A long string is stretched and its left end is oscillated upward and downward. Two points on the string are labeled A and B. Points A and B are indicated on the string. Orient the two vectors, v⃗ A and v⃗ B, to correctly represent the direction of the wave velocity at points A and B. Rotate the given vectors to indicate the direction of the wave velocity at the indicated points

Answer:

mass number = protons + neutrons.

Explanation:

Together, the number of protons and the number of neutrons determine an element's mass number: mass number = protons + neutrons. If you want to calculate how many neutrons an atom has, you can simply subtract the number of protons, or atomic number, from the mass number.

Answer: To efficiently communicate with others

Explanation:

this was the right on answer for me might be different for others

The main need or want the wave technology shown meets to see objects surrounding more clearly.

It is a floating device that operates in the same direction as the waves. With the use of the technology, energy may be captured even from relatively small waves. The device that is moved by waves activates a hydraulic system that can power a generator. The tube segment contains all the generation equipment and systems.

Early mechanization (1770s to 1830s), steam power and railroads (1830s to 1880s), electrical and heavy engineering (1880s to 1930s), Fordist mass production (1930s to 1970s), and information and communication are the five waves that have so far slammed into our society (1970s to 2010s).

Wave energy, also known as wave power, is the energy that ocean surface waves carry and absorb. The energy is then put to use in a variety of productive ways.

Thus, The main need or want the wave technology shown meets to see objects surrounding more clearly.

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In this theory, acidity is defined by the concentration of hydrogen ions: the greater the concentration, the more acidic a solution. The measure used is the pH—potential of hydrogen—scale, developed in 1909. The pH scale has values ranging from 0 (extremely acidic) to 14 (extremely alkaline).

To trace the pH scale, a group of standard solutions whose pH has been established by international agreement can be employed. The potential difference between a hydrogen electrode and a standard electrode, such as the silver chloride electrode, is measured using a concentration cell with transference to obtain the primary pH standard values. The pH of aqueous solutions can be measured using a glass electrode, a pH metre, or a color-changing indicator. pH measurements are important in many fields, including chemistry, agronomy, medicine, water treatment, and many more.

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To get 85g of nickel, 0.304 kilogram of the ore must be mined.

27.9% of what = 85g

0.279 * x = 85

x = 304.6g = 0.304kg

What is ore?

Ore is a naturally occurring rock or silt that has one or more precious minerals in it that may be extracted, processed, and sold for a profit. Metals are the most common valuable minerals found in ore. To remove the valuable metals or minerals from ore, it is mined from the earth and then processed or refined, frequently by smelting.

An ore is a naturally occurring collection of minerals from which metals can be profitably extracted. Originally, the term "ore" solely referred to metallic minerals, but today it also refers to nonmetallic materials that have been deposited in rock after it has formed.

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Answer:

The answer will be listed below.

Explanation:

Speed and velocity both represent a way to measure the change in position of an object relative to time. If the motion is in a straight lne, then the speed and velocity would be the same. When measuring speed and velocity, they are used in m/s.

The molarity of a solution that was prepared by dissolving 14.2 g of \(NaNO_3\) is 0.477 M.

To calculate the molarity of a solution, we use the formula:

Molarity (M) = moles of solute/volume of solution in liters

First, we need to calculate the moles of \(NaNO_3\) that were dissolved in the solution:

moles of \(NaNO_3\) = mass / molar mass

moles of \(NaNO_3\) = 14.2 g / 85.0 g/mol = 0.167 moles

Next, we need to convert the volume of the solution from milliliters (mL) to liters (L):

volume of solution = 350 mL = 0.350 L

Now we can use the molarity formula to calculate the molarity of the solution:

Molarity (M) = moles of solute/volume of solution in liters

Molarity (M) = 0.167 moles / 0.350 L = 0.477 M

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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Answer:

Explanation:

Data tables help you keep information organized. If you're collecting data from an experiment or scientific research, saving it in a data table will make it easier to look up later. Data tables can also help you make graphs and other charts based on your information.

Answer:

chlorine is for pool

Explanation:

hope is help

Q1. The formula for the energy levels of hydrogen is E = -13.6 eV/n².

Q2. a) The wavelength for the transition between n=1 and n=6 is approximately 93.5 nm. b) The wavelength for the transition between n=25 and n=26 is approximately 29.46 nm.

Q3. For the transitions in Q2, the relative densities are approximately 0.73 and 0.995, respectively.

Q4. The Lambert-Beers law relates the intensity of light transmitted through an absorber to the absorber's density, cross section for absorption, and position within the medium. It is expressed as I(x) = I₀ * exp(-n * σ(λ) * x).

Q1. The formula for the energy levels of hydrogen is given by the Rydberg formula, which is used to calculate the energy of an electron in the hydrogen atom:

E = -13.6 eV/n²

Where:

- E is the energy of the electron in electron volts (eV).

- n is the principal quantum number, which represents the energy level or shell of the electron.

Q2. a) To find the wavelength (in nm) for a transition between n=1 and n=6 in hydrogen, we can use the Balmer series formula:

1/λ = R_H * (1/n₁² - 1/n₂²)

Where:

- λ is the wavelength of the photon emitted or absorbed in meters (m).

- R_H is the Rydberg constant for hydrogen, approximately 1.097 x 10⁷ m⁻¹.

- n₁ and n₂ are the initial and final energy levels, respectively.

Plugging in the values, we have:

1/λ = (1.097 x 10⁷ m⁻¹) * (1/1² - 1/6²)

1/λ = (1.097 x 10⁷ m⁻¹) * (1 - 1/36)

1/λ = (1.097 x 10⁷ m⁻¹) * (35/36)

1/λ = 1.069 x 10⁷ m⁻¹

λ = 9.35 x 10⁻⁸ m = 93.5 nm

Therefore, the wavelength for the transition between n=1 and n=6 in hydrogen is approximately 93.5 nm.

b) Similarly, to find the wavelength (in nm) for a transition between n=25 and n=26 in hydrogen, we can use the same formula:

1/λ = R_H * (1/n₁² - 1/n₂²)

Plugging in the values:

1/λ = (1.097 x 10⁷ m⁻¹) * (1/25² - 1/26²)

1/λ = (1.097 x 10⁷ m⁻¹) * (1/625 - 1/676)

1/λ = (1.097 x 10⁷ m⁻¹) * (51/164000)

1/λ = 3.396 x 10⁴ m⁻¹

λ = 2.946 x 10⁻⁵ m = 29.46 nm

Therefore, the wavelength for the transition between n=25 and n=26 in hydrogen is approximately 29.46 nm.

Q3. To determine the relative density for each of the transitions in Q2, we need to calculate the ratio of the photon flux between the two states. The relative density is given by the equation:

Relative Density = (I(x2) / I(x1))

Where I(x2) and I(x1) are the photon fluxes at positions x2 and x1, respectively.

For a gas temperature of 300K, the relative density is proportional to the Boltzmann distribution of states, which is given by:

Relative Density = exp(-ΔE/kT)

Where ΔE is the energy difference between the two states, k is the Boltzmann constant (approximately 1.38 x 10⁻²³ J/K), and T is the temperature in Kelvin.

a) For the transition between n=1 and n=6, the energy difference is:

ΔE = E₁ - E₂ = (-13.6 eV / 1²) - (-13.6 eV / 6²)

ΔE = -13.6 eV + 0.6 eV = -13.0 eV

Converting the energy difference to joules:

ΔE = -13.0 eV * 1.6 x 10⁻¹⁹ J/eV = -2.08 x 10⁻¹⁸ J

Substituting the values into the relative density equation:

Relative Density = exp(-(-2.08 x 10⁻¹⁸ J) / (1.38 x 10⁻²³ J/K * 300 K))

Relative Density ≈ 0.73

Therefore, for the transition between n=1 and n=6, the relative density is approximately 0.73.

b) For the transition between n=25 and n=26, the energy difference is:

ΔE = E₁ - E₂ = (-13.6 eV / 25²) - (-13.6 eV / 26²)

ΔE ≈ -13.6 eV + 0.0585 eV ≈ -13.5415 eV

Converting the energy difference to joules:

ΔE ≈ -13.5415 eV * 1.6 x 10⁻¹⁹ J/eV ≈ -2.1664 x 10⁻¹⁸ J

Substituting the values into the relative density equation:

Relative Density = exp(-(-2.1664 x 10⁻¹⁸ J) / (1.38 x 10⁻²³ J/K * 300 K))

Relative Density ≈ 0.995

Therefore, for the transition between n=25 and n=26, the relative density is approximately 0.995.

Q4. Derivation of the Lambert-Beers law:

To derive the Lambert-Beers law, we consider a thin slice of the absorber with thickness dx. The intensity of light passing through this slice decreases due to absorption.

The change in intensity, dI, within the slice can be expressed as the product of the intensity at that position, I(x), and the fraction of light absorbed within the slice, nσ(λ)dx:

dI = -I(x) * nσ(λ)dx

The negative sign indicates the decrease in intensity due to absorption.

Integrating this equation from x = 0 to x = x (the total thickness of the absorber), we have:

∫[0,x] dI = -∫[0,x] I(x) * nσ(λ)dx

The left-hand side represents the total change in intensity, which is equal to I₀ - I(x) since the initial intensity is I₀.

∫[0,x] dI = I₀ - I(x)

Substituting this into the equation:

I₀ - I(x) = -∫[0,x] I(x) * nσ(λ)dx

Rearranging the equation:

I(x) = I₀ * exp(-nσ(λ)x)

This is the Lambert-Beers law, which shows the exponential decrease in intensity (photon flux) as light passes through an absorber. The law quantifies the dependence of intensity on the density of the absorber, the absorption cross section, and the position within the absorber.

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Sulfanilic acid and a-naphthylamine are red reagents that become clear in the presence of nitrate. This statement is True.

Sulfanilic acid and α-naphthylamine are two reactors commonly used in the Griess test for the detection of nitrite ions. In this test, the reactors react with nitrite to create a diazonium salt, which then responds with a yoke agent to form a red-colored azo dye. The existence of nitrite can be noticed by the formation of a red color.

This further testing includes the acquisition of sulfanilic acid also called Nitrate I and Dimethyl-alpha-Napthalamine (nitrate II). If this nitrate is there in the media, then it will react with nitrate I and nitrate II to generate a red mixture. This is believed as a positive result.

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Answer:

what is the question

Explanation:

Answer:

Um what do u want us to check?

Explanation:

Actually, interesting enough, smog is an example of a heterogeneous mixture. So no, it's not a pure substance.

Answer:

No, smog is not a pure substance.

Explanation:

Smog is a heterogeneous mixture, heterogeneous mixtures contain two or more phases.

Hope this helped :)

Answer:

30gtts/min

Explanation:

To solve this problem we need to divide the volume(mL) and time(min) then multiply by the drop factor. Note that 1hr = 60min.

120/60 * 15 = 30gtts/min

Best of Luck!

The packaging for tubing sets should include the drop factor. For instance, 10 gtt/ml (drop factor of 10) indicates that 10 drops are required to create 1 milliliter of fluid. The required drops per minute are 30gtts/min.

The amount of drips (represented as "gtt") that enter the drip chamber each minute is counted to determine the flow rate. The drop factor, as opposed to the drip factor, is the quantity of drops in 1 mL of solution. On packets of IV tubing, drop factors are printed.

To solve this problem we need to divide the volume(mL) and time(min) and then multiply by the drop factor. Note that 1hr = 60min.

120/60 × 15 = 30gtts/min

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Answer:

Logan could explain the lower mass by explaining that the reaction between hydrochloric acid and magnesium produces hydrogen gas, which escapes and therefore is not included in the final combined mass measurement. The reaction is:HCl + Mg → MgCl2 + H2Since the hydrogen gas has mass, its escape from the reaction vessel explains the decrease in the combined mass of the reactants after the reaction.

0 J

Work = Force * Displacement

Since displacement is 0 m (object isn't moving), work would also be 0.

Answer:

Energy

Explanation:

energy is defined in science as the ability to move matter or change matter in some other way energy can also be Eefined as the ability to do work which means using force to move an object over a distance when work is done energy is transferred from one object to another.

Answer

Based on the previous we can say that: The law of conservation of the mass states that the total mass will always stay the same during a chemical reaction. After the reaction, the vessel will have a mass equal to the initial 245 g.

Explanation

The Law of Conservation of Mass states that the mass is neither created nor destroyed in chemical reactions. This means the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Based on the previous we can say that: The law of conservation of the mass states that the total mass will always stay the same during a chemical reaction.

After the reaction, the vessel will have a mass equal to the initial 245 g.

Carbohydrates require carbon as their primary component. There is carbon in every known carbohydrate. All carbohydrates also contain hydrogen and oxygen atoms, with the exception of a few simple sugars, which only contain carbon and hydrogen atoms.

Carbon, hydrogen, and oxygen atoms make up the macromolecules known as carbohydrates. They are a significant energy source. They can be found in fruits and vegetables as sugars, starches, and fibre. What categories do the carbs fit into? Starchy meals are complex carbohydrates because they include two or more sugar units. Compared to simple carbs, complex carbohydrates' molecules digest and transform more slowly. They are widely distributed in whole-grain bread, cereals, lentils, beans, peanuts, potatoes, peas, and corn. As one of the three primary macronutrients, carbohydrates are one of the three.

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For every 60 grammes of ethane, 108 grammes of water are produced. We therefore obtain 10.8 g of water from the combustion of 6 g of ethane. As a result, is created in 0.6 moles.

The mole fraction of the solvent must be multiplied by the partial pressure of the solvent in order to determine an ideal solution's vapour pressure. The vapour pressure would be 2.7 mmHg, for example, if the mole fraction is 0.3 and the partial pressure is 9 mmHg.

One mol of the solute is contained in one thousand grammes of the solvent (water) in a one molal solution. It follows that the solution's vapour pressure is 12.08 kPa.

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Answer:

Sulfur

Explanation:

Sulfur would be expected the be the least reactive as it has the least Electronegativity than the other non-metals on that list.

Answer:

number C

Explanation:

An electric motor works by converting electrical energy to mechanical energy in order to create motion.

For example,Force is generated within the motor through the interaction between a magnetic field and winding alternating (AC) or direct (DC) current.

This works because…

Answer : When an electric current flows through the wire in the electromagnet, a magnetic field is produced in the coil.

\(\:\mathsf{Hope\:this\:helps\:you!}\)

Answer:

when an electric current flows through the wire in the electromagnet , a magnetic field is produced in the coil .

Explanation:

Dissolved oxygen levels are 20% less concentration than fresh water.

Dead sea is also known as salt lake. It is  locked between Israel and Jordan in the south western Asia. Its western shore belongs to israel and eastern shore belongs to Jordan. It is the lowest body of the water on the surface of the earth.The lake was 1300 feet on the earth surface in mid 20th century. and in the mid of 2010  its level has reached about 430 meter below the sea level . Dead sea receives water from Jordan river so it has no tides in it.it flows from north in to the lake.The water in the dead sea is is extremely saline water.no life can sustain in this water.only bacteria can sustain in salt lake. Dissolved oxygen is the level of free oxygen present in the water .the levels of too high or too cold can harm the aquatic and affect water quality.

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Complete the table to show the fraction of a radioisotope left after each half-life has passed:

Number of half-lives 0 1 2 3 4 5 6

Fraction remaining 1 1/2 1/4 1/8 1/16 1/32 1/64

Use the table above to help you answer the questions below:

a) After 5 half-lives, the fraction remaining is 1/32 or 0.03125. To find the percentage remaining, multiply by 100:

0.03125 x 100 = 3.125%

Therefore, after 5 half-lives, 3.125% of the sample will remain.

b) After 4 half-lives, the fraction remaining is 1/16 or 0.0625.

c) To find out how many half-lives it will take for 25% of a sample to remain, you can set up an equation:

\((1/2)^{(n)} = 0.25\)

where n is the number of half-lives.

Taking the logarithm of both sides gives:

n x log(1/2) = log(0.25)

n = log(0.25) / log(1/2)

n = 2.

Therefore, it will take 2 half-lives for 25% of the sample to remain.

d) After 3 half-lives, the fraction remaining is 1/8 or 0.125. To find the percentage remaining, multiply by 100:

0.125 x 100 = 12.5%

Therefore, after 3 half-lives, 12.5% of the sample will remain.

e) The fraction remaining after 8 half-lives is \((1/2)^8\), which simplifies to 1/256.

The half-life of iodine-131 is 10 days.

After 30 days, three half-lives have passed:

\((1/2)^3 = 1/8\)

Therefore, after 30 days, 1/8 or 0.125 of the original mass will remain:

0.125 x 15g = 1.875g

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Answer:

When fuels are burned in vehicle engines, high temperatures are reached. At these high temperatures, nitrogen and oxygen from the air combine to produce nitrogen monoxide. When this nitrogen monoxide is released from vehicle exhaust systems, it combines with oxygen in the air to form nitrogen dioxide.

Explanation:

Explanation:

Nitrogen and oxygen from the air combine at high temperatures in the engine to produce nitrogen (II) oxide by the reaction :

N2(g) + O2(g) → 2NO(g).

Nitric oxides rise in the atmosphere and are oxidized to nitrogen dioxide, NO2 which dissolves in the precipitating water to form acid rain.