A mass of 15 X 10^5 kg is held at a position 9 m away from a mass of 20 X 10^6 kg. What is the gravitational attraction between the two masses?

The moment of inertia of the object as a multiple of MR² is 0.126 MR².

According to the law of conservation of energy he is always conserved at each and every point so going by this,

At the top will be equal to the energy at the bottom.

Because at the top there will be no kinetic energy and add the bottom there will be no potential energy the bottom there will be only kinetic energy and rolling energy.

So we can write,

Mgh = 1/2IW² +1/2MV²

Where,

M is the mass of the body,

G is acceleration due to gravity,

H is the height,

I is the moment of inertia,

W is angular velocity,

V is the linear velocity.

The height of the object is given to be 2.11 m. Final velocity is given to be 5.8m/s.

Now, putting all the values,

M(2.11)(9.8) = 1/2(IV²/R²) + 1/2MV²

I = 0.126MR²

Hence the moment of inertia of the object is 0.126MR².

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Complete question- an object rolls without slipping down a 2.1 m high incline.

What is the moment of inertia of the object starting from rest if it has a final velocity of 5.8m/s stress the moment of inertia as a multiple of MR² object and R is its radius.

Answer:

Explanation:

A change in an object’s motion—such as Xander speeding up on his scooter—is called acceleration. Acceleration occurs whenever an object is acted upon by an unbalanced force. The greater the net force acting on the object, the greater its acceleration will be, but the mass of the object also affects its acceleration. The smaller its mass is, the greater its acceleration for a given amount of force. Newton’s second law of motion summarizes these relationships. According to this law, the acceleration of an object equals the net force acting on it divided by its mass.

The cable must withstand a tension of approximately 0.0005275 MN to accelerate the 1055 kg car vertically upward at 0.50 m/s².

To accelerate the car vertically upward at 0.50 m/s², we need to counteract the force of gravity acting on the car, which is given by its weight.

The weight of the car can be calculated using the formula:

Weight = mass x gravity

where mass is given as 1055 kg and gravity is approximately 9.81 m/s².

Weight = 1055 kg x 9.81 m/s²

Weight = 10347.55 N

To accelerate the car upward, we need to apply a force equal to the weight of the car plus the force due to acceleration.

The total force required is given by:

Force = Weight + (mass x acceleration)

where mass is given as 1055 kg and acceleration is 0.50 m/s².

Force = 10347.55 N + (1055 kg x 0.50 m/s²)

Force = 10347.55 N + 527.5 N

Force = 10875.05 N

To calculate the tension in the cable, we need to consider the direction of the forces acting on the car. The cable will be pulling the car upward, while the weight of the car will be pulling it downward.

The tension in the cable can be calculated using the following formula:

Tension = Force - Weight

Tension = 10875.05 N - 10347.55 N

Tension = 527.5 N

Finally, we can convert this force to mega newtons by dividing by 1,000,000:

Tension = 527.5 N ÷ 1,000,000

Tension = 0.0005275 MN

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Answer:

P =

\( \frac{mc{q2 - q1}{t} \)

The final velocity of the wreckage after the collision is 56.67 m/s.

Mass of the first rail car, m₁ = 10⁴kg

Velocity of the first rail car, v₁ = 50 m/s

Mass of the second rail car, m₂ = 5 x 10³kg

Velocity of the second rail car, v₂ = 70 m/s

According to the law of conservation of momentum, the momentum of an isolated system will remain a constant in a domain.

So, the initial momentum before collision will be equal to the final momentum after the collision.

So,

m₁v₁ + m₂v₂ = (m₁ + m₂)v

Therefore, the final velocity of the wreckage after the collision is,

v = (m₁v₁ + m₂v₂)/(m₁ + m₂)

v = [(10⁴x 50) + (5 x 10³x 70)]/(10⁴+ 5 x 10³)

v = [(50 x 10⁴) + (35 x 10⁴)]/15 x 10³

v = 85 x 10⁴/15 x 10³

v = 56.67 m/s

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Answer:

The moon is being pulled to the earth by gravity, so the net force makes a circular pattern.

Explanation:

The force of gravity is a force that pulls objects toward the centre of the earth. The acceleration due to gravity of the moon is about 1.6 metre per second square which is comparatively smaller than the earth's 10metre per second. Therefore, the moon isn't completely pulled to the centre of the earth, but orbits around the earth

The size of the field needed to create resonance is

= \(2\pi fmp/q\)

= \(2\pi (12.0X10\)⁶)(\(1.67X10\)⁻²⁷kg)

= 0.787T.

What is Kinetic energy?

A particle or an item that is in motion has a sort of energy called kinetic energy. When work, which entails the transmission of energy, is done on an object by applying a net force, that object acquires kinetic energy.

Therefore, the Kinetic energy is given by

K = 1/2 mv²

  = 1/2m\((2\pi Rf)\)²

 = 1/2\((1.67X10\)⁻²⁷kg)4\(\pi\)²(0.530m)²(12.0X10⁶Hz)²

 = 1.33X10⁻12J

 = 8.34X10⁶eV.

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According to the solving  the statement is correct. The work done on the car as it speeds up to 5.0 m/s is 22,500 J.

The work performed by a force is the sum of the movement and the component of something like the applied pressure of the object in the displacement direction. Work is accomplished when we push a block with a certain amount of force, "F," which causes the body to move with a certain amount of acceleration. Work completed is represented by the formula W = F.

KEf = (1/2)mv²

= (1/2)(1800 kg)(5.0 m/s)²

= 22,500 J

The work done on the car is equal to the change in kinetic energy:

W = KEf - KEi

= 22,500 J - 0 J

= 22,500 J

Therefore, the statement is correct. The work done on the car as it speeds up to 5.0 m/s is 22,500 J.

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I understand the the question you are looking for is:

If a 1800 kg car starts at rest and speeds up to 5. 0 m/s then the work done is?

The maximum elastic potential energy stored in the spring is 0.02 J.

The maximum elastic potential energy stored in a spring is given by the formula E = 1/2 k\(x^{2}\) where k is the spring constant and x is the displacement of the spring from its equilibrium position1.

In this case, the spring constant k = 100 N/m and the displacement of the spring x = 0.02 m. Substituting these values in the formula we get:

E = 1/2 × 100 N/m × (0.02 m) ² E = 0.02 J

Therefore, the maximum elastic potential energy stored in the spring is 0.02 J.

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Answer:

R = -2500N

Explanation:

Use formula ΣF = Ma. We can split the Net Force into two parts: Fe - Ff  =  Ma.

Fe is the force developed by the engine: 4000N

Ff (R) is the air resistance projected on the vehicle. This is the value we're looking for.

Mass: 1000kg

Acceleration: 1.5m/s^2

Next, just plug in the values and solve.

▪4000N - Ff  =  (1000kg)(1.5m/s^2)

▪Ff = 1500N - 4000N

▪Ff = -2500N

R = -2500N.

The air resistance acting on the car is R = -2500N.

Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Answer:

D. Mitochondria

Explanation:

(a) For constructive interference the two waves will have higher amplitude of 10 cm.

(b) For destructive interference the two waves will have zero amplitude.

For constructive interference the two waves will have higher amplitude after constructive interference.

Resulting amplitude = 5 cm + 5cm = 10 cm

For destructive interference the two waves will have zero amplitude after destructive interference.

Resulting amplitude = 5 cm - 5cm = 0

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After cycling of the deicing boots, residual ice will decrease as the airspeed decreases or the temperature increases. Deicing boots work by inflating and deflating rapidly, which breaks the ice off the surface of the boots.

Sometimes residual ice can remain after cycling the boots. This residual ice can be reduced by increasing the airspeed or temperature. Increasing the airspeed causes more airflow over the surface of the wings, which helps to remove any residual ice. Similarly, increasing the temperature can help to melt any remaining ice.

It is important to note that residual ice should always be monitored carefully and the pilot should take appropriate actions to ensure that the aircraft remains safe. Ultimately, residual ice can be dangerous and should be minimized as much as possible to prevent any accidents or incidents from occurring.

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Answer:

  C. increase as the airspeed or temperature decreases.

Explanation:

You want to know the effect of temperature and airspeed on residual ice after the deicing boots on an aircraft wing have been cycled.

Ice can accumulate on airplane wings when temperature, humidity, and/or precipitation conditions are just right. An airplane can defend itself against this potentially dangerous condition by ...

After the deicing boot has been cycled, there may be residual ice. This residual ice may increase if the conditions conducive to ice formation remain. That is, it will ...

  increase as the airspeed or temperature decreases, choice C.

__

Additional comment

Of course, the best approach to icing is to avoid flying in conditions conducive to ice formation, or to pass through those conditions as quickly as possible.

Explanation:

The Acceleration of the object = 6.4 m/s²

Mass of block (m) = 5 kg

Action force on block, (F₁) = 40 N

Frictional force opposing the motion (F₂) = 8 N

Acceleration of the object (a) = ?

⇒ Net force = Action force on block - Opposing friction force

⇒ F = F₁ - F₂

⇒ F = 40 - 8

⇒ F = 32 N

Net force of the block (F) = 32 N

Mass of block (m) = 5 kg

F is the Force in N.

m is the Mass in kg.

a is the Acceleration in m/s².

F = ma

⇛ a = F/m

⇛ a = 32/5

⇛ a = 6.4 m/s²

Answer:

He should report his findings to a reputable science journal.

When the plane flies from the initial position to the final position, the given parameter show's the average velocity of the plane.

Average velocity of an object is defined as the change in position or displacement of the object with the given time period in which it is in motion.

Mathematically, the average velocity of an object is given as;

v = Δx / Δt

where;

The average velocity of an object increases with increase in the displacement of the object for a short period of time.

For a plane that flies from the given initial position to the final position at a speed of 925 km/hr, the given average velocity can be converted into meter per seconds

v = 925 km/hr

In meters per second the average velocity is determined as ;

v = 925 km/hr/3.6  = 256.94 m/s

Thus, when the plane flies the given initial position to the final position at a speed of 925 km/hr. The information provided is showing the plane's average velocity.

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Answer:

2.4m/s

Explanation:

The vaulter has cleared a height of 6.00 m, and so their velocity at the landing area is 11.44 m/s.

The velocity of the pole vaulter striking the mat in the landing area is determined by the equation v = sqrt(2gh), where v is the velocity of the vaulter, g is the acceleration due to gravity (9.81 m/s2), and h is the height cleared by the vaulter. In this case, h = 6.00 m, so the velocity of the vaulter striking the mat is v = sqrt(2*9.81*6.00) = 11.44 m/s.

To better understand this equation, we need to consider Newton's Second Law of Motion, which states that F = ma, or force is equal to mass times acceleration. In pole vaulting, the vaulter's force is the force of gravity on the body, which is determined by the equation F = mg, where m is the mass of the vaulter and g is the acceleration due to gravity.
From Newton's Second Law, we can derive the equation for velocity: v = sqrt(2gh), where h is the height of the jump. This equation states that the velocity of the vaulter is proportional to the square root of the height they clear. In this case, the vaulter has cleared a height of 6.00 m, and so their velocity at the landing area is 11.44 m/s.

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Answer:

Explanation:

a. The direction of the force on the proton can be determined using the right-hand rule for magnetic fields. If the right hand is oriented such that the fingers point in the direction of the magnetic field (from north to south in this case) and the thumb points in the direction of the proton's velocity (to the right in this case), then the palm of the hand will point in the direction of the force on the proton. Using this rule, we can see that the force on the proton points downward, as shown in the diagram below:

     N

      |

 <----|---->

 |    |    |

 |    |    |

 |____|____|

      |

      S

b. The magnitude of the force on the proton can be calculated using the formula:

F = qvB

where F is the magnitude of the force, q is the charge of the particle, v is its velocity, and B is the magnetic field strength. For a proton, which has a charge of +1.6 x 10^-19 coulombs, the magnitude of the force is:

F = (1.6 x 10^-19 C)(5.6 x 10^3 m/s)(0.55 T) = 4.5 x 10^-14 N

Therefore, the magnitude of the force on the proton is 4.5 x 10^-14 N.

Answer:

The answer is

Explanation:

The mass of an object given it's momentum and velocity / speed can be found by using the formula

\(m = \frac{p}{v} \\ \)

where

m is the mass

p is the momentum

v is the speed or velocity

From the question

p = 280 kg/ms

v = 10 m/s

The mass of the object is

\(m = \frac{280}{10} = 28 \\ \)

We have the final answer as

Hope this helps you

Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

Half-life (t½) = 40 years

Final count rate (Cբ) = 25 count/min

Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

Number of half-lives (n) =?

Cբ = 1/2ⁿ × Cᵢ

25 = 1/2ⁿ × 400

Cross multiply

25 × 2ⁿ = 400

Divide both side by 25

2ⁿ = 400/25

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:

Half-life (t½) = 40 years

Number of half-lives (n) = 4

Time (t) =?

n = t / t½

4 = t / 40

Cross multiply

t = 4 × 40

t = 160 years.

Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.

When two surfaces touch, they exert a force that prevents the two surfaces from sliding past one another. Static friction is the name of this force.

The body's net force's strength and direction. All of the forces acting on a moving object are depicted in the free-bod diagram. Every force, in particular, is represented by an arrow, the direction of which corresponds to the force's direction and whose length corresponds to the force's magnitude. Therefore, the net force can be estimated from a free body diagram. In reality, one may calculate the net force acting in each of the two directions by examining the forces acting along the horizontal and vertical axes independently. These two forces then stand in for the constituent parts of the final force (net force) acting on the item.

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Answer:

Explanation:

The gravitational force acting on an object is called its weight. The weight of an object is equal to its mass multiplied by the acceleration due to gravity.

We know that the weight of the person on Ceres is 16.2 N and the mass of the person is 60 kg. So we can calculate the acceleration due to gravity on Ceres by dividing the weight by the mass:

Weight (N) = Mass (kg) x acceleration due to gravity (m/s^2)

16.2 N = 60 kg x g

g = 16.2 N / 60 kg

g = 0.27 m/s^2

Therefore, the acceleration due to gravity on Ceres is 0.27 m/s^2

It's important to note that Ceres is a dwarf planet and has a weaker gravitational pull than Earth, so the weight of a person on Ceres would be less than the weight of the same person on Earth.

The net force acting on the charge Q is in the direction D. The net force is the sum of forces from the two point charges Q+ each.

According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:

Fq =  k q1 q2 /r²

where, k is a constant.

As per this equation, the electrostatic force between two charges will increase as the magnitude of charge increases and the force decreases as the distance between them increases.

Here, the forces acting on the point charge Q- are the forces from the two Q+ charges. They are of different distances from the charges.  The force in the direction E will be greater here. The net force on -Q is acting in the direction D.

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Answer:

Net force = 10 N in downward direction

Explanation:

Given that,

Upward force = 10 N

Downward force = 20 N

Let downward is negative and upward is positive.

Net force = 10+(-20)

= -10 N

So, the net force is 20 N and it is acting in downward direction.

True. An object with no forces acting on it will continue to move with constant velocity. When there are no external forces acting on an object, its velocity does not change.

The object, on the other hand, maintains a steady motion with the same speed and direction. This is known as Newton's first law of motion, also known as the law of inertia. Newton's first law of motion states that an object at rest will remain at rest, and an object in motion will remain in motion at a steady velocity in a straight line until an external force acts upon it. This implies that if there is no net force acting on an object, it will remain stationary or continue to move at a constant velocity. Newton's first law of motion may be used to explain why drivers and passengers in a vehicle continue to move forward when the vehicle brakes abruptly, while objects in the car that aren't strapped down may go flying. According to Newton's first law of motion, an object in motion remains in motion at the same speed and in the same direction unless acted upon by an external force. Because the person's body is in motion, it will continue to move forward at the same speed as the car until an external force, such as the seatbelt or airbag, brings it to a stop.

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The vector's magnitude is 5.4m/s²and direction is 56.30°.

We will talk about vectors and scalars in this section. Quantities called vectors have both a magnitude and a direction. The indication of a vehicle's motion serves as a practical example of a vector.

Given,

ax = 3.0 m/s², ay = -4.5 m/s²

a = \(\sqrt{a^{2} _{x} + a^{2} _{y} }\)

a = \(\sqrt{3^{2} +-4.5^{2} }\)

a = \(\sqrt{9+20.25}\)

a = \(\sqrt{29.25}\)

a = 5.4m/s².

A vector's direction can be established by

α = tan⁻¹ y/x

α = tan⁻¹-4.5 / 3.0

α = tan⁻¹(1.5)

α = 56.30°.

The angle that the vector makes with the horizontal axis, or the X-axis, determines the vector's direction. By counterclockwise rotating the vector's angle at its tail toward the east, one can determine the vector's direction.

The vector's direction is therefore 23.375° away from the X-axis, i.e., the vector Ax = 26 m/s², Ay = 10 m/s² points in the direction of the North-East.

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Answer:

Nonmetals gain

while metals lose