A metalrod of length 40.0cm at 20°C is heated to a temperature of 45°C. If the new length is 40.05cm, Calculate its Linear expansivity.​

Answer:

I have no clue I'm just trying to get points

Explanation:

:) sorry

The best description of a well-designed testable question is "The question is clearly stated, the question can be tested in an experiment, and the results can be measured".

This type of question is the one that focuses on facts and aims at testing a hypothesis.

Some features include:

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Answer:

b

Explanation:

Answer:

the answer to this is letter b

Answer:

B) Technology helps scientists study things that are very small, far away, or hard to reach.

Answer:

B

Explanation:

water do not have a solid shape and that makes it take to shape of a container etc

Answer:

D. Requiring a lot of energy to change temperature

Explanation:

because im right n ur wrong

The gravitational force between two bodies is inversely proportional to the square of the distance between them.

So if the distance is divided by 4, the force is multiplied by 16.

The example of projectile is a basketball being shot by Steph Curry.

Projectile is any object propelled through space by the application of a force.

Projectile is used to describe any object that is cast, fired, flung, heaved, hurled, tossed, or thrown. For example, when a ball is thrown straight upward, or kicked.

In projectile motion, gravity is the only force acting on the object. This doesn’t necessarily mean that other forces do not act on it, just that their effect is minimal compared to gravity. The path followed by a projectile is known as a trajectory.

Other examples of projectile is as follows:

Therefore, it can be said that a basketball being shot by a renowned basket baller into the air is an example of projectile.

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Answer:

D Galileo Galilae

Explanation:

It's now understood that English astronomer Thomas Harriot, (1560-1621) made the first recorded observations of the Moon through a telescope, a month before Galileo

Answer: Galileo Galilae

Explanation:

The correct drills that can be used to practice digging in volleyball are b. shuffle steps and c. knock out drill.

b. Shuffle steps: Shuffle steps are an essential footwork drill for improving defensive movements, including digging.

In this drill, players shuffle laterally in a low defensive stance, simulating the movements required to dig a ball. It helps players develop quick and efficient footwork, enabling them to react and move quickly to reach the ball for a dig.

c. Knock out drill: The knock out drill focuses on improving a player's reaction time and defensive skills. In this drill, players form a line and take turns receiving rapid hits or "knocks" from a coach or teammate.

The objective is to successfully dig each hit and keep the ball in play.

This drill helps players develop their reflexes, positioning, and technique when digging in various directions and angles.

a. Double decker and 1. toss catch drill are not specific drills for practicing digging in volleyball. Double decker is a term used to describe a defensive formation, while the toss catch drill is more focused on developing ball control and setting skills rather than digging.

By incorporating shuffle steps and the knock out drill into practice sessions, players can enhance their digging abilities, improve their defensive movements, and develop the necessary skills to successfully retrieve hard-driven balls in a game situation.

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This question involves the concepts of the thin lens formula and focal length.

The image "56.25 cm" from the lens.

The focal length of the lens is the half of the radius of curvature.

\(f=\frac{R}{2}\)

where,

Therefore,

\(f=\frac{50\ cm}{2}\\\\f = 25\ cm\)

Now, according to the thin lens formula:

\(\frac{1}{f}=\frac{1}{p}+\frac{1}{q}\\\\\)

where,

Therefore.

\(\frac{1}{25\ cm}= \frac{1}{45\ cm}+\frac{1}{q}\\\\\frac{1}{q}= \frac{1}{25\ cm}-\frac{1}{45\ cm}\\\\\)

q = 56.25 cm

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The hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

This question involves vector addition, the resolution of vectors, the use of bearings, and trigonometry in the calculation of the hiker's movement.

This may appear to be a difficult problem, but with some visual aid and the proper use of mathematical formulas, the issue can be addressed correctly.

Resolution of VectorThe resolution of a vector is the process of dividing it into two or more components.

The angle between the resultant and the given vector is equal to the inverse tangent of the two rectangular components.

Angles will always be expressed in degrees in the solution.

The sine, cosine, and tangent functions in trigonometry are denoted by sin, cos, and tan.

The tangent function can be calculated using the sine and cosine functions as tan x = sin x/cos x. Also, in right-angled triangles, Pythagoras’ theorem is used to find the hypotenuse or one of the legs.

Distance Travelled North/SouthThe hiker traveled North for the first part of the hike and South for the second.

The angles that the hiker traveled in the first part and second parts are 53 degrees and 17 degrees, respectively.

The angle between the two is (180 - 53 - 17) = 110 degrees.

The angle between the resultant and the Northern direction is 110 - 53 = 57 degrees.

Using sine and cosine, we can calculate the north/south distance traveled to be 5 sin 57 = 4.02 km, and the east/west distance to be 5 cos 57 = 2.93 km.

Distance Travelled East/WestThe hiker walked East for the second part of the hike.

To calculate the distance travelled East/West, we must first calculate the component of the first part that was East/West.

The angle between the vector and the Eastern direction is 90 - 53 = 37 degrees.

Using sine and cosine, we can calculate that the distance travelled East/West for the first part of the hike is 5 cos 37 = 3.88 km.

To determine the net distance travelled East/West, we must combine this component with the distance travelled East/West in the second part of the hike.

The angle between the second vector and the Eastern direction is 17 degrees.

Using sine and cosine, we can calculate the distance traveled East/West to be 3 sin 17 = 0.86 km.

The net distance traveled East/West is 3.88 + 0.86 = 4.74 km.

Therefore, the hiker travelled 4.02 km North/South and 4.74 km East/West during her hike.

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Explanation:

density, mass of a unit volume of a material substance. The formula for density is d = M/V, where d is density, M is mass, and V is volume. Density is commonly expressed in units of grams per cubic centimetre.

The relative density of a substance is defined as the ratio of the density of that substance to the density of water at 4oC. It is also defined as the ratio of the mass of substance to the mass of equal volume of water at 4oC. i.e., R.D. = Mass of the substance / mass of an equal volume of water at 4oC

The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as

P=16.6pascal, Option D is correct

Generally, the equation for the Pressure   is mathematically given as

P=force/Area

Therefore, In considering the one with the most pressure we look at the one with the most force/Area

In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides

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The momentum of the zombie is 535.3 kg m/s.

Momentum is a fundamental concept in physics that describes the amount of motion that an object has. It is defined as the product of an object's mass and its velocity.

Here,

The momentum (p) of an object is defined as the product of its mass (m) and velocity (v)

p = m * v

In this case, the mass of the zombie is 101 kg and its velocity is 5.3 m/s. So, the momentum of the zombie can be calculated as:

p = 101 kg * 5.3 m/s

p = 535.3 kg m/s

Therefore, the momentum of the zombie is 535.3 kg m/s.

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Answer:

ω = θ / t

1 rev = 2 pi rad

t = 60 sec / min * 60 min / hr = 3600 sec / hr

v = ω R         tangential speed

v = (2 pi m / hr) / (3600 sec / hr) = .00175 m/sec

As a check

s = 2 pi * 1 m = 6.28 meters around dial

It takes 3600 sec for 1 rotation of the minute hand

v = 6.28 / 3600 = .0017 m/s

Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.

It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.

This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.

For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.

Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.

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The magnitude of the applied force is 3369.57 N.

Force can be defined as the product of mass and acceleration.

To calculate the magnitude of the applied force, we use the formula below.

Formula:

Where:

Make F the subject of the equation

From the question.

Given:

Substitute these values into equation 2

Hence, the magnitude of the applied force is 3369.57 N.

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Hello..! :)

The speed of the ancient ship is 3482 meters per hour or 96.72 centimeters per second.

Explanation:

Data:

Formula:

Developing:

Now, we convert to see what its speed is in cm/s.

Conversion:

V = 96.72 cm/s

¿Doubts? On the comments. Greetings :D

Answer:

Thanks For the points

It is or 96.72 cm/s

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Answer:

L = L0 (1 - v^2/c^2)     where L0 is proper length and L the measured length

L = 1.2 (1 - .87^2)^1/2 m = .59 m

We are given two points on the distance-time graph: (1, 40) and (3,130)

This means that:

At time 1 hour, the distance traveled was 40 km

At time 3 hours, the distance traveled was 130 km

We want to find the average speed during this 2 hour interval (from 1 hour to 3 hours).

Average speed is defined as:

Average Speed = Change in Distance / Change in Time

The change in distance is the distance traveled from 1 hour to 3 hours, which is 130 km - 40 km = 90 km

The change in time is 3 hours - 1 hour = 2 hours

Average Speed = 90 km / 2 hours

= 45 km/hr

Therefore, the average speed during this interval of time is 45 km/hr.

Answer:

The correct answer to the question will be compass i.e compass is not a part of a DC motor. Various parts of a DC motor are coil of wire, armature, field magnets, brushes and commutator. The coil of wire plays a vital role in DC motor.

Explanation:

Answer:

5 .07 s .

Explanation:

The child will move on a circle of radius r

r = 1.5 m

Let the velocity of rotation = v

radial acceleration = v² / r

v² / r = 2.3

v² = 2.3 r = 2.3 x 1.5

= 3.45

v = 1.857 m /s

Time of revolution = 2π r / v

= 2 x 3.14 x 1.5 / 1.857

= 5 .07 s .

The merry-go round will take 5.07 s to complete one complete revolution.

Given data:

The distance of child from the center is, r = 1.5 m.

The magnitude of radial acceleration is, \(a = 2.3 \;\rm m/s^{2}\).

Since, the child is on merry-go round, which is undergoing a rotational motion. And radial acceleration means that it is under the acceleration, whose value is given as,

\(a=\dfrac{v^{2}}{r}\\\\v=\sqrt{a \times r}\)

Here, v is the linear velocity.

Solving as,

\(v=\sqrt{2.3 \times 1.5} \\\\v=1.857 \;\rm m/s\)

Now, we to obtain the time taken by merry-go round to complete one revolution. Then the expression for the time taken to complete one revolution is,

\(T=\dfrac{2 \pi r}{v}\\\\T=\dfrac{2 \pi \times 1.5}{1.857}\\\\T = 5.07 \;\rm s\)

Thus, we can conclude that the merry-go round will take 5.07 s to complete one revolution.

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Answer:

Centripetal acceleration = 3.125 m/s²

Explanation:

Given the following data;

Radius, r = 50 m

Velocity, V = 12.5 m/s

To find the centripetal acceleration;

Centripetal acceleration = Velocity²/radius

Centripetal acceleration = 12.5²/50

Centripetal acceleration = 156.25/50

Centripetal acceleration = 3.125 m/s²

Therefore, the centripetal acceleration of the greyhound running on a circular track is 3.125 meters per seconds square.

Answer:

12g/cm³

Explanation:

Given parameters:

Mass of the metal  = 1200g

Volume of water in the measuring cylinder  = 150cm³

Volume of the metal  = 100cm³

Unknown:

Density of the metal  = ?

Solution:

Density is the mass per unit volume of a substance;

  Density  = \(\frac{mass}{volume}\)

Now insert the parameters and solve;

    Density  = \(\frac{1200}{100}\)   = 12g/cm³

Answer:

W = 6000 Joule

Explanation:

Work is defined as force times distance

W = F * d

We know that F = 15N, we just need the distance (d)

Imagine you have a square lawn with length of 10 m and width of 20m. So, we want to know the the distance you have to travel to cover every square meter of the lawn.

The width of the mower is only 50 cm = 0.5 m.

This means that you have to go back and forth 40 times to cover 20m (lawn width), with a distance of 10 m (lawn length). So,

d = 10 (meter) * 40 (times) = 400 meter

Therefore:

W = (15) * (400) = 6000 J

The cat travels with an average speed to the right of 0.179 m/s.

Simply add up the squares of the other two coordinates to determine the distance between any point and an axis, and then square root the result. We square the y- and z-coordinates, discover their sum, and then square root our result to determine the distance from the x-axis.

The total time elapsed is the sum of the time to run from A to B and the time to run from B to C, which is:

total time = 20.0 s + 8.00 s = 28.0 s

The average velocity is defined as the displacement divided by the elapsed time, so we have:

average velocity = displacement / elapsed time

average velocity = 5.00 m / 28.0 s

average velocity = 0.179 m/s.

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Answer:

The solution of the given problem is provided in the following subsection.

Explanation:

According to the question,

The change in the height of the glacier will be:

= \(1780-2010\)

= \(-230\)

Change in time,

= 5 years

Now,

The rate of change will be:

= \(\frac{m}{years}\)           ∵ (1 year = 12 months)

= \(\frac{230}{5}\)

= \(-46 \ m/years\)

or,

The rate of change will be:

= \(\frac{m}{months}\)         ∵ (5 years in months = 5×12 months)

= \(\frac{-230}{5\times 12}\)

= \(\frac{-230}{60}\)

= \(=3.83 \ m/months\)

Answer:

B. Atomic number minus mass number

Explanation: