a long focal length lens that magnifies the subject and narrows the field of view is called a __

I hope this woll work.Best of luck.Sorry of the answer ia wrong

The second largest moon in our solar system is Titan.

It is the largest moon of Saturn and the only moon in the solar system with a significant atmosphere. It is also one of the few bodies in the solar system, other than Earth, where there is evidence of stable bodies of surface liquid.

The Cassini-Huygens mission was launched in 1997 and reached the Saturn system in 2004. This mission provided detailed observations of Titan, including radar images of its surface and measurements of its atmosphere and composition.

The second largest moon in our solar system, Titan is bigger than Mercury. Ganymede, a moon of Jupiter, is just somewhat bigger (by around 2%). Titan's atmosphere is primarily composed of nitrogen, just like Earth's, but it has a surface pressure that is 50% higher.

Titan has liquid hydrocarbons like methane and ethane in its rivers, lakes, seas, clouds, rain, and atmosphere. The greatest seas are hundreds of miles across and several hundred feet deep. More liquid—an ocean made primarily of water as opposed to methane—lies beneath Titan's thick water ice layer. Titan's subterranean water might support life as we know it, while its liquid hydrocarbon lakes and seas might support life that has a distinct chemistry.

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Answer:

6.76875 • 10 ^-10 F

Explanation:

You just follow the formula:

C = εA/d

ε = 8.85 • 10^-12

A = 3.61 • 10^-4

D = 4.72 • 10 ^-6

So:

C = (8.85 • 10^-12)(3.61 • 10^-4)/4.72 • 10 ^-6 = 6.76875 • 10 ^-10 F

Good Luck!  :)

Answer:

\(28\; {\rm kg \cdot m\cdot s^{-1}}\).

Explanation:

The impulse on an object is equal to the change in momentum.

By the conservation of momentum, the total momentum of this system will stay unchanged. In other words, the sum of the change in the momentum of the wall and the projectile will be \(0\):

\(\Delta p(\text{projectile}) + \Delta p(\text{wall}) = 0\).

Rearrange to obtain:

\(\Delta p(\text{wall}) = -\Delta p(\text{projectile})\).

The change in the momentum of the projectile is:

\(\begin{aligned} & \Delta p(\text{projectile}) \\ &= m(\text{projectile}) \, \Delta v(\text{projectile}) \\ &= (2.0\; {\rm kg})\, ((8.0 - (-6.0))\; {\rm m\cdot s^{-1}}) \\ &= 28\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).

The change in the momentum of the wall would then be:

\(\Delta p(\text{wall}) = -\Delta p(\text{projectile}) = -28\; {\rm kg\cdot m\cdot s^{-1}}\).

Thus, the magnitude of the impulse on the wall would be \(28\; {\rm kg\cdot m\cdot s^{-1}}\).

Answer:

the third one T-W

Explanation:

the direction of the Tension and weight are opposite

Two point charges of 2.00 μc and -2.00 μc are 0.100 m apart the electric field at the point midway between the two charges: 7.20 x 10⁵ N/C.

The electric field at the point midway between two point charges can be determined by calculating the electric fields produced by each charge and then summing them up as vectors.

In this case, we have two point charges, +2.00 μC and -2.00 μC, separated by a distance of 0.100 m. Since the charges have the same magnitude but opposite signs, the electric fields they produce at the midpoint will have equal magnitudes but point in opposite directions.

The electric field produced by a point charge is given by the equation: E = k × |q| / r²

where E is the electric field, k is the electrostatic constant, |q| is the magnitude of the charge, and r is the distance between the charge and the point where the field is being calculated.

For the midpoint, the distances from each charge are equal, i.e., r = 0.050 m. Therefore, the electric field produced by each charge is:

E₁ = k × |2.00 μC| / (0.050 m)²

E₂ = k × |-2.00 μC| / (0.050 m)²

Substituting the values and considering the opposite directions of the fields, we have: E = E₁ - E₂

Calculating the magnitudes and taking into account the values of k and the charges, we find:

E = (9.0 x 10⁹ N·m²/C²) × (2.00 μC) / (0.050 m)²

E ≈ 7.20 x 10⁵ N/C

Therefore, the electric field at the point midway between the two charges is approximately 7.20 x 10⁵ N/C.

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The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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Answer:

Scientific tool used to identify organisms

Explanation:

Dichotomous keys consist of a series of statements with two choices in each step that will lead users to the correct identification.

The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

Electric field - Every point in space where a charge, in any form, is present has an electric property that is called an electric field.

The magnitude of the electric field strength is given as :

E = F/q

where

E = electric field

F = electrostatic force

q = charge

electron experiences a force of as it accelerates between two metal plates =  2 x 10⁻¹⁵ N

Charge of the electron,

q = 1.6 × 10⁻¹⁹ C

Then

E = (2 x 10⁻¹⁵ N)÷(1.6 × 10⁻¹⁹ C)

E = 1.25 x × 10⁴ N/C.

The magnitude of the electric field between the plates is 1.25 x × 10⁴ N/C.

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Answer:

a. 60 N*s

b. 60 (kg*m)/s

c. 3 m/s

Explanation:

Givens:

m = 20 kg

v_i = 0 m/s

t = 10 s

F = 6 N

a) Impulse:

I = F*t

I = 6 N*10 s

I = 60 N*s

b) Momentum:

p = v*m

F = m(a)

a = F/m

a = 6 N/20 kg

a = 0.3m/s^2

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

p = 3 m/s*20 kg

p = 60 (kg*m)/s

c. Final velocity

a = (v_f -v_i)/t

v_f = (0.3 m/s^2)*10 s

v_f = 3.0 m/s

The impulse, momentum and final velocity can all be obtained from Newton's second law.

Let us recall that the impulse is obtained as the product of force and time.

Impulse = Force × time

Impulse = 6 N × 10 s = 60 Ns

From Newton's second law of motion;

F.t = mv - mu

Since the object was initially at rest;

F.t = mv

Hence, the final velocity of the object is 60 Kgms-1

The final velocity is obtained from;

F.t = mv

v = F.t/m

v = 6 × 10/20

v = 3 m/s

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The extra mass of the magnesium oxide comes from then magnesium nitride that is also formed.

If we look at the law of the conservation of mass, we know from that very law that the masses of the substances at the beginning of the reaction must be the same as the masses of the substances at the end of the reaction and this is because the mass of the reaction is conserved.

Given the fact that magnesium does combine with nitrogen to give magnesium nitride in the reaction then the mass of the product would be higher.

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Answer:

The correct answer is

Explanation:

Answer:

13 m/s²

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration  = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m  (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

\(\\ \rm\longmapsto F=ma\)

\(\\ \rm\longmapsto a=\dfrac{F}{m}\)

\(\\ \rm\longmapsto a=\dfrac{2600}{200}\)

\(\\ \rm\longmapsto a=13m/s^2\)

Answer:

Explanation:

Before starting to move a crate using the right arrow button, we need to set the friction bar to medium. This is because friction is a force that opposes motion. Hence, if the crate is too heavy and the friction is low, the crate won't move easily.

Similarly, if the crate is too light and the friction is high, we need to apply more force to move it. Therefore, we should adjust the friction to a medium level which will allow us to move the crate with ease. After setting the friction to medium, the next step is to select a 50k crate. This is important because different crates have different weights. So, if we select a crate that is too heavy, it will be hard to move it even if the friction is set to medium.

Similarly, if we select a crate that is too light, we might have to apply more force than necessary to move it. Therefore, selecting a 50k crate is a good balance between weight and ease of movement.

Finally, once we have selected a 50k crate and set the friction to medium, we can slowly apply rightward force using the right arrow button. This is because we want to avoid applying too much force at once which might cause the crate to move too fast and become hard to control. By applying force slowly, we can ensure that the crate moves in the desired direction and speed.

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Answer:

D = 14.31 m

Explanation:

It is given that,

Displacement due east is 12 m

Displacement due north is 5 m

Displacement in vertically upward direction is 6 m

We need to find the magnitude of the sum of these displacements. We know that, vertically upward, east and north are mutually perpendicular direction. So, the resultant is given by :

\(R=\sqrt{12^2+5^2+6^2} \\\\R=\sqrt{144+25+36} \\\\R=14.31\ m\)

So, the magnitude of the sum of these displacements is 14.31 m.

The mean free path of an O2 molecule in a 1 L container at STP, with a diameter of \(3.75\) * \(10^{-10}\) m, is approximately \(6.0\) * \(10^{-7}\)m.

The mean free path of a molecule is the average distance it travels between collisions with other molecules. In order to calculate the mean free path of an O2 molecule, we need to consider its diameter and the number of molecules present in the container.

At STP (standard temperature and pressure), the temperature is 273.15 K and the pressure is 1 atmosphere (atm). We can use these values to calculate the number of O2 molecules in the container using the ideal gas law:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Since we know the volume (1 L), pressure (1 atm), and temperature (273.15 K), we can rearrange the ideal gas law to solve for n:

\(n=\frac{PV}{RT}\)

Using the value of the ideal gas constant\((R=0.0821 \frac{Latm}{(molK)} )\) , we can calculate the number of moles of O2 gas.

Once we have the number of moles, we can convert it to the number of molecules using Avogadro's number (\(6.22\) * \(10^{23} \frac{molecules}{mol}\)).

Now, we can calculate the average distance traveled by an O2 molecule between collisions, which is the mean free path. The mean free path (λ) can be determined using the formula:

λ = \((\frac{1}{\sqrt{2} } )\) * (\(\frac{V}{d^{2} }\) * N))

Where V is the volume, d is the diameter of the molecule, and N is the number of molecules.

Plugging in the known values, we find:

λ = \((\frac{1}{\sqrt{2} } )\) * \(\frac{1L}{\pi 3.75*10^{-10}m^{2}*N } )\)

Substituting the values, we get:

λ ≈ \(6.0*10^{-7}\)

Therefore, the mean free path of an O2 molecule in a 1 L container at STP, with a diameter of \(3.75*10^{-10}\), is approximately \(6.0*10^{-7}\) m.

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Temperature is the degree of hotness or coldness of an object or substance. The SI unit of temperature is Kelvin."97%": The question suggests that a reaction must be run at a specific temperature to achieve 97% yield or completion. Yield refers to the amount of product obtained from a reaction.

To achieve 97% yield or completion, the reaction must be run at a specific temperature. Temperature plays an essential role in chemical reactions since it affects the rate of reaction, activation energy, and equilibrium. The temperature at which a reaction runs optimally, producing the most product, is known as the reaction's optimum temperature. As a result, the temperature must be controlled during a chemical reaction.To achieve 97%, the reaction must be run at a specific temperature.

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Explanation:

Well it depends on what type of energy all plants produce energy for them to survive but if its a certain energy your looking for make sure to put it in you quesion

Answer:

ok?

Explanation:

It is because the weight W = 0, due to g = a, the person falling during the free fall will therefore experience weightlessness.

A free fall is a situation where a body or an object fall solely under the influence of gravity.

Why does a person feel weightlessness during freefall​ ?

The weight of a body = mg

When a person is falling, the person will be falling with a certain acceleration. The weight W of the person will be;

W = m( a - g )

During free fall, acceleration a will be equal to acceleration due to gravity g. That is, a = g

W = m( a - a )

W = m( 0 )

W = 0

Since the weight W = 0, the person falling during the free fall will therefore experience weightlessness.

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False. Staleness and burnout are often associated with overtraining, which occurs when an individual exceeds their capacity to recover from intense physical training or activity.

Overtraining can lead to physical and psychological symptoms, including decreased performance, fatigue, irritability, and decreased motivation. It is important for individuals to listen to their bodies and take rest and recovery periods to prevent overtraining and associated symptoms.

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These forces cancel each other out, and the motion of the item on which they act remains unchanged.

A force is an influence that changes the velocity of an item with mass, causing it to accelerate. It can be a push or a pull, with magnitude and direction always present, making it a vector quantity.

One example is pushing or shoving a door with force. Force is a vector quantity, which means it has a magnitude as well as a direction. Newton's second law states that force is defined as the "product of a body's mass and acceleration."

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Therefore for cart to stay here on track when it arrives at point P, the net force applied to it must be greater or equal than for the heaviness of the cart.

The force is an impact that has the power to alter an object's motion. A mass-containing object's velocity can be altered by a force. An obvious way to describe force is as a pushed or a pull. A vector quantity is called a force since it has both strength and the direction.

The strongest force in existence is thought to be the strong force. The gravitation, weak, and electromagnetism forces come after it in lowest to highest.

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The magnitude of the net force of A and B on object C which is stated as resultant force is 85.12 N.

The entire force operating on the item or body, combined with the body's direction, is referred to as the resultant force. When the object is at rest or moving at the same speed as the object, the resulting force is zero. Since all forces are acting in the same direction, the combined force should be equal for all forces.

Combining forces applied to the same body component might result in the same outcome. Combining forces with various points of application while maintaining the same effect on the body is not conceivable. By moving the forces to the same point of application and computing the associated torques, a system of forces operating on a rigid body is combined. These forces and torques are added to produce the final force and torque.

We have two forces as,

A = 25.6 sin 26.5 = 11.42

B = 99.7 cos 32.2 = 84.36

R = \(\sqrt{A^2+B^2}\) = \(\sqrt{11.42^2+84.36^2}\) = \(\sqrt{7247.026}\) = 85.12 N

Therefore, the magnitude of force on C is 85.12 N.

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The current through resistor R3 is 0.33 A. A circuit with three resistors connected in series is shown below: Circuit diagram of three resistors connected in series As per the given information, R2 has a resistance of 200 ohms and a voltage drop of 30 volts.

Therefore, the voltage drop across R1 is V1 = V - V2 - V3V = voltage supplied to the circuit = voltage drop across R1 + voltage drop across R2 + voltage drop across R3R1 = Resistance of resistor R1.R2 = Resistance of resistor R2 = 200 Ω.V3 = Voltage drop across resistor R3.I3 = Current through resistor R3.To calculate the current in resistor R3, let's follow the steps given below.Step 1: Find the voltage drop across R1.Using Ohm's Law, the voltage drop across R2 is V2 = IR2Substitute the values of V2 and R2 to get the value of current I.I = V2/R2I = 30/200I = 0.15 A

Using Kirchhoff's voltage law, the voltage drop across R1 isV1 = V - V2 - V3V = V1 + V2 + V3Substitute the values of V, V2, and V3 to get the value of V1.V1 = V - V2 - V3V1 = 100 - 30 - V1V1 = 70 VStep 2: Find the current through R3.Using Ohm's Law, the voltage drop across R3 is V3 = I3R3.Substitute the values of V3 and R3 to get the value of current I3.I3 = V3/R3I3 = (V - V1 - V2)/R3I3 = (100 - 70 - 30)/R3I3 = 0.33 A

Therefore, the current through resistor R3 is 0.33 A.

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Answer:

30Kg

Explanation:

Weight = mass x gravitational field strength

300 = mass x 10

mass = 30kg

gravitational field strength is 9.8 on earth but normally we take it to be 10 for easy reference and calculations

The mass will be "30 kg". A further solution is provided below.

According to the question,

Weight,

We know that,

Gravitational field strength,

The mass will be:

→ \(Weight = Mass\times Gravitational \ field \ strength\)

or,

→ \(Mass = \frac{Weight}{Gravitational \ field \ strength}\)

By putting the values, we get

→           \(= \frac{300}{10}\)    

→           \(= 30 \ kg\)

Thus the above solution is right.

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