A mixture of He, N2, and Ar has a pressure of 13.6 bar. The partial pressure of He is 383 kPa and the partial pressure of Ar is 401 kPa. The partial pressure of N2 would be 12.816 bar.
Calculating partial pressure of nitrogen:
To calculate the partial pressure of N2, we first need to find the total pressure contributed by He and Ar, and then subtract that from the total pressure of the mixture.
The partial pressure of He is given as 383 kPa, which is equal to 0.383 bar (since 1 bar = 100 kPa). Similarly, the partial pressure of Ar is given as 401 kPa, which is equal to 0.401 bar.
So the total pressure contributed by He and Ar is:
0.383 bar + 0.401 bar = 0.784 bar
Now, we can subtract this from the total pressure of the mixture to get the partial pressure of N2:
The total pressure of the mixture = 13.6 bar
The partial pressure of He = 0.383 bar
The partial pressure of Ar = 0.401 bar
The partial pressure of N2 = Total pressure of mixture - (Partial pressure of He + Partial pressure of Ar)
Partial pressure of N2 = 13.6 bar - (0.383 bar + 0.401 bar)
Partial pressure of N2 = 12.816 bar
Therefore, the partial pressure of N2 in the mixture is 12.816 bar.
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Please help me on due today
A personal enrichment goal is related to your life outside the classroom. You might set a goal to read every day or take on a new challenge in an extracurricular team, sport, or activity.
Your completed portfolio will demonstrate how you worked to achieve your stated goals.
• Step 1: Decide what you want to achieve.
• Step 2: Set your goal.
• Step 3: Decide what actions you need to take to reach your goal.
• Step 4: Set a time frame.
• Step 5: Think about your assets and obstacles.
Subject-Matter Achievement Goal
1. My subject-matter achievement goal is:
Answer:
2. My action steps are:
Answer:
3. My time frame is:
Answer:
4. Assets and Strengths:
Answer:
5. Motivation:
Answer:
6. Obstacles:
Answer:
7. Solutions:
Answer:
Study/Organizational Skills Goal
8. My study/organizational skills goal is:
Answer:
9. My action steps are:
Answer:
10. My time frame is:
Answer:
11. Assets and Strengths:
Answer:
12. Motivation:
Answer:
13. Obstacles:
Answer:
14. Solutions:
Answer:
Personal Enrichment Goal
15. My personal enrichment goal is:
Answer:
16. My action steps are:
Answer:
17. My time frame is:
Answer:
18. Assets and Strengths:
Answer:
19. Motivation:
Answer:
20. Obstacles:
Answer:
21. Solutions:
Answer:
Subject-Matter Achievement Goal
1. My subject-matter achievement goal is:
Answer: Read 1 full chapter book in 1 week
2. My action steps are:
Answer: Read an equal amount of chapters every day for a week
3. My time frame is:
Answer: 1 week
4. Assets and Strengths:
Answer: ability to focus,
5. Motivation:
Answer: Great interest in the book I chose
6. Obstacles:
Answer: Might lose page number, forget where I am at in the book, forget to read one day
7. Solutions:
Answer: Get or make a bookmark, keep a personal reading log, set alarm for a certain time each day
Study/Organizational Skills Goal
8. My study/organizational skills goal is:
Answer: manage my time better
9. My action steps are:
Answer: planning things out to be more organized
10. My time frame is:
Answer: from now to the end of the school year
11. Assets and Strengths:
Answer: a planner so I can pace myself
12. Motivation:
Answer: give breaks and take time to do things I enjoy
13. Obstacles:
Answer: leaving things last minute
14. Solutions:
Answer: planning to do certain things before a certain day
This can be for any of those goals
Personal Enrichment Goal
15. My personal enrichment goal is:
Answer: Stay healthy
16. My action steps are:
Answer: eat healthier foods
17. My time frame is:
Answer: now to the end of the school year
18. Assets and Strengths:
Answer: I don't make a big deal out of eating veggies and stuff
19. Motivation:
Answer: treat myself every so often
20. Obstacles:
Answer: Craving junk food
21. Solutions:
Answer: find a way to make healthier foods taste similar to junk food (EX. Put cheese on broccoli)
Newton's heating-cooling law states that the rate of change in the temperature, H, is proportional to the difference between the object and the surrounding temperature. Let H(t) be the temperature of the object being cooled and S be the surrounding temperature. A warm object at 100 degrees is placed in a refrigerator at 35 degrees Fahrenheit and after 30 minutes the object is 75 degrees. Write and solve the differential equation which describes the temperature of the object over time, where time is measured in hours. OH(t)=35-65e-0.97t OH(t)=35+65e-t(0.97) OH(t)=75-35e-0.97t OH(t)=35+75e0.971
The differential equation which describes the temperature of the object over time is;
dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
Newton’s law of heating and cooling is an application of the first law of thermodynamics. The law suggests that the rate of change of temperature of an object is proportional to the difference between its temperature and the temperature of the surroundings.
A warm object is placed in a refrigerator where the surrounding temperature is cooler, and the temperature of the object decreases. This phenomenon can be explained using differential equations. Given that H(t) is the temperature of the object being cooled and S is the surrounding temperature, the differential equation which describes the temperature of the object over time is given by;dH/dt = -k (H-S)
where k is the constant of proportionality.To solve this differential equation, we can use separation of variables, such that;
dH/dt = -k (H-S)dH/(H-S) = -k dt
Integrating both sides, we get;ln|H-S| = -kt + Cwhere C is the constant of integration.Rearranging, we have;
|H-S| = e^(-kt+C)
At time, t = 0, H = 100 and after 30 minutes the object is 75 degrees; t = 0.5 hours, H = 75. We can use these values to solve for C and k as follows;
|100-35| = e^(C) => 65 = e^(C) …(1)
and|75-35| = e^(-0.5k+C) => 40 = e^(C) e^(-0.5k) => e^(-0.5k) = 40/65 => e^(-0.5k) = 8/13 => -0.5k = ln(8/13) => k = -2ln(8/13) => k = 0.97 …(2)
Substituting equation (1) into (2), we get;H-S = 65e^(-0.97t) => H(t) = S + 65e^(-0.97t)
Therefore, the differential equation which describes the temperature of the object over time is;dH/dt = -k (H-S), where k = 0.97.
The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
The differential equation which describes the temperature of the object over time is;
dH/dt = -k (H-S), where k = 0.97. The solution to this differential equation is given by H(t) = S + 65e^(-0.97t).
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if a golf ball and baseball are thrown with the same force, which will have greater acceleration?
An electric iron of resistance 20Ω takes a current of 5A. Calculate the heat developed in 30seconds?
The amount of heat (H) produced is given by the joule’s law of heating as H= Vlt
Where,
Current, I = 5 A
Time, t = 30 s
Voltage, V = Current x Resistance = 5 x 20 = 100V
H= 100 x 5 x 30 = 1.5 x 10⁴ J.
Therefore, the amount of heat developed in the electric iron is 1.5 x 10⁴J.
Please mark me as a BRAINLIST
match each vocabulary word with the correct definition. 1 . weight measure of how quickly velocity is changing 2 . acceleration speed in a given direction 3 . velocity force that resists moving one object against another 4 . friction measure of the pull of gravity on an object 5 . magnitude tendency of an object to resist a change in motion 6 . inertia size
The different words used to match the given definitions are acceleration, velocity, friction, weight, inertia, magnitude.
1. Acceleration is a measure of how quickly the velocity is changing
2. Velocity is speed in a given direction
3. Friction is the force that resists the movement of one object against another
4. On an object weight is the measure of pull of gravity
5. Inertia is the tendency of an object to resist change in motion
6. Magnitude is the size.
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why is concave mirror used to make solar heater?Give reason
Concave mirror is used to make to solar heater because it can converge light of sun in a small area
hope it helps
What is a positive component of Heath called:
Answer:
vegetables food, sport sport sport
Explanation:
????!!!!
Normal human body temperature is 98.6°F. What is this temperature expressed in Celsius (°C) and in Kelvin (K)?
Answer: 37 Celsius and 310.15 K
Explanation:
C/5 = (F-32)/9 = (98.6-32)/9 = 66.6/9 = 7.4
C = 7.4 * 5 = 37 so the temperature is 37 Celsius
K = C + 273.15 = 37 + 273.15 = 310.15 K
7. All of the following descriptions are true about descriptive method of research except one:
A. The true meaning of data collected should be reported from the point of view of the objectives and the
basic assumptions of the project under way
B. Subtypes: experimental research, research survey, case study, job and activity, and library and documentary
research
C. The discussion of the data must be carried in the level of adequate interpretation
D. It is a fact-finding with adequate interpretation
Answer:
c
Explanation:
Two positively charged particles repel each other with a force of magnitude Fold. If the charges of both particles are doubled and the distance separating them is also doubled, what is the ratio of the new force compared to the original force, Fox? , Flex Fold
The ratio of the new force compared to the original force is `1`.
Given that two positively charged particles repel each other with a force of magnitude `Fold`.
The charges of both particles are doubled and the distance separating them is also doubled.
To find: What is the ratio of the new force compared to the original force,
We know that the force between two charged particles is given by Coulomb's law as,
F = k(q₁q₂)/r²where,
k = Coulomb constant = 9 × 10⁹ Nm²/C²
q₁ = charge of particle 1
q₂ = charge of particle 2
r = distance between two charged particles.
Now, According to the question,Q₁ and Q₂ charges of both particles have doubled, then
new charges are = 2q₁ and 2q₂
Also, the distance separating them is also doubled, then
new distance is = 2r.
Putting these values in Coulomb's law, the
new force (F') between them is,
F' = k(2q₁ × 2q₂)/(2r)²
F' = k(4q₁q₂)/(4r²)
F' = (kq₁q₂)/(r²) = Fold
The ratio of the new force compared to the original force is given by;
Fox = F'/Fold= 1
Therefore, the ratio of the new force compared to the original force is `1`.
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75 J of heat are added to a heat engine and 50 J of thermal energy is lost in the process. Determine the work done by the engine (in Joules)?
Answer:
The work done by the engine is 50 J.
Explanation:
Given;
amount of heat energy added to the heat engine, Q = 75 J
energy lost in the process, E = 50 J
let the work done by the engine (system) = W
Apply the first law of thermodynamic;
ΔU = Q - W
where;
ΔU is change in internal energy = 75 J - 50 J = 25 J
25 = 75 - W
25 - 75 = - W
-50 J = - W
W = 50 J
Therefore, the work done by the engine is 50 J.
What is a likely direct effect of a community program for local residents?
A. lower education costs
B. higher healthcare costs
C. higher salaries
D. Improved safety for children
Explanation:
improved saftey for children
Answer:
D. Improved safety for children
Explanation:
What are the Van Allen Radiation Belts ?
Answer:
A Van Allen radiation belt is a zone of energetic charged particles, most of which originate from the solar wind, that are captured by and held around a planet by that planet's magnetosphere. Earth has two such belts, and sometimes others may be temporarily created
Find the magnitude of the sum of these two vectors: B 101 m 60.0 ° 85.0 m A
Answer:
M= 161.1 m Deg= 32.9
Explanation:
I need help please help
Answer:
29 Joules
Explanation:
58N * 0.5m =
58 * 0.5 =
58 * 5/10 =
290/10 = 29 Joules
A soccer ball kicked with a force of 12.6 N
accelerates at 7.7 m/s^2
to the right.
What is the mass of the ball?
Answer in units of kg.
Answer:
The mass of the ball is 1.64 kg.
Explanation:
You have to apply Newton's second law, F = m×a where F represents force, m is mass and a is acceleration :
\(F = m \times a\)
\(let \: F = 12.6,a = 7.7\)
\(12.6 = m \times 7.7\)
\(12.6 \div 7.7 = m\)
\(m = 1.64kg \: (3sf)\)
why don't the air molecules in your room all spontaneously collect in one half of the room, leaving the other half of the room completely empty of air? newtons law
The answer is entropy here. It's quite unlikely that spontaneously air molecules moves exclusively to one half of your room. This can be explained by understanding the concept of entropy and second law of thermodynamics.
Why is the second law of thermodynamics true?Entropy is the measure of disturbance or disorder of universe.
The second law of thermodynamics states that entropy of an isolated system doesn't decrease over time.
The second law of thermodynamics is true because there are very few ways that particles can be concentrated in an area. In most situations, the particles are evenly distributed. Similarly, in a room, the particles are evenly distributed and as particles start moving, there is a nonzero probability of low entropy state, Most of the time the system will increase in entropy that is increase in disturbance evenly. Hence it is not possible that air molecules will collect in one part of the room and not on the other part.
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Marine science- question- what is climate change?
Answer:
Defined below
Explanation:
Climate change is simply the long term change in the average weather patterns that are associated with the local, regional and global climates of the earth. Climate change is usually driven by human activities like burning of fossils; natural processes like cyclic ocean patterns; external factors like volcanic eruptions.
8. An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120
specific heat capacity of the liquid in this temperature range. Assume that negligible h
O
O
O
2.51 x 10³ J/(kg. C°)
1.67 x 106 J/(kg C°)
2.02 x 104 J/(kg. C°)
The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.
Specific heat capacity of the liquidThe specific heat capacity of the liquid is calculated as follows;
Q = mcΔФ
where;
Q is quantity of heat c is specific heat capacitym is mass of the liquidΔФ is change in temperature = 22.54 - 18.55 = 3.99 ⁰Cc = Q/mΔФ
c = (65 x 120)/(0.78 x 3.99)
c = 2.51 x 10³ J/kg⁰C
The complete question is below:
An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.
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A golf ball of mass 0.045 kg is hit off the tee at a speed of 34m/s . The golf club was in contact with the ball for 3.50*10^-3s .
Find the impulse imparted to the golf ball.??
Find the average force exerted on the ball by the golf club.??
Express your answer to two significant figures and include the appropriate units.
The average force exerted on the ball by the golf club is 490 N.
Thus, F = p/t = 0.49 * 10³ N = 490 N.
Momentum is a metric for power and how challenging it is to stop an object. Zero momentum applies to any object that is not moving. tremendous, slow-moving objects have tremendous amounts of momentum.
A small, swiftly moving object also possesses a significant momentum. A bowling ball, for instance, has more momentum than a ping-pong ball if their velocities are equal.
This is because bowling balls are larger in mass than ping-pong balls.
Thus, The average force exerted on the ball by the golf club is 490 N.
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A gyroscope flywheel of radius 1.96 cm is accelerated from rest at 13.0 rad/s2 until its angular speed is 2270 rev/min. (a) What is the tangential acceleration of a point on the rim of the flywheel during this spin-up process
Tangential acceleration of a point on the rim of the flywheel during this spin-up process is 0.2548 m/s².
Tangential acceleration is defined as the rate of change of tangential velocity of the matter in the circular path.
Given,
Radius of flywheel (r) = 1.96 cm = 0.0196m
Angular acceleration (α)= 13.0 rad/s²
The tangential acceleration formula is at=rα
where, α is the angular acceleration, and r is the radius of the circle.
using the formula; at=rα = (13.0 rad/s²) (0.0196m) = 0.2548 m/s².
The tangential acceleration is 0.2548 m/s².
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While Steve is trekking in the Rocky Mountains, he realizes that he does not have a compass. He decides to find north direction at twelve noon. Which of these methods should he try?
A) locate the position of the Pole Star in the sky
B) face the Sun directly and observe the direction of his shadow
C) blow upon some dry grass to determine the direction of the wind
D) pour some water on the ground and observe the direction of its flow
Answer:
B
Explanation:
The Sun's shine comes from right above the Equator. The Equator is south from the Rocky Mountains, so the sunshine comes from south and the shade (the opposite direction of the sun) is north.
A proton is confined to moving in a one-dimensional box of width 0.200 nm.
(a) Find the lowest possible energy of the proton.
(b) What is the lowest possible energy of an electron confined to the same box?
(c) How do you account for the large difference in your results for (a) and (b)?
The question discusses a proton and an electron confined to a one-dimensional box with a width of 0.200 nm. It asks for the lowest possible energy of the proton.
(a) The lowest possible energy of a proton confined to a one-dimensional box can be found using the equation E = (n^2 * h^2) / (8 * m * L^2), where E is the energy, n is the quantum number (1 for the ground state), h is the Planck's constant, m is the mass of the proton, and L is the width of the box.
Substituting the values, we have E = (1^2 * h^2) / (8 * m * L^2). Calculating this expression will give us the lowest possible energy of the proton in the given one-dimensional box.
(b) For an electron confined to the same one-dimensional box, the lowest possible energy can be calculated using the same equation as in part (a). However, the mass of the electron and its quantum number will be used in the calculation.
(c) The large difference in the results for parts (a) and (b) can be attributed to the significant difference in mass between a proton and an electron. The mass of a proton is approximately 1836 times greater than that of an electron. This difference in mass affects the energy levels and results in the proton having a much higher energy compared to the electron in the same size box.
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A man running at 5 M/S increases his velocity to 10 M/S in 2 Seconds. What was his acceleration?
Caregivers should begin reading to children:
When they are babies.
When they can talk.
When they show an interest.
When they are two.
When they are preschoolers.
Answer:
When they are babies. to get them familar with it
Explanation:
Pls choose brainliest.
Answer:
When they are babies
Explanation:
Because they could hear the words and laern them.
If a transformer doubles its input voltage, what is the current in the secondary coil if the primary coil is 10 A.
Answer:
20Amp
Explanation:
Using the transformer formula
Vs/Vp = Ns/Np = Ip/Is
Vs/Vp = Ip/Is
Vp is the primary voltage = input voltage
Vs is the secondary voltage = output voltage
Ip is the current in the primary coil
Is is the amount of current in the secondary coil.
If the transformer doubles its input voltage Vp, its output voltage Vs will be
decreased by 2 but the output current will be doubled
Given the input current Ip = 10A, the current in the secondary coil (output current) will be doubled i.e Is = 2(10) = 20A
The current in the secondary coil be "50 A". To understand the calculation, check below.
Current and VoltageAccording to the question,
Current in primary coil, \(I_{in}\) = 10 A
We know the relation,
Power = \(V_{in} I_{in}\) = \(V_{out} I_{out}\)
then,
→ \(V_{in} I_{in}\) = \(V_{out} I_{out}\)
By substituting the values,
\(V_{in}\) × 10 = 2 \(V_{in} I_{out}\)
By applying cross-multiplication,
10 = 2 \(I_{out}\)
\(I_{out}\) = \(\frac{10}{2}\)
= 5 A
Thus the response above is correct.
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Explain why precipitation on earths surface is less common on land than itbis over the oceons. Base your answer on the water cycle
The combination of the vast moisture availability and relatively stable atmospheric conditions over the oceans contributes to more frequent precipitation compared to land areas.Due to this precipitation on earths surface is less common.
Precipitation on Earth's surface is generally less common on land compared to over the oceans due to several factors related to the water cycle. The water cycle involves the continuous movement of water between the atmosphere, land, and oceans.
Firstly, the oceans cover a significant portion of the Earth's surface, which means there is a larger expanse of water available for evaporation. Evaporation occurs when water from the surface of oceans turns into water vapor, rising into the atmosphere. The vastness of the oceans provides ample moisture for evaporation, resulting in a greater supply of water vapor in the atmosphere.
Secondly, land surfaces tend to heat up and cool down more quickly than the oceans. This difference in temperature leads to variations in air pressure and creates atmospheric circulation patterns. As warm air rises over land areas, it expands and cools, causing water vapor to condense and form clouds. However, the land areas often lack the necessary moisture content to sustain significant cloud formation and subsequent precipitation.
Moreover, when moist air masses from the oceans encounter land masses, they are forced to rise due to the topography of the land. As the air rises, it cools, leading to condensation and cloud formation. However, the presence of mountains or other geographical features can enhance this lifting process, resulting in increased precipitation in certain regions.
Overall, the combination of the vast moisture availability and relatively stable atmospheric conditions over the oceans contributes to more frequent precipitation compared to land areas. Land surfaces, with their varying temperatures, limited moisture content, and topographical features, often experience less common and more localized precipitation events.
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Define mechanics.
What is the difference between kinematics and Dynamics?
2.1. Give examples for kinematics and Dynamics.
Answer:
The branch of applied mathematics dealing with motion and forces producing motion is called mechanics.
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An inclined plane makes work easier by decreasing force. This means, it must also _____.
decrease work
increase weight
increase distance
decrease distance
Answer:
increase distance
Explanation:
Inclined planes make it easier to move objects to a higher elevation. The sloping surface of the inclined plane supports part of the weight of the object as it moves up the slope. As a result, it takes less force to move the object uphill.
Answer:
Hello your answer would be increase of distance
Explanation:
I know that because than you would have to go upward with the object.
Two 50 g metal blocks, one made of lead and the other of iron, are heated to 100°C. They are placed in identical calorimeters, each with 100 g of water at a starting temperature of 20°C. Which calorimeter will have the higher temperature at thermal equilibrium: the one with lead or the one with iron? Explain your answer
calorimeter with iron will have the higher temperature at thermal equilibrium.
The particular heat capacity (symbol c) of a material in thermodynamics is the heat capacity of a sample of the substance divided by the mass of the sample, also known as massic heat capacity. Informally, it is the quantity of heat that must be added to one unit of mass of the substance to generate one unit of temperature increase. Specific heat capacity is measured in joules per kelvin per kilogramme, or J⋅kg−1⋅K−1, The heat required to increase the temperature of 1 kilogramme of water by 1 K, for example, is 4184 joules, hence the specific heat capacity of water is 4184 J⋅kg−1⋅K−1. calorimeter with high specific heat have the higher temperature at thermal equilibrium.
In this problem, specific heat of lead is 120 J/kg.°C. and that of iron is 450 J/kg°C.
if the both elements are heated from room temperature 25°C to 100°C,
Total heat contained in lead is,
Q = cmΔT = 120×0.05kg×75°C = 450 J
Total heat contained in iron is,
Q = cmΔT = 450×0.05kg×75°C = 1687 J
Specific heat of the water is 4.2 J/g°C.
Temperature of the calorimeter due to lead
T₂ - T₁ = Q/cm = 450/4.2×100
T₂ - 25 = 1.07
T₂ = 1.07 +25 = 26.07°C
Temperature of the calorimeter due to iron
T₂ - T₁ = Q/cm = 1687 /4.2×100
T₂ - 25 = 4.01
T₂ = 4.01 + 25 = 29.01 °C
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