a lab uses negative numbers to describe a car moving backward on a road if the car was at -75.5 feet ,went forward 23 feet and then forward again 14.5 feet where is the car now

Answer:

2x^2- 3x - Y= -5 -x + Y = 5

there is no solve because it already is solved.

Step-by-step explanation:

Step-by-step explanation:

sorry if I don't get it right but I think it's no?

Answer:

 The answer is 8

Step-by-step explanation:

Hope it helps :)

Answer:B

Step-by-step explanation:

I TOOK THE UNIT TEST ON EDGE 2021 HAVVE A GOODDAY

For the first problem, there are no feasible solutions. In the second problem, the optimal solution is x₁ = 0, x₂ = 0, x₃ = -10, with the minimum value of Z = -30.


To demonstrate that the first problem has no feasible solutions using the Big M method and the simplex method, we will first convert the problem into standard form. The standard form of a linear programming problem involves converting all inequalities into equations and introducing slack, surplus, and artificial variables as needed.
1. Convert the inequalities to equations:
2x₁ + x₂ + s₁ = 2  (Constraint 1)
X₁ - x₂ - s₂ = 2    (Constraint 2)
X₁, x₂, s₁, s₂ ≥ 0
2. Introduce artificial variables and a big M:
Z = 90x₁ + 70x₂ - M(a₁ + a₂)  (Objective function)
2x₁ + x₂ + s₁ + a₁ = 2     (Constraint 1)
X₁ - x₂ - s₂ + a₂ = 2     (Constraint 2)
X₁, x₂, s₁, s₂, a₁, a₂ ≥ 0
3. Set up the initial simplex tableau:
       | 2x₁  |  x₂  | s₁ | s₂ | a₁ | a₂ | RHS |
Z       | -90  | -70  |  0 |  0 |  M |  M |  0  |
S₁      |   2  |   1  |  1 |  0 |  1 |  0 |  2  |
S₂      |   1  |  -1  |  0 | -1 |  0 |  1 |  2  |


4. Identify the pivot column (entering variable):
The most negative coefficient in the Z row is -90, so x₁ will enter the basis.
5. Identify the pivot row (leaving variable):
To determine the pivot row, calculate the ratio of the RHS to the positive coefficients in the entering column. Choose the smallest nonnegative ratio.
Ratios:
S₁: 2/2 = 1
S₂: 2/1 = 2
The smallest ratio is 1, so the pivot row is s₁.

6. Perform the pivot operation:
Divide the pivot row by the pivot element (1) to make the pivot element equal to 1:
       |  x₁  |   x₂   | s₁ |  s₂ |  a₁ |  a₂ | RHS |
Z       | -90  |  -70   |  0 |  0  |  M  |  M  |  0  |
X₁      |   1  |  0.5   |0.5 |  0  |0.5  |  0  |  1  |
S₂      |   1  |  -1    |  0 | -1  |  0  |  1  |  2  |

Perform row operations to make all other entries in the pivot column equal to zero:
       |  x₁  |   x₂   |  s₁ |  s₂ |  a₁ |  a₂ | RHS |
Z       |   0  |  15    | -90 |  0  | -45 |  90 | -90 |
X₁      |   1  |   0    |  1  |  0  |  1  |  0  |

 2  |
S₂      |   0  |  -2    | -1  | -1  | -0.5|  1  |  0  |

7. Check for optimality:
Since there are negative coefficients in the Z row, the current solution is not optimal. We need to continue iterating.
8. Repeat steps 4-7 until an optimal solution is reached:
The next pivot column is x₂ (coefficient: 15).
The next pivot row is s₂ (ratio: 0/(-2) = 0).
Perform the pivot operation:
       |  x₁  |  x₂  |  s₁ |  s₂ |  a₁ |  a₂ | RHS |
Z       |   0  |  0   | -90 |  15 | -75 |  75 | -180|
X₁      |   1  |  0   |  1  | -0.5| 0.5 | -0.5| 1   |
X₂      |   0  |  1   |  0  | -0.5| -0.5|  0.5| 0   |

The coefficients in the Z row are now nonnegative, but the artificial variables (a₁ and a₂) remain in the basis. This indicates that the original problem is infeasible since the optimal value of the objective function is negative.
Therefore, the first problem has no feasible solutions.

Now, let’s solve the second problem using the Big M method and the simplex method.
1. Convert the inequalities to equations:
-x₁ + x₂ + s₁ = 10    (Constraint 1)
2x₁ - x₂ + x₃ + s₂ = 10   (Constraint 2)
X₁, x₂, x₃, s₁, s₂ ≥ 0
2. Introduce artificial variables and a big M:
Z = 3x₁ + 2x₂ + 7x₃ + M(a₁ + a₂)   (Objective function)
-x₁ + x₂ + s₁ + a₁ = 10   (Constraint 1)
2x₁ - x₂ + x₃ + s₂ + a₂ = 10   (Constraint 2)
X₁, x₂, x₃, s₁, s₂, a₁, a₂ ≥ 0
3. Set up the initial simplex tableau:
       | -x₁ |  x₂  | x₃ | s₁ | s₂ | a₁ | a₂ | RHS |
Z       |  -3 |  -2  | -7 |  0 |  0 |  M |  M |  0   |
S₁      |  -1 |   1  |  0 |  1 |  0 |  1 |  0 |  10  |
S₂      |   2 |  -1  |  1 |  0 |  1 |  0 |  1 |  10  |

4. Identify the pivot column (entering variable):
The most negative coefficient in the Z row is -7, so x₃ will enter the basis.
5. Identify the pivot row (leaving variable):
Calculate the ratio of the RHS to the positive coefficients in the entering column. Choose the smallest nonnegative ratio.
Ratios:
S₁: 10
/1 = 10
S₂: 10/1 = 10
Both ratios are the same, so we can choose either. Let’s choose s₁ as the pivot row.
6. Perform the pivot operation:
Divide the pivot row by the pivot element (1) to make the pivot element equal to 1:
       | -x₁ |  x₂ |  x₃  | s₁ |  s₂ | a₁ | a₂ | RHS |
Z       |  -3 | -2  | -7   |  0 |  0  |  M |  M |  0   |
S₁      |  -1 |  1  |  0   |  1 |  0  |  1 |  0 |  10  |
S₂      |   2 | -1  |  1   |  0 |  1  |  0 |  1 |  10  |

Perform row operations to make all other entries in the pivot column equal to zero:
       | -x₁ |  x₂ |  x₃  |  s₁ |  s₂ | a₁ | a₂ | RHS |
Z       |   0 |  3  | -7   |   3 |  0  | -3 |  0 | -30  |
X₃      |   1 | -1  |  0   |  -1 |  0  | -1 |  0 | -10  |
S₂      |   0 | -3  |  1   |   2 |  1  |  2 |  1 |  30  |

7. Check for optimality:
Since there are no negative coefficients in the Z row, the current solution is optimal.
9. Read the solution:
The optimal solution is:
X₁ = 0
X₂ = 0
X₃ = -10
S₁ = 10
S₂ = 30
A₁ = 0
A₂ = 0
The minimum value of Z is -30.
Therefore, the second problem is feasible and has an optimal solution with x₁ = 0, x₂ = 0, x₃ = -10, and Z = -30.

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The largest interval I over which the solution is defined is (-∞, ∞).               I = (-∞, ∞)

To solve the given initial-value problem, we can use the method of separation of variables as follows:
1. Separate the variables by moving all terms with y to the left side of the equation and all terms with x to the right side:
y/y' = ex/x
2. Integrate both sides of the equation with respect to their respective variables:
∫y/y' dy = ∫ex/x d
ln(y) = ex + C
3. Solve for y:
y = e^(ex + C)
4. Use the initial condition y(1) = 9 to find the value of C:
9 = e^(e + C)
C = ln(9) - e
5. Substitute the value of C back into the equation for y:
y = e^(ex + ln(9) - e)
6. Simplify the equation:
y = 9e^(ex - e)
7. The largest interval I over which the solution is defined is (-∞, ∞), since there are no restrictions on the values of x or y therefore, the solution to the initial-value problem is y(x) = 9e^(ex - e) and the largest interval I over which the solution is defined is (-∞, ∞).

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Points are said to be collinear if they are on the same line. The possible lengths of CD are 31.6cm and 12.6cm

Given that:

\(CE=22.1cm\)

\(DE = 9.5cm\)

If E is between C and D, then:

\(CD =CE + DE\)

So, we have:

\(CD =22.1cm + 9.5cm\)

\(CD =31.6cm\)

Another possible scenario is:

If D is between C and E, then:

\(CE = CD + DE\)

Make CD the subject

\(CD = CE - DE\)

So, we have:

\(CD = 22.1cm -9.5cm\)

\(CD = 12.6cm\)

Hence, the possible values of CD are 31.6cm and 12.6cm

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Answer:

B

Step-by-step explanation:

each time the step changes, the amount of vertices(points) increases by 1. the last number of points was 4, so if you increase 4 by 1 you will get 5. figure B has 5 points!

Answer:

Option B

Step-by-step explanation:

With the circle series, there is a figure with an increasing number of points that are on the circle.

Circle one has two dots, circle two has three dots, circle three has four dots, etc.

It would make the most sense if the circle in the next series have five dots.

Option B should be the correct answer.  

All the right angles formed for the circle are: ∠CRI and ∠YRC are formed by the tangent and ∠LYR and ∠LVR are formed by the diameter of the circle.

A straight line one that touches the circumference of a circle once is said to be the tangent to that circle. This point in tangency or perhaps the point of contact is the location where the tangent contacts a circle.

A line is tangent to just a circle when and if only if it is perpendicular toward the radius defined to the point of tangency, according to the tangent theorem.

Thus, CRI and ∠YRC are formed by the tangent are 90 degrees.

The central angle's size is equal to twice the inscribed angle's size, according to the inscribed angle theorem, which is also known as such arrow theorem and the central angle theorem.

At any point on the circle, the diameter subtends a 90° angle.

Thus, ∠LYR and ∠LVR are formed by the diameter of the circle are 90 degress.

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Complete question -

For the given figure , determine all the right angles formed for the circle.

Answer:

I already sent u the link from there, even tho, they deleted my question, but yh i set the title as well incase u needed it! Good luck

Step-by-step explanation:

Answer:

If it says working for 23hrs then the answer is €204

Step-by-step explanation:

8×23=204

Answer:

Step-by-step explanation:

The two dots on the bottom of this figure define the base of a triangle.  If we now use a compass to draw the blue arcs on either side, as shown, the arcs will intersect at two points.  A straight line drawn through these two points will be perpendicular to the base. The triangle will be isosceles and could be (but doesn't have to be) equilateral.

Answer:

3y+3+2y+4=32

5y+7=32

5y=32-7

5y=25

y=5

To solve this problem, we can use the Poisson distribution formula.

The formula is P(X ≤ 10) = e^(-λ) ∑(k=0 to 10) (λ^k / k!) where λ is the average rate of customers per hour, which is 17.

Substituting the values,

we get P(X ≤ 10) = e^(-17) ∑(k=0 to 10) (17^k / k!)

Using a calculator, we get P(X ≤ 10) = 0.2588 or 25.88%. This means that during a given hour, the probability that 10 or fewer customers will arrive at the drive-thru is 25.88%.

It is important to note that the Poisson distribution assumes that the arrival rate is random and constant. In reality, there may be factors that affect the arrival rate, such as time of day, day of the week, and weather conditions. However, the Poisson distribution can still be a useful tool in predicting customer arrivals and managing staffing levels.

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Answer:

23.64

Step-by-step explanation:

\(\frac{6.6+3.2}{5}\) × (2 - 5)² + 6

= \(\frac{9.8}{5}\) × (- 3)² + 6

= 1.96 × 9 + 6

= 17.64 + 6

= 23.64

The value of the (6.6 + 3.2)/5*(2-5)²+6 is 23.64

An expression is a set of terms combined using the operations +, -, x or ÷, /

Given statement:

The sum of 6.6 and 3.2 all divided by 5 times the quantity of the squared difference of 2 minus 5 plus 6.

Now,

(6.6 + 3.2)/5*(2-5)²+6

=9.8/5*3²+6

=1.96*9+6

=17.64+6

=23.64

Hence, the value is 23.64.

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The solution of the inequality is, x ∈ (- ∞, 5) ∪ (10, ∞)

Where, x represent the number of totts.

A relation by which we can compare two or more mathematical expression is called an inequality.

We have to given that;

My friend Raw has either no more than 5 toots and more than 10 toots.

Now, Let number of toots = x

Hence, We get;

⇒ x < 5

And, x > 10

Thus, The solution of the inequality is,

⇒ x ∈ (- ∞, 5) ∪ (10, ∞)

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Answer:

3 and 4

36 and 48

Step-by-step explanation:

you got the 1 wrong

should be 5 and 4

20 and 16

Answer:

Part A: one solution:

Part B: x = 3, y = 4.

1) Part A: how many solutions does the pair of equations for lines A and B have?

The solution of a system of equations in a graph is given by the intersetion of the curves that represent the equations.

In this case, there are two straight lines, which intersect in one and only one point.

Hence, the system has one solution.

2) Part B: what is the solution to the equations of lines A and B?

The solution is the pair of coordinates of the intersection point. It is (3, 4).

Therefore, the solution is x = 3, y = 4.

Step-by-step explanation:

MRK ME BRAINLIEST PPLLZZZZZZZZZZZZZZZZZZZ

Answer:

Car 1

Step-by-step explanation:

Answer: Car 1

Step-by-step explanation:

Notice that the speed of each car is the slope of the line that represents its average speed.

Since the graph of the speed of Car 1 passes through (0,0) and (4,256), we get that its slope is:

256/4 = 64

Therefore the average speed of Car 1 is 64 mi/h.

 Now, since the equation that represents the average speed of Car 2 is in slope-intercept form, we get that its slope is 55.

Therefore the average speed of Car 2 is 55 mi/h.

Answer: Car 1.

Answer:

I am not sure

But I think it's 7

Answer:

2 millimeters.

Step-by-step explanation:

1 millimeter : 6 meters

x millimeters : 12 meters

x = (12÷6) × 1

x = 2×1

x = 2 millimeters

Given:

The set of ordered pairs is

{(0.5,2), (1.5,5), (4.0,12), (6.5,15)}

To find:

Which relation has the same domain as the given relation?

Solution:

We know that, domain is the set of input values or x-values.

For the given set {(0.5,2), (1.5,5), (4.0,12), (6.5,15)}, the domain is

Domain={0.5, 1.5, 4.0, 6.5}

Similarly,

For {(1,5),(2,2),(-3,15),(-8,12)},

Domain = {1, 2, -3,-8}

For {(0.5,1),(1.5,4),(4.0,11),(6.5,14)},

Domain={0.5, 1.5, 4.0, 6.5}

For {(2,1,1),(5,2.2),(12,3.3),(15,4.4)},

Domain = {2, 5, 12, 15}

For {(-1,6.5),(-3,1.5),(-6,4.0),(-10,0.5)}​,

Domain = {-1, -3, -6, -10}

So, the relation {(0.5,1),(1.5,4),(4.0,11),(6.5,14)} has the same domain as the given relation.

Therefore, the correct option is B.

Answer:

27

Step-by-step explanation:

f(x) = 5x - 8

f(7) = 5(7) - 8 = 27

Answer:

27

Step-by-step explanation:

f(x)=5x-8

Let x=7

f(7) = 5*7 -8

       =35-8

         27

The cost can be optimized by using a Linear Programming given the  linear constraint system

Reason:

Let X represent Type 1 bacteria, and let Y, represent Type II bacteria, we have;

The constraints are;

4·X + 3·Y ≥ 240

20 ≤ X ≤ 60

Y ≤ 70

P = 5·X + 7·Y

Solving the inequality gives;

4·X + 3·Y ≥ 240

The boundary of the feasible region are;

(20, 70)

(20, 53.\(\overline 3\))

(60, 0)

(60, 70)

The cost are ;

\(\begin{array}{|c|c|c|}X&Y&P= 5\times X + 7 \times Y\\20&70&590\\20&53.\overline 3&473.\overline 3\\60&0&300\\60&70&790\end{array}\right]\)

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Answer:

Step-by-step explanation:

a)  

4x - 3 = 2x + 7

4x - 2x = 7 + 3

2x = 10

x = 10 / 2

x = 5

b)

2x + 6 = 7x - 14

6 + 14 = 7x - 2x

20 = 5x

x = 20 / 5

x = 4