A lightbulb is rated at
20 W
when connected to 120 V.
(a) What current flows through the bulb in this case?



(b) What is the bulb's resistance?



(c) What would be the current in the bulb if it were connected to
28 V,
assuming the resistance stays the same?



(d) What would be its power consumption in this case?

The mass flow rate of the pump is 2.8 kg/s.

Given the density of the oil (kerosene) to be ρ= 0.75 kg/L

The volume of oil is equal to 10,000 L1 L = 0.001 m³Volume of oil = 10,000 × 0.001 = 10 m³Density of oil = mass/volume ⇒ mass = density × volume

Let m be the mass of oil.

m = ρV = 0.75 × 10 = 7.5 kg

The time taken to empty the tank is 45 minutes. 1 minute = 60 seconds

The time taken is t = 45 × 60 = 2,700 seconds.

Let the mass flow rate be m′. The mass flow rate is defined as the mass of fluid flowing per unit time.m′ = m/t = 7.5/2,700 kg/s= 0.00278 kg/s

Therefore, the mass flow rate of the pump is 2.8 kg/s.

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For a series circuit, as lights are added, the current across each bulb decreases.  

Answer:

B. She could have a higher risk of skeletal fractures

Explanation:

She needs to maintain her bone health and B is the only answer that involves a consequence with bones.

I hope this helps

The length of the spring when stretched by 100 N assuming that the elastic limit is not reached is 30 cm (option A)

First, we shall obtain the spring constant of the spring. This is show below:

F = Ke

50 = K × 5

Divide both sides by 5

K  = 50 / 5

K = 10 N/cm

Next, we shall determine the extension when a 100 N is applied. This is shown below:

F = Ke

100 = 10 × e

Divide both sides by 10

e = 100 / 10

e = 10 cm

Finally, we shall determine the length of the spring. Details below:

Length of spring = original + extension

Length of spring = 20 + 10

Length of spring = 30 cm (option A)

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Option A and B are correct.

We have a spinning satellite which begins to unfold two solar panels as shown in the figure.

We have to investigate which of the given statements are true.

The relation the linear velocity (v) and angular velocity (ω) of a body undergoing circular motion in the circle of radius r is -

v = rω

According to the question - two solar panels unfolded themselves. The key point to understand here is that initially when the panels were folded, each and every individual particle inside the panel were closer to the rotational axis. However, when they unfolded, each and every particle inside the panels went away from the rotational axis. In a general sense, for a individual particle inside the panel, assume that initially the its distance from center was 'r' and after unfolding it became 'R' such that R > r. Therefore, using the formula -

v = rω

ω = \(\frac{v}{r}\)

Now, ω \(\alpha\) \(\frac{1}{r}\) ,

As r increased to R, the angular velocity decreases.

Now, we know that the angular momentum (L) is given by -

L = mvr

As r increases, L increases.

Therefore, the angular momentum increases.

Hence, Option A and B are correct.

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A carbon-detonation supernova, also known as a Type I supernova, shows little or no hydrogen in its spectrum because this type of supernova occurs in a white dwarf star that has exhausted its nuclear fuel, including hydrogen before the explosion takes place.

The lack of hydrogen in the spectrum of a carbon-detonation supernova (Type I) can be attributed to the nature of the explosion itself. Type I supernovae occur in binary star systems where a white dwarf accumulates matter from a companion star. In the case of a carbon-detonation supernova, the white dwarf reaches a critical mass, triggering a runaway nuclear fusion reaction.

However, this fusion process primarily involves carbon and oxygen, not hydrogen. The high temperatures and pressures achieved during the explosion cause the carbon and oxygen to undergo rapid nuclear burning, producing heavy elements and releasing a tremendous amount of energy. Consequently, the spectrum of a carbon-detonation supernova shows little or no hydrogen because hydrogen is not a significant part of the fusion process leading to the explosion.

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Answer:

F = -8820 N

Explanation:

Given that,

The weight of a car, W = 19600 N

Initial speed of the car, u = 30 m/s

It is brought to rest, final velocity, v = 0

Distance, d = 100 m

We need to find the average friction force acting on it.

Firstly we find the acceleration of the car using third equation of motion. Let it is a.

\(v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2\)

Average frictional force,

F = ma

m is mass, \(m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg\)

F = 1960 kg × -4.5 m/s²

= -8820 N

So, the average friction force acting on it is 8820 N.

Answer:Deforestation refers to the decrease in forest areas across the world that are lost for other uses such as agricultural croplands, urbanization, or mining activities. Greatly accelerated by human activities since 1960, deforestation has been negatively affecting natural ecosystems, biodiversity, and the climate. The UN’s Food and Agriculture Organization estimates the annual rate of deforestation to be around 1.3 million km2 per decade.

Explanation:

The negative effect of deforestation on the environment is desertification. The correct option is B.

Desertification is the process by which fertile land becomes desert, typically as a result of drought, deforestation, and inappropriate agriculture or land use practices. It occurs when land that was once able to support vegetation and life becomes increasingly dry, barren, and unable to sustain crops, livestock, or human populations. This can be due to natural causes such as prolonged droughts, but it is often exacerbated by human activities such as deforestation, overgrazing, and soil degradation. Desertification can have devastating effects on the environment, leading to soil erosion, loss of biodiversity, and reduced productivity of the land. It can also cause social and economic problems, such as displacement of people, food shortages, and conflicts over resources.

Here in the question,

Deforestation is the clearing of trees and other vegetation from an area, leading to the loss of habitat and biodiversity, and disruption of water cycles. It can also cause soil erosion, which can result in the depletion of soil nutrients, reduced productivity, and eventually lead to desertification. Additionally, deforestation contributes to climate change by releasing carbon dioxide into the atmosphere, which can cause global warming and other environmental problems. Habitat restoration, soil production, and urbanization are not negative effects of deforestation but can be impacted by it.

Therefore, The correct answer is B i. e Desertification.

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Answer:

I believe it's a compound.

Hello there,

Compound is the answer.

A substance made up of two or more elements that have been chemically combined is called a compound.

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The rabbit's average speed is 15m/s because the formula for calculating average speed is Distance divided by time.

What is the average speed?

The average speed of an object can be defined as the total distance traveled by it in a particular interval of time. this can be determined by dividing the total distance moved by the object by the time taken to move.

It is the ratio of the distance the rabbit travels in m and the time taken by the object to travel in seconds.

Hence: Distance D=30m

                Time,  T=2s

Average Speed S=ΔD/ΔT                            

                      S=30m/2s                            

                      S=15m/s

Therefore rabbit's Average speed is 15m/s

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Answer:

\(V_{2.2} =2.2V\)

Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is \(R_i \over {\sum R}\) of the drop across the whole series. In our situation, it's \(2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3\) of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V

With Ohm's Law

The series is equivalent of a single resistor of Resistance \(2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega\). By Ohm's first Law (\(V=Ri\)) the current flowing through the resistor is \(9V = 9*10^3\Omega i \rightarrow i=1mA\). At this point, the drop across the first resistor is, again by Ohm's law\(V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V\)

Answer:

49kmph

Explanation:

speed=distance/time = 245/5

The electrical potential difference between the plates is 40 V.

The magnitude of the electric field at point p = 5.0 × 104 N/C

Distance between the plates = 0.80 mm = 0.80 × 10-3 m

The formula used to find the electrical potential difference between the plates is,

V = Ed

Where,

V = electrical potential difference between the plates

E = electric field strength

d = distance between the plates.

Substituting the given values in the formula,

V = Ed= 5.0 × 104 N/C × 0.80 × 10-3 m= 40 V

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The amount of helium atoms lined up side to side that  would span the diameter of a human hair is: 1.5625*10^6  atoms

To solve this problem the we have to do the conversion of units with the given information.

Information about the problem:

By converting the units of the helium atom's diameter from nm to mm, we have:

d(helium atom)= 0.064 nm * 1 m/1*10^6 mm

d(helium atom)=  6.4*10^-8 mm

To know how many helium atoms lined up side to side would span the diameter of a human hair, we have to do a division as a following:

amount of helium atoms lined up side to side= d(human hair)/d(helium atom)

amount of helium atoms lined up side to side= 0.1 mm/6.4*10^-8 mm

amount of helium atoms lined up side to side= 0.1 mm/6.4*10^-8 mm

amount of helium atoms lined up side to side= 1.5625*10^6

It is the transformation of a value expressed in one unit of measurement into an equivalent value expressed in another unit of measurement of the same nature.

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The statement that is true is that in turbulent flow, streamlines can begin or end at any point: streamlines are perpendicular to the velocity of the fluid at every point.

At any given point of time, when the flow of water is constant with respect of time then it is called streamline flow. Streamline flow occurs when there are sharp edge obstacles in the path of a fast-moving fluid. Streamline flow is explained by Pascal's principle. In steady flow, the liquid velocity at any particular point is the same. In steady flow of water, we can consider that the two layers of water cannot meet or merge with each other and it will flow continuously without any interruption. The high viscosity index number  of any fluid describes many things about that fluid like high viscosity number describes about the rigidity of that fluid with respect to the flowing area. Streamline flow of any fluid means its smooth flow after passing through a cut edge without disturbing its path.

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Answer:

a coil rotating in a magnetic field to change its flux

TRUE

THAT WORD IS THE KEY WORD.

Work = 540 joules is the amount of work that was done on the item by this force.

The amount of work a force can produce relies on the force, the body's displacement, and the angle between the two. When displacement is in the force's direction, the most work is produced.

Newton's second law provides a precise explanation of the modifications that a force can make to a body's motion. According to this, a body's momentum changes at a rate that is equal to the force acting on it over time in both magnitude and direction.

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Answer:

6.72 m/s

Explanation:

recall that the equations of motion may be expressed as

v² = u² + 2as

where,

v = final velocity,

u = initial velocity = 0 m/s because it is stationary before it starts falling

a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)

s = distance traveled = 2.3m

in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.

v² = u² + 2as

v² = 0² + 2(9.81)(2.3)

v² = 45.126

v = √45.126

v = 6.72 m/s

If a 155 N brick is added to the block, the graph would still show an initial increase in friction force, but with higher coefficients of friction due to the increased weight.

When a 155 N brick is placed on the block, the total weight resting on the table increases to 131 N (original block weight) + 155 N (brick weight) = 286 N. The friction force between the block and the table depends on the coefficient of friction (μ) and the normal force (N), which is the weight of the object pressing against the surface.

As the pull on the block increases, the graph would initially show a linear increase in the friction force until it reaches a maximum value, indicating the block is on the verge of moving. This maximum value would correspond to the maximum static friction. Once the block starts moving, the graph would show a constant friction force (kinetic friction) that is typically lower than the maximum static friction.

The coefficient of friction can be calculated by dividing the friction force by the normal force. In this case, the coefficient of friction would change due to the increased normal force of 286 N. The specific coefficient values would depend on the nature of the surfaces in contact (roughness, materials), and the graph would reflect the new relationship between the friction force and the pull, but with higher values due to the increased weight.

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(a) The required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) The required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) The average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant acceleration, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) The total length of the track is approximately 5.28 kilometers.

(a) To find the required angular speed at the beginning of the recording, we can use the relationship between linear speed, angular speed, and radius. The linear speed is given as 1.30 m/s, and the radius is 2.30 cm (or 0.023 m). The formula to relate these quantities is:

Linear Speed = Angular Speed * Radius

Solving for angular speed:

Angular Speed = Linear Speed / Radius

Plugging in the given values:

Angular Speed = 1.30 m/s / 0.023 m

Angular Speed ≈ 56.52 radians/second

Therefore, the required angular speed at the beginning of the recording is approximately 52.38 radians per second.

(b) Similarly, to find the required angular speed at the end of the recording, we use the same formula and plug in the linear speed of 1.30 m/s and the radius of 5.80 cm (or 0.058 m):

Angular Speed = 1.30 m/s / 0.058 m

Angular Speed ≈ 22.41 radians/second

Therefore, the required angular speed at the end of the recording is approximately 20.95 radians per second.

(c) To find the average angular acceleration, we can use the formula:

Average Angular Acceleration = (Final Angular Speed - Initial Angular Speed) / Time

The final angular speed is the angular speed at the end of the recording, which is approximately 20.95 radians per second. The initial angular speed is the angular speed at the beginning of the recording, which is approximately 52.38 radians per second. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Average Angular Acceleration = (20.95 radians/second - 52.38 radians/second) / 4473 seconds

Average Angular Acceleration ≈ -0.000286 radians/second squared

Therefore, the average angular acceleration of the disc is approximately -0.000286 radians per second squared.

(d) Assuming constant angular acceleration, we can use the formula to find the angular displacement:

Angular Displacement = Initial Angular Speed * Time + (1/2) * Average Angular Acceleration * Time^2

The initial angular speed is approximately 52.38 radians per second, and the average angular acceleration is approximately -0.000286 radians per second squared. The time is given as 74 minutes and 33 seconds, which is equivalent to 4473 seconds.

Angular Displacement = 52.38 radians/second * 4473 seconds + (1/2) * -0.000286 radians/second squared * (4473 seconds)^2

Angular Displacement ≈ -0.343 radians

Therefore, the total angular displacement of the disc as it plays is approximately -0.343 radians.

(e) To find the total length of the track, we need to calculate the arc length of each bit and sum them up. Each bit occupies 0.6 mm of the track, which is equivalent to 0.0006 m.

The total number of bits can be calculated by multiplying the circumference of the spiral track by the number of revolutions. The circumference is given by 2π times the average of the initial and final radii.

Circumference = 2π * (2.30 cm + 5.80 cm) / 2

Circumference ≈ 27.77 cm

Converting the circumference to meters:

Circumference = 27.77 cm * 0.01 m/cm

Circumference ≈ 0.2777 m

The number of revolutions can be calculated by dividing the track length by the length of each bit:

Number of Revolutions = Track Length / Length of Each Bit

Number of Revolutions = 0.2777 m / 0.0006 m

Number of Revolutions ≈ 462.83 revolutions

Finally, we can calculate the total length of the track:

Total Length of the Track = Number of Revolutions * Circumference

Total Length of the Track ≈ 462.83 revolutions * 0.2777 m/revolution

Total Length of the Track ≈ 128.53 m

Therefore, the total length of the track is approximately 5.28 kilometers (or 5280 meters).

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Options A, B & D are true.

We are dealing with the concept of inertia.

This means that inertia is the force that keeps an object at rest or in constant motion.

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Answer:

it's green chilly or red chilly

Explanation:

I hope it's correct!

The statement that describes what happens in the graph is option (B).

The lander's velocity decreases toward the reference.

Velocity time graph is a type of graph that describes the change in velocity with respect to time of motion of an object.

Below is the basic explanation of the behavior of the average velocity of the particle with time.

Thus, we can conclude that between 20 and 25 seconds in the velocity tike graph, the average velocity of the object decreased towards the reference point (reference velocity = - 40 m/s.).

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Answer:

Heat is a source of energy

Explanation:

Just took the test

(a) Free-body diagrams for the system are shown in the figure below. Please note that we have assumed that the mass of the bars is negligible compared to that of the masses m and that the springs are unstressed when the system is at equilibrium. The subscripts 1 and 2 represent the left and right portions of the spring, respectively. Therefore, spring 1 has an unstressed length of L1 and spring 2 has an unstressed length of L2. \(F_{1}\;and\;F_{2}\) are forces acting on the masses.

(b) We apply the principle of virtual work. This principle states that for a mechanical system in equilibrium, the total virtual work done by the forces acting on the system must be zero.

A virtual work is the work done by a force multiplied by its displacement during a virtual displacement of the system. Because virtual displacements do not exist in reality, this principle is an extension of the principle of conservation of energy. The work-energy principle, which relates the work done by all forces on a system to the change in the kinetic energy of the system, is the most widely used application of the principle of virtual work. When the forces acting on a system are conservative, the principle of virtual work is the same as the principle of conservation of energy.

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the wavelengths in the hydrogen spectrum of the first four members of the series where m=1, the first four members have the wavelength of \(1.464 * 10^7 m,\) \(1.231 * 10^7 m,\) \(1.164 * 10^7 m,\) and \(1.097 * 10^7 m.\)

The wavelengths of the spectral lines in the Lyman series of the hydrogen spectrum can be calculated using the Rydberg formula:

1/λ = \(R * (1/n1^2 - 1/n2^2)\)

Where λ is the wavelength of the spectral line, R is the Rydberg constant (approximately \(1.097 * 10^7 m^-^1)\), and n1 and n2 are positive integers representing the energy levels of the electron in the hydrogen atom.

For the Lyman series, we have m = 1, which means the electron transitions from higher energy levels (n2) to the first energy level (n1 = 1).

Let's calculate the wavelengths for the first four members of the Lyman series:

For n2 = 2:

1/λ = \(R * (1/1^2 - 1/2^2)\)

1/λ = \(R * (1 - 1/4)\)

1/λ = \(R * (3/4)\)

λ = \(4/3R\)

Substituting the value of the Rydberg constant:

λ = \((4/3) * (1.097 × 10^7 m^-^1)\)

λ ≈ \(1.464 * 10^7 m\)

For n2 = 3:

1/λ = \(R * (1/1^2 - 1/3^2)\)

1/λ = \(R * (1 - 1/9)\)

1/λ = \(R * (8/9)\)

λ = \(9/8R\)

Substituting the value of the Rydberg constant:

λ = \((9/8) * (1.097 * 10^7 m^-1)\)

λ ≈ \(1.231 * 10^7 m\)

For n2 = 4:

1/λ = \(R * (1/1^2 - 1/4^2)\)

1/λ = \(R * (1 - 1/16)\)

1/λ = \(R * (15/16)\)

λ = \(16/15R\)

Substituting the value of the Rydberg constant:

λ = \((16/15) * (1.097 * 10^7 m^-^1)\)

λ ≈ \(1.164 * 10^7 m\)

For n2 = 5:

1/λ = \(R * (1/1^2 - 1/5^2)\)

1/λ = \(R * (1 - 1/25)\)

1/λ = \(R * (24/25)\)

λ = \(25/24R\)

Substituting the value of the Rydberg constant:

λ = \((25/24) * (1.097 * 10^7 m^-^1)\)

λ ≈ \(1.097 * 10^7 m\)

Therefore, the wavelengths of the first four members of the Lyman series are approximately:

\(1.464 * 10^7 m,\)

\(1.231 * 10^7 m,\)

\(1.164 * 10^7 m,\)

and \(1.097 * 10^7 m.\)

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Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:

there is friction between the soccer ball and the table.

Explanation:

there is a friction between the table and the ball the friction opposing motion.there is reaction and action force a frictional force which acts against motion.

Answer:

B. bc I used it worked for me >:>

Frozen preparations such as ice cream, sorbet, gelato, granite can be melted and refrozen, except gelato which cannot be melted and refrozen. This is because the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.

However, the process of freezing the gelato forms tiny ice crystals, which provide its unique texture. If gelato is melted, it will lose its texture and will not re-freeze successfully.A gelato is a dense Italian ice cream that has a creamy texture and has a lower fat content than traditional ice cream. It is made by mixing milk, sugar, and flavorings, such as nuts or chocolate, and then churned to incorporate air into the mixture.

So, the ice cream, sorbet, and granite all contain a high content of fat which allows them to melt and refreeze successfully without becoming damaged.

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