(a) Is 2 ⊆ {2, 4, 6}?
(b) Is {3} ∈ {1, 3, 5}?

The equation of line passing through the point (4, 6) and parallel to x axis is y = 6.

According to the given question.

A line which is passes through the point (4, 6).

And also parallel to x-axis.

As we know that, the equation of line parallel to the x-axis, cuts the y-axis at the point (0, b) is y = b.

Since, the line is passing through the point (4, 6) and parallel to x-axis, cuts the y-axis at the point (0, 6).

As per the formula, the equation of line passing through the point (4, 6) and parallel to x axis is y = 6.

Hence, the equation of line passing through the point (4, 6) and parallel to x axis is y = 6.

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Answer:

50 %

Step-by-step explanation:

i think this is the answer

Answer:

75,76,84,85,87,88,90,91,92,94,99

Step-by-step explanation:

a) the dimension of its column space is also 2. b) the rank of A is 2. c) the nullity of matrix A is 1. d) the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

(a) The dimension of the row space of a matrix is equal to the dimension of its column space. So, if the dimension of the row space of matrix A is 2, then the dimension of its column space is also 2.

(b) The rank of a matrix is defined as the maximum number of linearly independent rows or columns in the matrix. Since the dimension of the row space of matrix A is 2, the rank of A is also 2.

(c) The nullity of a matrix is defined as the dimension of the null space, which is the set of all solutions to the homogeneous equation Ax = 0. In this case, the matrix A is a 3 x 3 matrix, so the nullity can be calculated using the formula:

nullity = number of columns - rank

nullity = 3 - 2 = 1

Therefore, the nullity of matrix A is 1.

(d) The dimension of the solution space of the homogeneous system Ax = 0 is equal to the nullity of the matrix A. In this case, we have already determined that the nullity of matrix A is 1. Therefore, the dimension of the solution space of the homogeneous system \(A_x = 0\) is also 1.

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Answer:

B (4, 1)

Step-by-step explanation:

When you rotate 90 degrees about the origin you do (x,y) ----> (y, -x)

So let's do that first to your points.

(-4, 1) -----> (1, 4)

Now we have to do y = x you do this (x,y) ---> (y, x)

All we have to do now is switch them again.

(1, 4) ----> (4,1)

Hope this helps ya!!

The four integers are -3, 8, -4, and 6.

i.e,

-3 x 8 = -24

-4 x 6 = -24

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

a x b = - 24

Where a and b are integers.

Now,

The factors of 24 are:

-1 x 24 = -24

-2 x 12 = -24

-3 x 8 = -24

-4 x 6 = -24

or

1 x -24 = -24

2 x -12 = -24

3 x -8 = -24

4 x -6 = -24

So,

The integers can be -1, -2, -3, -4, -24, -12, -8,  and -6.

Thus,

The four integers can be -3, 8, -4, and 6.

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To find the probability that both events occur (the kids eat their vegetables and the dog plays in the mud), we need to multiply their individual probabilities:  0.43 (probability of kids eating vegetables) x 0.38 (probability of dog playing in mud) = 0.1634

To find the probability of two independent events happening at the same time, you can multiply the probabilities of each event. In this case, the events are your brother's kids eating vegetables and your dog playing in the mud.
Probability of kids eating vegetables = 43% (0.43 as a decimal)
Probability of dog playing in the mud = 38% (0.38 as a decimal)
Now, we multiply these probabilities:
0.43 * 0.38 ≈ 0.1634
So, the probability of both events happening when your brother's family visits for dinner after a huge rainstorm is approximately 0.163 or 16.3%.

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Answer:

165 i believe ................

\(\text{Arc length,}\\\\s = r \theta \\\\~~=12\cdot \left(30 \times \dfrac{\pi}{180} \right)\\\\~~=12\cdot \dfrac{\pi}6\\\\~~=2\pi\)

Answer:

I think it's B I really don't know though

Answer:

Sorry dud it been long time I've not answered 0ne

Answer:

Heyy

Step-by-step explanation:

Did ya get the answer ???

The perimeter of triangle WXY is (8a + 3b - 5) in

the perimeter of the polygon is (4a + 8b -1) in.

The perimeter of triangle WXY is solved using addition of sides

perimeter of triangle = (2b + a) in + (4a - 3) in. +  (3a + b - 2) in.

perimeter of triangle = 8a + 3b - 5 in

perimeter of polygon = perimeter  of triangle WYZ - (4a - 3) in + (2b + a) in + (3a + b - 2) in.

perimeter of polygon = (4a + 5b - 2) in - (4a - 3) in + (2b + a) in + (3a + b - 2) in.

perimeter of polygon = (4a + 8b -1) in.

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====================================================

Explanation:

The two points given are

C = (x1,y1) = (2,-1)

D = (x2,y2) = (5,3)

Use the distance formula

\(d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(2-5)^2 + (-1-3)^2}\\\\d = \sqrt{(-3)^2 + (-4)^2}\\\\d = \sqrt{9 + 16}\\\\d = \sqrt{25}\\\\d = 5\\\\\)

The distance from C to D is 5 units. This is the same as saying segment CD is 5 units long.

The artificial variables is x1 ≥ 0, x2 ≥ 0, x3 ≥ 0, A1 ≥ 0, A2 ≥ 0

To reformulate the given problem as a convenient artificial problem for preparing to apply the simplex method, we introduce artificial variables. The steps to reformulate the problem are as follows:

1. Introduce the artificial variables. For each inequality constraint, introduce an artificial variable by subtracting a slack variable from the left-hand side of the inequality.

The problem can be reformulated as follows:

Minimize Z = 2x1 + x2 + 3x3

subject to:

5x1 + 2x2 + 7x3 + A1 = 420    (Equation 1)

3x1 + 2x2 + 5x3 + A2 = 280    (Equation 2)

where A1 and A2 are the artificial variables.

2. Rewrite the problem with the added artificial variables. The reformulated problem becomes:

Minimize Z = 2x1 + x2 + 3x3 + 0A1 + 0A2

subject to:

5x1 + 2x2 + 7x3 + A1 = 420    (Equation 1)

3x1 + 2x2 + 5x3 + A2 = 280    (Equation 2)

x1 ≥ 0, x2 ≥ 0, x3 ≥ 0, A1 ≥ 0, A2 ≥ 0

By introducing the artificial variables, we have transformed the original problem into a convenient artificial problem that can be solved using the simplex method.

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The complete question is:

Consider the following problem.

Minimize

Z = 2x_{1} + x_{2} + 3x_{3}

x_{3} >= 0

subject to

5x_{1} + 2x_{2} + 7x_{3} = 420

3x_{1} + 2x_{2} + 5x_{3} >= 280

and

x_{1} >= 0

x_{2} >= 0

Introduce artificial variables to reformulate this problem as a convenient artificial problem for preparing to apply the simplex method.

Answer:

7.2

Hope it was helpful.

Answer:

7.2!! :)

Step-by-step explanation:

The probability of Thuy rolling a 4 exactly 2 times is 1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 = 5⁵/6⁷

We know that:

Thuy rolls a number cube 7 times,

so the total outcomes are: 6.

Also, it is asked to find the probability of rolling a 4 exactly 2 times.

So it could be done by the method that:

1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6,

where 1/6 denotes the probability of rolling a 4 and 5/6 denotes the probability of rolling a number other than 4

therefore we know that, the probability of rolling a 4 exactly 2 times is 1/6 × 1/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 × 5/6 = 5⁵/6⁷

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Answer:

option a

Step-by-step explanation:

hope this helps

The expression that is an element of AxBxB is (1,2,3)

The given data is A= (a, b}, B = {1,2,3}

The product of two matrices A and B is defined if the number of columns of A is equal to the number of rows of B. If both A and B are square matrices of the same order, then both AB and BA are defined.

\(& \ A \times B=\left\{\begin{array}{c}(a, 1),(a, 2),(a, 3),(b, 1) \\(b, 2),(b, 3)\end{array}\right. \\\)

\(& A \times B \times B=\left\{\begin{array}{l}(a, 1,1),(a, 1,2),(a, 1,3), \\(a, 2,1),(a, 2,2),(a, 2,3),\end{array}\right. \\& (a, 3,1),(a, 3,2),(a, 3,3) \\ & (b, 1,1),(b, 1,2),(b, 1,3) \\& \left.\begin{array}{l}(b, 2,1),(b, 2,2),(b, 2,3) \\(b, 3,1),(b, 2),(b, 3,3)\end{array}\right\} \\\)

\(& \therefore(b, 2,3) \in D \times B \times B \\\\& (a, a, 1) \notin A \times B \times B \\\\& \left(b, 2^2\right) \quad \forall A \times B \times B \\\\& (2,1,1) \notin A \times B \times B \\\\&=(b, 2,3) \in \cap \times B \times B \\&\end{aligned}\)

The union of two sets X and Y is equal to the set of elements that are present in set X, in set Y, or in both the sets X and Y.

The intersection of sets can be denoted using the symbol ‘∩’. As defined above, the intersection of two sets A and B is the set of all those elements which are common to both A and B. Symbolically, we can represent the intersection of A and B as A ∩ B.

Therefore, the expression that is an element of AxBxB is (1,2,3).

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By using a system of equations of two variables the number of short answer problems is 10.

Total number of problems in the Test = 30

Maximum points of test = 50

Point of multiple choice = 1

Point of short answer problems = 3

Let the number of multiple choice questions is x and the number of short answer problems is y

So, x + y = 30    - (1)

and 1.x + 3.y = 50 ⇒ x + 3y = 50      -(2)

Equation (2) - Equation (1)

x + 3y - (x + y) = 50 - 30

2y = 20

y = 10

Put y = 10 in equation (1)

x = 30 - 10 = 20

Hence, the number of multiple-choice questions = 20 and the number of short answer problems = 10.

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Answer:

1 is the answer to your question mate

Answer:

maybe 90*

Step-by-step explanation:

Answer:

Unprovided measurements make question impossible to solve without a probability of sorts.

Step-by-step explanation:

Measure the edges and provide them with your question.

Answer:

They are on the 0 yard line

Step-by-step explanation:

15yards - 7yds + 3yds = 4 yards

4 yards - 7yds + 3yds = 0 yards

0 yards

(sorry if I misunderstood)

Answer:

To find the number of highway signs on the road trip, we need to divide the total length of the trip by the time between each sign, including the last one.

First, we need to find out how many signs are posted during the trip. To do this, we can divide the total length of the trip by the time between each sign:

16.2 / 0.6 = 27

So there will be 27 signs posted during the trip, including one at the end.

Therefore, there will be 27 highway signs on the road trip.

Answer:

The mathematical problem that forms the basis of most modern cryptographic algorithms is the difficulty of factoring large prime numbers.

Step-by-step explanation:

The problem that forms the basis of most modern cryptographic algorithms is the difficulty of factoring large integers into their prime factors. This is known as the integer factorization problem. It is believed to be a computationally hard problem, meaning that it would take an impractically long time to factor very large integers using classical computers. Many cryptographic algorithms, such as RSA, rely on this problem for their security.

Answer:

(8, -22)

Step-by-step explanation:

If you solve to find the slope of the first table on the left you get -4x +10 and the second table you get -3x+2. You can find their intersection on the calculator and get (8, -22)

9514 1404 393

Answer:

  13√731 ≈ 351.48 cm²

Step-by-step explanation:

When given three sides of a triangle, there are a number of ways that the area may be calculated. Perhaps the most straightforward is the use of Heron's formula.

Where s is the semi-perimeter, the area is given by ...

  A = √(s(s -a)(s -b)(s -c)) . . . . . . . . s = (a+b+c)/2

Here, the value of s is ...

  s = (30 +30 +26)/2 = 43

  A = √(43(13)(13)(17)) = 13√(43·17)

  A = 13√731 ≈ 351.48 . . . . . square centimeters

_____

Additional comments

This triangle is isosceles, so the altitude can be found from the Pythagorean theorem:

  h² +13² = 30²

  h = √(900 -169) = √731

Then the area is ...

  A = (1/2)bh = (1/2)(26 cm)(√731 cm) = 13√731 cm²

__

You can also find one of the angles using the Law of Cosines, then find the area from ...

  Area = (1/2)a·b·sin(C) . . . . . . for any two sides a, b, and enclosed angle C

__

Ultimately, all of these methods are equivalent to Heron's formula.

The solution of the given system of equations is x = -4, y = 5 and z = 2 is the answer.

The system of equations given below:x + 2y + 3z = 11;2x + 4y + 5z = 21;3x + 5y + 6z = 27.

Here, we will solve this system of equations using inverse of the matrix method as follows:

We can write the given system of equations in matrix form as AX = B where, A = [1 2 3; 2 4 5; 3 5 6], X = [x; y; z] and B = [11; 21; 27].

The inverse of matrix A is given by the formula: A-1 = (1/ det(A)) [d11 d12 d13; d21 d22 d23; d31 d32 d33]  where,

d11 = A22A33 – A23A32 = (4 × 6) – (5 × 5) = -1,

d12 = -(A21A33 – A23A31) = -[ (2 × 6) – (5 × 3)] = 3,

d13 = A21A32 – A22A31 = (2 × 5) – (4 × 3) = -2,

d21 = -(A12A33 – A13A32) = -[(2 × 6) – (5 × 3)] = 3,

d22 = A11A33 – A13A31 = (1 × 6) – (3 × 3) = 0,

d23 = -(A11A32 – A12A31) = -[(1 × 5) – (2 × 3)] = 1,

d31 = A12A23 – A13A22 = (2 × 5) – (3 × 4) = -2,

d32 = -(A11A23 – A13A21) = -[(1 × 5) – (3 × 3)] = 4,

d33 = A11A22 – A12A21 = (1 × 4) – (2 × 2) = 0.

We have A-1 = (-1/1) [0 3 -2; 3 0 1; -2 1 0] = [0 -3 2; -3 0 -1; 2 -1 0]

Now, X = A-1 B = [0 -3 2; -3 0 -1; 2 -1 0] [11; 21; 27] = [-4; 5; 2]

Therefore, the solution of the given system of equations is x = -4, y = 5 and z = 2.

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