Answer:
ß
Explanation:
statically and dynamically stable
A rocket has been fired upward to launch a stellite in its orbit name two forces acting on the rocket immediately after leaving the launching pad
Two forces acting on the rocket immediately after leaving the launching pad are the gravitational force and the thrust force.
1. Gravitational Force: The gravitational force is the force exerted by the Earth on the rocket due to their mutual gravitational attraction. It acts downward and is responsible for the rocket's weight.
This force can be represented by the equation Fg = mg, where Fg is the gravitational force, m is the mass of the rocket, and g is the acceleration due to gravity. The gravitational force acts to pull the rocket downward, opposing its upward motion.
2. Thrust Force: The thrust force is the force generated by the rocket's engines as they expel exhaust gases in the opposite direction. It acts upward and propels the rocket forward.
The magnitude of the thrust force depends on factors such as the design of the rocket engines, the amount of fuel burned, and the rate of exhaust gas expulsion. The thrust force must be greater than or equal to the gravitational force for the rocket to overcome Earth's gravity and achieve upward acceleration.
Initially, when the rocket is launched, the thrust force is at its maximum while the gravitational force remains constant. As the rocket gains altitude, the gravitational force decreases slightly due to the increasing distance from the Earth's center.
However, the thrust force continues to be the dominant force propelling the rocket upward.
It's important to note that other forces such as air resistance and wind may also act on the rocket, but immediately after leaving the launching pad, these forces are typically negligible compared to the gravitational force and thrust force.
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A bottle salad dressing must be shaken before it is poured onto a salad in order to evenly mix the particles . How can this salad dressing be classified
A.colloid
B.solution
C.suspension
D.compound
Answer:
D. compound. Google says salad dressing is a compound. Sorry if it's wrong.
Explanation:
How does the orientation of the bar magnet affect the measured magnetic field strength?
When two magnets are close to each other, the magnets experience a repulsive or attractive force. The magnetic field strength is affected by the orientation of the magnet.
The direction in which the bar magnet obtains its maximum magnetic property is called the orientation of the magnet. The magnetic field strength depends on the orientation of the magnet.
The magnetic field lines emerge from the north pole and end in the south pole. When the two bar magnets of opposite poles face each other, an attractive force will be produced and magnetic field strength increases.
When the bar magnet of the same poles faces each other, repulsive force will produce and magnetic field strength decreases. Hence from the orientation of the bar magnet, the magnetic field strength gets affected.
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When you squeeze one end of an inflated balloon, the other end bulges out.
Yes, yes it does. It's cool right?
A car traveling at 3500 m/s is to stop on a 35-meter long shoulder of the road. What minimum deceleration is required?
The minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
What is deceleration?Deceleration is defined as the decrease in speed as the body moves away from the starting point.
The minimum deceleration required can be calculated using the equation of motion:
d = v^2 / (2 * a)
where d is the distance, v is the initial velocity, and a is the acceleration.
Rearranging the equation to solve for a:
a = v^2 / (2 * d) = (3500 m/s)^2 / (2 * 35 m) = 40000 m/s^2
In conclusion, , the minimum deceleration required to stop the car in 35 meters is 40000 m/s^2.
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the density of brick is 1,600 kg/m3. what is the mass of a brick with a volume of 0.0006 m3? WILL MARK BRAINLIEST
Answer:
.0000004
Explanation:
The mass of a brick with a volume of 0.0006 m³ and a density of 1600 kg/m³ is 0.96kg.
HOW TO CALCULATE MASS?The mass of a substance can be calculated by multiplying the density of the substance by its volume. That is;
Mass = density × volume
According to this question, the density of brick is 1,600 kg/m3 and it has a volume of 0.0006m³. The mass is calculated as follows:
Mass = 0.0006 × 1600
Mass = 0.96kg
Therefore, the mass of a brick with a volume of 0.0006m³ and a density of 1600 kg/m³ is 0.96kg.
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g initial angular velocity of 39.1 rad/s. It starts to slow down uniformly and comes to rest, making 76.8 revolutions during the process. a) What is its angular acceleration (in rad/s2 )
Answer:
Approximately \(-1.58\; \rm rad \cdot s^{-2}\).
Explanation:
This question suggests that the rotation of this object slows down "uniformly". Therefore, the angular acceleration of this object should be constant and smaller than zero.
This question does not provide any information about the time required for the rotation of this object to come to a stop. In linear motions with a constant acceleration, there's an SUVAT equation that does not involve time:
\(v^2 - u^2 = 2\, a\, x\),
where
\(v\) is the final velocity of the moving object, \(u\) is the initial velocity of the moving object,\(a\) is the (linear) acceleration of the moving object, and\(x\) is the (linear) displacement of the object while its velocity changed from \(u\) to \(v\).The angular analogue of that equation will be:
\((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\), where
\(\omega(\text{final})\) and \(\omega(\text{initial})\) are the initial and final angular velocity of the rotating object,\(\alpha\) is the angular acceleration of the moving object, and\(\theta\) is the angular displacement of the object while its angular velocity changed from \(\omega(\text{initial})\) to \(\omega(\text{final})\).For this object:
\(\omega(\text{final}) = 0\; \rm rad\cdot s^{-1}\), whereas\(\omega(\text{initial}) = 39.1\; \rm rad\cdot s^{-1}\).The question is asking for an angular acceleration with the unit \(\rm rad \cdot s^{-1}\). However, the angular displacement from the question is described with the number of revolutions. Convert that to radians:
\(\begin{aligned}\theta &= 76.8\; \rm \text{revolution} \\ &= 76.8\;\text{revolution} \times 2\pi\; \rm rad \cdot \text{revolution}^{-1} \\ &= 153.6\pi\; \rm rad\end{aligned}\).
Rearrange the equation \((\omega(\text{final}))^2 - (\omega(\text{initial}))^2 = 2\, \alpha\, \theta\) and solve for \(\alpha\):
\(\begin{aligned}\alpha &= \frac{(\omega(\text{final}))^2 - (\omega(\text{initial}))^2}{2\, \theta} \\ &= \frac{-\left(39.1\; \rm rad \cdot s^{-1}\right)^2}{2\times 153.6\pi\; \rm rad} \approx -1.58\; \rm rad \cdot s^{-1}\end{aligned}\).
what is the 'Water Column"
Answer:a vertical expanse of water stretching between the surface and the floor of a body of water
Explanation:
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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a bar of gold measures .113m *.0254m*.0106m. how many gallons of water have the same mass as this bar?
The volume (in gallon) of water that have the same mass as the bar of gold is 0.153 gallon
How do I determine the volume (in gallon) of water?We'll begin by obtaining the mass of the gold bar. This is given below:
Volume of gold bar = 0.113 m × 0.0254 m × 0.0106 m = 0.00003 m³Density of gold = 19300 kg/m³Mass of gold bar =?Density = mass / volume
Cross multiply
Mass = Density × Volume
Mass of gold bar = 19300 × 0.00003
Mass of gold bar = 0.579 Kg
Finally, we shall determine the volume of water having the same mass as 0.579 Kg of the gold bar. Details below:
Mass of gold bar = 0.579 KgMass of water = Mass of gold bar = 0.579 KgDensity of water = 1000 Kg/m³ Volume of water = ?Volume = mass / density
Volume of water = 0.579 / 1000
Volume of water = 0.000579 m³
Multiply by 264.172 to express in gallon
Volume of water = 0.000579 × 264.172
Volume of water = 0.153 gallon
Thus, we can conclude that the volume of the water is 0.153 gallon
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Which one is the answer
The graph that shows the relationship between the speed and the kinetic energy is option B.
What is the relationship between kinetic energy and speed?Recall that the kinetic energy is referred to as the speed that a body possess by virtue of its motion. Thus an object that is in motion is said to posses the kinetic energy. The kinetic energy is the energy of an object that has a velocity
The kinetic energy is linearly related to the speed of the object. This implies that the speed is directly proportional to the kinetic energy of the object. If there is a direct relationship, it the follows that the graph of the speed against the kinetic energy of the object ought to be a straight line graph.
As such, the relationship between the kinetic energy and the speed of the object can be seen from the image in option B.
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The driver of a car moving with a constant speed applies the breaks, and the car comes to a stop after traveling 3.5 meters. Which force causes the deceleration of the car?
Answer:
Friction is the resistive force. when a driver applies brakes, the wheels stop rotating and there is friction between the tyres and the rough surface of the road. (but if you ask why it moves 3.5 m after braking, that is due to the intertia of the moving car)
A fishing boat uses an ultrasound of frequency 4.0×10²Hz to detect a fish blow it. two echo's of the ultrasound are received after 0.09s coming from the shoal of the fish and the other after 0.12s coming from the sea bed .if the sea bed is 64m below the ultrasound transmitter and the receiver, calculate; a. the speed of the ultrasound in water b. the wavelength of ultrasound in water. c. the depth of the fish below the boat.
a. the speed of the ultrasound in water is 1480 m/s
b. the wavelength of the ultrasound in water is 37 m
c. the depth of the fish below the boat is 89.76 m
How to calculate?a.
v = fλ
v = fλ = (4.0 x 10^2 Hz)(λ)
the speed of the ultrasound in water is given as :
v = v_water = 1480 m/s
substitute v_water into the equation above and solve for λ:
λ = v_water / f = (1480 m/s) / (4.0 x 10^2 Hz) = 37 m
Therefore, the speed of the ultrasound in water is 1480 m/s and the wavelength is 37 m.
c. The depth of the fish below the boat ia found using,
d = v_water * t / 2
The first echo came back after 0.09 s:
d = (1480 m/s) * (0.09 s) / 2 = 64.32 m
This is the depth of the sea bed, which is already known to be 64 m. So the fish must be deeper than the sea bed, and the second echo must have come from the fish. The second echo came back after 0.12 s:
d = (1480 m/s) * (0.12 s) / 2 = 89.76 m
So the depth of the fish below the boat is 89.76 m
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A meter stick has a mass of 0.30 kg and balances at its center. When a small chain is suspended from one end, the balance point moves 28.0 cm toward the end with the chain. Determine the mass of the chain.
Answer:
M L1 = m L2 torques must be zero around the fulcrum
M = m L2 / L1 = .3 kg * 28 cm / 22 cm = .382 kg
If an object is placed between a convex lens and its focal point, which type of image will be produced?
What happens when Earth rotates on its axis and how long does it take
Answer:
You get Day and Night
It takes 24 hour
Answer:
Explanation:
The Earth's orbit makes a circle around the sun. At the same time the Earth orbits around the sun, it also spins.Since the Earth orbits the sun and rotates on its axis at the same time we experience seasons, day and night, and changing shadows throughout the day.It only takes 23 hours, 56 minutes and 4.0916 seconds for the Earth to turn once on its axis.
Activity 4: Caste System - The Hierarchy
Instruction: Label the hierarchy of the caste system. Write your answer on the
space provided.
Please respect! Can you answer this for me?
Answer:
ıf u find the answer can u comment me to notification thank u
Explanation:
(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?
The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.
The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.
Is there a timepiece on the ISS?For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.
Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.
Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.
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Can we pretend that airplanes in the night sky are like shootin' stars
I could really use a wish right now, wish right now, wish right now
Can we pretend that airplanes in the night sky are like shootin' stars
I could really use a wish right now, wish right now, wish right now
Answer:
Ok
Explanation:
What type of map is shown above?
Political
Political
Physical
Physical
Historical
Historical
Thematic
The earth rotates on its axis with a period of 24 hours. What is the frequency in Hertz?
Answer:
The answer is 0.042 Hz (rounded)
or 0.0417 Hz
Explanation:
Hope it helps
Answer:
The answer is 0.041Hz
Explanation:
The answer is 0.041Hz
I guess
An object's speed is 3.6 m/s with a momentum of 180 kgm/s. What is the mass of the object?
Answer:
To solve the problem we must know the concept of momentum.
What is Momentum?
Momentum is defined as the product of the mass of an object and the velocity of an object. It is a vector quantity.
$$\rm{Momentum = velocity \times Mass$$
The mass of the object is 50 kg.
Given to us
velocity of the object = 3.60 m/s
momentum of the object = 180 kg m/s
Mass of the object
We know that momentum is the product of the mass of the object and the velocity of the object,
$$\rm{Momentum = velocity \times Mass$$
Substitute the values,
180 = 3.60 \times \rm Mass180=3.60×Mass
\rm Mass = \dfrac{180\ kg\ m/s}{3.6\ m/s}Mass=
3.6 m/s
180 kg m/s
\rm Mass = 50\ kgMass=50 kg
Hence, the mass of the object is 50 kg.
Describe and explain motion due to uniform velocity in one direction and uniform acceleration in a perpendicular direction
Answer: you have to divide and multiple fam
Explanation:
Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2
The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2
Step 1: used the ideal gas equation to calculate the moles of O2
that is Pv=n RT where;
P(pressure)= 1.00 atm
V(volume) =3.90 L
n(number of moles)=?
R(gas constant) = 0.0821 L.atm/mol.K
T(temperature) = 273 k
by making n the subject of the formula by dividing both side by RT
n= Pv/RT
n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles
Step 2: use the Avogadro's law constant to calculate the number of molecules
that is according to Avogadro's law
1 mole = 6.02 x10^23 molecules
0.174 moles=? molecules
by cross multiplication
the number of molecules
= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2
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6. A picture of weight, w is hanging from a steel nail as shown in the figure below. The nail has a diameter of 1.50 mm and an original length, Lo = 5.0 mm. Useful Information: The shear modulus, G for steel is 80 x 10° N.m². (a) (b) (c) 1.50 mm 3 Ax = 1.80 μm W Lo = 5.00 mm M What kind of deformation occurs in this case? How are stress and strain in this deformation related to each other? [3] When the picture is hung from the nail, the head of the nail displaces vertically downwards by an amount Ax = 1.80 µm. Find the mass of the picture. Neglect the weight of the nail. [6] What angle does the nail make with the horizontal after the picture is hung from it? [2]
The mass of the picture is approximately 5.19 kilograms.
How to solve for the problemThe deformation in this case is called shear deformation, a type of deformation that occurs when parallel internal surfaces slide past one another. It is caused by shear stress in the structure. The shear stress (τ) is the force (F) applied divided by the cross-sectional area (A) of the nail. The shear strain (γ) is the displacement (Δx) divided by the original length (L0).
The relationship between shear stress and shear strain is given by the shear modulus (G) in the formula:
τ = G * γ
To find the weight of the picture, we need to calculate the shear stress first:
The cross-sectional area A of the nail is given by the formula for the area of a circle:
A = πr² = π(d/2)² = π(0.0015 m / 2)² = 1.767 x 10^-6 m².
The shear strain γ is given by:
γ = Δx / L0 = (1.80 x 10^-6 m) / (5 x 10^-3 m) = 0.36.
The shear stress τ can now be calculated by rearranging the formula:
τ = G * γ
=> τ = (80 x 10^9 N/m²) * 0.36 = 28.8 x 10^9 N/m²
The force F on the nail is equal to the weight w of the picture, and it can be calculated from the shear stress:
τ = F / A
=> F = τ * A = (28.8 x 10^9 N/m²) * (1.767 x 10^-6 m²) = 50.89 N.
Since weight w = m * g, where m is mass and g is the acceleration due to gravity (approximately 9.81 m/s²), we can find the mass m:
m = w / g = (50.89 N) / (9.81 m/s²) = 5.19 kg.
So, the mass of the picture is approximately 5.19 kilograms.
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How high above the ground would a 2 kg object need to be in order to have 180 J
of gravitational potential energy?
Answer:
energy= MGH
2*9.8*h=180
h=180/19.6
h=9.32 m
The height of the object above the ground would be equal to 9.18 m.
What is gravitational potential energy?When an object of mass (m) is moved from infinity to a certain point inside the gravitational influence, the amount of work done in displacing it is stored in the form of potential energy and is known as gravitational potential energy.
The mathematical equation for gravitational potential energy can be written as:
Gravitational potential energy = m⋅g⋅h
Where m is the mass, g is the gravitational acceleration and h is the height above the ground.
Given, the mass of the given object, m = 2 Kg
The gravitational potential energy = 180 J
\(GPE = m\times g\times h\)
180 = 2 × 9.8 × h
h = 9.18 m
Therefore, the object should be at a height of 9.18 meters in order to have 180 J of gravitational potential energy.
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For each scenario below, choose the best graph.
(a) Maria bikes from home to work.
A line graph that plots either speed or distance against time.
Really, the type of graph depends on what quantity you want the graph to show.
An astronaut measure the period of a mass spring system on Earth. How would the period be affected if the astronaut measured the period of the same mass spring system on the moon? (Moon's gravity = 1/6 Earth's gravity.)
An astronaut measure the period of a mass spring system on Earth.
The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.
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Please help me on this
Answer:
Explanation:
read the assignment and use this
Topic sentence
Evidence from the text
Thoughts in your own words
Opinion
Wrap up sentence
T
E
T
O
W
and 2 of those make 2 paragraphs