A meteor is falling towards the earth. The mass and the radius of the earth is 6×10^24 kg and 6.4×10^3 km respectively. What is the height of the meteor from the earth surface at which the acceleration due to gravity is 4m/s^2

Answer:

In terms of the light spectrum, blue is a primary color, which means that it is one of the base colors that exist in the universe and it cannot be created by combining different colors together. The primary pigment colors are cyan, magenta, and yellow. Cyan absorbs red, yellow absorbs blue, and magenta absorbs green.

Explanation:

Hope this helped Mark BRAINLEST!!!

The minimum uncertainty in the position of an electron, given a velocity of 68 m/s and an uncertainty in velocity of 1%, is approximately 2.45 x \(10^-^9\)meters.

According to the Heisenberg uncertainty principle, there is an inherent trade-off between the uncertainty in an object's position and its momentum. The product of the uncertainties in position (Δx) and momentum (Δp) must be greater than or equal to Planck's constant divided by 4π (h/4π).

Given:

Velocity of the electron (v) = 68 m/s

Uncertainty in velocity = 1% of v = 0.01 * 68 m/s = 0.68 m/s

Since momentum (p) is given by mass (m) multiplied by velocity (v), we can write:

p = m * v

Uncertainty in momentum (Δp) can be calculated using the uncertainty in velocity:

Δp = m * Δv

According to the Heisenberg uncertainty principle:

Δx * Δp ≥ h/4π

To find the minimum uncertainty in position (Δx), we need to determine the uncertainty in momentum (Δp) and solve for Δx.

Δp = m * Δv

Δp = m * 0.68 m/s

Substituting this into the uncertainty principle equation:

Δx * (m * 0.68 m/s) ≥ h/4π

We can rearrange the equation to solve for Δx:

Δx ≥ h / (4π * (m * 0.68 m/s))

Now, we need to substitute the values of Planck's constant (h) and the mass of an electron (m) into the equation. The mass of an electron is approximately 9.11 x \(10^-^3^1\)kg, and Planck's constant is approximately 6.63 x \(10^-^3^4\) J·s.

Δx ≥ (6.63 x\(10^-^3^4\)J·s) / (4π * (9.11 x \(10^-^3^1\) kg * 0.68 m/s))

Calculating the minimum uncertainty in position gives us:

Δx ≥ 2.45 x \(10^-^9\) m

Therefore, the minimum uncertainty in the electron's position is approximately 2.45 x \(10^-^9\) meters.

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A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.

According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.

A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.

We are required to determine the momentum of the rocket.

Consider the fuel-filled rocket as a system.

We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas

We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.

Therefore: Momentum of rocket = - momentum of expelled gas

The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.

Hence, the momentum of the rocket is -1500 kg m/s.

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a) z = (-6) / (-24/5) = 5/2  

  y = (5 - 4z) / 5 = -1/2

  x = (-2 + z - y) / 2 = 1/2

b) z = (2/5) / (-9/5) = -2/9

  y = (-2 - z) / -5 = 2/5

  x = (2 - 2y - z) / 1 = 4/9

c)    x = t

      y = (1 + t) / 3

      z = t

(a) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [2 -2 -1 | -2]

  [4 1 2 | 1]

  [-2 1 -3 | -3]

2. Apply row operations to transform the matrix into row-echelon form:

  R2 = R2 - 2R1

  R3 = R3 + R1

  The resulting matrix is:

  [2 -2 -1 | -2]

  [0 5 4 | 5]

  [0 1 -4 | -5]

3. Further row operations:

  R3 = R3 - (1/5)R2

  The matrix becomes:

  [2 -2 -1 | -2]

  [0 5 4 | 5]

  [0 0 -24/5 | -6]

4. Solve for the variables using back substitution:

  z = (-6) / (-24/5) = 5/2

  y = (5 - 4z) / 5 = -1/2

  x = (-2 + z - y) / 2 = 1/2

(b) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [1 2 1 | 2]

  [2 -1 1 | 2]

  [0 3 1 | 4]

2. Apply row operations to achieve row-echelon form:

  R2 = R2 - 2R1

  R3 = R3 - 2R1

  The resulting matrix is:

  [1 2 1 | 2]

  [0 -5 -1 | -2]

  [0 -1 -1 | 0]

3. Further row operations:

  R3 = R3 - (1/5)R2

  The matrix becomes:

  [1 2 1 | 2]

  [0 -5 -1 | -2]

  [0 0 -9/5 | 2/5]

4. Solve for the variables using back substitution:

  z = (2/5) / (-9/5) = -2/9

  y = (-2 - z) / -5 = 2/5

  x = (2 - 2y - z) / 1 = 4/9

(c) To solve the system of equations using Gaussian elimination:

1. Write the augmented matrix:

  [2 1 -4 | -7]

  [1 -1 1 | -2]

  [-1 3 -2 | 6]

2. Apply row operations to obtain row-echelon form:

  R2 = R2 - (1/2)R1

  R3 = R3 + R1

  The resulting matrix is:

  [2 1 -4 | -7]

  [0 -3 3 | 1]

  [0 4 -6 | -1]

3. Further row operations:

  R3 = R3 + (4/3)R2

  The matrix becomes:

  [2 1 -4 | -7]

  [0 -3 3 | 1]

  [0 0 0 | 0]

4. Solve for the variables using back substitution:

  Let's denote a free variable as t.

  x = t

  y = (1 + t) / 3

  z = t

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To solve the system of equations, we can use Gaussian elimination and convert the equations to an augmented matrix. However, in this case, the row-echelon form shows that the system is inconsistent and has no solution.

To solve the system of equations using Gaussian elimination, we can use the augmented matrix. First we convert the system of equations into augmented matrix form:

Now, we perform row operations to obtain the row-echelon form:

From the row-echelon form, we can see that the system of equations is inconsistent as the last equation is always satisfied. Therefore, there is no solution for this system.

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Answer:

the unit must always be indicated

Explanation:

displacement is alway in metre (m)

Answer:

A: measurement and direction

Explanation:

on edge! hope this helps!!~ (≡^∇^≡)

Explanation:

The circuit board fails when the positive and negative of the circuit are connected together without any load between them.

Due to the high potential difference, fire and sparks are produced.

Final Answer: sparks and fire flying

Answer:

B

Explanation:

One object speeds up before it slows to a stop.

When reading this type of graph, we know that when the points are far apart, then the object is definitely moving quickly. Also again, we know that when the points are besides each other, then we say that the object is moving slow. When the distance that is between the points are changed, the velocity of the object subsequently changes too, and therefore, we say that the object is accelerated. When there are lots of points in one location, we will see that the object is not moving.

This then translates into that

The object(s) at the top begins to slow, eventually, it increases in its speed, going forward, it slows down again, before it finally halts. The object at the bottom on the other hand, starts fast, before slowing down.

then:

"One object speeds up before it slows to a stop "

Answer:

A

Explanation:

I think it's A, sorry if I'm wrong

Answer:

Explanation:

correct me if im wrong

The kinetic energy of the skater would increase while his potential energy would decrease as he descends from top to bottom.

The law of conservation of energy states that the energy possessed by a physical body can neither be created nor destroyed, but it can only be converted (transformed) from one form of energy to another.

Based on the law of conservation of energy, the total energy (potential energy + kinetic energy) would always remain constant because it is conserved.

The potential energy of this skater at a height of 5.0 meters is given by:

PE = mgh

PE = 75 × 9.8 × 5.0

PE = 3,675 Joules.

Also, the kinetic energy of this skater at a height of 0.0 meters would be equal to zero assuming it is at rest.

In conclusion, the potential energy possessed by a physical body is highly dependent on its height while kinetic energy depends only on motion, regardless of height.

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To calculate the magnitude of the force that would exactly counterbalance these three forces, we need to use the principle of vector addition. This involves combining the three forces vectorially to find the net force acting on the object.

First, we need to find the resultant of the two forces that are at an angle of 90 degrees to each other. This can be done using the Pythagorean theorem:

Resultant = √(25² + 12²) = √(625 + 144) = √769 = 27.74 N

Next, we need to find the net force acting on the object by adding the third force (4 N) to the resultant of the first two forces (27.74 N).

Net force = 4 N + 27.74 N = 31.74 N

Therefore, the magnitude of the force that would exactly counterbalance these three forces is 31.74 N.

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Answer:

Centrifugal force = 1230.77 Newton.

Explanation:

The force associated with the car is generally referred to as centrifugal force and it can be calculated using the formula;

Centrifugal force = mv²/r

Given the following data;

Mass = 800kg

Radius = 65m

Velocity = 10m/s

To find the force;

Centrifugal force = (800*10²)/65

Centrifugal force = (800*100)/65

Centrifugal force = 80000/65

Centrifugal force = 1230.77 Newton.

\(\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} \)

\(\qquad\)______________________________

Then –

\(\qquad\) \(\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}\)

\(\qquad\) \( \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }\)

\(\qquad\)\(\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }\)

\(\qquad\)\(\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }\)

\(\qquad\)\( \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }\)

\(\qquad\)\( \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }\)

\(\qquad\) \(\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }\)

\(\qquad\) \( \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }\)

Therefore, the vertical component of velocity of projectile at this height will be–

☀️\(\qquad\)\( \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }\)

Answer:

A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2

If the thickness of the myelin sheath is halved, the speed of the nerve impulses traveling down the axon will be reduced. This is because the myelin sheath acts as an insulator, allowing the nerve impulses to jump from node to node along the axon rather than traveling down the entire length of the axon.

When the myelin sheath is thinner, there is less insulation, and the nerve impulses will slow down.

It is difficult to say exactly how much the speed will be reduced without knowing the specific properties of the axon and myelin sheath, but it is likely that the speed will be less than 40 m/s. Generally, thicker myelin sheaths lead to faster nerve impulse transmission, so halving the thickness will likely result in a significant reduction in speed.

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Answer:

Time, t = 10 seconds

Explanation:

Given the following data;

Mass = 10kg

Force = 10N

Final velocity = 10m/s

Initial velocity = 0m/s

To find the time;

First of all, we would find the acceleration of the box.

Force = mass * acceleration

10 = 10 * acceleration

Acceleration = 10/10 = 1m/s²

Now, we can find the time by using the first equation of motion;

V = U + at

10 = 0 + 1t

10 = t

Time, t = 10 seconds

Therefore, it will take 10 seconds for the box to come to a complete stop.

Answer:

17.1

Explanation:

The distance ahead, of the deer when it is sighted by the park ranger, d = 20 m

The initial speed with which the ranger was driving, u = 11.4 m/s

The acceleration rate with which the ranger slows down, a = (-)3.80 m/s² (For a vehicle slowing down, the acceleration is negative)

The distance required for the ranger to come to rest, s = Required

The kinematic equation of motion that can be used to find the distance the ranger's vehicle travels before coming to rest (the distance 's'), is given as follows;

v² = u² + 2·a·s

∴ s = (v² - u²)/(2·a)

Where;

v = The final velocity = 0 m/s (the vehicle comes to rest (stops))

Plugging in the values for 'v', 'u', and 'a', gives;

s = (0² - 11.4²)/(2 × -3.8) = 17.1

The distance the required for the ranger's vehicle to com to rest, s = 17.1 (meters).

Answer:An object having balanced forces definitely cannot be accelerating.

Answer: i think they control the eyes to move them.

Explanation:

The distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

The following question has two parts

For part 1 we need to calculate the distance covered by the truck in 12 seconds

We know that

 s = ut + \(\frac{1}{2}a .t^{2}\) . . . . . . .  . . . . .(1)

where s = distance travelled

           u = initial velocity

           a = acceleration

           t  =  time in seconds

Now , As per the question

u = 6 m/s

a = 2 m/\(s^{2}\)

t  = 12 seconds

Putting the values in the equation (1)

                          s = 6 X 12 + \(\frac{1}{2}\) X 2 X 144

                          s = 72 + 144

                          s = 216 m

Therefore the distance travelled is 216 m

For part 2 we need to calculate the final velocity that Paco was driving

We know that

v = u + at . . . . . . . . . . .  .(2)

where v = final velocity

          u = initial velocity

          a = acceleration

           t = time in seconds

As per the question,

u = 4m/s

a = 0.5 m/\(s^{2}\)

t = 30 seconds

Putting in equation (2)

                                      v = 4 + 0.5 X 30

                                      v  =  4 + 15

                                      v = 19 m/s

Therefore the final velocity is 19 m/s

Therefore , the distance the truck travel in given time is 216 m and the final velocity of acceleration at 0.5m/\(s^{2}\) for 30 seconds is 19 m /s

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The final velocity of the scooter is 19 m/s.

Given:

Initial velocity of truck, u = 6 m/s

Acceleration of truck, a = 2 m/s²

Time taken by the truck, t = 12 s

Formula used:

s = ut + 1/2 at²

Where,

s = Distance travelled

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

s = ut + 1/2 at²

 = 6(12) + 1/2 × 2 × (12)²

 = 72 + 1/2 × 2 × 144

 = 72 + 144

 = 216 m

Therefore, the truck travels 216 m in the given time.

Given:

Initial velocity of scooter, u = 4 m/s

Acceleration of scooter, a = 0.5 m/s²

Time taken by the scooter, t = 30 s

Formula used:

v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time taken

Substituting the given values in the above formula, we get:

v = u + at

 = 4 + 0.5 × 30

 = 4 + 15

 = 19 m/s

Therefore, the final velocity of the scooter is 19 m/s.

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Answer:

This question is incomplete, as it lacks options. The options are:

A. chemical energy is the same and additional energy is produced as heat and light.

B. chemical energy is more than the amount of heat and light

C. the amount of chemical energy is less than the amount of heat and light energy

D. the amount of chemical energy equals the amount of heat and light energy.

The answer is D

Explanation:

According to the first law of thermodynamics, which is the LAW OF CONSERVATION OF ENERGY, energy is neither created nor destroyed but can only be changed from one form to another. This law states that no energy in a system is lost, hence, the input energy must be equal to the output energy.

When a log of wood is burnt, the chemical energy stored in it is converted to heat energy and light energy. Based on the law of conservation of energy, the amount of chemical energy present in the log before the burning process must equal the amount of light and heat energy it changed to after the burning process.

That is, chemical energy = light energy + heat energy.

Answer:

The correct option is (c) "it bounces the light towards a focal point"

Explanation:

There are two types of spherical mirrors i.e. concave and convex.

A concave mirror is a type of spherical mirror that is curved inwards. For this type of mirror the rays of light are bounced back and converge to the focal point of the mirror.

So, the correct option is (c).

Answer:

c

Explanation:

Answer: depends on what your nervous about

Explanation:tell me what your nervous about

To induce an electromotive force (emf) in a loop, the following changes can be considered, Change in magnetic field strength through the loop, Change in the area of the loop within the magnetic field, Change in the orientation of the loop with respect to the magnetic field.

When any of these changes occur, an emf is induced in the loop according to Faraday's law of electromagnetic induction. The emf is a voltage that drives an electric current within the loop.

1. Change in magnetic field strength: If the magnetic field strength passing through the loop changes, it will induce an emf in the loop. This can be achieved by altering the current flowing through a nearby wire or by using a magnet to change its distance or orientation relative to the loop.

2. Change in the area of the loop: If the area of the loop within the magnetic field changes, it will induce an emf. This can be done by physically changing the size or shape of the loop while keeping it within a constant magnetic field.

3. Change in the orientation of the loop: If the orientation of the loop with respect to the magnetic field changes, it will induce an emf. This can be achieved by rotating or tilting the loop relative to the magnetic field direction.

In summary, any change in the magnetic field strength, the area of the loop, or the orientation of the loop within the magnetic field will induce an emf in the loop, according to Faraday's law of electromagnetic induction.

Complete question is which of the following changes would induce an electromotive force (emf) in the loop? when you consider each option, assume that no other changes occur. check all that apply.

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Answer:

We can use Coulomb's law to solve this problem:

F = k * q1 * q2 / r^2

where F is the force between the two charges, k is Coulomb's constant (k = 9 x 10^9 N m^2 / C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between them.

We know the force F, the distance r, and the magnitude of one of the charges q1. We can rearrange the equation to solve for the magnitude of the other charge q2:

q2 = F * r^2 / (k * q1)

Substituting the values we have:

q2 = (250 N) * (0.15 m)^2 / (9 x 10^9 N m^2 / C^2 * 6.5 x 10^-5 C)

Simplifying:

q2 = 8.65 x 10^5 C

Therefore, the magnitude of the other charge is 8.65 x 10^5 C.

The magnitude of the torque that will bring the balls to a halt in 4.0 s is 2.9425 Nm, counterclockwise.

To solve this problem, we need to use the principle of conservation of angular momentum. The angular momentum of the system before the torque is applied is equal to the angular momentum after the torque is applied.

The angular momentum of a rigid body rotating about an axis is given by the formula:

L = Iω

where;

The moment of inertia of a system of particles is given by the formula:

I = Σmr²

where;

The angular velocity is related to the rotational speed by the formula:

ω = 2πn

where;

Given the mass and length of the rod, we can calculate the moment of inertia of the system as follows:

I = m1r1² + m2r2²

Therefore, we can use the formula for the moment of inertia of a rod about its center:

I = (1/12)ml²

I = (1/12)(6 kg)(3.0 m)² = 4.5 kg m²

The angular velocity is given as 25 rpm, which is equivalent to 2.617 rad/s.

Therefore, the initial angular momentum of the system is:

L = Iω = (4.5 kg m²)(2.617 rad/s) = 11.77 kg m²/s

To bring the system to a halt in 4.0 s, we need to apply a torque that will reduce the angular velocity to zero in that time. The magnitude of the torque is given by the formula:

τ = ΔL/Δt

where;

Since the final angular momentum is zero, the change in angular momentum is equal to the initial angular momentum. Therefore:

ΔL = -11.77 kg m²/s

Δt = 4.0 s

Substituting these values, we get:

τ = (-11.77 kg m²/s) / (4.0 s) = -2.9425 Nm

Since torque is a vector quantity, we should specify the direction of the torque. Since the system is rotating clockwise, the torque should be applied counterclockwise.

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Pressure vs. Depth Lab:

Pressure is defined as the force per unit area applied on an object. It is a scalar quantity, which means it only has magnitude and no specific direction.

It is often measured in units of Pascals (Pa), which is equivalent to one Newton of force per square meter of area. Pressure can be caused by the weight of an object, the force applied by a fluid, or the collision of particles with a surface.

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The momentum of object B is 11 kg x m/s.

To find the momentum of object B, we can use the principle of conservation of momentum. This principle states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision.

Therefore, we can calculate the momentum of object B as follows:
Total momentum before collision = Total momentum after collision

The total momentum before collision is the sum of the momentum of object A and the momentum of object B:
Total momentum before collision = 3 kg x m/s + momentum of object B
The total momentum after collision is given as 14 kg x m/s.

So we can set up an equation:
3 kg x m/s + momentum of object B = 14 kg x m/s
Simplifying this equation, we get:
momentum of object B = 14 kg x m/s - 3 kg x m/s
momentum of object B = 11 kg x m/s

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The normal force on the first box from the table will stay at 75 N even after a second box is placed on top of it.

The normal force is a contact force that is determined by the weight of the object, as well as the interaction between the two surfaces in contact. The regular force that the table normally applies to the first box will stay unchanged because the weight of the box has not changed.

The normal force, which is equivalent in strength to gravity's force and acts in the opposite direction, is a force that is perpendicular to the surface of contact. The box is prevented from dropping through the table's surface by this reactionary force.

In other words, the normal force is equivalent to the object's weight, which in this instance is 75 N.

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P(white) = 27/100 = 270/1000

Therefore, in 1,000 pulls, we eaxpect 270 white beads,

Unlike many other vector quantities, point of application is defined by their magnitude and direction, force. The point of application refers to the specific location or point where a force is applied to an object. It indicates where the force is acting or being exerted on an object.

The point of application is an essential aspect of force, along with its magnitude (strength) and direction.

Together, these characteristics fully define a force vector and determine its overall effect on an object's motion or deformation.

So, unlike many other vector quantities, point of application is defined by their magnitude and direction, force.

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