A ladder (ℓL = 7.80 m) of weight WL = 350 N leans against a smooth vertical wall. The term "smooth" means that the wall can exert only a normal force directed perpendicular to the wall and cannot exert a frictional force parallel to it. A firefighter, whose weight is 885 N, stands 6.40 m up from the bottom of the ladder (this distance goes along the ladder, it is not the vertical height). Assume that the ladder's weight acts at the ladder's center, and neglect the hose's weight. What is the minimum value for the coefficient of static friction between the ladder and the ground, so that the ladder (with the fireman on it) does not slip? (Assume = 54.0°.)

Answers

Answer 1

Answer: In order for the ladder (with the firefighter on it) to not slip against the ground, the friction between the ladder and the ground must provide enough horizontal force to prevent the ladder from sliding horizontally. The minimum value of the coefficient of static friction between the ladder and the ground can be calculated using the following steps:

Step 1: Identify the forces acting on the ladder.

The forces acting on the ladder are the weight of the ladder (WL) acting downward at the center of the ladder, the weight of the firefighter (Wf) acting downward at a distance of 6.40 m up from the bottom of the ladder, the normal force (N) exerted by the ground acting perpendicular to the ground, and the frictional force (f) acting horizontally in the direction opposite to the potential sliding motion of the ladder.

Step 2: Write down the equations for force equilibrium.

In the vertical direction, the sum of the vertical forces must be zero:

N + Wf - WL = 0

In the horizontal direction, the sum of the horizontal forces must be zero:

f = 0 (since there is no horizontal acceleration)

Step 3: Express the forces in terms of known quantities.

WL = 350 N (given)

Wf = 885 N (given)

The angle of inclination of the ladder with respect to the ground is given as 54.0°.

Step 4: Calculate the normal force N.

Using the vertical force equilibrium equation, we can solve for N:

N = WL - Wf = 350 N - 885 N = -535 N (negative sign indicates that N acts in the opposite direction of WL and Wf)

Step 5: Calculate the frictional force f.

Since the ladder is on the verge of slipping, the frictional force f will be at its maximum value, which is given by:

f = μN, where μ is the coefficient of static friction.

Step 6: Calculate the coefficient of static friction μ.

Using the calculated value of N, we can now calculate μ:

μ = f / N = (-535 N) / N = -535

Step 7: Determine the minimum value of μ.

The coefficient of static friction cannot be negative, as it is always non-negative in reality. Therefore, the minimum value of the coefficient of static friction between the ladder and the ground is 0, which means that the ladder must have sufficient friction with the ground to prevent slipping.

In conclusion, the minimum value for the coefficient of static friction between the ladder and the ground, so that the ladder (with the firefighter on it) does not slip, is 0.


Related Questions

El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una correcta asociación la cual sería * 3 puntos

Answers

La respuesta correcta para esta pregunta abierta es la siguiente.

No incluyes opciones, incisos, o alguna referencia específica para responder esta pregunta.

De ahí que responderemos en términos generales basándonos en nuestro conocimiento previo.

El concepto cosmológico abarca todo lo relativo a la cosmología y, al unir este término con la metafísica sería posible una correcta asociación la cual sería benéfica para ambos campos de conocimiento porque de esta manera se estarían complementando y enriqueciendo el uno al otro.

Cuando la ciencia -en este caso, la cosmología- acepte los conceptos metafísico que no tienen un sustento científico pero que sí contemplan alternativas en el mundo espiritual que son aceptadas por una innumerable cantidad de personas, entonces los expertos podrán plantear nuevas y diferentes posibilidades de entender los fenómenos que al día de hoy, carecen de una convincente explicación.

Tanto la cosmología como la metafísica podrían mostrarse más receptivos a las aportaciones de una y la otra, con objeto de poder aumentar las posibilidades de comprender un fenómeno. No necesariamente debe haber una teoría científica para poder avanzar en el conocimiento de algún tema. De ahí que las aportaciones metafísicas sean válidas como una alternativa de investigación.

A German scientist, George Ohm, discovered the relationship between current, voltage, and resistance. This became known as Ohm's law. According to Ohm’s law, if V is voltage, I is current, and R is resistance, their relationship is expressed by the equation

Answers

Answer:

I=V/R is the formula for ohm's law .

Explanation:  I=V/R is the formula for ohm's law

Answer:

I= V/R

Explanation:

The equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r. (Study.com)

(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00. (3 points)(b) A boat crossing a wide river moves with a speed of 10.0 km/h relative to water. The water in the river has a uniform speed of 5.0 km/h due east relative to the ground. If the boat heads due north, determine the magnitude the boat velocity relative to the ground. (2 points)

Answers

boat velocity relative to the ground is = 11.18 Km/h.

Full solution in pic.

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(a) A projectile's launch speed is five times its speed at maximum height. Find the launch angle 00.

imagine that a continuous random variable X defined on the range [0,1] follows the probability density function p(X=x∣a)={(a+1)xa0​ for x∈[0,1] everywhere else ​. where a>0 is a parameter that controls the shape of the distribution. Answer the following questions; you must include appropriate working. 1. Plot the probability density function of X when a=1/2 and a=2 for x∈[0,1]. 2. Determine the expected value of X, i.e., E[X]. 3. Determine the expected value of 1/X, i.e., E[1/X]. 4. Determine the variance of X, i.e., V[X]. 5. Determine the median of X. (hint: the answers to Q4.2 through Q4.5 will all be functions of a).

Answers

The probability density function of X is plotted for a=1/2 and a=2.

The expected value of X (E[X]) is determined.

The expected value of 1/X (E[1/X]) is determined.

The variance of X (V[X]) is determined.

The median of X is determined.

When a=1/2, the probability density function of X is given by p(X=x∣a)=((1/2)+1)x(1/2)^0=(3/2)x for x∈[0,1]. When a=2, the probability density function becomes p(X=x∣a)=(2+1)x^2=3x^2 for x∈[0,1]. To plot the probability density function, we can assign different values of x within the range [0,1], calculate the corresponding probabilities using the given formulas, and plot the points on a graph.

The expected value of X (E[X]) is calculated by integrating the product of X and its probability density function over the range [0,1]. For a=1/2, E[X] = ∫(x * (3/2)x) dx from 0 to 1. For a=2, E[X] = ∫(x * 3x^2) dx from 0 to 1. By evaluating these integrals, we can determine the expected values.

The expected value of 1/X (E[1/X]) is calculated similarly to E[X], but instead of integrating X, we integrate 1/X using the respective probability density functions for different values of a.

The variance of X (V[X]) can be computed by taking the second moment of X (E[X^2]) minus the square of the first moment (E[X]) squared. V[X] = E[X^2] - (E[X])^2. By calculating E[X^2] using the probability density function and the expected values obtained in step 2, we can determine the variances for different values of a.

The median of X is the value of X such that the cumulative distribution function (CDF) is equal to 0.5. To find the median, we integrate the probability density function from 0 to the median value and set it equal to 0.5. Solving for the median provides its value in terms of the parameter a.

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Materials A, B, and C are solids that are at their melting temperatures. Material A requires 200 J to melt 4 kg, material B requires 300 J to melt 5 kg, and material C requires 300 J to melt 6 kg. Rank the materials according to their heats of fusion. If multiple materials rank equally, use the same rank for each, then exclude the intermediate ranking (i.e. if objects A, B, and C must be ranked, and A and B must both be ranked first, the ranking would be A:Greatest, B:Greatest, C:Third greatest). If all materials rank equally, rank each as 'Greatest'.

Answers

Answer:

B: Greatest, A: Second greatest, C: Second geratest.

Explanation:

We can calculate the heat of fusion of a material (ΔHfus), which is the heat required to melt 1 kg of material, using the following expression.

ΔHfus = Q/m

where,

Q: heat providedm: mass

Material A

ΔHfus = 200 J/4 kg = 50 J/kg

Material B

ΔHfus = 300 J/5 kg = 60 J/kg

Material C

ΔHfus = 300 J/6 kg = 50 J/kg

Then, considering the heats of fusion,

B: Greatest, A: Second greatest, C: Second greatest.

Vanessa jogged 8 miles in 2 hours. What was her average speed?

Answers

Answer:

4 mph

Explanation:

This is because, if you divide the miles jogged by the hours you get 4.

Answer:

4 mph

Explanation:

Use the formula for average speed: \(Speed = \frac{Distance}{Time}\)

The distance that Vanessa traveled is 8 miles and the time she traveled was 2 hours. Therefore, put those numbers in their corresponding spots in the formula and solve for Speed by dividing 8 and 2: \(Speed = \frac{8}{2}\)

Vector C has length 10cm and makes an angle of 120 degrees counter-clockwise from the negative x-axis

What quadrant does vector C lie in?

Answers

Quadrant 1

Refer to the attachment

Vector C has length 10cm and makes an angle of 120 degrees counter-clockwise from the negative x-axisWhat

Here we have tapering (old fashioned) car antenna made of steel (e= 2 1011[nm2]).measuringxas the distance from the attachment point on the car:

Answers

The capacitance of the antenna is 1.38 × 10⁻¹⁰ farads.

Here we have a tapering (old fashioned) car antenna made of steel (e = 2 × 10¹¹ [nm²]), measuring x as the distance from the attachment point on the car:

Radius = 10 mm at x = 0 mm

Radius = 5 mm at x = 100 mm

We can calculate the capacitance of the antenna using the following formula:

C = 2 × pi × e × ln (r₁ / r₂)

Where:

C is the capacitance in farads

e is the permittivity of the material in farads per meter

ln is the natural logarithm

r1 is the radius of the antenna at x = 0 mm in meters

r2 is the radius of the antenna at x = 100 mm in meters

Plugging in the values:

C = 2 × pi × 2 × 10¹¹ × ln (10 / 5)

C = 1.38 × 10⁻¹⁰ farads

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A convex spherical mirror has a focal length of magnitude 6.90 cm.
(a) What is the location of an object for which the magnitude of the image distance is one-ninth the magnitude of the object distance? (units in cm)
(b) Find the magnification of the image.
(c) State whether it is upright or inverted.

Answers

(a) The object is located at a distance of 69 cm from the convex spherical mirror.

(b) The magnification of the image is -1.

(c) The image formed by the convex spherical mirror is inverted.

(a) Let's assume the object distance is denoted by "do" and the image distance is denoted by "di".

Given that the magnitude of the image distance is one-ninth the magnitude of the object distance, we have:

di = (1/9) * do

Since the mirror is convex, the focal length is positive, and we can use the mirror equation:

1/f = 1/di + 1/do

Substituting the given relationship between the magnitudes of the object and image distances, we have:

1/6.90 cm = 1/(1/9 * do) + 1/do

Simplifying, we get:

1/6.90 cm = 9/do + 1/do

Combining the fractions, we have:

1/6.90 cm = (9 + 1)/do

Simplifying further, we get:

1/6.90 cm = 10/do

Cross-multiplying, we have:

do = 6.90 cm * 10

do = 69 cm

Therefore, the object is located at a distance of 69 cm from the convex spherical mirror.

(b) The magnification (m) of the image can be calculated using the formula:

m = -di/do

Substituting the given values, we have:

m = -|do| / |do|

m = -1

The negative sign indicates that the image formed by the convex spherical mirror is inverted.

(c) The image formed by the convex spherical mirror is inverted.

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What energy transformation takes place when you push a pencil off your desk? A. Mechanical energy transforms into kinetic energy. B. Potential energy transforms into nuclear energy. C. Potential energy transforms into kinetic energy. D. Kinetic energy transforms into potential energy.​

Answers

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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what safety measures would you suggest to protect from harmful waves​

Answers

Answer:

If you're talking about the sun than:

Time, Distance and Shielding Time, distance, and shielding actions minimize your exposure to radiation in much the same way as they would to protect you against overexposure to the sun:

If you're talking about the ocean than:

Water safety precautions for teens and young adults:

Never go into the water if you can’t swim.

If you can’t swim, learn. Any age can receive swimming lessons.

Always wear a life jacket while boating or taking part in boating activities such as tubing or skiing.

Never swim alone or in an unsupervised area.

Know your swimming strength.

Don’t rough house around water. Never push, jump on or hang on to others in or around water.

Never drink alcohol while taking part in water or boating activities. Alcohol affects your motor skills therefore making it harder to swim, float, keep balance or drive.

Explanation:

A 0. 45 kg soccer ball changes its velocity by 20. 0 m/s due to a force applied to it in 0. 10 seconds. What force was necessary for this change in velocity? N.

Answers

Hi there!

We can begin by calculating the impulse exerted on the soccer ball:

I = Δp = mΔv

Plug in the given values:

I = 0.45 × 20 = 9 Ns

I = Ft, so:

I/t = F

9/0.1 = 90 N

state the factors that affect tha gravitational force​

Answers

Explanation:

1. Mass of an object

2. Distance between the objects

Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Explanation:

PLEASE let me know you are satisfied with my answer or not

A person first displaces 10 units towards North. After second displacement he is 7 units towards North. His 2nd displacement was: A. 3 units towards West ⃝ B. 3 units towards South C. 3 units towards North ⃝ D. 3 units towards East

Answers

D. 3 units towards East

Initially, the person displaces 10 units towards the North. This means that their starting point is 10 units North of their reference point. After the second displacement, the person is 7 units towards the North. This means that their final position is 7 units North of their reference point.

If the person moved 3 units towards the East, their final position would be 10 units North and 3 units East of their reference point, which is consistent with the given information.

Therefore, the correct answer is D. 3 units towards East.

A machine launches a tennis ball at an angle of 45° with the horizontal, as
shown. The ball has an initial vertical velocity of 9.0 meters per second and an initial
horizontal velocity of 9.0 meters per second. The ball reaches its maximum height
0.p2 second after its launch. [Neglect air resistance and assume the ball lands at the
same height above the ground from which it was launched.]
Elapsed Time
+0.92 s
Viy = 9.0 m/s
Launcher
V = 9.0 m/s
45
Horizontal
The total horizontal distance traveled by the tennis ball during the entire time it is in the air is

Answers

The motion or path of the tennis ball is the path of a projectile, which has

both vertical and horizontal motion.

The total horizontal distance traveled by the tennis ball during the entire

time it is in the air ≈ 16.514 meters.

Reasons:

The given parameters are;

The direction in which the ball is launched = 45°

The initial vertical velocity of the ball, \(v_y\) = 9.0 m/s

The initial horizontal velocity of the ball, vₓ = 9.0 m/s

The time it takes the ball to reach the maximum height, t = 0.92 seconds after its launch

The total horizontal distance traveled, by the tennis ball is given by the formula;

\(\Delta d_x = \dfrac{v_1^2 \cdot \left( 2 \cdot cos(\theta) \sin(\theta)}{y} = \dfrac{2 \times v_x \times v_y}{g}\)

Which gives;

\(\mathrm{The \ total \ distance \ travelled, \ \Delta} d_x = \dfrac{2 \times 9.0\times 9.0}{9.81} \approx 16.514\)

The total horizontal distance traveled by the tennis ≈ 16.514 meters

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what kind of image is formed by the lenses of the glasses worn by a 68-year-old male who sees an object 2 m away?

Answers

Answer:

virtual and reduced  -lenses in table = negative focal length = diverging lenses.  *Diverging lens= virtual and reduced images

Source:

C/P AAMC MCAT #2 - Quizlet

A wave is moving at the rate of 40 cm/s. Its wavelength is 5 cm. What is the frequency of the wave? INCLUDE THE CORRECT UNIT!

Answers

Answer:

Solution given:

velocity=40cm/s

wave length=5cm

we have

frequency =velocity/wavelength=40/5=8hertz.

the frequency of the wave is 8 hertz.

Who would most likely be required to work with sodium hydroxide?

Answers

Answer:

a plumber

Explanation:

what are the 4 stages of planetary development for a terrestrial planet like earth?

Answers

The four stages of planetary development for a terrestrial planet like Earth are 1. accretion, 2. differentiation, 3. cratering, 4. tectonics.

The four stages of development of terrestrial planet are explained below:

1. Accretion: The gravitational attraction between tiny particles in the solar nebulae allowed them to clump together, creating planetesimals that collided and combined to create planets.

2. Differentiation: During this stage, denser materials such as iron sank to the center of the planet to form the core, while lighter materials such as silicates rose to the surface to create the crust.

3. Cratering: During this stage, the planet was heavily bombarded by comets and asteroids, causing craters and other impact features to form. This stage lasted for about the first billion years of Earth's existence.

4. Tectonics: Plate tectonics emerged during this phase, which is marked by volcanism, mountain formation, and the movement of continents.

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The isotope 56
26Fe
decays into the isotope
56
27 Co.
By what process will this decay occur?
1. +
2. None of these
3. 4. ?
5.

Answers

The correct option is 4.

The process by which the isotope 56Fe decays into the isotope 56Co is beta decay.

The correct option is 4.What is beta decay? Beta decay is a type of radioactive decay in which a beta particle, a positron, or an electron is emitted by the nucleus of an atom. Beta decay is a decay process in which the atomic nucleus emits beta particles, which are high-energy, high-speed electrons or positrons.

In beta decay, a neutron in the nucleus transforms into a proton, causing the emission of an electron and a neutrino in the process. The isotope 56Fe decays into the isotope 56Co by the following beta decay process:56Fe26 → 56Co27 + β−where β- is a beta particle, and it is emitted from the nucleus, resulting in an increase in atomic number Z by one, while atomic mass number A remains unchanged. The daughter isotope is 56Co.

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Part I Ia. State the formula which relates the index of refraction n to φ and φ ′ . Compute n. IIb. You already have a good idea of the absolute error in the angles you measured as recorded in your data sheet, but we are interested in the absolute (and \%) error in the value of the index of refraction you measure. Derive a formula, starting from Snell's law, which gives the uncertainty in n (call it δn ) in terms of φ,φ ,δφ, and δφ ′'See me for help; you need to use partial derivatives and use radians for δφ and δφ ′ . Using your data, compute δn. In one line, state n,δn and the % uncertainty. Part II Ila. For the data you took, does d far =d near within your measurement uncertainties? If not, give ​

Answers

The formula that relates the index of refraction (n) to the angles φ and φ' is Snell's Law n = sin(φ) / sin(φ').  

The formula that relates the index of refraction (n) to the angles φ and φ' is Snell's Law, which is written as:

n = sin(φ) / sin(φ')

To compute n, you need to measure or know the values of φ and φ' and then apply the formula.

To find the uncertainty in the index of refraction (δn) using Snell's Law, you can apply the partial derivatives method.

First, rewrite Snell's Law as:
n - sin(φ) / sin(φ') = 0Differentiate the equation partially with respect to φ and φ' to find δn:
δn = (cos(φ) / sin(φ'))δφ - (sin(φ) * cos(φ') / sin^2(φ'))δφ'Input the values for φ, φ', δφ, and δφ' and compute δn.Finally, calculate the percentage uncertainty using the formula:
Percentage Uncertainty = (δn / n) * 100%

In summary, state n, δn, and the percentage uncertainty in one line as requested.

To determine if d_far is equal to d_near within your measurement uncertainties, compare the values with their associated uncertainties. If the difference between d_far and d_near is within the range of the combined uncertainties, then they can be considered equal within the measurement uncertainties. If not, they are not equal within the given uncertainties.

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a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball​

Answers

Answer:

please find the attached pdf

Explanation:

a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball

(9\%) Problem 1: A disk of massMand radiusR, a hoop of mass2Mand radiusR, and a ball of massMand radius2Rare rolling without slipping. The hoop can be treated as a thin ring and the ball should be modeled as a hollow sphere.25%Part (a) The objects are rolling on a flat surface with the same linear speed. Which have the same angular speed? Choose the best answer. Disk and Hoop✓Correct!25%Part (b) The objects are rolling on a flat surface with the same angular speed. Which have the same linear speed? Choose the best answer. Disk and Hoop✓Correct!25%Part (c) Which of the objects has the smallest moment of inertia? Choose the best answer. Disk 、 Correct!▹25%Part (d) The objects are placed at the top of an incline and released from rest. Assuming that the objects roll without slipping, which one is first reach the bottom of the incline? Choose the best answer. \begin{tabular}{llll} \hline Hints: & deduction per hint. Hints remaining: 2 & Feedback: & deduction per feedback. \end{tabular}

Answers

Beforehand to hit the bottom will be the disk. The measure of matter contained inside a molecule or item is indicated by its mass, which is represented either by symbol m.

There in International System (SI), the kilogram serves as the default unit of mass (kg). The item moving with the greatest acceleration would descend first. Currently, the formula for any object's acceleration while simply rolling down a slope is

\(a = \frac{gsin(theta)}{1 +\frac{1}{MR_{2} } }\)

where is the inclined plane's angle and g is the gravitational acceleration. The body's radius, mass, and inertia time are all represented by the letters M and R, respectively.

speed of a disk is calculated.

Given

1) Mass \(= M\)

2) Radius \(= R\)

3) \(I = \frac{1}{2}MR_{2}\) ⇒ \(\frac{1}{MR_{2} } = \frac{1}{2}\)

Hence, disk acceleration \(a^{d}\)

\(a = \frac{gsin(theta)}{1 + 0.5}\)

\(a = \frac{2}{3} gsin (theta)\)

Hoop acceleration calculations

Given:

1) Mass \(= 2M\)

2) Radius \(= R\)

3) \(I = 2MR_{2}\) ⇒ \(\frac{1}{2MR_{2} }\) \(= 1\)

acceleration \(ah\)

\(ah = \frac{gsin(theta)}{1 + 1}\)

\(ah = \frac{1}{2} gsin (theta)\)

Estimating the ball's acceleration

Given :

1) Mass = \(=M\)

2) Radius \(= 2R\)

3) \(I = \frac{2}{3} M(2R)_{2}\) ⇒ M \(\frac{1}{M (2R)2} = \frac{2}{3}\)

acceleration \(ab\)

\(ab = \frac{gsin(theta)}{1 + \frac{2}{3} }\)

\(ab = \frac{3}{5} gsin (theta)\)

By comparing, we obtain \(ad\) ≥ \(ab\) ≥ \(ah\)  therefore disk would reach the bottom initially.

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as shown, wind is blowing on a 55-gallon drum. estimate the wind speed needed to tip the drum over. work in si units. the mass of the drum is 48 lbm, the diameter is 22.5 in., and the height is 34.5 in.

Answers

Approximately 30 m/s (67 mph) wind speed is needed to tip over the 55-gallon drum.

The critical wind speed needed to tip over the drum can be estimated using the formula:

\(V = (5/2*(h/d)*(W/m))^(1/2)\)

where V is the critical wind speed, h is the height of the drum, d is the diameter of the drum, W is the weight of the drum, and m is the mass of the drum.

Converting the given values to SI units, we get:

\(h = 0.8763 md = 0.5715 mW = 214.5 Nm = 21.77 kg\)

Substituting these values in the formula, we get:

\(V = (5/2*(0.8763/0.5715)*(214.5/21.77))^(1/2) ≈ 30 m/s\)

Therefore, approximately 30 m/s (67 mph) wind speed is needed to tip over the 55-gallon drum.

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Projectile Motion: A ball is thrown horizontally from the edge of a 122.5 m cliff. Its initial horizontal velocity is 49 m/s. a. Find the x and y component of the velocity 2 s later. Also find the magnitude and direction of the velocity at that instant. b. How long is the ball in the air? 7. Addition of Velocities: A blimp cruising with a constant air speed of 150 km/h heads due north against a steady 75 km/h wind blowing toward southeast (or 45 degrees below the positive x-axis). a. Compute its ground speed (resultant) and its actual direction of travel. The resultant vector is shown by R. b. The distance traveled in after 3.25 hours of cruising.

Answers

the distance traveled is 545.89 km.

a) Horizontal velocity component = 49 m/s (unchanged)
Vertical velocity component at time t = 2s can be calculated as follows: From the given information, initial vertical velocity, u = 0 (since the ball is thrown horizontally)

Acceleration due to gravity, a = 9.8 m/s^2Time, t = 2sUsing the equation, s = ut + 0.5at^2, where s = vertical displacement

By substituting the given values, we can find the vertical velocity component, v = u + at, v = 0 + 9.8 × 2v = 19.6 m/s. Velocity at that instant can be found using the Pythagorean theorem:

v² = horizontal velocity component² + vertical velocity component²v² = 49² + 19.6²v² = 2539.16 magnitute of velocity = √2539.16. magnitute of velocity = 50.39 m/s.

The angle the velocity makes with the horizontal can be found using the inverse tangent function:θ = tan-1(vertical velocity component/horizontal velocity component)θ = tan-1(19.6/49)θ = 22.9° above the horizontal, or 67.1° below the horizontal.

b) We can use the formula, t = 2u/a to find the time the ball is in the air. Using the given values, t = 2u/a = 2 × 49/9.8 = 10 s. Hence, the ball is in the air for 10 s.7.

a) The ground speed of the blimp is given by the magnitude of the resultant vector R, which is given by the Pythagorean theorem:R² = (air speed)² + (wind speed)²R² = 150² + 75²R² = 22,500 + 5625R² = 28,125R = √28,125R = 167.83 km/h.

The direction of the velocity can be found using the inverse tangent function:

θ = tan-1(opposite/adjacent)θ = tan-1(75/150)θ = 26.6° north of east

b) We can use the formula, distance = speed × time, to find the distance traveled in 3.25 hours. distance = speed × time = 167.83 × 3.25distance = 545.89 km.

Hence, the distance traveled is 545.89 km.

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Explain why water droplets on polar surfaces have a low contact angle, and why water droplets on nonpolar surfaces have a high contact angle. (b) Keeping the surfaces the same, what would happen if oil was dispersed on the surfaces? Explain.

Answers

Water droplets on polar surfaces have a low contact angle, while water droplets on nonpolar surfaces have a high contact angle.

Water molecules are polar, with a positive and a negative end, and exhibit strong intermolecular forces. Polar surfaces, such as glass or hydrophilic materials, have regions of partial positive and negative charges, allowing water molecules to form hydrogen bonds and electrostatic interactions. This strong attraction between water and polar surfaces results in the spreading of water droplets, leading to a low contact angle.

On the other hand, nonpolar surfaces lack significant positive or negative charges and do not strongly interact with water molecules. The cohesive forces between water molecules are stronger than the adhesive forces between water and nonpolar surfaces. As a result, water droplets on nonpolar surfaces tend to minimize contact and form compact spherical shapes, resulting in a high contact angle.

In summary, the contact angle is determined by the balance between cohesive forces within the liquid and adhesive forces between the liquid and the surface. Polar surfaces promote strong adhesion and low contact angles, while nonpolar surfaces exhibit weak adhesion, resulting in high contact angles.

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Is it possible for an object to change its weight without changing its mass? Explain why or why not

Answers

Answer:

yes

Explanation:

weight depends on the strength of gravity, so on a different planet, or on the moon for example, things would have a different weight but have the same mass.

Please answer fast

A 50 kg boy jumps off the front of a 1.5 kg skateboard moving forward. Find the skateboard's velocity
immediately after the boy jumps, assuming that the skateboard's initial velocity is 3.5 m/s and the boy's
velocity when jumping off the front is 5 m/s?

Answers

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Answer:

The speed is 1.35 m/s

Explanation:

(m1+m2) vi= m1+m2v2

(50+1.5) (3.5)=50 (5+v2) +1.5 v2

180.25= 250+ 51.5 v2

180.25- 250+ 51.5 v2

-69.75= 51.5 v2

v2= -1.35 m

what are two factor that effect the force of gravitation​

Answers

mass and distance


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Johnny Hotfoot slams on the brakes of his car mov- ing at 60 mph (26.7 m/s) and skids to a stop in 4 s. (a) What is the deceleration of the car? (b) How far does it skid?

Answers

At 60 mph (26.7 m/s), Johnny Hotfoot slams on the brakes of his car and skids to a stop in 4 s. (A) How fast is the car slowing down? (b) The extent of the skid.

If the car had been traveling at 40.0 m/s, it would have slid 27.2 m.

The frictional force opposes the linear force pulling on the automobile. Consequently, m is the vehicle's mass, an is its acceleration, and c is its coefficient of friction.

The normal force is R.

given the aforementioned variables

Find the length of the skid if the vehicle had been traveling at 40.0 m/s.

The car would have skidded 27.2 meters if it had been driving at 40.0 meters per second.

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