A local computer shop has a deal on a new computer that i would like to buy. They want a deposit of £115 and then 6 payments of £64.How much will the computer cost me?

Answer:

Original volume = (4/3)π(6^3) = 288π

New volume = (4/3)π(18^3) = 7,776π

7,776π ÷ 28π = 27

When the radius of a sphere is tripled, the volume of the new sphere is 27 times the volume of the old sphere.

Esta estrategia se puede aplicar sumando  15,75 + 0,25, –1,8 + –0,20, 3,5 + 12,5 y 2,62 + 7,38 antes de sumar el tercer número dado en cada caso.

La estrategia propuesta consiste en sumar dos números decimales que den como resultado un número entero antes de sumar el tercer número decima. Por ejemplo si teneos  1,4 + 0,6  + 1,2, se debe sumar primero 1,4 + 0,6 lo que es igual a 2 antes de sumar el 1,2.

Este estrategia es beneficiosa porque facilita sumar números decimales.

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The first series, Συ, is an infinite geometric series with the common ratio of b. The second series, Σ b k-1, is an infinite series with terms that are just powers of b.

For the first series to converge, we need the absolute value of b to be less than 1, so -1 < b < 1. For any other value of b, the series will diverge.

The second series, on the other hand, will only converge if b is less than 1 in absolute value, so -1 < b < 1. If b is greater than or equal to 1, the series will diverge.

(a) The first series, Σu, is a constant series, meaning that every term in the series is the same constant value (u). The second series, Σ(b^k-1), is a geometric series with a common ratio of b.

(b) For the constant series Σu, it will only converge if the constant value is 0. Otherwise, the series will either grow infinitely or decrease infinitely, depending on the sign of the constant.

(c) For the geometric series Σ(b^k-1), it will converge if the common ratio (b) is between -1 and 1 (i.e., -1 < b < 1). If the common ratio is outside of this range, the series will not converge.

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The expression to represent the number of cousins that Anna has is c + 5.

We are given a statement that says:

Number of cousins that Simon has is equal to = c

Now, it is also given that Anna has 5 more cousins than Simon.

So, we have to write an expression to show the number of cousins that Anna has.

An expression is a combination of constants and variables to express something or a statement.

So, the expression will be made by adding 5 to c

So, we get the expression as:

The number of cousins that Anna has = c + 5

Therefore, we get that, the expression to represent the number of cousins that Anna has is c + 5.

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The required solutions of the given equation are x = 30 or x < -50.

We can solve the equation by isolating the absolute value expression on one side and then solving for x.

First, we add 6 to both sides to get:

| x/5 + 2 | = 8

Next, we can split the equation into two cases, one where x/5 + 2 is positive and one where it is negative.

Case 1: x/5 + 2 ≥ 0

In this case, we can remove the absolute value bars and solve for x:

x/5 + 2 = 8

Subtracting 2 from both sides gives:

x/5 = 6

Multiplying both sides by 5 gives:

x = 30

So one solution is x = 30.

Case 2: x/5 + 2 < 0

In this case, we can also remove the absolute value bars but we need to flip the inequality when we do so:

-(x/5 + 2) = 8

Simplifying, we get:

-x/5 - 2 = 8

Subtracting 2 from both sides gives:

-x/5 = 10

Multiplying both sides by -5 (and remembering to flip the inequality) gives:

x < -50

So the solutions in this case are all x such that x < -50.

Putting the solutions from both cases together, we get:

x = 30 or x < -50.

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The solution to the system is x = 2 and y = 6, represented as the ordered pair (2, 6). This corresponds to option (B) in the answer choices.

To solve the system using substitution, we'll substitute the value of one variable from one equation into the other equation and solve for the remaining variable.

Given the system:

x + y = 8

y = 3x

Substituting the value of y from the second equation into the first equation, we have:

x + (3x) = 8

4x = 8

x = 2

Now, substitute the value of x into the second equation to solve for y:

y = 3(2)

y = 6

Therefore, the solution to the system is (2, 6). Option (B) is the correct answer.

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So there are 5 raspberries in the bowl.

The unitary approach involves calculating the value of a single unit, from which we may calculate the values of the necessary number of units.

Two quantities are compared to form a ratio. An equality of two ratios is a percentage. How to format a ratio Analyze the ratio to see whether it is part to part or part to whole. Calculate the whole and the pieces as necessary.

We know that for every 3 raspberries, there are 5 blackberries.

We can set up an equation to represent this relationship:

5 blackberries = 3 raspberries

We also know that there are a total of 15 blackberries in the bowl.

We can use the equation to find the number of raspberries in the bowl:

15 blackberries = 3 raspberries

15 blackberries / 3 raspberries = 5 raspberries

So there are 5 raspberries in the bowl.

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Answer:

H

Step-by-step explanation:

Answer:

container A

Step-by-step explanation:

In Container A, we can plot the points (0,60) adn (2, 35)

The slope is :

\(m_A = \frac{y_2-y_1}{x_2-x_1} \\\\= \frac{35-60}{2-0} \\\\= \frac{-25}{2}\\ \\m_A = -12.5\\\)

For container B, the slope is:

\(m_B = \frac{y_2-y_1}{x_2-x_1} \\\\= \frac{32-54}{3-1} \\\\= \frac{-22}{2}\\ \\m_B = -11\\\)

The negative sign of the slope indicates the direction of the slope

\(|m_A| = 12.5\\\\|m_B| = 11\)

12.5 > 11

The slope of container A is steeper than container B

Therefore, the water is draining out of container A at a faster rate than container B

Answer:

153.45

Step-by-step explanation:

15.5 x 9.9 = 153.45

Answer:

y = -0.5x + 1

Step-by-step explanation:

slope-intercept form is y=mx+b where m = slope and b = y-intercept

b = y value when x = 0

as shown in the chart, when x = 0, y = 1 so b = 1

m = vertical change/horizontal change

as shown in the chart, when x moves 2u right, y moves 1u down

m = -1/2 = -0.5

plugging in m and b into the formula y=mx+b, we get:

y = 0.5x + 1

Step-by-step explanation:

450450450=100%

? =110%

110×450450450/100

495495495 mins=2nd month

add

495495495+450450450=

945945945 minutes

There are 945 minutes will he read in all during the two months.

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Given that;

Oliver read for 450 minutes this month.

And, His goal is to read for 10% more minutes next month.

Now,

Since, His goal is to read for 10% more minutes next month.

Hence, The extra minutes for next month = 10% of 450 minutes

                                                                 = 10/100 × 450

                                                                 = 45 minutes

Thus, The total minutes to read in all during the two months is,

⇒ 450 + (450 + 45) minutes

⇒ 450 + 495 minutes

⇒ 945 minutes

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Answer:

d

Step-by-step explanation:

So the problem states,

52 = 36 + 4x

16 = 4x

x = 4 (must be less than or equal to)

Answer:

A: x=-1

Step-by-step explanation:

y = mx + b

Is parallel to line 5x - 2y = 6

Slope m= ?

write

5x - 6= 2y

(5/2)x - (6/2)= y

2.5x - 3 = y

Then Slope m= 2.5

equation is y= 2.5x + b

Now, find b

b= y - 2.5x

Replace point (-

Answer:

volume = 41,472 in³

Step-by-step explanation:

volume = 24 x 48 x 36 = 41,472 in³

\(\\ \sf\longmapsto \left\{\left(-\dfrac{3}{4}\right)^5\right\}^2\)

\(\\ \sf\longmapsto \left\{-\dfrac{3^5}{4^5}\right\}^2\)

\(\\ \sf\longmapsto \left\{-\dfrac{243}{1024}\right\}^2\)

\(\\ \sf\longmapsto \dfrac{3^{10}}{4^{10}}\)

\(\\ \sf\longmapsto \dfrac{59049}{1048568}\)

The given statement "A joint frequency distribution would be useful for determining whether newer cars tend to be driven more miles than older cars." is true because it shows the frequencies, or counts in table.

A joint frequency distribution is a table that shows the frequencies, or counts, of two or more variables for a given dataset. In this case, the two variables are the number of miles driven last year and the age of the vehicle for a sample of car owners.

A joint frequency distribution would be useful for examining the relationship between these variables and determining whether newer cars tend to be driven more miles than older cars.

By examining the joint frequency distribution, one can calculate and compare the average miles driven for different age categories of cars. For example, the average miles driven per year for cars less than 5 years old can be compared to the average miles driven per year for cars 5 to 10 years old and cars over 10 years old.

This can provide insight into whether there is a relationship between car age and miles driven, and whether this relationship is significant.

Therefore, the statement that a joint frequency distribution would be useful for determining whether newer cars tend to be driven more miles than older cars is true. It is a useful tool for examining the relationship between two variables and identifying patterns and trends in the data.

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Answer:

Step-by-step explanation:

You had the first part of the first question correct. The answer is 100:64

The sides of the squares

Area of e = 69% more than area of area of f

e^2: f^2 = ( 1 + 69/100 ) / 1

e^2 : f^2 = (1.69)/1            Take the square root of both sides

e:f  = 1.3:1

From the graph we notice that the function takes values from -5 to 1. Although we notice that the function is not defined for the value -5 whereas it is defined for the value 1, this means that the domain is:

Answer:

48 and 32

Step-by-step explanation:

both numbers get rounded by 8 going up and down rounding it to 40

Using the binomial distribution, it is found that:

The formula is:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(C_{n,x} = \frac{n!}{x!(n-x)!}\)

The parameters are:

For this problem, the values of the parameters are:

n = 10, p = 0.2.

The probability that 6 VIPs attend is given by:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 6) = C_{10,6}.(0.2)^{6}.(0.8)^{4} = 0.0055\)

The probability that 10 VIPs attend is given by:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0\)

The probability that more than 6 VIPs attend is given by:

P(X > 6) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10).

Then:

\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)

\(P(X = 7) = C_{10,7}.(0.2)^{7}.(0.8)^{3} = 0.0008\)

\(P(X = 8) = C_{10,8}.(0.2)^{8}.(0.8)^{2} = 0.0001\)

\(P(X = 9) = C_{10,9}.(0.2)^{9}.(0.8)^{1} \approx 0\)

\(P(X = 10) = C_{10,10}.(0.2)^{10}.(0.8)^{0} \approx 0\)

So:

P(X > 6) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0008 + 0.0001 + 0 + 0 = 0.0009.

The probability that more than 6 VIPs attend is 0.0009 = 0.09%.

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The probability that the second child born to the couple will have blood type AB is 1/2.

Blood grouping is the categorization of blood into groups depending on the type of antigen and antibody present on the surface of red blood cells (RBCs).

The ABO blood grouping system, which includes A, B, AB, and O blood types, is the most well-known blood grouping system.

Blood group Rh (Rhesus) grouping system is another well-known blood grouping system that can be determined.

Therefore, the probability that the second child born to the couple will have blood type AB is 1/2.

50 percent of the offspring of this couple will inherit the gene for the ABO blood type A from the mother, while the remaining 50% will inherit the gene for the blood type B from the father.

The probability of inheriting the gene for blood type AB is thus 1/2 for a child born to these parents.

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To apply Green's Theorem to evaluate the given line integral, we need to express the integral as a double integral over the region bounded by the curve. In this case, the region is a triangle bounded by the lines x = 0, x + y = 1, and y = 0.

Green's Theorem states that for a vector field F = (P, Q) and a simple closed curve C oriented counterclockwise, the line integral of F around C is equal to the double integral of the curl of F over the region D bounded by C.

Let's calculate the curl of the vector field F = (y^2, x^2):

∂Q/∂x = 2x

∂P/∂y = 2y

The curl of F is given by ∂Q/∂x - ∂P/∂y:

curl(F) = 2x - 2y

Now, let's set up the double integral over the region D:

∬_D (2x - 2y) dA

To evaluate this integral, we need to express it in terms of the region D. The given region is a triangle bounded by the lines x = 0, x + y = 1, and y = 0.

We can rewrite the double integral using the limits of integration corresponding to the triangle:

∬_D (2x - 2y) dA = ∫_0^1 ∫_0^(1-x) (2x - 2y) dy dx

Evaluating the inner integral with respect to y:

∫_0^(1-x) (2x - 2y) dy = [2xy - y^2]_0^(1-x)

Plugging in the limits:

[2x(1-x) - (1-x)^2]_0^1

Simplifying:

[2x - 2x^2 - (1 - 2x + x^2)]_0^1

[2x - 2x^2 - 1 + 2x - x^2]_0^1

Combining like terms:

-3x^2 + 4x - 1

Therefore, the value of the line integral ∫ (y^2 dx + x^2 dy) over the triangle bounded by x = 0, x + y = 1, and y = 0 is -3x^2 + 4x - 1.

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Frankie's dad used 2/3 of the carton of eggs for their breakfast. Two equivalent fractions are 16/24 and 24/36.

Frankie's dad used 8 out of 12 eggs from a full carton. To express this as a fraction, we can write it as 8/12. However, this fraction can be simplified by dividing both the numerator and denominator by their greatest common factor, which in this case is 4. Thus, we get:

8/12 = (8 ÷ 4)/(12 ÷ 4) = 2/3

Alternatively, we can also express this fraction in different forms. One way to do this is by multiplying both the numerator and denominator by the same number. For example, if we multiply both by 2, we get:

8/12 = (8 × 2)/(12 × 2) = 16/24

Similarly, we can multiply by 3 to get:

8/12 = (8 × 3)/(12 × 3) = 24/36

Both of these fractions are equivalent to 2/3, and we can find infinitely many other equivalent fractions by multiplying both numerator and denominator by different numbers.

In summary, when Frankie's dad made scrambled eggs using 8 eggs from a full carton of 12 eggs, he used 2/3 of the carton. This fraction can be expressed in different forms that are equivalent to 2/3 by dividing both numerator and denominator by their greatest common factor or by multiplying both numerator and denominator by the same number.

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When Cedric walked into a party, two-thirds of those invited had already arrived. Six more people arrived just after Cedric, bringing the number at the party to of those invited. The total number of invited guests is 18 by Linear equations

What was the total number of invited guests?

There are different methods of solving the problem, and we will use the following steps to get the solution of the problem: Let the total number of invited guests be x.Let's solve the problem with a step-by-step explanation.

Step 1: At the time Cedric arrived, two-thirds of the guests were already present.Let the number of guests present at the party when Cedric arrived be A. Therefore, A = (2/3)x

Step 2: Six more people arrived after Cedric got there. Therefore, the total number of guests after the six people arrived is A + 6.

Step 3: The total number of guests present was also x, which is the total number of guests invited. Therefore A + 6 = x.

Step 4: Substitute A = (2/3)x from Step 1 into A + 6 = x from Step 3 to obtain: (2/3)x + 6 = xStep 5: To solve for x, we will get rid of the fraction by multiplying every term by 3x.

Then we will simplify. 3x * (2/3)x + 3x * 6 = 3x * x Simplifying further  2x + 18 = 3x Subtracting 2x from both sides of the equation 18 = x.

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Answer:

The Answer Is A. I believe