a number between 200 and 300 with a 7 in the thousandths place and a 2 in the hundredths place

The time Jack left Santa Clara is 1 : 55 pm

A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.

The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.

Therefore, the total time he spent is

25mins + 25 mins = 50 mins

He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;

2:45 pm = 14 :45

= 14:45 - 50mins

= 13:55

= 1 : 55pm

Therefore he left at 1:55 pm

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Step-by-step explanation:

1 m (meter) is 100 cm (centimeters).

so, 7 m is 700 cm.

each piece is r × 2.54 cm long (as every inch is 2.54 cm).

so,

number of pieces = 700 / (r × 2.54)

The number of species can find by expression is

700 / (r × 2.54)

We have given that

Sophia has 7 m of ribbon

she will cut pieces of ribbon that are each r inches long.

We have to calculate the number of pieces of ribbon that she will have

What is the value of 1 meter in cementer?

1 (meter) =100 (centimetres).........(1)

multiply both side by 7

7 m is 700 cm.

each piece is

r × 2.54 cm long ..................(as 1 inch is 2.54 cm).

so,

\(number of pieces = 700 / (2.54r)\)

Therefore the number of species can find by expression is

700 / (r × 2.54)

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Answer:

0.44 is the correct answer

Answer:

.44

Step-by-step explanation:

11/25

Multiply the top and bottom by 4

11*4

-------

25*4

44

-----

100

The decimal is .44

Answer:

a.{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b.{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.{d d, dg, g d, g g}

d.{dg, g d, gg}

Step-by-step explanation:

We have to find the sample space

a. We are given items

{a, b, c, d}

Therefore, the sample space

{a b, a c, a d, b c, b d, c d, b a, d c ,d b, c a, d a, c b}

b. Items

Therefore, the sample space

{a b, a c, a d, a e ,a f, a g, b c, bd,be,bf,bg,cd,ce,cf,cg,fg,ba,ca,da,ea,fa,ga,cd,db,eb,fb,gb,dc,ec,fc,gc,fe,ge,gf,de,df,dg,ed,fd,gd,ef,eg}

c.

Defective items (d)=4

Good items(g)=20

Therefore, the sample space

{d d, dg, g d, g g}

d.

Defective items (d)=1

Good items(g)=20

Therefore, the sample space

{d g, g d, g g}

Answer:

336 ft³ or 336 cubic feet

Step-by-step explanation:

Volume = Area triangle * height

Area triangle = 1/2(8 x 14)

Area triangle = 1/2(112) = 56 ft²

56 ft² * 6 ft = 336 ft³

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The value of y is 130°

The angles occupy the same relative position at each intersection where a straight line crosses two others. If the two lines are parallel, the corresponding angles are equal.

Given here:

Horizontal and parallel lines b and c are cut by transversal a. At the intersection of lines b and a, the bottom right angle is 50 degrees. At the intersection of lines c and a, the top left angle is y degrees.

Thus the angle adjacent to the 50-degree angle will be 130

but this angle corresponds to the angle y thus y=130 as corresponding angles are equal when a transversal intersects two parallel lines

Hence, The value of y is 130°

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Answer:

The numbers are 6 and 7.

Step-by-step explanation:

4² = 16

5² = 25

6² = 36

7² = 49

√36 = 6

√42 = ?

√49 = 7

The numbers are 6 and 7.

\( \Large \mathbb{SOLUTION:} \)

\( \begin{array}{l} \text{Let }r\text{ be the rate of the boat in still water and} \\ c\text{ be the rate of the current.} \\ \\ \text{So } \\ \begin{aligned} \quad&\bullet\:\text{Rate Upstream}= r - c \\ &\bullet\:\text{Rate Downstream}= r - c\end{aligned} \\ \\ \text{We know that }\text{Rate} = \dfrac{\text{Distance}}{\text{Time}}. \end{array} \)

\( \begin{array}{l} \bold{Equations:} \\ \\ \begin{aligned} &\quad\quad \quad r - c = \dfrac{104}{4} = 26\quad (1) \\ \\ & \quad \quad \quad r + c = \dfrac{200}{4} = 50\quad (2)\\ \\ & \text{Adding (1) and (2), we get} \\ \\ &\quad\quad 2r = 76 \implies \boxed{r = 38\ \text{kph}} \\ \\ &\text{Using (2), it follows that} \\ \\ & \quad \quad c = 50 - r \implies \boxed{c = 12\ \text{kph}} \end{aligned} \end{array} \)

Answer:

$50.40

Step-by-step explanation:

90 - 20%:

We can use fractions to simplify this percentage:

90 - 2/10 = 90 - 18 = 72.

So before it was put on clearance, it was $72.

After it's put on clearance:

72 - 30% = 72 - 3/10 = 72 - 21.6 = 50.4

So the final price is $50.4.

The motion of the skier from point A to point B, then to point C, and then point D, indicates that the distances and displacement traveled are;

a) The distance from A to C is 280 meters

b) The distance from point A to point D is 360 meters

c) The displacement of the skier from point B to point C is 120 meters.

Displacement is the change in the position or location of the object.

The possible diagram of the skier in the question can be presented as follows;

A \({}\)                            C                                                   D                          B

t = 0 min      \({}\)         t = 2 min                                       t = 3 min            \({}\)t = 1 min

ʂ         \({}\)                     ʂ                                                     ʂ                           ʂ

-|-------|------|------|------|-----|------|-----|------|------|-------|-------|--------|-------|-------|-----

0           \({}\)   20           40         60          80            100    120    140           160

The above diagram indicates that we get;

a) The distance from point A (t = 0 min) to point C(t = 2 min) is can be found as follows;

The skier moves from point A to point B then from point B to point C, therefore,

The distance from point A to point B = 160 m - 0 m = 160 m

The distance from point B to point C = 160 m - 40 m = 120 m

The distance from point A to point C is therefore;

b) The distance from point A to point D = The distance from point A to point C + The distance from point C to point D as follows;

AD = AC + CD

CD = 120 m - 40 m = 80 m

Therefore;

AD = 280 m + 80 m = 360 m

c) The displacement of the skier from point B (t = 1 min) to C (t = 2 min) can be found as follows;

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\(3x+(-8)=-71\)

Simplify:
\(3x-8=-71\)

Add 8 to both sides:

\(3x-8+8=-71+8\)

\(3x=-63\)

Divided both sides by 3:

\(\dfrac{3x}{3} =\dfrac{-63}{3}\)

\(\fbox{x = -21}\)

Answer:

(a) 1/6. One out of six sides will give you the desired result.

(b) 3/6. 3 out of 6 sides will give you the desired result.

(c) 2/3. 4 out of 6 sides will give you the desired result.

There are 6 goats and 17 ducks present in the farmhouse

Let x represent the number of goats

Let y represent the number of ducks

x + y= 23....equation1

Goats have 4 legs and ducks have 2 legs

4x + 2y= 58.......equation 2

From equation 1

x + y= 23

x= 23-y

Substitute 23-y for x in equation 2

4(23-y) + 2y = 58

92- 4y + 2y= 58

92-2y= 58

-2y= 58-92

-2y= -34

y- 34/2

y= 17

Substitute 17 for y in equation 1

x + y= 23

x + 17= 23

x= 23-17

x= 6

Hence there are 6 goats and 17 ducks in the farmhouse shelter

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Answer:caca

Step-by-step explanation:

poop

Answer: $16,244.55

Step-by-step explanation: Multiply $19,100 by .19 to find the discount. Then subtract that number from the original to find the discounted price. Then multiply the discounted price by .5 to find the tax. Add the tax to the discounted price to find the discounted taxed price. This is the final price and is $16,244.55

Answer:

x=-4,\:y=-2

Step-by-step explanation:

Answer:

x=-4

y=-2

Step-by-step explanation:

-4x-4y=24. .........1

3x+10=y...........2

since y is already isolated in equation 2 we can substitute the y value

subs 2 into 1

-4x-4(3x+10)=24.

-4x-12x-40=24

-16x=24+40

x=-4.....3

subs 3 into 2

3(-4)+10=y

-12+10=y

-2=y

g(x)=6 is a function whose outcome is equal to 6, regardless of the value of the input.

Therefore, four ordered pairs in the graph of the function, are

The answer is (0,6), (1,6), (2,6), (3,6); there is an infinite number of valid ordered pairs.

Answer: 0.0622009569378

Step-by-step explanation:

The profit function is P(x) = -500.523x^2 + 600x - 200.

To find the profit function, P(x), we need to subtract the cost function, C(a), from the revenue function, R(x).

Given:

Cost function: C(a) = 500x^2 + 300

Revenue function: R(x) = -0.523x^2 + 600x - 200 + 300

Profit function, P(x), is obtained by subtracting the cost function from the revenue function:

P(x) = R(x) - C(a)

P(x) = (-0.523x^2 + 600x - 200 + 300) - (500x^2 + 300)

Simplifying the expression:

P(x) = -0.523x^2 + 600x - 200 + 300 - 500x^2 - 300

P(x) = -500x^2 - 0.523x^2 + 600x + 300 - 200 - 300

P(x) = -500x^2 - 0.523x^2 + 600x - 200

Combining like terms:

P(x) = (-500 - 0.523)x^2 + 600x - 200

Simplifying further:

P(x) = -500.523x^2 + 600x - 200

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Option 3 yielded the most money after 10 years is 171.7

Option 1 yielded the most total money by the time you were 60 years old is 8,771.56

A solution of an equation is a value or set of values that satisfy the equation, meaning that when the value(s) is substituted for the variable(s) in the equation, both sides of the equation are equal.

Based on the given equations, Option 1 yielded the most money after 10 years, and Option 3 yielded the most total money by the time you were 60 years old.

After 10 years:

Option 1: 50×(1.09)¹⁰ - 30 =  88.36

Option 2: 50×(1.08)¹⁰ - 20 =  87.94

Option 3: 100×(1.07)¹⁰ - 25 =  171.71

Therefore, Option 3 yielded the most money after 10 years is 171.7

By the time you were 60 years old:

Option 1: 50×(1.09)⁶⁰ - 30 =  8,771.56

Option 2: 50×(1.08)⁶⁰ - 20 =  5,042.85

Option 3: 100×(1.07)⁶⁰ - 25 =  5,769.64

Therefore, Option 1 yielded the most total money by the time you were 60 years old is 8,771.56

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Answer:

13

Step-by-step explanation:

the sum to n terms of a geometric sequence is

\(S_{n}\) = \(\frac{a(r^{n}-1) }{r-1}\)

where a is the first term and r the common ratio

here a = 6 , r = \(\frac{12}{6}\) = 2 and \(S_{n}\) = 49146 , then

\(\frac{6(2^{n}-1) }{2-1}\) = 49146

6(\(2^{n}\) - 1) = 49146 ( divide both sides by 6 )

\(2^{n}\) - 1 = 8191 ( add 1 to both sides )

\(2^{n}\) = 8192 ( take log of both sides )

log \(2^{n}\) = log 8192 , that is

n log 2 = log 8192 ( divide both sides by log 2 )

n = \(\frac{log8192}{log2}\) = 13

\(\red{ \underline { \boxed{ \sf{Common \: Ratio,r = \frac{any\:observed\:term}{previous\:term}}}}}\)

\(\longrightarrow\)\(\sf Common \: Ratio,r = \frac{12}{6} \)

\(\quad \boxed{\sf {Common \:Ratio,r = 2 }}\)

Now,

\(\green{ \underline { \boxed{ \sf{Sum\: of \: G.P. \: to\: n\:term,S_n = \frac{a(r^n-1)}{r-1}}}}}\)

where

Putting Values -

\(\begin{gathered}\\\implies\quad \sf 49146 = \frac{6(2^n-1)}{2-1} \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf \frac{\cancel{49146}}{\cancel{6}} = \frac{2^n-1}{1} \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf 8191= \frac{2^n-1}{1} \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf 2^n-1 =8191 \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf 2^n =8191+1 \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf 2^n =8192 \\\end{gathered} \)

\(\begin{gathered}\\\implies\quad \sf 2^n =2^{13}\quad(8192= 2^{13}) \\\end{gathered} \)

Comparing powers on both sides-

\(\begin{gathered}\\\implies\quad \boxed{\sf{ n = 13}}\\\end{gathered} \)

\(\longrightarrow\)Therefore, to get a sum of 49146 , 13 terms of this G.P. should be taken.

Answer:

Which statement represents the expression?

24−8÷4

A. 24 minus 8 divided by 4

B. the difference of 24 and 8 divided by 4

C. 24 minus the quotient of 8 divided by 4

D. 24 minus 4 divided by 8

The answer is a. 24 minus 8 divided by 4

-----------------------------------

\( \green{ \boxed{ \boxed{ \sf{Lusi \: Adriana} } } } \)

Answer:16x16

Step-by-step explanation:

Answer: An exponential decay function models a situation in which a value decreases over time at a rate that is proportional to its current value. The function has the form:

y = A*e^(-kt)

Where y is the final value, A is the initial value, e is the base of the natural logarithm (approximately 2.718), k is the decay factor, and t is the time.

In this case, the initial value is 42 and the decay factor is 0.7. So the exponential decay function that models the situation is:

y = 42 * e^(-0.7t)

To compare the average rates of change over the given intervals, we need to find the derivative of the function, which represents the instantaneous rate of change of the function at any given point in time.

The derivative of this function is:

dy/dt = -0.742e^(-0.7t)

The negative sign indicates that the value is decreasing over time. The absolute value of the derivative will be the rate of decay.

So, the average rate of change over the given intervals is -0.7*42 which is -29.4

The rate of decay is always -29.4 for this function.

Step-by-step explanation:

\({\huge{\fbox{\tt{\blue{ANSWER}}}}}\)

______________________________________

The probability of answering a single problem correctly by randomly guessing is 1/4, since there are 4 answer choices and only one correct answer. Since the student randomly guessed the answer to both problems, the probability of answering both problems correctly is:

(1/4) x (1/4) = 1/16

Therefore, the probability that the student answered both problems correctly is 1/16.

Answer: The amount you would pay (including tax) for the item is:

$755.37 + $52.88 = $808.25

Step-by-step explanation: irst, we calculate the amount of discount that is applied to the original price:

30% of $1199 = 0.3 x 1199 = $359.70

So, the discounted price is:

$1199 - $359.70 = $839.30

Next, we apply the additional 10% off coupon to this discounted price:

10% of $839.30 = 0.1 x $839.30 = $83.93

The final price after the coupon is applied is:

$839.30 - $83.93 = $755.37

Finally, we calculate the sales tax on this final price:

7% of $755.37 = 0.07 x $755.37 = $52.88

The amount you would pay (including tax) for the item is:

$755.37 + $52.88 = $808.25