A stealthy target with an RCS of -30 dBsm can be detected at a range of approximately 7.17 km. This range is much smaller than the range at which the 10 \(m^2\) target was detected, indicating that the radar would have difficulty detecting smaller targets at longer ranges.
A monostatic radar system is used to detect and locate targets by transmitting a radar signal and analyzing the returned signal.
The power and sensitivity of the radar determine the range and accuracy of target detection.
In the given scenario, a 10 m2 target was detected at a range of 266.4 km.
The radar transmitted 100 kW of power at a frequency of 3 GHz, and had an antenna gain of 40 dB.
The received power was -100 dBm, which indicates a strong signal return.
Now, suppose a stealthy target with a radar cross-section (RCS) of -30 dBsm () needs to be detected.
The RCS of a target represents the amount of radar energy it reflects back towards the radar. A lower RCS value indicates a smaller target that is harder to detect.
To determine the range at which the stealthy target can be detected, we need to calculate the received power from the target.
The received power is given by the radar equation:
Pr =\(((Pt \times Gt \times Gr \times (\lambda^2) \times RCS) / ((4 \times \pi)^3 \times R^4))\)
where Pr is the received power,
Pt is the transmitted power,
Gt and Gr are the antenna gains,
\(\lambda\) is the wavelength of the signal,
RCS is the radar cross-section, and
R is the range to the target.
Using the given values and assuming the same antenna gain and frequency, we can solve for the range R:
R = \(((Pt \times Gt \times Gr \times (\lambda^2) \times RCS) / ((4 \times \pi)^3 \times Pr))^{0.25}\)
Substituting the values, we get:
\(R = ((100,000 \times 10^{(40/10)} \times 10^{(-100/10)} \times (0.1^2) \times 10^{(-3)}) / ((4 \times \pi)^3 \times (3 \times 10^8 / 3 \times 10^9)^2))^{0.25}\)
R = 7.17 km
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Someone please help I’m so confused
Explanation:
the switch and the battery
4. Use your research to explain whether the observations of your windmill
relate to current, real-world advances in windmill technology. Describe the
problems with windmill technology and how engineers have solved them.
Provide specific real-world examples of where new windmill technology is
being used.
Answer:
windmill, device for tapping the energy of the wind by means of sails mounted on a rotating shaft. The sails are mounted at an angle or are given a slight twist so that the force of wind against them is divided into two components, one of which, in the plane of the sails, imparts rotation.
Explanation:
The use of windmills was increasingly widespread in Europe from the 12th century until the early 19th century. Their slow decline, because of the development of steam power, lasted for a further 100 years. Their rapid demise began following World War I with the development of the internal-combustion engine and the spread of electric power; from that time on, however, electrical generation by wind power has served as the subject of more and more experiments
To work efficiently, the sails of a windmill must face squarely into the wind, and in the early mills the turning of the post-mill body, or the tower-mill cap, was done by hand by means of a long tailpole stretching down to the ground. In 1745 Edmund Lee in England invented the automatic fantail. This consists of a set of five to eight smaller vanes mounted on the tailpole or the ladder of a post mill at right angles to the sails and connected by gearing to wheels running on a track around the mill
The most important use of the windmill was for grinding grain. In certain areas its uses in land drainage and water pumping were equally important. The windmill has been used as a source of electrical power since P. La Cour’s mill, built in Denmark in 1890 with patent sails and twin fantails on a steel tower. Interest in the use of windmills for the generation of electric power, on both single-user and commercial scales, revived in the 1970s.
i need helppppppppppp :>
(can you make this five sentences or less
Answer:
The force of the bat is pushing harder than the ball. When there are unbalanced forces, one will move less or more than the other. Balanced forces stay the same force, that's why they're call "balanced" forces. so in this example, the bat has a stronger force than the ball, which causes the ball to have a greater reaction
how many "flavors" of quark are there (excluding antimatter)?
There are six different flavors of quarks known to exist in nature. There are 6 flavors of quark (excluding antimatter).
The six different flavors of quarks are up, down, charm, strange, top, and bottom. Each of these quarks has a unique mass, electric charge, and other properties that distinguish them from one another. Quarks are fundamental particles that make up protons and neutrons, which in turn make up the nucleus of atoms. While there are also six different types of anti-quarks, which have opposite charges to their corresponding quarks, they are not considered separate "flavors" in the same way that quarks are.
Quarks are elementary particles that make up protons and neutrons. They come in 6 distinct "flavors," which are different types with unique properties. The 6 flavors of quarks are: up, down, charm, strange, top, and bottom. Each flavor has a corresponding antimatter counterpart, but since we are excluding antimatter, the total number of quark flavors remains at 6.
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Melanie ran the 100 meters race in 12 seconds what was her avarage speed?
Answer:
melanie ran 8.3 meters per second
Explanation:
I think thats right, hope it helps.
sphygmo- (sphygmo/gram; sphygmo/meter) means:
Sphygmo- (sphygmo/gram; sphygmo/meter) means pulse.A sphygmomanometer is a device used to measure blood pressure. Sphygmography is a technique for recording the pulse wave produced by the beating of the heart.
Sphygmo- is a combining form that means pulse, beating. It derives from the Greek word σφυγμός (sphygmos), which means "pulse, beating."For example, a sphygmomanometer is a medical instrument that measures blood pressure and consists of an inflatable cuff that is wrapped around the upper arm and a pressure gauge. Sphygmomanometer is a composite word made up of three roots: sphygmo- (pulse), mano- (pressure), and -meter (measuring instrument).
Sphygmo- means pulse or beating. A sphygmomanometer is a device used to measure blood pressure. Sphygmography is a technique for recording the pulse wave produced by the beating of the heart.
Sphygmo- is a combining form that means pulse, beating. It derives from the Greek word σφυγμός (sphygmos), which means "pulse, beating." Sphygmo- is used to form a number of medical terms such as sphygmography, sphygmomanometer, and sphygmotonometer.
Sphygmography is a technique for recording the pulse wave produced by the beating of the heart. It is done by placing a special pen or stylus on a piece of paper that is moving at a fixed speed and allowing it to trace out a curve that represents the pulse wave. The resulting tracing is called a sphygmogram.A sphygmomanometer is a medical instrument that measures blood pressure. It consists of an inflatable cuff that is wrapped around the upper arm and a pressure gauge. The cuff is inflated to a pressure above the systolic pressure of the patient's blood pressure. Then, the pressure is gradually released until the blood flow is restored and the pulse is felt again. The pressure at which the pulse is felt again is recorded as the systolic pressure.The sphygmotonometer is a newer version of the sphygmomanometer. It is a fully automated device that measures blood pressure using an electronic sensor. The device inflates the cuff and records the blood pressure automatically, without requiring any manual intervention.Sphygmo- means pulse or beating. A sphygmomanometer is a device used to measure blood pressure. Sphygmography is a technique for recording the pulse wave produced by the beating of the heart.
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if you weigh 100 pounds and pull 4 g's how much do you now weigh
Answer:
sill 100?
Explanation:
Consider the electric field lines drawn below for a configuration of two charges. Several locations are labeled on the diagram. Rank these locations in order of the electric field strength - from smallest to largest.
Helppp
Answer:
The magnitude or strength of an electric field in the space surrounding a source charge is related directly to the quantity of charge on the source charge and inversely to the distance from the source charge. The direction of the electric field is always directed in the direction that a positive test charge would be pushed or pulled if placed in the space surrounding the source charge.
Explanation:
I really hope this helps you!
The rank for the strength of electric field can be given as D>B>E>C>A. The amplitude or intensity of such an electric field inside the region around a source charge is proportional to the amount of charge.
What is electric field lines?Electric field lines are a paper representation of electric field lines. These are drawings that employ lines and arrows to illustrate electric fields surrounding charged objects, making them highly useful in understanding field intensity and direction.
The amplitude or intensity of such an electric field inside the region around a source charge is proportional to the amount of charge just on source charge as well as inversely proportional to the distance first from source charge. The rank for the strength of electric field can be given as D>B>E>C>A.
Therefore, the rank for the strength of electric field can be given as D>B>E>C>A.
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a
17. When a 50 cm long wooden log has a radius of 7 cm and a mass of 770g, what is
the density of the wood?
Answer:
The density is 1.1gcm3
Which of the following changes would cause the fusion rate in the sun’s core to increase?
a. An increase in the core temperature
b. A decrease in the core radius
The changes that would cause the fusion rate in the sun’s core to increase are:
a.) An increase in the core temperature and
b)A decrease in the core radius
So, correct options are a and b.
The sun is the Main Sequence star. A Main Sequence star is powered by fusing hydrogen into the Helium within its core.
For this type of fusion to take place, a temperature of at least 10 million Kelvin is required, beyond the given point, the fusion rate is actually directly related to the core temperature. If temperature increases, the fusion rate will greatly increase.
Something similar happens if core reduces its radius. This can happen at the end of the star's lifetime, shortly before it becomes the red giant. Once hydrogen is depleted, the core will start to shrink because the force of gravity, and as it gets smaller, gets very more compressed, and its temperature increases
Hence, both a and b options are correct.
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17) Name two ways you could decrease the potential energy of a bucket full of water sitting on a bench.
Explanation:
The potential energy of an object has the following formula
Potential energy = mgh
where m = mass of the object
g = acceleration due to gravity
h = height of the object
This means that the potential energy of an object depends upon its mass, acceleration due to gravity, and height.
In the given situation we have a bucket full of water. If the mass and acceleration due to gravity are not changed, the only way the potential energy can be decreased is by reducing the height of the bucket full of water.
This can be done by: -
(i) Lifting the bucket full of water in such a way that you
decrease its height as compared to the bench.
(ii) Put the bucket full of water on a stool whose height is
lower than the bench.
Answer:
1.By decreasing it's contents- this decreases the weight of the bucket thus decreasing the potential energy of the bucket.
2.By decreasing the height of the bench we have decreased the amount of potential energy stored in the bucket
Two point charges are placed at the following points on the x-axis. +2.0 C at
×=0, -3.0.C at 0.40m. Find the electric field strength at 1.20m?
The electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
To find the electric field strength at a distance 1.20 m on the x-axis, we can use Coulomb's law:
\($$F=k\frac{q_1q_2}{r^2}$$\)
where F is the force between two charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is the Coulomb constant.For a single point charge q located at the origin of the x-axis, the electric field E at a distance r is given by:
\($$E=\frac{kq}{r^2}$$\) where k is the Coulomb constant.
So, let's calculate the electric field due to each charge separately and then add them up:
For the +2.0 C charge at x = 0, the electric field at a distance of 1.20 m is:\($$E_1=\frac{kq_1}{r^2}=\frac{(9\times10^9)(2.0)}{(1.2)^2}N/C$$\)
For the -3.0 C charge at x = 0.40 m, the electric field at a distance of 1.20 m is:
\($$E_2=\frac{kq_2}{r^2}\)
\(=\frac{(9\times10^9)(-3.0)}{(1.20-0.40)^2}N/C$$\)
The negative sign indicates that the direction of the electric field is opposite to that of the positive charge at x = 0.
To find the net electric field, we add the two electric fields\(:$$E_{net}=E_1+E_2$$\)
Substituting the values of E1 and E2:
\($$E_{net}=\frac{(9\times10^9)(2.0)}{(1.2)^2}-\frac{(9\times10^9)(3.0)}{(0.8)^2}N/C$$E\)
net comes out to be -1.5×10⁴ N/C.
Therefore, the electric field strength at a distance of 1.20 m on the x-axis is -1.5 × 10⁴ N/C.
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A 221-gram ball is thrown at a speed of 36.7 m/s from the top of a 39.8-m high cliff. Determine the impact speed of the ball when it strikes the ground. Assume negligible air resistance.
Given:
The mass of the ball is
\(\begin{gathered} m=221\text{ g} \\ =0.221\text{ kg} \end{gathered}\)The initial height of the ball is
\(h=39.8\text{ m}\)The initial speed of the ball is
\(v_i=36.7\text{ m/s}\)To find:
the impact speed of the ball when it strikes the ground
Explanation:
The initial potential energy of the ball is
\(\begin{gathered} (PE)_i=mgh \\ =0.221\times9.8\times39.8 \\ =86.2\text{ J} \end{gathered}\)The initial kinetic energy is
\(\begin{gathered} (KE)_i=\frac{1}{2}mv_i^2 \\ =\frac{1}{2}\times0.221\times(36.7)^2 \\ =148.8\text{ J} \end{gathered}\)The final energy of the ball is fully kinetic energy. Let the final impact speed of the ball is
\(v_f\)We can write, using the energy conservation principle that
\(\begin{gathered} (PE)_i+(KE)_i=\frac{1}{2}mv_f^2 \\ 86.2+148.8=\frac{1}{2}\times0.221\times v_f^2 \\ v_f^2=2\times\frac{86.2+148.8}{0.221} \\ v_f=46.1\text{ m/s} \end{gathered}\)Hence, the final impact speed of the ball is 46.1 m/s.
2. A 9.6 kg object is pulled along a horizontal surface. If the coefficient of friction between the surfaces is 0.11, what is the force of friction?
The force of friction is 10.36 N. Friction is an important concept in physics and plays a crucial role in various phenomena, such as walking, driving, and the operation of machines.
What is Frictions?
Friction is a force that opposes motion between two surfaces that are in contact with each other. It arises due to the roughness of the surfaces and the interlocking of the irregularities on the surfaces. Friction acts in a direction opposite to the direction of motion or the tendency of motion.
The force of friction can be calculated using the formula:
f = μN
where:
f = force of friction
μ = coefficient of friction
N = normal force (the force perpendicular to the surface)
In this case, we are given the coefficient of friction and the mass of the object, but we need to find the normal force. Since the object is being pulled horizontally, the normal force is equal to the weight of the object:
N = mg
where:
m = mass of the object
g = acceleration due to gravity (9.81 m/s^2)
N = (9.6 kg)(9.81 m/s^2) = 94.18 N
Now we can calculate the force of friction:
f = μN = (0.11)(94.18 N) = 10.36 N
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A short horizontal line leads to a small circle, which then has a longer line point up at about 45 degrees. A gap in the horizontal line that led to the circle ends with another small circle and then a short horizontal line segment. In a circuit diagram, what does this symbol represent? a resistor a light bulb a battery a switch. and the answer is D!!!!!!
Answer:
the answer is D
Explanation:
Answer:
The answer is D
Explanation:
yes
Ranjana has average velocity 3.2 m/s
How long does she take to cover a displacement
of 256 m
Answer:
t= 80 seonds
Explanation:
Given that,
The average velocity of Ranjana, v = 3.2 m/s
We need to find how long does she take to cover a displacement of 256 m. Let she takes t time.
We know that,
Average speed = distance/time
So,
\(t=\dfrac{d}{v}\\\\t=\dfrac{256\ m}{3.2\ m/s}\\\\t=80\ s\)
So, she will take 80 seconds to cover a displacement of 256 m.
Which element is represented by the atomic model below
A. Calcium
B. Neon
C. Oxygen
D. Helium
Answer:
b
Explanation:
because f its electronic configuration 2:8 indicating that it has 8 electrons in its outer most energy level
Find the position vector of a particle that has the given acceleration and the specified initial velocity and position. Then o your own using a computer, graph the path of the particle. a(t)=12ti+sin(t)j+cos(2t)k,v(0)=i,r(0)=j
The position vector of the particle is r(t) = (4t^3/3 - cos(t) + C1)i + (-cos(t) + C2)j + (sin(2t)/2 + C3)k.
To find the position vector of a particle given its acceleration, initial velocity, and initial position, we integrate the acceleration function twice.
In the given problem, the acceleration function is a(t) = 12ti + sin(t)j + cos(2t)k. Integrating with respect to time, we obtain the velocity function v(t) = 6t^2i - cos(t)j + sin(2t)/2k, where C1 is the constant of integration.
Integrating the velocity function with respect to time once again, we get the position function r(t) = (2t^3 - cos(t) + C1)i - sin(t)j + sin(2t)/2 + C2k, where C2 is the constant of integration.
Given the initial velocity v(0) = i, we can find the constant C1 by substituting t = 0 into the velocity function. Therefore, C1 = 0.
Given the initial position r(0) = j, we can find the constant C2 by substituting t = 0 into the position function. Therefore, C2 = 0.
Thus, the position vector of the particle is r(t) = (4t^3/3 - cos(t))i - cos(t)j + sin(2t)/2k.
To graph the path of the particle, we can use a computer to plot the position vector as a function of time. By varying the time, we can visualize the trajectory of the particle in three-dimensional space.
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if your mass is 72kg your textbooks in Madison has 3.7 kg and you and your textbook are separated by a distance of 0.33 M what is the gravitational force between you and your textbook
Answer:
1.63 X 10^-7N
Explanation:
I need help with the Reasoning to support my claim please.
Tariah is riding on her bike at 4m/s (North). If she accelerates at a rate of 1.5 m/s^2 for 2 s, what is her final velocity?
ANSWER:
7 m/s
STEP-BY-STEP EXPLANATION:
Given:
Initial velocity (u) = 4 m/s
Acceleration (a) = 1.5 m/s^2
Time (t) = 2 s
We can calculate the final velocity using the following formula:
\(v=u+a\cdot t\)We replace and calculate the value of the final velocity:
\(\begin{gathered} v=4+2\cdot1.5 \\ v=4+3 \\ v=7\text{ m/s} \end{gathered}\)The final velocity is equal to 7 m/s.
Is the number on a speedometer a scalar or a vector? PLS HELP !!
being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?
According to the law of constant composition, the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample.
The law of constant composition, also known as the law of definite proportions or law of definite composition, states that a particular chemical compound is composed of the same elements in the same proportions by mass, regardless of its source or method of formation. This law implies that the relative masses of the elements in a compound are fixed and constant.
When a compound undergoes decomposition, it breaks down into its constituent elements or simpler compounds. However, the relative proportions of these elements remain the same as in the original compound. This means that the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample.
For example, let's consider a compound composed of elements A and B in a fixed mass ratio of 2:1. According to the law of constant composition, any sample of this compound will have this 2:1 ratio of masses between elements A and B. If this compound decomposes, the resulting set of masses should still exhibit the 2:1 ratio of elements A and B. For instance, if the original sample had masses of 4 grams for element A and 2 grams for element B, the decomposition products should also have masses in a 2:1 ratio, such as 2 grams of element A and 1 gram of element B.
In conclusion, the law of constant composition states that the proportions of elements in a compound remain constant, both in the original compound and its decomposition products. Thus, the set of masses resulting from the decomposition should reflect the same relative proportions of elements as the original sample, in accordance with the law of constant composition.
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Erica throws a tennis ball against a wall, and it bounces back. Which force is responsible for sending the ball back to Erica?
OA. the force that the ball exerts on the wall
OB. the frictional for between the wall and the ball
OC, the acceleration of the ball as it approaches the wall
OD. the normal force that the wall exerts on the ball
calculate the efficiency of a machine if the input work is 200J and the output work is 150J.
Answer:
75% is the efficency of this maxhine
what is third variable problem?
The third variable problem refers to the possibility that a correlation between two variables may be caused by a third variable that is related to both of them.
In research, it is common to find a correlation between two variables, but it is important to consider the possibility that another factor may be influencing the relationship between those variables. This is where the third variable problem arises.
For example, if researchers find a correlation between ice cream consumption and crime rates, it would be erroneous to conclude that eating ice cream causes crime. It is possible that a third variable, such as temperature, could be influencing both ice cream consumption and crime rates.
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In the drawing below, R1 has a resistance of 6.8 Ω and R2 has a resistance of 1.9-Ω. Determine the current (magnitude and direction) in the 6.8 and 1.9-Ω resistors in the drawing.
For the 6.8 Ω resistors, the voltage across it is V1 = 4.0 V, so the current through it is I1 = V1 / R1 = 4.0 V / 6.8 Ω = 0.588 A
For the 1.9 Ω resistors, the voltage across it is V2 = 12 V, so the current through it is:
I2 = V2 / R2 = 12 V / 1.9 Ω = 6.32 A, directed from the negative terminal of V2 to the positive terminal.
Therefore, the current in the 6.8 Ω resistor is 0.588 A directed from the positive terminal of V1 to the negative terminal, and the current in the 1.9 Ω resistor is 6.32 A directed from the negative terminal of V2 to the positive terminal.
What are resistors?Resistors are electronic components used in electrical circuits to provide a specific amount of resistance to the flow of electric current. They are designed to impede the current flow and reduce the amount of voltage flowing through a circuit.
What does a circuit consist of?An electrical circuit consists of a closed loop of conductive material through which electric current can flow. A circuit typically includes a power source, wires to connect the components, and various components such as resistors, capacitors, inductors, diodes, and transistors, among others.
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Some students conduct an experiment to prove conservation of momentum. They use two objects that collide. Measurements are taken before and after the collision. Which two quantities will the students multiply together before and after the collision?.
Before and after the collision, how many different amounts will the pupils add together. Students should multiply "mass and velocity" (the two variables) before and after the impact.
In accordance with the principle of momentum conservation, In an isolated system, the total momentum of the system prior to the collision and the total momentum of the system following the collision are always identical.Consider two balls with masses "m1" and "m2" that are travelling at speeds "u1" and "u2," respectively, with the goal of demonstrating the law of conservation of momentum. These balls eventually run into each other, causing their speeds to change to "v1" and "v2," respectively.The accompanying image serves as an example of this circumstance.So, based on the principle of momentum conservation.Total Momentum Prior to Collision Equals Total Momentum Subsequent to Collision
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
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What does a step down transformer change in an alternating current
The step down transformer decrease the incoming current's voltage.
Transformers go with the principle of mutual inductance . A changing magnetic field in one circle of wire actuates an electromotive force (EMF) in an adjoining circle of wire, inductively coupled to the primary. In exceptionally fundamental terms, a transformer comprises two coils of wire with tall shared inductance. These coils are electrically isolated whereas they share a common magnetic circuit. In a step-down transformer, there is a decrease in the incoming current’s voltage, where the primary voltage is the incoming voltage whereas the outgoing voltage is considered the secondary. the second coil has fewer windings than the primary, permitting a decrease in voltage within the exiting electrical stream. The primary winding, which is the primary set of coils, interfaces to an alternating-current voltage source, or primary voltage influx. The secondary coil interfaces to the stack, or secondary voltage outpouring, conveying the electrical control absent from the transformer. The substituting current streaming in at the primary voltage makes a substituting magnetic flux. This actuates a similar current within the secondary coil, making a secondary voltage. Here, the diminished number of windings within the secondary coil successfully diminishes the resultant voltage, subsequently “stepping down” the voltage to a lower value whereas keeping up a steady frequency.
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A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?
Answer:
20 ohms
Explanation:
Resistance=Potential difference÷Electric current
X=260÷13
X=20