a horizontal force of 100 n is applied to move a 45-kg cart across a 9.0-m level surface. what work is done by the 100-n force?

The bandwidth of the periodic composite signal is drawn as a range between 100 Hz and 2100 Hz , The data rates for sending a digital signal using one harmonic, three harmonics, and five harmonics on a TV channel with a 6 MHz bandwidth would be 6 MHz, 18 MHz, and 30 MHz .

For the first question

Draw the bandwidth of a periodic composite signal, we need to consider the highest frequency component present in the signal.

We have two sine waves one with a frequency of 100 Hz and the other unspecified. Since the bandwidth is given as 2000 Hz, we can assume that the second sine wave has a frequency of 2100 Hz (2000 Hz above the first sine wave frequency).

Draw the bandwidth, we can create a graph with frequency on the x-axis and amplitude on the y-axis.

We plot the amplitude values for the two sine waves at their respective frequencies (100 Hz and 2100 Hz). The bandwidth will be the range between these two frequencies on the x-axis.

For the second question

The data rate for a digital signal transmitted using one harmonic, three harmonics, and five harmonics can be calculated by multiplying the channel bandwidth by the number of harmonics used. Since the bandwidth is given as 6 MHz, the data rates would be as follows:

One harmonic: 6 MHz

Three harmonics: 18 MHz

Five harmonics: 30 MHz

The data rate increases with the number of harmonics used because each harmonic contributes additional information to the signal, allowing for a higher data transmission rate.

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Answer:

4 kg m/s

Explanation:

When finding momentum after a collision, you can just add the momentums together, this would be 10 kgm/s -6 kgm/s to get 4 kgm/s

The total momentum of the carts after the collision is 4 kgm/s.

The momentum of an object is the product of mass and velocity of the object.

P = mv

The total momentum of the carts is calculated as follows;

P = P₁ + P₂

P = -6 + 10

P = 4 kgm/s

Thus, the total momentum of the carts after the collision is 4 kgm/s.

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Answer:

1 m/s

Explanation:

Impulse = Change in momentum

Force × Time = Mass(Final velocity) - Mass(Initial Velocity)

(1.0)(1.0) = (1.0)(Final Velocity) - (1.0)(0)

Final velocity = 1 m/s

The final speed of the skier depends on the slope's angle, the coefficient of friction, and the distance traveled. More information is needed to calculate the final speed accurately.

The final speed of the skier depends on several factors such as the slope's angle, the coefficient of friction between the skier and the snow, and the distance traveled. Without knowing these parameters, it is impossible to calculate the final speed accurately. However, we can use the conservation of energy principle to estimate the final speed.

According to the principle of conservation of energy, the total energy of the system remains constant. Initially, the skier has only potential energy, which is converted into kinetic energy as the skier slides down the slope. Assuming there is no significant air resistance, the total mechanical energy of the skier remains constant. Therefore, the kinetic energy gained by the skier equals the potential energy lost by the skier.

The potential energy of the skier is given by mgh, where m is the mass of the skier, g is the acceleration due to gravity, and h is the height of the slope. When the skier reaches the bottom of the slope, the potential energy is converted entirely into kinetic energy, which is given by (1/2)mv^2, where v is the final velocity of the skier. Setting these two equations equal, we can solve for v.

v = sqrt(2gh)

where sqrt represents the square root function.

In conclusion, the final speed of the skier can be estimated using the above equation if the height of the slope is known. However, for a more accurate calculation, other factors such as friction should also be considered.

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Answer:

starch into simple sugars

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the ratio of the moment of inertia through the second axis to the moment of inertia through the first axis is 0.676

The second axis is at the centroid of the rod.

The length of the rod is L = 100 cm = 1 m

The first axis is located at 20 cm = 0.2 m from the centroid.

Let m =  the mass of the rod.

The moment of inertia about the centroid (the 2nd axis) is

Ig =  ml^3/12 = (m kg) (1 m)^2/12 = m/12 kg - m^2

The parallel axis theorem states that

I1 = m/12+0.04 m = 0.1233 m kg - m2 is the moment of inertia about the first axis.

The ratio of the moment of inertia through the centroid of the second axis to the first axis is

Ig/I1= 0.0833 m / 0.1233 m = 0.676

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Lightning arresters are devices that are used in electrical systems to protect them from the destructive power of lightning. The use of lightning arresters in electrical systems is necessary because lightning is one of the most significant sources of transient over voltages, which can cause serious damage to electrical systems and equipment.

Lightning arresters work by providing a low-impedance path for the high-voltage surges caused by lightning. They are designed to conduct the high currents that are generated by lightning strikes to the ground, thus protecting the electrical system from damage.

During normal operation, lightning arresters are an open circuit. However, during a lightning strike, they become a closed circuit, providing a low-impedance path for the lightning current. When the lightning strikes the lightning arrester, an arc is created between the electrodes of the arrester, which is like a short circuit.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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A hot air balloon is 100 feet above the ground when a motorcycle (traveling in a straight line on a horizontal road) passes directly beneath it going 45 miles/hour.

Given that, The altitude of the balloon from the ground = 100 feet The velocity of the motorcycle = 45 miles/hour = 66 feet/second Rate of ascending of the balloon = 10 feet/second Now, When the motorcycle passed the balloon, both of them are on the same line passing through the ground.

Let the length of the balloon be L. The time taken for the balloon to move L distance = L / Rate of ascent of balloon L = 0 because it is already in sight. Hence, the motorcycle driver has to travel for no time before the balloon is out of sight.

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Answer:

\(1.2\; {\rm N}\), assuming that all other forces on this crab were balanced.

Explanation:

The impulse \(J\) on an object is equal to the change in momentum \(\Delta p\). In other words:

\(J = \Delta p\).

If the mass \(m\) of the object stays the same (as in the case of this question), the change in momentum can be rewritten as:

\(J = \Delta p = m\, \Delta v\), where \(\Delta v\) is the change in velocity.

Impulse is also equal to the net force on the object \(F_{\text{net}}\) times the duration \(\Delta t\) over which the force is applied:

\(J = F_{\text{net}}\, \Delta t\).

Equate the two expressions for \(J\) to obtain:

\(F_{\text{net}}\, \Delta t = m\, \Delta v\).

In this question:

Rearrange \(F_{\text{net}}\, \Delta t = m\, \Delta v\) and solve for the net force \(F_{\text{net}}\):

\(\begin{aligned}F_{\text{net}} &= \frac{m\, \Delta v}{\Delta t} \\ &= \frac{(3\; {\rm kg})\, (2\; {\rm m\cdot s^{-1}})}{5\; {\rm s}} \\ &= 1.2\; {\rm kg \cdot m\cdot s^{-2}} \\ &= 1.2\; {\rm N}\end{aligned}\).

Assuming that all other forces on this crab are balanced, the net force on the crab would be equal to the force from the tide. Hence, the tide would have pushed the crab with a force of \(1.2\; {\rm N}\).

The ways to store one kilogram of mushrooms for an extended period: You can refrigerate them in a breathable container, dry them for later use, freeze them after blanching, can them in jars, or pickle them in a vinegar solution.

There are multiple ways to store one kilogram of mushrooms for an extended period. Here are a few suggestions:

Refrigeration: Place the mushrooms in a paper bag or a breathable container and store them in the refrigerator. This helps to slow down the growth of bacteria and fungi, keeping the mushrooms fresh for a longer time. Make sure to avoid storing them near foods with strong odors as mushrooms can absorb flavors.

Drying: Slice the mushrooms into thin pieces and dry them. You can use a food dehydrator, an oven set to low heat, or air-dry them in a well-ventilated area. Once they are completely dried, store them in an airtight container or a vacuum-sealed bag. Dried mushrooms can be rehydrated before use.

Freezing: Clean and slice the mushrooms, then blanch them quickly in boiling water for a couple of minutes. Drain and cool them before placing them in freezer-safe bags or containers. Freezing helps to preserve the mushrooms' texture and flavor. Thaw them before using or cook them directly from frozen.

Canning: Preserve mushrooms by canning them in jars. This involves cooking the mushrooms in a brine or vinegar solution and sealing them in sterilized jars. Canned mushrooms can be stored at room temperature and have a longer shelf life.

Pickling: Pickling mushrooms is another method to extend their storage life. Prepare a pickling solution using vinegar, water, salt, and desired spices. Cook the mushrooms briefly, then transfer them to sterilized jars and pour the pickling solution over them. Seal the jars and store them in a cool, dark place.

Remember to follow proper food safety guidelines and ensure that the mushrooms are fresh and in good condition before storing them. The chosen storage method may depend on personal preference, the intended use of the mushrooms, and the available resources.

Therefore, The following are some ideas for long-term mushroom storage per kilogram: After blanching, you can freeze them, preserve them in jars, dry them for later use, store them in the refrigerator in a breathable container, or pickle them in a vinegar solution.

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The far that can it glide in terms of distance measured along the ground is 38,500 ft.

Given that,

World War I Sopwith Camel was 7.7.

If the aircraft is in flight at 5000 ft when the engine fails.

Based on the above information, the calculation is as follows:

\(\begin{aligned}& \frac{\text { lift }}{d r a g}=\frac{\text { Distance }}{\text { height }} \\& 7.7=\text { Distance } \div 5500\end{aligned}\)

So, the distance is 38,500 ft.

Distance is a measurement of how far away two things or locations are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in common use.

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The kinetic energy of an object is directly proportional to its mass and the square of its velocity. In this scenario, Susan has a smaller mass than Hannah but a greater velocity.

Therefore, Susan's kinetic energy is calculated as 0.5 x 25 kg x (10 m/s\()^2\)= 1250 joules, while Hannah's kinetic energy is calculated as 0.5 x 30 kg x (8.5 m/s\()^2\) = 1083.8 joules. Hence, Susan's kinetic energy is greater than Hannah's. This suggests that speed has a greater effect than mass in determining the kinetic energy of an object. In general, both mass and speed contribute to an object's kinetic energy, but the effect of speed is more significant.

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The frequency of its circular motion is\(2.67 *10^8 Hz\). This frequency represents the number of complete circles that the electron makes in one second. It is also known as the cyclotron frequency.

To calculate the speed of the electron, we need to use the equations for the motion of a charged particle in a magnetic field.

First, we can calculate the acceleration of the electron due to the potential difference. We know that the potential difference is 450 V, which is also equal to the electron's kinetic energy. Therefore, we can use the equation for kinetic energy:

\(KE =\frac{ 1}{2} mv^2\)

where KE is the kinetic energy, m is the mass of the electron, and v is its velocity. We can rearrange this equation to solve for v:

\(v = \sqrt(\frac{2KE}{m})\)

We know that KE = eV, where e is the charge of the electron and V is the potential difference, so we can substitute:

\(v = \sqrt(\frac{2eV}{m})\)

where e is the elementary charge \((-1.602 * 10^{-19 }C)\) and m is the mass of the electron\((9.109 *10^{-31} kg)\). Plugging in the values, we get:

\(v = \sqrt\frac{(2*(-1.602 *10^{-19} C)*(450 V)}{(9.109 * 10^{-31} kg)}) \\ = 6.02 x 10^6 m/s\)

This is the initial speed of the electron as it enters the magnetic field.

Next, we need to consider the motion of the electron in the magnetic field. Since the electron's velocity is perpendicular to the magnetic field, it will experience a force that is perpendicular to both its velocity and the magnetic field. This force can be calculated using the equation:

F = qvB

where F is the magnetic force, q is the charge of the electron, v is its velocity, and B is the magnetic field strength.

The magnetic force will cause the electron to move in a circular path with a radius given by the equation:

\(r =\frac{ mv }{ (qB)}\)

where r is the radius of the circular path.

Since we know the velocity of the electron and the magnetic field strength, we can calculate the radius of the circular path:

\(r = \frac{mv }{ (qB)}\)

\(=\frac{ (9.109 * 10^{-31} kg) * (6.02 * 10^{6 }m/s) }{ (1.602 *10^{-19 }C * 0.170 T) }\\\\= 1.18 * 10^{-2} m\)

Finally, we can use the speed of the electron and the radius of its circular path to calculate the frequency of its circular motion:

\(f =\frac{v}{ (2\pi r) }\\ = \frac{(6.02 * 10^{6 }m/s) }{ (2\pi * 1.18 * 10^{-2 }m)} \\= 2.67 * 10^{8 }Hz\)

This frequency represents the number of complete circles that the electron makes in one second. It is also known as the cyclotron frequency, and is a useful parameter in many applications involving charged particles in magnetic fields.

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Answer: Explanation:

Locations above the Arctic Circle (north of 66.5 degrees latitude; 90 degrees minus the tilt of Earth's axis) receive 24 hours of sunlight.

Orbits: Sun

The kinetic energy of the car is 125000 J (joules).

The kinetic energy (KE) of an object is given by the formula KE = 1/2 * m * v², where m is the mass of the object and v is its velocity. Plugging in the values for the car, we get:

Therefore, the kinetic energy of the car is 125000 joules.

Kinetic energy is the energy an object possesses due to its motion. It is defined as one half of the mass of the object multiplied by the square of its velocity. Kinetic energy is a scalar quantity and is measured in joules (J) in the International System of Units (SI). The greater the mass and velocity of an object, the greater its kinetic energy. When an object loses its motion, its kinetic energy is transformed into other forms of energy.

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Answer:

the bike will probly  go flying and the truck will go to a stop and the truck will  not flyover the bike bc the truck is heavier

Explanation:

The impact force and the change in acceleration of cycle will be greater.

We have a situation of head on collision between a bicycle and a massive truck.

We have to -

A head-on collision is a traffic collision where the front ends of two vehicles such as cars, trains, ships or planes hit each other when travelling in opposite directions.

According to the question -

Suppose that both the cycle and truck are moving with the same velocity v m/s.

PART - A

The difference between the mass of the cycle and truck is very large.

This means that the momentum of both cycle (c) and truck (t) will be -

p(t) >> p(c)

Hence, the impact force on the cycle is very very high.

PART - B

Since, the impact force on cycle is very high therefore the change in acceleration of cycle will be greater.

Hence, the impact force and the change in acceleration of cycle will be greater.

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This is due to the fact that the first and second laws of thermodynamics are universally applicable fundamental principles that can be utilised to examine particular systems and processes.

The part of thermodynamics that deals with chemical reactions is called chemical thermodynamics. The first law states that energy is conserved and cannot be created or destroyed. Second law: When natural processes in a closed system result in a rise in entropy, they are spontaneous.

According to the second rule of thermodynamics, an isolated system that is out of equilibrium over time must increase in entropy until it reaches the ultimate equilibrium value.

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Answer: D. Lever

Explanation: The biceps muscle provides the effort (force) and bends the forearm against the weight of the forearm and any weight that the hand might be holding. Many muscle and bone combinations in our bodies are of the Class 3 lever type.

Answer:

His new horizontal range is 4 times his initial range.

Explanation:

Since Mike serves the ball with velocity, u, his horizontal range is

R = u²sin2Ф/g where Ф is the angle between u and the horizontal.

Now, if on his second serve, the ball leaves his hand with twice the velocity of his initial serve, the new velocity is v = 2u.

So, the new range R' = v²sin2Ф/g

R' = (2u)²sin2Ф/g

R' = 4u²sin2Ф/g

Since R = u²sin2Ф/g,

R' = 4u²sin2Ф/g

R' = 4R

So, his new horizontal range is 4 times his initial range.

The pairs for which there is a point at which Vnet = 0 to the right of the particles are those with opposite charges, i.e., one positive and one negative charge.

In the context of electric charges and forces, Vnet refers to the net electric potential at a point in space due to two or more charged particles.

To find the pairs for which Vnet = 0 to the right of the particles, we must identify when the electric potential contributions from each particle cancel each other out.

Consider two charged particles with charges Q1 and Q2, separated by a distance r.

If both charges have the same sign (either positive or negative), the electric potentials created by them will add up, and there won't be a point to the right of the particles where Vnet = 0.

However, if the charges have opposite signs, one being positive and the other negative, there exists a point between them where their electric potentials cancel each other out, making Vnet = 0.

This occurs because the positive charge creates a positive electric potential while the negative charge creates a negative electric potential.

When these values are equal in magnitude and opposite in sign, they sum up to zero.

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Answer:

B

Explanation:

Gravity, the attractive force between all masses, is what keeps the planets in orbit. Newton’s universal law of gravitation relates the gravitational force to mass and distance

The force of gravity is what gives us our sense of weight. Unlike mass, which is constant, weight can vary depending on the force of gravity (or acceleration) you feel. When Kepler’s laws are reexamined in the light of Newton’s gravitational law, it becomes clear that the masses of both objects are important for the third law, which becomes a3 = (M1+ M2) × P2. Mutual gravitational effects permit us to calculate the masses of astronomical objects, from comets to galaxies.

The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.

From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:

Δx = (vf² - vi²) / 2a

Substituting the values, we get:

2.25 = (1.38² - 0) / (2 * 0.087)

Solving for time (t), we get:

t = 2.25 * 0.087 / 1.897

t ≈ 0.104 seconds

Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.

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Answer:

\( \boxed{\sf Distance \ travelled = 62.5 \ m} \)

Given:

Initial velocity (u) = 25 m/s

Final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\( \boxed{ \bold{s = (\frac{v + u}{2} )t}}\)

By substituting value of v, u & t in the equation we get:

\( \sf \implies s = ( \frac{0 + 25}{2} ) \times 5 \\ \\ \sf \implies s = \frac{25}{2} \times 5 \\ \\ \sf \implies s = 12.5 \times 5 \\ \\ \sf \implies s = 62.5 \: m\)

\( \therefore\)

Distance travelled by car (s) = 62.5 m

The distance  car travel during that time is 62.5 meter.

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Initial velocity (u) = 25 m/s

As the car becomes rest, final velocity (v) = 0 m/s (Rest)

Time taken (t) = 5 seconds.

The deceleration of the car: a = (initial speed - final speed)/time interval

= ( 25 m/s - 0 m/s)/5 second

= 5 m/s²

The distance  car travel during that time = ut - at²/2

= 25 × 5.0 meter - (5×5²/2) meter

= 62.5 meter.

Hence, the distance  car travel during that time is  62.5 meter.

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Answer:

Unlike acceleration, the average acceleration is calculated for a given interval. Here, Δ v is the change in velocity and Δ t is the total time over which the velocity is changing. If the velocity of a marble increases from 0 to 60 cm/s in 3 seconds, its average acceleration would be 20 .

Hope it helps.

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If a car, starting from rest, accelerates at 4.0 m / sec², then its velocity at the end of 8.0 seconds would be 32.0 meters per second.

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem if a car, starting from rest, accelerates at 4.0 m / sec ² , then we have to find its velocity at the end of 8.0 seconds,

By using the first equation of the motion to calculate the velocity of the car after 8.0 seconds.

v = u + a × t

  = 0 + 4.0 × 8.0

  = 0 + 32.0

   = 32.0 m / s

Thus, If a car, starting from rest, accelerates at 4.0 m / sec², then its velocity at the end of 8.0 seconds would be 32.0 meters per second.

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Answer: 2934.75 Joules

Explanation:

Potential energy can be defined as energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

P.E = mgh

Where P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per second square.

h represents the height measured in meters.

Given the following data;

Weight =645

Height = 4.55

P.E = mgh

But we know that weight = mg = 645N

Substituting into the equation, we have;

P.E = 645 • 4.55

P.E = 2934.75J

Potential energy, P.E = 2934.75 Joules.

The new volume of the gas is approximately 40 ml. This result makes sense, as increasing the pressure of the gas while keeping the temperature constant will result in a decrease in volume, according to Boyle's Law.

To calculate the new volume of the gas, we can use Boyle's Law formula, which states that the pressure and volume of a gas are inversely proportional, provided that the temperature and amount of gas remain constant.

Mathematically, Boyle's Law can be expressed as \(P_1V_1 = P_2V_2\), where \(P_1\)and \(V_1\) are the initial pressure and volume, and \(P_2\) and \(V_2\) are the final pressure and volume.

In this case, we know that the initial volume \(V_1\) is 50 ml, the initial pressure \(P_1\) is 81.0 kPa, and the final pressure \(P_2\) is 101.3 kPa. We can plug these values into the Boyle's Law formula and solve for \(V_2\):

\(P_1V_1 = P_2V_2\)

\(V_2 = \frac{P_1V_1}{P_2}\)

\(V_2\) = (81.0 kPa x 50 ml) / 101.3 kPa

\(V_2\) = 40 ml (rounded to two significant figures)

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Given:

The flow of energy

To find:

The flow of energy from coal in a power plant to a lightbulb in your bedroom

Explanation:

Coal-fired plants produce electricity by burning coal in a boiler to produce steam. Here the chemical energy changes to potential energy or mechanical energy in the form of steam.

Under tremendous pressure, the steam flows into a turbine, which spins a generator to create electricity. Here the mechanical energy converts into electrical energy.

The steam is then cooled, condensed into the water, and returned to the boiler to start the process.

The electrical current is sent through transformers, which increase the voltage so the power can be pushed over long distances.

The electricity reaches a substation from the transmission lines, where the voltage is lowered so it can be sent on smaller power lines.

The electricity is then sent through distribution lines to your neighborhood. Smaller transformers lower the voltage again so that the power is safe to use in our homes.

The electricity connects to your house, passing through a meter which measures the amount of electricity you use.

Finally, the electricity travels through wires inside the walls to the outlets and switches in your house - ready to power your devices!