Answer:
-4.6875 m/s
Explanation:
Mass of man; m_m = 100 kg
Mass of earth; m_e = 6.4 × 10 kg = 64 kg
Speed of man; v_m = 3 m/s
Since we are told that momentum is conserved, it means that momentum of the man will be equal and opposite to momentum of the Earth.
Thus;
m_m × v_m = -m_e × v_e
100 × 3 = -64 × v_e
v_e = 300/-64
v_e = -4.6875 m/s
Which property describes the rate at which waves pass by?
O A. Wavelength
B. Speed
O c. Period
C.
O D. Frequency
Option D is correct. Frequency is the property describes the rate at which waves pass by.
What is wave frequency?Wave frequency is the number of waves that travel through a specified location in a given amount of time.
The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.
Frequency is the property describes the rate at which waves pass by.
Hence,frequency is the right answer.
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Which of the following actions will increase the current induced in a wire by a
magnetic field?
Answer:
The induced current can be increased in the coil in the following ways: By increasing the strength of the magnet. By increasing the speed of the magnet through the coil.
Explanation:
Can u tell me the answer for both first and if I have different answers can I ask u why?
We are given that a train brakes with a force of 1.64x10^6N. To determine its final speed after 31 seconds we need first to determine its acceleration. To do that we will use Newton's second law:
\(F=ma\)Where:
\(\begin{gathered} F=\text{ force} \\ m=\text{ mass} \\ a=\text{ acceleration} \end{gathered}\)Now we solve for the acceleration by dividing both sides by "m":
\(\frac{F}{m}=a\)Now we substitute the given values:
\(\frac{1.64\times10^6N}{4.94\times10^6kg}=a\)Solving the operations we get:
\(0.33\frac{m}{s^2}=a\)Now we use the following equation of motion to determine the final speed:
\(v_f=v_0+at\)Where:
\(\begin{gathered} v_f=\text{ final sp}eed \\ v_0=\text{ initial spe}ed \\ a=\text{ acceleration} \\ t=\text{ time} \end{gathered}\)Now we substitute the values:
\(v_f=56.1\frac{\operatorname{km}}{h}-(0.33\frac{m}{s^2})(31s)\)We need to convert the km/h into m/s. To do that we will use the following conversion factors:
\(\begin{gathered} 1\operatorname{km}=1000m \\ 1h=3600s \end{gathered}\)Now we multiply the initial velocity by the conversion factors:
\(56.1\frac{\operatorname{km}}{h}\times\frac{1000m}{1\operatorname{km}}\times\frac{1h}{3600s}=15.58\frac{m}{s}\)Now we substitute the value:
\(v_f=15.58\frac{m}{s}-(0.33\frac{m}{s^2})(31s)\)Solving the operations we get:
\(v_f=5.35\frac{m}{s}\)Therefore, the final velocity is 5.35 meters per second.
Now we are asked to determine the distance traveled by the train. To do that we will use the following equation of motion:
\(2ad=v^2_f-v^2_0\)Where:
\(d=\text{ distance}\)Now we solve for the distance by dividing both sides by "2d":
\(d=\frac{v^2_f-v^2_0}{2a}\)Now we substitute the values:
\(d=\frac{(5.35\frac{m}{s})^2-(15.58\frac{m}{s})^2}{2(-0.33\frac{m}{s^2})}\)Solving the operations:
\(d=324.42m\)Therefore, the distance is 324.42 meters.
Hello! How do you answer a question? I will give you 25 points if you answer it. :)
Answer:
press add answer and it will let you answer the question
Explanation:
Answer:
you click on the question, then you click answer, then type what you want, and click the green button on the top right saying dd your answer
Explanation:
give the relationship between current, Resistance and potential difference
Explanation:
Current can be defined as the rate of flow of electric charge along a conductor.
Resistance can be defined as the opposition to the flow of charged electrons or current, it's unit is OhmQuestion 4 You are required to explain the terms lines of flow and stream lines when applied to fluid flow and deduced the relationship between them in laminar flow.
In fluid dynamics, the terms "lines of flow" and "streamlines" are used to describe the path followed by individual fluid particles as they move within a flow. While both terms are closely related, they have slightly different meanings.
Lines of flow refer to the imaginary lines that are drawn in a fluid flow field to represent the direction in which the fluid particles move. These lines can be fluid dynamics,as the path that a fluid particle would trace out over time. Lines of flow can provide information about the overall flow pattern and direction in a fluid system.
On the other hand, streamlines are the actual curves or lines that are tangent to the velocity vector at every point in the flow field.
These streamlines are defined as the locus of points through which a fluid particle passes at a given instant. Streamlines are a mathematical representation of the flow pattern and can be determined through computational fluid dynamics (CFD) or experimental methods.
In laminar flow, where the fluid flows smoothly in layers with minimal turbulence, the lines of flow and streamlines coincide with each other. This means that the lines of flow and streamlines are identical, and fluid particles move along these lines without crossing each other.
The streamlines do not intersect or cross paths in laminar flow, indicating that the flow is well-ordered and predictable.
In summary, lines of flow and streamlines both describe the path followed by fluid particles in a flow field, with the key difference being that lines of flow are conceptually drawn paths, while streamlines are the actual curves tangent to the velocity vector at each point. In laminar flow, the lines of flow and streamlines coincide, reflecting the organized and smooth nature of the flow.
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Which idea would most likely be dangerous for a student to think while entering a lab?
“I can figure out how to use the tools as I go along.”
“I need to stay calm even if an accident happens.”
“I should think like a scientist during the lab.”
“I will ask for help without worrying about my grade.”
What is evidence used by Galileo to disprove Aristotle and Ptolemy?
Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe.
Galileo Galilei played a crucial role in challenging the prevailing geocentric model of the universe proposed by Aristotle and supported by Ptolemy. He provided several lines of evidence that effectively disproved their theories and supported the heliocentric model proposed by Nicolaus Copernicus. Some of the key evidence used by Galileo includes:
1. Observations through a telescope: Galileo was one of the first astronomers to use a telescope to observe the heavens. His telescopic observations revealed several important discoveries that contradicted the Aristotelian-Ptolemaic worldview. He observed the phases of Venus, which demonstrated that Venus orbits the Sun and not Earth. He also observed the four largest moons of Jupiter, now known as the Galilean moons, which provided evidence for celestial bodies orbiting a planet other than Earth.
2. Sunspots: Galileo's observations of sunspots provided evidence that the Sun is not a perfect celestial body, as suggested by Aristotle. Sunspots indicated that the Sun has imperfections and undergoes changes, challenging the notion of celestial perfection.
3. Mountains on the Moon: Galileo observed the rugged and uneven surface of the Moon, which contradicted Aristotle's belief in celestial spheres made of perfect, unchanging material. The presence of mountains on the Moon suggested that celestial bodies are subject to the same physical laws as Earth.
4. Phases of Venus: Galileo's observations of the phases of Venus provided direct evidence for the heliocentric model. As Venus orbits the Sun, it goes through phases similar to the Moon, ranging from crescent to full. This observation strongly supported the idea that Venus revolves around the Sun.
These lines of evidence presented by Galileo challenged the Aristotelian-Ptolemaic model, providing support for the heliocentric model and paving the way for a new understanding of the universe. His work marked a significant turning point in the history of science and laid the foundation for modern astronomy.
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A rock falls off a cliff. How fast will it be going after falling for 4.33 seconds?
Answer:42.43m/s
Explanation:According to vf=vi+at, we can calculate it since v0 equals to 0. vf=0+9.8m/s^2*4.33s= 42.434m/s
A child is playing in a park on a rotating cylinder of radius, r , is set in rotation at an angular speed of w. The Base of the cylinder is slowly moved away, leasing the child suspended against the wall in a vertical position.
What Is the minimum coefficient of friction between the child's clothing and wall is needed to prevent it from falling .
Answer:
\(\mathbf{\mu_s = \dfrac{g}{\omega^2r}}\)
Explanation:
From the given information:
The force applied to the child should be at equilibrium in order to maintain him vertically hung on the wall.
Also, the frictional force acting on the child against gravitational pull is:
\(F_f = \mu _sN\)
where,
the centripetal force \(F_c\) acting outward on the child is equal to the normal force.
\(F_c= N\)
SO,
\(F_f = \mu_s F_c\)
Since the centripetal force \(F_c = \dfrac{mv^2}{r}\)
Then:
\(F_f = \dfrac{ \mu_s \times mv^2}{r}\)
Using Newton's law, the frictional force must be equal to the weight
\(F_f = W\)
\(\dfrac{ \mu_s \times mv^2}{r} = mg\)
\(\dfrac{ \mu_s v^2}{r} = g\)
Recall that:
The angular speed \(\omega = \dfrac{v}{r}\)
Therefore;
\(g = \mu_s \omega^2 r\)
Making the coefficient of friction \(\mu_s\) the subject of the formula:
\(\mathbf{\mu_s = \dfrac{g}{\omega^2r}}\)
Can I get help on this question please
it would be the 3rd one. so C
question 1+1677-789909
Answer:
your answer is -788231
Explanation:
1+1677=1678
1678-789909=-788231
A flat plate with surface area of 1.8 m2m2 is sliding on a horizontal table with 3.7 mmmm thick oil layer on top. Force applied on the plate in the direction of movement is 2.2 NN. Dynamic viscosity of the oil is 0.89 x10-³ Ns/m².
The velocity gradient across the 3.7 mm thick oil layer on the flat plate sliding on the horizontal table is 0.594 m/s/m.
Given:
Surface area of the plate (A) = 1.8 m^2
Thickness of the oil layer (h) = 3.7 mm = 0.0037 m
Force applied on the plate (F) = 2.2 N
Dynamic viscosity of the oil (η) = 0.89 x 10^-3 Ns/m^2
To calculate the velocity gradient across the oil layer, we can use the equation:
τ = η * du/dy
where τ is the shear stress, η is the dynamic viscosity, and du/dy is the velocity gradient.
Since the force (F) applied on the plate is responsible for the shear stress, we can write:
τ = F / A
Substituting the given values, we have:
F / A = η * du/dy
Solving for du/dy, we get:
du/dy = (F / A) / η
Substituting the values, we have:
du/dy = (2.2 N) / (1.8 m^2 * 0.89 x 10^-3 Ns/m^2)
du/dy = 0.594 m/s/m
Therefore, the velocity gradient across the oil layer is 0.594 m/s/m.
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817 cm3 at 80.8 kPa to 101.3 kPa
The volume of the gas at 101.3 kPa would be approximately 651.25 cm³.
To calculate the change in volume of a gas from an initial pressure to a final pressure, we can use Boyle's law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's law can be expressed as:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure (80.8 kPa)
V1 = Initial volume (817 cm³)
P2 = Final pressure (101.3 kPa)
V2 = Final volume (to be calculated)
Let's plug in the values into the equation and solve for V2:
80.8 kPa * 817 cm³ = 101.3 kPa * V2
V2 = (80.8 kPa * 817 cm³) / 101.3 kPa
V2 ≈ 651.25 cm³
Therefore, the volume of the gas at 101.3 kPa would be approximately 651.25 cm³.
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A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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A boy throws an arrow at an original velocity of 2m / s, aiming to create an angle 0, referring to the balloon at a distance of 3m from the point of departure. Calculate the angle 0 and the height of the arrow.
Answer:
s=0.204m
Explanation:
Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:
tan(0) = opposite/adjacent = height/distance
where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.
Rearranging the formula, we get:
0 = arctan(height/distance)
0 = arctan(height/3)
Taking the tangent of both sides, we get:
tan(0) = tan(arctan(height/3))
tan(0) = height/3
Now, we need to find the height of the arrow. Using the kinematic equation:
v^2 = u^2 + 2as
where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.
At maximum height, the final velocity is 0m/s. Therefore, we have:
0 = (2m/s)^2 + 2(-9.8m/s^2)s
Solving for s, we get:
s = 0.204m
Therefore, the height of the arrow is approximately 0.204m.
a glass beaker has a mass of 50g. a liquid of density 1.8g/cm3 is poured into the beaker until it reaches the 200cm3 mark. calculate the total mass of the beaker and its contents
Answer:
total mass = 410 g
Explanation:
density = 1.8 g/cm³
volume = 200 cm³
density = mass / volume
mass (of liquid) = density x volume
= 1.8 x 200
= 360 g
total mass (beaker + liquid) = 50 + 360 = 410 g [Ans]
Hope this helps!
The force that holds planets, stars, and other heavenly bodies in space is called _____.
inertia
universal force
gravity
cosmic force
Answer:
Gravity
Explanation:
The two plates of a capacitor hold +2.5 x 10-3 C and
-2.5 x 10-3 C of charge when the potential difference is
950 V. What is the capacitance?
Answer:
2.63 microfarads
Explanation:
C = Q/V = 2.5 x 10^-3 C / 950 V = 2.63 microfarads
7. A student pushed a box 25.0 meters across a smooth, horizontal floor using a constant force of 112 Newtons. If the force was applied for 7.00 seconds, how much power was developed?
The power developed was 1,568 Watts, the calculation is seen in the section below.
Computation of PowerIn science and engineering, power is the rate at which work is done or energy is delivered. It can be expressed as the product of the work done (W) or the energy transferred (E) divided by the time interval (t).
Given data
Distance = 25.0 metersApplied Force = 112 NewtonsTime = 7.00 seconds,We know that expression for Power is given as
Power = (Force x Distance) / Time
Substituting our data into the expression we have
Power = (112 N x 25.0 m) / 7.00 s
Power = 1,568 Watts.
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A vehicle, starting from rest, accelerates on a circular track with a 335m diameter.
The distance travelled by the vehicle around the circular track is 1,052.4 m.
What is the distance travelled by the vehicle in one complete cycle?
The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.
d = 2πr
d = πd
Where;
r is the radius of the circular trackd is the diameter of the circular trackIn one complete cycle, the vehicle will travel the circular track only once.
d = π(335 m)
d = 1,052.4 m
Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.
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The complete question is below:
A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?
Which observation is evidence that electromagnetic radiation (EMR) has particle-like
properties? (1 point)
O EMR refracts as it moves into a different medium.
O
A diffraction pattern is observed when EMR passes through a narrow slit.
O Some EMR is blocked when it passes through a polarized lens.
O EMR with energy above a certain value can eject electrons out of a metal.
The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
Electromagnetic radiations as particlesThe observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.
This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.
It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.
This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.
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According to the principal of superposition,
Answer:
the resultant wave is the algebraic sum of all the waves reaching that particular point at a given time.
Explanation:
imagine two or three waves reaching a particular particle x at the same time. The particle will vibrate those waves and give out or transmit a resultant wave which is the algebraic sum of the incoming two waves. If both the waves have the same amplitude and phase, the resultant wave will be amplified. However if the waves have the same amplitude and equal but opposite phase then the resultant wave will be a straight line
A 75.0 kg man pushes on a 500,000 kg wall for 250 s but it does not move.
a. How much work does he do on the wall? ____________
b. How much energy is used?__________
c. How much power is exerted?____________
Since no work is done, the power exerted is zero. Therefore, the man exerts no power on the wall.
What is force?In physics, force is defined as any action that can change the motion of an object or cause an object to accelerate. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction. The unit of force in the International System of Units (SI) is the Newton (N), which is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg × 1 m/s^2). Force can be measured using a variety of instruments, such as spring scales, strain gauges, or force plates. Some common types of forces include gravitational force, electromagnetic force, frictional force, and normal force. The study of forces and their effects on the motion of objects is known as mechanics and is a fundamental concept in physics.
Here,
a. The man does not do any work on the wall because the wall does not move. Work is only done when there is a displacement in the direction of the force applied.
b. Since no work is done, no energy is used or transferred.
c. The power exerted by the man can be calculated using the formula:
Power = Work / Time
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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 4.6 m/s. (a) In a stiff-legged landing he comes to a halt in 2.1 ms. Find the average net force that acts on him during this time. N (b) When he bends his knees, he comes to a halt in 0.09 s. Find the average force now. N (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of these forces, find the force of the ground on the man in parts (a) and (b). stiff legged landing N bent legged landing
Answer:
a) 1.725*10^5 N
b) 3.83*10^3 N
c) i) 173.24 kN
c) ii) 4.57 kN
Explanation:
See the attachment for calculations
Calculate the speed of an ancient ship that registers a distance of 3482m in 1 h
Hello..! :)
The speed of the ancient ship is 3482 meters per hour or 96.72 centimeters per second.
Explanation:
Data:
D = 3482mT = 1hV = ?Formula:
V = D/TDeveloping:
V = 3482m/1hV = 3482 m/hNow, we convert to see what its speed is in cm/s.
Conversion:
3482m/h (1m/100cm) (1h/3600s)V = 96.72 cm/s
¿Doubts? On the comments. Greetings :D
Answer:
Thanks For the points
It is or 96.72 cm/s
1. What were enron failure issue ? What were corporate Governance isues in Enron.
The Enron scandal drew attention to accounting and corporate fraud as its shareholders lost $74 billion in the four years leading up to its bankruptcy, and its employees lost billions in pension benefits.
What were Enron failure issue ?Enron's Board of Directors failed to fulfil its fiduciary duties towards the corporation's shareholders. Secondly, the top executives of Enron were greedy and acted in their own self-interest.
Enron's downfall was attributed to its reckless use of derivatives and special purpose entities. By hedging its risks with special purpose entities which it owned, Enron retained the risks associated with the transactions. This arrangement had Enron implementing hedges with itself.
Enron raised fundamental issues about corporate fraud, accounting transparency, and investor protection.
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in a vacuum a scientist drops both a hammer and a feather from the same height compare the speed from the objects as they fall
Describe the setup of the electromagnet. Why does the wire need to be a conductive material?
An electromagnet consists of a conductive wire wrapped around a magnetic core, creating a magnetic field when an electrical current is passed through it.
An electromagnet is a type of magnet that is created by running an electrical current through a wire. The setup of an electromagnet involves a few basic components. First, there must be a wire that is conductive, meaning that it can conduct electricity. This wire is usually wrapped around a core, which is often made of iron, steel, or another magnetic material. When an electrical current is run through the wire, it creates a magnetic field around the wire. This magnetic field then magnetizes the core, creating an even stronger magnetic field. The strength of the electromagnet can be controlled by adjusting the amount of current that is run through the wire. The wire must be a conductive material because it needs to be able to carry the electrical current that creates the magnetic field. If the wire were not conductive, then the electrical current would not be able to flow through it, and the magnetic field would not be created. In summary, the setup of an electromagnet involves a conductive wire wrapped around a magnetic core, which is magnetized by the electrical current running through the wire. The wire must be conductive to carry the electrical current and create the magnetic field.For more questions on electromagnet
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Most people can throw a baseball farther than a bowling ball, and most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball. Explain these two situations in terms of
Newton’s First Law of Motion
Newton’s Second Law of Motion
Based on Newton's first and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
What is Newton's first law of motion?
Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.
Newton's first law of motion is also called law of inertia because it depends on mass of the object.
An object with a greater mass will require greater force to be stopped or get moving.
Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.
Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.
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