accounts Receivable - Charu (Asset) - Rs 1,20,000
Credit: Sales (Income) - Rs 1,20,000
Credit: Cost of Goods Sold (Expense) - Rs 80,000
Credit: Profit on Sales (Income) - Rs 40,000
11. Rent paid for the building:
Debit: Rent Expense (Expense) - Rs 60,000
Credit: Bank (Liability) - Rs 60,000
12. Goods sold to Sunil:
Debit: Accounts Receivable - Sunil (Asset) - Rs 24,000
Credit: Sales (Income) - Rs 24,000
Credit: Cost of Goods Sold (Expense) - Rs 20,000
Credit: Profit on Sales (Income) - Rs 4,000
13. Goods purchased from Nanda and supplied to Helen:
Debit: Purchases (Expense) - Rs 1,000
Debit: Accounts Payable - Nanda (Liability) - Rs 1,000
Credit: Accounts Receivable - Helen (Asset) - Rs 1,300
Credit: Sales (Income) - Rs 1,300
14. Goods received from Rohit and Sons and supplied to Madan:
Debit: Purchases (Expense) - Rs 2,700 (after 10% trade discount)
Credit: Accounts Payable - Rohit and Sons (Liability) - Rs 2,700
Debit: Accounts Receivable - Madan (Asset) - Rs 3,000
Credit: Sales (Income) - Rs 3,000
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Let's roll two dice and find the probability of rolling a certain sum. Is this a simple or compound event?
Two dice - Red and Blue
Recall that a simple event has one and only one outcome of interest. In this example, we are rolling two dice, but we are only interested in one outcome, the sum of the two dice. This is a simple event.
What is the probability of:
Rolling a sum of 1?
Rolling a sum of 3?
Rolling a sum of 12?
Rolling a sum of 7?
Since we are rolling a pair of dice and looking for the sum, the sample space is a little more complicated than rolling one die. The chart below will help us determine the possible outcomes. The top row indicates the numbers on the sides of the blue die and the first column represents the number on the sides of the red die. The white area indicates the sum of the numbers in the row and column.
# Rolled 1 2 3 4 5 6
1 1+1=2
1
+
1
=
2
1+2=3
1
+
2
=
3
1+3=4
1
+
3
=
4
1+4=5
1
+
4
=
5
1+5=6
1
+
5
=
6
1+6=7
1
+
6
=
7
2 2+1=3
2
+
1
=
3
2+2=4
2
+
2
=
4
2+3=5
2
+
3
=
5
2+4=6
2
+
4
=
6
2+5=7
2
+
5
=
7
2+6=8
2
+
6
=
8
3 3+1=4
3
+
1
=
4
3+2=5
3
+
2
=
5
3+3=6
3
+
3
=
6
3+4=7
3
+
4
=
7
3+5=8
3
+
5
=
8
3+6=9
3
+
6
=
9
4 4+1=5
4
+
1
=
5
4+2=6
4
+
2
=
6
4+3=7
4
+
3
=
7
4+4=8
4
+
4
=
8
4+5=9
4
+
5
=
9
4+6=10
4
+
6
=
10
5 5+1=6
5
+
1
=
6
5+2=7
5
+
2
=
7
5+3=8
5
+
3
=
8
5+4=9
5
+
4
=
9
5+5=10
5
+
5
=
10
5+6=11
5
+
6
=
11
6 6+1=7
6
+
1
=
7
6+2=8
6
+
2
=
8
6+3=9
6
+
3
=
9
6+4=10
6
+
4
=
10
6+5=11
6
+
5
=
11
6+6=12
6
+
6
=
12
How many outcomes are in the sample space? Answer
Answers
Answer:
the answer to your question how many outcomes is really gonn adepend on you you slove you problem but my amswer is gonna be 7.
Answer the questions as stated In the picture.
Answers
The areas and perimeters of the shapes are:
Rectangle 1: A = 96 cm^2 and P = 40 cmRectangle 2: A =576 in^2 and P = 86 inRectangle 3: A = 144 ft^2 and P = 60 ftRectangle 4: A = 64 yd^2 and P = 40 ydRectangle 5: A = 280 mm^2 and P = 76 mmRectangle 6: A = 256 m^2 and P = 64 mmWhat are areas?The area of a shape is the amount of space on the shape
What are perimeters?The perimeter of a shape is the sum of the side lengths of the shape
How to determine the areas and the perimeters?Area is calculated as:
A = LW
Perimeter is calculated as:
P = 2(L+W)
When the length and the width are factored by 2, the area and the perimeter become
A = 4LW
P = 4(L+W)
Using the above formulas, we have:
Rectangle 1
A = 4LW = 4 * 4 * 6 = 96 cm^2
P = 4(L+W) = 4 * (4 + 6) = 40 cm
Rectangle 2
A = 4LW = 4 * 12 * 12 = 576 in^2
P = 4(L+W) = 4 * (12 + 12) = 86 in
Rectangle 3
A = 4LW = 4 * 3 * 12 = 144 ft^2
P = 4(L+W) = 4 * (3 + 12) = 60 ft
Rectangle 4
A = 4LW = 4 * 2 * 8 = 64 yd^2
P = 4(L+W) = 4 * (2 + 8) = 40 yd
Rectangle 5
A = 4LW = 4 * 5 * 14 = 280 mm^2
P = 4(L+W) = 4 * (5 + 14) = 76 mm
Rectangle 6
A = 4LW = 4 * 8 * 8 = 256 m^2
P = 4(L+W) = 4 * (8 + 8) = 64 mm
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In KLM, KM is extended through point M to point N,
(3x +19)°, m/LMN = (7x + 5)°, and
m/KLM = (2x+8)°. What is the value of x?
Answers
The value of the variable "x" is 11.
We have a triangle. The vertices of the triangle are K, L, and M. The side KM is extended from point M to point N. The measures of the angles MKL, LMN, and KLM are (3x + 19)°, (7x + 5)°, and (2x + 8)°, respectively. We need to find out the value of the variable "x".
The angles LMK and LMN form a linear pair. It means they are supplementary angles. The sum of the angles is 180°.
∠LMK + ∠LMN = 180°
∠LMK + (7x + 5)° = 180°
∠LMK = 180° - (7x + 5)°
In the triangle KLM, we will use the angle sum property of a triangle. The sum of all the angles in a triangle is equal to 180°.
∠K + ∠L + ∠M = 180°
(3x +19)° + (2x + 8)° + [180° - (7x + 5)°] = 180°
3x +19 + 2x + 8 + 180 - 7x - 5 = 180
-2x + 22 = 0
2x = 22
x = 11
Hence, the value of the variable "x" is 11.
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LA Fitness charges $50 to be a member and $2 each
time you attend the gym. 24 Hour Fitness charges $4
each time you attend the gym and $30 to be a
member.
Using your answer from the lastquestion, you should
have got after 10 visits, the costs will be the same at
either gym.....
How much would each gym cost if you attended 10
times?
$80
$100
$90
$70
$60
Answers
Answer:
$70
Step-by-step explanation:
$50 to start do 2*10 to get 20 add those 50+20=70
Next, $30 to start do 4*10 to get 40 add those 30+40=70
They both come out o $70
Vladimir buys 1.20 pounds of Skittles, 3 1/2 pounds of M&Ms, and 5.2 pounds of pretzels. If the candy cost $1.20 a pound and the pretzels cost $1.10 a pound, how much did Vladimir spend?
Answers
Answer: 12.2408
Step-by-step explanation: This is what I got I hope I got it right:)
the graph of a line is shown on the grid. the coordinates of both point indicated on the graph of the line are integer
Answers
Answer:
-5/6
Step-by-step explanation:
By the application of Analytical geometry the rate of change of y with respect to x is -5/6.
what is Analytical geometry?
Analytical geometry is a branch of mathematics that studies geometric shapes and figures using analytical methods. It is a branch of mathematics that uses algebraic techniques to describe geometric shapes and figures. It involves the use of analytical equations and formulas to study geometric concepts. Analytical geometry is used to study the properties of points, lines, angles, circles, and other geometric shapes. It can also be used to solve problems involving angles, distances, and areas of figures. In addition, analytical geometry can be used to find the intersection of two lines, calculate the area of a circle, and calculate the volume of a cylinder. Analytical geometry is a powerful tool used in many scientific and engineering fields.
The rate of change of y with respect to x for this line is -5/6
Therefore -5/6 is rate of change in this graph.
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Example 1: Every Number Has an Opposite
Locate the number 8 and its opposite on the number line. Explain how they are related to zero.
-8-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
Exercises 2-3
2. Locate and label the opposites of the numbers on the number line.
9
-2
4
a.
b.
C.
8
Answers
Answer:
To locate the number 8 and its opposite on the number line, we can use the given number line:
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
Number 8 is located to the right of zero. Its opposite can be found by moving an equal distance to the left of zero. Since the number line is symmetric about zero, the opposite of 8 would be -8.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑ ↑
So, the opposite of 8 is -8. They are related to zero as equal distances on opposite sides of zero on the number line.
Now, let's address exercises 2-3:
a. To locate the opposite of 9, we need to move an equal distance to the left of zero. The opposite of 9 is -9.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
b. To locate the opposite of -2, we need to move an equal distance to the right of zero. The opposite of -2 is 2.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
c. To locate the opposite of 4, we need to move an equal distance to the left of zero. The opposite of 4 is -4.
-8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7
↑
So, the opposites of the given numbers are:
9 → -9
-2 → 2
4 → -4
They are related to zero as equal distances on opposite sides of zero on the number line.
Step-by-step explanation:
Plsssss help I’m stuck on this one
Answers
9514 1404 393
Answer:
(a) x: Ferris wheel once; y: roller coaster once
Step-by-step explanation:
The coefficients of x and y are both 1 in the equation representing the statement ...
"if he rides them each once, it takes 14 minutes total."
That tells you that x and y represent the times for one ride.
__
The coefficient of x is 6 in the equation representing the statement ...
"he rides the Ferris wheel 6 times ..."
This tells you the variable x represents the Ferris wheel ride time. It is further confirmation that x represents the time for one ride.
(a) The number of terms in an arithmetic progression is 40 and the last is -54. Given that the sum of the 15 terms added to the sum of the first 30 terms is zero. Calculate (1) The first term and common difference, (ii) the sum of the progression.
Answers
(i) The first term (a) is 24 and the common difference (d) is -2.
(ii) The sum of the progression is 2520.
i) Finding the first term and common difference:
Given that the number of terms in the arithmetic progression is 40 and the last term is -54, we can use the formula for the nth term of an arithmetic progression to find the first term (a) and the common difference (d).
The nth term formula is: An = a + (n-1)d
Using the given information, we can substitute the values:
-54 = a + (40-1)d
-54 = a + 39d
We also know that the sum of the first 15 terms added to the sum of the first 30 terms is zero:
S15 + S30 = 0
The sum of the first n terms of an arithmetic progression can be calculated using the formula:
Sn = (n/2)(2a + (n-1)d)
Substituting the values for S15 and S30:
[(15/2)(2a + (15-1)d)] + [(30/2)(2a + (30-1)d)] = 0
Simplifying the equation:
15(2a + 14d) + 30(2a + 29d) = 0
30a + 210d + 60a + 870d = 0
90a + 1080d = 0
a + 12d = 0
a = -12d
Substituting this value into the equation -54 = a + 39d:
-54 = -12d + 39d
-54 = 27d
d = -2
Now we can find the value of a by substituting d = -2 into the equation a = -12d:
a = -12(-2)
a = 24
Therefore, the first term (a) is 24 and the common difference (d) is -2.
ii) Finding the sum of the progression:
The sum of the first n terms of an arithmetic progression can be calculated using the formula:
Sn = (n/2)(2a + (n-1)d)
Substituting the values:
S40 = (40/2)(2(24) + (40-1)(-2))
S40 = 20(48 - 39(-2))
S40 = 20(48 + 78)
S40 = 20(126)
S40 = 2520
Therefore, the sum of the arithmetic progression is 2520.
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Which linear function has the same y-intercept as the one that is represented by the graph?
On a coordinate plane, a line goes through points (3, 4) and (5, 0).
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 3, negative 1, 1, 3. Column 2 is labeled y with entries negative 4, 2, 8, 14.
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 4, negative 2, 2, 4. Column 2 is labeled y with entries negative 26, negative 18, negative 2, 6.
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 5, negative 3, 3, 5. Column 2 is labeled y with entries negative 15, negative 11, 1, 5.
A 2-column table with 4 rows. Column 1 is labeled x with entries negative 6, negative 4, 4, 6. Column 2 is lab
eled y with entries negative 26, negative 14, 34, 46.
Answers
The linear function that has the same y-intercept as the given graph is the equation y = -2x + 10, corresponding to option 3.
To determine the linear function with the same y-intercept as the graph, we need to find the equation of the line passing through the points (3, 4) and (5, 0).
First, let's find the slope of the line using the formula:
slope (m) = (change in y) / (change in x)
m = (0 - 4) / (5 - 3)
m = -4 / 2
m = -2
Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
Using the point (3, 4) as our reference point, we have:
y - 4 = -2(x - 3)
Expanding the equation:
y - 4 = -2x + 6
Simplifying:
y = -2x + 10
Now, let's check the given options to find the linear function with the same y-intercept:
Option 1: The table with x-values (-3, -1, 1, 3) and y-values (-4, 2, 8, 14)
The y-intercept is not the same as the given line. So, this option is not correct.
Option 2: The table with x-values (-4, -2, 2, 4) and y-values (-26, -18, -2, 6)
The y-intercept is not the same as the given line. So, this option is not correct.
Option 3: The table with x-values (-5, -3, 3, 5) and y-values (-15, -11, 1, 5)
The y-intercept is the same as the given line (10). So, this option is correct.
Option 4: The table with x-values (-6, -4, 4, 6) and y-values (-26, -14, 34, 46)
The y-intercept is not the same as the given line. So, this option is not correct.
Therefore, the linear function that has the same y-intercept as the given graph is the equation y = -2x + 10, corresponding to option 3.
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How many 3/8 are in 5/4
Answers
Answer:20
Step-by-step explanation:
Please help and thank you
Answers
Daniella: Were you thinking of perpendicular lines?
Ori: It seems like you've got the basic idea, but your definition could be more precise.
Kaori: Yes! Well done. Here, have a cookie. You've earned it.
Find the Error: Thomas paid a one-time registration fee of $15 and $10 for each cycling class
he took. He determined the equation for this relationship is y = 15x + 10. Find his error and
correct it if it is found. *
Answers
Answer:
y= 15+10x is correct........
How many different lines can be drawn if each line contains at least two of these points?
B
A
D
C
Answers
B) unique line can be drawn through two given points.
(-3,-2) (-4,0) ) slope = _
Answers
Answer:
-2
Step-by-step explanation:
[0-(-2)](rise) over [(-4) - (-3)](run)
2/-1 = -2 = slope
HOPE THIS HELPS!!!!
PLS HELP! WILL GIVE BRAINLIEST
Answers
Answer:
csc x sec x
Step-by-step explanation:
csc = 1/sin
1/sin^2 / cos/sin = 1 / sin^2 * sin/cos = 1 / sin cos = csc sec
Is 6 inches in 10 seconds proportional to 12 inches in 60 seconds?
Answers
Answer: No
Step-by-step explanation:
to be proportional, both numbers have to increase by the same number
because if u multiply 6 by 2 you get 12, but when you multiply 10 by 2 you get 20, not 60 it would be proportional if you said 6 and 10 in to 12 and 20 in
please help me if you know the answer
Answers
Answer:
it's c
Step-by-step explanation:
when doing expression the x means a unknown number and c doesn't have a number so it's C
Need answer to this question please don’t understand it
Answers
we have to do alot for this
so first we gotta change 12.3 into a mixed fraction
n = 5 so 5 ÷ 12.3
30 POINTS!!! PLEASE HELP ME! ASAP
Answers
Answer:
I think is higher
Step-by-step explanation:
write and solve an inequality to find the possible values of x
Answers
The inequality that represents the value of x is (b) x > 80
Writing and solving the inequality for xfrom the question, we have the following parameters that can be used in our computation:
The figure
The general rule is that
The larger the side length, the larger the angle opposite it
using the above as a guide, we have the following:
1/8x > 10
So, we have
x > 80
Hence, the inequality is x > 80
Read more about inequality at
https://brainly.com/question/32124899
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Help me please!? I don’t get it
Answers
9514 1404 393
Answer:
$48
Step-by-step explanation:
You are being asked to find the total surface area of the rectangular prism that is 14 in by 8 in by 4 in. Then you are to multiply that value by 3 (to make it be the area of 3 boxes). After that, you need to multiply by the cost per square inch to find the cost of the wrapping paper for three boxes.
__
The area formula is ...
A = 2(LW +H(L+W))
Filling in the given dimensions, we have ...
A = 2(14×8 +4(14 +8)) = 2(112 +4(22)) = 2(200) = 800 . . . square inches
The area of the box for 1 pair of shoes is 800 square inches, so the area of the boxes for 3 pairs of shoes is ...
3 × 800 in² = 2400 in²
And the cost is ...
(2400 in²)($0.02/in²) = $48
The cost to cover three shoe boxes is $48.
Answer:
48 $ box's............
Which choice is the correct graph of Ix <3?
A +
-6
B++
-6
C
-6
DH
-4
-5
-5
-6 -5
F++
-6
EH
-6
-4
-3
-4
-3
-3
3
-4
-5
-2
-2 -1
OA. Graph A
OB. Graph B
C. Graph C
-3 -2 -1
-2 -1
-20
-2
-3
0
0 1
0
0
-1 0
1
1
1
1
2
2
2
2
2
2
3
3
e
4
3 4
4 5
01
3
4
3
3 4
5
5
5
5
6
6
6
6
6
5
4
6
Answers
Answer:
2347 elevated in the cube
Step-by-step explanation:
nashe
IA...
Perhatikan gambar di bawah ini!
R
doſ 1
OD adalah jari-jari lingkaran dalam segitiga PQR. Jika RQ-28 cm, PR
2D siku-siku dan PD-DQ. hitunglah :
a. Luas segitiga PQR
b. Panjang OD
c. Panjang OQ
ng
JAWABAN
Answers
² = QR² - QT²
= 13² - 5²
= 169 - 25
= 144
TR = √144
TR = 12 cm
Menentukan panjang PR
PR = 2 × TR
= 2 × 12 cm
PR = 24 cm
What kind of transformation is illustrated in this figure?
Answers
The transformation illustrated in the figure is translation.
What is Translation?Translation is a Transformation process in which the size or shape of a figure is not changed rather it only changes the coordinates of the vertices that make up that shape by moving them from one point to another.
Analysis:
Both shapes are congruent, since all the vertices remain in their respective positions even though they were moved and no change in the shape or size, then the transformation process is Translation.
Learn more about Translation: brainly.com/question/12861087
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A tech company is curious about marketing their new drones for home security. Let the proportion of houses that have home security be p. If the tech company would like to know if the proportion of houses that have home security is different than 45%, what are the null and alternative hypotheses
Answers
Answer:
Step-by-step explanation:
The null hypothesis is described as the default hypothesis while the alternative hypothesis us always tested against this null ie the opposite of the null hypothesis.
In this case study, Let the proportion of houses that have home security be p
Thus, the null hypothesis is proportion of houses that have home security is 45% : p = 45%
The alternative hypothesis is proportion of houses that have home security is different than 45%: p =/ 45%